See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'josmiceli'

josmiceli answered: 9815 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839, >>Next

Money_Word_Problems/197937: .} Recovering an investment. The manager at Cream of the Crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit on each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally?
1 solutions

Answer 148427 by josmiceli(9817) About Me  on 2009-05-27 10:13:41 (Show Source):
You can put this solution on YOUR website!
Let w= the number of watermelons bought
given:
w+-+30= the number of watermelons sold
1.5%2A%28w+-+30%29= profit made on watermelons sold
200%2Fw= price paid per watermelon bought
--------------------------------------
%28200%2Fw+%2B+1.5%29%2A%28w+-+30%29+=+200
This is (cost/wm + profit/wm)*(actual wm's sold) = investment
200%2Fw+%2B+1.5+=+200%2F%28w+-+30%29
Multiply both sides by w%2A%28w+-+30%29
200%2A%28w+-+30%29+%2B+1.5w%2A%28w+-+30%29+=+200w
200w+-+6000+%2B+1.5w%5E2+-+45w+=+200w
1.5w%5E2+-+45w+-+6000+=+0
w+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a+=+1.5
b+=+-45
c+=+-6000
w+=+%28-%28-45%29+%2B-+sqrt%28+%28-45%29%5E2-4%2A1.5%2A%28-6000%29+%29%29%2F%282%2A1.5%29+
w+=+%2845+%2B-+sqrt%28+2025+%2B+36000+%29%29%2F3+
w+=+%2845+%2B-+sqrt%28+38025+%29%29%2F3+
w+=+%2845+%2B-+195%29%2F3+
w+=+240%2F3 (ignore negative result)
w+=+80
She bought 80 watermelons originally
check answer:
200%2F80+=+2.5= price paid per watermelon
80+-+30+=+50= watermelons sold
2.5%2A50+=+125= price paid for water melons sold
1.5%2A50+=+75= profit on watermelons sold
125+%2B+75+=+200
OK


Travel_Word_Problems/197923: There are 220 barrels of cement in one shed and 510 barrels in another. How many barrels must be transferred from the second to the first shed will contain two thirds as much as the second? I need help setting up the equation...plez. thank you
1 solutions

Answer 148409 by josmiceli(9817) About Me  on 2009-05-27 00:38:25 (Show Source):
You can put this solution on YOUR website!
Let x = barrels of cement to be transferred from 2nd to 1st shed
After transferring:
In shed 1 is 220+%2B+x
In shed 2 is 510+-+x
given:
220+%2B+x+=+%282%2F3%29%2A%28510+-+x%29
Multiply both sides by 3
660+%2B+3x+=+2%2A%28510+-+x%29
660+%2B+3x+=+1020+-+2x
5x+=+1020+-+660
5x+=+360
x+=+72
72 barrels of cement must be transferred from 2nd to 1st shed
check:
220+%2B+x+=+%282%2F3%29%2A%28510+-+x%29
220+%2B+72+=+%282%2F3%29%2A%28510+-+72%29
292+=+%282%2F3%29%2A438
Multiply both sides by 3
876+=+2%2A438
876+=+876
OK


Linear_Equations_And_Systems_Word_Problems/197922: A B and C can finish a job in 6 days. If B and C work together the job will take 9 days. If A and C work together the job will take 8 days. In how many days can each man working alone do the job?
1 solutions

