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Linear_Algebra/124795: This question is from textbook Algebra 2
Write an equation for the line containing the indicated points.
(-6,-6) and (-3,1)
1 solutions

Answer 91483 by jim_thompson5910(28593) About Me  on 2008-02-04 16:35:05 (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Finding the Equation of a Line
First lets find the slope through the points (-6,-6) and (-3,1)


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula (note: (x%5B1%5D,y%5B1%5D) is the first point (-6,-6) and (x%5B2%5D,y%5B2%5D) is the second point (-3,1))


m=%281--6%29%2F%28-3--6%29 Plug in y%5B2%5D=1,y%5B1%5D=-6,x%5B2%5D=-3,x%5B1%5D=-6 (these are the coordinates of given points)


m=+7%2F3 Subtract the terms in the numerator 1--6 to get 7. Subtract the terms in the denominator -3--6 to get 3



So the slope is

m=7%2F3


------------------------------------------------


Now let's use the point-slope formula to find the equation of the line:




------Point-Slope Formula------
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and (x%5B1%5D,y%5B1%5D) is one of the given points


So lets use the Point-Slope Formula to find the equation of the line


y--6=%287%2F3%29%28x--6%29 Plug in m=7%2F3, x%5B1%5D=-6, and y%5B1%5D=-6 (these values are given)



y%2B6=%287%2F3%29%28x--6%29 Rewrite y--6 as y%2B6



y%2B6=%287%2F3%29%28x%2B6%29 Rewrite x--6 as x%2B6



y%2B6=%287%2F3%29x%2B%287%2F3%29%286%29 Distribute 7%2F3


y%2B6=%287%2F3%29x%2B14 Multiply 7%2F3 and 6 to get 42%2F3. Now reduce 42%2F3 to get 14

y=%287%2F3%29x%2B14-6 Subtract 6 from both sides to isolate y


y=%287%2F3%29x%2B8 Combine like terms 14 and -6 to get 8

------------------------------------------------------------------------------------------------------------

Answer:



So the equation of the line which goes through the points (-6,-6) and (-3,1) is:y=%287%2F3%29x%2B8


The equation is now in y=mx%2Bb form (which is slope-intercept form) where the slope is m=7%2F3 and the y-intercept is b=8


Notice if we graph the equation y=%287%2F3%29x%2B8 and plot the points (-6,-6) and (-3,1), we get this: (note: if you need help with graphing, check out this solver)


Graph of y=%287%2F3%29x%2B8 through the points (-6,-6) and (-3,1)


Notice how the two points lie on the line. This graphically verifies our answer.





Graphs/124727: Please help solve:
-2x+3y=-2
y=3x-3
1 solutions

Answer 91435 by jim_thompson5910(28593) About Me  on 2008-02-03 23:07:05 (Show Source):
You can put this solution on YOUR website!

Start with the given system
-2x%2B3y=-2
y=3x-3



-2x%2B3%283x-3%29=-2 Plug in y=3x-3 into the first equation. In other words, replace each y with 3x-3. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.


-2x%2B9x-9=-2 Distribute


7x-9=-2 Combine like terms on the left side


7x=-2%2B9Add 9 to both sides


7x=7 Combine like terms on the right side


x=%287%29%2F%287%29 Divide both sides by 7 to isolate x



x=1 Divide




Now that we know that x=1, we can plug this into y=3x-3 to find y



y=3%281%29-3 Substitute 1 for each x


y=0 Simplify


So our answer is x=1 and y=0 which also looks like



Notice if we graph the two equations, we can see that their intersection is at . So this verifies our answer.


+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+%28-2%2B2x%29%2F3%2C+3x-3%29+ Graph of -2x%2B3y=-2 (red) and y=3x-3 (green)


Graphs/124725: graph the line with the slope 2/3 passing through the point (-2,1)
1 solutions

Answer 91433 by jim_thompson5910(28593) About Me  on 2008-02-03 22:56:35 (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of 2%2F3 which goes through the point (-2,1), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y-1=%282%2F3%29%28x--2%29 Plug in m=2%2F3, x%5B1%5D=-2, and y%5B1%5D=1 (these values are given)


y-1=%282%2F3%29%28x%2B2%29 Rewrite x--2 as x%2B2


y-1=%282%2F3%29x%2B%282%2F3%29%282%29 Distribute 2%2F3

y-1=%282%2F3%29x%2B4%2F3 Multiply 2%2F3 and 2 to get 4%2F3

y=%282%2F3%29x%2B4%2F3%2B1 Add 1 to both sides to isolate y

y=%282%2F3%29x%2B7%2F3 Combine like terms 4%2F3 and 1 to get 7%2F3 (note: if you need help with combining fractions, check out this solver)


------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line with a slope of 2%2F3 which goes through the point (-2,1) is:

y=%282%2F3%29x%2B7%2F3 which is now in y=mx%2Bb form where the slope is m=2%2F3 and the y-intercept is b=7%2F3

Notice if we graph the equation y=%282%2F3%29x%2B7%2F3 and plot the point (-2,1), we get (note: if you need help with graphing, check out this solver)

Graph of y=%282%2F3%29x%2B7%2F3 through the point (-2,1)
and we can see that the point lies on the line. Since we know the equation has a slope of 2%2F3 and goes through the point (-2,1), this verifies our answer.


Graphs/124724: graph the inequality
3x-4y>-32
1 solutions

Answer 91432 by jim_thompson5910(28593) About Me  on 2008-02-03 22:55:56 (Show Source):
You can put this solution on YOUR website!
In order to graph 3x-4y%3E-32, we need to graph the equation 3x-4y=-32 (just replace the inequality sign with an equal sign).
So lets graph the line 3x-4y=-32 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+%283%2F4%29x%2B8%29+ graph of 3x-4y=-32
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality 3x-4y%3E-32 with the test point

Substitute (0,0) into the inequality
3%280%29-4%280%29%3E-32 Plug in x=0 and y=0
0%3E-32 Simplify



(note: for some reason, some of the following images do not display correctly in Internet Explorer. So I recommend the use of
Firefox to see these images.)


