See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'jim_thompson5910'

jim_thompson5910 answered: 28703 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069 , 17070..17099 , 17100..17129 , 17130..17159 , 17160..17189 , 17190..17219 , 17220..17249 , 17250..17279 , 17280..17309 , 17310..17339 , 17340..17369 , 17370..17399 , 17400..17429 , 17430..17459 , 17460..17489 , 17490..17519 , 17520..17549 , 17550..17579 , 17580..17609 , 17610..17639 , 17640..17669 , 17670..17699 , 17700..17729 , 17730..17759 , 17760..17789 , 17790..17819 , 17820..17849 , 17850..17879 , 17880..17909 , 17910..17939 , 17940..17969 , 17970..17999 , 18000..18029 , 18030..18059 , 18060..18089 , 18090..18119 , 18120..18149 , 18150..18179 , 18180..18209 , 18210..18239 , 18240..18269 , 18270..18299 , 18300..18329 , 18330..18359 , 18360..18389 , 18390..18419 , 18420..18449 , 18450..18479 , 18480..18509 , 18510..18539 , 18540..18569 , 18570..18599 , 18600..18629 , 18630..18659 , 18660..18689 , 18690..18719 , 18720..18749 , 18750..18779 , 18780..18809 , 18810..18839 , 18840..18869 , 18870..18899 , 18900..18929 , 18930..18959 , 18960..18989 , 18990..19019 , 19020..19049 , 19050..19079 , 19080..19109 , 19110..19139 , 19140..19169 , 19170..19199 , 19200..19229 , 19230..19259 , 19260..19289 , 19290..19319 , 19320..19349 , 19350..19379 , 19380..19409 , 19410..19439 , 19440..19469 , 19470..19499 , 19500..19529 , 19530..19559 , 19560..19589 , 19590..19619 , 19620..19649 , 19650..19679 , 19680..19709 , 19710..19739 , 19740..19769 , 19770..19799 , 19800..19829 , 19830..19859 , 19860..19889 , 19890..19919 , 19920..19949 , 19950..19979 , 19980..20009 , 20010..20039 , 20040..20069 , 20070..20099 , 20100..20129 , 20130..20159 , 20160..20189 , 20190..20219 , 20220..20249 , 20250..20279 , 20280..20309 , 20310..20339 , 20340..20369 , 20370..20399 , 20400..20429 , 20430..20459 , 20460..20489 , 20490..20519 , 20520..20549 , 20550..20579 , 20580..20609 , 20610..20639 , 20640..20669 , 20670..20699 , 20700..20729 , 20730..20759 , 20760..20789 , 20790..20819 , 20820..20849 , 20850..20879 , 20880..20909 , 20910..20939 , 20940..20969 , 20970..20999 , 21000..21029 , 21030..21059 , 21060..21089 , 21090..21119 , 21120..21149 , 21150..21179 , 21180..21209 , 21210..21239 , 21240..21269 , 21270..21299 , 21300..21329 , 21330..21359 , 21360..21389 , 21390..21419 , 21420..21449 , 21450..21479 , 21480..21509 , 21510..21539 , 21540..21569 , 21570..21599 , 21600..21629 , 21630..21659 , 21660..21689 , 21690..21719 , 21720..21749 , 21750..21779 , 21780..21809 , 21810..21839 , 21840..21869 , 21870..21899 , 21900..21929 , 21930..21959 , 21960..21989 , 21990..22019 , 22020..22049 , 22050..22079 , 22080..22109 , 22110..22139 , 22140..22169 , 22170..22199 , 22200..22229 , 22230..22259 , 22260..22289 , 22290..22319 , 22320..22349 , 22350..22379 , 22380..22409 , 22410..22439 , 22440..22469 , 22470..22499 , 22500..22529 , 22530..22559 , 22560..22589 , 22590..22619 , 22620..22649 , 22650..22679 , 22680..22709 , 22710..22739 , 22740..22769 , 22770..22799 , 22800..22829 , 22830..22859 , 22860..22889 , 22890..22919 , 22920..22949 , 22950..22979 , 22980..23009 , 23010..23039 , 23040..23069 , 23070..23099 , 23100..23129 , 23130..23159 , 23160..23189 , 23190..23219 , 23220..23249 , 23250..23279 , 23280..23309 , 23310..23339 , 23340..23369 , 23370..23399 , 23400..23429 , 23430..23459 , 23460..23489 , 23490..23519 , 23520..23549 , 23550..23579 , 23580..23609 , 23610..23639 , 23640..23669 , 23670..23699 , 23700..23729 , 23730..23759 , 23760..23789 , 23790..23819 , 23820..23849 , 23850..23879 , 23880..23909 , 23910..23939 , 23940..23969 , 23970..23999 , 24000..24029 , 24030..24059 , 24060..24089 , 24090..24119 , 24120..24149 , 24150..24179 , 24180..24209 , 24210..24239 , 24240..24269 , 24270..24299 , 24300..24329 , 24330..24359 , 24360..24389 , 24390..24419 , 24420..24449 , 24450..24479 , 24480..24509 , 24510..24539 , 24540..24569 , 24570..24599 , 24600..24629 , 24630..24659 , 24660..24689 , 24690..24719 , 24720..24749 , 24750..24779 , 24780..24809 , 24810..24839 , 24840..24869 , 24870..24899 , 24900..24929 , 24930..24959 , 24960..24989 , 24990..25019 , 25020..25049 , 25050..25079 , 25080..25109 , 25110..25139 , 25140..25169 , 25170..25199 , 25200..25229 , 25230..25259 , 25260..25289 , 25290..25319 , 25320..25349 , 25350..25379 , 25380..25409 , 25410..25439 , 25440..25469 , 25470..25499 , 25500..25529 , 25530..25559 , 25560..25589 , 25590..25619 , 25620..25649 , 25650..25679 , 25680..25709 , 25710..25739 , 25740..25769 , 25770..25799 , 25800..25829 , 25830..25859 , 25860..25889 , 25890..25919 , 25920..25949 , 25950..25979 , 25980..26009 , 26010..26039 , 26040..26069 , 26070..26099 , 26100..26129 , 26130..26159 , 26160..26189 , 26190..26219 , 26220..26249 , 26250..26279 , 26280..26309 , 26310..26339 , 26340..26369 , 26370..26399 , 26400..26429 , 26430..26459 , 26460..26489 , 26490..26519 , 26520..26549 , 26550..26579 , 26580..26609 , 26610..26639 , 26640..26669 , 26670..26699 , 26700..26729 , 26730..26759 , 26760..26789 , 26790..26819 , 26820..26849 , 26850..26879 , 26880..26909 , 26910..26939 , 26940..26969 , 26970..26999 , 27000..27029 , 27030..27059 , 27060..27089 , 27090..27119 , 27120..27149 , 27150..27179 , 27180..27209 , 27210..27239 , 27240..27269 , 27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499 , 28500..28529 , 28530..28559 , 28560..28589 , 28590..28619 , 28620..28649 , 28650..28679 , 28680..28709, >>Next

