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2x- y = -4
-3x + y = -9 1 solutions
Answer 87727 by jim_thompson5910(28504) on 2008-01-11 19:13:18 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Solving a linear system of equations by subsitution |
Lets start with the given system of linear equations


Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
Solve for y for the first equation
Subtract from both sides
Divide both sides by -1.
Which breaks down and reduces to
Now we've fully isolated y
Since y equals we can substitute the expression into y of the 2nd equation. This will eliminate y so we can solve for x.
Replace y with . Since this eliminates y, we can now solve for x.
Distribute 1 to 
Multiply
Reduce any fractions
Subtract from both sides
Combine the terms on the right side
Now combine the terms on the left side.
Multiply both sides by . This will cancel out and isolate x
So when we multiply and (and simplify) we get
<---------------------------------One answer
Now that we know that , lets substitute that in for x to solve for y
Plug in into the 2nd equation
Multiply
Add to both sides
Combine the terms on the right side
Multiply both sides by . This will cancel out 1 on the left side.
Multiply the terms on the right side
Reduce
So this is the other answer
<---------------------------------Other answer
So our solution is
and 
which can also look like
( , )
Notice if we graph the equations (if you need help with graphing, check out this solver)


we get
graph of (red) and (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
and we can see that the two equations intersect at ( , ). This verifies our answer.
-----------------------------------------------------------------------------------------------
Check:
Plug in ( , ) into the system of equations
Let and . Now plug those values into the equation 
Plug in and 
Multiply
Add
Reduce. Since this equation is true the solution works.
So the solution ( , ) satisfies 
Let and . Now plug those values into the equation 
Plug in and 
Multiply
Add
Reduce. Since this equation is true the solution works.
So the solution ( , ) satisfies 
Since the solution ( , ) satisfies the system of equations


this verifies our answer.
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Complex_Numbers/119657: 2x + y = 3 with no given numbers 1 solutions
Answer 87726 by jim_thompson5910(28504) on 2008-01-11 19:11:41 (Show Source):
You can put this solution on YOUR website!Do you want to graph?
| Solved by pluggable solver: Graphing Linear Equations |
Start with the given equation
Subtract from both sides
Multiply both sides by 
Distribute 
Multiply
Rearrange the terms
Reduce any fractions
So the equation is now in slope-intercept form ( ) where (the slope) and (the y-intercept)
So to graph this equation lets plug in some points
Plug in x=-3

Multiply
Add
So here's one point (-3,9)

Now lets find another point
Plug in x=-2

Multiply
Add
So here's another point (-2,7). Add this to our graph

Now draw a line through these points
So this is the graph of through the points (-3,9) and (-2,7)
So from the graph we can see that the slope is (which tells us that in order to go from point to point we have to start at one point and go down -2 units and to the right 1 units to get to the next point), the y-intercept is (0, )and the x-intercept is ( ,0) ,or ( ,0) . So all of this information verifies our graph.
We could graph this equation another way. Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0, ).
So we have one point (0, )

Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0, ), we can go down 2 units

and to the right 1 units to get to our next point

Now draw a line through those points to graph 
So this is the graph of through the points (0,3) and (1,1)
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Linear-equations/119723: Graph each equation, 2x - 3y =12 1 solutions
Answer 87723 by jim_thompson5910(28504) on 2008-01-11 18:32:58 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Graphing Linear Equations |
Start with the given equation
Subtract from both sides
Multiply both sides by 
Distribute 
Multiply
Rearrange the terms
Reduce any fractions
So the equation is now in slope-intercept form ( ) where (the slope) and (the y-intercept)
So to graph this equation lets plug in some points
Plug in x=-6

Multiply
Add
Reduce
So here's one point (-6,-8)

Now lets find another point
Plug in x=-3

Multiply
Add
Reduce
So here's another point (-3,-6). Add this to our graph

Now draw a line through these points
So this is the graph of through the points (-6,-8) and (-3,-6)
So from the graph we can see that the slope is (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 3 units to get to the next point) the y-intercept is (0, )and the x-intercept is ( ,0) . So all of this information verifies our graph.
We could graph this equation another way. Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0, ).
So we have one point (0, )

Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0, ), we can go up 2 units

and to the right 3 units to get to our next point

Now draw a line through those points to graph 
So this is the graph of through the points (0,-4) and (3,-2)
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Polynomials-and-rational-expressions/119700: factoring z^2+18z+45 1 solutions
Answer 87711 by jim_thompson5910(28504) on 2008-01-11 16:03:54 (Show Source):
You can put this solution on YOUR website!
Looking at  we can see that the first term is  and the last term is  where the coefficients are 1 and 45 respectively.
Now multiply the first coefficient 1 and the last coefficient 45 to get 45. Now what two numbers multiply to 45 and add to the middle coefficient 18? Let's list all of the factors of 45:
Factors of 45:
1,3,5,9,15,45
-1,-3,-5,-9,-15,-45 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 45
1*45
3*15
5*9
(-1)*(-45)
(-3)*(-15)
(-5)*(-9)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 18? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 18
| First Number | Second Number | Sum | | 1 | 45 | 1+45=46 | | 3 | 15 | 3+15=18 | | 5 | 9 | 5+9=14 | | -1 | -45 | -1+(-45)=-46 | | -3 | -15 | -3+(-15)=-18 | | -5 | -9 | -5+(-9)=-14 |
From this list we can see that 3 and 15 add up to 18 and multiply to 45
Now looking at the expression  , replace  with  (notice  adds up to  . So it is equivalent to  )
Now let's factor  by grouping:
 Group like terms
 Factor out the GCF of  out of the first group. Factor out the GCF of  out of the second group
 Since we have a common term of  , we can combine like terms
So  factors to
So this also means that  factors to  (since  is equivalent to  )
------------------------------------------------------------
Answer:
So  factors to
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Polynomials-and-rational-expressions/119704: Factor completlety 16x^2-2x-3 1 solutions
Answer 87710 by jim_thompson5910(28504) on 2008-01-11 16:02:07 (Show Source):
You can put this solution on YOUR website!
Looking at  we can see that the first term is  and the last term is  where the coefficients are 16 and -3 respectively.
Now multiply the first coefficient 16 and the last coefficient -3 to get -48. Now what two numbers multiply to -48 and add to the middle coefficient -2? Let's list all of the factors of -48:
Factors of -48:
1,2,3,4,6,8,12,16,24,48
-1,-2,-3,-4,-6,-8,-12,-16,-24,-48 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -48
(1)*(-48)
(2)*(-24)
(3)*(-16)
(4)*(-12)
(6)*(-8)
(-1)*(48)
(-2)*(24)
(-3)*(16)
(-4)*(12)
(-6)*(8)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -2
| First Number | Second Number | Sum | | 1 | -48 | 1+(-48)=-47 | | 2 | -24 | 2+(-24)=-22 | | 3 | -16 | 3+(-16)=-13 | | 4 | -12 | 4+(-12)=-8 | | 6 | -8 | 6+(-8)=-2 | | -1 | 48 | -1+48=47 | | -2 | 24 | -2+24=22 | | -3 | 16 | -3+16=13 | | -4 | 12 | -4+12=8 | | -6 | 8 | -6+8=2 |
From this list we can see that 6 and -8 add up to -2 and multiply to -48
Now looking at the expression  , replace  with  (notice  adds up to  . So it is equivalent to  )
Now let's factor  by grouping:
 Group like terms
 Factor out the GCF of  out of the first group. Factor out the GCF of  out of the second group
 Since we have a common term of  , we can combine like terms
So  factors to
So this also means that  factors to  (since  is equivalent to  )
------------------------------------------------------------
Answer:
So  factors to
