Tutor:

New! Get regular updates about newly solved problems via algebra.com's RSS system.

---

Recent problems solved by 'jim_thompson5910'

jim_thompson5910 answered: 28499 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069 , 17070..17099 , 17100..17129 , 17130..17159 , 17160..17189 , 17190..17219 , 17220..17249 , 17250..17279 , 17280..17309 , 17310..17339 , 17340..17369 , 17370..17399 , 17400..17429 , 17430..17459 , 17460..17489 , 17490..17519 , 17520..17549 , 17550..17579 , 17580..17609 , 17610..17639 , 17640..17669 , 17670..17699 , 17700..17729 , 17730..17759 , 17760..17789 , 17790..17819 , 17820..17849 , 17850..17879 , 17880..17909 , 17910..17939 , 17940..17969 , 17970..17999 , 18000..18029 , 18030..18059 , 18060..18089 , 18090..18119 , 18120..18149 , 18150..18179 , 18180..18209 , 18210..18239 , 18240..18269 , 18270..18299 , 18300..18329 , 18330..18359 , 18360..18389 , 18390..18419 , 18420..18449 , 18450..18479 , 18480..18509 , 18510..18539 , 18540..18569 , 18570..18599 , 18600..18629 , 18630..18659 , 18660..18689 , 18690..18719 , 18720..18749 , 18750..18779 , 18780..18809 , 18810..18839 , 18840..18869 , 18870..18899 , 18900..18929 , 18930..18959 , 18960..18989 , 18990..19019 , 19020..19049 , 19050..19079 , 19080..19109 , 19110..19139 , 19140..19169 , 19170..19199 , 19200..19229 , 19230..19259 , 19260..19289 , 19290..19319 , 19320..19349 , 19350..19379 , 19380..19409 , 19410..19439 , 19440..19469 , 19470..19499 , 19500..19529 , 19530..19559 , 19560..19589 , 19590..19619 , 19620..19649 , 19650..19679 , 19680..19709 , 19710..19739 , 19740..19769 , 19770..19799 , 19800..19829 , 19830..19859 , 19860..19889 , 19890..19919 , 19920..19949 , 19950..19979 , 19980..20009 , 20010..20039 , 20040..20069 , 20070..20099 , 20100..20129 , 20130..20159 , 20160..20189 , 20190..20219 , 20220..20249 , 20250..20279 , 20280..20309 , 20310..20339 , 20340..20369 , 20370..20399 , 20400..20429 , 20430..20459 , 20460..20489 , 20490..20519 , 20520..20549 , 20550..20579 , 20580..20609 , 20610..20639 , 20640..20669 , 20670..20699 , 20700..20729 , 20730..20759 , 20760..20789 , 20790..20819 , 20820..20849 , 20850..20879 , 20880..20909 , 20910..20939 , 20940..20969 , 20970..20999 , 21000..21029 , 21030..21059 , 21060..21089 , 21090..21119 , 21120..21149 , 21150..21179 , 21180..21209 , 21210..21239 , 21240..21269 , 21270..21299 , 21300..21329 , 21330..21359 , 21360..21389 , 21390..21419 , 21420..21449 , 21450..21479 , 21480..21509 , 21510..21539 , 21540..21569 , 21570..21599 , 21600..21629 , 21630..21659 , 21660..21689 , 21690..21719 , 21720..21749 , 21750..21779 , 21780..21809 , 21810..21839 , 21840..21869 , 21870..21899 , 21900..21929 , 21930..21959 , 21960..21989 , 