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Is the degree of the polynomial odd or even?
Is the leading coefficient of the polynomial positive or negative?
Number of zeros?
1 solutions
Answer 108760 by jim_thompson5910(28598) on 2008-07-15 18:08:20 (Show Source):
You can put this solution on YOUR website!# 26
First let's plot the points
Now let's draw a quadratic through these points (let me know if any other type of polynomial needs to be drawn otherwise)
If you need the equation of the quadratic, simply set up the system of equations
note: let me know if you need help with the setup
Now use either your graphing calculator or other software to solve for "a","b", and "c" simultaneously through the use of matrices. The solution that I get is
a = 1.04, b = -1.92 and c = -4
So the equation that goes through these points is
Is the degree of the polynomial odd or even?
Notice how as x approaches negative infinity (ie x goes to the left), then y approaches infinity. Also as x approaches positive infinity (ie x goes to the right), then y approaches infinity. So this tells us that the degree of the polynomial is even. Also, from the equation  , we can see that the degree is 2, which is even.
Is the leading coefficient of the polynomial positive or negative?
Since the parabola is opening upward, this means that the leading coefficient is positive. Also, since the leading coefficient is 1.04, this also tells us that the leading coefficient is positive.
Number of zeros?
From the graph, we can see that there are two zeros. Also, if you use the quadratic equation on  , you'll find that the polynomial has 2 zeros.
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Graphs/148406: (-1,2) (0,0)(1,-2) Form an equation from these plots and answer the same questions above:
Is the degree of the polynomial odd or even?
Is the leading coefficient of the polynomial positive or negative?
Number of zeros?
1 solutions
Answer 108759 by jim_thompson5910(28598) on 2008-07-15 18:07:15 (Show Source):
You can put this solution on YOUR website!If we plot the points we get
Now draw a curve through these points to get the equation:
Now if we find the equation of the line through those points, we get the equation
note: let me know if you need help with finding the equation of the line.
Is the degree of the polynomial odd or even?
The degree is odd since one end of the polynomial goes in the positive y direction and the other end goes in the negative y direction.
Is the leading coefficient of the polynomial positive or negative?
Since the leading coefficient is -2, this means that the leading coefficient is negative.
Number of zeros?
From the graph, we can see that there is only one zero
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Graphs/148405: 24. From the list of plotted points
(-5,5) (3,5)
(-4, 3/2) (2, 3/2)
(-3,-1) (1,-1)
(-2, -5/2) (0, -5/2)
(-1,-3)
Form an equation after plotting these points and then answer the questions below:
Is the degree of the polynomial odd or even?
Is the leading coefficient of the polynomial positive or negative?
Number of zeros
1 solutions
Answer 108758 by jim_thompson5910(28598) on 2008-07-15 18:05:43 (Show Source):
You can put this solution on YOUR website!If we plot the points we get
Now draw a curve through these points to get the equation:
From the graph, we can see that the degree is even (since both ends of the graph go in the same y direction). Also, we can see that the leading coefficient is positive (since the graph opens upward). Finally, we can see that there are two zeros (since there are two x-intercepts).
------------------------------------------------------
Since we have all of this info, we don't need the equation. However, if you do need the equation, this is how you would find it:
From the graph, we can see that the vertex is (-1,-3).
 Start with the general vertex equation.
 Plug in  and
 Simplify.
Now let's plug in another point. Let's plug in (1,-1)
 Plug in  and
 Add
 Square 2 to get 4.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
So this means that the equation is
 FOIL
 Distribute
 Multiply
 Combine like terms.
So the equation that goes through the points is
From the equation, we can see that the degree of the polynomial is even. Also, we can see that the leading coefficient is positive since  . Finally, if we use the quadratic formula, we'll find that the polynomial  has 2 zeros.
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Equations/148310: 3x + 4 = 4x -5
3x +4-4= 4x-5-4
3x=4x-1
3x=4x-1
3 = 3
3x=3x
3 =3
x=3
I know i'm doing somthing wrong. I think i miss a step.
1 solutions
Answer 108709 by jim_thompson5910(28598) on 2008-07-15 00:15:47 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the answer is
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Rational-functions/148307: Write in standard form: (3-2i)^2 1 solutions
Answer 108706 by jim_thompson5910(28598) on 2008-07-14 23:59:23 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Expand. Remember something like  .
Now let's FOIL the expression.
Remember, when you FOIL an expression, you follow this procedure:
 Multiply the First terms:  .
 Multiply the Outer terms:  .
 Multiply the Inner terms:  .
 Multiply the Last terms:  .