Average/550626: perform the indicated operation, and if possible, simplify. please show all of your work. write your final answer exactly as a fraction in lowest terms.
3/14+2/5
1 solutions

Answer 358944 by jim_thompson5910(28715) About Me  on 2011-12-28 12:00:56 (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Fractions Solver


3%2F14%2B2%2F5 Start with the given expression




In order to add these two fractions, these fractions need to have a common denominator.


In order to do that, we simply find that the LCM of 14 and 5 is 70 (note: if you need help with finding the LCM, check out this solver)


Now we need to get each denominator to 70



%285%2F5%29%283%2F14%29%2B2%2F5 Multiply 3%2F14 by %285%2F5%29


15%2F70%2B2%2F5 Multiply 3%2F14 and %285%2F5%29 to get 15%2F70



15%2F70%2B%2814%2F14%29%282%2F5%29 Multiply 2%2F5 by %2814%2F14%29


15%2F70%2B28%2F70 Multiply 2%2F5 and %2814%2F14%29 to get 28%2F70



Since both fractions have a common denominator of 70, we can now combine the fractions


%2815%2B28%29%2F70 Combine the fractions


43%2F70 Add the numerators



So

3%2F14%2B2%2F5=43%2F70



Average/550619: translate the following phrase an algebraic expression
the difference of fifteen and twice a number
1 solutions

Answer 358943 by jim_thompson5910(28715) About Me  on 2011-12-28 11:59:49 (Show Source):
You can put this solution on YOUR website!
"the difference of fifteen and twice a number" translates to 2x-15 where 'x' is the unknown number.


Distributive-associative-commutative-properties/550613: use the commutation law of multiplication to write an equivalent expression.
5(8+x)
1 solutions

Answer 358942 by jim_thompson5910(28715) About Me  on 2011-12-28 11:59:11 (Show Source):
You can put this solution on YOUR website!
5(8+x) is equivalent to (8+x)5 using the commutative law of multiplication


Square-cubic-other-roots/550649: leave a non-perfect square under the radial sign: x^2+23=144. what is a non-perfect square and what is a radical sign?
what I have come up with is x^2+23=144-23; x^2=121; sqrt of 121 is 11
i need to know what a perfect square is and what a radical sign is
1 solutions

Answer 358940 by jim_thompson5910(28715) About Me  on 2011-12-28 11:57:49 (Show Source):
You can put this solution on YOUR website!
A perfect square is a number x such that x=k%5E2 where k is some whole number.