21990..22019 , 22020..22049 , 22050..22079 , 22080..22109 , 22110..22139 , 22140..22169 , 22170..22199 , 22200..22229 , 22230..22259 , 22260..22289 , 22290..22319 , 22320..22349 , 22350..22379 , 22380..22409 , 22410..22439 , 22440..22469 , 22470..22499 , 22500..22529 , 22530..22559 , 22560..22589 , 22590..22619 , 22620..22649 , 22650..22679 , 22680..22709 , 22710..22739 , 22740..22769 , 22770..22799 , 22800..22829 , 22830..22859 , 22860..22889 , 22890..22919 , 22920..22949 , 22950..22979 , 22980..23009 , 23010..23039 , 23040..23069 , 23070..23099 , 23100..23129 , 23130..23159 , 23160..23189 , 23190..23219 , 23220..23249 , 23250..23279 , 23280..23309 , 23310..23339 , 23340..23369 , 23370..23399 , 23400..23429 , 23430..23459 , 23460..23489 , 23490..23519 , 23520..23549 , 23550..23579 , 23580..23609 , 23610..23639 , 23640..23669 , 23670..23699 , 23700..23729 , 23730..23759 , 23760..23789 , 23790..23819 , 23820..23849 , 23850..23879 , 23880..23909 , 23910..23939 , 23940..23969 , 23970..23999 , 24000..24029 , 24030..24059 , 24060..24089 , 24090..24119 , 24120..24149 , 24150..24179 , 24180..24209 , 24210..24239 , 24240..24269 , 24270..24299 , 24300..24329 , 24330..24359 , 24360..24389 , 24390..24419 , 24420..24449 , 24450..24479 , 24480..24509 , 24510..24539 , 24540..24569 , 24570..24599 , 24600..24629 , 24630..24659 , 24660..24689 , 24690..24719 , 24720..24749 , 24750..24779 , 24780..24809 , 24810..24839 , 24840..24869 , 24870..24899 , 24900..24929 , 24930..24959 , 24960..24989 , 24990..25019 , 25020..25049 , 25050..25079 , 25080..25109 , 25110..25139 , 25140..25169 , 25170..25199 , 25200..25229 , 25230..25259 , 25260..25289 , 25290..25319 , 25320..25349 , 25350..25379 , 25380..25409 , 25410..25439 , 25440..25469 , 25470..25499 , 25500..25529 , 25530..25559 , 25560..25589 , 25590..25619 , 25620..25649 , 25650..25679 , 25680..25709 , 25710..25739 , 25740..25769 , 25770..25799 , 25800..25829 , 25830..25859 , 25860..25889 , 25890..25919 , 25920..25949 , 25950..25979 , 25980..26009 , 26010..26039 , 26040..26069 , 26070..26099 , 26100..26129 , 26130..26159 , 26160..26189 , 26190..26219 , 26220..26249 , 26250..26279 , 26280..26309 , 26310..26339 , 26340..26369 , 26370..26399 , 26400..26429 , 26430..26459 , 26460..26489 , 26490..26519 , 26520..26549 , 26550..26579 , 26580..26609 , 26610..26639 , 26640..26669 , 26670..26699 , 26700..26729 , 26730..26759 , 26760..26789 , 26790..26819 , 26820..26849 , 26850..26879 , 26880..26909 , 26910..26939 , 26940..26969 , 26970..26999 , 27000..27029 , 27030..27059 , 27060..27089 , 27090..27119 , 27120..27149 , 27150..27179 , 27180..27209 , 27210..27239 , 27240..27269 , 27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499, >>Next

