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Equations/591241: 8x + 3 + x = 5x + 3 + 4x 1 solutions
Answer 375546 by jim_thompson5910(28595) on 2012-03-25 12:25:36 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Simplify.
Since this equation is always true for any x value, this means x can equal any number.
So there are an infinite number of solutions.
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Equations/591061: Can you please help me solve this equation? the equation is: 3x-6x-2=2x-x+3 1 solutions
Answer 375472 by jim_thompson5910(28595) on 2012-03-24 17:28:19 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Equations/590560: 6z-7=2z-2 would the answer be z=6 1 solutions
Answer 375450 by jim_thompson5910(28595) on 2012-03-24 14:42:06 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
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Answer:
So the solution is
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Equations/590567: 3c-15=17-c 1 solutions
Answer 375448 by jim_thompson5910(28595) on 2012-03-24 14:41:14 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Add  to both sides.
 Add  to both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Equations/590599: 2/5x+7=9 1 solutions
Answer 375447 by jim_thompson5910(28595) on 2012-03-24 14:40:30 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Multiply both sides by the LCD  to clear any fractions.
 Distribute and multiply.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Equations/590955: need help : add the following(2b^4-3b^3+4b^2+13b-7)+(b^5+9b^3+4b^2-4b+3)+(-5b^4+b^2-5b-7), simplify your answer 1 solutions
Answer 375446 by jim_thompson5910(28595) on 2012-03-24 14:39:53 (Show Source):
You can put this solution on YOUR website!(2b^4-3b^3+4b^2+13b-7)+(b^5+9b^3+4b^2-4b+3)+(-5b^4+b^2-5b-7)
2b^4-3b^3+4b^2+13b-7+b^5+9b^3+4b^2-4b+3-5b^4+b^2-5b-7
b^5+(2b^4-5b^4)+(-3b^3+9b^3)+(4b^2+4b^2+b^2)+(13b-4b-5b)+(-7+3-7)
b^5-3b^4+6b^3+9b^2+4b-11
So (2b^4-3b^3+4b^2+13b-7)+(b^5+9b^3+4b^2-4b+3)+(-5b^4+b^2-5b-7) completely simplifies to b^5-3b^4+6b^3+9b^2+4b-11
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Graphs/590949: Graph the equation id the Y
y=3/4x-5 1 solutions
Answer 375444 by jim_thompson5910(28595) on 2012-03-24 14:36:37 (Show Source):
You can put this solution on YOUR website!Looking at  we can see that the equation is in slope-intercept form  where the slope is  and the y-intercept is
Since  this tells us that the y-intercept is ) .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is  , this means:
which shows us that the rise is 3 and the run is 4. This means that to go from point to point, we can go up 3 and over 4
So starting at ) , go up 3 units
and to the right 4 units to get to the next point
Now draw a line through these points to graph
 So this is the graph of  through the points ) and
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Functions/591023: 1. domanin and range and function { (-8, -3), (7, -3), (3, 7), (4, 3), (-5, 3)}
13. domanin and range and function( {147, 180), (170, -200), (113, -200)} 1 solutions
Answer 375440 by jim_thompson5910(28595) on 2012-03-24 14:32:43 (Show Source):
You can put this solution on YOUR website!I'll do the first one to get you started.
# 1
Recall that the domain is the set of all allowable inputs. So the domain is the set of allowed 'x' values. The range is the set of possible outputs, so it's the set of possible 'y' values.
So the domain and range are...
Domain: {-8, -5, 3, 4, 7}
Range: {-3, 3, 7}
Note: duplicates are tossed out
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Polynomials-and-rational-expressions/590924: trial and error answer for 2x^2-5x-7 1 solutions
Answer 375365 by jim_thompson5910(28595) on 2012-03-24 01:09:49 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,7,14
-1,-2,-7,-14
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-14) = -14
2*(-7) = -14
(-1)*(14) = -14
(-2)*(7) = -14
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -14 | 1+(-14)=-13 | | 2 | -7 | 2+(-7)=-5 | | -1 | 14 | -1+14=13 | | -2 | 7 | -2+7=5 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Equations/590925: 8x-7=15+19x solve please 1 solutions
Answer 375364 by jim_thompson5910(28595) on 2012-03-24 01:09:02 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Graphs/590906: What is the slope of the line that contains the points (3, 4) and (1, 2)? 1 solutions
Answer 375359 by jim_thompson5910(28595) on 2012-03-24 00:05:34 (Show Source):
You can put this solution on YOUR website!Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
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Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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absolute-value/590920: What is the solution to: -2|x|<6 ? 1 solutions
Answer 375353 by jim_thompson5910(28595) on 2012-03-23 23:57:51 (Show Source):
You can put this solution on YOUR website!-2|x|<6
|x| > 6/(-2)
|x| > -3
Since the absolute value of any number is ALWAYS nonnegative, this means that |x| will either be 0 or some positive number.
So |x| is ALWAYS larger/greater than -3 for any value of x.
So there are an infinite number of solutions.
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Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Polynomials-and-rational-expressions/590916: Is there an easy way to understand how to work these? Would someone please show me?
FACTOR BY GROUPING
5x^3 - 15x^2 - 4x + 12 1 solutions
Answer 375352 by jim_thompson5910(28595) on 2012-03-23 23:55:21 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression
 Group the terms in two pairs
 Factor out the GCF  out of the first group. Factor out the GCF  out of the second group
 Since we have the common term  , we can combine like terms
So  factors to
In other words,  for all values of x.
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Polynomials-and-rational-expressions/590911: Would someone show me how to do this step by step?
Factor completely
5s^2 - 22s + 8 1 solutions
Answer 375350 by jim_thompson5910(28595) on 2012-03-23 23:54:29 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,4,5,8,10,20,40
-1,-2,-4,-5,-8,-10,-20,-40
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*40 = 40
2*20 = 40
4*10 = 40
5*8 = 40
(-1)*(-40) = 40
(-2)*(-20) = 40
(-4)*(-10) = 40
(-5)*(-8) = 40
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 40 | 1+40=41 | | 2 | 20 | 2+20=22 | | 4 | 10 | 4+10=14 | | 5 | 8 | 5+8=13 | | -1 | -40 | -1+(-40)=-41 | | -2 | -20 | -2+(-20)=-22 | | -4 | -10 | -4+(-10)=-14 | | -5 | -8 | -5+(-8)=-13 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
--------------------------------------------------------------------------------------------------------------
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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