For example, 100 is a perfect square because 100=10%5E2. You can figure out if a number is a perfect square by evaluating the square root of that number. If the square root of that number is a whole number, then that number is a perfect square.

So sqrt%28100%29=10 (which makes it a perfect square), but sqrt%28101%29=10.0498756211209 (which makes it a non-perfect square)


The radical sign is just another way of saying the square root sign.


Note: keep in mind that x = -11 is also a solution along with x = 11


Polynomials-and-rational-expressions/550648: i am helping my son with a worksheet from school and the answer sheet for his worksheet is saying his answer is wrong the question he is stuck on is (2xy)(3xy)(6x^8y^6) he is doing a multiplication of monomials worksheet and the answer he got is 36x^10y^6 is that right or is the worksheet right when it states the answer is 11x^10y^6 and why?
1 solutions

Answer 358938 by jim_thompson5910(28715) About Me  on 2011-12-28 11:49:24 (Show Source):
You can put this solution on YOUR website!
The answer is actually 36x^10y^8, so the worksheet is wrong.


The final coefficient is equal to the product of the other coefficients. So the final coefficient is 2*3*6=6*6=36


Then you multiply the x terms to get x*x*x^8 = x^(1+1+8)=x^10

and then you multiply the y terms to get y*y*y^6 = y^(1+1+6) = y^8


put this all together to get 36x^10y^8


Quadratic_Equations/550612: simplify (5h^9)^6
1 solutions

Answer 358937 by jim_thompson5910(28715) About Me  on 2011-12-28 11:42:17 (Show Source):
You can put this solution on YOUR website!
(5h^9)^6

(5)^6(h^9)^6

15625h^(9*6)

15625h^(54)

So the answer is


Geometric_formulas/550603: what is the equation of the line that passes through (9, -2) and (4,6)?
1 solutions

Answer 358936 by jim_thompson5910(28715) About Me  on 2011-12-28 11:40:59 (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=9 and y%5B1%5D=-2.
Also, is the second point . So this means that x%5B2%5D=4 and y%5B2%5D=6.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%286--2%29%2F%284-9%29 Plug in y%5B2%5D=6, y%5B1%5D=-2, x%5B2%5D=4, and x%5B1%5D=9


m=%288%29%2F%284-9%29 Subtract -2 from 6 to get 8


m=%288%29%2F%28-5%29 Subtract 9 from 4 to get -5


m=-8%2F5 Reduce


So the slope of the line that goes through the points and is m=-8%2F5


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y--2=%28-8%2F5%29%28x-9%29 Plug in m=-8%2F5, x%5B1%5D=9, and y%5B1%5D=-2


y%2B2=%28-8%2F5%29%28x-9%29 Rewrite y--2 as y%2B2


y%2B2=%28-8%2F5%29x%2B%28-8%2F5%29%28-9%29 Distribute


y%2B2=%28-8%2F5%29x%2B72%2F5 Multiply


y=%28-8%2F5%29x%2B72%2F5-2 Subtract 2 from both sides.


y=%28-8%2F5%29x%2B62%2F5 Combine like terms. note: If you need help with fractions, check out this solver.


So the equation that goes through the points and is y=%28-8%2F5%29x%2B62%2F5


Polynomials-and-rational-expressions/550614: divide & simplify 5^13/5^3
1 solutions

Answer 358935 by jim_thompson5910(28715) About Me  on 2011-12-28 11:40:03 (Show Source):
You can put this solution on YOUR website!
5^13/5^3

5^(13-3)

5^10

9765625



So 5^13/5^3 = 9765625


Average/550621: evaluate
2x+7y/30
for x=15 and y=3
write your final answer exactly as a fraction in lowest terms.
1 solutions

Answer 358934 by jim_thompson5910(28715) About Me  on 2011-12-28 11:38:27 (Show Source):
You can put this solution on YOUR website!
(2x+7y)/30

(2*15+7*3)/30

(30+21)/30

51/30

17/10


So (2x+7y)/30 = 17/10 when x=15 and y=3


Square-cubic-other-roots/550647: leave a non-perfect square under the radical sign: 3n^2-2n^2+8=89. how do I solve something like this?
1 solutions

Answer 358933 by jim_thompson5910(28715) About Me  on 2011-12-28 11:36:42 (Show Source):
You can put this solution on YOUR website!
3n^2-2n^2+8=89

