See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'jim_thompson5910'

jim_thompson5910 answered: 28586 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069 , 17070..17099 , 17100..17129 , 17130..17159 , 17160..17189 , 17190..17219 , 17220..17249 , 17250..17279 , 17280..17309 , 17310..17339 , 17340..17369 , 17370..17399 , 17400..17429 , 17430..17459 , 17460..17489 , 17490..17519 , 17520..17549 , 17550..17579 , 17580..17609 , 17610..17639 , 17640..17669 , 17670..17699 , 17700..17729 , 17730..17759 , 17760..17789 , 17790..17819 , 17820..17849 , 17850..17879 , 17880..17909 , 17910..17939 , 17940..17969 , 17970..17999 , 18000..18029 , 18030..18059 , 18060..18089 , 18090..18119 , 18120..18149 , 18150..18179 , 18180..18209 , 18210..18239 , 18240..18269 , 18270..18299 , 18300..18329 , 18330..18359 , 18360..18389 , 18390..18419 , 18420..18449 , 18450..18479 , 18480..18509 , 18510..18539 , 18540..18569 , 18570..18599 , 18600..18629 , 18630..18659 , 18660..18689 , 18690..18719 , 18720..18749 , 18750..18779 , 18780..18809 , 18810..18839 , 18840..18869 , 18870..18899 , 18900..18929 , 18930..18959 , 18960..18989 , 18990..19019 , 19020..19049 , 19050..19079 , 19080..19109 , 19110..19139 , 19140..19169 , 19170..19199 , 19200..19229 , 19230..19259 , 19260..19289 , 19290..19319 , 19320..19349 , 19350..19379 , 19380..19409 , 19410..19439 , 19440..19469 , 19470..19499 , 19500..19529 , 19530..19559 , 19560..19589 , 19590..19619 , 19620..19649 , 19650..19679 , 19680..19709 , 19710..19739 , 19740..19769 , 19770..19799 , 19800..19829 , 19830..19859 , 19860..19889 , 19890..19919 , 19920..19949 , 19950..19979 , 19980..20009 , 20010..20039 , 20040..20069 , 20070..20099 , 20100..20129 , 20130..20159 , 20160..20189 , 20190..20219 , 20220..20249 , 20250..20279 , 20280..20309 , 20310..20339 , 20340..20369 , 20370..20399 , 20400..20429 , 20430..20459 , 20460..20489 , 20490..20519 , 20520..20549 , 20550..20579 , 20580..20609 , 20610..20639 , 20640..20669 , 20670..20699 , 20700..20729 , 20730..20759 , 20760..20789 , 20790..20819 , 20820..20849 , 20850..20879 , 20880..20909 , 20910..20939 , 20940..20969 , 20970..20999 , 21000..21029 , 21030..21059 , 21060..21089 , 21090..21119 , 21120..21149 , 21150..21179 , 21180..21209 , 21210..21239 , 21240..21269 , 21270..21299 , 21300..21329 , 21330..21359 , 21360..21389 , 21390..21419 , 21420..21449 , 21450..21479 , 21480..21509 , 21510..21539 , 21540..21569 , 21570..21599 , 21600..21629 , 21630..21659 , 21660..21689 , 21690..21719 , 21720..21749 , 21750..21779 , 21780..21809 , 21810..21839 , 21840..21869 , 21870..21899 , 21900..21929 , 21930..21959 , 21960..21989 , 21990..22019 , 22020..22049 , 22050..22079 , 22080..22109 , 