Answer 148407 by josmiceli(9817) About Me  on 2009-05-27 00:27:14 (Show Source):
You can put this solution on YOUR website!
I will say the following:
A's rate of working is (1 job)/(a days)
B's rate of working is (1 job)/{b days)
C's rate of working is (1 job)/(c days)
---------------------------------------
I can add their rates of working to get a
rate at which they work together
(1) 1%2Fa+%2B+1%2Fb+%2B+1%2Fc+=+1%2F6
(2) 1%2Fb+%2B+1%2Fc+=+1%2F9
(3) 1%2Fa+%2B+1%2Fc+=+1%2F8
-------------------------
From (2)
1%2Fb+=+1%2F9+-+1%2Fc
From (3)
1%2Fa+=+1%2F8+-+1%2Fc
Substitute these into (1)
(1) 1%2Fa+%2B+1%2Fb+%2B+1%2Fc+=+1%2F6
1%2F8+-+1%2Fc+%2B+1%2F9+-+1%2Fc+%2B+1%2Fc+=+1%2F6
1%2F8+%2B+1%2F9+-+1%2Fc+=+1%2F6
1%2Fc+=+1%2F8+%2B+1%2F9+-+1%2F6
Multiply both sides by 72c
72+=+9c+%2B+8c+-+12c
5c+=+72
c+=+14.4
From (2)
(2) 1%2Fb+%2B+1%2Fc+=+1%2F9
1%2Fb+%2B+5%2F72+=+1%2F9
72+%2B+5b+=+8b
3b+=+72
b+=+24
From (3)
(3) 1%2Fa+%2B+1%2Fc+=+1%2F8
1%2Fa+%2B+5%2F72+=+1%2F8
72+%2B+5a+=+9a
4a+=+72
a+=+18
A can do the job in 18 days
B can do the job in 24 days
C can do the job in 14.4 days
check answer:
(1) 1%2Fa+%2B+1%2Fb+%2B+1%2Fc+=+1%2F6
1%2F18+%2B+1%2F24+%2B+1%2F14.4+=+1%2F6
Multiply both sides by 72
4+%2B+3+%2B+5+=+12
12+=+12
OK
(2) 1%2Fb+%2B+1%2Fc+=+1%2F9
1%2F24+%2B+1%2F14.4+=+1%2F9
Multiply both sides by 72
3+%2B+5+=+8
8+=+8
OK
(3) 1%2Fa+%2B+1%2Fc+=+1%2F8
1%2F18+%2B+1%2F14.4+=+1%2F8
Multiply both sides by 72
4+%2B+5+=+9
9+=+9
OK


Travel_Word_Problems/197729: Thelma's average driving speed is 3 miles per hour faster than Doug's. In the same length of time it takes Thelma to drive 200 miles, Doug only drives 188 miles. What is Thelma's average driving speed?
1 solutions

Answer 148406 by josmiceli(9817) About Me  on 2009-05-26 23:51:34 (Show Source):
You can put this solution on YOUR website!
I have an equation for each one
d%5Bt%5D+=+r%5Bt%5D%2At%5Bt%5D
and
d%5Bd%5D+=+r%5Bd%5D%2At%5Bd%5D
---------------------
given:
r%5Bt%5D+=+r%5Bd%5D+%2B+3 mi/hr
t%5Bt%5D+=+t%5Bd%5D (I'll call them both t)
d%5Bt%5D+=+200 mi
d%5Bd%5D+=+188 mi
---------------------
What is Thelma's average driving speed?
d%5Bt%5D+=+r%5Bt%5D%2At%5Bt%5D
200+=+r%5Bt%5D%2At
200+=+%28r%5Bd%5D+%2B+3%29%2At
and
d%5Bd%5D+=+r%5Bd%5D%2At%5Bd%5D
188+=+r%5Bd%5D%2At
r%5Bd%5D+=+188%2Ft
Substituting,
200+=+%28188%2Ft+%2B+3%29%2At
200+=+188+%2B+3t
3t+=+12
t+=+4 hr
Substituting,
200+=+r%5Bt%5D%2At
r%5Bt%5D+=+200%2F4
r%5Bt%5D+=+50
Thelma's average driving speed was 50 mi/hr
check:
r%5Bt%5D+=+r%5Bd%5D+%2B+3 mi/hr
50+=+r%5Bd%5D+%2B+3
r%5Bd%5D+=+47 mi/hr
d%5Bd%5D+=+r%5Bd%5D%2At%5Bd%5D
188+=+47%2A4
188+=+188
and
d%5Bt%5D+=+r%5Bt%5D%2At%5Bt%5D
200+=+50%2A4
200+=+200
OK


Equations/197753: A math teacher collects old books. One day, a student asked him how many old math books he has. He replied, "If I divide the books into unequal whole numbers, then 64 times the difference between the two numbers equals the difference between the squares of the two numbers." How many old math books does the teacher have?
1 solutions

