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Equations/624249: factor 3x^2 +13x -10 1 solutions
Answer 393141 by jim_thompson5910(28598) on 2012-06-30 12:34:26 (Show Source):
You can put this solution on YOUR website!I'm assuming you meant to write 3x^2+13 x-10
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-30) = -30
2*(-15) = -30
3*(-10) = -30
5*(-6) = -30
(-1)*(30) = -30
(-2)*(15) = -30
(-3)*(10) = -30
(-5)*(6) = -30
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -30 | 1+(-30)=-29 | | 2 | -15 | 2+(-15)=-13 | | 3 | -10 | 3+(-10)=-7 | | 5 | -6 | 5+(-6)=-1 | | -1 | 30 | -1+30=29 | | -2 | 15 | -2+15=13 | | -3 | 10 | -3+10=7 | | -5 | 6 | -5+6=1 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
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Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Geometry_proofs/624775: Given:
Angle 1 is congruent to angle 3.
Prove:
Angle 2 is congruent to angle 4.
*Angle 1 and 2 are vertical angles.
Angle 3 and 4 are vertical angles. 1 solutions
Answer 393042 by jim_thompson5910(28598) on 2012-06-29 17:55:56 (Show Source):
You can put this solution on YOUR website!Angles 1 and 2 are vertical angles. So angle 1 = angle 2 because vertical angles are congruent.
Angles 3 and 4 are vertical as well. So angle 3 = angle 4 by the same reason.
-------------------------------------------------------
Since it's given that "Angle 1 is congruent to angle 3. ", this also means that angle 1 = angle 3
Now we can use substitution to get
angle 1 = angle 3
angle 2 = angle 3 << -- replace "angle 1" with "angle 2" (since the two are congruent)
angle 2 = angle 4 << -- replace "angle 3" with "angle 4" (since the two are congruent)
So because we've shown that angle 2 = angle 4 , this proves Angle 2 is congruent to angle 4
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Exponents-negative-and-fractional/624778: Scientific Notation problem:
Short Answer: Convert this number to scientific notation. SHOW ALL WORK!
76,485
Seemed simple when I started, but it wasn't. Help. 1 solutions
Answer 393040 by jim_thompson5910(28598) on 2012-06-29 17:49:06 (Show Source):
You can put this solution on YOUR website!Place the decimal point between the first two digits to get 7.6485
Now move the decimal 4 places to the right (to get back to the original number).
So the base is 7.6485 and the exponent is 4
This means that
76,485 = 7.6485 x 10^ 4
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Linear_Algebra/624750: Assume that all matrices are invertible and solve for the matrix X in:
(A^-1 X)^-1 =A (B^-1 A)^-1 1 solutions
Answer 393006 by jim_thompson5910(28598) on 2012-06-29 15:17:10 (Show Source):
You can put this solution on YOUR website!(A^-1 X)^-1 =A (B^-1 A)^-1
(A^-1 X)^-1(A^-1 X) =(A (B^-1 A)^-1)(A^-1 X)
I =(A (B^-1 A)^-1)(A^-1 X)
A^-1 * I =(A^-1 A (B^-1 A)^-1)(A^-1 X)
A^-1 = ((B^-1 A)^-1)(A^-1 X)
(B^-1 A)A^-1 = ((B^-1 A)(B^-1 A)^-1)(A^-1 X)
(B^-1 A)A^-1 = A^-1 X
A(B^-1 A)A^-1 = A*A^-1 X
A(B^-1 A)A^-1 = X
X = A(B^-1 A)A^-1
So the solution is X = A(B^-1 A)A^-1
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Age_Word_Problems/624743: Ina church the ratio of adults to children is 7 to 5. there are 85 people. How many of them are children? 1 solutions
Answer 393003 by jim_thompson5910(28598) on 2012-06-29 15:02:05 (Show Source):
You can put this solution on YOUR website!7/5 = a/c
7/5 = (85-c)/c
7c = 5(85-c)
7c = 425-5c
7c+5c = 425
12c = 425
c = 425/12
c = 35.41666
Round to the nearest integer to get 35 children
***Note: because I'm getting a decimal answer, there might be a typo somewhere in the original problem***
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Money_Word_Problems/624683: So I have tried to work this out, I have no idea where to start and I'm stuck. Could someone please help me figure this out and tell me how you got the answer do I can try to so the second part of the problem. The price of a certain stock at the beginning of the week was $61. Here are the changes in price during the week: +3,+2,-1,-4,-5. What is the price of the stock at the end of the week? Thank you very much. 1 solutions
Answer 392991 by jim_thompson5910(28598) on 2012-06-29 14:07:07 (Show Source):
You can put this solution on YOUR website!Add up the changes: +3+2+(-1)+(-4)+(-5) = -5
So the final change is -5
This means that the stock lost $5 at the end of the week.
