See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'josmiceli'

josmiceli answered: 9658 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659, >>Next

Miscellaneous_Word_Problems/659054: Two sailboats are 9.8 miles apart and sailing toward each other. The larger boat sails 4 miles per hour faster than the smaller boat. The two boats pass each other after 0.7 hour. Find the speed of each boat.
1 solutions

Answer 410621 by josmiceli(9661) About Me  on 2012-09-29 20:24:50 (Show Source):
You can put this solution on YOUR website!
You can think of one boat as standing
still and the other approaching at the
sum of their speeds.
Let +s+ = the speed of the smaller boat
+s+%2B+4+ = the speed of the larger boat
-------------
+9.8+=+%28+s+%2B+s+%2B+4+%29%2A.7+
+9.8+=+1.4s++%2B+2.8+
+1.4s+=+7+
+s+=+5+
+s+%2B+4+=+9+
The speed of the smaller boat is 5 mi/hr
The speed of the larger boat is 9 mi/hr


Miscellaneous_Word_Problems/659057: Paul and Donna Petrie invested $12,000 part at 5% simple interest and the rest a 7% simple interest for a period of 1 year. How much did they invest at each rate if their total annual interest from both investments was $800? (Use interest= principal x rate x time.)
1 solutions

Answer 410616 by josmiceli(9661) About Me  on 2012-09-29 20:12:07 (Show Source):
You can put this solution on YOUR website!
interest= principal x rate x time
Let +x+ = amount invested at 5%
+12000+-+x+ = amount invested at 7%
+I%5B1%5D+=+x%2A.05%2A1+
+I%5B1%5D+=+.05x+
--------------
+I%5B2%5D+=+%28+12000+-+x+%29%2A.07%2A1+
+I%5B2%5D+=+840+-+.07x+
-------------------
+I%5B1%5D+%2B+I%5B2%5D+=+800+
+.05x+%2B+840+-+.07x+=+800+
+-.02x+=+-40+
+x+=+2000+
+12000+-+x+=+12000+-+2000+
+12000+-+x+=+10000+
$2,000 = amount invested at 5%
$10,000 = amount invested at 7%


Mixture_Word_Problems/658959: Suppose that you have a supply of a 40% solution of alcohol and a 60% solution of alcohol. How many quarts of each should be mixed to produce 90 quarts that is 50% alcohol?

1 solutions

Answer 410571 by josmiceli(9661) About Me  on 2012-09-29 15:59:46 (Show Source):
You can put this solution on YOUR website!
Let a = quarts of 40% solution needed
Let b = quarts of 60% solution needed
given:
(1) +a+%2B+b+=+90+
(2) +%28+.4a+%2B+.6b+%29+%2F+90+=+.5+
--------------------------
(2) +.4a+%2B+.6b+=+.5%2A90+
(2) +.4a+%2B+.6b+=+45+
(2) +4a+%2B+6b+=+450+
--------------------
Multiply both sides of (1) by +4+
and subtract (1) from (2)
(2) +4a+%2B+6b+=+450+
(1) +-4a+-+4b+=+-360+
+2b+=+90+
+b+=+45+
and, since
(1) +a+%2B+b+=+90+
(1) +a+%2B+45+=+90+
(1) +a+=+45+
45 quarts of 40% solution are needed
45 quarts of 60% solution are needed
check:
(2) +%28+.4%2A45+%2B+.6%2A45+%29+%2F+90+=+.5+
(2) +%28+18+%2B+27+%29+%2F+90+=+.5+
(2) +45+%2F+90+=+.5+
(2) +45+=+.5%2A90+
(2) +45+=+45+
OK


Linear-equations/658968: Where does the equations y=-6x+30 and y=3x-6 intersect? I need the solution. Please HELP ME RIGHT AWAY!
1 solutions

