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# Recent problems solved by 'jim_thompson5910'

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 Circles/530393: I'm really lost. Please help. find the center and radius of the circle with the given equation. x^2+y^2-28=0 All help is appreciated!1 solutions Answer 350014 by jim_thompson5910(28598)   on 2011-11-12 13:59:38 (Show Source): You can put this solution on YOUR website! The equation is now in form, which is a circle, where , and Remember that the center is (h,k) and the radius is r. So the center is (0,0) and the radius is units. If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 test/530398: 1 solutions Answer 350013 by jim_thompson5910(28598)   on 2011-11-12 13:55:36 (Show Source): You can put this solution on YOUR website!There's nothing here...please post a problem.
 Signed-numbers/530401: I am stuck on the answer to this, I know what it is, but how it was solved How did it get to 33 over 12 (33/12) 26 = -7 + 12p1 solutions Answer 350012 by jim_thompson5910(28598)   on 2011-11-12 13:55:09 (Show Source):
 absolute-value/530403: evaluate [40+(-8)]1 solutions Answer 350011 by jim_thompson5910(28598)   on 2011-11-12 13:53:17 (Show Source): You can put this solution on YOUR website![40+(-8)] = [40-8] = [32] = 32
 Miscellaneous_Word_Problems/530247: Marcy has a locker at school. the locker number is 2 digits. Each digit is 1,2,3 or 7, and the digits are different. The number is prime number that is 1 greater than a multiple of 8. What could the locker number be?1 solutions Answer 349980 by jim_thompson5910(28598)   on 2011-11-11 23:56:15 (Show Source): You can put this solution on YOUR website!List out all the possible combos and you'll find that only 17 and 73 are the only numbers that fit the description.
 Equations/530262: factor x^3+8x^2+2x+161 solutions Answer 349979 by jim_thompson5910(28598)   on 2011-11-11 23:53:29 (Show Source): You can put this solution on YOUR website! Start with the given expression Group the terms in two pairs Factor out the GCF out of the first group. Factor out the GCF out of the second group Since we have the common term , we can combine like terms So factors to In other words, If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 Equations/530236: (18x^2-63x+81)divided by 91 solutions Answer 349965 by jim_thompson5910(28598)   on 2011-11-11 21:38:45 (Show Source): You can put this solution on YOUR website! So If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 Linear-systems/530230: solve by substitution x+2y=8 and x+3y=121 solutions Answer 349959 by jim_thompson5910(28598)   on 2011-11-11 21:24:00 (Show Source): You can put this solution on YOUR website!Hint: Solve for x in equation 1 to get x = 8-2y Now plug in x = 8-2y into x+3y=12 to get 8-2y + 3y = 12 From here, solve for y. Once you have a value for y, use it to find x.
 Linear-equations/530233: Given: m = (y2 - y1)/x2 - x1), y = mx + b, and the points (-2, 2) and (2, 4). Find the y-intercept. Write the equation of the line in slope-intercept form1 solutions Answer 349958 by jim_thompson5910(28598)   on 2011-11-11 21:22:29 (Show Source): You can put this solution on YOUR website! First let's find the slope of the line through the points and Note: is the first point . So this means that and . Also, is the second point . So this means that and . Start with the slope formula. Plug in , , , and Subtract from to get Subtract from to get Reduce So the slope of the line that goes through the points and is Now let's use the point slope formula: Start with the point slope formula Plug in , , and Rewrite as Distribute Multiply Add 2 to both sides. Combine like terms. So the equation that goes through the points and is If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 Linear-systems/530221: solve by substitution y=0.5x+2 and -y=-2x+41 solutions Answer 349953 by jim_thompson5910(28598)   on 2011-11-11 21:05:03 (Show Source): You can put this solution on YOUR website!Hint: Start with -y=-2x+4 and replace 'y' with 0.5x+2 to get -(0.5x+2) = -2x+4 Solve for x. Once you have a solution for x, plug it into y = 0.5x+2 to find y.
Polynomials-and-rational-expressions/530219: factor completely 10x^2-29x-3
1 solutions

Answer 349947 by jim_thompson5910(28598)   on 2011-11-11 20:50:14 (Show Source):
You can put this solution on YOUR website!

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .

Now multiply the first coefficient by the last term to get .

Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?

To find these two numbers, we need to list all of the factors of (the previous product).

