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Answer 392503 by jim_thompson5910(28503) on 2012-06-26 17:14:39 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Distribute.
 Combine like terms on the left side.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
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Answer:
So the solution is
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Quadratic-relations-and-conic-sections/624053: x^2+5x-12
HELP!! 1 solutions
Answer 392499 by jim_thompson5910(28503) on 2012-06-26 17:10:54 (Show Source):
You can put this solution on YOUR website!I'm assuming you want to factor this.
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,6,12
-1,-2,-3,-4,-6,-12
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-12) = -12
2*(-6) = -12
3*(-4) = -12
(-1)*(12) = -12
(-2)*(6) = -12
(-3)*(4) = -12
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -12 | 1+(-12)=-11 | | 2 | -6 | 2+(-6)=-4 | | 3 | -4 | 3+(-4)=-1 | | -1 | 12 | -1+12=11 | | -2 | 6 | -2+6=4 | | -3 | 4 | -3+4=1 |
From the table, we can see that there are no pairs of numbers which add to  . So  cannot be factored.
===============================================================
Answer:
So doesn't factor at all (over the rational numbers).
So is prime.
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Inequalities/623967: 3(x-2) - 2 < x - 5
1 solutions
Answer 392458 by jim_thompson5910(28503) on 2012-06-26 12:30:03 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality.
 Distribute.
 Combine like terms on the left side.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
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Answer:
So the solution is
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Rectangles/623768: Hi,
I am reviewing to retake the SAT's and need help with the following problem.
If the perimeter of a rectangular property is 46 meters, and the area of the property is 76 meters squared, what is the length of each of the shorter sides?
Knowing the steps to take would be very helpful.
Thanks!! 1 solutions
Answer 392300 by jim_thompson5910(28503) on 2012-06-25 18:20:48 (Show Source):
You can put this solution on YOUR website!P = 2L + 2W
"If the perimeter of a rectangular property is 46 meters" ---> P = 46
46 = 2L + 2W
-------------------------------------------------------
Area = Length * Width
A = LW
"the area of the property is 76 meters squared" ----> A = 76
76 = LW
W = 76/L
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46 = 2L + 2W
46 = 2L + 2(76/L)
I'll let you finish up. Let me know if you have any questions or if you still need help. Thanks.
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Equations/619659: a+5=-5a+5 1 solutions
Answer 392290 by jim_thompson5910(28503) on 2012-06-25 17:36:25 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Subtract  from both sides.
 Add  to both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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percentage/623688: 12 games were won out of 16. What percent of the games were won?
My solution:
16-12=4
4/16= 1/4 convert 4/1= .25; therefore they won 25% of their games, but the answer key says that it is 75%. I just want to know if i'm right or wrong; if not please instruct me where the error is; thank you. 1 solutions
Answer 392222 by jim_thompson5910(28503) on 2012-06-25 11:48:39 (Show Source):
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Equations/623658: 2x + 7= x + 18 1 solutions
Answer 392202 by jim_thompson5910(28503) on 2012-06-25 10:37:19 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
----------------------------------------------------------------------
Answer:
So the solution is
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Inequalities/623597: what is the solution and graph of 4x - 5 > 3x - 31? 1 solutions
Answer 392195 by jim_thompson5910(28503) on 2012-06-25 10:17:35 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
----------------------------------------------------------------------
Answer:
So the solution is
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Equations/623535: T = (((X * A * B * (100 - C) / 100) - Y) / Z) ... solve for X
Can you help me with the answer? Thank you. 1 solutions
Answer 392149 by jim_thompson5910(28503) on 2012-06-24 22:15:26 (Show Source):
You can put this solution on YOUR website!T = (((X * A * B * (100 - C) / 100) - Y) / Z)
ZT = (X * A * B * (100 - C) / 100) - Y
ZT + Y = (X * A * B * (100 - C) / 100)
100*(ZT + Y) = X * A * B * (100 - C)
100ZT + 100Y = X * A * B * (100 - C)
(100ZT + 100Y)/(A * B * (100 - C)) = X
X = (100ZT + 100Y)/(A * B * (100 - C))
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Rectangles/623509: A rectangle is twice as long as it is wide. The perimeter is 84 feet. how can i find the dimensions? 1 solutions
Answer 392140 by jim_thompson5910(28503) on 2012-06-24 20:09:39 (Show Source):
You can put this solution on YOUR website!Hint: "A rectangle is twice as long as it is wide" means that L = 2W
"The perimeter is 84 feet" means that P = 2L+2W ---> 84 = 2L+2W
From here, plug in L = 2W to get 84 = 2*2W + 2W which becomes 84 = 4W + 2W
I'll let you finish. You simply need to solve for W. Then use the solution for W to find L.
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Equations/623508: How do you solve 4(3x-8)+2x<16 ? This prefreshman engineering program gives us hard equations & doesnt even explain it tous ! please tell me how step by step ... 1 solutions
Answer 392136 by jim_thompson5910(28503) on 2012-06-24 20:01:03 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality.
 Distribute.
 Combine like terms on the left side.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
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If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
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