Answer 410568 by josmiceli(9661) About Me  on 2012-09-29 15:49:00 (Show Source):
You can put this solution on YOUR website!
Hi
These equations are in the slope-intercept form.
I would put them into the standard form which
looks like +ax+%2B+by+=+c+
+y+=+-6x+%2B+30+
Add +6x+ to both sides
(1) +6x+%2B+y+=+30+
and
+y=3x-6+
Subtract +y+ from both sides
+0+=+3x+-+y+-+6+
Add +6+ to both sides
+6+=+3x+-+y+
Now write it the other way around
(2) +3x+-+y+=+6+
Add equations (1) and (2)
(1) +6x+%2B+y+=+30+
(2) +3x+-+y+=+6+
+9x+=+36+
+x+=+4+
Now plug this result back into (1) or (2)
(1) +6%2A4+%2B+y+=+30+
(1) +24+%2B+y+=+30+
(1) +y+=+30+-+24+
(1) +y+=+6+
The intersection is at ( 4,6 )
Here's the plot:
+graph%28+400%2C+400%2C+-4%2C+10%2C+-4%2C+10%2C+-6x+%2B+30%2C+3x+-+6+%29+


logarithm/658889: knowing that log10((x+y)/3)=1/2(log10(x)+log10(y)) determine the value for x/y
P.S - the 3 is inside the log and the log base is 10.
1 solutions

Answer 410542 by josmiceli(9661) About Me  on 2012-09-29 12:38:36 (Show Source):
You can put this solution on YOUR website!
++log%28+%28x%2By%29%2F3+%29+=+%281%2F2%29%2A%28+log%28x%29+%2B+log%28y%29+%29+
++log%28+%28x%2By%29%2F3+%29+=+%281%2F2%29%2A%28+log%28x%2Ay%29+%29+
++log%28+%28x%2By%29%2F3+%29+=++log%28sqrt%28x%2Ay%29%29++
+%28+x+%2B+y+%29+%2F+3+=+sqrt%28+x%2Ay+%29+
Square both sides
+%28+x+%2B+y+%29%5E2+%2F+9+=+x%2Ay+
++x%5E2+%2B+2x%2Ay+%2B+y%5E2++=+9x%2Ay+
+x%5E2+%2B+y%5E2+=+7x%2Ay+
Divide both sides by +y%5E2+
++%28x%2Fy%29%5E2+%2B+1++=+7%2A%28x%2Fy%29+
Solve for +x%2Fy+ Have to run.
Hope I got it.




Mixture_Word_Problems/658888: A tank holds 140 liters of checmical solution. Currently the solution has a strength of 60%. How much of this should be drained and replaced with 100% solution to get a final strength of 80%?
1 solutions

Answer 410540 by josmiceli(9661) About Me  on 2012-09-29 12:10:54 (Show Source):
You can put this solution on YOUR website!
For clarity, I'll just suppose the solution
is water plus antifreeze, so it's 60%
antifreeze.
--------------------
given:
+.6%2A140+=+84+ liter of antifreeze in 60% solution
Let +x+ = liters of 60% antifreeze to be drained
and repaced with 100% antifreeze
( note there is 140 liters when you start
and 140 liters when you finish )
--------------------
+%28+84+-+.6x+%2B+x+%29+%2F+140+=+.8+
+84+%2B+.4x+=+.8%2A140+
+84+%2B+.4x+=+112+
+.4x+=+28+
+x+=+70+
70 liters of solution must be drained and
replaced with 100% solution


Travel_Word_Problems/658752: an airplane flew in a direct line from its base at the rate of 300 miles an hour and returned over the same route at the rate of 250 miles an hour, requiring 15 minutes longer on the return trip. how far from its base did it fly?
1 solutions