Since this inequality is true, we simply shade the entire region that contains (0,0)
Graph of 3x-4y%3E-32 with the boundary (which is the line 3x-4y=-32 in red) and the shaded region (in green)
(note: since the inequality contains a greater-than sign, this means the boundary is excluded. This means the solid red line is really a dashed line)


Graphs/124723: graph the inequality
4x+5y<16
1 solutions

Answer 91431 by jim_thompson5910(28593) About Me  on 2008-02-03 22:55:12 (Show Source):
You can put this solution on YOUR website!
In order to graph 4x%2B5y%3C16, we need to graph the equation 4x%2B5y=16 (just replace the inequality sign with an equal sign).
So lets graph the line 4x%2B5y=16 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+-%284%2F5%29x%2B%2816%2F5%29%29+ graph of 4x%2B5y=16
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality 4x%2B5y%3C16 with the test point

Substitute (0,0) into the inequality
4%280%29%2B5%280%29%3C16 Plug in x=0 and y=0
0%3C16 Simplify





Since this inequality is true, we simply shade the entire region that contains (0,0)
Graph of 4x%2B5y%3C16 with the boundary (which is the line 4x%2B5y=16 in red) and the shaded region (in green)
(note: since the inequality contains a less-than sign, this means the boundary is excluded. This means the solid red line is really a dashed line)


Graphs/124722: graph the line with the slope -4 ppassing through the point (2,-1)
1 solutions

Answer 91430 by jim_thompson5910(28593) About Me  on 2008-02-03 22:54:23 (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of -4 which goes through the point (2,-1), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y--1=%28-4%29%28x-2%29 Plug in m=-4, x%5B1%5D=2, and y%5B1%5D=-1 (these values are given)


y%2B1=%28-4%29%28x-2%29 Rewrite y--1 as y%2B1


y%2B1=-4x%2B%28-4%29%28-2%29 Distribute -4

y%2B1=-4x%2B8 Multiply -4 and -2 to get 8

y=-4x%2B8-1 Subtract 1 from both sides to isolate y

y=-4x%2B7 Combine like terms 8 and -1 to get 7
------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line with a slope of -4 which goes through the point (2,-1) is:

y=-4x%2B7 which is now in y=mx%2Bb form where the slope is m=-4 and the y-intercept is b=7

Notice if we graph the equation y=-4x%2B7 and plot the point (2,-1), we get (note: if you need help with graphing, check out this solver)

Graph of y=-4x%2B7 through the point (2,-1)
and we can see that the point lies on the line. Since we know the equation has a slope of -4 and goes through the point (2,-1), this verifies our answer.


Graphs/124720: Graph f(x) = 3x + 2.
THIS IS REALLY GIVING ME PROBLEMS TRYING TO GRAPH THIS EQUASTION.
1 solutions

Answer 91422 by jim_thompson5910(28593) About Me  on 2008-02-03 22:21:43 (Show Source):
You can put this solution on YOUR website!

Looking at y=3x%2B2 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=3 and the y-intercept is b=2


Since b=2 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 3, this means:

rise%2Frun=3%2F1


which shows us that the rise is 3 and the run is 1. This means that to go from point to point, we can go up 3 and over 1



So starting at , go up 3 units


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=3x%2B2

So this is the graph of y=3x%2B2 through the points and


Graphs/124719: Graph the inequality.

y%3C=3x

1 solutions

Answer 91420 by jim_thompson5910(28593) About Me  on 2008-02-03 22:19:35 (Show Source):


Graphs/124718: Solve the system by graphing.
x – 2y = 8
x + y = –1
REALLY NEED HELP GRAPHING!
1 solutions

Answer 91419 by jim_thompson5910(28593) About Me  on 2008-02-03 22:18:38 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:

1x-2y=8
1x%2By=-1




In order to graph these equations, we need to solve for y for each equation.



So let's solve for y on the first equation

1x-2y=8 Start with the given equation


-2y=8-x Subtract +x from both sides


-2y=-x%2B8 Rearrange the equation


y=%28-x%2B8%29%2F%28-2%29 Divide both sides by -2


y=%28-1%2F-2%29x%2B%288%29%2F%28-2%29 Break up the fraction


y=%281%2F2%29x-4 Reduce


Now lets graph y=%281%2F2%29x-4 (note: if you need help with graphing, check out this solver)


+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F2%29x-4%29+ Graph of y=%281%2F2%29x-4



So let's solve for y on the second equation

1x%2By=-1 Start with the given equation


1y=-1-x Subtract +x from both sides


1y=-x-1 Rearrange the equation


y=%28-x-1%29%2F%281%29 Divide both sides by 1


y=%28-1%2F1%29x%2B%28-1%29%2F%281%29 Break up the fraction


y=-x-1 Reduce



Now lets add the graph of y=-x-1 to our first plot to get:

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F2%29x-4%2C-x-1%29+ Graph of y=%281%2F2%29x-4(red) and y=-x-1(green)

From the graph, we can see that the two lines intersect at the point (2,-3) (note: you might have to adjust the window to see the intersection)


Graphs/124717: Solve the system by substitution.
2x – 4y = 18
y = –x – 12

1 solutions

Answer 91418 by jim_thompson5910(28593) About Me  on 2008-02-03 22:17:28 (Show Source):
You can put this solution on YOUR website!
Start with the given system
2x-4y=18
y=-x-12



2x-4%28-x-12%29=18 Plug in y=-x-12 into the first equation. In other words, replace each y with -x-12. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.


