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Can you please explain how you got the answer because I have a quiz tomorrow and I am still very confused! 1 solutions
Answer 418719 by jim_thompson5910(28595) on 2012-10-29 22:09:43 (Show Source):
You can put this solution on YOUR website!This is an equilateral triangle, so ALL 3 SIDES ARE EQUAL (sorry if that sounds like I'm shouting, I'm just emphasizing the point)
This means that
3x+1 = 2x+5
Solve that for x. Then plug this value of x back into either 3x+1 or 2x+5 to find the side length of the triangle.
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Expressions-with-variables/673374: 2 +7b - 44= -3b +12+ 9b 1 solutions
Answer 418627 by jim_thompson5910(28595) on 2012-10-29 16:11:40 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
----------------------------------------------------------------------
Answer:
So the solution is
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Functions/673311: I am very confused about this question:
Let h(x) = 2x + 7. Find the value of h(x) + 14.
I have done many other questions like this but they have been with only one value. Could you please show the steps to this problem?
Thanks in advance! :) 1 solutions
Answer 418585 by jim_thompson5910(28595) on 2012-10-29 13:59:50 (Show Source):
You can put this solution on YOUR website!h(x) + 14
(2x+7) + 14 ... Replace 'h(x)' with '2x+7' (since h(x) = 2x+7)
2x + 7 + 14
2x + (7 + 14)
2x + 21
So h(x) + 14 = 2x + 21
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Problems-with-consecutive-odd-even-integers/672884: Prove that for every positive integer n, n3 + n is even 1 solutions
Answer 418378 by jim_thompson5910(28595) on 2012-10-28 14:12:42 (Show Source):
You can put this solution on YOUR website!Case 1: n is an even integer
Let n be an even integer.
So n = 2k for some integer k.
So if n = 2k, then n^3 = (2k)^3 = 8k^3
and
n^3 + n
becomes
8k^3 + 2k
which partially factors to
2(4k^3 + k)
which is in the form
2q
where q = 4k^3 + k (which can be proven that it is also an integer).
Since 2q is even for any integer q, this proves that if n is an even integer, then n^3+n is even.
-------------------------------------------------------------------------
Case 2: n is an odd integer
Let n be an odd integer.
So n = 2k+1 for some integer k.
So if n = 2k+1, then n^3 = (2k+1)^3 = 8k^3 + 12k^2 + 6k + 1
So
n^3 + n
becomes
(8k^3 + 12k^2 + 6k + 1) + (2k + 1)
8k^3 + 12k^2 + 6k + 1 + 2k + 1
8k^3 + 12k^2 + 8k + 2
which partially factors to
2(4k^3+6k^2+4k+1)
which is in the form
2q
where q = 4k^3+6k^2+4k+1 (which can be proven that it is also an integer).
Since 2q is even for any integer q, this proves that if n is an odd integer, then n^3+n is even.
===========================================================================================================
We've exhausted all possibilities and scenarios because any integer is either even or odd (cannot be something else or both).
So these two cases prove that n^3 + n is an even integer for every integer n.
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Polynomials-and-rational-expressions/672866: 8a^2+14a-49 1 solutions
Answer 418360 by jim_thompson5910(28595) on 2012-10-28 13:27:42 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,4,7,8,14,28,49,56,98,196,392
-1,-2,-4,-7,-8,-14,-28,-49,-56,-98,-196,-392
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-392) = -392
2*(-196) = -392
4*(-98) = -392
7*(-56) = -392
8*(-49) = -392
14*(-28) = -392
(-1)*(392) = -392
(-2)*(196) = -392
(-4)*(98) = -392
(-7)*(56) = -392
(-8)*(49) = -392
(-14)*(28) = -392
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -392 | 1+(-392)=-391 | | 2 | -196 | 2+(-196)=-194 | | 4 | -98 | 4+(-98)=-94 | | 7 | -56 | 7+(-56)=-49 | | 8 | -49 | 8+(-49)=-41 | | 14 | -28 | 14+(-28)=-14 | | -1 | 392 | -1+392=391 | | -2 | 196 | -2+196=194 | | -4 | 98 | -4+98=94 | | -7 | 56 | -7+56=49 | | -8 | 49 | -8+49=41 | | -14 | 28 | -14+28=14 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Word_Problems_With_Coins/672875: how many ways can 1.00 dollar be made using 19 coins? i am not aloud to use 50 cent pieces. 1 solutions
Answer 418359 by jim_thompson5910(28595) on 2012-10-28 13:26:40 (Show Source):
You can put this solution on YOUR website!There are 7 ways to do this (where you use exactly 19 coins to get $1.00):
=================================================================================================
18 nickels + 1 dime = $1.00
-----------------------------------------
5 pennies + 9 nickels + 5 dimes = $1.00
-----------------------------------------
5 pennies + 12 nickels + 1 dime + 1 quarter = $1.00
-----------------------------------------
10 pennies + 9 dimes = $1.00
-----------------------------------------
10 pennies + 3 nickels + 5 dimes + 1 quarter = $1.00
-----------------------------------------
10 pennies + 6 nickels + 1 dime + 2 quarters = $1.00
-----------------------------------------
15 pennies + 1 dime + 3 quarters = $1.00
=================================================================================================
Again, there are 7 ways to do this
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Linear-systems/672870: -1x + 2 = -4/5x + 8/5 1 solutions
Answer 418354 by jim_thompson5910(28595) on 2012-10-28 13:15:03 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Multiply both sides by the LCD  to clear any fractions.