Inequalities/484756: 1/3x=2-2/3x 1 solutions Answer 331613 by jim_thompson5910(28510)   on 2011-08-23 00:32:01 (Show Source): You can put this solution on YOUR website! Start with the given equation. Multiply both sides by the LCD to clear any fractions. Distribute and multiply. Add to both sides. Combine like terms on the left side. Divide both sides by to isolate . Reduce. ---------------------------------------------------------------------- Answer: So the solution is

test/484741: Hi. I was wondering if someone has a list of THE MOST IMPORTANT SAT questions. I really need to practice math section. Can anyone kindly send me the link or something. Thanks 1 solutions Answer 331604 by jim_thompson5910(28510)   on 2011-08-22 23:17:29 (Show Source): You can put this solution on YOUR website! Here is one such link: http://www.majortests.com/sat/problem-solving.php Here is another: http://www.proprofs.com/quiz-school/story.php?title=Free-SAT-Math-Practice-Questions-II Both links were found typing "sat practice math problems" (without quotes) into Google

Equations/484743: 15+w+15=30+9. 1 solutions Answer 331603 by jim_thompson5910(28510)   on 2011-08-22 23:16:00 (Show Source): You can put this solution on YOUR website! Start with the given equation. Combine like terms on the left side. Combine like terms on the right side. Subtract from both sides. Combine like terms on the right side. ---------------------------------------------------------------------- Answer: So the solution is

Conjunction/484726: Would somebody please help me with this? Thank you so much. Form the inverse: If I do not wash my clothes, then I will have nothing clean to wear. 1. If I have nothing clean to wear, then I did not wash my clothes. 2. If I wash my clothes, then I will have something clean to wear. 3. If I have something clean to wear, then I washed my clothes. 4. If I have something clean to wear, then I did not wash my clothes. 5. If I do not wash my clothes, then I will have something clean to wear. 1 solutions Answer 331602 by jim_thompson5910(28510)   on 2011-08-22 22:57:42 (Show Source): You can put this solution on YOUR website! The inverse of p --> q is ~p --> ~q. Likewise, the inverse of ~p --> ~q is p --> q In this case, p: I wash my clothes q: I will have something clean to wear So ~p: I do not wash my clothes ~q: I will have nothing clean to wear So the original statement of "If I do not wash my clothes, then I will have nothing clean to wear" translates to ~p --> ~q Using the rule given above, the inverse of that is p --> q which translates back into "If I wash my clothes, then I will have something clean to wear" So the answer is choice 2

Polynomials-and-rational-expressions/484361: multiply and simplify. assume that all variables represent nonnegative numbers (sqrt(5)+4)(sqrt(5)-1)) 1 solutions Answer 331597 by jim_thompson5910(28510)   on 2011-08-22 22:03:23 (Show Source): You can put this solution on YOUR website! So

Equations/484482: what is x in this problem 6x-3=11 1 solutions Answer 331482 by jim_thompson5910(28510)   on 2011-08-22 16:13:25 (Show Source): You can put this solution on YOUR website! 6x-3=11 6x=11+3 6x=14 x=14/6 x=7/3

Equations/484479: I need help sovling 7-5x=-(x+1) Thank you!! 1 solutions Answer 331478 by jim_thompson5910(28510)   on 2011-08-22 16:08:32 (Show Source): You can put this solution on YOUR website! 7-5x=-(x+1) 7-5x=-x-1 -5x+x=-1-7 -4x=-8 x=-8/(-4) x = 2

Probability-and-statistics/484465: I just confused my school math teacher! How lovely! Anyways HOPE you guys can seriously help me out more then these people at my college! I dont get why I pay thousands of dollars and not get adequate help! Which pair has equally likely outcomes? List the letters of the two choices below which have equal probabilities of success, separated by a comma. A standard deck of cards has 12 face cards and four Aces (Aces are not face cards). A. drawing a black two out of a standard 52 card deck given it’s not a face card or an Ace. B. drawing a six out of a standard 52 card deck given it’s not a face card or an Ace. C. rolling a sum of 7 on two fair six sided dice D. rolling a sum of 3 on two fair six sided dice E. rolling a sum of 10 on two fair six sided dice 1 solutions Answer 331477 by jim_thompson5910(28510)   on 2011-08-22 16:06:45 (Show Source): You can put this solution on YOUR website! A. drawing a black two out of a standard 52 card deck given it’s not a face card or an Ace. Since it's "given it's not a face card or an Ace.", we know that the drawn card is a 2, 3, 4, 5, 6, 7, 8, 9, or 10 (and it's either red of black) There are 9 cards listed from 2 to 10 (shown above) and there are 4 suits. So there are 9*4 = 36 cards that are NOT face cards and that are NOT aces. So in this part, there are essentially 36 cards to worry about. Note: you can think of it as we're throwing out the face cards and the aces from the deck. The cards we desire are the two of clubs and the two of spades (both of which are black cards). So there are two cards with the face value of 2 that are black. So the probability of drawing a black 2 (given the card is NOT a face card and NOT an ace) is Note: probability of event = (# of desired outcomes)/(# of total possible out comes) ====================================================================== B. drawing a six out of a standard 52 card deck given it’s not a face card or an Ace. Again, we're dealing with 36 cards (we threw out the face cards and aces; see part a) There are now four cards we desire: a six of hearts, a six of diamonds, a six of spades, and a six of clubs (ie the card with a face value of 6 drawn from each suit) So the probability is now ========================================================================= C. rolling a sum of 7 on two fair six sided dice There are 6 ways to roll a 7, and they are: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) Note: something like (2,5) means that the first die reads "2" and the second die reads "5" (and they add to 2+5=7) Overall, there are 36 ways to roll 2 dice (since 6*6 = 36). To see this better, make a table where the columns represent die #1 and the rows represent die #2. You'll then see 6*6 = 36 individual boxes (to represent the individual sums of all the possible combos) So the probability is ========================================================================= D. rolling a sum of 3 on two fair six sided dice There are only 2 ways to roll a 3 and they are: (1,2) and (2,1) Basically, one die reads "2" and the other reads "1" From part C, we know that there are 36 different ways two dice can fall. So the probability is ========================================================================= E. rolling a sum of 10 on two fair six sided dice There are 3 ways to roll a ten and they are: (4,6), (5,5), (6,4) There are 36 different possible combinations when two dice are rolled. So the probability is ========================================================================= Summary: We get the following probabilities for each part A) B) C) D) E) So parts A and D have equal probabilities (both equal to ) So the answer is A,D