2x%2B4x%2B48=18 Distribute


6x%2B48=18 Combine like terms on the left side


6x=18-48Subtract 48 from both sides


6x=-30 Combine like terms on the right side


x=%28-30%29%2F%286%29 Divide both sides by 6 to isolate x



x=-5 Divide




Now that we know that x=-5, we can plug this into y=-1x-12 to find y



y=-%28-5%29-12 Substitute -5 for each x


y=-7 Simplify


So our answer is x=-5 and y=-7 which also looks like



Notice if we graph the two equations, we can see that their intersection is at . So this verifies our answer.


+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%2818-2x%29%2F%28-4%29%2C+-x-12%29+ Graph of 2x-4y=18 (red) and y=-x-12 (green)


decimal-numbers/124702: write 1/300 using sientifc notation.
i feel stupid for this but oh well.
1 solutions

Answer 91416 by jim_thompson5910(28593) About Me  on 2008-02-03 22:12:15 (Show Source):
You can put this solution on YOUR website!
First divide 1%2F300 to get 0.00333333333333 which rounds to 0.0033



3.3 Place a decimal between the first digit 3 and the second digit 3.

Now how many spots to the left must the decimal move to go from the number 3.3 to the number 0.0033?

The decimal needs to move 3 places to the left. So this is equivalent to multiplying 3.3 by 10%5E-3 to move the decimal 3 places to the left. Notice how the exponent -3 corresponds to the number of spots the decimal needs to move.


So putting all of this information together, we get

3.3%2A10%5E-3


This means that the number 0.0033 in scientific notation is 3.3%2A10%5E-3


In other words, 0.0033=3.3%2A10%5E-3



So this also means that the approximate value for 1%2F300 is 3.3%2A10%5E-3


Linear-systems/124713: The sum of two numbers is 52. Twice the first number is 17 more than the second. Find the numbers. I just need to know how to set this up.
1 solutions

Answer 91415 by jim_thompson5910(28593) About Me  on 2008-02-03 22:05:43 (Show Source):
You can put this solution on YOUR website!
The sentence "The sum of two numbers is 52" translates to x%2By=52


The sentence "Twice the first number is 17 more than the second" translates to 2x=y%2B17

So you get the system

x%2By=52
2x=y%2B17


Graphs/124698: Solve the system by graphing.
x – 2y = 8
x + y = –1

1 solutions

Answer 91414 by jim_thompson5910(28593) About Me  on 2008-02-03 22:02:47 (Show Source):
You can put this solution on YOUR website!


Start with the given system of equations:

1x-2y=8
1x%2By=-1




In order to graph these equations, we need to solve for y for each equation.



So let's solve for y on the first equation

1x-2y=8 Start with the given equation


-2y=8-x Subtract +x from both sides


-2y=-x%2B8 Rearrange the equation


y=%28-x%2B8%29%2F%28-2%29 Divide both sides by -2


y=%28-1%2F-2%29x%2B%288%29%2F%28-2%29 Break up the fraction


y=%281%2F2%29x-4 Reduce


Now lets graph y=%281%2F2%29x-4 (note: if you need help with graphing, check out this solver)


+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F2%29x-4%29+ Graph of y=%281%2F2%29x-4



So let's solve for y on the second equation

1x%2By=-1 Start with the given equation


1y=-1-x Subtract +x from both sides


1y=-x-1 Rearrange the equation


y=%28-x-1%29%2F%281%29 Divide both sides by 1


y=%28-1%2F1%29x%2B%28-1%29%2F%281%29 Break up the fraction


y=-x-1 Reduce



Now lets add the graph of y=-x-1 to our first plot to get:

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F2%29x-4%2C-x-1%29+ Graph of y=%281%2F2%29x-4(red) and y=-x-1(green)

From the graph, we can see that the two lines intersect at the point (2,-3) (note: you might have to adjust the window to see the intersection)


Graphs/124711: graph the inequality
2x+y<-9
1 solutions

Answer 91413 by jim_thompson5910(28593) About Me  on 2008-02-03 21:59:51 (Show Source):
You can put this solution on YOUR website!
In order to graph 2x%2By%3C-9, we need to graph the equation 2x%2By=-9 (just replace the inequality sign with an equal sign).
So lets graph the line 2x%2By=-9 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+-2x-9%29+ graph of 2x%2By=-9
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality 2x%2By%3C-9 with the test point

Substitute (0,0) into the inequality
2%280%29%2B%280%29%3C-9 Plug in x=0 and y=0
0%3C-9 Simplify



(note: for some reason, some of the following images do not display correctly in Internet Explorer. So I recommend the use of
Firefox to see these images.)


Since this inequality is not true, we do not shade the entire region that contains (0,0). So this means we shade the region that is on the opposite side of the line
Graph of 2x%2By%3C-9 with the boundary (which is the line 2x%2By=-9 in red) and the shaded region (in green)
(note: since the inequality contains a less-than sign, this means the boundary is excluded. This means the solid red line is really a dashed line)


Graphs/124710: graph the inequality
-x-y<8
1 solutions

Answer 91412 by jim_thompson5910(28593) About Me  on 2008-02-03 21:58:50 (Show Source):
You can put this solution on YOUR website!
In order to graph -x-y%3C8, we need to graph the equation -x-y=8 (just replace the inequality sign with an equal sign).
So lets graph the line -x-y=8 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+-x-8%29+ graph of -x-y=8
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality -x-y%3C8 with the test point

Substitute (0,0) into the inequality
-%280%29-%280%29%3C8 Plug in x=0 and y=0
0%3C8 Simplify



(note: for some reason, some of the following images do not display correctly in Internet Explorer. So I recommend the use of
Firefox to see these images.)