3n^2-2n^2=89-8

n^2=81

n=+-sqrt(81)

n=9 or n=-9


Average/550627: write a true sentence using either < or >
-2.172_-2.17
1 solutions

Answer 358932 by jim_thompson5910(28715) About Me  on 2011-12-28 11:35:35 (Show Source):
You can put this solution on YOUR website!
-2.172 < -2.17 since -2.172 is larger in absolute value (so that places it to the left of -2.17)


Sequences-and-series/550646: 1) 3(4x-7)=2(7x+13)
2) x+6
____ = x-12
3
1 solutions

Answer 358931 by jim_thompson5910(28715) About Me  on 2011-12-28 11:33:48 (Show Source):
You can put this solution on YOUR website!
I'll do the first one to get you started.


# 1


3%284x-7%29=2%287x%2B13%29 Start with the given equation.


12x-21=14x%2B26 Distribute.


12x=14x%2B26%2B21 Add 21 to both sides.


12x-14x=26%2B21 Subtract 14x from both sides.


-2x=26%2B21 Combine like terms on the left side.


-2x=47 Combine like terms on the right side.


x=%2847%29%2F%28-2%29 Divide both sides by -2 to isolate x.


x=-47%2F2 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x=-47%2F2


Angles/550566: can you expand this: (4z-3)^2
1 solutions

Answer 358848 by jim_thompson5910(28715) About Me  on 2011-12-27 22:33:01 (Show Source):
You can put this solution on YOUR website!

%284z-3%29%5E2 Start with the given expression.


%284z-3%29%284z-3%29 Expand. Remember something like x%5E2=x%2Ax.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%284z%29-3%29%28highlight%284z%29-3%29 Multiply the First terms:%284%2Az%29%2A%284%2Az%29=16%2Az%5E2.


%28highlight%284z%29-3%29%284z%2Bhighlight%28-3%29%29 Multiply the Outer terms:%284%2Az%29%2A%28-3%29=-12%2Az.


%284z%2Bhighlight%28-3%29%29%28highlight%284z%29-3%29 Multiply the Inner terms:%28-3%29%2A%284%2Az%29=-12%2Az.


%284z%2Bhighlight%28-3%29%29%284z%2Bhighlight%28-3%29%29 Multiply the Last terms:%28-3%29%2A%28-3%29=9.


---------------------------------------------------
So we have the terms: 16%2Az%5E2, -12%2Az, -12%2Az, 9


16%2Az%5E2-12%2Az-12%2Az%2B9 Now add every term listed above to make a single expression.


16z%5E2-24z%2B9 Now combine like terms.


So %284z-3%29%5E2 FOILs to 16z%5E2-24z%2B9.


In other words, %284z-3%29%5E2=16z%5E2-24z%2B9.


logarithm/550554: Solve, 81^(x) = 9^(x+4).
1 solutions

Answer 358840 by jim_thompson5910(28715) About Me  on 2011-12-27 21:34:00 (Show Source):
You can put this solution on YOUR website!
81^(x) = 9^(x+4)


(9^2)^(x) = 9^(x+4)


9^(2x) = 9^(x+4)

-------------------------------------------------------

Since the bases are equal, the exponents are equal.

2x = x+4

2x - x = 4

x = 4


Numbers_Word_Problems/550551: When 18 is subtracted from four times a certain number, the result is 5/2 the original number. What is the number?
1 solutions

Answer 358839 by jim_thompson5910(28715) About Me  on 2011-12-27 21:09:33 (Show Source):
You can put this solution on YOUR website!
"When 18 is subtracted from four times a certain number, the result is 5/2 the original number. " means that we have the equation 4n-18=%285%2F2%29n. Let's solve this equation for n.


4n-18=%285%2F2%29n Start with the given equation.


2%284n-18%29=2%28%285%2Fcross%282%29%29n%29 Multiply both sides by the LCD 2 to clear any fractions.


8n-36=5n Distribute and multiply.


8n=5n%2B36 Add 36 to both sides.


8n-5n=36 Subtract 5n from both sides.


3n=36 Combine like terms on the left side.


n=%2836%29%2F%283%29 Divide both sides by 3 to isolate n.


n=12 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is n=12


So the unknown number is 12


Linear_Equations_And_Systems_Word_Problems/550549: When 18 is subtracted from four times a certain number, the result is the original number. What is the number?
1 solutions

Answer 358838 by jim_thompson5910(28715) About Me  on 2011-12-27 21:07:01 (Show Source):
You can put this solution on YOUR website!
"When 18 is subtracted from four times a certain number, the result is the original number." means that we have the equation 4n-18=n. Let's solve this equation for n.


