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Numeric_Fractions/540613: I need help solving this problem really bad factor: b^2+8ab-20c^2 1 solutions
Answer 354440 by jim_thompson5910(28598) on 2011-12-05 18:31:09 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last coefficient is  .
Now multiply the first coefficient  by the last coefficient  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,4,5,10,20
-1,-2,-4,-5,-10,-20
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-20) = -20
2*(-10) = -20
4*(-5) = -20
(-1)*(20) = -20
(-2)*(10) = -20
(-4)*(5) = -20
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -20 | 1+(-20)=-19 | | 2 | -10 | 2+(-10)=-8 | | 4 | -5 | 4+(-5)=-1 | | -1 | 20 | -1+20=19 | | -2 | 10 | -2+10=8 | | -4 | 5 | -4+5=1 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Equations/541570: solve for x. Express your answer in interval notation. 8-2(3-x)< 12
I really appreciate help from you guys,! Thanks to you I still might be able to pass my math class!
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1 solutions
Answer 354210 by jim_thompson5910(28598) on 2011-12-04 19:51:54 (Show Source):
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Linear-equations/541348: Find the slope and y-intercept of the graph of the equation Ax+By=C where B is not equal to 0. Use your results to find the slope and y-intercept of the graph of 3x+2y=18 1 solutions
Answer 354157 by jim_thompson5910(28598) on 2011-12-04 14:16:40 (Show Source):
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Probability-and-statistics/541321: You are trying your luck to win the lottery. There are 50 numbers on the lottery ticket to choose from. In order to win you must pick the correct six numbers.
Find the probability of selecting exactly one of the 6 correct winning numbers, where the order in which these numbers are selected does not matter from the set of positive numbers not exceeding 50 (that is the positive integers from 1,2,3,4,5,6...50)
So far I know that the denominator is 50C6 but I cannot figure out the numerator. Any help would be appreciated, thank you. 1 solutions
Answer 354153 by jim_thompson5910(28598) on 2011-12-04 13:41:11 (Show Source):
You can put this solution on YOUR website!The answer to your question can be found buried in the sentence "Find the probability of selecting exactly ONE of the 6 correct winning numbers..."
So the numerator is simply 1.
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Radicals/541275: Factor completely
180w^2+300wf+125f^2 1 solutions
Answer 354140 by jim_thompson5910(28598) on 2011-12-04 12:46:26 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Factor out the GCF  .
Now let's try to factor the inner expression
---------------------------------------------------------------
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last coefficient is  .
Now multiply the first coefficient  by the last coefficient  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,5,6,9,10,12,15,18,20,25,30,36,45,50,60,75,90,100,150,180,225,300,450,900
-1,-2,-3,-4,-5,-6,-9,-10,-12,-15,-18,-20,-25,-30,-36,-45,-50,-60,-75,-90,-100,-150,-180,-225,-300,-450,-900
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*900 = 900
2*450 = 900
3*300 = 900
4*225 = 900
5*180 = 900
6*150 = 900
9*100 = 900
10*90 = 900
12*75 = 900
15*60 = 900
18*50 = 900
20*45 = 900
25*36 = 900
30*30 = 900
(-1)*(-900) = 900
(-2)*(-450) = 900
(-3)*(-300) = 900
(-4)*(-225) = 900
(-5)*(-180) = 900
(-6)*(-150) = 900
(-9)*(-100) = 900
(-10)*(-90) = 900
(-12)*(-75) = 900
(-15)*(-60) = 900
(-18)*(-50) = 900
(-20)*(-45) = 900
(-25)*(-36) = 900
(-30)*(-30) = 900
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 900 | 1+900=901 | | 2 | 450 | 2+450=452 | | 3 | 300 | 3+300=303 | | 4 | 225 | 4+225=229 | | 5 | 180 | 5+180=185 | | 6 | 150 | 6+150=156 | | 9 | 100 | 9+100=109 | | 10 | 90 | 10+90=100 | | 12 | 75 | 12+75=87 | | 15 | 60 | 15+60=75 | | 18 | 50 | 18+50=68 | | 20 | 45 | 20+45=65 | | 25 | 36 | 25+36=61 | | 30 | 30 | 30+30=60 | | -1 | -900 | -1+(-900)=-901 | | -2 | -450 | -2+(-450)=-452 | | -3 | -300 | -3+(-300)=-303 | | -4 | -225 | -4+(-225)=-229 | | -5 | -180 | -5+(-180)=-185 | | -6 | -150 | -6+(-150)=-156 | | -9 | -100 | -9+(-100)=-109 | | -10 | -90 | -10+(-90)=-100 | | -12 | -75 | -12+(-75)=-87 | | -15 | -60 | -15+(-60)=-75 | | -18 | -50 | -18+(-50)=-68 | | -20 | -45 | -20+(-45)=-65 | | -25 | -36 | -25+(-36)=-61 | | -30 | -30 | -30+(-30)=-60 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
 Condense the terms.
--------------------------------------------------
So  then factors further to
===============================================================
Answer:
So  completely factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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