Since this inequality is true, we simply shade the entire region that contains (0,0)
Graph of -x-y%3C8 with the boundary (which is the line -x-y=8 in red) and the shaded region (in green)
(note: since the inequality contains a less-than sign, this means the boundary is excluded. This means the solid red line is really a dashed line)


Graphs/124709: graph the line with slope 4 passing through the point (4,2)
1 solutions

Answer 91411 by jim_thompson5910(28593) About Me  on 2008-02-03 21:57:52 (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of 4 which goes through the point (4,2), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y-2=%284%29%28x-4%29 Plug in m=4, x%5B1%5D=4, and y%5B1%5D=2 (these values are given)


y-2=4x%2B%284%29%28-4%29 Distribute 4

y-2=4x-16 Multiply 4 and -4 to get -16

y=4x-16%2B2 Add 2 to both sides to isolate y

y=4x-14 Combine like terms -16 and 2 to get -14
------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line with a slope of 4 which goes through the point (4,2) is:

y=4x-14 which is now in y=mx%2Bb form where the slope is m=4 and the y-intercept is b=-14

Notice if we graph the equation y=4x-14 and plot the point (4,2), we get (note: if you need help with graphing, check out this solver)

Graph of y=4x-14 through the point (4,2)
and we can see that the point lies on the line. Since we know the equation has a slope of 4 and goes through the point (4,2), this verifies our answer.


Equations/124706: t/9-7=-5
1 solutions

Answer 91409 by jim_thompson5910(28593) About Me  on 2008-02-03 21:48:51 (Show Source):
You can put this solution on YOUR website!

t%2F9-7=-5 Start with the given equation



%289%29%28t%2F9-7%29=%289%29%28-5%29 Multiply both sides by the LCM of 9. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)



t-63=-45 Distribute and multiply the LCM to each side



t=-45%2B63Add 63 to both sides


t=18 Combine like terms on the right side

--------------------------------------------------------------
Answer:
So our answer is t=18


Graphs/124700: Solve the system by substitution.
2x – 4y = 18
y = –x – 12

1 solutions

Answer 91407 by jim_thompson5910(28593) About Me  on 2008-02-03 21:38:44 (Show Source):
You can put this solution on YOUR website!
Start with the given system
2x-4y=18
y=-x-12



2x-4%28-x-12%29=18 Plug in y=-x-12 into the first equation. In other words, replace each y with -x-12. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.


2x%2B4x%2B48=18 Distribute


6x%2B48=18 Combine like terms on the left side


6x=18-48Subtract 48 from both sides


6x=-30 Combine like terms on the right side


x=%28-30%29%2F%286%29 Divide both sides by 6 to isolate x



x=-5 Divide




Now that we know that x=-5, we can plug this into y=-1x-12 to find y



y=-%28-5%29-12 Substitute -5 for each x


y=-7 Simplify


So our answer is x=-5 and y=-7 which also looks like



Notice if we graph the two equations, we can see that their intersection is at . So this verifies our answer.


+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%2818-2x%29%2F%28-4%29%2C+-x-12%29+ Graph of 2x-4y=18 (red) and y=-x-12 (green)


Equations/124703: Write the equation of the line with slope –7 and y-intercept (0, 5).
1 solutions

Answer 91406 by jim_thompson5910(28593) About Me  on 2008-02-03 21:35:08 (Show Source):
You can put this solution on YOUR website!

If you want to find the equation of line with a given a slope of -7 which goes through the point (0,5), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y-5=%28-7%29%28x-0%29 Plug in m=-7, x%5B1%5D=0, and y%5B1%5D=5 (these values are given)


y-5=-7x%2B%28-7%29%28-0%29 Distribute -7

y-5=-7x%2B0 Multiply -7 and -0 to get 0

y=-7x%2B0%2B5 Add 5 to both sides to isolate y

y=-7x%2B5 Combine like terms 0 and 5 to get 5
------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line with a slope of -7 which goes through the point (0,5) is:

y=-7x%2B5 which is now in y=mx%2Bb form where the slope is m=-7 and the y-intercept is b=5

Notice if we graph the equation y=-7x%2B5 and plot the point (0,5), we get (note: if you need help with graphing, check out this solver)

Graph of y=-7x%2B5 through the point (0,5)
and we can see that the point lies on the line. Since we know the equation has a slope of -7 and goes through the point (0,5), this verifies our answer.


Graphs/124692: The sum of two numbers is 29. Their difference is 7. What are the two numbers
1 solutions

Answer 91403 by jim_thompson5910(28593) About Me  on 2008-02-03 21:20:44 (Show Source):
You can put this solution on YOUR website!
The sentence "The sum of two numbers is 29" translates to the equation x%2By=29


The sentence "Their difference is 7" translates to the equation x-y=7




Start with the given system of equations:

system%28x%2By=29%2Cx-y=7%29



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the first equation

x%2By=29 Start with the first equation


y=29-x Subtract x from both sides


y=-x%2B29 Rearrange the equation


y=%28-x%2B29%29%2F%281%29 Divide both sides by 1


y=%28%28-1%29%2F%281%29%29x%2B%2829%29%2F%281%29 Break up the fraction


y=-x%2B29 Reduce



---------------------

Since y=-x%2B29, we can now replace each y in the second equation with -x%2B29 to solve for x



x-highlight%28%28-x%2B29%29%29=7 Plug in y=-x%2B29 into the first equation. In other words, replace each y with -x%2B29. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



x%2Bx-29=7 Distribute the negative


2x-29=7 Combine like terms on the left side


2x=7%2B29Add 29 to both sides


2x=36 Combine like terms on the right side


x=%2836%29%2F%282%29 Divide both sides by 2 to isolate x



x=18 Divide





-----------------First Answer------------------------------


So the first part of our answer is: x=18









Since we know that x=18 we can plug it into the equation y=-x%2B29 (remember we previously solved for y in the first equation).



y=-x%2B29 Start with the equation where y was previously isolated.