Answer 410463 by josmiceli(9661) About Me  on 2012-09-28 21:46:50 (Show Source):
You can put this solution on YOUR website!
Let +t+ = time for 1st trip
Let +d+ = distance from base
Equation for 1st trip
(1) +d+=+300t+
Equation for 2nd trip:
(2) +d+=+250%2A%28+t+%2B+1%2F4+%29+
------------------------
Substitute (1) into (2)
(2) +300t+=+250%2A%28+t+%2B+1%2F4+%29+
(2) +300t+=+250t+%2B+250%2F4+
(2) +6t+=+5t+%2B+5%2F4+
(2) +t+=+5%2F4+
-------------
(1) +d+=+300%2A%285%2F4%29+
(1) +d+=+75%2A5+
(1) +d+=+375+
It flew 375 mi from base
check:
(2) +375+=+250%2A%28+t+%2B+1%2F4+%29+
(2) +3+=+2%2A%28+t+%2B+1%2F4+%29+
(2) +3+=+2t+%2B+1%2F2+
(2) +2t+=+5%2F2+
(2) +t+=+5%2F4+
OK



Age_Word_Problems/658400: Taylor is half as old as his father. Next year, their ages will total 62. How old is each now?
1 solutions

Answer 410274 by josmiceli(9661) About Me  on 2012-09-27 22:06:25 (Show Source):
You can put this solution on YOUR website!
+t+=+%281%2F2%29%2Ad+
+t+%2B+1++%2B+d+%2B+1+=+62+
----------------------
+t+%2B+d+=+60+
By substitution:
+%281%2F2%29%2Ad+%2B+d+=+60+
+d+%2B+2d+=+120+
+3d+=+120+
+d+=+40+
and
+t+=+%281%2F2%29%2Ad+
+t+=+%281%2F2%29%2A40+
+t+=+20+
Taylor is 20
Dad is 40
----------
check:
Next year
Taylor is 21
Dad is 41
+21+%2B+41+=+62+
OK


Linear_Algebra/658385: Paula is 12 years older than her brother Bob.Four years from now Bob will be two thirds as old as Paula. how old are they now ?
1 solutions

Answer 410271 by josmiceli(9661) About Me  on 2012-09-27 21:57:30 (Show Source):
You can put this solution on YOUR website!
Let +p+ = Paula's age now
Let +b+ = Bob's age now
given:
(1) +p+=+b+%2B+12+
(2) +b+%2B+4+=+%282%2F3%29%2A%28+p+%2B+4+%29+
---------------------------
(2) +3b+%2B+12+=+2p+%2B+8+
(2) +2p+-+3b+=+4+
Substitute (1) into (2)
(2) +2%2A%28+b+%2B+12+%29+-+3b+=+4+
(2) +2b+%2B+24+-+3b+=+4+
(2) +-b+=+-20+
(2) +b+=+20+
and
(1) +p+=+b+%2B+12+
(1) +p+=+20+%2B+12+
(1) +p+=+32+
Paula is 32
Bob is 20
------------
check:
In 4 years Paula is 36
In 4 years Bob is 24
+24+=+%282%2F3%29%2A36+
Divide both sides by 12
+2+=+%282%2F3%29%2A3+
+2%2F3+=+2%2F3+
OK


Word_Problems_With_Coins/658393: Anna has $4.00 in change. If she has 5 quarters what is the maximum numbers of dimes that she can have

1 solutions

Answer 410269 by josmiceli(9661) About Me  on 2012-09-27 21:46:08 (Show Source):
You can put this solution on YOUR website!
5 quarters = $1.25
$4.00 minus $1.25 = $2.75
If she has only 1 nickel, she can have
+27%2A.1+=+2.7+, or $2.70 which is
27 dimes, which is the maximum


Age_Word_Problems/658387: Dayna is 8 and her mother is 31. How long will it be before her mother is twice as old as she is?

1 solutions

Answer 410266 by josmiceli(9661) About Me  on 2012-09-27 21:40:55 (Show Source):
You can put this solution on YOUR website!
Add +x+ years to both their ages
given:
+31+%2B+x+=+2%2A%28+8+%2B+x+%29+
+31+%2B+x+=+16+%2B+2x+
+x+=+31+-+16+
+x+=+15+
In 15 years the Mother's age will be twice the Daughter's
check:
In 15 yrs Mother is 31 + 15 = 46
In 15 yrs Daughter is 8 + 15 = 23
46 is twice 23
OK


Mixture_Word_Problems/658364: how many liters of a 10% alcohol solution must be mixed with 70 liters of a 80% solution to get a 60% solution? can you show me how to solve it as well as the answer please?

