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The instructions say for each function, find f^-1. Help please, step by step. Thank you...
f(x)= 6^x-1
Also, solve each equation. Find the Exact solutions.
1/2^x = 5 the exponent is above the 2 only. 1 solutions
Answer 109646 by jim_thompson5910(28598) on 2008-07-23 17:42:16 (Show Source):
You can put this solution on YOUR website! Start with the given function.
 Switch x and f(x).
 Take the log of both sides.
 Rewrite the right side using the identity
 Distribute
 Add  to both sides.
 Combine the logs using the identity
 Divide both sides by  to isolate f(x)
 Use the change of base formula to rewrite the left side.
So the inverse function is
 Start with the given equation.
 Multiply both sides by  .
 Divide both sides by  .
 Take the log of both sides.
 Rewrite the right side using the identity
 Divide both sides by  to isolate x
 Use the change of base formula to rewrite the left side.
So the answer is  which approximates to
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Graphs/149454: 1)line l goes through (1,3) and is parallel to the line through (4,3) and (-3,1) FInd the slope of l.
the answer I got was 2/7 is this correct?
2)line l goes through the point (5,-2) and is perpendicular to the line through (-2,1)and (-4,-2) Find the slope of l
the answer I got was -3/2 is this correct?
3)Write the equation y=1/3x-2 in standard form using only integers and a positive coefficent for x
The answer I got was x+3y=6 is this correct?
4) A Line that goes through (-1,-3)and has a slope of 4.
My answer is y=4x-3 is this correct? 1 solutions
Answer 109645 by jim_thompson5910(28598) on 2008-07-23 17:29:53 (Show Source):
You can put this solution on YOUR website!1) correct
2) You're on the right track. The slope through (-2,1)and (-4,-2) is 3/2. So flip the fraction and change the sign to get -2/3. So the perpendicular slope is -2/3
3) Close, but you forgot to multiply the term "3y" by negative 1 (since you multiplied the "x" term by -1). So the correct equation is x-3y=6
4)
If you want to find the equation of line with a given a slope of  which goes through the point (  ,  ), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
 where  is the slope, and ) is the given point
So lets use the Point-Slope Formula to find the equation of the line
 Plug in  ,  , and  (these values are given)
 Rewrite  as
 Rewrite  as
 Distribute
 Multiply  and  to get
 Subtract 3 from both sides to isolate y
 Combine like terms  and  to get
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Answer:
So the equation of the line with a slope of  which goes through the point (  ,  ) is:
 which is now in  form where the slope is  and the y-intercept is
Notice if we graph the equation  and plot the point (  ,  ), we get (note: if you need help with graphing, check out this solver)
Graph of through the point ( , )
and we can see that the point lies on the line. Since we know the equation has a slope of and goes through the point ( , ), this verifies our answer.
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Polynomials-and-rational-expressions/149449: If someone can please help me with these problems.I have answered them and want to know if my answers are correct if not how can I successfully answer these questions right......
1)s/6-2/9=0
The answer I came up with is 1/3 is this correct?
2)Solve -43 less than 20 -9v less than or greater to -7
The answer I came up with is (1,7]is this correct?
3)Complete the ordered pair so that it satifies the given equation.
2x-5y=-12:(-1, )
the answer I came up with is (-1,4) is this correct?
4)Find the x and y intercepts of 7x-2y=-5
5)Find the slope of the line that contains the points (-4,-2) and (1,1) 1 solutions
Answer 109637 by jim_thompson5910(28598) on 2008-07-23 16:54:40 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Multiply both sides by the LCD 18 to clear out the fractions.
 Distribute and multiply.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
----------------------------------------------------------------------
Answer:
So the answer is
Which approximates to
2)
 Start with the given compound inequality.
 Subtract  from all sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide all sides by -9. Note: dividing all sides of the inequality will flip the signs
 Reduce.
 Rearrange the inequality.
So the answer in interval notation is [ )
Also, the answer in set-builder notation is
Here's the graph of the solution set
 Graph of the solution set
Note:
There is a closed circle at  which means that we're including this value in the solution set
Also, there is an open circle at  which means that we're excluding this value from the solution set.