Age_Word_Problems/484466: 8 more than d is 31 1 solutions Answer 331475 by jim_thompson5910(28510)   on 2011-08-22 15:45:51 (Show Source): You can put this solution on YOUR website! "8 more than d" means So "8 more than d is 31" translates to

Polynomials-and-rational-expressions/484377: Add. Simplify, if possible. 7/25z^3+1/35z^2 1 solutions Answer 331426 by jim_thompson5910(28510)   on 2011-08-22 12:29:22 (Show Source): You can put this solution on YOUR website! 7/25z^3+1/35z^2 49/175z^3+5z/175z^3 (49+5z)/175z^3 So

Equations/484336: if r=5z then 15z =3y, then r= 1 solutions Answer 331424 by jim_thompson5910(28510)   on 2011-08-22 12:27:30 (Show Source): You can put this solution on YOUR website! 15z =3y 5z=y r=5z=y So r = y

expressions/484365: express each answer in exponential form 1. 4^2 x 4^7 2. 8^4/8^2 3. 2^ + 2^8 1 solutions Answer 331421 by jim_thompson5910(28510)   on 2011-08-22 12:26:05 (Show Source): You can put this solution on YOUR website! 1. 4^2 x 4^7 = 4^9 ... add the exponents 2. 8^4/8^2 = 8^2 ... Subtract the exponents 3. 2^ + 2^8 = ????... You're missing something here

Polynomials-and-rational-expressions/484372: Simplify by removing factors of 1. y^2-10y+25/y^2+2y-35 The simplified form is 1 solutions Answer 331417 by jim_thompson5910(28510)   on 2011-08-22 12:17:10 (Show Source): You can put this solution on YOUR website! Start with the given equation. Factor the numerator. Factor the denominator. Highlight the common terms. Cancel out the common terms. Simplify. So

Probability-and-statistics/484220: What is the probability of getting a 9 on two dice? a) 11% b) 17% c) 14% d) 22% 1 solutions Answer 331340 by jim_thompson5910(28510)   on 2011-08-22 01:00:02 (Show Source): You can put this solution on YOUR website! There are 4 ways to roll a 9 out of 36 rolls total, so the probability is which is roughly 11%

Exponential-and-logarithmic-functions/484241: I'm having trouble with this problem. Thanks for your help. Solve. Express x as a logarithm if necessary. e^(x)+e^(-x)=4 1 solutions Answer 331339 by jim_thompson5910(28510)   on 2011-08-22 00:54:28 (Show Source): You can put this solution on YOUR website! Start with the given equation. Rewrite as Multiply EVERY term by the LCD to clear out the fractions. Get everything to one side. Rearrange the terms. Rewrite the first term Replace EVERY copy of with 'z' (so ) Notice that the quadratic is in the form of where , , and Let's use the quadratic formula to solve for "z": Start with the quadratic formula Plug in , , and Negate to get . Square to get . Multiply to get Subtract from to get Multiply and to get . Simplify the square root Break up the fraction. Reduce. or Break up the expression. So the solutions are or But remember, we said that So or Now convert to logarithmic form to get or So the solutions are or

