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Answer 441122 by jim_thompson5910(28595) on 2013-02-25 20:19:56 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Distribute
 Multiply
 Add 3 to both sides.
 Combine like terms. note: If you need help with fractions, check out this solver.
So the equation that goes through the points ) and ) is
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Equations/718807: what is the answer to 2y-3=5-2y 1 solutions
Answer 441064 by jim_thompson5910(28595) on 2013-02-25 17:07:45 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Add  to both sides.
 Add  to both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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Angles/718701: Two angles are complementary and their sizes are in the ratio 5 : 7
What is the size of the smaller of the two angles?
1 solutions
Answer 441040 by jim_thompson5910(28595) on 2013-02-25 15:59:20 (Show Source):
You can put this solution on YOUR website!5x + 7x = 90
12x = 90
x = 90/12
x = 15/2
x = 7.5
5x = 5*7.5 = 37.5
7x = 7*7.5 = 52.5
So the two angles are 37.5 degrees and 52.5 degrees
Therefore, the smaller angle is 37.5 degrees
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test/718715: 18x^2+11x-24 1 solutions
Answer 441035 by jim_thompson5910(28595) on 2013-02-25 15:48:51 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,6,8,9,12,16,18,24,27,36,48,54,72,108,144,216,432
-1,-2,-3,-4,-6,-8,-9,-12,-16,-18,-24,-27,-36,-48,-54,-72,-108,-144,-216,-432
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-432) = -432
2*(-216) = -432
3*(-144) = -432
4*(-108) = -432
6*(-72) = -432
8*(-54) = -432
9*(-48) = -432
12*(-36) = -432
16*(-27) = -432
18*(-24) = -432
(-1)*(432) = -432
(-2)*(216) = -432
(-3)*(144) = -432
(-4)*(108) = -432
(-6)*(72) = -432
(-8)*(54) = -432
(-9)*(48) = -432
(-12)*(36) = -432
(-16)*(27) = -432
(-18)*(24) = -432
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -432 | 1+(-432)=-431 | | 2 | -216 | 2+(-216)=-214 | | 3 | -144 | 3+(-144)=-141 | | 4 | -108 | 4+(-108)=-104 | | 6 | -72 | 6+(-72)=-66 | | 8 | -54 | 8+(-54)=-46 | | 9 | -48 | 9+(-48)=-39 | | 12 | -36 | 12+(-36)=-24 | | 16 | -27 | 16+(-27)=-11 | | 18 | -24 | 18+(-24)=-6 | | -1 | 432 | -1+432=431 | | -2 | 216 | -2+216=214 | | -3 | 144 | -3+144=141 | | -4 | 108 | -4+108=104 | | -6 | 72 | -6+72=66 | | -8 | 54 | -8+54=46 | | -9 | 48 | -9+48=39 | | -12 | 36 | -12+36=24 | | -16 | 27 | -16+27=11 | | -18 | 24 | -18+24=6 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Polynomials-and-rational-expressions/718760: How would this look like in a descending order? I am having trouble with it.
11a6– 8a – 3 +12a3 1 solutions
Answer 441034 by jim_thompson5910(28595) on 2013-02-25 15:48:11 (Show Source):
You can put this solution on YOUR website!When they say decreasing order, they just want the exponents to be sorted from largest to smallest. So 6 is the largest exponent here and it goes first. 3 is the next largest exponent, so it goes next. One is the next largest (the exponent for  ), so that goes next. Finally, the last term is -3 since it has an exponent of 0 (-3 = -3a^0)
So the answer is
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Triangles/718758: can triangle can be formed by three segments with the lengths of 27 inches, 31 inches, and 48 inches? 1 solutions
Answer 441032 by jim_thompson5910(28595) on 2013-02-25 15:46:01 (Show Source):
You can put this solution on YOUR website!Notice how adding any two sides always results in a sum that's larger than the third side (that you didn't add). So this shows you that a triangle is possible here.