Factors of :
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30

Note: list the negative of each factor. This will allow us to find all possible combinations.

These factors pair up and multiply to .
1*(-30) = -30
2*(-15) = -30
3*(-10) = -30
5*(-6) = -30
(-1)*(30) = -30
(-2)*(15) = -30
(-3)*(10) = -30
(-5)*(6) = -30

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :

First NumberSecond NumberSum
1-301+(-30)=-29
2-152+(-15)=-13
3-103+(-10)=-7
5-65+(-6)=-1
-130-1+30=29
-215-2+15=13
-310-3+10=7
-56-5+6=1

From the table, we can see that the two numbers and add to (the middle coefficient).

So the two numbers and both multiply to and add to

Now replace the middle term with . Remember, and add to . So this shows us that .

Replace the second term with .

Group the terms into two pairs.

Factor out the GCF from the first group.

Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.

Combine like terms. Or factor out the common term

===============================================================

So factors to .

In other words, .

Note: you can check the answer by expanding to get or by graphing the original expression and the answer (the two graphs should be identical).

If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim

 Geometry_proofs/530218: the last statement on my graph has segment ab is congruent to segment dc. thats my question.. this is the problem.. given: segment ae congruent to segment de, segment be congruent to segment ce. prove: segment ab congruent to segment dc. Statements. Reasons 1.Segment AE congr. segment DE| Given 2.Segment BE congr. Segment CE| Given 3.Angle AEB congr. Angle DEC | Alternate Interior Angles Thm. 4.Triangle AEB congr. Triangle DEC|SAS Congruence postulate 5.Segment AB congr. segment DE| *blank* ------------------------------------------------------------------ i dont get #5. please help. i need this answer by tonight and i cant find it in my book. 1 solutions Answer 349946 by jim_thompson5910(28598)   on 2011-11-11 20:46:29 (Show Source): You can put this solution on YOUR website!Do you have a picture to go along with this?
 logarithm/530212: what is -5ln(x)+ln(3y)-ln(2z) as a single logarithm?1 solutions Answer 349945 by jim_thompson5910(28598)   on 2011-11-11 20:41:51 (Show Source): You can put this solution on YOUR website!-5ln(x)+ln(3y)-ln(2z) ln(3y)-5ln(x)-ln(2z) ln(3y)-(5ln(x)+ln(2z)) ln(3y)-(ln(x^5)+ln(2z)) ln[ (3y)/(x^5*2z) ]
 Probability-and-statistics/530215: One card is selected at random from a deck of cards. Determine the probability that the card selected is a diamond.1 solutions Answer 349943 by jim_thompson5910(28598)   on 2011-11-11 20:40:21 (Show Source): You can put this solution on YOUR website!P(Diamond) = (# of diamonds)/(# of cards total) P(Diamond) = 13/52 P(Diamond) = 1/4
 Polynomials-and-rational-expressions/530214: The scale on a map indicates that 1 inch on the map corresponds to an actual distance of 105 miles. Two cities are 4.5 inches apart on the map. What is the actual distance between the two cities?1 solutions Answer 349942 by jim_thompson5910(28598)   on 2011-11-11 20:39:23 (Show Source): You can put this solution on YOUR website!1/105 = 4.5/x 1x = 105*4.5 x = 472.5 So the two cities are 472.5 miles apart. If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 Inequalities/530209: Could you help me solve this problem or 1 solutions Answer 349938 by jim_thompson5910(28598)   on 2011-11-11 20:22:54 (Show Source): You can put this solution on YOUR website! or or or or or If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 Expressions-with-variables/530205: what is the slope of the line parallel to this, y = -4/3x - 91 solutions Answer 349936 by jim_thompson5910(28598)   on 2011-11-11 20:03:19 (Show Source): You can put this solution on YOUR website!Hint: Parallel lines have the same slope and the slope of y = mx+b is m
 Probability-and-statistics/530188: A committee contains 9 women and 6 men. If we choose three random people for a subcommittee, how many ways could we choose exactly 1 woman? Here's my work: # ways to pick 1 woman: 9C1 = 9 # ways to pick 2 men: 6C2 = 15 Answer: 135 ways to choose exactly 1 woman Is this answer correct? If not, could you explain the steps and answer? Really appreciate an answer to this. Need to submit homework online tonight!1 solutions Answer 349925 by jim_thompson5910(28598)   on 2011-11-11 19:06:47 (Show Source): You can put this solution on YOUR website!You are correct, congrats. This is of course assuming that order does not matter.
 Sequences-and-series/530187: the sum of the square are two consecutive positive integers is 221. find the integers? i put as the answer 4,5? 1 solutions Answer 349923 by jim_thompson5910(28598)   on 2011-11-11 19:01:18 (Show Source): You can put this solution on YOUR website!No, you are incorrect since 4^2 + 5^2 = 16+25 = 41 "the sum of the square are two consecutive positive integers is 221" means that Note: in the phrase above, I think you truly mean "the sum of the squares of two consecutive positive integers is 221" or or Assuming you want positive integers only, the answer is So the two integers are 10 and 11 If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
Polynomials-and-rational-expressions/530186: Find the factor of:
2a + 7
-----------
a2 - 2a - 15