Exponential-and-logarithmic-functions/484242: How do I rewrite the exponential expression 16^3x to have a base 2? Thank you! 1 solutions Answer 331334 by jim_thompson5910(28510)   on 2011-08-22 00:46:44 (Show Source): You can put this solution on YOUR website! So

Polynomials-and-rational-expressions/484111: Solve equation. 4xsqared-7x+3=0 1 solutions Answer 331239 by jim_thompson5910(28510)   on 2011-08-21 18:54:39 (Show Source): You can put this solution on YOUR website! Start with the given equation. Notice that the quadratic is in the form of where , , and Let's use the quadratic formula to solve for "x": Start with the quadratic formula Plug in , , and Negate to get . Square to get . Multiply to get Subtract from to get Multiply and to get . Take the square root of to get . or Break up the expression. or Combine like terms. or Simplify. So the solutions are or

Permutations/484084: you have a total 27 members, 7 more of them are male. how many males do you have? 1 solutions Answer 331229 by jim_thompson5910(28510)   on 2011-08-21 17:55:59 (Show Source): You can put this solution on YOUR website! f+m=27 f+(7+f)=27 2f+7=27 2f=20 f=10 So there are 10 females and 17 males

Conjunction/484081: construct a truth table for (~pVq)->p be sure to include all intermediate steps. thank you ahead of time for your help. 1 solutions Answer 331228 by jim_thompson5910(28510)   on 2011-08-21 17:54:43 (Show Source): You can put this solution on YOUR website! p q ~p ~p V q (~p V q) -> p T T F T T T F F F T F T T T F F F T T F

Equations/484046: can you show each step to 6t=3(t+4)-t 1 solutions Answer 331221 by jim_thompson5910(28510)   on 2011-08-21 17:11:39 (Show Source): You can put this solution on YOUR website! Start with the given equation. Distribute. Combine like terms on the right side. Subtract from both sides. Combine like terms on the left side. Divide both sides by to isolate . Reduce. ---------------------------------------------------------------------- Answer: So the solution is

Equations/484048: can you show each step to 2(4-2r)=-2(r+5)? 1 solutions Answer 331220 by jim_thompson5910(28510)   on 2011-08-21 17:11:01 (Show Source): You can put this solution on YOUR website! Start with the given equation. Distribute. Subtract from both sides. Add to both sides. Combine like terms on the left side. Combine like terms on the right side. Divide both sides by to isolate . Reduce. ---------------------------------------------------------------------- Answer: So the solution is

Equations/484030: Solve the following equation by clearing fractions. Please show your work. x/6+2=4/5-x 1 solutions Answer 331215 by jim_thompson5910(28510)   on 2011-08-21 16:46:02 (Show Source): You can put this solution on YOUR website! Start with the given equation. Multiply both sides by the LCD to clear any fractions. Distribute and multiply. Subtract from both sides. Add to both sides. Combine like terms on the left side. Combine like terms on the right side. Divide both sides by to isolate . ---------------------------------------------------------------------- Answer: So the solution is

Equations/484036: Solve the following equation for m. U=m-4n/6 1 solutions Answer 331214 by jim_thompson5910(28510)   on 2011-08-21 16:45:19 (Show Source): You can put this solution on YOUR website!

Expressions-with-variables/483997: "Solve each system by substitution." y=-4x+16 y=2x+4 I changed y=-4x+16 to -4x+y=16 then I put the bottom equation (y=2x+4) into that so: -4x+(2x+4)=16 and got x=-6 so I put that into y=2x+4 so y=2(6)+4 and got y=16 but I don't think it's right. (-6,16) 1 solutions Answer 331198 by jim_thompson5910(28510)   on 2011-08-21 15:12:47 (Show Source): You can put this solution on YOUR website! y=-4x+16 2x+4 =-4x+16 2x+4x =16-4 6x =12 x=12/6 x=2 ------------ y=2x+4 y=2(2)+4 y=4+4 y=8 So x = 2 and y = 8 giving us the ordered pair (2,8)