22110..22139 , 22140..22169 , 22170..22199 , 22200..22229 , 22230..22259 , 22260..22289 , 22290..22319 , 22320..22349 , 22350..22379 , 22380..22409 , 22410..22439 , 22440..22469 , 22470..22499 , 22500..22529 , 22530..22559 , 22560..22589 , 22590..22619 , 22620..22649 , 22650..22679 , 22680..22709 , 22710..22739 , 22740..22769 , 22770..22799 , 22800..22829 , 22830..22859 , 22860..22889 , 22890..22919 , 22920..22949 , 22950..22979 , 22980..23009 , 23010..23039 , 23040..23069 , 23070..23099 , 23100..23129 , 23130..23159 , 23160..23189 , 23190..23219 , 23220..23249 , 23250..23279 , 23280..23309 , 23310..23339 , 23340..23369 , 23370..23399 , 23400..23429 , 23430..23459 , 23460..23489 , 23490..23519 , 23520..23549 , 23550..23579 , 23580..23609 , 23610..23639 , 23640..23669 , 23670..23699 , 23700..23729 , 23730..23759 , 23760..23789 , 23790..23819 , 23820..23849 , 23850..23879 , 23880..23909 , 23910..23939 , 23940..23969 , 23970..23999 , 24000..24029 , 24030..24059 , 24060..24089 , 24090..24119 , 24120..24149 , 24150..24179 , 24180..24209 , 24210..24239 , 24240..24269 , 24270..24299 , 24300..24329 , 24330..24359 , 24360..24389 , 24390..24419 , 24420..24449 , 24450..24479 , 24480..24509 , 24510..24539 , 24540..24569 , 24570..24599 , 24600..24629 , 24630..24659 , 24660..24689 , 24690..24719 , 24720..24749 , 24750..24779 , 24780..24809 , 24810..24839 , 24840..24869 , 24870..24899 , 24900..24929 , 24930..24959 , 24960..24989 , 24990..25019 , 25020..25049 , 25050..25079 , 25080..25109 , 25110..25139 , 25140..25169 , 25170..25199 , 25200..25229 , 25230..25259 , 25260..25289 , 25290..25319 , 25320..25349 , 25350..25379 , 25380..25409 , 25410..25439 , 25440..25469 , 25470..25499 , 25500..25529 , 25530..25559 , 25560..25589 , 25590..25619 , 25620..25649 , 25650..25679 , 25680..25709 , 25710..25739 , 25740..25769 , 25770..25799 , 25800..25829 , 25830..25859 , 25860..25889 , 25890..25919 , 25920..25949 , 25950..25979 , 25980..26009 , 26010..26039 , 26040..26069 , 26070..26099 , 26100..26129 , 26130..26159 , 26160..26189 , 26190..26219 , 26220..26249 , 26250..26279 , 26280..26309 , 26310..26339 , 26340..26369 , 26370..26399 , 26400..26429 , 26430..26459 , 26460..26489 , 26490..26519 , 26520..26549 , 26550..26579 , 26580..26609 , 26610..26639 , 26640..26669 , 26670..26699 , 26700..26729 , 26730..26759 , 26760..26789 , 26790..26819 , 26820..26849 , 26850..26879 , 26880..26909 , 26910..26939 , 26940..26969 , 26970..26999 , 27000..27029 , 27030..27059 , 27060..27089 , 27090..27119 , 27120..27149 , 27150..27179 , 27180..27209 , 27210..27239 , 27240..27269 , 27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499 , 28500..28529 , 28530..28559 , 28560..28589, >>Next