Answer 148404 by josmiceli(9817) About Me  on 2009-05-26 23:31:17 (Show Source):
You can put this solution on YOUR website!
Call the larger number a
Call the smaller number b
given:
64%2A%28a+-+b%29+=+a%5E2+-+b%5E2
64%2A%28a+-+b%29+=+%28a+%2B+b%29%28a+-+b%29
64+=+a+%2B+b
I now know that the sum of the numbers is 64
I can think of the right side of the equation as
(hypotenuse)^2 - (one leg)^2 of a right triangle
where a is the hypotenuse and b is the leg
The left side of the equation must be c%5E2
where c+=+sqrt%2864%2A%28a+-+b%29%29
From above, b+=+64+-+a+, so
c+=+8%2Asqrt%28a+-+%2864+-+a%29%29
c+=+8%2Asqrt%282a+-+64%29
c must be a whole number, since the right side
of the original equation is a whole number
That means that sqrt%282a+-+64%29 must be a whole number
Note that if a+=+32, then c+=+0 and
c%5E2+=+0, a%5E2+=+b%5E2, a+=+b and that is
not allowed by the problem.
So a+%3E+32
I'll try a+=+33
b+=+64+-+a
b+=+64+-+33
b+=+31
c+=+8%2Asqrt%2866+-+64%29
c+=+8%2Asqrt%282%29
Not allowed, since c has to be a whole number
I'll try a+=+34
b+=+30
c+=+8%2Asqrt%2868+-+64%29
c+=+8%2Asqrt%284%29
c+=+16
c%5E2+=+256
a%5E2+-+b%5E2+=+34%5E2+-+30%5E2
a%5E2+-+b%5E2+=+1156+-+900
a%5E2+-+b%5E2+=+256
So, c%5E2+=+a%5E2+-+b%5E2
64%2A%28a+-+b%29+=+a%5E2+-+b%5E2
64%2A%2834+-+30%29+=+256
64%2A4+=+256
256+=+256
---------------
a+%2B+b+=+64
The teacher had 64 old math books


Age_Word_Problems/197870: The ten's digit of a two digit number is 3 more than the unit's digit. The number is eight more than six times the sum of the digits. Find the number.
1 solutions

Answer 148397 by josmiceli(9817) About Me  on 2009-05-26 22:48:08 (Show Source):
You can put this solution on YOUR website!
Call the tens digit a
Call the units digit b
The number is 10a+%2B+b
given:
(1) a+=+b+%2B+3
(2) 10a+%2B+b+=+6%2A%28a+%2B+b%29+%2B+8
Substitute (1) in (2)
(2) 10%2A%28b+%2B+3%29+%2B+b+=+6%2A%28b+%2B+3+%2B+b%29+%2B+8
10b+%2B+30+%2B+b+=+6b+%2B+18+%2B+6b+%2B+8
11b+%2B+30+=+12b+%2B+26
b+=+4
And, from (1)
a+=+4+%2B+3
a+=+7
The number is 74
check answer:
(2) 10a+%2B+b+=+6%2A%28a+%2B+b%29+%2B+8
10%2A7+%2B+4+=+6%2A%287+%2B+4%29+%2B+8
74+=+6%2A11+%2B+8
74+=+74


Polynomials-and-rational-expressions/197872: A rectangular pen has a length of 3 feet greater than its width. If both dimensions are increased by 5 feet, which expression gives the resulting increase in area?
a. 10x + 40
b. 13x + 40
c. x2 + 13x + 40
d. x2 + 10x =40
My attempt: area = length x width
original pen would be x(x+3)=x2+3x
new pen would be (x+5)(x+8)=x2+13x+40
However answer sheet says correct answer is A.
Thank you
1 solutions

Answer 148395 by josmiceli(9817) About Me  on 2009-05-26 22:33:52 (Show Source):
You can put this solution on YOUR website!
What they're asking for is: "How much bigger
is the 2nd pen than the 1st?
So, in words
Difference = (area of 2nd pen) - (area of 1st pen)
A%5B1%5D+=+x%2A%28x%2B3%29
A%5B2%5D+=+%28x%2B5%29%2A%28x+%2B+8%29
A%5B2%5D+-+A%5B1%5D+=+x%5E2+%2B+13x+%2B+40+-+x%5E2+-+3x
A%5B2%5D+-+A%5B1%5D+=+10x+%2B+40


Equations/197480: Please help me solve for x in this problem
3/(5x)-4/(3x)=7
Thanks
1 solutions

Answer 148090 by josmiceli(9817) About Me  on 2009-05-23 22:28:09 (Show Source):
You can put this solution on YOUR website!
3%2F%285x%29-4%2F%283x%29=7
Note that x can't be 0, since that would mean
dividing by 0, which is prohibited
Multiply both sides by 15x, the LCD
9+-+20+=+105x
105x+=+-11
x+=+-11%2F105
check answer:
3%2F%285%2A%28-11%2F105%29%29+-+4%2F%283%2A%28-11%2F105%29%29+=+7
Multiply both sides by -11%2F105
3%2F5+-+4%2F3+=+-77%2F105
Multiply both sides by 105
63+-+140+=+-77
-77+=+-77
OK


percentage/197461: An item which normally sells for $80 is on sale at a 20% discount. The sale price of the item is
1) $100
2) $16
3) $60
4) $64
1 solutions

