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27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499 , 28500..28529, >>NextGraphs/132771: sketching this graph of P(x)=X5(X+2)3 (X-3)4 (X-5)3
the numbers after the X and outside the parenthesis are the small numbers i.e x square but I have no idea how to do this little numbers on my computer 1 solutions
Answer 97015 by jim_thompson5910(28536) on 2008-03-19 12:42:17 (Show Source):
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Equations/132770: Please explain how you would solve this equation:
20b^2+33b-4=-14 1 solutions
Answer 97012 by jim_thompson5910(28536) on 2008-03-19 12:32:44 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Add 14 to both sides.
 Combine like terms
 Factor the left side (note: if you need help with factoring, check out this solver)
Now set each factor equal to zero:
 or
 or  Now solve for b in each case
So our solutions are
 or
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Equations/132769: Please explain how you would solve this equation:
150x^2+120x+24 1 solutions
Answer 97011 by jim_thompson5910(28536) on 2008-03-19 12:31:05 (Show Source):
You can put this solution on YOUR website!You cannot solve this since it is not an equation. But you can factor
 Start with the given expression
 Factor out the GCF
Now let's focus on the inner expression
------------------------------------------------------------
Looking at  we can see that the first term is  and the last term is  where the coefficients are 25 and 4 respectively.
Now multiply the first coefficient 25 and the last coefficient 4 to get 100. Now what two numbers multiply to 100 and add to the middle coefficient 20? Let's list all of the factors of 100:
Factors of 100:
1,2,4,5,10,20,25,50
-1,-2,-4,-5,-10,-20,-25,-50 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to 100
1*100
2*50
4*25
5*20
10*10
(-1)*(-100)
(-2)*(-50)
(-4)*(-25)
(-5)*(-20)
(-10)*(-10)
note: remember two negative numbers multiplied together make a positive number
Now which of these pairs add to 20? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 20
| First Number | Second Number | Sum | | 1 | 100 | 1+100=101 | | 2 | 50 | 2+50=52 | | 4 | 25 | 4+25=29 | | 5 | 20 | 5+20=25 | | 10 | 10 | 10+10=20 | | -1 | -100 | -1+(-100)=-101 | | -2 | -50 | -2+(-50)=-52 | | -4 | -25 | -4+(-25)=-29 | | -5 | -20 | -5+(-20)=-25 | | -10 | -10 | -10+(-10)=-20 |
From this list we can see that 10 and 10 add up to 20 and multiply to 100
Now looking at the expression  , replace  with  (notice  adds up to  . So it is equivalent to  )
Now let's factor  by grouping:
 Group like terms
 Factor out the GCF of  out of the first group. Factor out the GCF of  out of the second group
 Since we have a common term of  , we can combine like terms
So  factors to
So this also means that  factors to  (since  is equivalent to  )
note:  is equivalent to  since the term  occurs twice. So  also factors to
------------------------------------------------------------
So our expression goes from  and factors further to
------------------
Answer:
So  factors to
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Inverses/132658: Please help.
1.Solve these using the multiplication principle.
9x = 90
-x = 42
-x/4 = 11
-3/5x = 12/35
1 solutions
Answer 96941 by jim_thompson5910(28536) on 2008-03-18 18:15:50 (Show Source):
You can put this solution on YOUR website!I'll do the first two to get you started
# 1
 Start with the given equation
 Multiply both sides by  to isolate x. Note:  is the multiplicative inverse of 9
 Multiply
 Divide
--------------------------------------------------------------
Answer:
So our answer is
# 2
 Start with the given equation
 Multiply both sides by  to isolate x. Note:  is the multiplicative inverse of -1
 Multiply
 Divide
--------------------------------------------------------------
Answer:
So our answer is
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logarithm/132653: 
i know you have to first get the same bases but how? 1 solutions
Answer 96940 by jim_thompson5910(28536) on 2008-03-18 18:05:56 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Rewrite 8 as  . Notice how the two sides have the same base.
Since the bases are equal, this means that the exponents are equal.