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expressions/119708: How do I factor this?
X^2-12x+36 1 solutions
Answer 87709 by jim_thompson5910(28504) on 2008-01-11 16:01:02 (Show Source):
You can put this solution on YOUR website!
Looking at  we can see that the first term is  and the last term is  where the coefficients are 1 and 36 respectively.
Now multiply the first coefficient 1 and the last coefficient 36 to get 36. Now what two numbers multiply to 36 and add to the middle coefficient -12? Let's list all of the factors of 36:
Factors of 36:
1,2,3,4,6,9,12,18
-1,-2,-3,-4,-6,-9,-12,-18 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 36
1*36
2*18
3*12
4*9
6*6
(-1)*(-36)
(-2)*(-18)
(-3)*(-12)
(-4)*(-9)
(-6)*(-6)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to -12? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -12
| First Number | Second Number | Sum | | 1 | 36 | 1+36=37 | | 2 | 18 | 2+18=20 | | 3 | 12 | 3+12=15 | | 4 | 9 | 4+9=13 | | 6 | 6 | 6+6=12 | | -1 | -36 | -1+(-36)=-37 | | -2 | -18 | -2+(-18)=-20 | | -3 | -12 | -3+(-12)=-15 | | -4 | -9 | -4+(-9)=-13 | | -6 | -6 | -6+(-6)=-12 |
From this list we can see that -6 and -6 add up to -12 and multiply to 36
Now looking at the expression  , replace  with  (notice  adds up to  . So it is equivalent to  )
Now let's factor  by grouping:
 Group like terms
 Factor out the GCF of  out of the first group. Factor out the GCF of  out of the second group
 Since we have a common term of  , we can combine like terms
So  factors to
So this also means that  factors to  (since  is equivalent to  )
note:  is equivalent to  since the term  occurs twice. So  also factors to
------------------------------------------------------------
Answer:
So  factors to
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expressions/119714: Is this the right factoring
x^2-5x-6
(x-2)(x-3) 1 solutions
Answer 87708 by jim_thompson5910(28504) on 2008-01-11 16:00:04 (Show Source):
You can put this solution on YOUR website!No it is not. If you foil  you'll get
Looking at  we can see that the first term is  and the last term is  where the coefficients are 1 and -6 respectively.
Now multiply the first coefficient 1 and the last coefficient -6 to get -6. Now what two numbers multiply to -6 and add to the middle coefficient -5? Let's list all of the factors of -6:
Factors of -6:
1,2,3,6
-1,-2,-3,-6 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -6
(1)*(-6)
(2)*(-3)
(-1)*(6)
(-2)*(3)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -5? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -5
| First Number | Second Number | Sum | | 1 | -6 | 1+(-6)=-5 | | 2 | -3 | 2+(-3)=-1 | | -1 | 6 | -1+6=5 | | -2 | 3 | -2+3=1 |
From this list we can see that 1 and -6 add up to -5 and multiply to -6
Now looking at the expression  , replace  with  (notice  adds up to  . So it is equivalent to  )
Now let's factor  by grouping:
 Group like terms
 Factor out the GCF of  out of the first group. Factor out the GCF of  out of the second group
 Since we have a common term of  , we can combine like terms
So  factors to
So this also means that  factors to  (since  is equivalent to  )
------------------------------------------------------------
Answer:
So  factors to
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expressions/119713: Was I able to factor this correctly?
4x^2-15x-25
=(2x+5)(2x+5)
1 solutions
Answer 87707 by jim_thompson5910(28504) on 2008-01-11 15:56:22 (Show Source):
You can put this solution on YOUR website!
