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4x squared = 13x + 12 1 solutions
Answer 83605 by jim_thompson5910(28536) on 2007-12-05 23:12:23 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
 Move all of the terms to the right side
 Sort the terms
 Switch both sides (I find it easier to read if all of the terms are on the left side)
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve  ( notice  ,  , and  )
 Plug in a=-4, b=13, and c=12
 Square 13 to get 169
 Multiply  to get
 Combine like terms in the radicand (everything under the square root)
 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
 Multiply 2 and -4 to get -8
So now the expression breaks down into two parts
 or
Lets look at the first part:
 Add the terms in the numerator
 Divide
So one answer is
Now lets look at the second part:
 Subtract the terms in the numerator
 Divide
So another answer is
So our solutions are:
 or
Notice when we graph  , we get:
and we can see that the roots are  and  . This verifies our answer
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Graphs/114722: Solve. 6x – 7 = 2x + 13 1 solutions
Answer 83603 by jim_thompson5910(28536) on 2007-12-05 23:05:25 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
 Add 7 to both sides
 Subtract 2x from both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by 4 to isolate x
 Divide
--------------------------------------------------------------
Answer:
So our answer is
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Functions/114811: use the horizontal line test to determine which of the following are one to one functions
A) y=2x^2+5x-3 B) y= [x-2] C) y=x^-1/2 1 solutions
Answer 83534 by jim_thompson5910(28536) on 2007-12-05 16:18:44 (Show Source):
You can put this solution on YOUR website!If we graph  , we get
which fails the horizontal line test. So the function is not one-to-one
----------------------------------------------
If we graph  , we get
which fails the horizontal line test. So the function is not one-to-one
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Remember,  is the same as
If we graph  , we get
which passes the horizontal line test. So the function is one-to-one
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Functions/114785: find f and g such that h=f*g where h(x)=(1/2x-3)^3 and the inner function g is rational 1 solutions
Answer 83529 by jim_thompson5910(28536) on 2007-12-05 15:16:01 (Show Source):
You can put this solution on YOUR website!Is this a function composition, or just multiplication? If it's a composition, then...
If  and h(x)=f(g(x)), then simply let  and  .
Notice if we evaluate f(g(x)), then we get
So this shows that if  and  , then
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Money_Word_Problems/114793: The sophomore class at south high school raised $800 from sales tickets to a dance. tickets sold for $1.50 in advance and $ 2.00 at the door. if a total of 475 tickets were sold, what were the number of tickets sold at the door 1 solutions
Answer 83527 by jim_thompson5910(28536) on 2007-12-05 15:07:36 (Show Source):
You can put this solution on YOUR website!Let x=# of advance tickets, y=# of door tickets
Since there were a total of 475 tickets sold, the first equation is
And since those tickets brought in $800, the next equation is
Now multiply both sides by 10 to get
| Solved by pluggable solver: Solving a linear system of equations by subsitution |
Lets start with the given system of linear equations


Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
Solve for y for the first equation
Subtract from both sides
Divide both sides by 1.
Which breaks down and reduces to
Now we've fully isolated y
Since y equals we can substitute the expression into y of the 2nd equation. This will eliminate y so we can solve for x.
Replace y with . Since this eliminates y, we can now solve for x.
Distribute 20 to 
Multiply
Reduce any fractions
Subtract from both sides
Combine the terms on the right side
Now combine the terms on the left side.
Multiply both sides by . This will cancel out and isolate x
So when we multiply and (and simplify) we get
<---------------------------------One answer
Now that we know that , lets substitute that in for x to solve for y
Plug in into the 2nd equation
Multiply
Subtract from both sides
Combine the terms on the right side
Multiply both sides by . This will cancel out 20 on the left side.
Multiply the terms on the right side
Reduce
So this is the other answer
<---------------------------------Other answer
So our solution is
and 
which can also look like
( , )
Notice if we graph the equations (if you need help with graphing, check out this solver)


we get
graph of (red) and (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
and we can see that the two equations intersect at ( , ). This verifies our answer.
-----------------------------------------------------------------------------------------------
Check:
Plug in ( , ) into the system of equations
Let and . Now plug those values into the equation 
Plug in and 
Multiply
Add
Reduce. Since this equation is true the solution works.
So the solution ( , ) satisfies 
Let and . Now plug those values into the equation 
Plug in and 
Multiply
Add
Reduce. Since this equation is true the solution works.
So the solution ( , ) satisfies 
Since the solution ( , ) satisfies the system of equations


this verifies our answer.
|
So they sold 300 tickets in advance and 175 tickets at the door.
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Quadratic_Equations/114788: Write the equation of the line passing through (–3, –5) and (3, 0). 1 solutions
Answer 83523 by jim_thompson5910(28536) on 2007-12-05 15:02:47 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Finding the Equation of a Line |
First lets find the slope through the points ( , ) and ( , )
Start with the slope formula (note: ( , ) is the first point ( , ) and ( , ) is the second point ( , ))
Plug in , , , (these are the coordinates of given points)
Subtract the terms in the numerator to get . Subtract the terms in the denominator to get 
So the slope is