Circles/530393: I'm really lost. Please help.
find the center and radius of the circle with the given equation.
x^2+y^2-28=0
All help is appreciated!
1 solutions

Answer 350014 by jim_thompson5910(28598) About Me  on 2011-11-12 13:59:38 (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2-28=0


x%5E2%2By%5E2=28


%28x-0%29%5E2%2B%28y-0%29%5E2=%28sqrt%2828%29%29%5E2


The equation is now in %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 form, which is a circle, where h=0, k=0 and r=sqrt%2828%29


Remember that the center is (h,k) and the radius is r.


So the center is (0,0) and the radius is sqrt%2828%29 units.


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


test/530398:
1 solutions

Answer 350013 by jim_thompson5910(28598) About Me  on 2011-11-12 13:55:36 (Show Source):
You can put this solution on YOUR website!
There's nothing here...please post a problem.


Signed-numbers/530401: I am stuck on the answer to this, I know what it is, but how it was solved
How did it get to 33 over 12 (33/12)
26 = -7 + 12p
1 solutions

Answer 350012 by jim_thompson5910(28598) About Me  on 2011-11-12 13:55:09 (Show Source):


absolute-value/530403: evaluate [40+(-8)]
1 solutions

Answer 350011 by jim_thompson5910(28598) About Me  on 2011-11-12 13:53:17 (Show Source):
You can put this solution on YOUR website!
[40+(-8)] = [40-8] = [32] = 32


Miscellaneous_Word_Problems/530247: Marcy has a locker at school. the locker number is 2 digits. Each digit is 1,2,3 or 7, and the digits are different. The number is prime number that is 1 greater than a multiple of 8. What could the locker number be?
1 solutions

Answer 349980 by jim_thompson5910(28598) About Me  on 2011-11-11 23:56:15 (Show Source):
You can put this solution on YOUR website!
List out all the possible combos and you'll find that only 17 and 73 are the only numbers that fit the description.


Equations/530262: factor
x^3+8x^2+2x+16
1 solutions

Answer 349979 by jim_thompson5910(28598) About Me  on 2011-11-11 23:53:29 (Show Source):
You can put this solution on YOUR website!

x%5E3%2B8x%5E2%2B2x%2B16 Start with the given expression


%28x%5E3%2B8x%5E2%29%2B%282x%2B16%29 Group the terms in two pairs


x%5E2%28x%2B8%29%2B2%28x%2B8%29 Factor out the GCF x%5E2 out of the first group. Factor out the GCF 2 out of the second group


%28x%5E2%2B2%29%28x%2B8%29 Since we have the common term x%2B8, we can combine like terms


So x%5E3%2B8x%5E2%2B2x%2B16 factors to %28x%5E2%2B2%29%28x%2B8%29


In other words, x%5E3%2B8x%5E2%2B2x%2B16=%28x%5E2%2B2%29%28x%2B8%29


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Equations/530236: (18x^2-63x+81)divided by 9
1 solutions

Answer 349965 by jim_thompson5910(28598) About Me  on 2011-11-11 21:38:45 (Show Source):
You can put this solution on YOUR website!
%2818x%5E2-63x%2B81%29%2F9


%2818x%5E2%29%2F9%2B%28-63x%29%2F9%2B%2881%29%2F9


2x%5E2-7x%2B9


So %2818x%5E2-63x%2B81%29%2F9=2x%5E2-7x%2B9


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim



Linear-systems/530230: solve by substitution x+2y=8 and x+3y=12
1 solutions

Answer 349959 by jim_thompson5910(28598) About Me  on 2011-11-11 21:24:00 (Show Source):
You can put this solution on YOUR website!
Hint: Solve for x in equation 1 to get x = 8-2y

Now plug in x = 8-2y into x+3y=12 to get 8-2y + 3y = 12


From here, solve for y. Once you have a value for y, use it to find x.


Linear-equations/530233: Given: m = (y2 - y1)/x2 - x1), y = mx + b, and the points (-2, 2) and (2, 4).
Find the y-intercept. Write the equation of the line in slope-intercept form
1 solutions

Answer 349958 by jim_thompson5910(28598) About Me  on 2011-11-11 21:22:29 (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=-2 and y%5B1%5D=2.
Also, is the second point . So this means that x%5B2%5D=2 and y%5B2%5D=4.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%284-2%29%2F%282--2%29 Plug in y%5B2%5D=4, y%5B1%5D=2, x%5B2%5D=2, and x%5B1%5D=-2


m=%282%29%2F%282--2%29 Subtract 2 from 4 to get 2


m=%282%29%2F%284%29 Subtract -2 from 2 to get 4


m=1%2F2 Reduce


So the slope of the line that goes through the points and is m=1%2F2


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-2=%281%2F2%29%28x--2%29 Plug in m=1%2F2, x%5B1%5D=-2, and y%5B1%5D=2


y-2=%281%2F2%29%28x%2B2%29 Rewrite x--2 as x%2B2


y-2=%281%2F2%29x%2B%281%2F2%29%282%29 Distribute


y-2=%281%2F2%29x%2B1 Multiply


y=%281%2F2%29x%2B1%2B2 Add 2 to both sides.


y=%281%2F2%29x%2B3 Combine like terms.