3)
 Start with the given equation.
 Plug in  .
 Multiply.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
So the ordered pair is (-1,2)
Note: you can plug in the numbers x=-1 and y=2 into the equation to check your answer.
4)
 Start with the given equation
Let's find the x-intercept
To find the x-intercept, let y=0 and solve for x:
 Plug in
 Simplify
 Divide both sides by 7
So the x-intercept is ) (note: the x-intercept will always have a y-coordinate equal to zero)
------------------
 Start with the given equation
Now let's find the y-intercept
To find the y-intercept, let x=0 and solve for y:
 Plug in
 Simplify
 Divide both sides by -2
 Reduce
So the y-intercept is ) (note: the y-intercept will always have a x-coordinate equal to zero)
------------------------------------------
So we have these intercepts:
x-intercept:
y-intercept:
5)
 Start with the slope formula.
 Plug in  ,  ,  ,  , ,
 Subtract  from  to get
 Subtract  from  to get
So the slope of the line that goes through the points ) and ) is
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Functions/149447: f(x)=8x2-4x-5
for the given function f match each domain value(-1,0,1/2,2) with its corresponding range value.
1 solutions
Answer 109635 by jim_thompson5910(28598) on 2008-07-23 16:45:05 (Show Source):
You can put this solution on YOUR website!With the given domain values are -1,0,1/2, and 2, we can find the corresponding range values by plugging in each value. So I'll do the first one and the third one.
# 1
Let's find the corresponding range value for
 Start with the given equation.
 Plug in  .
 Square  to get  .
 Multiply  and  to get  .
 Multiply  and  to get  .
 Combine like terms.
So with the given domain value of  , the corresponding range value is
-----------------
# 3
Let's find the corresponding range value for
 Start with the given equation.
 Plug in  .
 Square  to get  .
 Multiply  and  to get  .
 Multiply  and  to get  .
 Combine like terms.
So with the given domain value of  , the corresponding range value is
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Trigonometry-basics/149438: Please help me finde the value of cos^-1(0)
Thank you, Natalie 1 solutions
Answer 109628 by jim_thompson5910(28598) on 2008-07-23 16:24:16 (Show Source):
You can put this solution on YOUR website!What ) is asking for is an angle. So this means that ) .
So, let's reference the unit circle
From the picture, we can see that the point (0,1) tells us that  or  (remember, the x coordinate corresponds to cosine).
=0) Start with the given equation.
) Take the inverse cosine of both sides. This will eliminate the "cos" on the left side.
So =90) (in degrees) or =\frac{\pi}{2}) (in radians)
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Sequences-and-series/149402: how do you figure out the nth term of :
21,19,17,15...
please help!!! xxx
1 solutions
Answer 109615 by jim_thompson5910(28598) on 2008-07-23 14:30:19 (Show Source):
You can put this solution on YOUR website!Lets assume this sequence is an arithmetic sequence. The general form of the arithmetic sequence is
 where  is the nth term, d is the difference, and  is the first term
So lets find the difference between 2 terms (i.e. the difference between two terms)
====================================================================================================================
To find the difference, simply pick any term and subtract the previous term from that selected term
 Select the 2nd term (which is 19) and subtract the 1st term (which is 21) from it.
So we get a difference of
Lets pick another pair of terms to verify:
 Select the 3rd term (which is 17) and subtract the 2nd term (which is 19) from it.
And again, we get a difference of
-----------------------------------------------------
Lets pick another pair of terms to verify:
 Select the 4th term (which is 15) and subtract the 3rd term (which is 17) from it.
And again, we get a difference of
-----------------------------------------------------
====================================================================================================================
Since we've tested every consecutive pair of terms, we've verified that the sequence has a constant difference of  . This means the sequence is arithmetic
Since the difference is  and the first term is  , this means the arithmetic sequence is
 where  starts at
Check:
Notice if we plug in  we get
 plug in
 Multiply
 Add
which is our first term
Notice if we plug in  we get
 plug in
 Multiply
 Add
which is our second term
Notice if we plug in  we get
 plug in
 Multiply
 Add
which is our third term
Notice if we plug in  we get
 plug in
 Multiply
 Add
which is our fourth term
Since each term corresponds to the terms of the given list, this verifies our sequence.