------------------------------------------------
Now let's use the point-slope formula to find the equation of the line:
------Point-Slope Formula------
where is the slope, and ( , ) is one of the given points
So lets use the Point-Slope Formula to find the equation of the line
Plug in , , and (these values are given)
Rewrite as 
Rewrite as 
Distribute 
Multiply and to get . Now reduce to get 
Subtract from both sides to isolate y
Combine like terms and to get (note: if you need help with combining fractions, check out this solver)
------------------------------------------------------------------------------------------------------------
Answer:
So the equation of the line which goes through the points ( , ) and ( , ) is:
The equation is now in form (which is slope-intercept form) where the slope is and the y-intercept is 
Notice if we graph the equation and plot the points ( , ) and ( , ), we get this: (note: if you need help with graphing, check out this solver)
Graph of through the points ( , ) and ( , )
Notice how the two points lie on the line. This graphically verifies our answer.
|
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Polynomials-and-rational-expressions/114757: Use the ac test to determine which of the following trinomials can be factored. Find the values of m and n for each trinomial that can be factored.
x squared + 2x - 15 1 solutions
Answer 83498 by jim_thompson5910(28536) on 2007-12-05 12:38:18 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Factoring using the AC method (Factor by Grouping) |
In order to factor , first multiply the leading coefficient 1 and the last term -15 to get -15. Now we need to ask ourselves: What two numbers multiply to -15 and add to 2? Lets find out by listing all of the possible factors of -15
Factors:
1,3,5,15,
-1,-3,-5,-15, List the negative factors as well. This will allow us to find all possible combinations
These factors pair up to multiply to -15.
(-1)*(15)=-15
(-3)*(5)=-15
Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2
| First Number | | | Second Number | | | Sum | | 1 | | | -15 | || | 1+(-15)=-14 | | 3 | | | -5 | || | 3+(-5)=-2 | | -1 | | | 15 | || | (-1)+15=14 | | -3 | | | 5 | || | (-3)+5=2 |
We can see from the table that -3 and 5 add to 2. So the two numbers that multiply to -15 and add to 2 are: -3 and 5
So the original quadratic

breaks down to this (just replace with the two numbers that multiply to -15 and add to 2, which are: -3 and 5)
Replace with 
Group the first two terms together and the last two terms together like this:

Factor a 1x out of the first group and factor a 5 out of the second group.

Now since we have a common term we can combine the two terms.
Combine like terms.
==============================================================================
Answer:
So the quadratic factors to 
Notice how foils back to our original problem . This verifies our answer. | |
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Radicals/114754: Can some one help me please.
Solve by completing the square
x^2 + 8x + 13 = 0
Thank you inadavance. 1 solutions
Answer 83497 by jim_thompson5910(28536) on 2007-12-05 12:29:41 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
 Subtract 13 from both sides
Take half of the x coefficient 8 to get 4 (ie  )
Now square 4 to get 16 (ie  )
 Add this result (16) to both sides. Now the expression  is a perfect square trinomial.
 Factor  into  (note: if you need help with factoring, check out this solver)
 Combine like terms on the right side
 Take the square root of both sides
 Subtract 4 from both sides to isolate x.
So the expression breaks down to
 or
So our answer is approximately
 or
Here is visual proof
 graph of
When we use the root finder feature on a calculator, we would find that the x-intercepts are  and  , so this verifies our answer.
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Quadratic_Equations/114734: Graph the inequality.
y is equal to or greater then 1
1 solutions
Answer 83493 by jim_thompson5910(28536) on 2007-12-05 11:44:53 (Show Source):
You can put this solution on YOUR website!In order to graph  , we need to graph the equation  (just replace the inequality sign with an equal sign).
So lets graph the line  (simply draw a horizontal line through  )
 graph of
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality  with the test point
Substitute (0,0) into the inequality
 Plug in  and
 Simplify
(note: for some reason, some of the following images do not display correctly in Internet Explorer. So I recommend the use of Firefox to see these images.)
Since this inequality is not true, we do not shade the entire region that contains (0,0). So this means we shade the region that is on the opposite side of the line
 Graph of  with the boundary (which is the line  in red) and the shaded region (in green)
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Quadratic_Equations/114744: Graph by first solving for y.
x – 3y = 9
1 solutions
Answer 83492 by jim_thompson5910(28536) on 2007-12-05 11:42:12 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Graphing Linear Equations |
Start with the given equation
Subtract from both sides
Multiply both sides by 
Distribute 
Multiply
Rearrange the terms
Reduce any fractions
So the equation is now in slope-intercept form ( ) where (the slope) and (the y-intercept)
So to graph this equation lets plug in some points
Plug in x=-9