Answer 148089 by josmiceli(9817) About Me  on 2009-05-23 22:04:46 (Show Source):
You can put this solution on YOUR website!
Let x= the sale price
x+=+80+-+.2%2A80
x+=+80+-+16
x+=+64
The sale price is $64


Equations/197479: Please help me solve this problem.
6/(15x) +7/75-2/(3x)
I think you should find the lcd which would be 75 I think but then I get confused with the x's. Thanks
1 solutions

Answer 148088 by josmiceli(9817) About Me  on 2009-05-23 22:00:38 (Show Source):
You can put this solution on YOUR website!
This has to equal something to solve. As it sits, it's not
even a problem. I'll pick a number for it to equal, say
6%2F%2815x%29+%2B7%2F75-2%2F%283x%29+=+1%2F25
The LCD is 75x
Multiply both sides by 75x
30+%2B+7x+-+50+=+3x
7x+-+20+=+3x
4x+=+20
x+=+5
check answer:
6%2F%2815%2A5%29+%2B7%2F75-2%2F%283%2A5%29+=+1%2F25
6%2F75+%2B+7%2F75+-+10%2F75+=+3%2F75
13%2F75+-+10%2F75+=+3%2F75
3%2F75+=+3%2F75
OK


Equations/197478: please help me solve the following problem. I get very confused with the letters instead of numbers as denominators. 1/a+2/b+3/c
1 solutions

Answer 148084 by josmiceli(9817) About Me  on 2009-05-23 21:37:36 (Show Source):
You can put this solution on YOUR website!
It has to equal something to solve it, like:
+1%2Fa%2B2%2Fb%2B3%2Fc+=+407
It can't be solved the way it is.
For an equation with 3 unknowns, you need
2 more equations to solve it.
If you know what any 2 of the unknowns are,
you can solve for the remaining one.
a+=+3
b+=+7
1%2F3+%2B+2%2F7+%2B+3%2Fc+=+407
Multiply both sides by 21c. The is the common denominator
7c+%2B+6c+%2B+63+=+407
13c+=+344
c+=+26.461


Quadratic_Equations/197469: Can someone help me with this problem: x^2 + 3/2x = 3
1 solutions

Answer 148080 by josmiceli(9817) About Me  on 2009-05-23 21:26:29 (Show Source):
You can put this solution on YOUR website!
+x%5E2+%2B+3%2F2x+=+3
Complete the square
x%5E2+%2B+%283%2F2%29%2Ax+%2B+%283%2F4%29%5E2+=+3+%2B+%283%2F4%29%5E2
x%5E2+%2B+%283%2F2%29%2Ax+%2B+9%2F16+=+48%2F16+%2B+9%2F16
The left side is a perfect square
%28x+%2B+%283%2F4%29%29%5E2+=+57%2F16
Take the square root of both sides
x+%2B+3%2F4+=++0+%2B-+sqrt%2857%29%2F4
x+=+%28-3+%2B+sqrt%2857%29%29+%2F+4
and
x+=+%28-3+-+sqrt%2857%29%29+%2F+4
---------------------
I checked one solution with pencil&paper
OK


Quadratic_Equations/196945: Find two numbers whose difference is 14 and whose product is a minimum. Be sure to use "let statement".
1 solutions

Answer 147938 by josmiceli(9817) About Me  on 2009-05-21 21:43:24 (Show Source):
You can put this solution on YOUR website!
Let the numbers be x and y
y+-+x+=+14
y+=+x+%2B+14
The product is x%2Ay
x%2Ay+=+x%2A%28x+%2B+14%29
x%2Ay+=+x%5E2+%2B+14x
The function f%28x%29+=+x%5E2+%2B+14x
Is a minimum when x+=+-b%2F%282a%29
a+=+1
b+=+14
x%5Bmin%5D+=+-14%2F2
x%5Bmin%5D+=+-7
y+=+x+%2B+14
y+=+-7+%2B+14
y+=+7
The numbers are 7 and -7
check:
The product is -49
If I change the numbers very slightly, what
happens to the product?
x+=+-6.9
y+=+x+%2B+14
y+=+-6.9+%2B+14
y+=+7.1
-6.9%2A7.1+=+-48.99
This gives me more confidence answer is right