1 solutions

Answer 410261 by josmiceli(9661) About Me  on 2012-09-27 21:10:56 (Show Source):
You can put this solution on YOUR website!
Let +x+ = liters of 10% alcohol solution needed
+.1x+ = liters of alcohol in 10% solution
+.8%2A70+=+56+ liters of alcohol in 80% solution
given:
+%28+.1x+%2B+56+%29+%2F+%28+x+%2B+70+%29+=+.6+
+.1x+%2B+56+=+.6%2A%28+x+%2B+70+%29+
+.1x+%2B+56+=+.6x+%2B+42+
+.5x+=+14+
+x+=+14%2F.5+
+x+=+28++
28 liters of 10% alcohol solution are needed
check:
+%28+.1x+%2B+56+%29+%2F+%28+x+%2B+70+%29+=+.6+
+%28+.1%2A28+%2B+56+%29+%2F+%28+28+%2B+70+%29+=+.6+
+%28+2.8+%2B+56+%29+%2F+98+=+.6+
+58.8+%2F+98+=+.6+
+58.8+=+.6%2A98+
+58.8+=+58.8+
OK


Equations/658332: A pet store bought a litter of puppies for $800. After selling all but 3 puppies in the litter their sales were $800. Each puppy was sold for $60 more than they paid for them. How many puppies were in the litter?
1 solutions

Answer 410259 by josmiceli(9661) About Me  on 2012-09-27 21:00:23 (Show Source):
You can put this solution on YOUR website!
Let +p+ = number of puppies in the litter
The store paid +800%2Fp+ for each puppy
They sold +p+-+3+ puppies
+800+%2F+%28+p+-+3+%29+ is the money received per puppy
+800+%2F+%28+p-3+%29+=+800%2Fp+%2B+60+
Multiply each side by +p%2A%28+p+-+3+%29+
+800p+=+800%2A%28+p+-+3+%29+%2B+60%2Ap%2A%28+p+-+3+%29+
+800p+=+800p+-+2400+%2B+60p%5E2+-+180p+
+60p%5E2+-+180p+-+2400+=+0+
+p%5E2+-+3p+-+40+=+0+
Looking at this, I can see
+%28+p+-+8+%29%2A%28+p+%2B+5+%29+=+0+
+p+=+8+ ( ignore the negative root )
There are 8 puppies in the litter
check:
They sold all but 3, which is 5 puppies
800/5 = $160 per puppy
160 - 60 = $100
This means they paid $100 for each of the 8 puppies
or $800
OK


Percentage-and-ratio-word-problems/658336: A trip to the White Mountains of New Hampshire from Boston will take you 2 3/4 hours. Assume you have traveled 1/11 of the way. How much longer will the trip take?

1 solutions

Answer 410256 by josmiceli(9661) About Me  on 2012-09-27 20:40:23 (Show Source):
You can put this solution on YOUR website!
Assuming a fixed speed, the distance traveled
is proportional to the time
I can set up the proportion
+1%2F11+=+t%2F2.75+
+2.75+=+11t+
+t+=+.25+ hrs
The time left is +2.75+-+.25+=+2.5+
The trip will take 2.5 hours longer


absolute-value/658270: If you have 2 math grades (88 and 94) and needed to get at least a 90 average, how would you solve this.
1 solutions

Answer 410235 by josmiceli(9661) About Me  on 2012-09-27 19:19:50 (Show Source):
You can put this solution on YOUR website!
You do have at least a 90% average
+%28+88+%2B+94+%29+%2F+2+=+182%2F2+
+182%2F2+=+91+
You have a 91% average


Travel_Word_Problems/658264: If Amy can run 3.5 miles in 40 minutes, about how many minutes would it take her to run 8 miles at the same rate?
Can you please show me the formula to work this out?
1 solutions