So the equation that goes through the points and is y=%281%2F2%29x%2B3


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Linear-systems/530221: solve by substitution y=0.5x+2 and -y=-2x+4
1 solutions

Answer 349953 by jim_thompson5910(28598) About Me  on 2011-11-11 21:05:03 (Show Source):
You can put this solution on YOUR website!
Hint: Start with -y=-2x+4 and replace 'y' with 0.5x+2 to get


-(0.5x+2) = -2x+4


Solve for x. Once you have a solution for x, plug it into y = 0.5x+2 to find y.


Polynomials-and-rational-expressions/530219: factor completely 10x^2-29x-3
1 solutions

Answer 349947 by jim_thompson5910(28598) About Me  on 2011-11-11 20:50:14 (Show Source):
You can put this solution on YOUR website!

Looking at the expression 10x%5E2-29x-3, we can see that the first coefficient is 10, the second coefficient is -29, and the last term is -3.


Now multiply the first coefficient 10 by the last term -3 to get %2810%29%28-3%29=-30.


Now the question is: what two whole numbers multiply to -30 (the previous product) and add to the second coefficient -29?


To find these two numbers, we need to list all of the factors of -30 (the previous product).


Factors of -30:
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -30.
1*(-30) = -30
2*(-15) = -30
3*(-10) = -30
5*(-6) = -30
(-1)*(30) = -30
(-2)*(15) = -30
(-3)*(10) = -30
(-5)*(6) = -30

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -29:


First NumberSecond NumberSum
1-301+(-30)=-29
2-152+(-15)=-13
3-103+(-10)=-7
5-65+(-6)=-1
-130-1+30=29
-215-2+15=13
-310-3+10=7
-56-5+6=1



From the table, we can see that the two numbers 1 and -30 add to -29 (the middle coefficient).


So the two numbers 1 and -30 both multiply to -30 and add to -29


Now replace the middle term -29x with x-30x. Remember, 1 and -30 add to -29. So this shows us that x-30x=-29x.


10x%5E2%2Bhighlight%28x-30x%29-3 Replace the second term -29x with x-30x.


%2810x%5E2%2Bx%29%2B%28-30x-3%29 Group the terms into two pairs.


x%2810x%2B1%29%2B%28-30x-3%29 Factor out the GCF x from the first group.


x%2810x%2B1%29-3%2810x%2B1%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x-3%29%2810x%2B1%29 Combine like terms. Or factor out the common term 10x%2B1


===============================================================


Answer:


So 10x%5E2-29x-3 factors to %28x-3%29%2810x%2B1%29.


In other words, 10x%5E2-29x-3=%28x-3%29%2810x%2B1%29.


Note: you can check the answer by expanding %28x-3%29%2810x%2B1%29 to get 10x%5E2-29x-3 or by graphing the original expression and the answer (the two graphs should be identical).


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Geometry_proofs/530218: the last statement on my graph has segment ab is congruent to segment dc.
thats my question..
this is the problem..
given: segment ae congruent to segment de,
segment be congruent to segment ce.
prove: segment ab congruent to segment dc.
Statements. Reasons
1.Segment AE congr. segment DE| Given
2.Segment BE congr. Segment CE| Given
3.Angle AEB congr. Angle DEC | Alternate Interior Angles Thm.
4.Triangle AEB congr. Triangle DEC|SAS Congruence postulate
5.Segment AB congr. segment DE| *blank*
------------------------------------------------------------------
i dont get #5.
please help. i need this answer by tonight and i cant find it in my book.
1 solutions

