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Graphs/132771: sketching this graph of P(x)=X5(X+2)3 (X-3)4 (X-5)3
the numbers after the X and outside the parenthesis are the small numbers i.e x square but I have no idea how to do this little numbers on my computer
1 solutions

Answer 97015 by jim_thompson5910(28536) About Me  on 2008-03-19 12:42:17 (Show Source):
You can put this solution on YOUR website!
Doe your equation look like this: x%5E5%28x%2B2%29%5E3%28x-3%29%5E4%28x-5%29%5E3


If it does, then the graph looks like this:



Equations/132770: Please explain how you would solve this equation:
20b^2+33b-4=-14
1 solutions

Answer 97012 by jim_thompson5910(28536) About Me  on 2008-03-19 12:32:44 (Show Source):
You can put this solution on YOUR website!
20b%5E2%2B33b-4=-14 Start with the given equation


20b%5E2%2B33b-4%2B14=0 Add 14 to both sides.


20b%5E2%2B33b%2B10=0 Combine like terms


%284b%2B5%29%285b%2B2%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:
4b%2B5=0 or 5b%2B2=0

b=-5%2F4 or b=-2%2F5 Now solve for b in each case


So our solutions are

b=-5%2F4 or b=-2%2F5


Equations/132769: Please explain how you would solve this equation:
150x^2+120x+24
1 solutions

Answer 97011 by jim_thompson5910(28536) About Me  on 2008-03-19 12:31:05 (Show Source):
You can put this solution on YOUR website!
You cannot solve this since it is not an equation. But you can factor



150x%5E2%2B120x%2B24 Start with the given expression


6%2825x%5E2%2B20x%2B4%29 Factor out the GCF 6


Now let's focus on the inner expression 25x%5E2%2B20x%2B4




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Looking at 25x%5E2%2B20x%2B4 we can see that the first term is 25x%5E2 and the last term is 4 where the coefficients are 25 and 4 respectively.

Now multiply the first coefficient 25 and the last coefficient 4 to get 100. Now what two numbers multiply to 100 and add to the middle coefficient 20? Let's list all of the factors of 100:



Factors of 100:
1,2,4,5,10,20,25,50

-1,-2,-4,-5,-10,-20,-25,-50 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 100
1*100
2*50
4*25
5*20
10*10
(-1)*(-100)
(-2)*(-50)
(-4)*(-25)
(-5)*(-20)
(-10)*(-10)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 20? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 20

First NumberSecond NumberSum
11001+100=101
2502+50=52
4254+25=29
5205+20=25
101010+10=20
-1-100-1+(-100)=-101
-2-50-2+(-50)=-52
-4-25-4+(-25)=-29
-5-20-5+(-20)=-25
-10-10-10+(-10)=-20



From this list we can see that 10 and 10 add up to 20 and multiply to 100


Now looking at the expression 25x%5E2%2B20x%2B4, replace 20x with 10x%2B10x (notice 10x%2B10x adds up to 20x. So it is equivalent to 20x)

25x%5E2%2Bhighlight%2810x%2B10x%29%2B4


Now let's factor 25x%5E2%2B10x%2B10x%2B4 by grouping:


%2825x%5E2%2B10x%29%2B%2810x%2B4%29 Group like terms


5x%285x%2B2%29%2B2%285x%2B2%29 Factor out the GCF of 5x out of the first group. Factor out the GCF of 2 out of the second group


%285x%2B2%29%285x%2B2%29 Since we have a common term of 5x%2B2, we can combine like terms

So 25x%5E2%2B10x%2B10x%2B4 factors to %285x%2B2%29%285x%2B2%29


So this also means that 25x%5E2%2B20x%2B4 factors to %285x%2B2%29%285x%2B2%29 (since 25x%5E2%2B20x%2B4 is equivalent to 25x%5E2%2B10x%2B10x%2B4)


note: %285x%2B2%29%285x%2B2%29 is equivalent to %285x%2B2%29%5E2 since the term 5x%2B2 occurs twice. So 25x%5E2%2B20x%2B4 also factors to %285x%2B2%29%5E2