4n-18=n Start with the given equation.


4n=n%2B18 Add 18 to both sides.


4n-n=18 Subtract n from both sides.


3n=18 Combine like terms on the left side.


n=%2818%29%2F%283%29 Divide both sides by 3 to isolate n.


n=6 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is n=6


So the unknown number is 6


Word_Problems_With_Coins/550541: Find the number of possible ways using only quarters and/or nickels to make $20.
1 solutions

Answer 358837 by jim_thompson5910(28715) About Me  on 2011-12-27 21:00:33 (Show Source):
You can put this solution on YOUR website!
Here are all the possible ways to make $20 using only quarters and/or nickels



# of Quarters    |  # of Nickels
   0                     400
   1                     395
   2                     390
   3                     385
   4                     380
   5                     375
   6                     370
   7                     365
   8                     360
   9                     355
   10                    350
   11                    345
   12                    340
   13                    335
   14                    330
   15                    325
   16                    320
   17                    315
   18                    310
   19                    305
   20                    300
   21                    295
   22                    290
   23                    285
   24                    280
   25                    275
   26                    270
   27                    265
   28                    260
   29                    255
   30                    250
   31                    245
   32                    240
   33                    235
   34                    230
   35                    225
   36                    220
   37                    215
   38                    210
   39                    205
   40                    200
   41                    195
   42                    190
   43                    185
   44                    180
   45                    175
   46                    170
   47                    165
   48                    160
   49                    155
   50                    150
   51                    145
   52                    140
   53                    135
   54                    130
   55                    125
   56                    120
   57                    115
   58                    110
   59                    105
   60                    100
   61                    95
   62                    90
   63                    85
   64                    80
   65                    75
   66                    70
   67                    65
   68                    60
   69                    55
   70                    50
   71                    45
   72                    40
   73                    35
   74                    30
   75                    25
   76                    20
   77                    15
   78                    10
   79                    5
   80                    0



There are 81 ways to make $20 using only quarters and/or nickels


Linear-systems/550539: HELP PLEASE?????
solve using substitution method
3x + 9y = 57
-7x + y = 65
type an ordered pair
1 solutions

Answer 358835 by jim_thompson5910(28715) About Me  on 2011-12-27 20:40:25 (Show Source):
You can put this solution on YOUR website!


Start with the given system of equations:

system%283x%2B9y=57%2C-7x%2By=65%29


Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.


So let's isolate y in the second equation

-7x%2By=65 Start with the second equation


y=65%2B7x Add 7x to both sides


y=%2B7x%2B65 Rearrange the equation


---------------------

Since y=7x%2B65, we can now replace each y in the first equation with 7x%2B65 to solve for x



3x%2B9highlight%28%287x%2B65%29%29=57 Plug in y=7x%2B65 into the second equation. In other words, replace each y with 7x%2B65. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



3x%2B%289%29%287%29x%2B%289%29%2865%29=57 Distribute 9 to 7x%2B65


3x%2B63x%2B585=57 Multiply


66x%2B585=57 Combine like terms on the left side


66x=57-585Subtract 585 from both sides


66x=-528 Combine like terms on the right side


x=%28-528%29%2F%2866%29 Divide both sides by 66 to isolate x



x=-8 Divide





-----------------First Answer------------------------------


So the first part of our answer is: x=-8









Since we know that x=-8 we can plug it into the equation y=7x%2B65 (remember we previously solved for y in the first equation).



y=7x%2B65 Start with the equation where y was previously isolated.


y=7%28-8%29%2B65 Plug in x=-8


y=-56%2B65 Multiply


y=9 Combine like terms



-----------------Second Answer------------------------------


So the second part of our answer is: y=9









-----------------Summary------------------------------

So our answers are:

x=-8 and y=9

which form the point


Now let's graph the two equations (if you need help with graphing, check out this solver)


From the graph, we can see that the two equations intersect at . This visually verifies our answer.




graph of -7x%2By=65 (red) and 3x%2B9y=57 (green) and the intersection of the lines (blue circle).


Numeric_Fractions/550536: 2x^2 - 12x
__________
x - 6
1 solutions

Answer 358834 by jim_thompson5910(28715) About Me  on 2011-12-27 20:07:26 (Show Source):
You can put this solution on YOUR website!
(2x^2 - 12x)/(x-6)

(2x(x - 6))/(x-6)

2x

So (2x^2 - 12x)/(x-6) = 2x


Expressions-with-variables/550535: what is the speed in meters per secound of a paper airplaine that flies 24 meters in 6 secound
1 solutions

Answer 358833 by jim_thompson5910(28715) About Me  on 2011-12-27 20:01:07 (Show Source):
You can put this solution on YOUR website!
The speed is 24/6 = 4 meters per second


Expressions-with-variables/550534: solve for x 3 over 5(x+2)=x-4

1 solutions

Answer 358832 by jim_thompson5910(28715) About Me  on 2011-12-27 19:57:35 (Show Source):
You can put this solution on YOUR website!
%283%2F5%29%28x%2B2%29=x-4 Start with the given equation.