Looking at  we can see that the first term is  and the last term is  where the coefficients are 4 and -25 respectively.
Now multiply the first coefficient 4 and the last coefficient -25 to get -100. Now what two numbers multiply to -100 and add to the middle coefficient -15? Let's list all of the factors of -100:
Factors of -100:
1,2,4,5,10,20,25,50
-1,-2,-4,-5,-10,-20,-25,-50 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -100
(1)*(-100)
(2)*(-50)
(4)*(-25)
(5)*(-20)
(-1)*(100)
(-2)*(50)
(-4)*(25)
(-5)*(20)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -15? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -15
| First Number | Second Number | Sum | | 1 | -100 | 1+(-100)=-99 | | 2 | -50 | 2+(-50)=-48 | | 4 | -25 | 4+(-25)=-21 | | 5 | -20 | 5+(-20)=-15 | | -1 | 100 | -1+100=99 | | -2 | 50 | -2+50=48 | | -4 | 25 | -4+25=21 | | -5 | 20 | -5+20=15 |
From this list we can see that 5 and -20 add up to -15 and multiply to -100
Now looking at the expression  , replace  with  (notice  adds up to  . So it is equivalent to  )
Now let's factor  by grouping:
 Group like terms
 Factor out the GCF of  out of the first group. Factor out the GCF of  out of the second group
 Since we have a common term of  , we can combine like terms
So  factors to
So this also means that  factors to  (since  is equivalent to  )
So  factors to
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Polynomials-and-rational-expressions/119703: factor completely -3t^3+3t^2-6t 1 solutions
Answer 87705 by jim_thompson5910(28504) on 2008-01-11 15:30:53 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression
 Factor out the GCF
Now let's focus on the inner expression
------------------------------------------------------------
Looking at  we can see that the first term is  and the last term is  where the coefficients are 1 and 2 respectively.
Now multiply the first coefficient 1 and the last coefficient 2 to get 2. Now what two numbers multiply to 2 and add to the middle coefficient -1? Let's list all of the factors of 2:
Factors of 2:
1,2
-1,-2 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 2
1*2
(-1)*(-2)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to -1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -1
| First Number | Second Number | Sum | | 1 | 2 | 1+2=3 | | -1 | -2 | -1+(-2)=-3 |
None of these pairs of factors add to -1. So the expression  cannot be factored
------------------------------------------------------------
Answer:
So  factors to
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Equations/119697: Can you help me with this equation?
Calculate the total rent paid on an apartment for n months if the rent is $565 a month 1 solutions
Answer 87689 by jim_thompson5910(28504) on 2008-01-11 13:56:00 (Show Source):
You can put this solution on YOUR website!To find the total rent after 2 months, just multiply 2 and 565 to get  . To find the total rent after 3 months, just multiply 3 and 565 to get  . This pattern continues...
So to find the total rent after n months, just multiply n and 565 to get  .
So the total rent due after n months is 565n
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Linear-equations/119694: graph equation
y=3\4x+2 1 solutions
Answer 87687 by jim_thompson5910(28504) on 2008-01-11 13:38:53 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Graphing Linear Equations |
In order to graph we only need to plug in two points to draw the line
So lets plug in some points
Plug in x=-8

