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Geometry_proofs/663868: I don't understand proofs. For example:
Given: Segment AB is congruent to segment TP.
Prove: Segment AT is congruent to segment BP.
There is a line image accompanying it.
<---a--b--------t--p---> 1 solutions
Answer 413055 by jim_thompson5910(28476) on 2012-10-09 17:47:11 (Show Source):
You can put this solution on YOUR website!Notice how AP = AT + TP and AP = AB + BP
Since AB = TP (given), this means
AP = AT + TP and AP = AB + BP
becomes
AP = AT + TP and AP = TP + BP
AP = AT + TP and AP = BP + TP
So this means that
AP = AT + TP
BP + TP = AT + TP
BP + TP - TP = AT + TP - TP
BP = AT
AT = BP
which proves that segment AT is congruent to segment BP
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Equations/663942: 6-(b+1)=9 1 solutions
Answer 413054 by jim_thompson5910(28476) on 2012-10-09 17:40:27 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Distribute.
 Combine like terms on the left side.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
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test/663939: x-8+(x+2)>0 1 solutions
Answer 413053 by jim_thompson5910(28476) on 2012-10-09 17:39:51 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality.
 Combine like terms on the left side.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
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Probability-and-statistics/663913: You pick 5 apples from a grocery store owned by the professor. The probability of a randomly chosen apple being rotten is 0.518. Let X represent the number of apples that are NOT rotten. Find the probability of X=k in the table below.
k P(X = k)
0
1
2
3
4
5
I tried multiplying .482*0 then .482*1 all the way down the table. 1 solutions
Answer 413040 by jim_thompson5910(28476) on 2012-10-09 17:28:32 (Show Source):
You can put this solution on YOUR website!The probability of a randomly chosen apple being rotten is 0.518
So the probability of a randomly chosen apple NOT being rotten is 1 - 0.518 = 0.482
So p = 0.482
There are 5 apples picked, so n = 5.
This is a binomial distribution problem, so use the formula P(X = k) = (n C x)*(p)^(x)*(1-p)^(n-x)
For k = 0
P(X = k) = (n C x)*(p)^(x)*(1-p)^(n-x)
P(X = 0) = (5 C 0)*(0.482)^(0)*(1-0.482)^(5-0)
P(X = 0) = (5 C 0)*(0.482)^(0)*(0.518)^(5-0)
P(X = 0) = (1)*(0.482)^(0)*(0.518)^5
P(X = 0) = (1)*(1)*(0.037294844329568)
P(X = 0) = 0.037294844329568
P(X = 0) = 0.03729
For k = 1
P(X = k) = (n C x)*(p)^(x)*(1-p)^(n-x)
P(X = 1) = (5 C 1)*(0.482)^(1)*(1-0.482)^(5-1)
P(X = 1) = (5 C 1)*(0.482)^(1)*(0.518)^(5-1)
P(X = 1) = (5)*(0.482)^(1)*(0.518)^4
P(X = 1) = (5)*(0.482)*(0.071997768976)
P(X = 1) = 0.17351462323216
P(X = 1) = 0.17351
For k = 2
P(X = k) = (n C x)*(p)^(x)*(1-p)^(n-x)
P(X = 2) = (5 C 2)*(0.482)^(2)*(1-0.482)^(5-2)
P(X = 2) = (5 C 2)*(0.482)^(2)*(0.518)^(5-2)
P(X = 2) = (10)*(0.482)^(2)*(0.518)^3
P(X = 2) = (10)*(0.232324)*(0.138991832)
P(X = 2) = 0.32291138377568
P(X = 2) = 0.32291
For k = 3
P(X = k) = (n C x)*(p)^(x)*(1-p)^(n-x)
P(X = 3) = (5 C 3)*(0.482)^(3)*(1-0.482)^(5-3)
P(X = 3) = (5 C 3)*(0.482)^(3)*(0.518)^(5-3)
P(X = 3) = (10)*(0.482)^(3)*(0.518)^2
P(X = 3) = (10)*(0.111980168)*(0.268324)
P(X = 3) = 0.30046966598432
P(X = 3) = 0.30047
For k = 4
P(X = k) = (n C x)*(p)^(x)*(1-p)^(n-x)
P(X = 4) = (5 C 4)*(0.482)^(4)*(1-0.482)^(5-4)
P(X = 4) = (5 C 4)*(0.482)^(4)*(0.518)^(5-4)
P(X = 4) = (5)*(0.482)^(4)*(0.518)^1
P(X = 4) = (5)*(0.053974440976)*(0.518)
P(X = 4) = 0.13979380212784
P(X = 4) = 0.13979
and finally, for k = 5
P(X = k) = (n C x)*(p)^(x)*(1-p)^(n-x)
P(X = 5) = (5 C 5)*(0.482)^(5)*(1-0.482)^(5-5)
P(X = 5) = (5 C 5)*(0.482)^(5)*(0.518)^(5-5)
P(X = 5) = (1)*(0.482)^(5)*(0.518)^0
P(X = 5) = (1)*(0.026015680550432)*(1)
P(X = 5) = 0.026015680550432
P(X = 5) = 0.02602
The updated table is then
| k |
P(X = k) |
| 0 |
0.03729 |
| 1 |
0.17351 |
| 2 |
0.32291 |
| 3 |
0.30047 |
| 4 |
0.13979 |
| 5 |
0.02602 |
How to read the table above. Let's say you look at the third row. In this row is 2 and 0.32291, which says "the probability of picking exactly 2 rotten apples (out of 5 total) is roughly 0.32291 or 32.291%
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Probability-and-statistics/663910: Find the variance of the following probability distribution.