------------------------------------------------------------




So our expression goes from 6%2825x%5E2%2B20x%2B4%29 and factors further to 6%285x%2B2%29%5E2


------------------
Answer:

So 150x%5E2%2B120x%2B24 factors to 6%285x%2B2%29%5E2


Square-cubic-other-roots/132680: Rationalize the denominator:
2____
√[3] + √[2]

1 solutions

Answer 96998 by jim_thompson5910(28536) About Me  on 2008-03-18 23:13:56 (Show Source):
You can put this solution on YOUR website!
%282%29%2F%28sqrt%282%29%2Bsqrt%283%29%29 Start with the given expression


Multiply by the fraction by %28sqrt%282%29-sqrt%283%29%29%2F%28sqrt%282%29-sqrt%283%29%29. Note sqrt%282%29-sqrt%283%29 is the conjugate of sqrt%282%29%2Bsqrt%283%29.


Combine the fractions


Foil the denominator


Cancel like terms


%28%282%29%28sqrt%282%29-sqrt%283%29%29%29%2F%282-3%29 Multiply


%28%282%29%28sqrt%282%29-sqrt%283%29%29%29%2F%28-1%29 Combine like terms


-2%28sqrt%282%29-sqrt%283%29%29 Divide and simplify


-2sqrt%282%29%2B2sqrt%283%29 Distribute


So %282%29%2F%28sqrt%282%29%2Bsqrt%283%29%29 simplifies to -2sqrt%282%29%2B2sqrt%283%29



In other words, %282%29%2F%28sqrt%282%29%2Bsqrt%283%29%29=-2sqrt%282%29%2B2sqrt%283%29


Square-cubic-other-roots/132660: i have to simplify this
1/8(3x+1)^(3/2) + 1/4(3x+1)^(1/2)
^ means to the power of if you didnt know
1 solutions

Answer 96945 by jim_thompson5910(28536) About Me  on 2008-03-18 18:36:00 (Show Source):
You can put this solution on YOUR website!
%281%2F8%29%283x%2B1%29%5E%283%2F2%29+%2B+%281%2F4%29%283x%2B1%29%5E%281%2F2%29+ Start with the given expression


%281%2F8%29%283x%2B1%29%5E%283%2A%281%2F2%29%29+%2B+%281%2F4%29%283x%2B1%29%5E%281%2F2%29+ Rewrite 3%2F2 as 3%2A%281%2F2%29


%281%2F8%29%28%283x%2B1%29%5E%281%2F2%29%29%5E3+%2B+%281%2F4%29%283x%2B1%29%5E%281%2F2%29+ Rewrite the first expression using the identity x%5E%28y%2Az%29=%28x%5Ey%29%5Ez


%281%2F8%29%28sqrt%283x%2B1%29%29%5E3+%2B+%281%2F4%29sqrt%283x%2B1%29+ Now rewrite %283x%2B1%29%5E%281%2F2%29 as sqrt%283x%2B1%29



Let u=sqrt%283x%2B1%29


%281%2F8%29u%5E3+%2B+%281%2F4%29u+ Plug in u=%283x%2B1%29%5E%281%2F2%29


%281%2F4%29u%28%281%2F2%29u%5E2+%2B+1%29+ Factor out the GCF %281%2F4%29u


%281%2F4%29%28sqrt%283x%2B1%29%29%28%281%2F2%29%28sqrt%283x%2B1%29%29%5E2+%2B+1%29+ Now substitute sqrt%283x%2B1%29 back in for u


%281%2F4%29%28sqrt%283x%2B1%29%29%28%281%2F2%29%283x%2B1%29+%2B+1%29+ Square sqrt%283x%2B1%29 to get 3x%2B1


%281%2F4%29%28sqrt%283x%2B1%29%29%28%281%2F2%293x%2B1%2F2+%2B+1%29+ Distribute


%281%2F4%29%28sqrt%283x%2B1%29%29%28%281%2F2%293x%2B3%2F2%29+ Combine like terms


sqrt%283x%2B1%29%281%2F4%29%28%281%2F2%293x%2B3%2F2%29+ Rearrange the terms


sqrt%283x%2B1%29%28%281%2F8%293x%2B3%2F8%29+ Distribute


%28%281%2F8%293x%2B3%2F8%29sqrt%283x%2B1%29+ Rearrange the terms



Inverses/132658: Please help.
1.Solve these using the multiplication principle.
9x = 90
-x = 42
-x/4 = 11
-3/5x = 12/35