Equations/197106: This question is from textbook
Seven inches are equivalent to 17.78 cm. Find the equation converting length in cm to length in inches. What is the length in inches of a 96.2 cm bar.
1 solutions

Answer 147921 by josmiceli(9817) About Me  on 2009-05-21 19:25:59 (Show Source):
You can put this solution on YOUR website!
Let c= length in cm
Let i= length in inches
For a direct relation:
c+=+k%2Ai where
k+=+17.78%2F7 cm/in
In terms of units only,
cm = (cm/in) x in
cm = cm
The equation is
c+=+%2817.78%2F7%29%2Ai


Average/197028: sir/madam
hello i have a question
In what ratio should water mixed with spirit costing $12 per liter so as to make a profit of 25% by selling the diluted liquid at $13.75
1 solutions

Answer 147714 by josmiceli(9817) About Me  on 2009-05-20 10:37:56 (Show Source):
You can put this solution on YOUR website!
I assume the diluted liquid is sold for $13.75 per liter
Let w =liters water in final mixture
Let s= liters of spirit in final mixture
13.75%2A%28w%2Bs%29 is the price of spirit in final mixture
12s is what the spirit cost originally
13.75%2A%28w%2Bs%29+=+1.25%2A12s
13.75w+%2B+13.75s+=+15s
13.75w+=+1.25s
w%2Fs+=+1.25%2F13.75




Radicals/197047: Simplify: 1/9 -5/2. which is one over nine with negative 5/2 exponent.
1 solutions

Answer 147713 by josmiceli(9817) About Me  on 2009-05-20 09:35:44 (Show Source):
You can put this solution on YOUR website!
%281%2F9%29%5E%28-5%2F2%29
%28%281%2F9%29%5E%281%2F2%29%29%5E%28-5%29%29
%281%2F3%29%5E%28-5%29
1%2F%281%2F3%29%5E5
1%2F%281%2F243%29
243 answer
check answer:
%281%2F9%29%5E%28-5%2F2%29+=+243
%281%2F9%29%5E%28-5%2F2%29+=+3%5E5
Multiply both sides by %281%2F9%29%5E%285%2F2%29
%281%2F9%29%5E%28-5%2F2%29%2A%281%2F9%29%5E%285%2F2%29+=+3%5E5%2A%281%2F9%29%5E%285%2F2%29
The left side is the same as a%5Eb+%2Aa%5E%28-b%29+=+a%5E0
and a%5E0+=+1
1+=+3%5E5%2A%281%2F9%29%5E%285%2F2%29
The right side is the same as a%5Ec%2Ab%5Ec+=+%28a%2Ab%29%5Ec
1+=+%283%2A%281%2F9%29%5E%281%2F2%29%29%5E5
1+=+%283%2A%281%2F3%29%29%5E5
1+=+1%5E5
1+=+1
OK


Polynomials-and-rational-expressions/196704: A chemist has 500 mL of a solution that is 60% acid. how much of a 30% solution must be added to make a solution that is 50% acid?
1 solutions

Answer 147437 by josmiceli(9817) About Me  on 2009-05-17 21:05:22 (Show Source):
You can put this solution on YOUR website!
given:
.6%2A500+=+300ml of acid
Let x= ml of solution to be added
.3x= ml of acid added
%28.6%2A500+%2B+.3x%29+%2F+%28500+%2B+x%29+=+.5
Multiply both sides by 500+%2B+x
300+%2B+.3x+=+.5%2A%28500+%2B+x%29
300+%2B+.3x+=+250+%2B+.5x
.2x+=+50
x+=+250 ml
250 ml of a 30% solution must be added
check:
%28.6%2A500+%2B+.3x%29+%2F+%28500+%2B+x%29+=+.5
%28.6%2A500+%2B+.3%2A250%29+%2F+%28500+%2B+250%29+=+.5
%28300+%2B+75%29+%2F+750+=+.5
375+=+.5%2A750
375+=+375
OK


Word_Problems_With_Coins/196511: In Canada, $1 and $2 bills have been replaced by coins. When Marissa returned home to San Fran from a trip to Canada, she found that she had acquired 37 of these coins, with a total value of 51 canadian dollars. How many coins of each denomination did she have?
1 solutions

