New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'josmiceli'
josmiceli answered: 9815 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839, >>NextMoney_Word_Problems/197937: .} Recovering an investment. The manager at Cream of the Crop bought a load of watermelons for $200. She priced the melons so that she would make $1.50 profit on each melon. When all but 30 had been sold, the manager had recovered her initial investment. How many did she buy originally? 1 solutions
Answer 148427 by josmiceli(9817) on 2009-05-27 10:13:41 (Show Source):
|
Linear_Equations_And_Systems_Word_Problems/197922: A B and C can finish a job in 6 days. If B and C work together the job will take 9 days. If A and C work together the job will take 8 days. In how many days can each man working alone do the job? 1 solutions
Answer 148407 by josmiceli(9817) on 2009-05-27 00:27:14 (Show Source):
You can put this solution on YOUR website!I will say the following:
A's rate of working is (1 job)/(a days)
B's rate of working is (1 job)/{b days)
C's rate of working is (1 job)/(c days)
---------------------------------------
I can add their rates of working to get a
rate at which they work together
(1)
(2) 
(3) 
-------------------------
From (2)

From (3)

Substitute these into (1)
(1)

Multiply both sides by

From (2)
(2)

From (3)
(3)

A can do the job in 18 days
B can do the job in 24 days
C can do the job in 14.4 days
check answer:
(1)

Multiply both sides by

OK
(2)

Multiply both sides by

OK
(3)

Multiply both sides by

OK
|
Equations/197753: A math teacher collects old books. One day, a student asked him how many old math books he has. He replied, "If I divide the books into unequal whole numbers, then 64 times the difference between the two numbers equals the difference between the squares of the two numbers." How many old math books does the teacher have? 1 solutions
Answer 148404 by josmiceli(9817) on 2009-05-26 23:31:17 (Show Source):
You can put this solution on YOUR website!Call the larger number 
Call the smaller number 
given:

I now know that the sum of the numbers is 
I can think of the right side of the equation as
(hypotenuse)^2 - (one leg)^2 of a right triangle
where  is the hypotenuse and  is the leg
The left side of the equation must be 
where 
From above,  , so
 must be a whole number, since the right side
of the original equation is a whole number
That means that  must be a whole number
Note that if  , then  and
 ,  ,  and that is
not allowed by the problem.
So 
I'll try

Not allowed, since  has to be a whole number
I'll try

So,

---------------

The teacher had 64 old math books
|
Polynomials-and-rational-expressions/197872: A rectangular pen has a length of 3 feet greater than its width. If both dimensions are increased by 5 feet, which expression gives the resulting increase in area?
a. 10x + 40
b. 13x + 40
c. x2 + 13x + 40
d. x2 + 10x =40
My attempt: area = length x width
original pen would be x(x+3)=x2+3x
new pen would be (x+5)(x+8)=x2+13x+40
However answer sheet says correct answer is A.
Thank you 1 solutions
Answer 148395 by josmiceli(9817) on 2009-05-26 22:33:52 (Show Source):
You can put this solution on YOUR website!What they're asking for is: "How much bigger
is the 2nd pen than the 1st?
So, in words
Difference = (area of 2nd pen) - (area of 1st pen)
|
percentage/197461: An item which normally sells for $80 is on sale at a 20% discount. The sale price of the item is
1) $100
2) $16
3) $60
4) $64 1 solutions
Answer 148089 by josmiceli(9817) on 2009-05-23 22:04:46 (Show Source):
|
Equations/197479: Please help me solve this problem.
6/(15x) +7/75-2/(3x)
I think you should find the lcd which would be 75 I think but then I get confused with the x's. Thanks 1 solutions
Answer 148088 by josmiceli(9817) on 2009-05-23 22:00:38 (Show Source):
|
Equations/197478: please help me solve the following problem. I get very confused with the letters instead of numbers as denominators. 1/a+2/b+3/c 1 solutions
Answer 148084 by josmiceli(9817) on 2009-05-23 21:37:36 (Show Source):
You can put this solution on YOUR website!It has to equal something to solve it, like:

It can't be solved the way it is.
For an equation with 3 unknowns, you need
2 more equations to solve it.
If you know what any 2 of the unknowns are,
you can solve for the remaining one.