1 solutions

Answer 96941 by jim_thompson5910(28536) About Me  on 2008-03-18 18:15:50 (Show Source):
You can put this solution on YOUR website!
I'll do the first two to get you started

# 1


9x=90 Start with the given equation



%281%2Fcross%289%29%29cross%289%29x=%281%2F%289%29%2990 Multiply both sides by 1%2F9 to isolate x. Note: 1%2F9 is the multiplicative inverse of 9



x=90%2F9 Multiply


x=10 Divide

--------------------------------------------------------------
Answer:
So our answer is x=10







# 2



-x=42 Start with the given equation



%28-1%2Fcross%281%29%29cross%28-1%29x=%28-1%2F%281%29%2942 Multiply both sides by -1%2F1 to isolate x. Note: -1%2F1 is the multiplicative inverse of -1



x=%28-42%29%2F1 Multiply


x=-42 Divide

--------------------------------------------------------------
Answer:
So our answer is x=-42


logarithm/132653: 2%5E%28x%2B1%29=1%2F8
i know you have to first get the same bases but how?
1 solutions

Answer 96940 by jim_thompson5910(28536) About Me  on 2008-03-18 18:05:56 (Show Source):
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2%5E%28x%2B1%29=1%2F8 Start with the given equation


2%5E%28x%2B1%29=2%5E%28-3%29 Rewrite 8 as 2%5E%28-3%29. Notice how the two sides have the same base.


Since the bases are equal, this means that the exponents are equal.



x%2B1=-3 Set the exponents equal to one another



x=-3-1 Subtract 1 from both sides


x=-4 Combine like terms on the right side

--------------------------------------------------------------
Answer:
So our answer is x=-4


Equations/132650: Solve using principles together.
2x-16=-2
1 solutions

Answer 96939 by jim_thompson5910(28536) About Me  on 2008-03-18 18:02:49 (Show Source):
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2x-16=-2 Start with the given equation



2x=-2%2B16Add 16 to both sides


2x=14 Combine like terms on the right side


x=%2814%29%2F%282%29 Divide both sides by 2 to isolate x



x=7 Divide

--------------------------------------------------------------
Answer:
So our answer is x=7




Quadratic_Equations/132651: Given f(x)=3^x, which statement is true?
a) f(x+y)=f(x)+(y)
b) f(x+y)=f(x)f(y)
c) f(xy)=f(x)+f(y)
d) f(x/y)=f(x-y)
1 solutions

Answer 96938 by jim_thompson5910(28536) About Me  on 2008-03-18 18:02:09 (Show Source):
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Remember if you have something like a%5E%28x%2By%29 it decomposes to a%5Ex%2Ax%5Ey. So this shows us that b) is the solution since 3%5E%28x%2By%29=3%5Ex%2A3%5Ey

So the statement b) f(x+y)=f(x)f(y) is a true statement


Quadratic_Equations/132645: Two lines have slopes 2k-4 and k+6. What value(s) of k will produce perpendicular lines? I think the answer is k=-4+or- sqrt66/2????????
1 solutions

Answer 96937 by jim_thompson5910(28536) About Me  on 2008-03-18 17:58:52 (Show Source):
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Their slopes will be perpendicular when their product is -1. So we have the equation

%282k-4%29%2A%28k%2B6%29=-1


2k%5E2%2B8k-24=-1 Foil


2k%5E2%2B8k-23=0 Add 1 to both sides

Let's use the quadratic formula to solve for k:


Starting with the general quadratic

ak%5E2%2Bbk%2Bc=0

the general solution using the quadratic equation is:

k+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29



So lets solve 2%2Ak%5E2%2B8%2Ak-23=0 ( notice a=2, b=8, and c=-23)




k+=+%28-8+%2B-+sqrt%28+%288%29%5E2-4%2A2%2A-23+%29%29%2F%282%2A2%29 Plug in a=2, b=8, and c=-23



k+=+%28-8+%2B-+sqrt%28+64-4%2A2%2A-23+%29%29%2F%282%2A2%29 Square 8 to get 64



k+=+%28-8+%2B-+sqrt%28+64%2B184+%29%29%2F%282%2A2%29 Multiply -4%2A-23%2A2 to get 184



k+=+%28-8+%2B-+sqrt%28+248+%29%29%2F%282%2A2%29 Combine like terms in the radicand (everything under the square root)



k+=+%28-8+%2B-+2%2Asqrt%2862%29%29%2F%282%2A2%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



k+=+%28-8+%2B-+2%2Asqrt%2862%29%29%2F4 Multiply 2 and 2 to get 4

So now the expression breaks down into two parts

k+=+%28-8+%2B+2%2Asqrt%2862%29%29%2F4 or k+=+%28-8+-+2%2Asqrt%2862%29%29%2F4


Now break up the fraction


k=-8%2F4%2B2%2Asqrt%2862%29%2F4 or k=-8%2F4-2%2Asqrt%2862%29%2F4


Simplify


k=-2%2Bsqrt%2862%29%2F2 or k=-2-sqrt%2862%29%2F2


So these expressions approximate to

k=1.93700393700591 or k=-5.93700393700591


So our solutions are:
k=1.93700393700591 or k=-5.93700393700591


Quadratic_Equations/132648: Collect like terms.
17y-y=

1 solutions

Answer 96935 by jim_thompson5910(28536) About Me  on 2008-03-18 17:52:13 (Show Source):
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17y-y Start with the given expression


%2817y-y%29 Group like terms


16y Combine like terms


Equations/132644: x/5=5 Is the answer 28?
1 solutions

Answer 96934 by jim_thompson5910(28536) About Me  on 2008-03-18 17:51:48 (Show Source):
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x%2F5=5 Start with the given equation



cross%285%29%28x%2Fcross%285%29%29=%285%29%285%29 Multiply both sides by 5.


x=25 Multiply


--------------------------------------------------------------
Answer:
So our answer is x=25



Equations/132647: b=5+a, for a
Can someone help me please??
1 solutions

Answer 96931 by jim_thompson5910(28536) About Me  on 2008-03-18 17:50:12 (Show Source):
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b=5%2Ba Start with the given equation


b-5=a Subtract 5 from both sides


a=b-5 Rearrange the equation


Quadratic_Equations/132637: 9x-8=5x
Can someone help me with this.
1 solutions

Answer 96930 by jim_thompson5910(28536) About Me  on 2008-03-18 17:49:02 (Show Source):
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9x-8=5x Start with the given equation



9x=5x%2B8Add 8 to both sides


9x-5x=%2B8 Subtract 5x from both sides


4x=8 Combine like terms on the left side


x=%288%29%2F%284%29 Divide both sides by 4 to isolate x



x=2 Divide

--------------------------------------------------------------
Answer:
So our answer is x=2


Equations/132636: a/b=x-y/y-z
solve for y
1 solutions

Answer 96928 by jim_thompson5910(28536) About Me  on 2008-03-18 17:48:00 (Show Source):
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a%2Fb=%28x-y%29%2F%28y-z%29 Start with the given equation


a%28y-z%29=b%28x-y%29 Cross multiply


ay-az=bx-by Distribute


-az=bx-by-ay Subtract ay from both sides


-az-bx=-by-ay Subtract bx from both sides


-az-bx=y%28-b-a%29 Factor out the GCF "y" from the right side

%28-az-bx%29%2F%28-b-a%29=y Divide both sides by -b-a


y=%28-az-bx%29%2F%28-b-a%29 Rearrange the equation


y=%28-1%28az%2Bbx%29%29%2F%28-b-a%29 Factor out -1 from the numerator


y=%28-1%28az%2Bbx%29%29%2F%28-1%28b%2Ba%29%29 Factor out -1 from the denominator


y=cross%28-1%29%28az%2Bbx%29%2Fcross%28-1%29%28b%2Ba%29 Cancel out the "-1" terms


y=%28az%2Bbx%29%2F%28b%2Ba%29 Simplify


logarithm/132628: log%28x%2B5%29-log%28x%2B2%29=log5
1 solutions

Answer 96924 by jim_thompson5910(28536) About Me  on 2008-03-18 17:38:36 (Show Source):
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log%2810%2C%28x%2B5%29%29-log%2810%2C%28x%2B2%29%29=log%2810%2C%285%29%29 Start with the given equation



log%2810%2C%28%28x%2B5%29%2F%28x%2B2%29%29=log%2810%2C%285%29%29%29 Combine the logs using the identity log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29



Raise both sides as exponents with bases of 10. This will undo the logs


%28x%2B5%29%2F%28x%2B2%29=5 Simplify


x%2B5=5%28x%2B2%29 Multiply both sides by x%2B2


x%2B5=5x%2B10 Distribute


x=5x%2B10-5Subtract 5 from both sides


x-5x=10-5 Subtract 5x from both sides


-4x=10-5 Combine like terms on the left side


-4x=5 Combine like terms on the right side


x=%285%29%2F%28-4%29 Divide both sides by -4 to isolate x



x=-5%2F4 Reduce

--------------------------------------------------------------
Answer:
So our answer is x=-5%2F4 (which is approximately x=-1.25 in decimal form)


Quadratic_Equations/132626: simplify
-40xz/250xz
HELP!
1 solutions

Answer 96922 by jim_thompson5910(28536) About Me  on 2008-03-18 17:30:33 (Show Source):
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-40xz%2F250xz Start with the given expression


-40cross%28x%29cross%28z%29%2F250cross%28x%29cross%28z%29 Cancel like terms


-40%2F250 Simplify


-4%2F25 Reduce



So -40xz%2F250xz simplifies to -4%2F25


In other words, -40xz%2F250xz=-4%2F25 where x%3C%3E0 and z%3C%3E0


Quadratic_Equations/132624: Translate to an algebriac expression.
1 more than d
Can someone please help me with this?
1 solutions

Answer 96921 by jim_thompson5910(28536) About Me  on 2008-03-18 17:27:18 (Show Source):
You can put this solution on YOUR website!
Algebraically, "more" means that you're adding some amount.

So,

1 more than d = d + 1


Quadratic_Equations/132622: Translate to an algebriac expression.
Twice d
1 solutions

Answer 96920 by jim_thompson5910(28536) About Me  on 2008-03-18 17:25:25 (Show Source):
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Twice d = 2 times d = 2*d


Miscellaneous_Word_Problems/132611: This question is from textbook Algebra Structure and Method
I have been struggling with this math problem for awhile now and I was wondering if anyone could help? I would deeply appreciate it!! Please and Thank You!!
Transforming Formulas
solve. C=K(Rr over R-r);R
1 solutions

Answer 96913 by jim_thompson5910(28536) About Me  on 2008-03-18 16:38:05 (Show Source):
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C=K%28Rr%2F%28R-r%29%29 Start with the given equation


C=KRr%2F%28R-r%29 Multiply


C%28R-r%29=KRr Multiply both sides by R-r


CR-Cr=KRr Distribute


-Cr=KRr-CR Subtract CR from both sides


-Cr=R%28Kr-C%29 Factor out the GCF "R" from the right side


-Cr%2F%28Kr-C%29=R Divide both sides by Kr-C


R=-Cr%2F%28Kr-C%29 Rearrange the equation


Miscellaneous_Word_Problems/132608: This question is from textbook Algebra Structure and Method
I did this math problem and I don't know if I did it right so I was wondering if I could have help and check my answers with one of the tutors? I would deeply appreciate it!! Please and Thank You!!

Transforming Formulas
Solve.
s=a over a-r;r
1 solutions

Answer 96908 by jim_thompson5910(28536) About Me  on 2008-03-18 16:17:41 (Show Source):
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s=a%2F%28a-r%29 Start with the given equation


s%28a-r%29=a Multiply both sides by a-r


sa-sr=a Distribute


sa=a%2Bsr Add sr to both sides


sa-a=sr Subtract "a" from both sides


%28sa-s%29%2Fs=r Divide both sides by s to isolate r


r=%28sa-s%29%2Fs Rearrange the equation


Linear-equations/132609: find the midpoint between these two points
(1,-6) and (-5, -2)
1 solutions

Answer 96907 by jim_thompson5910(28536) About Me  on 2008-03-18 16:12:24 (Show Source):
You can put this solution on YOUR website!
In order to find the midpoint between the points (1,6) and (-5,-2), we need to average each corresponding coordinate. In other words, we need to add up the corresponding coordinates and divide the sum by 2.