Answer 147295 by josmiceli(9817) About Me  on 2009-05-16 00:01:18 (Show Source):
You can put this solution on YOUR website!
Let a= the number of $1 coins she has
Let b= the number of $2 coins she has
given:
a+%2B+b+=+37
1%2Aa+%2B+2%2Ab+=+51
Subtract the 1st equation from the 2nd
1%2Aa+%2B+2%2Ab+=+51
-a+-+b+=+-37
b+=+14
And, since
a+%2B+b+=+37
a+%2B+14+=+37
a+=+37+-+14
a+=+23
She has 23 $1 coins and 14 $2 coins
check:
a+%2B+b+=+37
23+%2B+14+=+37
37+=+37
OK
a+%2B+2b+=+51
23+%2B+28+=+51
51+=+51
OK


Quadratic_Equations/196540: Solve by completing the square:
x^2 + 8x + 13 = 0
1 solutions

Answer 147294 by josmiceli(9817) About Me  on 2009-05-15 23:41:42 (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+8x+%2B+13+=+0
x%5E2+%2B+8x+=+-13
x%5E2+%2B+8x+%2B+%288%2F2%29%5E2+=+-13+%2B+%288%2F2%29%5E2
x%5E2+%2B+8x+%2B+16+=+-13+%2B+16
The left side is a perfect square
%28x+%2B+4%29%5E2+=+3
Take the square root of both sides
x+%2B+4+=+sqrt%283%29
x+=+14+%2B+sqrt%283%29
and
x+%2B+4+=+-sqrt%283%29
x+=+-4+-+sqrt%283%29
I'll check the 2nd result
x%5E2+%2B+8x+%2B+13+=+0
%28-4+-+sqrt%283%29%29%5E2+%2B+8%2A%28-4+-sqrt%283%29%29+%2B+13+=+0
16+%2B+8%2Asqrt%283%29+%2B+3+-+32+-+8%2Asqrt%283%29+%2B+13+=+0
16+%2B+3+-+32+%2B+13+=+0
0+=+0
OK


Miscellaneous_Word_Problems/196339: respected sir,
1] After paying a 10 percent tax on all income over $3,000, a person had a net income of $12,000. What was the income before taxes?
plz solve my doubt as soon as possible..waiting for yur reply........
thanks
binita
1 solutions

Answer 147253 by josmiceli(9817) About Me  on 2009-05-15 00:03:15 (Show Source):
You can put this solution on YOUR website!
Let the income before taxes = x
The income after taxes will then be x+-+.1%2A%28x+-+3000%29
The problem says the income after taxes is 12000, so
x+-+.1%28x+-+3000%29+=+12000
x+-+.1x+%2B+300+=+12000
.9x+=+12000+-+300
.9x+=+11700
x+=+13000
The income before taxes was $13,000


Exponents-negative-and-fractional/196370: This question is from textbook algebra structure and method
Can you please help me solve and leave in simplest radical form the following: (((x^2+8x= -16)))
1 solutions

Answer 147250 by josmiceli(9817) About Me  on 2009-05-14 23:51:47 (Show Source):
You can put this solution on YOUR website!
x%5E2%2B8x=+-16
Using the complete the square method:
x%5E2+%2B+8x+%2B+%288%2F2%29%5E2+=+-16+%2B+%288%2F2%29%5E2
The left side is a perfect square
%28x+%2B+4%29%5E2+=+-16+%2B+16
%28x+%2B+4%29%5E2+=+0
x+%2B+4+=+0
x+=+-4
This is a double root at x+=+-4
I'll plot the function
+graph%28+300%2C+300%2C+-10%2C+1%2C+-1%2C+10%2C++x%5E2+%2B+8x+%2B+16%29+


Exponents-negative-and-fractional/196373: This question is from textbook algebra structure and method
Can you please help me solve the following by using the quadratic formula and leave irrational roots in the simplest radical form:2x^2-3x+1=0)))
1 solutions

Answer 147246 by josmiceli(9817) About Me  on 2009-05-14 23:39:21 (Show Source):
You can put this solution on YOUR website!
2x%5E2+-+3x+%2B+1=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a+=+2
b+=+-3
c+=+1
x+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%2A2%2A1+%29%29%2F%282%2A2%29+
x+=+%28+3+%2B-+sqrt%28+9+-+8+%29%29%2F+4+
x+=+%28+3+%2B-+1%29%2F+4+
x+=+1
x+=+1%2F2
If you plug these values into equation,
they both check OK


Travel_Word_Problems/196230: The track team ran to the cemetary at 8mph and jogged back home at 6mph. If the total trip took 7 hours, how far was it to the cemetary?
1 solutions