 Now collect every term to make a single expression.
 Now combine like terms.
Now the number is in standard form a+bi where a=5 and b=-12
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Rational-functions/148299: (22 pts) Consider the polynomial f(x) = 2x^3 – 3x^2 – 8x – 3.
(i) By using the Rational Zero Theorem, list all possible rational zeros of the given polynomial.
(ii) Find all of the zeros of the given polynomial. Be sure to show work, explaining how you have found them.
1 solutions
Answer 108699 by jim_thompson5910(28598) on 2008-07-14 23:30:26 (Show Source):
You can put this solution on YOUR website!i)
Any rational zero can be found through this equation
 where p and q are the factors of the last and first coefficients
So let's list the factors of -3 (the last coefficient):
Now let's list the factors of 2 (the first coefficient):
Now let's divide each factor of the last coefficient by each factor of the first coefficient
Now simplify
These are all the distinct rational zeros of the function that could occur
--------------------------------------------------------
ii)
With the help of a graphing calculator, we see that -1 is a zero of
note: let me know if you need to find the zeros a different way.
So let's set up a synthetic division table by placing the value -1 in the upper left corner and placing the coefficients of the polynomial to the right of -1.
Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 2)
Multiply -1 by 2 and place the product (which is -2) right underneath the second coefficient (which is -3)
Add -2 and -3 to get -5. Place the sum right underneath -2.
Multiply -1 by -5 and place the product (which is 5) right underneath the third coefficient (which is -8)
Add 5 and -8 to get -3. Place the sum right underneath 5.
Multiply -1 by -3 and place the product (which is 3) right underneath the fourth coefficient (which is -3)
Add 3 and -3 to get 0. Place the sum right underneath 3.
Since the last column adds to zero, this means that -1 is a zero of  (this confirms our original claim).
Now lets look at the bottom row of coefficients:
The first 3 coefficients (2,-5,-3) form the quotient
So
Basically  factors to
Now lets find the zeros for  .
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the zeros of  are  ,  , or
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Rational-functions/148297: Use synthetic division to divide the polynomial 2x^3 – 7x + 10 by x + 3, and write the quotient polynomial and the remainder. 1 solutions
Answer 108698 by jim_thompson5910(28598) on 2008-07-14 23:17:30 (Show Source):
You can put this solution on YOUR website!
Let's simplify this expression using synthetic division
Start with the given expression
First lets find our test zero:
 Set the denominator  equal to zero
 Solve for x.
so our test zero is -3
Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.(note: remember if a polynomial goes from  to  there is a zero coefficient for  . This is simply because  really looks like
Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 2)
Multiply -3 by 2 and place the product (which is -6) right underneath the second coefficient (which is 0)
Add -6 and 0 to get -6. Place the sum right underneath -6.
Multiply -3 by -6 and place the product (which is 18) right underneath the third coefficient (which is -7)
Add 18 and -7 to get 11. Place the sum right underneath 18.
Multiply -3 by 11 and place the product (which is -33) right underneath the fourth coefficient (which is 10)
Add -33 and 10 to get -23. Place the sum right underneath -33.
| -3 | | | 2 | 0 | -7 | 10 | | | | | -6 | 18 | -33 | | | | 2 | -6 | 11 | -23 |
Since the last column adds to -23, we have a remainder of -23. This means  is not a factor of
Now lets look at the bottom row of coefficients:
The first 3 coefficients (2,-6,11) form the quotient
and the last coefficient -23, is the remainder, which is placed over  like this
Putting this altogether, we get:
So
which looks like this in remainder form:
 remainder -23
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Functions/148258: John increased the area of his garden by 120 ft^2. The original garden was 12 ft. by 14 ft., and he increased the length and the width by the same amount. Find the exact dimensions of the new garden and approximate the dimensions in feet and inches. 1 solutions
Answer 108657 by jim_thompson5910(28598) on 2008-07-14 16:41:14 (Show Source):
You can put this solution on YOUR website!Let x=amount he increased the dimensions of his garden,  =area of original garden and  =area of new garden
Since the original garden is 12 ft by 14 ft, this means that the area of the original garden is
So  which means that the area of the original garden is 168 ft^2
Because the area of the new garden is 120 ft^2 larger than the original garden, this means that
 Plug in
 Add
So the area of the new garden is 288 ft^2
Now since he increased the dimensions by some unknown amount, this means that the area of the new garden is equal to:
 Plug in
 FOIL
 Subtract 288 from both sides.
 Combine and rearrange the terms.
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the possible answers are  or
However, since a negative length is not possible, this means that he increased his garden by 4 feet.