Answer 349946 by jim_thompson5910(28598) About Me  on 2011-11-11 20:46:29 (Show Source):
You can put this solution on YOUR website!
Do you have a picture to go along with this?


logarithm/530212: what is -5ln(x)+ln(3y)-ln(2z) as a single logarithm?
1 solutions

Answer 349945 by jim_thompson5910(28598) About Me  on 2011-11-11 20:41:51 (Show Source):
You can put this solution on YOUR website!
-5ln(x)+ln(3y)-ln(2z)


ln(3y)-5ln(x)-ln(2z)


ln(3y)-(5ln(x)+ln(2z))


ln(3y)-(ln(x^5)+ln(2z))


ln[ (3y)/(x^5*2z) ]



Probability-and-statistics/530215: One card is selected at random from a deck of cards. Determine the probability that the card selected is a diamond.
1 solutions

Answer 349943 by jim_thompson5910(28598) About Me  on 2011-11-11 20:40:21 (Show Source):
You can put this solution on YOUR website!
P(Diamond) = (# of diamonds)/(# of cards total)


P(Diamond) = 13/52


P(Diamond) = 1/4


Polynomials-and-rational-expressions/530214: The scale on a map indicates that 1 inch on the map corresponds to an actual distance of 105 miles. Two cities are 4.5 inches apart on the map. What is the actual distance between the two cities?
1 solutions

Answer 349942 by jim_thompson5910(28598) About Me  on 2011-11-11 20:39:23 (Show Source):
You can put this solution on YOUR website!
1/105 = 4.5/x


1x = 105*4.5


x = 472.5


So the two cities are 472.5 miles apart.


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Inequalities/530209: Could you help me solve this problem +6b-1+%3C=+41 or 2b%2B1+%3E=+11+
1 solutions

Answer 349938 by jim_thompson5910(28598) About Me  on 2011-11-11 20:22:54 (Show Source):
You can put this solution on YOUR website!
+6b-1+%3C=+41 or 2b%2B1+%3E=+11+


+6b+%3C=+41%2B1 or 2b+%3E=+11-1+


+6b+%3C=+42 or 2b+%3E=+10+


+b+%3C=+42%2F6 or b+%3E=+10%2F2+


+b+%3C=+7 or b+%3E=+5+


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Expressions-with-variables/530205: what is the slope of the line parallel to this, y = -4/3x - 9
1 solutions

Answer 349936 by jim_thompson5910(28598) About Me  on 2011-11-11 20:03:19 (Show Source):
You can put this solution on YOUR website!
Hint: Parallel lines have the same slope and the slope of y = mx+b is m


Probability-and-statistics/530188: A committee contains 9 women and 6 men. If we choose three random people for a subcommittee, how many ways could we choose exactly 1 woman?
Here's my work: # ways to pick 1 woman: 9C1 = 9
# ways to pick 2 men: 6C2 = 15
Answer: 135 ways to choose exactly 1 woman
Is this answer correct? If not, could you explain the steps and answer?
Really appreciate an answer to this. Need to submit homework online tonight!
1 solutions

Answer 349925 by jim_thompson5910(28598) About Me  on 2011-11-11 19:06:47 (Show Source):
You can put this solution on YOUR website!
You are correct, congrats. This is of course assuming that order does not matter.


Sequences-and-series/530187: the sum of the square are two consecutive positive integers is 221. find the integers? i put as the answer 4,5?
1 solutions

Answer 349923 by jim_thompson5910(28598) About Me  on 2011-11-11 19:01:18 (Show Source):
You can put this solution on YOUR website!
No, you are incorrect since 4^2 + 5^2 = 16+25 = 41


"the sum of the square are two consecutive positive integers is 221" means that x%5E2%2B%28x%2B1%29%5E2=221

