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Miscellaneous_Word_Problems/530247: Marcy has a locker at school. the locker number is 2 digits. Each digit is 1,2,3 or 7, and the digits are different. The number is prime number that is 1 greater than a multiple of 8. What could the locker number be? 1 solutions
Answer 349980 by jim_thompson5910(28598) on 2011-11-11 23:56:15 (Show Source):
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Linear-equations/530233: Given: m = (y2 - y1)/x2 - x1), y = mx + b, and the points (-2, 2) and (2, 4).
Find the y-intercept. Write the equation of the line in slope-intercept form 1 solutions
Answer 349958 by jim_thompson5910(28598) on 2011-11-11 21:22:29 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Distribute
 Multiply
 Add 2 to both sides.
 Combine like terms.
So the equation that goes through the points ) and ) is
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
|
Polynomials-and-rational-expressions/530219: factor completely 10x^2-29x-3 1 solutions
Answer 349947 by jim_thompson5910(28598) on 2011-11-11 20:50:14 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-30) = -30
2*(-15) = -30
3*(-10) = -30
5*(-6) = -30
(-1)*(30) = -30
(-2)*(15) = -30
(-3)*(10) = -30
(-5)*(6) = -30
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -30 | 1+(-30)=-29 | | 2 | -15 | 2+(-15)=-13 | | 3 | -10 | 3+(-10)=-7 | | 5 | -6 | 5+(-6)=-1 | | -1 | 30 | -1+30=29 | | -2 | 15 | -2+15=13 | | -3 | 10 | -3+10=7 | | -5 | 6 | -5+6=1 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
|
Geometry_proofs/530218: the last statement on my graph has segment ab is congruent to segment dc.
thats my question..
this is the problem..
given: segment ae congruent to segment de,
segment be congruent to segment ce.
prove: segment ab congruent to segment dc.
Statements. Reasons
1.Segment AE congr. segment DE| Given
2.Segment BE congr. Segment CE| Given
3.Angle AEB congr. Angle DEC | Alternate Interior Angles Thm.
4.Triangle AEB congr. Triangle DEC|SAS Congruence postulate
5.Segment AB congr. segment DE| *blank*
------------------------------------------------------------------
i dont get #5.
please help. i need this answer by tonight and i cant find it in my book. 1 solutions
Answer 349946 by jim_thompson5910(28598) on 2011-11-11 20:46:29 (Show Source):
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Probability-and-statistics/530188: A committee contains 9 women and 6 men. If we choose three random people for a subcommittee, how many ways could we choose exactly 1 woman?
Here's my work: # ways to pick 1 woman: 9C1 = 9
# ways to pick 2 men: 6C2 = 15
Answer: 135 ways to choose exactly 1 woman
Is this answer correct? If not, could you explain the steps and answer?
Really appreciate an answer to this. Need to submit homework online tonight! 1 solutions
Answer 349925 by jim_thompson5910(28598) on 2011-11-11 19:06:47 (Show Source):
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Polynomials-and-rational-expressions/530186: Find the factor of:
2a + 7
-----------
a2 - 2a - 15
1 solutions
Answer 349922 by jim_thompson5910(28598) on 2011-11-11 18:54:23 (Show Source):
You can put this solution on YOUR website!you mean factor a^2 - 2a - 15 ?
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,3,5,15
-1,-3,-5,-15
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-15) = -15
3*(-5) = -15
(-1)*(15) = -15
(-3)*(5) = -15
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -15 | 1+(-15)=-14 | | 3 | -5 | 3+(-5)=-2 | | -1 | 15 | -1+15=14 | | -3 | 5 | -3+5=2 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
|
Linear-equations/530138: What is the equation of the line that passes through the points (-8,-1) and (-2,23)? 1 solutions
Answer 349909 by jim_thompson5910(28598) on 2011-11-11 16:52:36 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Rewrite  as
 Distribute
 Multiply
 Subtract 1 from both sides.
 Combine like terms.
So the equation that goes through the points ) and ) is
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Systems-of-equations/530105: question: Using complete sentences, explain which method you would use to solve the following system of equations and why. In your answer, include the solution to one of the variables and how you found it using the method you chose.
x – 5y + 2z = 0
x + 4y – z = 12
2x – y + 3z = 10
MY answer: in this equation i used the elimination method because its easiest for me.
addition eliminates x and y so i am solving for z
i got: 0+0-2z=2
then i multiplied by -1 and got 2z= -2
then i divided both sides by 2 and my final answer is: z= -1 1 solutions
Answer 349883 by jim_thompson5910(28598) on 2011-11-11 15:24:16 (Show Source):
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Linear-equations/530095: Write the slope-intercept equation for the line that passes through (-4, -3) and (-6, 7). 1 solutions
Answer 349877 by jim_thompson5910(28598) on 2011-11-11 14:51:00 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Rewrite  as
 Distribute
 Multiply
 Subtract 3 from both sides.
 Combine like terms.
So the equation that goes through the points ) and ) is
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Polynomials-and-rational-expressions/530088: factor the following polynomial:
12a^2+8a-15 1 solutions
Answer 349872 by jim_thompson5910(28598) on 2011-11-11 14:10:30 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,5,6,9,10,12,15,18,20,30,36,45,60,90,180
-1,-2,-3,-4,-5,-6,-9,-10,-12,-15,-18,-20,-30,-36,-45,-60,-90,-180
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-180) = -180
2*(-90) = -180
3*(-60) = -180
4*(-45) = -180
5*(-36) = -180
6*(-30) = -180
9*(-20) = -180
10*(-18) = -180
12*(-15) = -180
(-1)*(180) = -180
(-2)*(90) = -180
(-3)*(60) = -180
(-4)*(45) = -180
(-5)*(36) = -180
(-6)*(30) = -180
(-9)*(20) = -180
(-10)*(18) = -180
(-12)*(15) = -180
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -180 | 1+(-180)=-179 | | 2 | -90 | 2+(-90)=-88 | | 3 | -60 | 3+(-60)=-57 | | 4 | -45 | 4+(-45)=-41 | | 5 | -36 | 5+(-36)=-31 | | 6 | -30 | 6+(-30)=-24 | | 9 | -20 | 9+(-20)=-11 | | 10 | -18 | 10+(-18)=-8 | | 12 | -15 | 12+(-15)=-3 | | -1 | 180 | -1+180=179 | | -2 | 90 | -2+90=88 | | -3 | 60 | -3+60=57 | | -4 | 45 | -4+45=41 | | -5 | 36 | -5+36=31 | | -6 | 30 | -6+30=24 | | -9 | 20 | -9+20=11 | | -10 | 18 | -10+18=8 | | -12 | 15 | -12+15=3 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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