y=-%2818%29%2B29 Plug in x=18


y=-18%2B29 Multiply


y=11 Combine like terms



-----------------Second Answer------------------------------


So the second part of our answer is: y=11









-----------------Summary------------------------------

So our answers are:

x=18 and y=11

which form the point




So the two numbers are 18 and 11


Inequalities/124678: Find the solution set

%28x-1%29%2F%28x%2B2%29-%28x-3%29%2F%28x%2B1%29%3C1

1 solutions

Answer 91384 by jim_thompson5910(28593) About Me  on 2008-02-03 19:39:58 (Show Source):
You can put this solution on YOUR website!
%28x-1%29%2F%28x%2B2%29-%28x-3%29%2F%28x%2B1%29%3C1 Start with the given inequality




Multiply both sides by the LCD %28x%2B2%29%28x%2B1%29%281%29. Doing this will eliminate every fraction.


%28x%2B1%29%28x-1%29-%28x%2B2%29%28x-3%29%3C%28x%2B2%29%28x%2B1%29 Distribute and multiply. Notice every denominator has been canceled out.


%28x%5E2-1%29-%28x%5E2-x-6%29%3Cx%5E2%2B3x%2B2 Foil


x%5E2-1-x%5E2%2Bx%2B6%3Cx%5E2%2B3x%2B2 Distribute the negative


x%5E2-1-x%5E2%2Bx%2B6-x%5E2-3x-2%3C0 Get every term to the left side


-x%5E2-2x%2B3%3C0 Combine like terms


If we set -x%5E2-2x%2B3 equal to zero and solve, we'll find that the critical values are x=-3 or x=1


Now let's test a value that is less than -3


Let x=-4

-x%5E2-2x%2B3%3C0 Start with the given inequality


-%28-4%29%5E2-2%28-4%29%2B3%3C0 Plug in x=-4


-5%3C0 Simplify


Since this inequality is true, this means that any values less than x=-3 will satisfy the inequality



-------------------------------------


Now let's test a value that is in between -3 and 1


Let x=0

-x%5E2-2x%2B3%3C0 Start with the given inequality


-%280%29%5E2-2%280%29%2B3%3C0 Plug in x=0


3%3C0 Simplify


Since this inequality is not true, this means that any values in between -3 and 1 will not satisfy the inequality.


-------------------------------------


Now let's test a value that is in greater than 1


Let x=2

-x%5E2-2x%2B3%3C0 Start with the given inequality


-%282%29%5E2-2%282%29%2B3%3C0 Plug in x=2


-5%3C0 Simplify


Since this inequality is true, this means that any values greater than x=1 will satisfy the inequality




---------------------------------

Answer:


So any values that are either less than -3 or greater than 1 will satisfy the inequality


In other words, x%3C-3 or x%3E1


So the solution in interval notation is

U


Inequalities/124677: Find the solution set

-3%2F2%3C%283%282x-4%29%29%2F5%3C=2

1 solutions

Answer 91382 by jim_thompson5910(28593) About Me  on 2008-02-03 19:37:08 (Show Source):
You can put this solution on YOUR website!
-3%2F2%3C%283%282x-4%29%29%2F5%3C=2 Start with the given compound inequality


10%28-3%2F2%29%3C10%28%283%282x-4%29%29%2F5%29%3C=10%282%29 Multiply all sides by the LCD 10. This will eliminate the fractions


-15%3C6%282x-4%29%3C=20 Distribute and multiply


-15%3C12x-24%3C=20 Distribute again




9%3C12x%3C=44 Add 24 to all sides






9%2F12%3Cx%3C=44%2F12 Divide every side by 12 to isolate x.


3%2F4%3Cx%3C=11%2F3 Reduce.



So the solution in interval notation is: (3%2F4,11%2F3]


Now let's graph the solution set



Note: at x=3%2F4 there is a open circle (which means this point is excluded) and at x=11%2F3 there is a closed circle (which means this point is included)




Travel_Word_Problems/124676: A girl walked from her home into town at the rate of 4 miles per hour. She returned by bus over the same route. The bus averaged 20 miles per hour, and the entire round trip took 1 hour and 40 minutes, including the 10 minute wait for the bus. How far did the girl walk?


1 solutions

Answer 91381 by jim_thompson5910(28593) About Me  on 2008-02-03 19:34:37 (Show Source):
You can put this solution on YOUR website!
Let t%5B1%5D=walking time and t%5B2%5D=driving time


Now we're going to use the distance-rate-time equation d=rt

Since the walking speed is 4 mph and the walking time is t%5B1%5D, this means r=4 and t=t%5B1%5D

d=4t%5B1%5D Plug in r=4 and t=t%5B1%5D



Also, since the driving speed is 20 mph and the driving time is t%5B2%5D, this means r=20 and t=t%5B2%5D

d=20t%5B2%5D Plug in r=20 and t=t%5B2%5D


Because the distance is the same both ways, this means that d=4t%5B1%5D=20t%5B2%5D


4t%5B1%5D=20t%5B2%5D Start with the given equation


t%5B1%5D=5t%5B2%5D Divide both sides by 4 to isolate t%5B1%5D




If the entire trip took 1 hour and 40 minutes and there was a 10 minute wait, then the traveling portion took 1 hour and 30 minutes (which is 1.5 hours)