1 solutions

Answer 349922 by jim_thompson5910(28598)   on 2011-11-11 18:54:23 (Show Source):
You can put this solution on YOUR website!
you mean factor a^2 - 2a - 15 ?

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .

Now multiply the first coefficient by the last term to get .

Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?

To find these two numbers, we need to list all of the factors of (the previous product).

Factors of :
1,3,5,15
-1,-3,-5,-15

Note: list the negative of each factor. This will allow us to find all possible combinations.

These factors pair up and multiply to .
1*(-15) = -15
3*(-5) = -15
(-1)*(15) = -15
(-3)*(5) = -15

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :

First NumberSecond NumberSum
1-151+(-15)=-14
3-53+(-5)=-2
-115-1+15=14
-35-3+5=2

From the table, we can see that the two numbers and add to (the middle coefficient).

So the two numbers and both multiply to and add to

Now replace the middle term with . Remember, and add to . So this shows us that .

Replace the second term with .

Group the terms into two pairs.

Factor out the GCF from the first group.

Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.

Combine like terms. Or factor out the common term

===============================================================

So factors to .

In other words, .

Note: you can check the answer by expanding to get or by graphing the original expression and the answer (the two graphs should be identical).

If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim

 test/530162: 1 solutions Answer 349914 by jim_thompson5910(28598)   on 2011-11-11 17:48:39 (Show Source): You can put this solution on YOUR website!There's nothing here....Please post a problem.
 Quadratic_Equations/530156: -7ab/a, a not equal to 0 1 solutions Answer 349912 by jim_thompson5910(28598)   on 2011-11-11 17:24:30 (Show Source):
 Linear-equations/530138: What is the equation of the line that passes through the points (-8,-1) and (-2,23)?1 solutions Answer 349909 by jim_thompson5910(28598)   on 2011-11-11 16:52:36 (Show Source): You can put this solution on YOUR website! First let's find the slope of the line through the points and Note: is the first point . So this means that and . Also, is the second point . So this means that and . Start with the slope formula. Plug in , , , and Subtract from to get Subtract from to get Reduce So the slope of the line that goes through the points and is Now let's use the point slope formula: Start with the point slope formula Plug in , , and Rewrite as Rewrite as Distribute Multiply Subtract 1 from both sides. Combine like terms. So the equation that goes through the points and is If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 Linear-equations/530135: What is the slope of the line that passes through the points (–2, 5) and (1, 4)?1 solutions Answer 349907 by jim_thompson5910(28598)   on 2011-11-11 16:41:28 (Show Source): You can put this solution on YOUR website!Note: is the first point . So this means that and . Also, is the second point . So this means that and . Start with the slope formula. Plug in , , , and Subtract from to get Subtract from to get So the slope of the line that goes through the points and is If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 Radicals/530101: square x-10 =51 solutions Answer 349884 by jim_thompson5910(28598)   on 2011-11-11 15:25:50 (Show Source):
 Systems-of-equations/530105: question: Using complete sentences, explain which method you would use to solve the following system of equations and why. In your answer, include the solution to one of the variables and how you found it using the method you chose. x – 5y + 2z = 0 x + 4y – z = 12 2x – y + 3z = 10 MY answer: in this equation i used the elimination method because its easiest for me. addition eliminates x and y so i am solving for z i got: 0+0-2z=2 then i multiplied by -1 and got 2z= -2 then i divided both sides by 2 and my final answer is: z= -11 solutions Answer 349883 by jim_thompson5910(28598)   on 2011-11-11 15:24:16 (Show Source): You can put this solution on YOUR website!You have the correct answer for z. Good job. Now use that answer to find x and y.
 Sequences-and-series/530104: I need the fourth term in the following sequence and how you got it. 1,4,27,n,61251 solutions Answer 349881 by jim_thompson5910(28598)   on 2011-11-11 15:22:23 (Show Source): You can put this solution on YOUR website!1 = 1^1 4 = 2^2 27 = 3^3 ... Starting to see the pattern? The next number is then n = 256 = 4^4 then the next number is 3125 = 5^5 ... Note: you may have a typo in the problem
 Linear-equations/530095: Write the slope-intercept equation for the line that passes through (-4, -3) and (-6, 7). 1 solutions Answer 349877 by jim_thompson5910(28598)   on 2011-11-11 14:51:00 (Show Source): You can put this solution on YOUR website! First let's find the slope of the line through the points and Note: is the first point . So this means that and . Also, is the second point . So this means that and . Start with the slope formula. Plug in , , , and Subtract from to get Subtract from to get Reduce So the slope of the line that goes through the points and is Now let's use the point slope formula: Start with the point slope formula Plug in , , and Rewrite as Rewrite as Distribute Multiply Subtract 3 from both sides. Combine like terms. So the equation that goes through the points and is If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim
 Functions/530093: is x=-2 a function?1 solutions Answer 349876 by jim_thompson5910(28598)   on 2011-11-11 14:49:03 (Show Source): You can put this solution on YOUR website!No, it's not a function because the graph violates the vertical line test. Also, the one input x = -2 maps to more than one output. So it cannot be a function.
Polynomials-and-rational-expressions/530088: factor the following polynomial:
12a^2+8a-15
1 solutions