Answer 410231 by josmiceli(9661) About Me  on 2012-09-27 19:05:37 (Show Source):
You can put this solution on YOUR website!
+d+=+r+%2A+t+
+3.5+=+r%2A%28+40%2F60+%29+ ( time in hours )
+r+=+3.5%2A%283%2F2%29+
+r+=+5.25+ mi/hr
--------------
+8+=+5.25%2At+
+t+=+8+%2F+5.25+
+t+=+1.52381+ hrs
+.52381+%2F+60+=+31.4286+
+.4286+%2F+60+=+7.143+
It will take her
1 hr 31 min 7 sec


Linear_Equations_And_Systems_Word_Problems/658204: A roll of carpet 9 ft wide is 30 ft longer than a roll of carpet 15 ft wide. Both rolls have the same area. Make a sketch of the unrolled carpets and find the dimensions of each.
1 solutions

Answer 410225 by josmiceli(9661) About Me  on 2012-09-27 18:34:43 (Show Source):
You can put this solution on YOUR website!
Let +x+ = the length of the 15' wide carpet
given:
+x+%2B+30+ = the width of the 9' wide carpet
Area for each is length x width, so
+15x+=+9%2A%28+x+%2B+30+%29+
+15x+=+9x+%2B+270+
+6x+=+270+
+x+=+45+
+x+%2B+30+=+75+
The carpets are
15 x 45
and
9 x 75
-------
check:
+15%2A45+=+675+
+9%2A75+=+675+
OK








Inequalities/658021: A CHEMIST NEEDS TO MIX AN 18% ACID SOLUTION WITH A 45% ACID SOLUTION TO OBTAIN 12 GALLONS OF A 36% ACID SOLUTION. HOW MANY GALLONS OF EACH OF THE ACID SOLUTIONS MUST HE USE?

1 solutions

Answer 410113 by josmiceli(9661) About Me  on 2012-09-27 12:30:40 (Show Source):
You can put this solution on YOUR website!
Let +a+ = gallons of 18% solution needed
Let +b+ = gallons of 45% solution needed
given:
(1) +a+%2B+b+=+12+
(2) +%28+.18a+%2B+.45b+%29+%2F+12+=+.36+
-----------------------------
(2) +.18a+%2B+.45b+=+.36%2A12+
(2) +.18a+%2B+.45b+=+4.32+
(2) +18a+%2B+45b+=+432+
Multiply both sides of (1) by +18+
and subtract (1) from (2)
(2) +18a+%2B+45b+=+432+
(1) +-18a+-+18b+=+-216+
+27b+=+216+
+b+=+8+
and, since
(1) +a+%2B+b+=+12+
(1) +a+=+12+-+8+
(1) +a+=+4+
-------------
4 gallons of 18% solution are needed
8 gallons of 45% solution are needed
check:
(2) +%28+.18%2A4+%2B+.45%2A8+%29+%2F+12+=+.36+
(2) +%28+.72+%2B+3.6+%29+%2F+12+=+.36+
(2) +4.32+=+.36%2A12+
(2) +4.32+=+4.32+
OK


Age_Word_Problems/657990: The mother is 6 years more than three times older than her son. Four years ago, she was 5 times older as her son. How old is her son.
1 solutions

Answer 410108 by josmiceli(9661) About Me  on 2012-09-27 12:18:39 (Show Source):
You can put this solution on YOUR website!
Let +m+ = Mother's age no
Let +s+ = Son's age now
given:
(1) +m+=+3s+%2B+6+
(2) +m+-+4+=+5%2A%28+s+-+4+%29+
-----------------------
Substitute (1) into (2)
(2) +3s+%2B+6+-+4+=+5%2A%28+s+-+4+%29+
(2) +3s+%2B+2+=+5s+-+20+
(2) +2s+=+20+%2B+2+
(2) +2s+=+22+
(2) +s+=+11+
Son is 11
check:
(1) +m+=+3%2A11+%2B+6+
(1) +m+=+39+
and
(2) +39+-+4+=+5%2A%28+s+-+4+%29+
(2) +35+=+5s+-+20+
(2) +5s+=+55+
(2) +s+=+11+
OK