So the sum of these two times is 1.5. In other words, we have this first equation


t%5B1%5D%2Bt%5B2%5D=1.5


5t%5B2%5D%2Bt%5B2%5D=1.5 Plug in t%5B1%5D=5t%5B2%5D


6t%5B2%5D=1.5 Combine like terms


t%5B2%5D=0.25 Divide both sides by 6 to isolate t%5B2%5D


So the driving time is 0.25 hours or 15 minutes

Now let's go back to the equation d=20t%5B2%5D


d=20t%5B2%5D Start with the given equation


d=20%280.25%29 Plug in our answer t%5B2%5D=0.25


d=5 Multiply


So the distance that she traveled is 5 miles


Radicals/124675: Solve.
sqrt%28x-1%29%2Bsqrt%28x-4%29=sqrt%282x-1%29
1 solutions

Answer 91380 by jim_thompson5910(28593) About Me  on 2008-02-03 19:33:13 (Show Source):
You can put this solution on YOUR website!
sqrt%28x-1%29%2Bsqrt%28x-4%29=sqrt%282x-1%29 Start with the given equation


%28sqrt%28x-1%29%2Bsqrt%28x-4%29%29%5E2=%28sqrt%282x-1%29%29%5E2 Square both sides


%28sqrt%28x-1%29%2Bsqrt%28x-4%29%29%5E2=2x-1 Square the right side to remove the square root


sqrt%28x-1%29sqrt%28x-1%29%2B2sqrt%28x-1%29sqrt%28x-4%29%2Bsqrt%28x-4%29sqrt%28x-4%29=2x-1 Foil the left side

%28x-1%29%2B2sqrt%28%28x-1%29%28x-4%29%29%2B%28x-4%29=2x-1 Multiply


%28x-1%29%2B2sqrt%28x%5E2-5x%2B4%29%2B%28x-4%29=2x-1 Foil


2x-5%2B2sqrt%28x%5E2-5x%2B4%29=2x-1 Combine like terms


2sqrt%28x%5E2-5x%2B4%29=2x-1-2x%2B5 Subtract 2x from both sides. Add 5 to both sides.


2sqrt%28x%5E2-5x%2B4%29=4 Combine like terms


sqrt%28x%5E2-5x%2B4%29=2 Divide both sides by 2


x%5E2-5x%2B4=4 Square both sides


x%5E2-5x=0 Subtract 4 from both sides.


x%28x-5%29=0 Factor the left side


Now set each factor equal to zero:
x=0 or x-5=0

x=0 or x=5 Now solve for x in each case


So our possible answers are:
x=0 or x=5



Check:
Let's verify the first solution x=0

sqrt%28x-1%29%2Bsqrt%28x-4%29=sqrt%282x-1%29 Start with the given equation


sqrt%280-1%29%2Bsqrt%280-4%29=sqrt%282%280%29-1%29 Plug in x=0


sqrt%28-1%29%2Bsqrt%28-4%29=sqrt%28-1%29 Combine like terms


i%2B2i=i Simplify


3i=i Add. Since the two sides of the equation are not equal, this means that x=0 is not a solution.


-----------------

Let's verify the second solution x=5

sqrt%28x-1%29%2Bsqrt%28x-4%29=sqrt%282x-1%29 Start with the given equation


sqrt%285-1%29%2Bsqrt%285-4%29=sqrt%282%285%29-1%29 Plug in x=5


sqrt%284%29%2Bsqrt%281%29=sqrt%289%29 Combine like terms


2%2B1=3 Take the square root


3=3 Add. Since the two sides of the equation are equal, this verifies the solution


So the only solution is x=5


Inequalities/124674: Solve. Express your answer in interval notation and graph


abs%285x-14%29%3E=2x
1 solutions

Answer 91379 by jim_thompson5910(28593) About Me  on 2008-02-03 19:30:04 (Show Source):
You can put this solution on YOUR website!
abs%285x-14%29%3E=2x Start with the given inequality


5x-14%3E=2x or 5x-14%3C=-2x Break up the absolute value


Now let's solve the first inequality 5x-14%3E=2x


5x-14%3E=2x Start with the given inequality



5x%3E=2x%2B14Add 14 to both sides


5x-2x%3E=%2B14 Subtract 2x from both sides


3x%3E=14 Combine like terms on the left side


x%3E=%2814%29%2F%283%29 Divide both sides by 3 to isolate x



--------------------------------------------------------------
Answer:
So our answer is x%3E=14%2F3 (which is approximately x%3E=4.66666666666667 in decimal form)



Now let's solve the second inequality 5x-14%3C=-2x



5x-14%3C=-2x Start with the given inequality



5x%3C=-2x%2B14Add 14 to both sides


5x%2B2x%3C=%2B14 Add 2x to both sides


7x%3C=14 Combine like terms on the left side


x%3C=%2814%29%2F%287%29 Divide both sides by 7 to isolate x



x%3C=2 Divide

--------------------------------------------------------------
Answer:
So our answer is x%3C=2


--------------------------------------------------------------
Answer:

So our two answers are


x%3C=2 or x%3E=%2814%29%2F%283%29



So in interval notation our answer is

(-,2] U [14/3 ,



So if we graph the solutions, we get



Linear-systems/124657: The sum of two numbers is 38. Their difference is 10. What are the two numbers?

1 solutions

Answer 91377 by jim_thompson5910(28593) About Me  on 2008-02-03 19:16:56 (Show Source):
You can put this solution on YOUR website!
The sentence "The sum of two numbers is 38" translates to the equation x%2By=38



The sentence "Their difference is 10" translates to the equation x-y=10




Start with the given system of equations:

system%28x%2By=38%2Cx-y=10%29



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the first equation

x%2By=38 Start with the first equation


y=38-x Subtract x from both sides


y=-x%2B38 Rearrange the equation


y=%28-x%2B38%29%2F%281%29 Divide both sides by 1


y=%28%28-1%29%2F%281%29%29x%2B%2838%29%2F%281%29 Break up the fraction


y=-x%2B38 Reduce



---------------------

Since y=-x%2B38, we can now replace each y in the second equation with -x%2B38 to solve for x



x-highlight%28%28-x%2B38%29%29=10 Plug in y=-x%2B38 into the first equation. In other words, replace each y with -x%2B38. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



x%2Bx-38=10 Distribute the negative


2x-38=10 Combine like terms on the left side


2x=10%2B38Add 38 to both sides


2x=48 Combine like terms on the right side


x=%2848%29%2F%282%29 Divide both sides by 2 to isolate x



x=24 Divide





-----------------First Answer------------------------------


So the first part of our answer is: x=24









Since we know that x=24 we can plug it into the equation y=-x%2B38 (remember we previously solved for y in the first equation).