Now simply add 4 to each dimension 12 and 14 to get:
12+4=16 by 14+4=18
So the dimensions of the new garden are
16 ft by 18 ft
note: the approximate answers are the same as the exact answers since there are no square roots, fractions, decimals, etc. in the answer
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Functions/148253: The velocity of sound is given by . Find the temperature when the velocity is 348 m/s 1 solutions
Answer 108651 by jim_thompson5910(28598) on 2008-07-14 16:24:34 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Plug in
 Divide both sides by 20.
 Square both sides.
 Square 17.4 to get 302.6
 Divide both sides by 273.
 Take the 6th root of both sides to isolate t.
 Take the 6th root of 1.10842 to get 1.0173
 Now round to the nearest degree
So when the temperature is 1 degree Celcius, then the approximate velocity of sound is 348 meters per second
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Equations/148216: Which of the following cannot be a base for exponential and logarithmic functions?
0.1
π
1
e
1 solutions
Answer 108621 by jim_thompson5910(28598) on 2008-07-14 12:43:18 (Show Source):
You can put this solution on YOUR website!The previous solution is correct, but there's more to this solution. Let's say that you could have a base of 1. So this means that  can be written as  by use of the property  ===>
Now using the change of base formula, we can rewrite  as  . However,  which means that  becomes  . Since you cannot divide by zero, this means that a base of 1 is not possible for a logarithmic function.
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Exponential-and-logarithmic-functions/148215: Determine x for 10^2x + 1 = 1000^x - 1
a. x = -2
b. x = 4
c. x = 9
d. No solution
1 solutions
Answer 108614 by jim_thompson5910(28598) on 2008-07-14 12:30:33 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Rewrite 1000 as
 Multiply the exponents.
 Distribute.
 Since the bases are equal, this means that the exponents are equal.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the answer is
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Graphs/148210: IN NEED OF HELP. I CANT SEEM TO GET THESE CAN ANYONE HELP? FIND THE SLOPE AND y-INTERCEPT OF THE GIVEN LINE. 1. 5y-2x+8=0 A. m = B. y-intercept 2. x=-9 A. m = B. y-intercept 3. 2x-7y=8 A. m = y-intercept D.y=5 A. m= B. y-intercept 1 solutions
Answer 108612 by jim_thompson5910(28598) on 2008-07-14 12:27:34 (Show Source):
You can put this solution on YOUR website!I'll do the first two to get you started.
# 1
 Start with the given equation.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Break up the fraction.
Now the equation is in slope intercept form  where the slope is  and the y-intercept is
# 2
Since the equation x=-9 is not in slope intercept form, this means that the slope is undefined and there is no y-intercept (the line is parallel to the y-axis).
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Equations/148209: What is the domain of standard exponential functions?
a. x (0, ∞)
b. x (-∞, ∞)
c. x [0, ∞)
d. x (0, 1) (1, 2) (2, 3) (3, 4) (4, 5) .....
1 solutions
Answer 108608 by jim_thompson5910(28598) on 2008-07-14 12:19:18 (Show Source):
You can put this solution on YOUR website!If you graph a standard exponential function like  , you get
From the graph, we can see that x can be any number. So the domain is b. x (-∞, ∞)
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Equations/148205: Which of the following represents the numerical solution of: log2((4^2)(2^3)
a. 5
b. 12
c. 7
d. There is no numerical solution; this expression cannot be resolved
1 solutions
Answer 108605 by jim_thompson5910(28598) on 2008-07-14 12:15:52 (Show Source):
You can put this solution on YOUR website! Start with the given expression.
 Rewrite  as
 Multiply the exponents.
 Multiply the terms by adding the exponents.
 Rewrite the expression using the identity  .
 Evaluate  to get 1
 Multiply
So
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Geometry_proofs/148202: Verify the identity.
a)(csc(-t)-sin(-t))/(sin(-t))=cot^(2)t
b)ln cotx= -ln tanx 1 solutions
Answer 108603 by jim_thompson5910(28598) on 2008-07-14 12:12:06 (Show Source):
You can put this solution on YOUR website!a)
Note: I'm only algebraically manipulating the left side. I'm showing the right side for comparison.