Note: in the phrase above, I think you truly mean "the sum of the squares of two consecutive positive integers is 221"



x%5E2%2Bx%5E2%2B2x%2B1=221


x%5E2%2Bx%5E2%2B2x%2B1-221=0


2x%5E2%2B2x-220=0


2%28x%5E2%2Bx-110%29=0


2%28x-10%29%28x%2B11%29=0


x-10=0 or x%2B11=0


x=10 or x=-11


Assuming you want positive integers only, the answer is x=10


So the two integers are 10 and 11


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Polynomials-and-rational-expressions/530186: Find the factor of:
2a + 7
-----------
a2 - 2a - 15

1 solutions

Answer 349922 by jim_thompson5910(28598) About Me  on 2011-11-11 18:54:23 (Show Source):
You can put this solution on YOUR website!
you mean factor a^2 - 2a - 15 ?





Looking at the expression a%5E2-2a-15, we can see that the first coefficient is 1, the second coefficient is -2, and the last term is -15.


Now multiply the first coefficient 1 by the last term -15 to get %281%29%28-15%29=-15.


Now the question is: what two whole numbers multiply to -15 (the previous product) and add to the second coefficient -2?


To find these two numbers, we need to list all of the factors of -15 (the previous product).


Factors of -15:
1,3,5,15
-1,-3,-5,-15


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -15.
1*(-15) = -15
3*(-5) = -15
(-1)*(15) = -15
(-3)*(5) = -15

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -2:


First NumberSecond NumberSum
1-151+(-15)=-14
3-53+(-5)=-2
-115-1+15=14
-35-3+5=2



From the table, we can see that the two numbers 3 and -5 add to -2 (the middle coefficient).


So the two numbers 3 and -5 both multiply to -15 and add to -2


Now replace the middle term -2a with 3a-5a. Remember, 3 and -5 add to -2. So this shows us that 3a-5a=-2a.


a%5E2%2Bhighlight%283a-5a%29-15 Replace the second term -2a with 3a-5a.


%28a%5E2%2B3a%29%2B%28-5a-15%29 Group the terms into two pairs.


a%28a%2B3%29%2B%28-5a-15%29 Factor out the GCF a from the first group.


a%28a%2B3%29-5%28a%2B3%29 Factor out 5 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28a-5%29%28a%2B3%29 Combine like terms. Or factor out the common term a%2B3


===============================================================


Answer:


So a%5E2-2a-15 factors to %28a-5%29%28a%2B3%29.


In other words, a%5E2-2a-15=%28a-5%29%28a%2B3%29.


Note: you can check the answer by expanding %28a-5%29%28a%2B3%29 to get a%5E2-2a-15 or by graphing the original expression and the answer (the two graphs should be identical).


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


test/530162:
1 solutions

Answer 349914 by jim_thompson5910(28598) About Me  on 2011-11-11 17:48:39 (Show Source):
You can put this solution on YOUR website!
There's nothing here....Please post a problem.


Quadratic_Equations/530156: -7ab/a, a not equal to 0

1 solutions

Answer 349912 by jim_thompson5910(28598) About Me  on 2011-11-11 17:24:30 (Show Source):


Linear-equations/530138: What is the equation of the line that passes through the points (-8,-1) and (-2,23)?
1 solutions

Answer 349909 by jim_thompson5910(28598) About Me  on 2011-11-11 16:52:36 (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=-8 and y%5B1%5D=-1.
Also, is the second point . So this means that x%5B2%5D=-2 and y%5B2%5D=23.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%2823--1%29%2F%28-2--8%29 Plug in y%5B2%5D=23, y%5B1%5D=-1, x%5B2%5D=-2, and x%5B1%5D=-8


m=%2824%29%2F%28-2--8%29 Subtract -1 from 23 to get 24


m=%2824%29%2F%286%29 Subtract -8 from -2 to get 6


m=4 Reduce


So the slope of the line that goes through the points and is m=4


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y--1=4%28x--8%29 Plug in m=4, x%5B1%5D=-8, and y%5B1%5D=-1


y--1=4%28x%2B8%29 Rewrite x--8 as x%2B8


y%2B1=4%28x%2B8%29 Rewrite y--1 as y%2B1


y%2B1=4x%2B4%288%29 Distribute


y%2B1=4x%2B32 Multiply


y=4x%2B32-1 Subtract 1 from both sides.


y=4x%2B31 Combine like terms.


