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Polynomials-and-rational-expressions/145203: Simplify the expression:
( 4 x + 1 ) 2 + (2 x - 4 ) 2
Choose the correct answer from the following:
20x 2 - 8x + 17
12x 2 - 8x + 15
4x 2 + 8x - 15
1 solutions

Answer 105875 by jim_thompson5910(28476) About Me  on 2008-06-13 13:46:21 (Show Source):
You can put this solution on YOUR website!
First FOIL %28+4+x+%2B+1+%29+%5E+2

%282x-4%29%5E2 Start with the given expression


%284x%2B1%29%284x%2B1%29 Expand. Remember something like x%5E2=x%2Ax


Now let's FOIL the expression



Remember, when you FOIL an expression, you follow this procedure:


%28highlight%284x%29%2B1%29%28highlight%284x%29%2B1%29 Multiply the First terms:%284x%29%2A%284x%29=16x%5E2


%28highlight%284x%29%2B1%29%284x%2Bhighlight%281%29%29 Multiply the Outer terms:%284x%29%2A%281%29=4x


%284x%2Bhighlight%281%29%29%28highlight%284x%29%2B1%29 Multiply the Inner terms:%281%29%2A%284x%29=4x


%284x%2Bhighlight%281%29%29%284x%2Bhighlight%281%29%29 Multiply the Last terms:%281%29%2A%281%29=1


16x%5E2%2B4x%2B4x%2B1 Now collect every term to make a single expression



16x%5E2%2B8x%2B1 Now combine like terms


So %284x%2B1%29%5E2 foils and simplifies to 16x%5E2%2B8x%2B1

In other words, %284x%2B1%29%5E2=16x%5E2%2B8x%2B1








Now let's FOIL %282+x+-+4+%29%5E+2+



%282x-4%29%282x-4%29 Expand. Remember something like x%5E2=x%2Ax


Now let's FOIL the expression



Remember, when you FOIL an expression, you follow this procedure:


%28highlight%282x%29-4%29%28highlight%282x%29-4%29 Multiply the First terms:%282x%29%2A%282x%29=4x%5E2


%28highlight%282x%29-4%29%282x%2Bhighlight%28-4%29%29 Multiply the Outer terms:%282x%29%2A%28-4%29=-8x


%282x%2Bhighlight%28-4%29%29%28highlight%282x%29-4%29 Multiply the Inner terms:%28-4%29%2A%282x%29=-8x


%282x%2Bhighlight%28-4%29%29%282x%2Bhighlight%28-4%29%29 Multiply the Last terms:%28-4%29%2A%28-4%29=16


4x%5E2-8x-8x%2B16 Now collect every term to make a single expression



4x%5E2-16x%2B16 Now combine like terms


So %282x-4%29%5E2 foils and simplifies to 4x%5E2-16x%2B16

In other words, %282x-4%29%5E2=4x%5E2-16x%2B16







So %28+4+x+%2B+1+%29+%5E+2%2B+%282+x+-+4+%29%5E+2+ now becomes %2816x%5E2%2B8x%2B1%29%2B%284x%5E2-16x%2B16%29


%2816x%5E2%2B8x%2B1%29%2B%284x%5E2-16x%2B16%29 Start with the given expression


20x%5E2-8x%2B17 Combine like terms



So %28+4+x+%2B+1+%29+%5E+2%2B+%282+x+-+4+%29%5E+2=20x%5E2-8x%2B17


Polynomials-and-rational-expressions/145202: Choose the polynominal that represents the area of the rectangle with sides (x + 6) and (x - 2):
x 2 - 4x - 12
x 2 + 8x - 12
x 2 + 8x + 12
x 2 - 8x - 12
x 2 - 8x + 12
x 2 - 4x + 12
x 2 + 4x + 12
x 2 + 4x - 12

1 solutions

Answer 105872 by jim_thompson5910(28476) About Me  on 2008-06-13 13:40:08 (Show Source):
You can put this solution on YOUR website!


%28x%2B6%29%28x-2%29 To find the area, simply multiply the given sides x%2B6 and x-2


Now let's FOIL the expression



Remember, when you FOIL an expression, you follow this procedure:


%28highlight%28x%29%2B6%29%28highlight%28x%29-2%29 Multiply the First terms:%28x%29%2A%28x%29=x%5E2


%28highlight%28x%29%2B6%29%28x%2Bhighlight%28-2%29%29 Multiply the Outer terms:%28x%29%2A%28-2%29=-2x


%28x%2Bhighlight%286%29%29%28highlight%28x%29-2%29 Multiply the Inner terms:%286%29%2A%28x%29=6x


%28x%2Bhighlight%286%29%29%28x%2Bhighlight%28-2%29%29 Multiply the Last terms:%286%29%2A%28-2%29=-12


x%5E2-2x%2B6x-12 Now collect every term to make a single expression



x%5E2%2B4x-12 Now combine like terms


---------------------
Answer:
So %28x%2B6%29%28x-2%29 foils and simplifies to x%5E2%2B4x-12

In other words, %28x%2B6%29%28x-2%29=x%5E2%2B4x-12



So the area is x%5E2%2B4x-12


Systems-of-equations/145185: This question is from textbook Beginning Algebra
I need help and lots of it LOL :)Thanks...
Page 490
Number 14
5x-3y=14
2x-y=6
1 solutions

Answer 105867 by jim_thompson5910(28476) About Me  on 2008-06-13 13:01:27 (Show Source):
You can put this solution on YOUR website!
Do you want to use elimination/addition to solve this system?






Start with the given system of equations:

system%285x-3y=14%2C2x-y=6%29



Now in order to solve this system by using elimination/addition, we need to solve (or isolate) one variable. I'm going to solve for y.





In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).


So lets eliminate x. In order to do that, we need to have both x coefficients that are equal in magnitude but have opposite signs (for instance 2 and -2 are equal in magnitude but have opposite signs). This way they will add to zero. By adding to zero, they can be eliminated.



So to make the x coefficients equal in magnitude but opposite in sign, we need to multiply both x coefficients by some number to get them to an common number. So if we wanted to get 5 and 2 to some equal number, we could try to get them to the LCM.



Since the LCM of 5 and 2 is 10, we need to multiply both sides of the top equation by 2 and multiply both sides of the bottom equation by -5 like this:




2%285x-3y%29=2%2814%29 Multiply the top equation (both sides) by 2
-5%282x-y%29=-5%286%29 Multiply the bottom equation (both sides) by -5




Distribute and multiply

10x-6y=28
-10x%2B5y=-30


Now add the equations together. In order to add 2 equations, group like terms and combine them

%2810x-10x%29%2B%28-6y%2B5y%29=28-30

Combine like terms and simplify



cross%2810x-10x%29-y=-2 Notice how the x terms cancel out




-y=-2 Simplify




y=-2%2F-1 Divide both sides by -1 to isolate y




y=2 Reduce



Now plug this answer into the top equation 5x-3y=14 to solve for x

5x-3y=14 Start with the first equation



5x-3%282%29=14 Plug in y=2




5x-6=14 Multiply



5x=14%2B6Add 6 to both sides


5x=20 Combine like terms on the right side


x=%2820%29%2F%285%29 Divide both sides by 5 to isolate x



x=4 Divide




So our answer is
x=4 and y=2



which also looks like




Now let's graph the two equations (if you need help with graphing, check out this solver)


From the graph, we can see that the two equations intersect at . This visually verifies our answer.




graph of 5x-3y=14 (red) and 2x-y=6 (green) and the intersection of the lines (blue circle).


Matrices-and-determiminant/145192: Could someone help me with a few system of equations problems please? These ones are to be solved by the graphing method,and I have to show how I got them when I take the test in the future,So if you could show me step by step that would be great.
1) -x + y = -1
x + y = 3

2) 3x + y = -6
x + y = -4
1 solutions

Answer 105866 by jim_thompson5910(28476) About Me  on 2008-06-13 12:57:48 (Show Source):
You can put this solution on YOUR website!
I'll do the first one to get you started





Start with the given system of equations:

-x%2By=-1
x%2By=3




In order to graph these equations, we need to solve for y for each equation.



So let's solve for y on the first equation

-x%2By=-1 Start with the given equation


y=-1%2Bx Add +x to both sides


y=%2Bx-1 Rearrange the equation


Now lets graph y=x-1 (note: if you need help with graphing, check out this solver)


+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+x-1%29+ Graph of y=x-1



So let's solve for y on the second equation

x%2By=3 Start with the given equation


y=3-x Subtract +x from both sides


y=-x%2B3 Rearrange the equation



Now lets add the graph of y=-x%2B3 to our first plot to get:

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+x-1%2C-x%2B3%29+ Graph of y=x-1(red) and y=-x%2B3(green)

From the graph, we can see that the two lines intersect at the point (2,1)


Age_Word_Problems/145106: if 7 is subtracted from twice a number, the result is 5. find the number.
1 solutions

Answer 105799 by jim_thompson5910(28476) About Me  on 2008-06-12 13:58:57 (Show Source):
You can put this solution on YOUR website!
"7 is subtracted from twice a number, the result is 5" translates to 2x-7=5



2x-7=5 Start with the given equation



2x=5%2B7Add 7 to both sides


2x=12 Combine like terms on the right side


x=%2812%29%2F%282%29 Divide both sides by 2 to isolate x



x=6 Divide

--------------------------------------------------------------
Answer:
So our answer is x=6


Graphs/145104: How many positive real soulutions are there in x^4-4x^3+6x^2-4x+1
1 solutions

Answer 105796 by jim_thompson5910(28476) About Me  on 2008-06-12 13:34:05 (Show Source):
You can put this solution on YOUR website!
Let's count the sign changes of f%28x%29=x%5E4-4x%5E3%2B6x%5E2-4x%2B1

From x%5E4 to -4x%5E3, there is a sign change from positive to negative

From -4x%5E3 to 6x%5E2, there is a sign change from negative to positive

From 6x%5E2 to -4x, there is a sign change from positive to negative

From -4x to 1, there is a sign change from negative to positive

So there are 4 sign changes for the expression f%28x%29=x%5E4-4x%5E3%2B6x%5E2-4x%2B1.

So there are 4, 2, or 0 positive zeros (remember to count down by 2's)


Exponents-negative-and-fractional/145102: -x Squared + 2x = 8
1 solutions

Answer 105795 by jim_thompson5910(28476) About Me  on 2008-06-12 13:10:46 (Show Source):
You can put this solution on YOUR website!

-x%5E2%2B+2x+=+8 Start with the given equation.


-x%5E2%2B+2x+-8=0 Get all terms to the left side.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=-1, b=2, and c=-8


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%282%29+%2B-+sqrt%28+%282%29%5E2-4%28-1%29%28-8%29+%29%29%2F%282%28-1%29%29 Plug in a=-1, b=2, and c=-8


x+=+%28-2+%2B-+sqrt%28+4-4%28-1%29%28-8%29+%29%29%2F%282%28-1%29%29 Square 2 to get 4.


x+=+%28-2+%2B-+sqrt%28+4-32+%29%29%2F%282%28-1%29%29 Multiply 4%28-1%29%28-8%29 to get 32


x+=+%28-2+%2B-+sqrt%28+-28+%29%29%2F%282%28-1%29%29 Subtract 32 from 4 to get -28


x+=+%28-2+%2B-+sqrt%28+-28+%29%29%2F%28-2%29 Multiply 2 and -1 to get -2.


x+=+%28-2+%2B-+2i%2Asqrt%287%29%29%2F%28-2%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x+=+%28-2%29%2F%28-2%29+%2B-+%282i%2Asqrt%287%29%29%2F%28-2%29 Break up the fraction.


x+=+1+%2B-+-1sqrt%287%29%2Ai Reduce.


x+=+1-1sqrt%287%29%2Ai or x+=+1%2B1sqrt%287%29%2Ai Break up the expression.


So our answers are x+=+1-1sqrt%287%29%2Ai or x+=+1%2B1sqrt%287%29%2Ai


which approximate to x=-1.646%2Ai or x=3.646%2Ai


Equations/145054: Can you explain how to figure this problem (6±√8)/2 and provide answer ?
Thank You.
1 solutions

Answer 105745 by jim_thompson5910(28476) About Me  on 2008-06-11 20:45:11 (Show Source):
You can put this solution on YOUR website!
Start with the given expression



Simplify sqrt%288%29 to get 2%2Asqrt%282%29


or Break up the expression


or Break up the fraction for each case


or Reduce


logarithm/145032: Express both in terms of x
1. ln(x) = 2
what I thought was x = e^2 but that seemed too simple
2. tan^-1 x = 1

1 solutions

Answer 105734 by jim_thompson5910(28476) About Me  on 2008-06-11 18:53:18 (Show Source):
You can put this solution on YOUR website!
1.
You are correct, the answer is x=e%5E2

2.
Start with the given equation


Take the tangent of both sides to eliminate the inverse tangent


Simplify


Polynomials-and-rational-expressions/145030: What is the value of the discriminant of the polynomial below?
4x^2 + 7x + 4
1 solutions

Answer 105732 by jim_thompson5910(28476) About Me  on 2008-06-11 17:15:34 (Show Source):
You can put this solution on YOUR website!

From 4x%5E2%2B7x%2B4 we can see that a=4, b=7, and c=4


D=b%5E2-4ac Start with the discriminant formula


D=%287%29%5E2-4%284%29%284%29 Plug in a=4, b=7, and c=4


D=49-4%284%29%284%29 Square 7 to get 49


D=49-64 Multiply 4%284%29%284%29 to get %2816%29%284%29=64


D=-15 Subtract 64 from 49 to get -15

So the discriminant is D=-15


Equations/145021: I need help with 2 homework problems. I can use any method (elimination, subtitution or graphical methods) the problems are 5x + 6y = 14
-3y + x = 7 I got (35/12, -7/12)

next problem 2x/3 + 3y/4 = 11/12

x/3 + 7y/18 = 1/2



(I got (8/5, -3/35)
1 solutions

Answer 105727 by jim_thompson5910(28476) About Me  on 2008-06-11 15:54:35 (Show Source):
You can put this solution on YOUR website!
# 1





Start with the given system of equations:

system%285x%2B6y=14%2Cx-3y=7%29




1%285x%2B6y%29=1%2814%29 Multiply the top equation (both sides) by 1
-5%28x-3y%29=-5%287%29 Multiply the bottom equation (both sides) by -5




Distribute and multiply

5x%2B6y=14
-5x%2B15y=-35


Now add the equations together. In order to add 2 equations, group like terms and combine them

%285x-5x%29%2B%286y%2B15y%29=14-35

Combine like terms and simplify



cross%285x-5x%29%2B21y=-21 Notice how the x terms cancel out




21y=-21 Simplify




y=-21%2F21 Divide both sides by 21 to isolate y




y=-1 Reduce



Now plug this answer into the top equation 5x%2B6y=14 to solve for x

5x%2B6y=14 Start with the first equation



5x%2B6%28-1%29=14 Plug in y=-1




5x-6=14 Multiply



5x=14%2B6Add 6 to both sides


5x=20 Combine like terms on the right side


x=%2820%29%2F%285%29 Divide both sides by 5 to isolate x



x=4 Divide




So our answer is
x=4 and y=-1



which also looks like




Now let's graph the two equations (if you need help with graphing, check out this solver)


From the graph, we can see that the two equations intersect at . This visually verifies our answer.




graph of 5x%2B6y=14 (red) and x-3y=7 (green) and the intersection of the lines (blue circle).













# 2




Let's look at the first equation 2x%2F3%2B3y%2F4=11%2F12


12%282x%2Fcross%283%29%2B3y%2Fcross%284%29%29=12%2811%2Fcross%2812%29%29 Multiply both sides of the first equation by the LCD 12


8x%2B9y=11 Distribute


---------


Let's look at the second equation x%2F3%2B7y%2F18=1%2F2

18%28x%2Fcross%283%29%2B7y%2Fcross%2818%29%29=18%281%2Fcross%282%29%29 Multiply both sides of the second equation by the LCD 18


6x%2B7y=9 Distribute


---------



So our new system of equations is:


system%288x%2B9y=11%2C6x%2B7y=9%29




3%288x%2B9y%29=3%2811%29 Multiply the top equation (both sides) by 3
-4%286x%2B7y%29=-4%289%29 Multiply the bottom equation (both sides) by -4




Distribute and multiply

24x%2B27y=33
-24x-28y=-36


Now add the equations together. In order to add 2 equations, group like terms and combine them

%2824x-24x%29%2B%2827y-28y%29=33-36

Combine like terms and simplify



cross%2824x-24x%29-y=-3 Notice how the x terms cancel out




-y=-3 Simplify




y=-3%2F-1 Divide both sides by -1 to isolate y




y=3 Reduce



Now plug this answer into the top equation 8x%2B9y=11 to solve for x

8x%2B9y=11 Start with the first equation



8x%2B9%283%29=11 Plug in y=3




8x%2B27=11 Multiply



8x=11-27Subtract 27 from both sides


8x=-16 Combine like terms on the right side


x=%28-16%29%2F%288%29 Divide both sides by 8 to isolate x



x=-2 Divide




So our answer is
x=-2 and y=3



which also looks like



Equations/145018: express each equation in slope-intercept form. then determin, without silving the system, whether the system of equations has exactly one solution, none, or an infinite number
4x+6y=26
-6x-9y=-39
1 solutions

Answer 105724 by jim_thompson5910(28476) About Me  on 2008-06-11 15:37:25 (Show Source):
You can put this solution on YOUR website!

4x%2B6y=26 Start with the first equation


6y=26-4x Subtract 4+x from both sides


6y=-4x%2B26 Rearrange the equation


y=%28-4x%2B26%29%2F%286%29 Divide both sides by 6


y=%28-4%2F6%29x%2B%2826%29%2F%286%29 Break up the fraction


y=%28-2%2F3%29x%2B13%2F3 Reduce



So the equation is now in slope-intercept form (y=mx%2Bb) where the slope is m=-2%2F3 and the y-intercept is b=13%2F3



----------------------------------------------





-6x-9y=-39 Move onto the second equation


-9y=-39%2B6x Add 6+x to both sides


-9y=%2B6x-39 Rearrange the equation


y=%28%2B6x-39%29%2F%28-9%29 Divide both sides by -9


y=%28%2B6%2F-9%29x%2B%28-39%29%2F%28-9%29 Break up the fraction


y=%28-2%2F3%29x%2B13%2F3 Reduce



So the equation is now in slope-intercept form (y=mx%2Bb) where the slope is m=-2%2F3 and the y-intercept is b=13%2F3



------------------------------

Since the slope and y-intercept for both equations are the same, this means that there are an infinite number of solutions (since one equation lies on top of the other)


real-numbers/145005: How many real solutions are there to the equation shown below?
x^2 + 3x + 10 = 0
1 solutions

Answer 105703 by jim_thompson5910(28476) About Me  on 2008-06-11 14:34:56 (Show Source):
You can put this solution on YOUR website!

From x%5E2%2B3x%2B10 we can see that a=1, b=3, and c=10


D=b%5E2-4ac Start with the discriminant formula


D=%283%29%5E2-4%281%29%2810%29 Plug in a=1, b=3, and c=10


D=9-4%281%29%2810%29 Square 3 to get 9


D=9-40 Multiply 4%281%29%2810%29 to get %284%29%2810%29=40


D=-31 Subtract 40 from 9 to get -31


Since the discriminant is less than zero, this means that there are two complex solutions. In other words, there are no real solutions.


Polynomials-and-rational-expressions/145003: What is the value of the discriminant of the polynomial below?
4x^2 + 7x + 4
1 solutions

Answer 105702 by jim_thompson5910(28476) About Me  on 2008-06-11 14:33:57 (Show Source):
You can put this solution on YOUR website!
From 4x%5E2%2B7x%2B4 we can see that a=4, b=7, and c=4


D=b%5E2-4ac Start with the discriminant formula


D=%287%29%5E2-4%284%29%284%29 Plug in a=4, b=7, and c=4


D=49-4%284%29%284%29 Square 7 to get 49


D=49-64 Multiply 4%284%29%284%29 to get %2816%29%284%29=64


D=-15 Subtract 64 from 49 to get -15

So the discriminant is D=-15


Quadratic_Equations/145001: Use the quadratic formula to find the solutions to the quadratic equation below. Check all that apply.
3x^2 - x - 2 = 0
A. - 2/3 (both are negative)
B. -1
C. 3/2
D. -4/5 (only 4 is negative)
E. 1
F. 5/4

1 solutions

Answer 105695 by jim_thompson5910(28476) About Me  on 2008-06-11 14:17:48 (Show Source):
You can put this solution on YOUR website!

Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%283%29%28-2%29+%29%29%2F%282%283%29%29 Plug in a=3, b=-1, and c=-2


x+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%283%29%28-2%29+%29%29%2F%282%283%29%29 Negate -1 to get 1.


x+=+%281+%2B-+sqrt%28+1-4%283%29%28-2%29+%29%29%2F%282%283%29%29 Square -1 to get 1.


x+=+%281+%2B-+sqrt%28+1--24+%29%29%2F%282%283%29%29 Multiply 4%283%29%28-2%29 to get -24


x+=+%281+%2B-+sqrt%28+1%2B24+%29%29%2F%282%283%29%29 Rewrite sqrt%281--24%29 as sqrt%281%2B24%29


x+=+%281+%2B-+sqrt%28+25+%29%29%2F%282%283%29%29 Add 1 to 24 to get 25


x+=+%281+%2B-+sqrt%28+25+%29%29%2F%286%29 Multiply 2 and 3 to get 6.


x+=+%281+%2B-+5%29%2F%286%29 Take the square root of 25 to get 5.


x+=+%281+%2B+5%29%2F%286%29 or x+=+%281+-+5%29%2F%286%29 Break up the expression.


x+=+%286%29%2F%286%29 or x+=++%28-4%29%2F%286%29 Combine like terms.


x+=+1 or x+=+-2%2F3 Simplify.


So our answers are x+=+1 or x+=+-2%2F3



Quadratic-relations-and-conic-sections/144994: The vertex of the parabola below is at the point (1, 3) and the point (2, 6) is on the parabola. What is the equation of the parabola?
i had gotten y = 6(x - 1)^2 + 3 but it came out wrong.
these are the other options
A. y = 3(x + 1)^2 - 3
C. y = 3(x - 1)^2 + 3
D. x = 2(y - 3)^2 + 1


1 solutions

Answer 105679 by jim_thompson5910(28476) About Me  on 2008-06-11 13:35:12 (Show Source):
You can put this solution on YOUR website!
Since the vertex is (1,3) this means y=a%28x-1%29%5E2%2B3


6=a%282-1%29%5E2%2B3 Now plug in x=2 and y=6


6=a%281%29%5E2%2B3 Subtract


6=a%281%29%2B3 Square 1 to get 1


6=a%2B3 Multiply


3=a Subtract 3 from both sides


So the equation is y=3%28x-1%29%5E2%2B3 which means that the answer is choice C)


Quadratic-relations-and-conic-sections/144993: What is the x-coordinate of the center of the ellipse with the following equation?
(y+6)^2/18+(x-5)^2/4=5

1 solutions

Answer 105674 by jim_thompson5910(28476) About Me  on 2008-06-11 13:20:57 (Show Source):
You can put this solution on YOUR website!
%28y%2B6%29%5E2%2F18%2B%28x-5%29%5E2%2F4=5 Start with the given equation


%28x-5%29%5E2%2F4%2B%28y%2B6%29%5E2%2F18=5 Rearrange the terms


%28x-5%29%5E2%2F20%2B%28y%2B6%29%5E2%2F90=1 Divide both sides by 5



So the equation is in the form %28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1 where h=5, k=-6, a=2%2Asqrt%285%29, and b=3%2Asqrt%2810%29


Since the x-coordinate of the center is x=h this means that the x-coordinate of the center is x=5


Polynomials-and-rational-expressions/144991: The polynomial (x - 2) is a factor of the polynomial F(x) = 3x^2 - 8x + 2.
True or false
1 solutions

Answer 105671 by jim_thompson5910(28476) About Me  on 2008-06-11 13:14:10 (Show Source):
You can put this solution on YOUR website!
First let's factor 3x%5E2-8x%2B2





Looking at 3x%5E2-8x%2B2 we can see that the first term is 3x%5E2 and the last term is 2 where the coefficients are 3 and 2 respectively.

Now multiply the first coefficient 3 and the last coefficient 2 to get 6. Now what two numbers multiply to 6 and add to the middle coefficient -8? Let's list all of the factors of 6:



Factors of 6:
1,2,3,6

-1,-2,-3,-6 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 6
1*6
2*3
(-1)*(-6)
(-2)*(-3)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to -8? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -8

First NumberSecond NumberSum
161+6=7
232+3=5
-1-6-1+(-6)=-7
-2-3-2+(-3)=-5

None of these pairs of factors add to -8. So the expression 3x%5E2-8x%2B2 cannot be factored




So (x - 2) is NOT a factor of 3x%5E2-8x%2B2


So the statement is false


Functions/144988: Which of these equations represent functions? Check all that apply.
A. y = (x - 2)^2 + 5
B. x^2 - 4y^2 = 1
C. y = 3x - 3
D. y = 4x^5

1 solutions

Answer 105670 by jim_thompson5910(28476) About Me  on 2008-06-11 13:12:12 (Show Source):
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Choices A,C, and D are all functions. If you graph each one, you'll notice that they all pass the vertical line test


Distributive-associative-commutative-properties/144984: Not sure how to solve:
3x^2-x=0
1 solutions

Answer 105665 by jim_thompson5910(28476) About Me  on 2008-06-11 12:59:28 (Show Source):
You can put this solution on YOUR website!

3x%5E2-x=0 Start with the given equation

x%283x-1%29=0 Factor the left side


Now set each factor equal to zero:
x=0 or 3x-1=0

x=0 or x=1%2F3 Now solve for x in each case


So our answers are

x=0 or x=1%2F3


Notice if we graph y=3x%5E2-x we can see that the roots are x=0 and x=1%2F3 . So this visually verifies our answer.


+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+3x%5E2-x%29+


Quadratic_Equations/144981: The sum of two numbers is 8. The sum of the squares of the two numbers is 34. Find the numbers.
I know they are 3 and 5, but how do I show I arrived at that answer
1 solutions

Answer 105655 by jim_thompson5910(28476) About Me  on 2008-06-11 12:26:08 (Show Source):
You can put this solution on YOUR website!
"The sum of two numbers is 8" translates to x%2By=8


"The sum of the squares of the two numbers is 34" translates to x%5E2%2By%5E2=34


x%2By=8 Start with the first equation


y=8-x Subtract x from both sides to isolate y


x%5E2%2By%5E2=34 Move onto the second equation


x%5E2%2B%288-x%29%5E2=34 Plug in y=8-x


x%5E2%2B64-16x%2Bx%5E2=34 Foil


x%5E2%2B64-16x%2Bx%5E2-34=0 Get all terms to the left side.


2x%5E2-16x%2B30=0 Combine like terms.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=2, b=-16, and c=30


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%28-16%29+%2B-+sqrt%28+%28-16%29%5E2-4%282%29%2830%29+%29%29%2F%282%282%29%29 Plug in a=2, b=-16, and c=30


x+=+%2816+%2B-+sqrt%28+%28-16%29%5E2-4%282%29%2830%29+%29%29%2F%282%282%29%29 Negate -16 to get 16.


x+=+%2816+%2B-+sqrt%28+256-4%282%29%2830%29+%29%29%2F%282%282%29%29 Square -16 to get 256.


x+=+%2816+%2B-+sqrt%28+256-240+%29%29%2F%282%282%29%29 Multiply 4%282%29%2830%29 to get 240


x+=+%2816+%2B-+sqrt%28+16+%29%29%2F%282%282%29%29 Subtract 240 from 256 to get 16


x+=+%2816+%2B-+sqrt%28+16+%29%29%2F%284%29 Multiply 2 and 2 to get 4.


x+=+%2816+%2B-+4%29%2F%284%29 Take the square root of 16 to get 4.


x+=+%2816+%2B+4%29%2F%284%29 or x+=+%2816+-+4%29%2F%284%29 Break up the expression.


x+=+%2820%29%2F%284%29 or x+=++%2812%29%2F%284%29 Combine like terms.


x+=+5 or x+=+3 Simplify.


So our answers are x+=+5 or x+=+3


Polynomials-and-rational-expressions/144979: Which term prevents the following expression from being considered polynomial?
F(x)= 1/√2 x^4-1/√5 x^3-7x^-2+1.4x+21

A. -7x-2
B. 1/√2 x^4
C. -1/√5 x^3
D. 1.4x
E. 21

1 solutions

Answer 105654 by jim_thompson5910(28476) About Me  on 2008-06-11 12:11:40 (Show Source):
You can put this solution on YOUR website!
Notice how 7x%5E%28-2%29=7%2Fx%5E2. Since there is a division by a variable, this means that the expression is not a polynomial. So the answer is A)


Distributive-associative-commutative-properties/144978: This question is from textbook Elementary and Intermediate Algebra for College Students
how do you solve?
4x^2-16=0
1 solutions

Answer 105653 by jim_thompson5910(28476) About Me  on 2008-06-11 12:10:20 (Show Source):
You can put this solution on YOUR website!

4x%5E2-16=0 Start with the given equation


4%28x%5E2-4%29=0 Factor out the GCF 4


4%28x%2B2%29%28x-2%29=0 Factor the left side using the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29


Now set each factor equal to zero:

x%2B2=0 or x-2=0

x=-2 or x=2 Now solve for x in each case


So our answers are

x=-2 or x=2


Notice if we graph y=4x%5E2-16 we can see that the roots are x=-2 and x=2 . So this visually verifies our answer.


+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+4x%5E2-16%29+


Distributive-associative-commutative-properties/144977: This question is from textbook Elementary and Intermediate Algebra for College Students
how do you solve?
4x^2-16=0
1 solutions

Answer 105652 by jim_thompson5910(28476) About Me  on 2008-06-11 12:09:19 (Show Source):
You can put this solution on YOUR website!

4x%5E2-16=0 Start with the given equation


4%28x%5E2-4%29=0 Factor out the GCF 4


4%28x%2B2%29%28x-2%29=0 Factor the left side using the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29


Now set each factor equal to zero:

x%2B2=0 or x-2=0

x=-2 or x=2 Now solve for x in each case


So our answers are

x=-2 or x=2


Notice if we graph y=4x%5E2-16 we can see that the roots are x=-2 and x=2 . So this visually verifies our answer.


+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C0%2C+4x%5E2-16%29+


Distributive-associative-commutative-properties/144974: This question is from textbook Elementary and Intermediate Algebra for college students
How do i solve this:
Factor:
a^2+a+3a+3
1 solutions

Answer 105651 by jim_thompson5910(28476) About Me  on 2008-06-11 11:49:41 (Show Source):
You can put this solution on YOUR website!

a%5E2%2Ba%2B3a%2B3 Start with the given expression

%28a%5E2%2Ba%29%2B%283a%2B3%29 Group like terms


a%28a%2B1%29%2B3%28a%2B1%29 Factor out the GCF a out of the first group. Factor out the GCF 3 out of the second group


%28a%2B3%29%28a%2B1%29 Since we have the common term a%2B1, we can combine like terms

So a%5E2%2Ba%2B3a%2B3 factors to %28a%2B3%29%28a%2B1%29


Polynomials-and-rational-expressions/144973: For the polynomial below, find F(4).
F(x) = 2x^3 - x^2 - 4x + 9
1 solutions

Answer 105650 by jim_thompson5910(28476) About Me  on 2008-06-11 11:48:12 (Show Source):
You can put this solution on YOUR website!

f%28x%29=2x%5E3-x%5E2-4x%2B9 Start with the given function


f%284%29=2%284%29%5E3-%284%29%5E2-4%284%29%2B9 Plug in x=4


f%284%29=2%2A64-4%5E2-4%2A4%2B9 Raise 4 to the 3rd power to get 64


f%284%29=128-4%5E2-4%2A4%2B9 Multiply 2 and 64 to get 128


f%284%29=128-16-4%2A4%2B9 Raise 4 to the 2nd power to get 16


f%284%29=112-4%2A4%2B9 Subtract 16 from 128 to get 112


f%284%29=112-16%2B9 Multiply 4 and 4 to get 16


f%284%29=96%2B9 Subtract 16 from 112 to get 96


f%284%29=105 Add 96 and 9 to get 105





Systems-of-equations/144943: Hi I am having a problem solving this any help would be appreciated thank you in advance.
I have to find the solution to the system of equations by the substitution method.
this is my problem:
#2 x=4- 4y
-x +2y = 2
1 solutions

Answer 105647 by jim_thompson5910(28476) About Me  on 2008-06-11 11:27:36 (Show Source):
You can put this solution on YOUR website!
Start with the given system
-x%2B2y=2
x=4-4y



-%284-4y%29%2B2y=2 Plug in x=4-4y into the first equation. In other words, replace each x with 4-4y. Notice we've eliminated the x variables. So we now have a simple equation with one unknown.


-4%2B4y%2B2y=2 Distribute


6y-4=2 Combine like terms on the left side


6y=2%2B4Add 4 to both sides


6y=6 Combine like terms on the right side


y=%286%29%2F%286%29 Divide both sides by 6 to isolate y



y=1 Divide




Now that we know that y=1, we can plug this into x=4-4y to find x



x=4-4%281%29 Substitute 1 for each y


x=0 Simplify


So our answer is x=0 and y=1 which also looks like



Notice if we graph the two equations, we can see that their intersection is at . So this verifies our answer.


+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+%282%2Bx%29%2F2%2C+%28x-4%29%2F%28-4%29%29+ Graph of -x%2B2y=2 (red) and x=4-4y (green)


Systems-of-equations/144944: This question is from textbook Toby Slater beginning Algebra
Hi I am having a problem solving this any help would be appreciated thank you in advance.
I have to find the solution to the system of equations by the substitution method.
this is my problem:
#2 x=4- 4y
-x +2y = 2
1 solutions

Answer 105646 by jim_thompson5910(28476) About Me  on 2008-06-11 11:26:07 (Show Source):
You can put this solution on YOUR website!

Start with the given system
-x%2B2y=2
x=4-4y



-%284-4y%29%2B2y=2 Plug in x=4-4y into the first equation. In other words, replace each x with 4-4y. Notice we've eliminated the x variables. So we now have a simple equation with one unknown.


-4%2B4y%2B2y=2 Distribute


6y-4=2 Combine like terms on the left side


6y=2%2B4Add 4 to both sides


6y=6 Combine like terms on the right side


y=%286%29%2F%286%29 Divide both sides by 6 to isolate y



y=1 Divide




Now that we know that y=1, we can plug this into x=4-4y to find x



x=4-4%281%29 Substitute 1 for each y


x=0 Simplify


So our answer is x=0 and y=1 which also looks like



Notice if we graph the two equations, we can see that their intersection is at . So this verifies our answer.


+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+%282%2Bx%29%2F2%2C+%28x-4%29%2F%28-4%29%29+ Graph of -x%2B2y=2 (red) and x=4-4y (green)


Sequences-and-series/144841: The sum of the first 6 multiples of 8 , starting with 8 ,is
1 solutions

Answer 105537 by jim_thompson5910(28476) About Me  on 2008-06-10 14:03:47 (Show Source):
You can put this solution on YOUR website!
8+16+24+32+40+48=168


Equations/144834: Simplify the expression.Write the answer in scientific notation.


(1.9 x 10^5)^3

1 solutions

Answer 105534 by jim_thompson5910(28476) About Me  on 2008-06-10 14:00:53 (Show Source):


Linear_Algebra/144840: Hello name is susan,
will you help me understand this problem solve for k,
t=3k +3u


1 solutions

Answer 105532 by jim_thompson5910(28476) About Me  on 2008-06-10 13:58:15 (Show Source):
You can put this solution on YOUR website!
t=3k%2B3u Start with the given equation



0=3k%2B3u-tSubtract t from both sides


-3k=3u-t Subtract 3k from both sides


k=%283u-t%29%2F%28-3%29 Divide both sides by -3 to isolate k



k=%28-3u%2Bt%29%2F%283%29 Simplify


--------------------------------------------------------------
Answer:
So our answer is k=%28-3u%2Bt%29%2F%283%29