Money_Word_Problems/658002: An adult ticket for the fair (a) is 7 dollars more than a childs ticket which cost 5 dollars, if two adults and three children go to the fair how much will the tickets cost all together?
-how do i work this problem out and whats the answer
1 solutions

Answer 410106 by josmiceli(9661) About Me  on 2012-09-27 12:12:24 (Show Source):
You can put this solution on YOUR website!
given:
Child's ticket = $5
Adult's ticket = $5 + 7$
$5 + $7 = $12
2 adults tickets cost
+2%2A12+=+24+
3 child's tickets cost
+3%2A5+=+15+
and
+24+%2B+15+=+39+
All together the tickets cost $39


Equations/657799: what are the steps to getting the solutions of this equation 5a^2 - 10a = 0
1 solutions

Answer 410008 by josmiceli(9661) About Me  on 2012-09-26 22:40:59 (Show Source):
You can put this solution on YOUR website!
+5a%5E2+-+10a+=+0+
+5a%2A%28+a+-+2+%29+=+0+
The solutions are
+a+=+0+
+a+-+2+=+0+
+a+=+2+


Human-and-algebraic-language/657793: if a hen and a half lay an egg and a half, in a day and a half, how many eggs are laid by six hens in six days? show work to explain answer
1 solutions

Answer 410007 by josmiceli(9661) About Me  on 2012-09-26 22:36:46 (Show Source):
You can put this solution on YOUR website!
1.5 hens, 1.5 eggs, 1.5 days
------------------------
The same number of hens lay 4 times
as many eggs in 4 times as many days
1.5 hens, 6 eggs, 6 days
---------------------
4 times as many hens will lay 4 times as many
eggs in the same number of days
6 hens lay 24 eggs in 6 days



Mixture_Word_Problems/657787: apple pucker is 15% alcohol and vodka is 35% alcohol. how much of each should be mixed to make an 8 oz drink that is 30% alcohol
1 solutions

Answer 410004 by josmiceli(9661) About Me  on 2012-09-26 22:29:00 (Show Source):
You can put this solution on YOUR website!
Let +a+ = oz of pucker needed
Let +b+ = oz of vodka needed
given:
(1) +a+%2B+b+=+8+
(2) +%28+.15a+%2B+.35b+%29+%2F+8+=+.3+
---------------------------
(2) +.15a+%2B+.35b+=+2.4+
(2) +15a+%2B+35b+=+240+
(2) +3a+%2B+7b+=+48+
Multiply both sides of (1) by 3
and subtract (1) from (2)
(2) +3a+%2B+7b+=+48+
(1) +-3a+-+3b+=+-24+
+4b+=+24+
+b+=+6+
and
(1) +a+%2B+6+=+8+
(1) +a+=+2+
2 oz of pucker are needed
6 oz of vodka are needed
check:
(2) +%28+.15%2A2+%2B+.35%2A6+%29+%2F+8+=+.3+
(2) +%28+.3+%2B+2.1+%29+%2F+8+=+.3+
(2) +2.4+=+.3%2A8+
(2) +2.4+=+2.4+
OK


Angles/657781: The ratio of an angle to its supplement is 2:7. What is the ratio of the angle to its ratio to its complement?
PLEASE HELP ME ON THIS... T.T
1 solutions

Answer 410002 by josmiceli(9661) About Me  on 2012-09-26 22:14:16 (Show Source):
You can put this solution on YOUR website!
Let the angle = +a+
It's supplement = +180+-+a+
given:
+a+%2F+%28+180-a+%29+=+2%2F7+
+7a+=+2%2A%28+180+-+a+%29+
+7a+=+360+-+2a+
+9a+=+360+
+a+=+40+
----------
+a+%2F+%28+90+-+a+%29+=+40+%2F+%28+90+-+40+%29+
+a+%2F+%28+90+-+a+%29+=+4%2F5+ answer



Geometry_Word_Problems/657775: find a rectangle whose perimeter is 22' and has an area that is LARGER than 30'.i come up with 5w x 6l but only equals 30'??
1 solutions