Answer 147091 by josmiceli(9817) About Me  on 2009-05-13 16:38:40 (Show Source):
You can put this solution on YOUR website!
Let d = the one-way distance to the cemetary in miles
If d+=+r%2At, then
t+=+d%2Fr
d%2F8+%2B+d%2F6+=+7
Multiply both sides by 48
6d+%2B+8d+=+7%2A48
14d+=+336
d+=+24
It is 24 miles to the cemetary


Equations/196219: Hello.
I'm having some difficulty figuring out the following word problem, Can you help me?
A bottle contains 650 mL of fruit punch with a concentration of 50% pure fruit juice. Jill drinks 100 mL of the punch and then refills the bottle with an equal amount of a cheaper brand of punch. If the concentration of juice in the bottle is now reduced to 48%, what was the concentration in the punch that Jill added?
1 solutions

Answer 147090 by josmiceli(9817) About Me  on 2009-05-13 16:34:27 (Show Source):
You can put this solution on YOUR website!
If Jill drinks some of the 50% pure fruit juice,
what she drinks has that same concentration
and what is left has that same concentration
What is left is:
650+-+100+=+550 ml of 50% pure fruit juice
She filled up the bottle, replacing what she drank
with cheaper drink with 100 ml of unknown
concentration fruit juice.
Let x = the ml of pure juice in the cheaper drink
In words, I need to write this equation:
(ml of pure juice I end up with)/(total ml of punch) = 48%
%28.5%2A550+%2B+x%29+%2F+650+=+.48
+275+%2B+x+=+.48%2A650
x+=+312+-+275
x+=+37 ml
Now the question is: How much of the cheap drink added was water?
There was 550 ml in the bottle before she added it
She added 37 ml of pure juice, so
550+%2B+37+=+587
The rest of the 650 ml bottle must have been water
650+-+587+=+63ml
And the concentration of the cheap drink was
37%2F%2837+%2B+63%29+=+37%2F100
37% is the answer
check: does the fruit drink + water add up to 650?
fruit drink:
275+%2B+37
water:
275+%2B+63
275+%2B+37+%2B+275+%2B+63+=+650
OK


Money_Word_Problems/196226: In the period of a year, an investor lost twice as much as he gained. If he originally had $10,000 , and he now has 8,000, what amount did he gain and what amount did he lose.
My daughter and I have been working ont his but I am quite sure that we are not getting the right answer and we are totally stumped!
I hope someone can help!!!!
She is thinking gain of 2000 and loss of 4000- that seems wrong but who knows...
I think our minds are blown at this point
Please Help!!
1 solutions

Answer 147086 by josmiceli(9817) About Me  on 2009-05-13 15:54:00 (Show Source):
You can put this solution on YOUR website!
Let g= the amount he gained
Then 2g will be the amount he lost
given:
10000+%2B+g+-+2g+=+8000
10000+-+g+=+8000
-g+=+-+2000
g+=+2000
2g+=+4000
He gained $2,000 and lost $4,000
check:
10000+%2B+2000+-+4000+=+8000
12000+-+4000+=+8000
8000+=+8000
OK - I think your daughter was right


Radicals/196224: Can someone please help me Simplify or reduce these Radicals
root%283%2C24x%5E5y%5E3%29
Please help me I do Appreciate it
1 solutions

Answer 147083 by josmiceli(9817) About Me  on 2009-05-13 15:46:44 (Show Source):
You can put this solution on YOUR website!
What you have is the cube root of 24x%5E5%2Ay%5E3
If I say a%2Aa%2Aa+=+24x%5E5%2Ay%5E3, then
a+=+%2824x%5E5%2Ay%5E3%29%5E%281%2F3%29
I can also say


%2824x%5E5%2Ay%5E3%29%5E%281%2F3%29+=+3%5E%281%2F3%29%2Ax%5E%285%2F3%29%2A2y
%2824x%5E5%2Ay%5E3%29%5E%281%2F3%29+=+%283x%5E5%29%5E%281%2F3%29%2A2y


Mixture_Word_Problems/196090: Ten liters of a 4% acid solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?
1 solutions