Multiply both sides by  . The is the common denominator
|
Equations/197106: This question is from textbook
Seven inches are equivalent to 17.78 cm. Find the equation converting length in cm to length in inches. What is the length in inches of a 96.2 cm bar. 1 solutions
Answer 147921 by josmiceli(9817) on 2009-05-21 19:25:59 (Show Source):
You can put this solution on YOUR website!Let  = length in cm
Let  = length in inches
For a direct relation:
 where
 cm/in
In terms of units only,
cm = (cm/in) x in
cm = cm
The equation is
|
Average/197028: sir/madam
hello i have a question
In what ratio should water mixed with spirit costing $12 per liter so as to make a profit of 25% by selling the diluted liquid at $13.75 1 solutions
Answer 147714 by josmiceli(9817) on 2009-05-20 10:37:56 (Show Source):
You can put this solution on YOUR website!I assume the diluted liquid is sold for $13.75 per liter
Let  =liters water in final mixture
Let  = liters of spirit in final mixture
 is the price of spirit in final mixture
 is what the spirit cost originally
|
Word_Problems_With_Coins/196511: In Canada, $1 and $2 bills have been replaced by coins. When Marissa returned home to San Fran from a trip to Canada, she found that she had acquired 37 of these coins, with a total value of 51 canadian dollars. How many coins of each denomination did she have? 1 solutions
Answer 147295 by josmiceli(9817) on 2009-05-16 00:01:18 (Show Source):
|
Equations/196219: Hello.
I'm having some difficulty figuring out the following word problem, Can you help me?
A bottle contains 650 mL of fruit punch with a concentration of 50% pure fruit juice. Jill drinks 100 mL of the punch and then refills the bottle with an equal amount of a cheaper brand of punch. If the concentration of juice in the bottle is now reduced to 48%, what was the concentration in the punch that Jill added? 1 solutions
Answer 147090 by josmiceli(9817) on 2009-05-13 16:34:27 (Show Source):
You can put this solution on YOUR website!If Jill drinks some of the 50% pure fruit juice,
what she drinks has that same concentration
and what is left has that same concentration
What is left is:
 ml of 50% pure fruit juice
She filled up the bottle, replacing what she drank
with cheaper drink with  ml of unknown
concentration fruit juice.
Let  = the ml of pure juice in the cheaper drink
In words, I need to write this equation:
(ml of pure juice I end up with)/(total ml of punch) = 48%
 ml
Now the question is: How much of the cheap drink added was water?
There was  ml in the bottle before she added it
She added  ml of pure juice, so

The rest of the  ml bottle must have been water
 ml
And the concentration of the cheap drink was

37% is the answer
check: does the fruit drink + water add up to 650?
fruit drink:

water:

OK
|
Finance/196180: This question is from textbook
Three-fifths of the men in chemistry class have beards and two-thirds of the women have long hair. If there are 120 men in the class and 46 are not in the above groups, how many men and how many women are there in the class?
I have the answer but I can't figure out how to get it. I've done it a zillion different ways and get nothing close. 1 solutions
Answer 147051 by josmiceli(9817) on 2009-05-13 01:58:57 (Show Source):
You can put this solution on YOUR website!If there are 120 men in the class, and 3/5 have beards,
then  have beards.
The remaining  do not have beards
There are already 48 who are not in one of the bearded
or long-haired groups, so 46 is too low. Was there a
misprint or copy error?
|
Linear_Equations_And_Systems_Word_Problems/196171: In a family there are two cars. The sum of the average miles per gallon obtained by the two cars in a particular week is 45. The first car has consumed 40 gallons during that week, and the second car has consumed 20 gallons, for a total of 1400 miles driven by the two cars combined. What was the average gas mileage obtained by each of the two cars that week? 1 solutions
Answer 147050 by josmiceli(9817) on 2009-05-13 01:49:16 (Show Source):
You can put this solution on YOUR website!Let  = the average mpg for the 1st car
Let  = the average mpg for the 2nd car
given:
(1)  mi/gal
(2)  mi
Multiply both sides of (1) by 20
and subtract (1) from (2)
 mi/gal
and
(1)
 mi/gal
The 1st car got 25 mpg and the 2nd car got 20 mpg
|
|