 Distribute and multiply.
 Subtract  from both sides.
 Add  to both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
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Polynomials-and-rational-expressions/672867: 9y^2+17y-2 1 solutions
Answer 418353 by jim_thompson5910(28595) on 2012-10-28 13:14:28 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,6,9,18
-1,-2,-3,-6,-9,-18
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-18) = -18
2*(-9) = -18
3*(-6) = -18
(-1)*(18) = -18
(-2)*(9) = -18
(-3)*(6) = -18
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -18 | 1+(-18)=-17 | | 2 | -9 | 2+(-9)=-7 | | 3 | -6 | 3+(-6)=-3 | | -1 | 18 | -1+18=17 | | -2 | 9 | -2+9=7 | | -3 | 6 | -3+6=3 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
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Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Numeric_Fractions/672673: i need to put this problem into 2 equal parts
5 7/8 into two equal pieces 1 solutions
Answer 418273 by jim_thompson5910(28595) on 2012-10-27 22:06:26 (Show Source):
You can put this solution on YOUR website!5 7/8 = 5+7/8
5 7/8 = 5(8/8)+7/8
5 7/8 = 40/8+7/8
5 7/8 = 47/8
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Now cut 47/8 in half by multiplying it by 1/2
47/8 * 1/2 = (47*1)/8*2) = 47/16
Then convert back to a mixed number
47/16 = 2 remainder 15
47/16 = 2 + 15/16
47/16 = 2 15/16
So 5 7/8 cut in half is 2 15/16
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Expressions-with-variables/672662: 4a+5b-6c=2
-3a-2b+7c=-15
-a+4b+2c=-13
I know the answer is (-3, -2 -4) but can't figure out how to get it 1 solutions
Answer 418268 by jim_thompson5910(28595) on 2012-10-27 21:50:23 (Show Source):
You can put this solution on YOUR website!There are many ways to do this, but here is one of them.
Convert
4a+5b-6c=2
-3a-2b+7c=-15
-a+4b+2c=-13
to matrix form to get
4 5 -6 2
-3 -2 7 -15
-1 4 2 -13
Then use row reduction
4 5 -6 2
-3 -2 7 -15
-1 4 2 -13
1 1.25 -1.5 0.5 0.25*R1
-3 -2 7 -15
-1 4 2 -13
1 1.25 -1.5 0.5
0 1.75 2.5 -13.5 R2 + (3)*R1
-1 4 2 -13
1 1.25 -1.5 0.5
0 1.75 2.5 -13.5
0 5.25 0.5 -12.5 R3 + (1)*R1
1 1.25 -1.5 0.5
0 1 1.4286 -7.7143 0.571429*R2
0 5.25 0.5 -12.5
1 0 -3.2857 10.1429 R1 + (-1.25)*R2
0 1 1.4286 -7.7143
0 5.25 0.5 -12.5
1 0 -3.2857 10.1429
0 1 1.4286 -7.7143
0 0 -7 28 R3 + (-5.25)*R2
1 0 -3.2857 10.1429
0 1 1.4286 -7.7143
0 0 1 -4 -0.142857*R3
1 0 0 -3 R1 + (3.28571)*R3
0 1 1.4286 -7.7143
0 0 1 -4
1 0 0 -3
0 1 0 -2 R2 + (-1.42857)*R3
0 0 1 -4
The right hand column is -3, -2, -4
These 3 values correspond to a, b, and c respectively.
So the solutions are...
a = -3
b = -2
c = -4
They form the ordered triple (-3, -2, -4)
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Radicals/672638: Find the distance between (–4, 0) and (–5, –3). Express your answer in simplified radical form. 1 solutions
Answer 418228 by jim_thompson5910(28595) on 2012-10-27 17:18:41 (Show Source):
You can put this solution on YOUR website!d = sqrt((x2-x1)^2+(y2-y1)^2)
d = sqrt((-5-(-4))^2+( -3- 0)^2)
d = sqrt((-5+4)^2+( -3- 0)^2)
d = sqrt((-1)^2+(-3)^2)
d = sqrt(1+9)
d = sqrt(10)
So exact distance between the two points is sqrt(10) units.
Using a calculator, the approximate distance is roughly 3.16228 units.
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Quadratic_Equations/672615: A bicyclist is riding at a speed of 18mi/h when she starts down a long hill. The distance d she travels in feet can be modeled by d(t) = 4t^2 + 18t, where t is the time in seconds. How long will it take her to reach the bottom of a 400-foot-long hill?
We have to use the quadratic formula to find t.
I attempted the problem and i got 12.5 seconds.. but im not sure if im right
Heres my work:
d(t)=4t^2+18t=400
d(t)=4t^2+18t=400/4
t^2+4.5t=100
t^2+4.5t-100=0
(x-12.5)(x+8)
12.5 & -8 seconds.
is this correct?
Thanks(: 1 solutions
Answer 418216 by jim_thompson5910(28595) on 2012-10-27 15:51:24 (Show Source):
You can put this solution on YOUR website!You should have 8 or -12.5 seconds.
Because a negative amount of time doesn't make sense, you toss out the negative solution to get t = 8 seconds.
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