Answer 147068 by josmiceli(9817) About Me  on 2009-05-13 10:34:11 (Show Source):
You can put this solution on YOUR website!
Let x= liters of 10% acid solution needed
In words:
(liters of acid in final solution)/(total liters of solution) = 6%
%28.04%2A10+%2B+.1x%29+%2F+%2810+%2B+x%29+=+.06
Multiply both sides by 10+%2B+x
.4+%2B+.1x+=+.06%2A%2810+%2B+x%29
.4+%2B+.1x+=+.6+%2B+.06x
.04x+=+.6+-+.4
.04x+=+.2
x+=+5
5 liters of 10% acid solution are needed
check answer:
.4+%2B+.1%2A5+=+.06%2A%2810+%2B+5%29
.4+%2B+.5+=+.06%2A15
.9+=+.9
OK


Linear_Equations_And_Systems_Word_Problems/196141: A chemist has three samples of unknown mass. Each pair of the samples is balanced against the third sample and one of the three known masses. Find the unknown masses if the known ones are 9 g, 15 g, and 27 g.
1 solutions

Answer 147054 by josmiceli(9817) About Me  on 2009-05-13 02:42:03 (Show Source):
You can put this solution on YOUR website!
Let the unknown masses be a, b, and c
a+%2B+b+=+c+%2B+9
b+%2B+c+=+a+%2B+15
c+%2B+a+=+b+%2B+27
From those I get:
a+%2B+b+-+c+=+9
-a+%2B+b+%2B+c+=+15
a+-+b+%2B+c+=+27
Adding the 1st two:
2b+=+24
b+=+12
Adding the 2nd two:
2c+=+42
c+=+21
And from the 1st:
a+%2B+b+-+c+=+9
a+%2B+12+-+21+=+9
a+%2B+12+=+30
a+=+18
The unknown masses are 18g, 12g, and 21g


Finite-and-infinite-sets/196165: Determine the vertex (h,k) of f%28x%29=+%28x-4%29%5E2-1
I am supposed to find the x intercept(s), y intercept(s) and graph the function.
Thank you in advance for your help.
1 solutions

Answer 147053 by josmiceli(9817) About Me  on 2009-05-13 02:29:12 (Show Source):
You can put this solution on YOUR website!
Any value I pick for x except x+=+4
will give me a value for f%28x%29 which is
greater than -1 by some amount, so
(4, -1) is a minimum vertex.
The x-intercept is where f%28x%29=0
f%28x%29=+%28x-4%29%5E2-1
0+=+%28x-4%29%5E2+-+1
x=5
x=3
The x-intercepts are (5,0) and (3,0)
The y-intercept is where x=0
f%28x%29=+%28x-4%29%5E2-1
f%28x%29=+%280-4%29%5E2-1
f%28x%29=+15
The y-intercept is at (0,15)
Here's the plot:
+graph%28+500%2C+500%2C+-2%2C+10%2C+-2%2C+20%2C+%28x-4%29%5E2+-+1%29+


Finance/196180: This question is from textbook
Three-fifths of the men in chemistry class have beards and two-thirds of the women have long hair. If there are 120 men in the class and 46 are not in the above groups, how many men and how many women are there in the class?
I have the answer but I can't figure out how to get it. I've done it a zillion different ways and get nothing close.
1 solutions

Answer 147051 by josmiceli(9817) About Me  on 2009-05-13 01:58:57 (Show Source):
You can put this solution on YOUR website!
If there are 120 men in the class, and 3/5 have beards,
then .6%2A120+=+72 have beards.
The remaining 120+-+72+=+48 do not have beards
There are already 48 who are not in one of the bearded
or long-haired groups, so 46 is too low. Was there a
misprint or copy error?


Linear_Equations_And_Systems_Word_Problems/196171: In a family there are two cars. The sum of the average miles per gallon obtained by the two cars in a particular week is 45. The first car has consumed 40 gallons during that week, and the second car has consumed 20 gallons, for a total of 1400 miles driven by the two cars combined. What was the average gas mileage obtained by each of the two cars that week?
1 solutions

Answer 147050 by josmiceli(9817) About Me  on 2009-05-13 01:49:16 (Show Source):
You can put this solution on YOUR website!
Let a= the average mpg for the 1st car
Let b= the average mpg for the 2nd car
given:
(1) a+%2B+b+=+45 mi/gal
(2) 40a+%2B+20b+=+1400 mi
Multiply both sides of (1) by 20
and subtract (1) from (2)
40a+%2B+20b+=+1400
-20a+-20b+=+-900
20a+=+500
a+=+25 mi/gal
and
(1) a+%2B+b+=+45
25+%2B+b+=+45
b+=+45+-+25
b+=+20 mi/gal
The 1st car got 25 mpg and the 2nd car got 20 mpg