y=-x%2B38 Start with the equation where y was previously isolated.


y=-%2824%29%2B38 Plug in x=24


y=-24%2B38 Multiply


y=14 Combine like terms



-----------------Second Answer------------------------------


So the second part of our answer is: y=14









-----------------Summary------------------------------

So our answers are:

x=24 and y=14

which form the point




So the two numbers are 24 and 14


Radicals/124652: Solve.
1) m squared - 6m = 16

2) x squared + 5x = 3
1 solutions

Answer 91373 by jim_thompson5910(28593) About Me  on 2008-02-03 19:09:07 (Show Source):
You can put this solution on YOUR website!
# 1


m%5E2-6m=16 Start with the given equation


m%5E2-6m-16=0 Subtract 16 from both sides.

%28m-8%29%28m%2B2%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:
m-8=0 or m%2B2=0

m=8 or m=-2 Now solve for m in each case


So our answer is
m=8 or m=-2


Notice if we graph y=x%5E2-6x-16 (just replace m with x) we can see that the roots are x=8 and x=-2 . So this visually verifies our answer.


+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+x%5E2-6x-16%29+







# 2


x%5E2%2B5x=3 Start with the given equation


x%5E2%2B5x-3=0 Subtract 3 from both sides.

Let's use the quadratic formula to solve for x:


Starting with the general quadratic

ax%5E2%2Bbx%2Bc=0

the general solution using the quadratic equation is:

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29



So lets solve x%5E2%2B5%2Ax-3=0 ( notice a=1, b=5, and c=-3)




x+=+%28-5+%2B-+sqrt%28+%285%29%5E2-4%2A1%2A-3+%29%29%2F%282%2A1%29 Plug in a=1, b=5, and c=-3



x+=+%28-5+%2B-+sqrt%28+25-4%2A1%2A-3+%29%29%2F%282%2A1%29 Square 5 to get 25



x+=+%28-5+%2B-+sqrt%28+25%2B12+%29%29%2F%282%2A1%29 Multiply -4%2A-3%2A1 to get 12



x+=+%28-5+%2B-+sqrt%28+37+%29%29%2F%282%2A1%29 Combine like terms in the radicand (everything under the square root)



x+=+%28-5+%2B-+sqrt%2837%29%29%2F%282%2A1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



x+=+%28-5+%2B-+sqrt%2837%29%29%2F2 Multiply 2 and 1 to get 2

So now the expression breaks down into two parts

x+=+%28-5+%2B+sqrt%2837%29%29%2F2 or x+=+%28-5+-+sqrt%2837%29%29%2F2


Now break up the fraction


x=-5%2F2%2Bsqrt%2837%29%2F2 or x=-5%2F2-sqrt%2837%29%2F2




So these expressions approximate to

x=0.54138126514911 or x=-5.54138126514911


So our solutions are:
x=0.54138126514911 or x=-5.54138126514911

Notice when we graph x%5E2%2B5%2Ax-3, we get:



when we use the root finder feature on a calculator, we find that x=0.54138126514911 and x=-5.54138126514911.So this verifies our answer


Linear-systems/124654: Solve the system by substitution.
x + 5y = 11
–3x – 2y = –7

1 solutions

Answer 91371 by jim_thompson5910(28593) About Me  on 2008-02-03 19:05:17 (Show Source):
You can put this solution on YOUR website!


Start with the given system of equations:

system%28x%2B5y=11%2C-3x-2y=-7%29



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the first equation

x%2B5y=11 Start with the first equation


5y=11-x Subtract x from both sides


5y=-x%2B11 Rearrange the equation


y=%28-x%2B11%29%2F%285%29 Divide both sides by 5


y=%28%28-1%29%2F%285%29%29x%2B%2811%29%2F%285%29 Break up the fraction


y=%28-1%2F5%29x%2B11%2F5 Reduce



---------------------

Since y=%28-1%2F5%29x%2B11%2F5, we can now replace each y in the second equation with %28-1%2F5%29x%2B11%2F5 to solve for x



-3x-2highlight%28%28%28-1%2F5%29x%2B11%2F5%29%29=-7 Plug in y=%28-1%2F5%29x%2B11%2F5 into the first equation. In other words, replace each y with %28-1%2F5%29x%2B11%2F5. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



-3x%2B%28-2%29%28-1%2F5%29x%2B%28-2%29%2811%2F5%29=-7 Distribute -2 to %28-1%2F5%29x%2B11%2F5


-3x%2B%282%2F5%29x-22%2F5=-7 Multiply


%285%29%28-3x%2B%282%2F5%29x-22%2F5%29=%285%29%28-7%29 Multiply both sides by the LCM of 5. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)



-15x%2B2x-22=-35 Distribute and multiply the LCM to each side



-13x-22=-35 Combine like terms on the left side


-13x=-35%2B22Add 22 to both sides


-13x=-13 Combine like terms on the right side


x=%28-13%29%2F%28-13%29 Divide both sides by -13 to isolate x



x=1 Divide





-----------------First Answer------------------------------


So the first part of our answer is: x=1









Since we know that x=1 we can plug it into the equation y=%28-1%2F5%29x%2B11%2F5 (remember we previously solved for y in the first equation).



y=%28-1%2F5%29x%2B11%2F5 Start with the equation where y was previously isolated.


y=%28-1%2F5%29%281%29%2B11%2F5 Plug in x=1


y=-1%2F5%2B11%2F5 Multiply


y=2 Combine like terms and reduce. (note: if you need help with fractions, check out this solver)



-----------------Second Answer------------------------------


So the second part of our answer is: y=2









-----------------Summary------------------------------

So our answers are:

x=1 and y=2

which form the point








Now let's graph the two equations (if you need help with graphing, check out this solver)


From the graph, we can see that the two equations intersect at . This visually verifies our answer.




graph of x%2B5y=11 (red) and -3x-2y=-7 (green) and the intersection of the lines (blue circle).