Complex_Numbers/483996: If a*b = b^2-2a, what is the value of (3*4)*5? choose the answer and explain the reason to choose your response 15 23 -9 5 1 solutions Answer 331196 by jim_thompson5910(28510)   on 2011-08-21 14:59:09 (Show Source): You can put this solution on YOUR website! a*b = b^2-2a 3*4 = 4^2-2(3) 3*4 = 10 ------------------------ (3*4)*5 = 10*5 a*b = b^2-2a 10*5 = 5^2-2(10) 10*5 = 5 So (3*4)*5 = 5

Polynomials-and-rational-expressions/483536: I would like help on the specific steps for this equation. I believe I'm doing something wrong. It says solve for x 2x-1/x+2= 4/5 I end up with 13/6. Another question. solve for y. 4(y - 1/2)- y = 6(5 - y) I end up with 32/9. 1 solutions Answer 330904 by jim_thompson5910(28510)   on 2011-08-20 04:03:19 (Show Source): You can put this solution on YOUR website! You have the correct answers for both of them. Good job.

Polynomials-and-rational-expressions/483522: Factor: 56b^2 + 23b -63 1 solutions Answer 330892 by jim_thompson5910(28510)   on 2011-08-20 00:01:54 (Show Source): You can put this solution on YOUR website! Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is . Now multiply the first coefficient by the last term to get . Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ? To find these two numbers, we need to list all of the factors of (the previous product). Factors of : 1,2,3,4,6,7,8,9,12,14,18,21,24,28,36,42,49,56,63,72,84,98,126,147,168,196,252,294,392,441,504,588,882,1176,1764,3528 -1,-2,-3,-4,-6,-7,-8,-9,-12,-14,-18,-21,-24,-28,-36,-42,-49,-56,-63,-72,-84,-98,-126,-147,-168,-196,-252,-294,-392,-441,-504,-588,-882,-1176,-1764,-3528 Note: list the negative of each factor. This will allow us to find all possible combinations. These factors pair up and multiply to . 1*(-3528) = -3528 2*(-1764) = -3528 3*(-1176) = -3528 4*(-882) = -3528 6*(-588) = -3528 7*(-504) = -3528 8*(-441) = -3528 9*(-392) = -3528 12*(-294) = -3528 14*(-252) = -3528 18*(-196) = -3528 21*(-168) = -3528 24*(-147) = -3528 28*(-126) = -3528 36*(-98) = -3528 42*(-84) = -3528 49*(-72) = -3528 56*(-63) = -3528 (-1)*(3528) = -3528 (-2)*(1764) = -3528 (-3)*(1176) = -3528 (-4)*(882) = -3528 (-6)*(588) = -3528 (-7)*(504) = -3528 (-8)*(441) = -3528 (-9)*(392) = -3528 (-12)*(294) = -3528 (-14)*(252) = -3528 (-18)*(196) = -3528 (-21)*(168) = -3528 (-24)*(147) = -3528 (-28)*(126) = -3528 (-36)*(98) = -3528 (-42)*(84) = -3528 (-49)*(72) = -3528 (-56)*(63) = -3528 Now let's add up each pair of factors to see if one pair adds to the middle coefficient : First Number Second Number Sum 1 -3528 1+(-3528)=-3527 2 -1764 2+(-1764)=-1762 3 -1176 3+(-1176)=-1173 4 -882 4+(-882)=-878 6 -588 6+(-588)=-582 7 -504 7+(-504)=-497 8 -441 8+(-441)=-433 9 -392 9+(-392)=-383 12 -294 12+(-294)=-282 14 -252 14+(-252)=-238 18 -196 18+(-196)=-178 21 -168 21+(-168)=-147 24 -147 24+(-147)=-123 28 -126 28+(-126)=-98 36 -98 36+(-98)=-62 42 -84 42+(-84)=-42 49 -72 49+(-72)=-23 56 -63 56+(-63)=-7 -1 3528 -1+3528=3527 -2 1764 -2+1764=1762 -3 1176 -3+1176=1173 -4 882 -4+882=878 -6 588 -6+588=582 -7 504 -7+504=497 -8 441 -8+441=433 -9 392 -9+392=383 -12 294 -12+294=282 -14 252 -14+252=238 -18 196 -18+196=178 -21 168 -21+168=147 -24 147 -24+147=123 -28 126 -28+126=98 -36 98 -36+98=62 -42 84 -42+84=42 -49 72 -49+72=23 -56 63 -56+63=7 From the table, we can see that the two numbers and add to (the middle coefficient). So the two numbers and both multiply to and add to Now replace the middle term with . Remember, and add to . So this shows us that . Replace the second term with . Group the terms into two pairs. Factor out the GCF from the first group. Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis. Combine like terms. Or factor out the common term =============================================================== Answer: So factors to . In other words, . Note: you can check the answer by expanding to get or by graphing the original expression and the answer (the two graphs should be identical).