So the stock price at the end of the week is 61 + (-5) = 56 dollars
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Graphs/624608: Solve these equations using the addition property.
x + y = k
x - y = k
The lines intersect at 1 solutions
Answer 392902 by jim_thompson5910(28598) on 2012-06-28 19:49:19 (Show Source):
You can put this solution on YOUR website!x + y = k
x - y = k
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2x + 0y = 2k
2x = 2k
x = 2k/2
x = k
----------------------------------------------------------------
x+y = k
k+y = k
y = k-k
y = 0
So the solutions are x = k and y = 0
So the lines intersect at (k, 0)
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Polynomials-and-rational-expressions/624554: I need to factor the polynomials and solve the equation
32xy^3 +4x=
I factored out 4x to get 4x(8y^3+1)
but I am unsure if I should do that.
Thanks in advance for your help. Also can you please show me the steps. 1 solutions
Answer 392841 by jim_thompson5910(28598) on 2012-06-28 15:21:00 (Show Source):
You can put this solution on YOUR website!Now let's factor
 Start with the given expression.
 Rewrite  as  . Rewrite  as  .
 Now factor by using the sum of cubes formula. Remember the sum of cubes formula is
 Multiply
So  factors to  .
In other words,
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Answer:
So in the end,  completely factors to
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Geometry_Word_Problems/624552: It's laundry time again, and you have a roll of $10 worth of quarters to take to the Wash-'n-Whirl. Each US quarter has width of 1.75 mm and a radius of 12 mm. What is the volume of the roll of quarters?
1 solutions
Answer 392834 by jim_thompson5910(28598) on 2012-06-28 14:57:25 (Show Source):
You can put this solution on YOUR website!There are 10/0.25 = 40 quarters total.
The total height of the stack of quarters is h = 40*1.75 = 70 mm
The volume is then...
V = pi*r^2*h
V = pi*12^2*70
V = 10080pi << ------- Exact Volume
V = 10080(3.14159)
V = 31667.2272 << ------- Approximate Volume
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Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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Mixture_Word_Problems/624549: What is the first ten terms of a sequence whose first term is -10 and whose common difference is -2. 1 solutions
Answer 392831 by jim_thompson5910(28598) on 2012-06-28 14:42:06 (Show Source):
You can put this solution on YOUR website!Start with the first term of -10 and subtract off 2 each time to get the next term, so the first ten terms are...
-10,-12,-14,-16,-18,-20,-22,-24,-26,-28
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Quadratic_Equations/624550: I Need Help With This Quadratic equation . 2m^2+2m-12=0 1 solutions
Answer 392830 by jim_thompson5910(28598) on 2012-06-28 14:39:03 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "m":
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the solutions are  or
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Jim
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Probability-and-statistics/624539: If you had 13 toppings how many different 4 topping pizzas can you make 1 solutions
Answer 392820 by jim_thompson5910(28598) on 2012-06-28 13:31:30 (Show Source):
You can put this solution on YOUR website!Use the combination formula...
n C r = (n!)/(r!(n-r)!)
13 C 4 = (13!)/(4!*(13-4)!)
13 C 4 = (13!)/(4!*9!)
13 C 4 = (13*12*11*10*9!)/(4!*9!)
13 C 4 = (13*12*11*10)/(4!)
13 C 4 = (13*12*11*10)/(4*3*2*1)
13 C 4 = (17160)/(24)
13 C 4 = 715
So there are 715 different pizzas you can make.
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