Linear-systems/124655: Solve the system by addition.
4x – 5y = –19
x + 3y = 8

1 solutions

Answer 91370 by jim_thompson5910(28593) About Me  on 2008-02-03 19:04:12 (Show Source):
You can put this solution on YOUR website!


Start with the given system of equations:

system%284x-5y=-19%2Cx%2B3y=8%29



Now in order to solve this system by using elimination/addition, we need to solve (or isolate) one variable. I'm going to solve for y.





In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).


So lets eliminate x. In order to do that, we need to have both x coefficients that are equal in magnitude but have opposite signs (for instance 2 and -2 are equal in magnitude but have opposite signs). This way they will add to zero. By adding to zero, they can be eliminated.



So to make the x coefficients equal in magnitude but opposite in sign, we need to multiply both x coefficients by some number to get them to an common number. So if we wanted to get 4 and 1 to some equal number, we could try to get them to the LCM.



Since the LCM of 4 and 1 is 4, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -4 like this:




1%284x-5y%29=1%28-19%29 Multiply the top equation (both sides) by 1
-4%28x%2B3y%29=-4%288%29 Multiply the bottom equation (both sides) by -4




Distribute and multiply

4x-5y=-19
-4x-12y=-32


Now add the equations together. In order to add 2 equations, group like terms and combine them

%284x-4x%29%2B%28-5y-12y%29=-19-32

Combine like terms and simplify



cross%284x-4x%29-17y=-51 Notice how the x terms cancel out




-17y=-51 Simplify




y=-51%2F-17 Divide both sides by -17 to isolate y




y=3 Reduce



Now plug this answer into the top equation 4x-5y=-19 to solve for x

4x-5y=-19 Start with the first equation



4x-5%283%29=-19 Plug in y=3



4x=-19%2B15Add 15 to both sides


4x=-4 Combine like terms on the right side


x=%28-4%29%2F%284%29 Divide both sides by 4 to isolate x



x=-1 Divide




So our answer is
x=-1 and y=3



which also looks like




Now let's graph the two equations (if you need help with graphing, check out this solver)


From the graph, we can see that the two equations intersect at . This visually verifies our answer.




graph of 4x-5y=-19 (red) and x%2B3y=8 (green) and the intersection of the lines (blue circle).




Linear-systems/124659:
Given f(x) = x2 + 5x + 2, find f(0).
1 solutions

Answer 91369 by jim_thompson5910(28593) About Me  on 2008-02-03 19:02:19 (Show Source):
You can put this solution on YOUR website!

f%28x%29=x%5E2%2B5x%2B2 Start with the given function.


f%280%29=%280%29%5E2%2B5%280%29%2B2 Plug in x=0. In other words, replace each x with 0.


f%280%29=0%2B5%280%29%2B2 Evaluate %280%29%5E2 to get 0.


f%280%29=0%2B0%2B2 Multiply 5 and 0 to get 0


f%280%29=2 Now combine like terms


Radicals/124660: Solve.
x squared - 6x - 3 = 0
1 solutions

Answer 91367 by jim_thompson5910(28593) About Me  on 2008-02-03 19:01:10 (Show Source):
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:


Starting with the general quadratic

ax%5E2%2Bbx%2Bc=0

the general solution using the quadratic equation is:

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29



So lets solve x%5E2-6%2Ax-3=0 ( notice a=1, b=-6, and c=-3)




x+=+%28--6+%2B-+sqrt%28+%28-6%29%5E2-4%2A1%2A-3+%29%29%2F%282%2A1%29 Plug in a=1, b=-6, and c=-3



x+=+%286+%2B-+sqrt%28+%28-6%29%5E2-4%2A1%2A-3+%29%29%2F%282%2A1%29 Negate -6 to get 6



x+=+%286+%2B-+sqrt%28+36-4%2A1%2A-3+%29%29%2F%282%2A1%29 Square -6 to get 36 (note: remember when you square -6, you must square the negative as well. This is because %28-6%29%5E2=-6%2A-6=36.)



x+=+%286+%2B-+sqrt%28+36%2B12+%29%29%2F%282%2A1%29 Multiply -4%2A-3%2A1 to get 12



x+=+%286+%2B-+sqrt%28+48+%29%29%2F%282%2A1%29 Combine like terms in the radicand (everything under the square root)



x+=+%286+%2B-+4%2Asqrt%283%29%29%2F%282%2A1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



x+=+%286+%2B-+4%2Asqrt%283%29%29%2F2 Multiply 2 and 1 to get 2

So now the expression breaks down into two parts

x+=+%286+%2B+4%2Asqrt%283%29%29%2F2 or x+=+%286+-+4%2Asqrt%283%29%29%2F2


Now break up the fraction


x=%2B6%2F2%2B4%2Asqrt%283%29%2F2 or x=%2B6%2F2-4%2Asqrt%283%29%2F2


Simplify


x=3%2B2%2Asqrt%283%29 or x=3-2%2Asqrt%283%29


So these expressions approximate to

x=6.46410161513775 or x=-0.464101615137754


So our solutions are:
x=6.46410161513775 or x=-0.464101615137754

Notice when we graph x%5E2-6%2Ax-3, we get:



when we use the root finder feature on a calculator, we find that x=6.46410161513775 and x=-0.464101615137754.So this verifies our answer