%283%2F5%29x%2B6%2F5=x-4 Distribute.


5%28%283%2Fcross%285%29%29x%2B6%2Fcross%285%29%29=5%28x-4%29 Multiply both sides by the LCD 5 to clear any fractions.


3x%2B6=5x-20 Distribute and multiply.


3x=5x-20-6 Subtract 6 from both sides.


3x-5x=-20-6 Subtract 5x from both sides.


-2x=-20-6 Combine like terms on the left side.


-2x=-26 Combine like terms on the right side.


x=%28-26%29%2F%28-2%29 Divide both sides by -2 to isolate x.


x=13 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x=13


Expressions-with-variables/550533: if a+ar=b+r the value of a in terms of b and r can be expressed as

1 solutions

Answer 358831 by jim_thompson5910(28715) About Me  on 2011-12-27 19:53:59 (Show Source):
You can put this solution on YOUR website!
a+ar=b+r

a(1+r)=b+r

a=(b+r)/(1+r)


Polynomials-and-rational-expressions/550525: Factor completely, if prime, state this
5tˆ3 – 21tˆ2 + 18t

1 solutions

Answer 358827 by jim_thompson5910(28715) About Me  on 2011-12-27 19:23:15 (Show Source):
You can put this solution on YOUR website!

5t%5E3-21t%5E2%2B18t Start with the given expression.


t%285t%5E2-21t%2B18%29 Factor out the GCF t.


Now let's try to factor the inner expression 5t%5E2-21t%2B18


---------------------------------------------------------------


Looking at the expression 5t%5E2-21t%2B18, we can see that the first coefficient is 5, the second coefficient is -21, and the last term is 18.


Now multiply the first coefficient 5 by the last term 18 to get %285%29%2818%29=90.


Now the question is: what two whole numbers multiply to 90 (the previous product) and add to the second coefficient -21?


To find these two numbers, we need to list all of the factors of 90 (the previous product).


Factors of 90:
1,2,3,5,6,9,10,15,18,30,45,90
-1,-2,-3,-5,-6,-9,-10,-15,-18,-30,-45,-90


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 90.
1*90 = 90
2*45 = 90
3*30 = 90
5*18 = 90
6*15 = 90
9*10 = 90
(-1)*(-90) = 90
(-2)*(-45) = 90
(-3)*(-30) = 90
(-5)*(-18) = 90
(-6)*(-15) = 90
(-9)*(-10) = 90

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -21:


First NumberSecond NumberSum
1901+90=91
2452+45=47
3303+30=33
5185+18=23
6156+15=21
9109+10=19
-1-90-1+(-90)=-91
-2-45-2+(-45)=-47
-3-30-3+(-30)=-33
-5-18-5+(-18)=-23
-6-15-6+(-15)=-21
-9-10-9+(-10)=-19



From the table, we can see that the two numbers -6 and -15 add to -21 (the middle coefficient).


So the two numbers -6 and -15 both multiply to 90 and add to -21


Now replace the middle term -21t with -6t-15t. Remember, -6 and -15 add to -21. So this shows us that -6t-15t=-21t.


5t%5E2%2Bhighlight%28-6t-15t%29%2B18 Replace the second term -21t with -6t-15t.


%285t%5E2-6t%29%2B%28-15t%2B18%29 Group the terms into two pairs.


t%285t-6%29%2B%28-15t%2B18%29 Factor out the GCF t from the first group.


t%285t-6%29-3%285t-6%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28t-3%29%285t-6%29 Combine like terms. Or factor out the common term 5t-6


--------------------------------------------------


So t%285t%5E2-21t%2B18%29 then factors further to t%28t-3%29%285t-6%29


===============================================================


Answer:


So 5t%5E3-21t%5E2%2B18t completely factors to t%28t-3%29%285t-6%29.


In other words, 5t%5E3-21t%5E2%2B18t=t%28t-3%29%285t-6%29.


Note: you can check the answer by expanding t%28t-3%29%285t-6%29 to get 5t%5E3-21t%5E2%2B18t or by graphing the original expression and the answer (the two graphs should be identical).


Polynomials-and-rational-expressions/550524: Factor completely. Remember to look first for a common factor. If a polynomial is prime, state this.