Multiply
Add
Reduce
So here's one point (-8,-4)

Now lets find another point
Plug in x=-4

Multiply
Add
Reduce
So here's another point (-4,-1). Add this to our graph

Now draw a line through these points
So this is the graph of through the points (-8,-4) and (-4,-1)
So from the graph we can see that the slope is (which tells us that in order to go from point to point we have to start at one point and go up 3 units and to the right 4 units to get to the next point) the y-intercept is (0, )and the x-intercept is ( ,0) ,or ( ,0)
We could graph this equation another way. Since this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0, ).
So we have one point (0, )

Now since the slope is , this means that in order to go from point to point we can use the slope to do so. So starting at (0, ), we can go up 3 units

and to the right 4 units to get to our next point

Now draw a line through those points to graph 
So this is the graph of through the points (0,2) and (4,5)
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Linear-equations/119695: graph equation using intercept method
2x+3y=6 2x-3y=12 1 solutions
Answer 87686 by jim_thompson5910(28504) on 2008-01-11 13:37:29 (Show Source):
You can put this solution on YOUR website!#1
 Start with the given equation
Let's find the x-intercept
To find the x-intercept, let y=0 and solve for x:
 Plug in
 Simplify
 Divide both sides by 2
 Reduce
So the x-intercept is ) (note: the x-intercept will always have a y-coordinate equal to zero)
------------------
 Start with the given equation
Now let's find the y-intercept
To find the y-intercept, let x=0 and solve for y:
 Plug in
 Simplify
 Divide both sides by 3
 Reduce
So the y-intercept is ) (note: the y-intercept will always have a x-coordinate equal to zero)
------------------------------------------
So we have these intercepts:
x-intercept:
y-intercept:
Now plot the two points ) and
Now draw a line through the two points to graph
 graph of  through the points ) and
#2
 Start with the given equation
Let's find the x-intercept
To find the x-intercept, let y=0 and solve for x:
 Plug in
 Simplify
 Divide both sides by 2
 Reduce
So the x-intercept is ) (note: the x-intercept will always have a y-coordinate equal to zero)
------------------
 Start with the given equation
Now let's find the y-intercept
To find the y-intercept, let x=0 and solve for y:
 Plug in
 Simplify
 Divide both sides by -3
 Reduce
So the y-intercept is ) (note: the y-intercept will always have a x-coordinate equal to zero)
------------------------------------------
So we have these intercepts:
x-intercept:
y-intercept:
Now plot the two points ) and
Now draw a line through the two points to graph
 graph of  through the points ) and
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Expressions-with-variables/119691: Solve each system by substitution. check your answer.
y=x-2
y=4x+1 1 solutions
Answer 87683 by jim_thompson5910(28504) on 2008-01-11 13:15:22 (Show Source):
You can put this solution on YOUR website!
Start with the given system
 Plug in  into the first equation. In other words, replace each  with  . Notice we've eliminated the  variables. So we now have a simple equation with one unknown.
 Subtract 1 from both sides
 Subtract x from both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by 3 to isolate x
 Divide
Now that we know that  , we can plug this into  to find
 Substitute  for each
 Simplify
So our answer is  and
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Quadratic_Equations/119662: One root of x^2-4x+4a=0 is 2-4i. What is the value of a ? 1 solutions
Answer 87681 by jim_thompson5910(28504) on 2008-01-11 12:53:13 (Show Source):
You can put this solution on YOUR website!If 2-4i is a root, then when  , the entire left side will equal zero.
 Start with the given equation
 Plug in
 Foil and distribute
 Replace  with
 Multiply
 Combine like terms
 Add 20 to both sides
 Combine like terms on the right side
 Divide both sides by 4 to isolate a
 Divide
--------------------------------------------------------------
Answer:
So our answer is
Note: you can check this answer by using the quadratic formula
|
Rational-functions/119617: Hey, I need help with identities in chapter 6 lesson 6 of my book entitled Rational Expressions and Equations it says as follows: Equations that are true for all acceptable replacements of the variable are identities. Determine which equations areidenties.
problem as follows: xsquared + 6x - 16/ x-2 = x + 8
I also need help with solving rational expressions.
This is algebra 2
Thank you so much
I can realy use the help I need to bring up my grade cause I am realy worried about my G.P.A. because I want to get into a very good college.
Thanks again 1 solutions
Answer 87619 by jim_thompson5910(28504) on 2008-01-10 20:29:22 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation. Note: since  since that will make the denominator equal to zero
 Factor  to get
 Combine the fractions
 Cancel like terms
 Simplify
 Subtract 8 from both sides
 Subtract x from both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Simplify
Since this equation is always true for any x value, this means  is an identity and x can equal any number except 2.
|
logarithm/119567: can you please explain this to me step by step so i can understand it.
log(3-2x) - log (x+9)=0
i hope you can help me understand this
thank you
julie 1 solutions
Answer 87603 by jim_thompson5910(28504) on 2008-01-10 18:23:43 (Show Source):
You can put this solution on YOUR website! Start with the given equation. Note: Since you did not specify a base, this means that we're going to use the default base 10.