So the equation that goes through the points and is y=4x%2B31


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Linear-equations/530135: What is the slope of the line that passes through the points (–2, 5) and (1, 4)?
1 solutions

Answer 349907 by jim_thompson5910(28598) About Me  on 2011-11-11 16:41:28 (Show Source):
You can put this solution on YOUR website!
Note: is the first point . So this means that x%5B1%5D=-2 and y%5B1%5D=5.
Also, is the second point . So this means that x%5B2%5D=1 and y%5B2%5D=4.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%284-5%29%2F%281--2%29 Plug in y%5B2%5D=4, y%5B1%5D=5, x%5B2%5D=1, and x%5B1%5D=-2


m=%28-1%29%2F%281--2%29 Subtract 5 from 4 to get -1


m=%28-1%29%2F%283%29 Subtract -2 from 1 to get 3


So the slope of the line that goes through the points and is m=-1%2F3


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim



Radicals/530101: square x-10 =5
1 solutions

Answer 349884 by jim_thompson5910(28598) About Me  on 2011-11-11 15:25:50 (Show Source):


Systems-of-equations/530105: question: Using complete sentences, explain which method you would use to solve the following system of equations and why. In your answer, include the solution to one of the variables and how you found it using the method you chose.
x – 5y + 2z = 0
x + 4y – z = 12
2x – y + 3z = 10
MY answer: in this equation i used the elimination method because its easiest for me.
addition eliminates x and y so i am solving for z
i got: 0+0-2z=2
then i multiplied by -1 and got 2z= -2
then i divided both sides by 2 and my final answer is: z= -1
1 solutions

Answer 349883 by jim_thompson5910(28598) About Me  on 2011-11-11 15:24:16 (Show Source):
You can put this solution on YOUR website!
You have the correct answer for z. Good job.

Now use that answer to find x and y.


Sequences-and-series/530104: I need the fourth term in the following sequence and how you got it.
1,4,27,n,6125
1 solutions

Answer 349881 by jim_thompson5910(28598) About Me  on 2011-11-11 15:22:23 (Show Source):
You can put this solution on YOUR website!
1 = 1^1
4 = 2^2
27 = 3^3
...

Starting to see the pattern?

The next number is then

n = 256 = 4^4

then the next number is

3125 = 5^5 ... Note: you may have a typo in the problem


Linear-equations/530095: Write the slope-intercept equation for the line that passes through (-4, -3) and (-6, 7).
1 solutions

Answer 349877 by jim_thompson5910(28598) About Me  on 2011-11-11 14:51:00 (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=-4 and y%5B1%5D=-3.
Also, is the second point . So this means that x%5B2%5D=-6 and y%5B2%5D=7.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%287--3%29%2F%28-6--4%29 Plug in y%5B2%5D=7, y%5B1%5D=-3, x%5B2%5D=-6, and x%5B1%5D=-4


m=%2810%29%2F%28-6--4%29 Subtract -3 from 7 to get 10


m=%2810%29%2F%28-2%29 Subtract -4 from -6 to get -2


m=-5 Reduce


So the slope of the line that goes through the points and is m=-5


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y--3=-5%28x--4%29 Plug in m=-5, x%5B1%5D=-4, and y%5B1%5D=-3


y--3=-5%28x%2B4%29 Rewrite x--4 as x%2B4


y%2B3=-5%28x%2B4%29 Rewrite y--3 as y%2B3


y%2B3=-5x%2B-5%284%29 Distribute


y%2B3=-5x-20 Multiply


y=-5x-20-3 Subtract 3 from both sides.


y=-5x-23 Combine like terms.