------------------------------------------------------------------------------------------------------------------------
Answer:
So the list of numbers 21,19,17,15... can be generated by the sequence
 where  starts at
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logarithm/149398: Solve the exponential or logarithmic equations. (Write your final answer in BOTH exact and approximate value).
(a) 6^x-3 = 2^x
(b) log(5x-6) = 2log x 1 solutions
Answer 109613 by jim_thompson5910(28598) on 2008-07-23 14:25:14 (Show Source):
You can put this solution on YOUR website!I'll do the first one to get you started.
a)
 Start with the given equation.
 Take the log of both sides.
 Rewrite both sides using the identity
 Distribute.
 Subtract  from both sides.
 Add  to both sides.
 Factor out the GCF "x"
 Combine the logs using the identity
 Divide.
 Divide both sides by  to isolate x
 Rewrite the expression using the identity
 Raise 6 to the 3rd power to get 216
 Use the change of base formula to rewrite the right side.
So the exact answer is  which approximates to
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logarithm/149400: Rewrite each expression in exponential form and determine the value of x.
(a) log49 x=1/2
(b) log9 27 = x
1 solutions
Answer 109609 by jim_thompson5910(28598) on 2008-07-23 14:16:03 (Show Source):
You can put this solution on YOUR website!a)
 Start with the given equation.
 Rewrite the equation using the property:  ====>
 Convert from rational notation to radical notation.
 Take the square root of 49 to get 7. Note: only the positive square root is considered in this case.
So the answer is
b)
 Start with the given equation.
 Rewrite the equation using the property:  ====>
 Rewrite  as  and  as
 Multiply the exponents.
 Since the bases are equal, the exponents are equal.
 Divide both sides by 2.
So the answer is
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Quadratic_Equations/149395: What type of solution do you get for quadratic equations where D<0? Give reasons for your answer. Also provide an example of such a quadratic equation and find the solution of the equation. 1 solutions
Answer 109606 by jim_thompson5910(28598) on 2008-07-23 14:09:40 (Show Source):
You can put this solution on YOUR website!If  , then the quadratic will have two complex (ie non real) solutions.
For example, let's find the discriminant for
From  we can see that  ,  , and
 Start with the discriminant formula
 Plug in  ,  , and
 Square  to get
 Multiply  to get
 Subtract  from  to get
Since the discriminant is less than zero, this means that there are two complex solutions
Now let's use the quadratic formula to find the solutions of
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Break up the fraction for each case.
 or  Reduce.
So our answers are  or
Since our answers are complex, this verifies our original claim.
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Quadratic_Equations/149392: Please help with the following word problem:
A stone is thrown upward from a bridge. The stone's height in feet, "h", above the water "t" seconds after the stone is thrown is a function given by h=-16t2 + 32t + 256.
a. How tall is the bridge from which the stone was thrown? My answer is 256 ft.
b. How high above the water is the stone after 3 seconds? My answer is 208 ft.
c. What is the maximum height of the stone? Stuck on this question.
d. After how many seconds does the stone reach the maximum height? Stuck on this question too.
e. How long does it take for the stone to hit the water? My answer is 5.12 seconds.
Please help with questions c and d.
Any help would be greatly appreciated. Thank you. 1 solutions
Answer 109604 by jim_thompson5910(28598) on 2008-07-23 14:05:47 (Show Source):
You can put this solution on YOUR website!a) correct
b) correct
c)
To find the max height, we need to find the vertex.
In order to find the vertex, we first need to find the x-coordinate of the vertex.
To find the x-coordinate of the vertex, use this formula:  .
 Start with the given formula.
From  , we can see that  ,  , and  .
 Plug in  and  .
 Multiply 2 and  to get  .
 Divide.
So the x-coordinate of the vertex is  . Note: this means that the axis of symmetry is also  .
Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.
 Start with the given equation.
 Plug in  .
 Start with the given equation.
 Plug in  .
 Square  to get  .
 Multiply  and  to get  .
 Multiply  and  to get  .
 Combine like terms.
So the y-coordinate of the vertex is  .
So the vertex is ) .
So the highest point on the graph of  is ) .
This means that maximum height of the stone is 272 feet
From the previous solution, the highest point is at the point ) . So when t=1, then h=272. So the stone reaches the highest point at 1 second
e) correct.
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Angles/149389: the measure of angle j is half of its compliment plus 12 degrees 1 solutions
Answer 109602 by jim_thompson5910(28598) on 2008-07-23 13:57:51 (Show Source):
You can put this solution on YOUR website!"measure of angle j is half of its compliment plus 12 degrees" translates to
Also, since angle j and angle c are complementary angles, this means that
 Plug in
 Multiply every term by 2 to clear the fraction.
 Subtract 12 from both sides.
 Combine like terms.
 Divide both sides by 3.
 Go back to the first equation.
 Plug in
 Add
 Multiply.
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Miscellaneous_Word_Problems/149388: Find the multiplicative inverse of the following number: -0.25
1 solutions
Answer 109598 by jim_thompson5910(28598) on 2008-07-23 13:37:16 (Show Source):
You can put this solution on YOUR website!First write -0.25 as the fraction
Now to find the multiplicative inverse, simply flip the fraction to get  or
So the multiplicative inverse of -0.25 is -4
Check:
Simply multiply the two numbers -0.25 and -4 to get
Since their product is 1, this means that -4 is the multiplicative inverse of -0.25 (and vice versa).
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Linear-equations/149380: graph the line and find the slope
(-2,5) (3,0)
find the slope of the line m= 1 solutions
Answer 109587 by jim_thompson5910(28598) on 2008-07-23 11:59:15 (Show Source):
You can put this solution on YOUR website!First graph the points (-2,5) and (3,0)
Now draw a line through those points
Now start at the point (-2,5) and move 5 units down (to get to the same level as the second point). Since we went 5 units down, this means that the rise is -5.
Now move 5 units to the right to get to the next point. Since we went 5 units to the right, this means that the run is 5.
So the rise is -5 and the run is 5. This makes the slope
So the slope between the two points (-2,5) and (3,0) is
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Inequalities/149361: 3-3x>-6 1 solutions
Answer 109586 by jim_thompson5910(28598) on 2008-07-23 11:46:28 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  . note: Remember, the inequality sign flips when we divide both sides by a negative number.
 Reduce.
----------------------------------------------------------------------
Answer:
So the answer is
So the answer in interval notation is
Also, the answer in set-builder notation is
Here's the graph of the solution set
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Linear-equations/149376: 4x + 3y = 12 1 solutions
Answer 109585 by jim_thompson5910(28598) on 2008-07-23 11:43:33 (Show Source):
You can put this solution on YOUR website!Do you want to graph?
 Start with the given equation.
 Subtract  from both sides.
 Divide both sides by  to isolate  .
 Simplify.
Looking at  we can see that the equation is in slope-intercept form  where the slope is  and the y-intercept is
Since  this tells us that the y-intercept is ) .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is  , this means:
which shows us that the rise is -4 and the run is 3. This means that to go from point to point, we can go down 4 and over 3
So starting at ) , go down 4 units
and to the right 3 units to get to the next point
Now draw a line through these points to graph
 So this is the graph of  through the points ) and
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Linear-equations/149331: Solve the following:
Passing through (5,-9) and perpendicular to x + 7y = 12 1 solutions
Answer 109553 by jim_thompson5910(28598) on 2008-07-22 23:11:17 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Subtract x from both sides.
 Divide both sides by 7.
 Break up the fraction and simplify.
We can see that the equation  has a slope  and a y-intercept  .
Now to find the slope of the perpendicular line, simply flip the slope  to get  . Now change the sign to get  . So the perpendicular slope is  .
Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope  and the coordinates of the given point ) .
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Distribute
 Multiply
 Subtract 9 from both sides.
 Combine like terms.
So the equation of the line perpendicular to  that goes through the point ) is  .
Here's a graph to visually verify our answer:
 Graph of the original equation  (red) and the perpendicular line  (green) through the point ) .
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Equations/149304: 5t^-16t=-12
i have tried everything. please help me. I am so greatful for this site and your time. thank you so much. This is factoring equations. 1 solutions
Answer 109532 by jim_thompson5910(28598) on 2008-07-22 20:06:26 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Add 12 to both sides.
Now let's factor the left side
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,5,6,10,12,15,20,30,60
-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*60
2*30
3*20
4*15
5*12
6*10
(-1)*(-60)
(-2)*(-30)
(-3)*(-20)
(-4)*(-15)
(-5)*(-12)
(-6)*(-10)
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 60 | 1+60=61 | | 2 | 30 | 2+30=32 | | 3 | 20 | 3+20=23 | | 4 | 15 | 4+15=19 | | 5 | 12 | 5+12=17 | | 6 | 10 | 6+10=16 | | -1 | -60 | -1+(-60)=-61 | | -2 | -30 | -2+(-30)=-32 | | -3 | -20 | -3+(-20)=-23 | | -4 | -15 | -4+(-15)=-19 | | -5 | -12 | -5+(-12)=-17 | | -6 | -10 | -6+(-10)=-16 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
So  factors to  .
Note: you can check to see if you did it right by FOILing  to get  .
So  becomes  .
Now set each factor equal to zero:
 or
 or  Now solve for t in each case
So our answers are
 or
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Graphs/149240: Solve the inequality  1 solutions
Answer 109486 by jim_thompson5910(28598) on 2008-07-22 14:13:00 (Show Source):
You can put this solution on YOUR website!First, we need to find the vertical asymptote(s)
Vertical Asymptote:
To find the vertical asymptote, just set the denominator equal to zero and solve for x
 Set the denominator equal to zero
 Add 7 to both sides
 Combine like terms on the right side
So the vertical asymptote is
--------------------
Now we need to find any x-intercepts
 Start with the given equation
 Plug in
 Multiply both sides by  .
 Add 4 to both sides.
So the x-intercept is (4,0)
---------------
This means that we'll have to test three regions
Region 1:
This region is from negative infinity to the x-intercept
So let's test the value
 Start with the given equation
 Plug in
 Simplify.
Since  is greater than or equal to zero, this means that every point in the interval ( ] is above the x-axis.
So the interval ( ] is part of the solution to the inequality
-----------
Region 2:
This region is from the x-intercept  to the vertical asymptote
So let's test the value
 Start with the given equation
 Plug in
 Simplify.
Since  is not greater than or equal to zero, this means that every point in the interval ( ) is below the x-axis.
So the interval ( ) is not part of the solution to the inequality
-----------
Region 3:
This region is from the vertical asymptote  to positive infinity
So let's test the value
 Start with the given equation
 Plug in
 Simplify.
Since  is greater than or equal to zero, this means that every point in the interval ( ) is above the x-axis.
So the interval ( ) is part of the solution to the inequality
So that means that the solution is
( ] ( )
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Graphs/149237: Given ,
A) Find the domain.
B) Determine the vertical asymptote(s).
C) Determine the horizontal asymptote or oblique asymptote.
D) Find the y-intercept.
E) Find the x-intercept(s). 1 solutions
Answer 109485 by jim_thompson5910(28598) on 2008-07-22 13:54:55 (Show Source):
You can put this solution on YOUR website!A)
Domain:
 Start with the given function
 Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.
 Factor the left side (note: if you need help with factoring, check out this solver)
Now set each factor equal to zero:
 or
 or  Now solve for x in each case
So our solutions are  or
Since  and  make the denominator equal to zero, this means we must exclude  and  from our domain
So our domain is:
which in plain English reads: x is the set of all real numbers except  or
So our domain looks like this in interval notation
note: remember, the parenthesis excludes -5 and 5 from the domain
--------------------------------------------------
B)
Vertical Asymptote:
To find the vertical asymptote, just set the denominator equal to zero and solve for x
 Set the denominator equal to zero
 Add 25 to both sides
 Combine like terms on the right side
 Take the square root of both sides
 or  Simplify
So the vertical asymptotes are  or
--------------------------------------------------
Looking at the numerator  , we can see that the degree is  since the highest exponent of the numerator is  . For the denominator  , we can see that the degree is  since the highest exponent of the denominator is  .