Answer 349872 by jim_thompson5910(28598)   on 2011-11-11 14:10:30 (Show Source):
You can put this solution on YOUR website!

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .

Now multiply the first coefficient by the last term to get .

Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?

To find these two numbers, we need to list all of the factors of (the previous product).

Factors of :
1,2,3,4,5,6,9,10,12,15,18,20,30,36,45,60,90,180
-1,-2,-3,-4,-5,-6,-9,-10,-12,-15,-18,-20,-30,-36,-45,-60,-90,-180

Note: list the negative of each factor. This will allow us to find all possible combinations.

These factors pair up and multiply to .
1*(-180) = -180
2*(-90) = -180
3*(-60) = -180
4*(-45) = -180
5*(-36) = -180
6*(-30) = -180
9*(-20) = -180
10*(-18) = -180
12*(-15) = -180
(-1)*(180) = -180
(-2)*(90) = -180
(-3)*(60) = -180
(-4)*(45) = -180
(-5)*(36) = -180
(-6)*(30) = -180
(-9)*(20) = -180
(-10)*(18) = -180
(-12)*(15) = -180

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :

First NumberSecond NumberSum
1-1801+(-180)=-179
2-902+(-90)=-88
3-603+(-60)=-57
4-454+(-45)=-41
5-365+(-36)=-31
6-306+(-30)=-24
9-209+(-20)=-11
10-1810+(-18)=-8
12-1512+(-15)=-3
-1180-1+180=179
-290-2+90=88
-360-3+60=57
-445-4+45=41
-536-5+36=31
-630-6+30=24
-920-9+20=11
-1018-10+18=8
-1215-12+15=3

From the table, we can see that the two numbers and add to (the middle coefficient).

So the two numbers and both multiply to and add to

Now replace the middle term with . Remember, and add to . So this shows us that .

Replace the second term with .

Group the terms into two pairs.

Factor out the GCF from the first group.

Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.

Combine like terms. Or factor out the common term

===============================================================

So factors to .

In other words, .

Note: you can check the answer by expanding to get or by graphing the original expression and the answer (the two graphs should be identical).

If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim

 Equations/530075: 3x+5-2x=251 solutions Answer 349871 by jim_thompson5910(28598)   on 2011-11-11 14:02:07 (Show Source): You can put this solution on YOUR website! Start with the given equation. Combine like terms on the left side. Subtract from both sides. Combine like terms on the right side. ---------------------------------------------------------------------- Answer: So the solution is If you need more help, email me at jim_thompson5910@hotmail.com Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you Jim