So the equation that goes through the points and is y=-5x-23


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Functions/530093: is x=-2 a function?
1 solutions

Answer 349876 by jim_thompson5910(28598) About Me  on 2011-11-11 14:49:03 (Show Source):
You can put this solution on YOUR website!
No, it's not a function because the graph violates the vertical line test.

Also, the one input x = -2 maps to more than one output. So it cannot be a function.


Polynomials-and-rational-expressions/530088: factor the following polynomial:
12a^2+8a-15
1 solutions

Answer 349872 by jim_thompson5910(28598) About Me  on 2011-11-11 14:10:30 (Show Source):
You can put this solution on YOUR website!

Looking at the expression 12a%5E2%2B8a-15, we can see that the first coefficient is 12, the second coefficient is 8, and the last term is -15.


Now multiply the first coefficient 12 by the last term -15 to get %2812%29%28-15%29=-180.


Now the question is: what two whole numbers multiply to -180 (the previous product) and add to the second coefficient 8?


To find these two numbers, we need to list all of the factors of -180 (the previous product).


Factors of -180:
1,2,3,4,5,6,9,10,12,15,18,20,30,36,45,60,90,180
-1,-2,-3,-4,-5,-6,-9,-10,-12,-15,-18,-20,-30,-36,-45,-60,-90,-180


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -180.
1*(-180) = -180
2*(-90) = -180
3*(-60) = -180
4*(-45) = -180
5*(-36) = -180
6*(-30) = -180
9*(-20) = -180
10*(-18) = -180
12*(-15) = -180
(-1)*(180) = -180
(-2)*(90) = -180
(-3)*(60) = -180
(-4)*(45) = -180
(-5)*(36) = -180
(-6)*(30) = -180
(-9)*(20) = -180
(-10)*(18) = -180
(-12)*(15) = -180

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 8:


First NumberSecond NumberSum
1-1801+(-180)=-179
2-902+(-90)=-88
3-603+(-60)=-57
4-454+(-45)=-41
5-365+(-36)=-31
6-306+(-30)=-24
9-209+(-20)=-11
10-1810+(-18)=-8
12-1512+(-15)=-3
-1180-1+180=179
-290-2+90=88
-360-3+60=57
-445-4+45=41
-536-5+36=31
-630-6+30=24
-920-9+20=11
-1018-10+18=8
-1215-12+15=3



From the table, we can see that the two numbers -10 and 18 add to 8 (the middle coefficient).


So the two numbers -10 and 18 both multiply to -180 and add to 8


Now replace the middle term 8a with -10a%2B18a. Remember, -10 and 18 add to 8. So this shows us that -10a%2B18a=8a.


12a%5E2%2Bhighlight%28-10a%2B18a%29-15 Replace the second term 8a with -10a%2B18a.


%2812a%5E2-10a%29%2B%2818a-15%29 Group the terms into two pairs.


2a%286a-5%29%2B%2818a-15%29 Factor out the GCF 2a from the first group.


2a%286a-5%29%2B3%286a-5%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%282a%2B3%29%286a-5%29 Combine like terms. Or factor out the common term 6a-5


===============================================================


Answer:


So 12a%5E2%2B8a-15 factors to %282a%2B3%29%286a-5%29.


In other words, 12a%5E2%2B8a-15=%282a%2B3%29%286a-5%29.


Note: you can check the answer by expanding %282a%2B3%29%286a-5%29 to get 12a%5E2%2B8a-15 or by graphing the original expression and the answer (the two graphs should be identical).


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim


Equations/530075: 3x+5-2x=25
1 solutions

Answer 349871 by jim_thompson5910(28598) About Me  on 2011-11-11 14:02:07 (Show Source):
You can put this solution on YOUR website!
3x%2B5-2x=25 Start with the given equation.


x%2B5=25 Combine like terms on the left side.


x=25-5 Subtract 5 from both sides.


x=20 Combine like terms on the right side.


----------------------------------------------------------------------

Answer:

So the solution is x=20


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim