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Graphs/140316: Find the domain of the function f%28x%29=%281%29%2F%283x%2B2%29%5E2


1 solutions

Answer 102186 by jim_thompson5910(28550) About Me  on 2008-05-06 11:09:04 (Show Source):
You can put this solution on YOUR website!
f%28x%29=%281%29%2F%283x%2B2%29%5E2 Start with the given function


%283x%2B2%29%5E2=0 Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.


3x%2B2=0 Take the square root of both sides


3x=0-2Subtract 2 from both sides


3x=-2 Combine like terms on the right side


x=%28-2%29%2F%283%29 Divide both sides by 3 to isolate x



x=-2%2F3 Reduce





Since x=-2%2F3 makes the denominator equal to zero, this means we must exclude x=-2%2F3 from our domain

So our domain is:

which in plain English reads: x is the set of all real numbers except x%3C%3E-2%2F3

So our domain looks like this in interval notation


note: remember, the parenthesis excludes -2/3 from the domain

If we wanted to graph the domain on a number line, we would get:

Graph of the domain in blue and the excluded value represented by open circle

Notice we have a continuous line until we get to the hole at x=-2%2F3 (which is represented by the open circle).
This graphically represents our domain in which x can be any number except x cannot equal -2/3


Graphs/140315: Graph the solution to the system

x%2By%3E=8
x%2B3y%3E12


1 solutions

Answer 102185 by jim_thompson5910(28550) About Me  on 2008-05-06 11:06:09 (Show Source):
You can put this solution on YOUR website!
Start with the given system of inequalities
x%2By%3E=8
x%2B3y%3E12

In order to graph this system of inequalities, we need to graph each inequality one at a time.


First lets graph the first inequality x%2By%3E=8
In order to graph x%2By%3E=8, we need to graph the equation x%2By=8 (just replace the inequality sign with an equal sign).
So lets graph the line x%2By=8 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+-x%2B8%29+ graph of x%2By=8
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality x%2By%3E=8 with the test point

Substitute (0,0) into the inequality
%280%29%2B%280%29%3E=8 Plug in x=0 and y=0
0%3E=8 Simplify



(note: for some reason, some of the following images do not display correctly in Internet Explorer. So I recommend the use of
Firefox to see these images.)


Since this inequality is not true, we do not shade the entire region that contains (0,0). So this means we shade the region that is on the opposite side of the line
Graph of x%2By%3E=8 with the boundary (which is the line x%2By=8 in red) and the shaded region (in green)

---------------------------------------------------------------


Now lets graph the second inequality x%2B3y%3E12
In order to graph x%2B3y%3E12, we need to graph the equation x%2B3y=12 (just replace the inequality sign with an equal sign).
So lets graph the line x%2B3y=12 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+-%281%2F3%29x%2B4%29+ graph of x%2B3y=12
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality x%2B3y%3E12 with the test point

Substitute (0,0) into the inequality
%280%29%2B3%280%29%3E12 Plug in x=0 and y=0
0%3E12 Simplify



Since this inequality is not true, we do not shade the entire region that contains (0,0). So this means we shade the region that is on the opposite side of the line
Graph of x%2B3y%3E12 with the boundary (which is the line x%2B3y=12 in red) and the shaded region (in green)
(note: since the inequality contains a greater-than sign, this means the boundary is excluded. This means the solid red line is really a dashed line)
---------------------------------------------------------------


So we essentially have these 2 regions:

Region #1
Graph of x%2By%3E=8


Region #2
Graph of x%2B3y%3E12




When these inequalities are graphed on the same coordinate system, the regions overlap to produce this region. It's a little hard to see, but after evenly shading each region, the intersecting region will be the most shaded in.







Here is a cleaner look at the intersection of regions




Here is the intersection of the 2 regions represented by the series of dots


Graphs/140314: Graph the equation x%5E2%2By%5E2-6x%2B2y%2B1=0


1 solutions

Answer 102184 by jim_thompson5910(28550) About Me  on 2008-05-06 11:03:47 (Show Source):
You can put this solution on YOUR website!

x%5E2%2By%5E2-6x%2B2y%2B1=0 Start with the given equation


x%5E2-6x%2By%5E2%2B2y%2B1=0 Rearrange the terms


x%5E2-6x%2By%5E2%2B2y=-1 Subtract 1 from both sides


%28x-3%29%5E2-9%2By%5E2%2B2y=-1 Complete the square for the x terms (let me know if you need help completing the square)


%28x-3%29%5E2-9%2B%28y%2B1%29%5E2-1=-1 Complete the square for the y terms


%28x-3%29%5E2%2B%28y%2B1%29%5E2-10=-1 Combine like terms


%28x-3%29%5E2%2B%28y%2B1%29%5E2=-1%2B10 Add 10 to both sides


%28x-3%29%5E2%2B%28y%2B1%29%5E2=9 Combine like terms


%28y%2B1%29%5E2=9-%28x-3%29%5E2 Subtract %28x-3%29%5E2 from both sides


y%2B1=0%2B-sqrt%289-%28x-3%29%5E2%29 Take the square root of both sides


y=0%2B-sqrt%289-%28x-3%29%5E2%29-1 Subtract 1 from both sides


So we have the two equations

y=sqrt%289-%28x-3%29%5E2%29-1 and y=-sqrt%289-%28x-3%29%5E2%29-1


When we graph the two, we get

Graph of y=sqrt%289-%28x-3%29%5E2%29-1 (red) and y=-sqrt%289-%28x-3%29%5E2%29-1(green)


Graphs/140313: Graph the equation %28x-2%29%5E2%2B%28y%2B1%29%5E2=12


1 solutions

Answer 102182 by jim_thompson5910(28550) About Me  on 2008-05-06 10:56:41 (Show Source):
You can put this solution on YOUR website!
%28x-2%29%5E2%2B%28y%2B1%29%5E2=12 Start with the given equation


%28y%2B1%29%5E2=12-%28x-2%29%5E2 Subtract %28x-2%29%5E2 from both sides


y%2B1=0%2B-sqrt%2812-%28x-2%29%5E2%29 Take the square root of both sides


y=0%2B-sqrt%2812-%28x-2%29%5E2%29-1 Subtract 1 from both sides


So we have the two equations

y=sqrt%2812-%28x-2%29%5E2%29-1 and y=-sqrt%2812-%28x-2%29%5E2%29-1



So when we graph the two equations we get

Graph of y=sqrt%2812-%28x-2%29%5E2%29-1 (red) and y=-sqrt%2812-%28x-2%29%5E2%29-1 (green)


Graphs/140312: Graph the equation %28x%2B5%29%5E2%2B%28y-1%29%5E2=16


1 solutions

Answer 102181 by jim_thompson5910(28550) About Me  on 2008-05-06 10:54:14 (Show Source):
You can put this solution on YOUR website!
%28x%2B5%29%5E2%2B%28y-1%29%5E2=16 Start with the given equation


%28y-1%29%5E2=16-%28x%2B5%29%5E2 Subtract %28x%2B5%29%5E2 from both sides


y-1=0%2B-sqrt%2816-%28x%2B5%29%5E2%29 Take the square root of both sides


y=0%2B-sqrt%2816-%28x%2B5%29%5E2%29%2B1 Add 1 to both sides


So we have the two equations

y=sqrt%2816-%28x%2B5%29%5E2%29%2B1 and y=-sqrt%2816-%28x%2B5%29%5E2%29%2B1



So when we graph the two equations we get

Graph of y=sqrt%2816-%28x%2B5%29%5E2%29%2B1 (red) and y=-sqrt%2816-%28x%2B5%29%5E2%29%2B1 (green)


Quadratic_Equations/140238: x^2+4x+1=0
1 solutions

Answer 102153 by jim_thompson5910(28550) About Me  on 2008-05-06 00:19:27 (Show Source):
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:


Starting with the general quadratic

ax%5E2%2Bbx%2Bc=0

the general solution using the quadratic equation is:

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29



So lets solve x%5E2%2B4%2Ax%2B1=0 ( notice a=1, b=4, and c=1)




x+=+%28-4+%2B-+sqrt%28+%284%29%5E2-4%2A1%2A1+%29%29%2F%282%2A1%29 Plug in a=1, b=4, and c=1



x+=+%28-4+%2B-+sqrt%28+16-4%2A1%2A1+%29%29%2F%282%2A1%29 Square 4 to get 16



x+=+%28-4+%2B-+sqrt%28+16%2B-4+%29%29%2F%282%2A1%29 Multiply -4%2A1%2A1 to get -4



x+=+%28-4+%2B-+sqrt%28+12+%29%29%2F%282%2A1%29 Combine like terms in the radicand (everything under the square root)



x+=+%28-4+%2B-+2%2Asqrt%283%29%29%2F%282%2A1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



x+=+%28-4+%2B-+2%2Asqrt%283%29%29%2F2 Multiply 2 and 1 to get 2

So now the expression breaks down into two parts

x+=+%28-4+%2B+2%2Asqrt%283%29%29%2F2 or x+=+%28-4+-+2%2Asqrt%283%29%29%2F2


Now break up the fraction


x=-4%2F2%2B2%2Asqrt%283%29%2F2 or x=-4%2F2-2%2Asqrt%283%29%2F2


Simplify


x=-2%2Bsqrt%283%29 or x=-2-sqrt%283%29


So these expressions approximate to

x=-0.267949192431123 or x=-3.73205080756888


So our solutions are:
x=-0.267949192431123 or x=-3.73205080756888

Notice when we graph x%5E2%2B4%2Ax%2B1, we get:



when we use the root finder feature on a calculator, we find that x=-0.267949192431123 and x=-3.73205080756888.So this verifies our answer


Linear-equations/140258: (2,-3)
(-5,4)

find the slope , show the linear equation, draw a graph
1 solutions

Answer 102152 by jim_thompson5910(28550) About Me  on 2008-05-06 00:17:46 (Show Source):
You can put this solution on YOUR website!
First lets find the slope through the points (2,-3) and (-5,4)

m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula (note: is the first point (2,-3) and is the second point (-5,4))

m=%284--3%29%2F%28-5-2%29 Plug in y%5B2%5D=4,y%5B1%5D=-3,x%5B2%5D=-5,x%5B1%5D=2 (these are the coordinates of given points)

m=+7%2F-7 Subtract the terms in the numerator 4--3 to get 7. Subtract the terms in the denominator -5-2 to get -7


m=-1 Reduce

So the slope is
m=-1

------------------------------------------------


Now let's use the point-slope formula to find the equation of the line:



------Point-Slope Formula------
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is one of the given points

So lets use the Point-Slope Formula to find the equation of the line

y--3=%28-1%29%28x-2%29 Plug in m=-1, x%5B1%5D=2, and y%5B1%5D=-3 (these values are given)


y%2B3=%28-1%29%28x-2%29 Rewrite y--3 as y%2B3


y%2B3=-x%2B%28-1%29%28-2%29 Distribute -1

y%2B3=-x%2B2 Multiply -1 and -2 to get 2

y=-x%2B2-3 Subtract 3 from both sides to isolate y

y=-x-1 Combine like terms 2 and -3 to get -1
------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line which goes through the points (2,-3) and (-5,4) is:y=-x-1

The equation is now in y=mx%2Bb form (which is slope-intercept form) where the slope is m=-1 and the y-intercept is b=-1

Notice if we graph the equation y=-x-1 and plot the points (2,-3) and (-5,4), we get this: (note: if you need help with graphing, check out this solver)

Graph of y=-x-1 through the points (2,-3) and (-5,4)

Notice how the two points lie on the line. This graphically verifies our answer.


Polynomials-and-rational-expressions/140099: I am having trouble solving this type of problems.
x^3+5x^2-6x+10
______________
x+3
1 solutions

Answer 102085 by jim_thompson5910(28550) About Me  on 2008-05-05 10:24:00 (Show Source):
You can put this solution on YOUR website!

Let's simplify this expression using synthetic division


Start with the given expression %28x%5E3+%2B+5x%5E2+-+6x+%2B+10%29%2F%28x%2B3%29

First lets find our test zero:

x%2B3=0 Set the denominator x%2B3 equal to zero

x=-3 Solve for x.

so our test zero is -3


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
-3|15-610
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 1)
-3|15-610
|
1

Multiply -3 by 1 and place the product (which is -3) right underneath the second coefficient (which is 5)
-3|15-610
|-3
1

Add -3 and 5 to get 2. Place the sum right underneath -3.
-3|15-610
|-3
12

Multiply -3 by 2 and place the product (which is -6) right underneath the third coefficient (which is -6)
-3|15-610
|-3-6
12

Add -6 and -6 to get -12. Place the sum right underneath -6.
-3|15-610
|-3-6
12-12

Multiply -3 by -12 and place the product (which is 36) right underneath the fourth coefficient (which is 10)
-3|15-610
|-3-636
12-12

Add 36 and 10 to get 46. Place the sum right underneath 36.
-3|15-610
|-3-636
12-1246

Since the last column adds to 46, we have a remainder of 46. This means x%2B3 is not a factor of x%5E3+%2B+5x%5E2+-+6x+%2B+10
Now lets look at the bottom row of coefficients:

The first 3 coefficients (1,2,-12) form the quotient

x%5E2+%2B+2x+-+12

and the last coefficient 46, is the remainder, which is placed over x%2B3 like this

46%2F%28x%2B3%29



Putting this altogether, we get:

x%5E2+%2B+2x+-+12%2B46%2F%28x%2B3%29

So %28x%5E3+%2B+5x%5E2+-+6x+%2B+10%29%2F%28x%2B3%29=x%5E2+%2B+2x+-+12%2B46%2F%28x%2B3%29

which looks like this in remainder form:
%28x%5E3+%2B+5x%5E2+-+6x+%2B+10%29%2F%28x%2B3%29=x%5E2+%2B+2x+-+12 remainder 46


You can use this online polynomial division calculator to check your work




Equations/140072: I would be so grateful if someone could help me with this. 4=3(x-3)+4-2x
Thank you in advance.

1 solutions

Answer 102084 by jim_thompson5910(28550) About Me  on 2008-05-05 10:22:01 (Show Source):
You can put this solution on YOUR website!

4=3%28x-3%29%2B4-2x Start with the given equation



4=3x-9%2B4-2x Distribute


4=x-5 Combine like terms on the right side


4%2B5=xAdd 5 to both sides


9=x Combine like terms on the left side


--------------------------------------------------------------
Answer:
So our answer is x=9




Functions/140040: determine the domain of the function f(x)=sqrt of 3-x
1 solutions

Answer 102070 by jim_thompson5910(28550) About Me  on 2008-05-04 22:02:17 (Show Source):
You can put this solution on YOUR website!

sqrt%283-x%29 Start with the given expression

Remember you cannot take the square root of a negative value. So that means the argument 3-x must be greater than or equal to zero (i.e. the argument must be positive)

3-x%3E=0 Set the inner expression greater than or equal to zero

-x%3E=0-3Subtract 3 from both sides


-x%3E=-3 Combine like terms on the right side


x%3C=%28-3%29%2F%28-1%29 Divide both sides by -1 to isolate x (note: Remember, dividing both sides by a negative number flips the inequality sign)



x%3C=3 Divide


So that means x must be less than or equal to 3 in order for x to be in the domain

So the domain in set-builder notation is




So here is the domain in interval notation: (-,3]




Notice if we graph y=sqrt%283-x%29 , we get
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%283-x%29%29+ notice how the graph never crosses the line x=3

and we can see that x must be less than or equal to 3 in order to lie on the graph. So this graphically verifies our answer.


Linear-equations/140012: f(x)=-4x-5
Find the Slope
and the y-intercept
1 solutions

Answer 102050 by jim_thompson5910(28550) About Me  on 2008-05-04 20:23:00 (Show Source):
You can put this solution on YOUR website!
Notice how y=-4x-5 is in slope-intercept form y=mx%2Bb where m is the slope and b is the y-intercept.

So this shows us that the slope is m=-4 and the y-intercept is b=-5 which is the point (0,-5).


test/140019: Reduce the given expression to lowest terms.
3x2+7x+2
--------
4x2-16







1 solutions

Answer 102049 by jim_thompson5910(28550) About Me  on 2008-05-04 20:21:42 (Show Source):
You can put this solution on YOUR website!
%283x%5E2%2B7x%2B2%29%2F%284x%5E2-16%29 Start with the given expression

%28%28x%2B2%29%283x%2B1%29%29%2F%284x%5E2-16%29 Factor 3x%5E2%2B7x%2B2 to get %28x%2B2%29%283x%2B1%29

%28%28x%2B2%29%283x%2B1%29%29%2F%284%28x%2B2%29%28x-2%29%29 Factor 4x%5E2-16 to get 4%28x%2B2%29%28x-2%29


%28x%2B2%29%283x%2B1%29%2F4%28x%2B2%29%28x-2%29 Combine the fractions


cross%28%28x%2B2%29%29%283x%2B1%29%2F4cross%28%28x%2B2%29%29%28x-2%29 Cancel like terms


%283x%2B1%29%2F4%28x-2%29 Simplify



-------------------------------------------

Answer:


So %283x%5E2%2B7x%2B2%29%2F%284x%5E2-16%29 simplifies to %283x%2B1%29%2F4%28x-2%29


Graphs/140018: 2. One number exceeds another by 5. The sum of their reciprocals equal to 19
divided by the product of the two numbers. Find the two numbers.
(a) How will you set up the problem?
(b) What is the equation that the one number exceeds another by 5?
(c) What is the product of two numbers, in terms of x?
(d) What is x? Also check your answer.

1 solutions

Answer 102047 by jim_thompson5910(28550) About Me  on 2008-05-04 20:17:20 (Show Source):
You can put this solution on YOUR website!
a)
Let x=first number and y=second number
b)
Since "One number exceeds another by 5", this means that the first equation is y=x%2B5
c)
The product of the two numbers in terms of x is
x%28x%2B5%29=x%5E2%2B5x

d)
The value of x is 7


----------------------------


So let's solve the problem


Let x=first number and y=second number

Since "One number exceeds another by 5", this means that the first equation is y=x%2B5

Also, because "The sum of their reciprocals equal to 19 divided by the product of the two numbers" we have the second equation

1%2Fx%2B1%2Fy=19%2F%28x%2Ay%29

1%2Fx%2B1%2F%28x%2B5%29=19%2F%28x%2A%28x%2B5%29%29 Plug in y=x%2B5


Multiply both sides by the LCD x%2A%28x%2B5%29 to clear out the fractions


x%2B5%2Bx=19 Distribute and multiply


2x%2B5=19 Combine like terms on the left side


2x=19-5Subtract 5 from both sides


2x=14 Combine like terms on the right side


x=%2814%29%2F%282%29 Divide both sides by 2 to isolate x


x=7 Divide

--------------------------------------------------------------
Answer:
So our answer is x=7


Graphs/140017: 1. The perimeter of a rectangular box is 42 inches. The length of the box is 15 inches
more than the width. Determine the dimensions of the rectangle in terms of feet
Also find the area of the box in terms of feet. Draw the diagram by showing the
dimensions.
(a) How will you set up the problem.
(b) What are the two linear equations.
(c) What is the product of two dimensions of the rectangle.
(d) How is this product different from perimeter. Interpret on that.

1 solutions

Answer 102045 by jim_thompson5910(28550) About Me  on 2008-05-04 20:16:25 (Show Source):
You can put this solution on YOUR website!
a)

Let L=length, W=width


b)
Since "The length of the box is 15 inches more than the width", this means the first equation is L=W%2B15


Remember the perimeter formula is P=2%2AW%2B2%2AL

If we plug in P=42, we get the second equation:

42=2%2AW%2B2%2AL


So the two equations are:
L=W%2B15
42=2%2AW%2B2%2AL


c) the product of the two dimensions of the rectangle is

W%2AL=W%2A%28W%2B15%29=W%5E2%2B15W


d) The perimeter is a linear equation while the product is a nonlinear equation


Exponential-and-logarithmic-functions/140001: simplify 4m^4n^3p^3/3m^2n^2p^4
1 solutions

Answer 102040 by jim_thompson5910(28550) About Me  on 2008-05-04 19:34:43 (Show Source):
You can put this solution on YOUR website!
%284m%5E4n%5E3p%5E3%29%2F%283m%5E2n%5E2p%5E4%29 Start with the given expression.


m%5E%284-2%29n%5E%283-2%29p%5E%283-4%29 Remember when you divide monomials, you subtract their corresponding exponents. For instance x%5E2%2Fx%5E3=x%5E%282-3%29=x%5E-1


%284%2F3%29%28m%5E2n%5E1p%5E-1%29 Simplify. Remember to reduce the coefficients (which are numbers in front of the variables) to get 4%2F3=4%2F3.


%284%2F3%29%28m%5E2n%2Fp%29 Flip the expression with a negative exponent.


%284m%5E2n%29%2F%283p%29 Simplify



--------------------------------------------
Answer:

So %284m%5E4n%5E3p%5E3%29%2F%283m%5E2n%5E2p%5E4%29 simplifies to %284m%5E2n%29%2F%283p%29.

In other words, %284m%5E4n%5E3p%5E3%29%2F%283m%5E2n%5E2p%5E4%29=%284m%5E2n%29%2F%283p%29 where m%3C%3E0 and n%3C%3E0


Polynomials-and-rational-expressions/140005: Multiply and match your result to the correct answer below:
(z – 8)(z + 8)
A)z2 + 16
B)z2 – 64
C)z2 – 16
D)z2 – 16y – 64

1 solutions

Answer 102039 by jim_thompson5910(28550) About Me  on 2008-05-04 19:31:33 (Show Source):
You can put this solution on YOUR website!

%28z-8%29%28z%2B8%29 Start with the given expression


Now let's FOIL the expression



Remember, when you FOIL an expression, you follow this procedure:


%28highlight%28z%29-8%29%28highlight%28z%29%2B8%29 Multiply the First terms:%28z%29%2A%28z%29=z%5E2


%28highlight%28z%29-8%29%28z%2Bhighlight%288%29%29 Multiply the Outer terms:%28z%29%2A%288%29=8z


%28z%2Bhighlight%28-8%29%29%28highlight%28z%29%2B8%29 Multiply the Inner terms:%28-8%29%2A%28z%29=-8z


%28z%2Bhighlight%28-8%29%29%28z%2Bhighlight%288%29%29 Multiply the Last terms:%28-8%29%2A%288%29=-64


z%5E2%2B8z-8z-64 Now collect every term to make a single expression



z%5E2-64 Now combine like terms


---------------------
Answer:
So %28z-8%29%28z%2B8%29 foils and simplifies to z%5E2-64

In other words, %28z-8%29%28z%2B8%29=z%5E2-64


test/140011: Factor completely and match your result to the correct answer below.
r2 + 2r – 80
A)(r + 10)(r + 8)
B)(r – 10)(r + 8)
C)(r – 10)(r – 8)
D)(r + 10)(r – 8)

1 solutions

Answer 102038 by jim_thompson5910(28550) About Me  on 2008-05-04 19:30:54 (Show Source):
You can put this solution on YOUR website!

Looking at r%5E2%2B2r-80 we can see that the first term is r%5E2 and the last term is -80 where the coefficients are 1 and -80 respectively.

Now multiply the first coefficient 1 and the last coefficient -80 to get -80. Now what two numbers multiply to -80 and add to the middle coefficient 2? Let's list all of the factors of -80:



Factors of -80:
1,2,4,5,8,10,16,20,40,80

-1,-2,-4,-5,-8,-10,-16,-20,-40,-80 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -80
(1)*(-80)
(2)*(-40)
(4)*(-20)
(5)*(-16)
(8)*(-10)
(-1)*(80)
(-2)*(40)
(-4)*(20)
(-5)*(16)
(-8)*(10)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2

First NumberSecond NumberSum
1-801+(-80)=-79
2-402+(-40)=-38
4-204+(-20)=-16
5-165+(-16)=-11
8-108+(-10)=-2
-180-1+80=79
-240-2+40=38
-420-4+20=16
-516-5+16=11
-810-8+10=2



From this list we can see that -8 and 10 add up to 2 and multiply to -80


Now looking at the expression 1r%5E2%2B2r-80, replace 2r with -8r%2B10r (notice -8r%2B10r adds up to 2r. So it is equivalent to 2r)

r%5E2%2Bhighlight%28-8r%2B10r%29%2B-80


Now let's factor r%5E2-8r%2B10r-80 by grouping:


%281r%5E2-8r%29%2B%2810r-80%29 Group like terms


r%28r-8%29%2B10%28r-8%29 Factor out the GCF of r out of the first group. Factor out the GCF of 10 out of the second group


%28r%2B10%29%28r-8%29 Since we have a common term of r-8, we can combine like terms

So r%5E2-8r%2B10r-80 factors to %28r%2B10%29%28r-8%29


So this also means that r%5E2%2B2r-80 factors to %28r%2B10%29%28r-8%29 (since r%5E2%2B2r-80 is equivalent to 1r%5E2-8r%2B10r-80)



------------------------------------------------------------



Answer:
So r%5E2%2B2r-80 factors to %28r%2B10%29%28r-8%29


test/140010: Factor: st + 5b – bs – 5t
A) (s – 5)(t + b)
B) (s – 5)(t – b)
C) (s + 5)(t – b)
D) The expression is prime.

1 solutions

Answer 102037 by jim_thompson5910(28550) About Me  on 2008-05-04 19:29:15 (Show Source):
You can put this solution on YOUR website!
st%2B5b-bs-5t Start with the given expression


st-bs%2B5b-5t Rearrange the terms


%28st-bs%29%2B%285b-5t%29 Group like terms


s%28t-b%29-5%28-b%2Bt%29 Factor out the GCF "s" from the first group. Factor out the GCF -5 from the second group


s%28t-b%29-5%28t-b%29 Rearrange -b%2Bt in the second group to get t-b


%28s-5%29%28t-b%29 Combine like terms


-----------------------------
Answer:

So st%2B5b-bs-5t factors to %28s-5%29%28t-b%29


test/140008: Factor completely: 12p2 + 20p
A)2(6p2 + 10)
B)4p(3p + 20)
C)4p(3p + 5)
D)6p(2p + 5)

1 solutions

Answer 102036 by jim_thompson5910(28550) About Me  on 2008-05-04 19:23:36 (Show Source):
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12p%5E2%2B20p Start with the given expression


4p%283p%2B5%29 Factor out the GCF 4p




-----------------------------------------------------------

Answer:


So 12p%5E2%2B20p factors to 4p%283p%2B5%29


test/140007: Factor: z2 – 14z + 49
A) (z – 7)2
B) (z – 7)(z + 7)
C) (z – 14)(z + 1)
D) The expression is prime.

1 solutions

Answer 102035 by jim_thompson5910(28550) About Me  on 2008-05-04 19:21:53 (Show Source):
You can put this solution on YOUR website!

Looking at 1z%5E2-14z%2B49 we can see that the first term is 1z%5E2 and the last term is 49 where the coefficients are 1 and 49 respectively.

Now multiply the first coefficient 1 and the last coefficient 49 to get 49. Now what two numbers multiply to 49 and add to the middle coefficient -14? Let's list all of the factors of 49:



Factors of 49:
1,7

-1,-7 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 49
1*49
7*7
(-1)*(-49)
(-7)*(-7)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to -14? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -14

First NumberSecond NumberSum
1491+49=50
777+7=14
-1-49-1+(-49)=-50
-7-7-7+(-7)=-14



From this list we can see that -7 and -7 add up to -14 and multiply to 49


Now looking at the expression 1z%5E2-14z%2B49, replace -14z with -7z%2B-7z (notice -7z%2B-7z adds up to -14z. So it is equivalent to -14z)

1z%5E2%2Bhighlight%28-7z%2B-7z%29%2B49


Now let's factor 1z%5E2-7z-7z%2B49 by grouping:


%281z%5E2-7z%29%2B%28-7z%2B49%29 Group like terms


z%28z-7%29-7%28z-7%29 Factor out the GCF of z out of the first group. Factor out the GCF of -7 out of the second group


%28z-7%29%28z-7%29 Since we have a common term of z-7, we can combine like terms

So 1z%5E2-7z-7z%2B49 factors to %28z-7%29%28z-7%29


So this also means that 1z%5E2-14z%2B49 factors to %28z-7%29%28z-7%29 (since 1z%5E2-14z%2B49 is equivalent to 1z%5E2-7z-7z%2B49)


note: %28z-7%29%28z-7%29 is equivalent to %28z-7%29%5E2 since the term z-7 occurs twice. So 1z%5E2-14z%2B49 also factors to %28z-7%29%5E2


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Answer:

So 1z%5E2-14z%2B49 factors to %28z-7%29%5E2


test/140006: Factor: y2 – 64
A) (y – 8)(y + 8)
B) (y – 8)2
C) (8 – y)(8 + y)
D) The expression is prime.

1 solutions

Answer 102034 by jim_thompson5910(28550) About Me  on 2008-05-04 19:21:05 (Show Source):
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y%5E2-64 Start with the given expression

%28y%29%5E2-64 Rewrite y%5E2 as %28y%29%5E2

%28y%29%5E2-%288%29%5E2 Rewrite 64 as %288%29%5E2


Now use the difference of squares. Remember, the difference of squares formula is A%5E2-B%5E2=%28A%2BB%29%28A-B%29 where in this case A=y and B=8

y%5E2-64=%28y%2B8%29%28y-8%29 Plug in A=y and B=8

So the expression

y%5E2-64

factors to

%28y%2B8%29%28y-8%29

Notice that if you foil the factored expression, you get the original expression. This verifies our answer.


Geometric_formulas/139954:
1 solutions

Answer 102009 by jim_thompson5910(28550) About Me  on 2008-05-04 13:25:13 (Show Source):
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Let x=supplement to angle A

Remember, supplement angles add to 180. So if we want to find the supplement to angle A, then

x%2B72=180



x=180-72Subtract 72 from both sides


x=108 Combine like terms on the right side

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Answer:
So our answer is x=108

So the supplement to angle A is 108 degrees


Geometric_formulas/139952: 7. Find the measure of angle x and measure of angle y.


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1 solutions

Answer 102008 by jim_thompson5910(28550) About Me  on 2008-05-04 13:20:11 (Show Source):
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Notice how angle x and 135 degrees form a 180 degree angle. So this means that

x%2B135=180



x%2Bcross%28135-135%29=180-135Subtract 135 from both sides


x=45 Combine like terms on the right side



Also, notice how angle x and angle y also form a 180 degree angle. So

x%2By=180

But we know what x is, so plug in the value of x


45%2By=180 Plug in x=45




y=180-45Subtract 45 from both sides


y=135 Combine like terms on the right side




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Answer:


So the values are

x=45 and y=135


Geometric_formulas/139951: 6. Find the missing angle.


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1 solutions

Answer 102006 by jim_thompson5910(28550) About Me  on 2008-05-04 13:14:15 (Show Source):
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To find the missing angle, first add up the two given angles

75%2B73=148


So the sum of the two angles is 148 degrees. Now subtract this answer from 180 (remember the sum of the three angles of a triangle is 180 degrees)

180-148=32

So the missing angle is 32 degrees


Geometric_formulas/139950: 5. Which two triangles are similar?


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1 solutions

Answer 102005 by jim_thompson5910(28550) About Me  on 2008-05-04 13:08:48 (Show Source):
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First, we need to find the missing angles of each triangle.


For the first triangle, first add up the two given angles 69 and 48 to get

69%2B48=117

Now subtract 117 from 180 to get

180-117=63


So the first triangle has these angles


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For the second triangle, first add up the two given angles 63 and 48 to get

63%2B48=111

Now subtract 111 from 180 to get

180-111=69


So the second triangle has these angles


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For the third triangle, first add up the two given angles 63 and 48 to get

63%2B78=141

Now subtract 111 from 180 to get

180-141=39


So the third triangle has these angles


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Summary:



So the three triangles have these angles


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Answer:


Remember, similar triangles have equal angles. From the figure, we can see that triangles a) and b) have equal angles. So triangles a) and b) are similar triangles.


Geometric_formulas/139948: 4. The two triangles are similar. Find the indicated side. Find y.

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1 solutions

Answer 102003 by jim_thompson5910(28550) About Me  on 2008-05-04 12:54:18 (Show Source):
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Since the triangles are similar, this means that the length of the sides are dependent on one another. In fact, these sides form the ratio:


10%2F8=5%2Fy


%2810%2F8%29%2Ay=5 Multiply both sides by y


10%2Ay=5%2A8 Multiply both sides by 8


10%2Ay=40 Multiply


y=40%2F10 Divide both sides by 10


y=4 Simplify



So our answer is y=4


Geometric_formulas/139946: 3. Identify the hypotenuse of the triangle by giving its letter


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1 solutions

Answer 102002 by jim_thompson5910(28550) About Me  on 2008-05-04 12:48:23 (Show Source):
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The hypotenuse is the longest side. So in this case, the hypotenuse is z.


Geometric_formulas/139945: Find the missing length of the right triangle
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1 solutions

Answer 102001 by jim_thompson5910(28550) About Me  on 2008-05-04 12:45:30 (Show Source):
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Let's use Pythagoreans theorem to solve this problem

Pythagoreans theorem:

a%5E2%2Bb%5E2=c%5E2 where a and b are the legs of the triangle and c is the hypotenuse



7%5E2%2B24%5E2=c%5E2 Plug in a=7, b=24. Now lets solve for c.


4+9+%2B+5+7+6+=++c++%5E+2 Square each individual term



6+2+5+=++c++%5E+2 Combine like terms


s+q+r+t+%28+6+2+5+%29+=+s+q+r+t+%28++c++%5E+2+%29 Take the square root of both sides


25=c Simplify the square root


So our answer is
c=25


So the length of the unknown side is 25 units.


Geometric_formulas/139941: 1. Approximate sqrt%2831%29 by giving the two whole numbers that it lies between
1 solutions

Answer 102000 by jim_thompson5910(28550) About Me  on 2008-05-04 12:10:17 (Show Source):
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First, note that the numbers 25 and 36 are perfect squares. In other words, 5%5E2=25 and 6%5E2=36. So since 31 is in between 25 and 36, this means that the square root of 31 is in between 5 and 6. In other words, since 25%3C31%3C36, this means 5%3Csqrt%2831%29%3C6.


Notice how 31 is 6 units away from 25 and 5 units away from 36. So 31 is about the halfway point from 25 to 36. So a good approximation for sqrt%2831%29 is 5.5 since 5.5 is halfway between 5 and 6.


So


If we take the square root of 31 with a calculator, we get sqrt%2831%29=5.5677643628. So this shows us that our approximation is very close.


Equations/139872: Find the slope of a line whose equation is y= -6x+3
1 solutions

Answer 101938 by jim_thompson5910(28550) About Me  on 2008-05-03 15:09:29 (Show Source):
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Notice how y=-6x%2B3 is in slope-intercept form y=mx%2Bb where m is the slope and b is the y-intercept.

So this shows us that the slope is m=-6 and the y-intercept is b=3


Quadratic_Equations/139853: Please help me solve this equation:
5x+4y=12
I have tried the equation by doing this:
5x+4y=12
5x-5x+4y=12-5x
4y=12-5x
4y/4=12-5x/4
My answer came totaled to: y=3-5x
1 solutions

Answer 101934 by jim_thompson5910(28550) About Me  on 2008-05-03 14:14:02 (Show Source):
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Do you want to solve for y?



5x%2B4y=12 Start with the given equation


4y=12-5x Subtract 5+x from both sides


4y=-5x%2B12 Rearrange the equation


y=%28-5x%2B12%29%2F%284%29 Divide both sides by 4


y=%28-5%2F4%29x%2B%2812%29%2F%284%29 Break up the fraction


y=%28-5%2F4%29x%2B3 Reduce