Multiply
Add
Reduce
So here's one point (-9,-6)

Now lets find another point
Plug in x=-6

Multiply
Add
Reduce
So here's another point (-6,-5). Add this to our graph

Now draw a line through these points
So this is the graph of through the points (-9,-6) and (-6,-5)
So from the graph we can see that the slope is (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 3 units to get to the next point) the y-intercept is (0, )and the x-intercept is ( ,0) . So all of this information verifies our graph.
We could graph this equation another way. Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0, ).
So we have one point (0, )

Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0, ), we can go up 1 units

and to the right 3 units to get to our next point

Now draw a line through those points to graph 
So this is the graph of through the points (0,-3) and (3,-2)
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Quadratic_Equations/114663: 7x – 5 + 3x = 6 + x – 10 1 solutions
Answer 83440 by jim_thompson5910(28536) on 2007-12-04 22:28:27 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
 Combine like terms on the left side
 Combine like terms on the right side
 Add 5 to both sides
 Subtract x from both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by 9 to isolate x
 Reduce
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Answer:
So our answer is  (which is approximately  in decimal form)
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Quadratic_Equations/114666: 10(–x – 7) + 20 = –5(2x + 4) 1 solutions
Answer 83438 by jim_thompson5910(28536) on 2007-12-04 22:26:50 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
 Distribute
 Combine like terms on the left side
 Add 50 to both sides
 Add 10x to both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Simplify
Since this equation is never true for any x value, this means there are no solutions.
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Equations/114668: 2(x-3)-3(x+5)=3(x-2)-7 1 solutions
Answer 83436 by jim_thompson5910(28536) on 2007-12-04 22:24:51 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
 Distribute
 Combine like terms on the left side
 Combine like terms on the right side
 Add 21 to both sides
 Subtract 3x from both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by -4 to isolate x
 Divide
--------------------------------------------------------------
Answer:
So our answer is
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Quadratic_Equations/114678: Solve by using the quadratic formula:
9z squared + 12z + 4 = 0 1 solutions
Answer 83434 by jim_thompson5910(28536) on 2007-12-04 22:22:50 (Show Source):
You can put this solution on YOUR website!Let's use the quadratic formula to solve for z:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve  ( notice  ,  , and  )
 Plug in a=9, b=12, and c=4
 Square 12 to get 144
 Multiply  to get
 Combine like terms in the radicand (everything under the square root)
 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
 Multiply 2 and 9 to get 18
So now the expression breaks down into two parts
 or
Lets look at the first part:
 Add the terms in the numerator
 Divide
So one answer is
Now lets look at the second part:
 Subtract the terms in the numerator
 Divide
So another answer is
So our only solution is:
Notice when we graph  (just replace z with x), we get:
and we can see that the roots is  . This verifies our answer
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Quadratic_Equations/114676: Solve by using the quadratic formula:
Z squared + 4z + 1 = 0 1 solutions
Answer 83433 by jim_thompson5910(28536) on 2007-12-04 22:20:56 (Show Source):
You can put this solution on YOUR website!Let's use the quadratic formula to solve for z:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve  ( notice  ,  , and  )
 Plug in a=1, b=4, and c=1
 Square 4 to get 16
 Multiply  to get
 Combine like terms in the radicand (everything under the square root)
 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
 Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
 or
Now break up the fraction
 or
Simplify
 or
So these expressions approximate to
 or
So our solutions are:
 or
Notice when we graph  (just replace z with x), we get:
when we use the root finder feature on a calculator, we find that  and  .So this verifies our answer
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Linear-equations/114651: Solve for y then graph.
2x-3y=12
(2x-3y)+(-2x)=12+(-2x)
2x-3y-2x=-2x+12
2x-2x-3y=-2x+12
-3y=-2x+12
-3y=-2x+12
My question is this: Am I correct on this equation so far and I am not sure how to graph this I have been working on this all afternoon.
Thank you for your help,
Barb Neely 1 solutions
Answer 83421 by jim_thompson5910(28536) on 2007-12-04 21:03:42 (Show Source):
You can put this solution on YOUR website!You are correct so far
 Start with the given equation
 Divide both sides by -3
 Break up the fraction
 Reduce
| Solved by pluggable solver: Graphing Linear Equations |
In order to graph we only need to plug in two points to draw the line
So lets plug in some points
Plug in x=-6