x P(x)
0 0.1052
1 0.0455
2 0.3337
3 0.3754
4 0.1401
variance = 1 solutions
Answer 413024 by jim_thompson5910(28476) on 2012-10-09 17:14:49 (Show Source):
You can put this solution on YOUR website!Mean or Expected Value:
E[X] = Sum( P(X = xi) * xi )
E[X] = [P(X = x1)*(x1)] + [P(X = x2)*(x2)] + [P(X = x3)*(x3)] + [P(X = x4)*(x4)] + [P(X = x5)*(x5)]
E[X] = [0.1052*(0)] + [0.0455*(1)] + [0.3337*(2)] + [0.3754*(3)] + [0.1401*(4)]
E[X] = 0.1052*(0) + 0.0455*(1) + 0.3337*(2) + 0.3754*(3) + 0.1401*(4)
E[X] = 0 + 0.0455 + 0.6674 + 1.1262 + 0.5604
E[X] = 2.3995
So mu = 2.3995
--------------------------------------------------------------------------------------------------
Variance:
sigma^2 = Sum( P(X = xi) * (xi - E(X) )^2 )
sigma^2 = [P(X = x1)*(x1 - mu)^2] + [P(X = x2)*(x2 - mu)^2] + [P(X = x3)*(x3 - mu)^2] + [P(X = x4)*(x4 - mu)^2] + [P(X = x5)*(x5 - mu)^2]
sigma^2 = [0.1052*(0 - 2.3995)^2] + [0.0455*(1 - 2.3995)^2] + [0.3337*(2 - 2.3995)^2] + [0.3754*(3 - 2.3995)^2] + [0.1401*(4 - 2.3995)^2]
sigma^2 = [0.1052*(-2.3995)^2] + [0.0455*(-1.3995)^2] + [0.3337*(-0.3995)^2] + [0.3754*(0.6005)^2] + [0.1401*(1.6005)^2]
sigma^2 = [0.1052*(5.75760025)] + [0.0455*(1.95860025)] + [0.3337*(0.15960025)] + [0.3754*(0.36060025)] + [0.1401*(2.56160025)]
sigma^2 = 0.1052*(5.75760025) + 0.0455*(1.95860025) + 0.3337*(0.15960025) + 0.3754*(0.36060025) + 0.1401*(2.56160025)
sigma^2 = 0.6056995463 + 0.089116311375 + 0.053258603425 + 0.13536933385 + 0.358880195025
sigma^2 = 1.242323989975
So the variance is roughly 1.242323989975
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Probability-and-statistics/663780: Good day! I am so confused regarding the following question:
Solve the problem. Round results to the nearest hundredth.
The mean of a set of data is -3.82 and its standard deviation is 2.31. Find the z score for a value of 3.99
Any advice you can provide would be greatly appreciated! Thank you very much! Have a wonderful day!
Sincerely,
Gina C. 1 solutions
Answer 412941 by jim_thompson5910(28476) on 2012-10-09 14:36:07 (Show Source):
You can put this solution on YOUR website!z = (x - mu)/(sigma)
z = (3.99 - (-3.82))/(2.31)
z = (3.99 + 3.82)/(2.31)
z = (7.81)/(2.31)
z = 3.38095238095238
z = 3.38
So the answer is z = 3.38
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Polynomials-and-rational-expressions/663778: Factor the polynomial? 2x^3+4x^2+8x 1 solutions
Answer 412940 by jim_thompson5910(28476) on 2012-10-09 14:30:00 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Factor out the GCF  .
Now let's try to factor the inner expression
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Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,4
-1,-2,-4
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*4 = 4
2*2 = 4
(-1)*(-4) = 4
(-2)*(-2) = 4
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 4 | 1+4=5 | | 2 | 2 | 2+2=4 | | -1 | -4 | -1+(-4)=-5 | | -2 | -2 | -2+(-2)=-4 |
From the table, we can see that there are no pairs of numbers which add to  . So  cannot be factored.
===============================================================
Answer:
So simply factors to
In other words, .
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Linear-systems/663774: 5(2x+3)=2(3x+7) 1 solutions
Answer 412938 by jim_thompson5910(28476) on 2012-10-09 14:20:33 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Distribute.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
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Answer:
So the solution is
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Equations/663500: Is 5y+13=5(y+13) all real numbers or no solution.
1 solutions
Answer 412799 by jim_thompson5910(28476) on 2012-10-08 20:21:26 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Distribute.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Simplify.
Since this equation is never true for any y value, this means that there are no solutions.
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test/663505: x/3-5=6 1 solutions
Answer 412796 by jim_thompson5910(28476) on 2012-10-08 20:19:44 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Multiply both sides by the LCD  to clear any fractions.
 Distribute and multiply.
 Add  to both sides.
 Combine like terms on the right side.
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Answer:
So the solution is
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Average/663480: maddie took a science test with 50 questions. she scored 84%. how many questions did she answer correctly
A)0.084
B)0.48
C)0.50
D)0.84 1 solutions
Answer 412787 by jim_thompson5910(28476) on 2012-10-08 20:00:58 (Show Source):
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Linear-systems/663314: 9x-3>6x-12 1 solutions
Answer 412717 by jim_thompson5910(28476) on 2012-10-08 15:55:38 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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