Answer 409998 by josmiceli(9661) About Me  on 2012-09-26 22:05:20 (Show Source):
You can put this solution on YOUR website!
A square is a rectangle with equal side
Since +4%2A5.5+=+22+, and
Area = +5.5%5E2+=+30.25+
The rectangle is a square with sides
= 5.5'


Distributive-associative-commutative-properties/657397: what is the product of (7x+1/2) and (-10x-22)? i have gotten -70x squared -11 but my teacher told me that was incorrect and i dont know what im doing wrong.
1 solutions

Answer 409850 by josmiceli(9661) About Me  on 2012-09-26 13:46:20 (Show Source):
You can put this solution on YOUR website!
The rule is:
( a + b ) x ( c + d ) = ac + bc + ad + bd
You got the ac and the bd, but you
left out the bc and ad
++%287x%2B1%2F2%29%2A%28-10x-22%29+=+-70x%5E2+-5x+-154x+-+11+
+-70x%5E2+-+159x+-+11+
-------------------------
You can check by plugging in some value for x
I'll say +x+=+-1%2F2+
++%287x%2B1%2F2%29%2A%28-10x-22%29+=+%28-7%2F2+%2B+1%2F2%29%2A%285+-+22%29+
+%28-3%29%2A%28-17%29+=+51+
and, also
+-70x%5E2+-+159x+-+11+=+-70%2A%281%2F4%29+-+159%2A%28-1%2F2%29+-+11+
+-17+-+1%2F2+%2B+79+%2B+1%2F2+-+11+
+-17+%2B+79+-+11+=+79+-+28+
+79+-+28+=+51+
OK


Word_Problems_With_Coins/657388: P has pennies, dimes, and quarters. They add up to a total of $5.59. There are 43 coins and the number of quarters plus 9 equals the number of pennies and dimes. How many quarters? pennies? and dimes does P have?
1 solutions

Answer 409848 by josmiceli(9661) About Me  on 2012-09-26 13:34:13 (Show Source):
You can put this solution on YOUR website!
+p+ = number of pennies
+d+ = number of dimes
+q+ = number of quarters
given:
(1) +p+%2B+d+%2B+q+=+43+
(2) +p+%2B+10d+%2B+25q+=+559+ ( in cents )
(3) +q+%2B+9+=+p+%2B+d+
-------------------
Substitute (3) into (1)
(1) +q+%2B+9+%2B+q+=+43+
(1) +2q+=+34+
(1) +q+=+17+
-------------
(3) +17+%2B+9+=+p+%2B+d+
(3) +p+=+26+-+d+
Substitute this back into (2)
-----------------
(2) +26+-+d+%2B+10d+%2B+25%2A17+=+559+
(2) +26+%2B+9d+%2B+425+=+559+
(2) +9d+=+559+-+425+-+26+
(2) +9d+=+108+
(2) +d+=+12+
--------------
(1) +p+%2B+d+%2B+q+=+43+
(1) +p+%2B+12+%2B+17+=+43+
(1) +p+=+43+-+12+-+17+
(1) +p+=+14+
-------------
P has 14 pennies
12 dimes
17 quarters
-----------
check:
(2) +p+%2B+10d+%2B+25q+=+559+
(2) +14+%2B+10%2A12+%2B+25%2A17+=+559+
(2) +14+%2B+120+%2B+425+=+559+
(2) +559+=+559+
OK


Miscellaneous_Word_Problems/657386: I am working with these word Problem and what I believe the way to solve it but I don't end up with a whole number answer. What am I doing wrong?
Loretta owns a pet shop that specializes in exotic tropical fish. In April,Loretta doubled the number of fish she had on hand,and then sold 30 of them. In May,she tripled the number of fish she had on hand, and then sold 54 of them. In June, she quadrupled the number of fish she had, and then sold 72 of them. she now had 48 fish left. How many fish did she start with?
x=fish she started with
(2x-30)+(3x-54)+(4x-72)=48
Thank You for your help!
1 solutions