6p^2 − 6q^2
1 solutions

Answer 358826 by jim_thompson5910(28715) About Me  on 2011-12-27 19:15:06 (Show Source):
You can put this solution on YOUR website!
6p^2-6q^2

6(p^2-q^2)

6(p-q)(p+q)


Polynomials-and-rational-expressions/550523: Factor completely. If a polynomial is prime, state this.
6x2 + 19x + 10
1 solutions

Answer 358825 by jim_thompson5910(28715) About Me  on 2011-12-27 19:01:40 (Show Source):
You can put this solution on YOUR website!
Looking at the expression 6x%5E2%2B19x%2B10, we can see that the first coefficient is 6, the second coefficient is 19, and the last term is 10.


Now multiply the first coefficient 6 by the last term 10 to get %286%29%2810%29=60.


Now the question is: what two whole numbers multiply to 60 (the previous product) and add to the second coefficient 19?


To find these two numbers, we need to list all of the factors of 60 (the previous product).


Factors of 60:
1,2,3,4,5,6,10,12,15,20,30,60
-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 60.
1*60 = 60
2*30 = 60
3*20 = 60
4*15 = 60
5*12 = 60
6*10 = 60
(-1)*(-60) = 60
(-2)*(-30) = 60
(-3)*(-20) = 60
(-4)*(-15) = 60
(-5)*(-12) = 60
(-6)*(-10) = 60

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 19:


First NumberSecond NumberSum
1601+60=61
2302+30=32
3203+20=23
4154+15=19
5125+12=17
6106+10=16
-1-60-1+(-60)=-61
-2-30-2+(-30)=-32
-3-20-3+(-20)=-23
-4-15-4+(-15)=-19
-5-12-5+(-12)=-17
-6-10-6+(-10)=-16



From the table, we can see that the two numbers 4 and 15 add to 19 (the middle coefficient).


So the two numbers 4 and 15 both multiply to 60 and add to 19


Now replace the middle term 19x with 4x%2B15x. Remember, 4 and 15 add to 19. So this shows us that 4x%2B15x=19x.


6x%5E2%2Bhighlight%284x%2B15x%29%2B10 Replace the second term 19x with 4x%2B15x.


%286x%5E2%2B4x%29%2B%2815x%2B10%29 Group the terms into two pairs.


2x%283x%2B2%29%2B%2815x%2B10%29 Factor out the GCF 2x from the first group.


2x%283x%2B2%29%2B5%283x%2B2%29 Factor out 5 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%282x%2B5%29%283x%2B2%29 Combine like terms. Or factor out the common term 3x%2B2


===============================================================


Answer:


So 6x%5E2%2B19x%2B10 factors to %282x%2B5%29%283x%2B2%29.


In other words, 6x%5E2%2B19x%2B10=%282x%2B5%29%283x%2B2%29.


Note: you can check the answer by expanding %282x%2B5%29%283x%2B2%29 to get 6x%5E2%2B19x%2B10 or by graphing the original expression and the answer (the two graphs should be identical).


Linear-systems/550512: -2x – 8y = -42
-4x + 6y = -18
1 solutions

Answer 358822 by jim_thompson5910(28715) About Me  on 2011-12-27 18:30:54 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:
system%28-2x-8y=-42%2C-4x%2B6y=-18%29


-2%28-2x-8y%29=-2%28-42%29 Multiply the both sides of the first equation by -2.


4x%2B16y=84 Distribute and multiply.


So we have the new system of equations:
system%284x%2B16y=84%2C-4x%2B6y=-18%29


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%284x%2B16y%29%2B%28-4x%2B6y%29=%2884%29%2B%28-18%29


%284x%2B-4x%29%2B%2816y%2B6y%29=84%2B-18 Group like terms.


0x%2B22y=66 Combine like terms.


22y=66 Simplify.


y=%2866%29%2F%2822%29 Divide both sides by 22 to isolate y.


y=3 Reduce.


------------------------------------------------------------------


4x%2B16y=84 Now go back to the first equation.


4x%2B16%283%29=84 Plug in y=3.


4x%2B48=84 Multiply.


4x=84-48 Subtract 48 from both sides.


4x=36 Combine like terms on the right side.


x=%2836%29%2F%284%29 Divide both sides by 4 to isolate x.


x=9 Reduce.


So the solutions are x=9 and y=3.


Which form the ordered pair .


This means that the system is consistent and independent.


Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.


Graph of -2x-8y=-42 (red) and -4x%2B6y=-18 (green)


Linear-systems/550506: HELP!!!!! PLEASE........solve using substitution method....
8x + 2y = 0
-7x + y = 22
type an ordered pair
1 solutions

Answer 358816 by jim_thompson5910(28715) About Me  on 2011-12-27 18:12:09 (Show Source):
You can put this solution on YOUR website!