So lets find the averages between the two points



To find , average the x-coordinates between the two points
x%5Bmid%5D=%281%2B-5%29%2F2=%28-4%29%2F2=-2


So the x-coordinate of the midpoint is -2 (i.e. x=-2)
-----------------------------------------------------------------------------------------------------------------


To find , average the y-coordinates between the two points
y%5Bmid%5D=%286%2B-2%29%2F2=%284%29%2F2=2


So the y-coordinate of the midpoint is 2 (i.e. y=2)
-----------------------------------------------------------------------------------------------------------------
Answer:
Since the coordinates of the midpoint are x=-2, y=2, this means the midpoint is (-2,2)

Check:
Here is a graph to visually see the answer
Graph of the line segment with the endpoints (1,6) and (-5,-2) with the midpoint (-2,2)



We could visually verify our answer if we simply draw right triangles from each point like this:


Here we can see that the two triangles are congruent (they both have a right angle and equal leg lengths), so our answer is verified.


Miscellaneous_Word_Problems/132607: This question is from textbook Algebra Structure and Method
I have been struggling on this problem for awhile now and I was wondering if anyone could help me? I would deeply appreciate it!! Please and Thank You!!

Transforming Formulas
a=180(n-2) over n;n
1 solutions

Answer 96905 by jim_thompson5910(28536) About Me  on 2008-03-18 16:10:46 (Show Source):
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Do you want to solve for n?


a=180%28n-2%29%2Fn Start with the given equation


an=180%28n-2%29 Multiply both sides by n


an%2F180=n-2 Divide both sides by 180


an%2F180%2B2=n Add 2 to both sides



So our answer is n=an%2F180%2B2


Inequalities/132605: 3x-15<9+7x
1 solutions

Answer 96903 by jim_thompson5910(28536) About Me  on 2008-03-18 16:03:54 (Show Source):
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3x-15%3C9%2B7x Start with the given inequality



3x%3C9%2B7x%2B15Add 15 to both sides


3x-7x%3C9%2B15 Subtract 7x from both sides


-4x%3C9%2B15 Combine like terms on the left side


-4x%3C24 Combine like terms on the right side


x%3E%2824%29%2F%28-4%29 Divide both sides by -4 to isolate x (note: Remember, dividing both sides by a negative number flips the inequality sign)



x%3E-6 Divide

--------------------------------------------------------------
Answer:
So our answer is x%3E-6



Rational-functions/132602: This question is from textbook Algebra II
+3%2F%28x-2%29+%2B+5%2F%28x%2B2%29+=+4x%5E2%2F%28x%5E2-4%29+
I am trying to solve this problem however I do not even know how to begin to work it out. How do I solve this problem?
1 solutions

Answer 96902 by jim_thompson5910(28536) About Me  on 2008-03-18 16:02:58 (Show Source):
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+3%2F%28x-2%29+%2B+5%2F%28x%2B2%29+=+4x%5E2%2F%28x%5E2-4%29+ Start with the given equation


+3%2F%28x-2%29+%2B+5%2F%28x%2B2%29+=+4x%5E2%2F%28%28x-2%29%28x%2B2%29%29+ Factor x%5E2-4 to get %28x-2%29%28x%2B2%29


Notice how the LCD is %28x-2%29%28x%2B2%29



Multiply both sides by the LCD %28x-2%29%28x%2B2%29. Doing this will eliminate every fraction.


3%28x%2B2%29%2B5%28x-2%29=4x%5E2 Distribute and multiply. Notice every denominator has been canceled out.


3x%2B6%2B5x-10=4x%5E2 Distribute again


8x-4=4x%5E2 Combine like terms


8x-4-4x%5E2=0 Subtract 4x%5E2 from both sides.