Polynomials-and-rational-expressions/483520: 5x^2-34x-7 1 solutions Answer 330887 by jim_thompson5910(28510)   on 2011-08-19 23:43:59 (Show Source): You can put this solution on YOUR website! Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is . Now multiply the first coefficient by the last term to get . Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ? To find these two numbers, we need to list all of the factors of (the previous product). Factors of : 1,5,7,35 -1,-5,-7,-35 Note: list the negative of each factor. This will allow us to find all possible combinations. These factors pair up and multiply to . 1*(-35) = -35 5*(-7) = -35 (-1)*(35) = -35 (-5)*(7) = -35 Now let's add up each pair of factors to see if one pair adds to the middle coefficient : First Number Second Number Sum 1 -35 1+(-35)=-34 5 -7 5+(-7)=-2 -1 35 -1+35=34 -5 7 -5+7=2 From the table, we can see that the two numbers and add to (the middle coefficient). So the two numbers and both multiply to and add to Now replace the middle term with . Remember, and add to . So this shows us that . Replace the second term with . Group the terms into two pairs. Factor out the GCF from the first group. Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis. Combine like terms. Or factor out the common term =============================================================== Answer: So factors to . In other words, . Note: you can check the answer by expanding to get or by graphing the original expression and the answer (the two graphs should be identical).

Proportions/483501: how to solve x/3=x+2/5 1 solutions Answer 330883 by jim_thompson5910(28510)   on 2011-08-19 22:41:17 (Show Source): You can put this solution on YOUR website!

Linear-systems/483505: I have been working a problem over and over for my online algebra class and I have also used the "help me with this problem" link and the "veiw an example" link and for some reason when I work the problem I am not getting the right answer. The problem says" Write an equation that is paralell to the given equation and point".(MyMathLab, wk6, problem 32). given equation: 4x=3y+5 given point (-3,4). I know that I need to get my given equation to y=mx+b so that I can find what my slope is and use that same slope in my new equation. 4x=3y+5 -4x -3y -3y=-4x+5 /-3 /-3 this is divide by -3 from both sides y=4/3x-5/3 So my slope is 4/3 now I can substitute in my points for x and y to find b. 4=4/3(-3)+b 4=-12/3+b 4=-4+b -4 -4 0=b So my new problem would be y=4/3x+0. But when I input that answer into my solution it says that I am wrong. I am not sure what I am doing wrong. Please help I have four problems like this and cannot figure out what I am doing wrong. 1 solutions Answer 330880 by jim_thompson5910(28510)   on 2011-08-19 22:11:11 (Show Source): You can put this solution on YOUR website! You made a mistake in your last step 4=-4+b 4+4=b 8=b So b = 8 giving you

Equations/483504: Find the equation of the line satisfying the given conditions, giving it in slope-intercept form if possible. 1) Through (1,-4), perpendicular for x=4 1 solutions Answer 330877 by jim_thompson5910(28510)   on 2011-08-19 22:05:26 (Show Source): You can put this solution on YOUR website! Anything perpendicular to x=4 will be of the y=k where k is some number Since the line MUST go through (1,-4), we know that k=-4 (since the y-coordinate is -4) So the equation of the perpendicular line is y = -4