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Here's where a triangle isn't possible: side lengths of 1, 2, 18
Notice how 1+2 = 3 but that's not larger than 18, so the side lengths come up short making this triangle not possible
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Linear-equations/718510: y=x+5 1 solutions
Answer 440946 by jim_thompson5910(28595) on 2013-02-25 01:47:28 (Show Source):
You can put this solution on YOUR website!Looking at  we can see that the equation is in slope-intercept form  where the slope is  and the y-intercept is
Since  this tells us that the y-intercept is ) .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is  , this means:
which shows us that the rise is 1 and the run is 1. This means that to go from point to point, we can go up 1 and over 1
So starting at ) , go up 1 unit
and to the right 1 unit to get to the next point
Now draw a line through these points to graph
 So this is the graph of  through the points ) and
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test/718551: 2x^2+13x+15 1 solutions
Answer 440945 by jim_thompson5910(28595) on 2013-02-25 01:45:54 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*30 = 30
2*15 = 30
3*10 = 30
5*6 = 30
(-1)*(-30) = 30
(-2)*(-15) = 30
(-3)*(-10) = 30
(-5)*(-6) = 30
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 30 | 1+30=31 | | 2 | 15 | 2+15=17 | | 3 | 10 | 3+10=13 | | 5 | 6 | 5+6=11 | | -1 | -30 | -1+(-30)=-31 | | -2 | -15 | -2+(-15)=-17 | | -3 | -10 | -3+(-10)=-13 | | -5 | -6 | -5+(-6)=-11 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Number-Line/717898: x|x is a natural number less than 12 1 solutions
Answer 440641 by jim_thompson5910(28595) on 2013-02-23 19:25:31 (Show Source):
You can put this solution on YOUR website!x|x is a natural number less than 12
translates to this set
{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11}
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Linear-equations/717775: Can you help show me how to solve the following equation?
16x-1= -4x+14 1 solutions
Answer 440529 by jim_thompson5910(28595) on 2013-02-23 02:15:35 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Add  to both sides.
 Add  to both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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Graphs/717733: What is the slope of the line that contains the points (-1, 8) and (5, -4)? 1 solutions
Answer 440471 by jim_thompson5910(28595) on 2013-02-22 20:20:58 (Show Source):
You can put this solution on YOUR website!
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
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Equations/717737: If f(x)=x/(x-3) and g(x)=2x-1, find (f-g)(x).
My choices are:
A. (-2x^2+8x-3)/(x-3)
B. (-2x^2+6x+1)/(x-3)
C. (-2x^2+5x-3)/(x-3)
D. (2x^2+6x+3)/(x-3)
If I had to guess I would say either A or C, but I have no idea. Thank you for your help! 1 solutions
Answer 440469 by jim_thompson5910(28595) on 2013-02-22 20:15:45 (Show Source):
You can put this solution on YOUR website!(f-g)(x) = f(x) - g(x)
(f-g)(x) = x/(x-3) - (2x - 1)
(f-g)(x) = x/(x-3) - (2x - 1)(x-3)/(x-3)
(f-g)(x) = (x- (2x - 1)(x-3))/(x-3)
(f-g)(x) = (x- (2x^2 - 6x - x + 3))/(x-3)
(f-g)(x) = (x- (2x^2 - 7x + 3))/(x-3)
(f-g)(x) = (x- 2x^2 + 7x - 3)/(x-3)
(f-g)(x) = (-2x^2 + 8x - 3)/(x-3)
So the answer is choice A
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Graphs/716968: x^2+2x+1 1 solutions
Answer 440035 by jim_thompson5910(28595) on 2013-02-20 21:09:19 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1
-1
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*1 = 1
(-1)*(-1) = 1
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 1 | 1+1=2 | | -1 | -1 | -1+(-1)=-2 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
 Condense the terms.
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Numeric_Fractions/716926: 8(6x-5)+7(7x-6)-5=7-3 1 solutions
Answer 440029 by jim_thompson5910(28595) on 2013-02-20 20:35:20 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Distribute.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
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Answer:
So the solution is
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