 Combine the logs using the identity
 Rewrite the equation using the property:  ====>
 Evaluate  to get
 Multiply both sides by
 Subtract 9 from both sides
 Add 2x to both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by 3 to isolate x
 Divide
--------------------------------------------------------------
Answer:
So our answer is
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Inequalities/119564: how do you solve and graph the absolute value 2x > 6? 1 solutions
Answer 87601 by jim_thompson5910(28504) on 2008-01-10 18:16:47 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality
Break up the absolute value (remember, if you have  , then  or  )
 or  Break up the absolute value inequality using the given rule
Now lets focus on the first inequality
 Start with the given inequality
 Divide both sides by 2 to isolate x
 Divide
Now lets focus on the second inequality
 Start with the given inequality
 Divide both sides by 2 to isolate x
 Divide
----------------------------------------------------
Answer:
So our answer is
 or
which looks like this in interval notation
if you wanted to graph the solution set, you would get
 Graph of the solution set in blue and the excluded values represented by open circles
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logarithm/119561: can you please explain this to me in step by step form so hopefully i can understand this.
log x 9/4 =2
please help me
thank you
julie 1 solutions
Answer 87599 by jim_thompson5910(28504) on 2008-01-10 18:11:14 (Show Source):
You can put this solution on YOUR website!Does this say: "log base x of 9/4 equals 2"? If it does, then...
 Start with the given equation.
 Rewrite the equation using the property:  ====>
 Take the square root of both sides. Since you cannot take the log of a negative number, I'm going to exclude the negative answer.
 Break up the square root
 Simplify  to get
 Simplify  to get
So our answer is
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Triangles/119555: In a quadrilateral JKLM, measure angle J=x,measure angle K=2x, measure angle L=2x+10,and measure angle M=3x-5. Find the measure of the angle. 1 solutions
Answer 87598 by jim_thompson5910(28504) on 2008-01-10 18:05:23 (Show Source):
You can put this solution on YOUR website!For any quadrilateral, the sum of the 4 angles is 360 degrees. So in this case,
 Start with the given equation
 Plug in  ,  ,  ,and
 Combine like terms on the left side
 Subtract 5 from both sides
 Combine like terms on the right side
 Divide both sides by 8 to isolate x
 Reduce
Since  (which is  in decimal form), our first angle is
Since  , we can plug this into  to get
So our second angle is
Since  , we can plug this into  to get
So our third angle is
Since  , we can plug this into  to get
So our fourth angle is
--------------------------------------------------------------
Answer:
So the measures of the four angles are:
 ,  ,  , and
Check:
 Start with the given equation
 Plug in  ,  ,  , and
 Add. Since the two sides of the equation are equal, this verifies our answer.
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Quadratic_Equations/119529: This question is from textbook
determine whether the equation has 2 solutions, 1 solution, or no solution. SHOW WORK! PUT IN STANDARD FORM!
22)x^2-3x+2=0
24)-3x^2+5x-1=0
26)x^2-2x+4=0
28)3x^2-6x+3=0
30)-5x^2+6x-6=0 1 solutions
Answer 87595 by jim_thompson5910(28504) on 2008-01-10 17:46:15 (Show Source):
You can put this solution on YOUR website!I'll do the first two to help you get started
#22
From the quadratic formula
the discriminant consists of all of the terms in the square root. So the discriminant is
the discriminant tells us how many solutions (and what type of solutions) we can expect for any quadratic.
Now let's find the discriminant for  :
 Plug in a=1, b=-3, c=2
 Square -3 to get 9
 Multiply -4*1*2 to get -8
 Combine 9 and -8 to get 1
Since the discriminant equals 1 (which is greater than zero) , this means there are two real solutions. Remember if the discriminant is greater than zero, then the quadratic will have two real solutions.
#24
From the quadratic formula
the discriminant consists of all of the terms in the square root. So the discriminant is
the discriminant tells us how many solutions (and what type of solutions) we can expect for any quadratic.
Now let's find the discriminant for  :
 Plug in a=-3, b=5, c=-1
 Square 5 to get 25
 Multiply -4*-3*-1 to get -12
 Combine 25 and -12 to get 13
Since the discriminant equals 13 (which is greater than zero) , this means there are two real solutions. Remember if the discriminant is greater than zero, then the quadratic will have two real solutions.
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test/119540: This question is from textbook Algebra II
I really really need help and I've been searching over the internet for the best source to hepl me unfortunately my school exam on this is tomorrow. But it would really help to know how to do the problems. My main problem is in Chapter 3 of my book , on Solving Linear Systems Alegraically. I don't understand anything about it, it just confuses me .
such as 3x + 4y equals -4
x + 2y equals 2
and in the book it says to solve the linear system using the substituion method.
I'm having problems on problems like that and on graphing in section 3.3 of my book on Graphing and Solving Systems of Linear inequalities.
on pages 159 and 148 mostly those pages
THanks! 1 solutions
Answer 87594 by jim_thompson5910(28504) on 2008-01-10 17:35:57 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Solving a linear system of equations by subsitution |
Lets start with the given system of linear equations


Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
Solve for y for the first equation
Subtract from both sides
Divide both sides by 4.
Which breaks down and reduces to
Now we've fully isolated y
Since y equals we can substitute the expression into y of the 2nd equation. This will eliminate y so we can solve for x.
Replace y with . Since this eliminates y, we can now solve for x.
Distribute 2 to 
Multiply
Reduce any fractions
Add to both sides
Combine the terms on the right side
Make 1 into a fraction with a denominator of 2
Now combine the terms on the left side.
Multiply both sides by . This will cancel out and isolate x
So when we multiply and (and simplify) we get
<---------------------------------One answer
Now that we know that , lets substitute that in for x to solve for y
Plug in into the 2nd equation
Multiply
Add to both sides
Combine the terms on the right side
Multiply both sides by . This will cancel out 2 on the left side.
Multiply the terms on the right side
Reduce
So this is the other answer
<---------------------------------Other answer
So our solution is
and 
which can also look like
( , )
Notice if we graph the equations (if you need help with graphing, check out this solver)


we get
graph of (red) and (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
and we can see that the two equations intersect at ( , ). This verifies our answer.
-----------------------------------------------------------------------------------------------
Check:
Plug in ( , ) into the system of equations
Let and . Now plug those values into the equation 
Plug in and 
Multiply
Add
Reduce. Since this equation is true the solution works.
So the solution ( , ) satisfies 
Let and . Now plug those values into the equation 
Plug in and 
Multiply
Add
Reduce. Since this equation is true the solution works.
So the solution ( , ) satisfies 
Since the solution ( , ) satisfies the system of equations


this verifies our answer.
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Linear-equations/119522: a line with slope 305and y-intercept (0,4)
9 1 solutions
Answer 87568 by jim_thompson5910(28504) on 2008-01-10 16:00:01 (Show Source):
You can put this solution on YOUR website!Is the slope supposed to say "3/5"?
If you want to find the equation of line with a given a slope of  which goes through the point (  ,  ), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
 where  is the slope, and ) is the given point
So lets use the Point-Slope Formula to find the equation of the line
 Plug in  ,  , and  (these values are given)
 Distribute
 Multiply  and  to get
 Add 4 to both sides to isolate y
 Combine like terms  and  to get
------------------------------------------------------------------------------------------------------------
Answer:
So the equation of the line with a slope of  which goes through the point (  ,  ) is:
 which is now in  form where the slope is  and the y-intercept is
Notice if we graph the equation  and plot the point (  ,  ), we get (note: if you need help with graphing, check out this solver)
Graph of through the point ( , )
and we can see that the point lies on the line. Since we know the equation has a slope of and goes through the point ( , ), this verifies our answer.
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Inequalities/119513: how would you solve this -3 > 7y-3 > -24 1 solutions
Answer 87565 by jim_thompson5910(28504) on 2008-01-10 15:39:30 (Show Source):
You can put this solution on YOUR website! Start with the given compound inequality
 Reverse the compound inequality by switching the outer sides and reversing the inequality signs
 Add 3 to all sides
 Divide every side by 7 to isolate y.
So the solution in interval notation is: (-3,0)
Now let's graph the solution set
Note: at  there is a open circle (which means this point is excluded) and at  there is a open circle (which means this point is excluded)
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expressions/119518: I really need help with these questions.
Evaluate each function for x= -2,0,and 5.
1.) y = 9 + x
2.) y = x^2 - 1
Please help me because I need to get this to my teacher tommorrow. 1 solutions
Answer 87562 by jim_thompson5910(28504) on 2008-01-10 15:34:29 (Show Source):
You can put this solution on YOUR website!#1
Let's evaluate
 Start with the given function.
 Plug in  . In other words, replace each x with -2.
 Multiply 1 and -2 to get -2
 Now combine like terms
-----------Now let's evaluate another value---------
Let's evaluate
 Start with the given function.
 Plug in  . In other words, replace each x with 0.
 Multiply 1 and 0 to get 0
 Now combine like terms
-----------Now let's evaluate another value---------
Let's evaluate
 Start with the given function.
 Plug in  . In other words, replace each x with 5.
 Multiply 1 and 5 to get 5
 Now combine like terms
#2
Let's evaluate
 Start with the given function.
 Plug in  . In other words, replace each x with -2.
 Evaluate  to get 4.
 Now combine like terms
-----------Now let's evaluate another value---------
Let's evaluate
 Start with the given function.
 Plug in  . In other words, replace each x with 0.
 Evaluate  to get 0.
 Now combine like terms
-----------Now let's evaluate another value---------
Let's evaluate
 Start with the given function.
 Plug in  . In other words, replace each x with 5.
 Evaluate  to get 25.
 Now combine like terms
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Radicals/119510: Find the distance between each pair of points.
1. (0,8)and(0,-4)
2. (2,6)and(-3,4)
I'm lost on where to start on this type of problem. 1 solutions
Answer 87548 by jim_thompson5910(28504) on 2008-01-10 13:15:12 (Show Source):
You can put this solution on YOUR website!#1
Start with the given distance formula
 where ) is the first point ) and ) is the second point
 Plug in  ,  ,  ,
 Evaluate  to get 0. Evaluate  to get 12.
 Square each value
 Add
 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
So the distance between (0,8) and (0,-4) is 12 units
#2
Start with the given distance formula
 where ) is the first point ) and ) is the second point
 Plug in  ,  ,  ,
 Evaluate  to get 5. Evaluate  to get 2.
 Square each value
 Add
So the distance approximates to
which rounds to
5.39
So the distance between (2,6) and (-3,4) is approximately 5.39 units
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