(csc(-t)-sin(-t))/(sin(-t))=cot^(2)t ... Start with the given equation
(1/sin(-t)-sin(-t))/(sin(-t))=cot^(2)t .... Replace csc(-t) with 1/sin(-t)
-(-1/sin(t)+sin(t))/(sin(t))=cot^(2)t .... Replace each sin(-t) with -sin(t)
(1/sin(t)-sin(t))/(sin(t))=cot^(2)t .... Simplify
(1/sin(t)-sin^2(t)/sin(t))/(sin(t))=cot^(2)t ... Rewrite sin(t) as sin^2(t)/sin(t)
((1-sin^2(t))/sin(t))/(sin(t))=cot^(2)t ... Combine the fractions in the numerator
((1-sin^2(t))/sin^2(t)=cot^(2)t ... Divide the fractions
(cos^2(t))/sin^2(t)=cot^(2)t ... Replace 1-sin^2(t) with cos^2(t)
cot^2(t)=cot^(2)t .... Replace (cos^2(t))/sin^2(t) with cot^2(t)
So this verifies the identity.
--------------------------------------------------
b)
Note: I'm only algebraically manipulating the left side. I'm showing the right side for comparison.
ln(cot(x))= -ln(tan(x)) ... Start with the given equation.
ln(1/tan(x))= -ln(tan(x)) ... Rewrite cot(x) as 1/tan(x)
ln((tan(x))^(-1))= -ln(tan(x)) ... Rewrite 1/tan(x) as (tan(x))^(-1)
-1*ln(tan(x))= -ln(tan(x)) ... Rewrite the left side using the identity
-ln(tan(x))= -ln(tan(x)) .... Multiply
So this verifies the identity.
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Graphs/148204: solve the inequality 6+3y<4(3-x) for y and graph the solution. Please show me this step by step because I think I went wrong somewhere down the line, and I need to see where. Thanks in advance! 1 solutions
Answer 108601 by jim_thompson5910(28598) on 2008-07-14 12:05:31 (Show Source):
You can put this solution on YOUR website! Start with the given inequality.
 Distribute.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Break up the fraction.
 Reduce
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Answer:
So the answer is
Now let's graph the equation  (replace the inequality sign with an equals sign)
 Graph of
Now plug in a test point (0,0) into the inequality
 Start with the given inequality.
 Plug in  and
 Evaluate and simplify.
Since the inequality is true, this means that we shade the entire region that contains the point (0,0)
In other words, we simply shade the entire region that is below the line.
 Graph of  with the shaded region in green
note: the boundary should be a dotted line.
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Angles/148176: Please try to help me on this question:
If the measure of an angle is (7x-13)degree and the measure of its supplement is (5x-11)degree, find x.
1 solutions
Answer 108599 by jim_thompson5910(28598) on 2008-07-14 11:43:56 (Show Source):
You can put this solution on YOUR website!Since the two angles are supplementary, this means that the two angles add to 180 degrees. So this means that
 Start with the given equation.
 Combine like terms on the left side.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the answer is
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Linear-systems/148199: Write the equation of a line whose slope is 6 and whose y intercept is -3. 1 solutions
Answer 108597 by jim_thompson5910(28598) on 2008-07-14 11:39:12 (Show Source):
You can put this solution on YOUR website!Since the equation has a y intercept of -3, this means that the equation goes through the point (0,-3).
If you want to find the equation of line with a given a slope of  which goes through the point (0,-3), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
 where  is the slope, and ) is the given point
So lets use the Point-Slope Formula to find the equation of the line
 Plug in  ,  , and  (these values are given)
 Rewrite  as
 Distribute
 Multiply  and  to get
 Subtract 3 from both sides to isolate y
 Combine like terms  and  to get
------------------------------------------------------------------------------------------------------------
Answer:
So the equation of the line with a slope of  which goes through the point (0,-3) is:
 which is now in  form where the slope is  and the y-intercept is
Notice if we graph the equation  and plot the point (0,-3), we get (note: if you need help with graphing, check out this solver)
Graph of through the point (0,-3)
and we can see that the point lies on the line. Since we know the equation has a slope of and goes through the point (0,-3), this verifies our answer.
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Graphs/148201: 1. Line j contains the points (-2,3) and (1,5).
a) Determine the slope of the line.---I got that part. slope=2/3
b) Write an equation for the line.
y=2/3x+ ???
I need help right there. 1 solutions
Answer 108595 by jim_thompson5910(28598) on 2008-07-14 11:36:24 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
 Start with the slope formula.
 Plug in  ,  ,  ,  , ,
 Subtract  from  to get
 Subtract  from  to get
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Distribute
 Multiply
 Add 3 to both sides.
 Rewrite  as  .
 Combine the fractions.
So the equation that goes through the points ) and ) is
Notice how the graph of  goes through the points ) and ) . So this visually verifies our answer.
 Graph of  through the points ) and
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