-4x%5E2%2B8x-4=0 Rearrange the terms


-4%28x-1%29%28x-1%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:
x-1=0 or x-1=0

x=1 or x=1 Now solve for x in each case


Since we have a repeating answer, our only answer is x=1


---------------------------------------------------------------------

Answer:

So the solution is x=1


Linear-equations/132601: This question is from textbook Intermediate Algebra
Solve for x. Collect xs on the left side. The solution shold be presented with x firstm the correct ienequality symbol, and the the number.
-7x+2+x-10=-3(x-1)

1 solutions

Answer 96901 by jim_thompson5910(28536) About Me  on 2008-03-18 15:55:40 (Show Source):
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-7x%2B2%2Bx-10=-3%28x-1%29 Start with the given equation



-7x%2B2%2Bx-10=-3x%2B3 Distribute


-6x-8=-3x%2B3 Combine like terms on the left side


-6x=-3x%2B3%2B8Add 8 to both sides


-6x%2B3x=3%2B8 Add 3x to both sides


-3x=3%2B8 Combine like terms on the left side


-3x=11 Combine like terms on the right side


x=%2811%29%2F%28-3%29 Divide both sides by -3 to isolate x



x=-11%2F3 Reduce

--------------------------------------------------------------
Answer:
So our answer is x=-11%2F3 (which is approximately x=-3.667 in decimal form)


Inequalities/132563: Solve for the inequality. -2/11<-4/11x
Optional answers - (11, infinity) (1/2,infinity) (-infinity, 1/2) (1/2, infinity) (-infinity, 2)
Thank-you
1 solutions

Answer 96880 by jim_thompson5910(28536) About Me  on 2008-03-18 12:23:18 (Show Source):
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-2%2F11%3C-%284%2F11%29x Start with the given inequality



cross%2811%29%28-2%2Fcross%2811%29%29%3Ccross%2811%29%28-%284%2Fcross%2811%29%29x%29 Multiply both sides by 11.


-2%3C-4x Multiply and simplify


-2%2F-4%3Ex Divide both sides by -4 to isolate x (note: Remember, dividing both sides by a negative number flips the inequality sign)



1%2F2%3Ex Reduce



x%3C1%2F2 Rearrange the inequality


--------------------------------------------------------------
Answer:
So our answer is x%3C1%2F2 (which is approximately x%3C0.5 in decimal form)



So the answer in interval notation is


Square-cubic-other-roots/132520: Can you please help me this problem!
The directions are the solve it using the square root method:
x^2=16

I don't know!
Please help! =]
1 solutions

Answer 96865 by jim_thompson5910(28536) About Me  on 2008-03-18 00:19:50 (Show Source):
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Start with the given equation



Take the square root of both sides




Take the square root of 16 to get 4



Break the solution into two parts


  or   

 



-----------------------------------
Answer:
So our solution is

  or   

 


Linear-systems/132508: This question is from textbook algebra 1
what is 4x-y-7=0 written in standard form with interger co efficients

1 solutions

Answer 96848 by jim_thompson5910(28536) About Me  on 2008-03-17 20:46:49 (Show Source):
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4x-y-7=0 Start with the given equation


4x-y=7 Add 7 to both sides


Since the equation resembles the general equation Ax%2BBy=C, the equation is now in standard form.


Linear-systems/132507: This question is from textbook algebra 1
i dont understand

1 solutions

Answer 96847 by jim_thompson5910(28536) About Me  on 2008-03-17 20:44:52 (Show Source):
You can put this solution on YOUR website!
You need to post the problem since most of us do not have your book


Equations/132506: x+x+x+2+1=11
1 solutions

Answer 96846 by jim_thompson5910(28536) About Me  on 2008-03-17 20:44:23 (Show Source):
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x%2Bx%2Bx%2B2%2B1=11 Start with the given equation



3x%2B3=11 Combine like terms on the left side


3x=11-3Subtract 3 from both sides


3x=8 Combine like terms on the right side


x=%288%29%2F%283%29 Divide both sides by 3 to isolate x


--------------------------------------------------------------
Answer:
So our answer is x=8%2F3 (which is approximately x=2.667 in decimal form)