Start with the given system of equations:

system%288x%2B2y=0%2C-7x%2By=22%29



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the second equation

-7x%2By=22 Start with the second equation


y=22%2B7x Add 7x to both sides


y=7x%2B22 Rearrange the equation


---------------------

Since y=7x%2B22, we can now replace each y in the first equation with 7x%2B22 to solve for x



8x%2B2highlight%28%287x%2B22%29%29=0 Plug in y=7x%2B22 into the first equation. In other words, replace each y with 7x%2B22. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



8x%2B%282%29%287%29x%2B%282%29%2822%29=0 Distribute 2 to 7x%2B22


8x%2B14x%2B44=0 Multiply


22x%2B44=0 Combine like terms on the left side


22x=0-44Subtract 44 from both sides


22x=-44 Combine like terms on the right side


x=%28-44%29%2F%2822%29 Divide both sides by 22 to isolate x



x=-2 Divide





-----------------First Answer------------------------------


So the first part of our answer is: x=-2









Since we know that x=-2 we can plug it into the equation y=7x%2B22 (remember we previously solved for y in the first equation).



y=7x%2B22 Start with the equation where y was previously isolated.


y=7%28-2%29%2B22 Plug in x=-2


y=-14%2B22 Multiply


y=8 Combine like terms



-----------------Second Answer------------------------------


So the second part of our answer is: y=8









-----------------Summary------------------------------

So our answers are:

x=-2 and y=8

which form the point








Now let's graph the two equations (if you need help with graphing, check out this solver)


From the graph, we can see that the two equations intersect at . This visually verifies our answer.




graph of -7x%2By=22 (red) and 8x%2B2y=0 (green) and the intersection of the lines (blue circle).




Conjunction/550503: Use De Morgan’s laws to determine whether the two statements are equivalent. Show your work. ∼(p ∨ ∼q), ∼p ∧ q

1 solutions

Answer 358814 by jim_thompson5910(28715) About Me  on 2011-12-27 17:59:47 (Show Source):
You can put this solution on YOUR website!
~(p V ~q)

~(p) ^ ~(~q)

~p ^ q

So the two expressions are equivalent


Linear-equations/550501: 9x + 11y = 86
9x – 2y = -5
1 solutions

Answer 358809 by jim_thompson5910(28715) About Me  on 2011-12-27 17:55:00 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:
system%289x%2B11y=86%2C9x-2y=-5%29


-1%289x%2B11y%29=-1%2886%29 Multiply the both sides of the first equation by -1.


-9x-11y=-86 Distribute and multiply.


So we have the new system of equations:
system%28-9x-11y=-86%2C9x-2y=-5%29


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%28-9x-11y%29%2B%289x-2y%29=%28-86%29%2B%28-5%29


%28-9x%2B9x%29%2B%28-11y%2B-2y%29=-86%2B-5 Group like terms.


0x%2B-13y=-91 Combine like terms.


-13y=-91 Simplify.


y=%28-91%29%2F%28-13%29 Divide both sides by -13 to isolate y.


y=7 Reduce.


------------------------------------------------------------------


-9x-11y=-86 Now go back to the first equation.


-9x-11%287%29=-86 Plug in y=7.


-9x-77=-86 Multiply.


-9x=-86%2B77 Add 77 to both sides.


-9x=-9 Combine like terms on the right side.


x=%28-9%29%2F%28-9%29 Divide both sides by -9 to isolate x.


x=1 Reduce.


So the solutions are x=1 and y=7.


Which form the ordered pair .


This means that the system is consistent and independent.


Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.


Graph of 9x%2B11y=86 (red) and 9x-2y=-5 (green)


Geometric_formulas/550500: what is the next term in the sequence? 729, -243, 81, -27
1 solutions

Answer 358805 by jim_thompson5910(28715) About Me  on 2011-12-27 17:46:08 (Show Source):
You can put this solution on YOUR website!
You're dividing by -3 each time, so the next term is -27/(-3) = 9


Geometric_formulas/550496: if the complement of an angle measures 22 degrees, what is the measure of its supplement?
1 solutions

Answer 358804 by jim_thompson5910(28715) About Me  on 2011-12-27 17:45:14 (Show Source):
You can put this solution on YOUR website!
Let x = the unknown angle

The complement of angle x is 90-x and because the complement is 22 degrees, we know that 90-x = 22


Solve for x to get -x = 22-90 ---> -x = -68 ---> x = 68


So the original angle is 68 degrees and the supplement of 68 degrees is 180 - 68 = 112 degrees