Multiply
Add
Reduce
So here's one point (-6,-8)

Now lets find another point
Plug in x=-3

Multiply
Add
Reduce
So here's another point (-3,-6). Add this to our graph

Now draw a line through these points
So this is the graph of through the points (-6,-8) and (-3,-6)
So from the graph we can see that the slope is (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 3 units to get to the next point) the y-intercept is (0, )and the x-intercept is ( ,0)
We could graph this equation another way. Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0, ).
So we have one point (0, )

Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0, ), we can go up 2 units

and to the right 3 units to get to our next point

Now draw a line through those points to graph 
So this is the graph of through the points (0,-4) and (3,-2)
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Inequalities/114648: -x-4>3x-2 1 solutions
Answer 83416 by jim_thompson5910(28536) on 2007-12-04 20:54:52 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality
 Add 4 to both sides
 Subtract 3x from both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by -4 to isolate x (note: Remember, dividing both sides by a negative number flips the inequality sign)
 Reduce
--------------------------------------------------------------
Answer:
So our answer is  (which is approximately  in decimal form)
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Functions/114591: Consider the function f(x) = x^2 +6x - 2
Find h, the x-coordinate of the vertex of this parabola 1 solutions
Answer 83366 by jim_thompson5910(28536) on 2007-12-04 17:25:47 (Show Source):
You can put this solution on YOUR website!To find the x-coordinate, simply use this formula:
So in this case, a=1 and b=6. Now plug them into the formula
 Multiply
 Reduce
So the x-coordinate, or h, is -3
Check: Notice if we graph  , we can see that the x-coordinate of the vertex is -3. So this verifies our answer.
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Coordinate-system/114588: Find the equation, in standard form, with all interger coeffecients, of the line perpendicular to 3x - 6y = 9 and passing through (-2,-1) 1 solutions
Answer 83361 by jim_thompson5910(28536) on 2007-12-04 17:05:58 (Show Source):
You can put this solution on YOUR website!First convert 3x - 6y = 9 to slope intercept form
Now let's find the equation of the line through points (-2,-1) that is perpendicular to
| Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line |
Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of , you can find the perpendicular slope by this formula:
where is the perpendicular slope
So plug in the given slope to find the perpendicular slope
When you divide fractions, you multiply the first fraction (which is really ) by the reciprocal of the second
Multiply the fractions.
So the perpendicular slope is 
So now we know the slope of the unknown line is (its the negative reciprocal of from the line ).
Also since the unknown line goes through (-2,-1), we can find the equation by plugging in this info into the point-slope formula
Point-Slope Formula:
where m is the slope and ( , ) is the given point
Plug in , , and 
Distribute 
Multiply
Subtract from both sides to isolate y
Combine like terms
So the equation of the line that is perpendicular to and goes through ( , ) is 
So here are the graphs of the equations and 
graph of the given equation (red) and graph of the line (green) that is perpendicular to the given graph and goes through ( , )
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Age_Word_Problems/114581: This question is from textbook
This is the closest subject I could find, so, here goes.The real subject is digit problems.
::A number between 300 and 400 is forty times the sum of its digits. The tens digit is 6 more than the units digit. Find the number. 1 solutions
Answer 83360 by jim_thompson5910(28536) on 2007-12-04 17:01:52 (Show Source):
You can put this solution on YOUR website!Let x=tens digit, y=units digit
Since "The tens digit is 6 more than the units digit" we get
Since the number is between 300 and 400, we know that the number must be of the form  and since the number is 40 times the sum of the digits, we then have the equation
 Distribute
 Now plug in
 Distribute again
 Combine like terms
 Subtract 11y from both sides
 Subtract 360 from both sides
 Combine like terms
 Divide both sides by 91
So the units digit is 0
This means the tens digit is:
So we have:
tens digit: 6 , ones digit: 0
-----------------------------------------
Answer:
So our number is 360
Check:
Notice if we add the digits of 360, we get
3+6+0=9
Now multiply the sum by 40
9*40=360
which is our number. So our answer is verified
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