 Set the exponents equal to one another
 Subtract 1 from both sides
 Combine like terms on the right side
--------------------------------------------------------------
Answer:
So our answer is
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Quadratic_Equations/132645: Two lines have slopes 2k-4 and k+6. What value(s) of k will produce perpendicular lines? I think the answer is k=-4+or- sqrt66/2???????? 1 solutions
Answer 96937 by jim_thompson5910(28536) on 2008-03-18 17:58:52 (Show Source):
You can put this solution on YOUR website!Their slopes will be perpendicular when their product is -1. So we have the equation
 Foil
 Add 1 to both sides
Let's use the quadratic formula to solve for k:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve  ( notice  ,  , and  )
 Plug in a=2, b=8, and c=-23
 Square 8 to get 64
 Multiply  to get
 Combine like terms in the radicand (everything under the square root)
 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
 Multiply 2 and 2 to get 4
So now the expression breaks down into two parts
 or
Now break up the fraction
 or
Simplify
 or
So these expressions approximate to
 or
So our solutions are:
 or
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Equations/132636: a/b=x-y/y-z
solve for y 1 solutions
Answer 96928 by jim_thompson5910(28536) on 2008-03-18 17:48:00 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Cross multiply
 Distribute
 Subtract ay from both sides
 Subtract bx from both sides
 Factor out the GCF "y" from the right side
 Divide both sides by
 Rearrange the equation
 Factor out -1 from the numerator
 Factor out -1 from the denominator
 Cancel out the "-1" terms
 Simplify
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logarithm/132628:  1 solutions
Answer 96924 by jim_thompson5910(28536) on 2008-03-18 17:38:36 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Combine the logs using the identity
}=10^{\log _{10} \left(5 \right)}) Raise both sides as exponents with bases of 10. This will undo the logs
 Simplify
 Multiply both sides by
 Distribute
 Subtract 5 from both sides
 Subtract 5x from both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by -4 to isolate x
 Reduce
--------------------------------------------------------------
Answer:
So our answer is  (which is approximately  in decimal form)
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Linear-equations/132609: find the midpoint between these two points
(1,-6) and (-5, -2) 1 solutions
Answer 96907 by jim_thompson5910(28536) on 2008-03-18 16:12:24 (Show Source):
You can put this solution on YOUR website!In order to find the midpoint between the points (1,6) and (-5,-2), we need to average each corresponding coordinate. In other words, we need to add up the corresponding coordinates and divide the sum by 2.
So lets find the averages between the two points
To find  , average the x-coordinates between the two points
So the x-coordinate of the midpoint is -2 (i.e. x=-2)
-----------------------------------------------------------------------------------------------------------------
To find  , average the y-coordinates between the two points
So the y-coordinate of the midpoint is 2 (i.e. y=2)
-----------------------------------------------------------------------------------------------------------------
Answer:
Since the coordinates of the midpoint are x=-2, y=2, this means the midpoint is (-2,2)
Check:
Here is a graph to visually see the answer
 Graph of the line segment with the endpoints (1,6) and (-5,-2) with the midpoint (-2,2)
We could visually verify our answer if we simply draw right triangles from each point like this:
Here we can see that the two triangles are congruent (they both have a right angle and equal leg lengths), so our answer is verified.
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Inequalities/132605: 3x-15<9+7x 1 solutions
Answer 96903 by jim_thompson5910(28536) on 2008-03-18 16:03:54 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality
 Add 15 to both sides
 Subtract 7x from both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by -4 to isolate x (note: Remember, dividing both sides by a negative number flips the inequality sign)
 Divide
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Answer:
So our answer is
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Rational-functions/132602: This question is from textbook Algebra II
I am trying to solve this problem however I do not even know how to begin to work it out. How do I solve this problem? 1 solutions
Answer 96902 by jim_thompson5910(28536) on 2008-03-18 16:02:58 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Factor  to get
Notice how the LCD is
 Multiply both sides by the LCD  . Doing this will eliminate every fraction.
 Distribute and multiply. Notice every denominator has been canceled out.
 Distribute again
 Combine like terms
 Subtract  from both sides.
 Rearrange the terms
 Factor the left side (note: if you need help with factoring, check out this solver)
Now set each factor equal to zero:
 or
 or  Now solve for x in each case
Since we have a repeating answer, our only answer is
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Answer:
So the solution is
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Linear-equations/132601: This question is from textbook Intermediate Algebra
Solve for x. Collect xs on the left side. The solution shold be presented with x firstm the correct ienequality symbol, and the the number.
-7x+2+x-10=-3(x-1)
1 solutions
Answer 96901 by jim_thompson5910(28536) on 2008-03-18 15:55:40 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
 Distribute
 Combine like terms on the left side
 Add 8 to both sides
 Add 3x to both sides
 Combine like terms on the left side
 Combine like terms on the right side
 Divide both sides by -3 to isolate x
 Reduce
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Answer:
So our answer is  (which is approximately  in decimal form)
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Inequalities/132563: Solve for the inequality. -2/11<-4/11x
Optional answers - (11, infinity) (1/2,infinity) (-infinity, 1/2) (1/2, infinity) (-infinity, 2)
Thank-you 1 solutions
Answer 96880 by jim_thompson5910(28536) on 2008-03-18 12:23:18 (Show Source):
You can put this solution on YOUR website! Start with the given inequality
 Multiply both sides by 11.
 Multiply and simplify
 Divide both sides by -4 to isolate x (note: Remember, dividing both sides by a negative number flips the inequality sign)
 Reduce
 Rearrange the inequality
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Answer:
So our answer is  (which is approximately  in decimal form)
So the answer in interval notation is
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Square-cubic-other-roots/132520: Can you please help me this problem!
The directions are the solve it using the square root method:
x^2=16
I don't know!
Please help! =] 1 solutions
Answer 96865 by jim_thompson5910(28536) on 2008-03-18 00:19:50 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Take the square root of both sides
 Take the square root of 16 to get 4
Break the solution into two parts
or
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Answer:
So our solution is
or
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Equations/132506: x+x+x+2+1=11 1 solutions
Answer 96846 by jim_thompson5910(28536) on 2008-03-17 20:44:23 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Combine like terms on the left side
 Subtract 3 from both sides
 Combine like terms on the right side
 Divide both sides by 3 to isolate x
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Answer:
So our answer is  (which is approximately  in decimal form)
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