Answer 409844 by josmiceli(9661) About Me  on 2012-09-26 13:15:25 (Show Source):
You can put this solution on YOUR website!
She starts with x
Then 2x
Next +2x+-+30+
Then +3%2A%28+2x+-+30+%29+-+54+
Then +4%2A%28+3%2A%28+2x+-+30+%29+-+54+%29+-72+=+48+
+12%2A%282x+-+30%29+-+216+-+72+=+48+
+24x+-+360+-+216+-+72+=+48+
+24x+=+360+%2B+216+%2B+72+%2B+48+
+24x+=+696+
+x+=+29+
She started with 29 fish
check:
+29+
then +58+
then +58+-+30+=+28+
then +3%2A28+-+54+=+30+
then +4%2A30+-+72+=+48+
+120+-+72+=+48+
+48+=+48+
OK


Travel_Word_Problems/657324: Two children cross a startign line at the same time, one running with a velocity of +3.5 m/s and the other with a velocity of 4.0 m/s. How far apart are they after 12 seconds?
1 solutions

Answer 409813 by josmiceli(9661) About Me  on 2012-09-26 10:35:44 (Show Source):
You can put this solution on YOUR website!
First one's distance:
+d%5B1%5D+=+3.5%2A12+
+d%5B1%5D+=+42+ m
---------------
2nd one's distance:
+d%5B2%5D+=+4%2A12+
+d%5B2%5D+=+48+ m
---------------
+d%5B2%5D+-+d%5B1%5D+=+48+-+42+
+48+-+42+=+6+
They are 6 m apart after 12 sec


Age_Word_Problems/657315: Loretta age in 19 years will be three times what it was 15 years ago. How old is Loretta now

1 solutions

Answer 409812 by josmiceli(9661) About Me  on 2012-09-26 10:31:56 (Show Source):
You can put this solution on YOUR website!
Let +x+ = Loretta's age now
+x+%2B+19+ = Loretta's age in 19 years
+x+-+15+ = Loretta's age 15 years ago
given:
+x+%2B+19+=+3%2A%28+x+-+15+%29+
+x+%2B+19+=+3x+-+45+
+2x+=+19+%2B+45+
+2x+=+64+
+x+=+32+
She is 32 now
check:
+x+%2B+19+=+3%2A%28+x+-+15+%29+
+32+%2B+19+=+3%2A%28+32+-+15+%29+
+51+=+3%2A17+
+51+=+51+
OK


Word_Problems_With_Coins/657292: A clerk was asked to change a $10 bill. She returned 9 more dimes than nickels and twenty-one more quarters than dimes. How many coins of each did she return?
1 solutions

Answer 409811 by josmiceli(9661) About Me  on 2012-09-26 10:25:22 (Show Source):
You can put this solution on YOUR website!
Let +n+ = number of nickels
Let +d+ = number of dimes
Let +q+ = number of quarters
given:
(1) +d+=+n+%2B+9+
(2) +q+=+d+%2B+21+
(3) +5n+%2B+10d+%2B+25q+=+1000+ ( in cents )
----------------------------
From (1):
(1) +n+=+d+-+9+
Substitute (1) and (2) into (3)
(3) +5%2A%28+d+-+9+%29+%2B+10d+%2B+25%2A%28+d+%2B+21+%29+=+1000+
(3) +5d+-+45+%2B+10d+%2B+25d+%2B+525+=+1000+
(3) +40d+=+1000+-+525+%2B+45+
(3) +40d+=+520+
(3) +d+=+13+
--------------
and
(1) +n+=+d+-+9+
(1) +n+=+13+-+9+
(1) +n+=+4+
and
(2) +q+=+d+%2B+21+
(2) +q+=+13+%2B+21+
(2) +q+=+34+
She returned
4 nickels
13 dimes
34 quarters
----------
check:
(3) +5%2A4+%2B+10%2A13+%2B+25%2A34+=+1000+
(3) +20+%2B+130+%2B+850+=+1000+
(3) +1000+=+1000+
OK