C)
Horizontal/Oblique Asymptote:
Since the degree of the numerator and the denominator are the same, we can find the horizontal asymptote using this procedure:
To find the horizontal asymptote, first we need to find the leading coefficients of the numerator and the denominator.
Looking at the numerator  , the leading coefficient is
Looking at the denominator  , the leading coefficient is
So the horizontal asymptote is the ratio of the leading coefficients. In other words, simply divide  by  to get
So the horizontal asymptote is
--------------------------------------------------
D)
Y-Intercept:
To find the y-intercept, simply plug in
 Start with the given function
 Plug in
 Simplify
So the y-intercept is
--------------------------------------------------
E)
X-Intercept(s):
To find the x-intercept(s), simply plug in  and solve for x
 Start with the given function
 Plug in
Since the denominator cannot be equal to zero, this means that the numerator is equal to zero.
 Add 18 to both sides.
 Divide both sides by 2.
 or  Take the square root of both sides.
So the x-intercepts are ) and
------------------------------
Notice if we graph  , we can visually verify our answers:
 Graph of  with the horizontal asymptote  (blue line) and the vertical asymptotes  and  (green lines)
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Graphs/149236: Graph  1 solutions
Answer 109484 by jim_thompson5910(28598) on 2008-07-22 13:52:02 (Show Source):
You can put this solution on YOUR website!First, let's find the asymptotes of the equation
Horizontal Asymptote:
Since the degree of the numerator (which is  ) is less than the degree of the denominator (which is  ), the horizontal asymptote is always
So the horizontal asymptote is
--------------------------------------------------
Vertical Asymptote:
To find the vertical asymptote, just set the denominator equal to zero and solve for x
 Set the denominator equal to zero
 Add 4 to both sides
 Combine like terms on the right side
 Take the square root of both sides
 or  Break up the expression and simplify.
So the vertical asymptotes are  or
------------------
Now we need to test each region to see if it lies above or below the x-axis
Region 1:
This region is to the left of the vertical asymptote
So let's plug in
 Start with the given equation.
 Plug in  .
 Simplify.
Since the y-value is negative, this means that every point in the interval ) is below the x-axis.
------
Region 2:
This region lies between the vertical asymptote  and the x-axis
So let's plug in
 Start with the given equation.
 Plug in  .
 Simplify.
Since the y-value is positive, this means that every point in the interval ) is above the x-axis.
------
Region 3:
This region lies between the x-axis  and the vertical asymptote
So let's plug in
 Start with the given equation.
 Plug in  .
 Simplify.
Since the y-value is negative, this means that every point in the interval ) is below the x-axis.
-----------------
Region 3:
This region lies to the right of the vertical asymptote
So let's plug in
 Start with the given equation.
 Plug in  .
 Simplify.
Since the y-value is positive, this means that every point in the interval ) is above the x-axis.
----------------
So with all of this information, we can now graph the function
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Graphs/149234: Solve the inequality (x + 3)(x + 1)(x – 5) < 0 and write the solution set both in interval notation and in set notation. Show work/explanation. 1 solutions
Answer 109482 by jim_thompson5910(28598) on 2008-07-22 13:36:45 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality
 Set the left side equal to zero
Set each individual factor equal to zero:
 ,  or
Solve for x in each case:
 ,  or
So our critical values are  ,  and
Now set up a number line and plot the critical values on the number line
So let's pick some test points that are near the critical values and evaluate them.
Let's pick a test value that is less than  (notice how it's to the left of the leftmost endpoint):
So let's pick
 Start with the given inequality
 Plug in
 Evaluate and simplify the left side
Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is ( )
---------------------------------------------------------------------------------------------
Let's pick a test value that is in between  and  :
So let's pick
 Start with the given inequality
 Plug in
 Evaluate and simplify the left side
Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.
---------------------------------------------------------------------------------------------
Let's pick a test value that is in between  and  :
So let's pick
 Start with the given inequality
 Plug in
 Evaluate and simplify the left side
Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is ( )
---------------------------------------------------------------------------------------------
Let's pick a test value that is greater than  (notice how it's to the right of the rightmost endpoint):
So let's pick
 Start with the given inequality
 Plug in
 Evaluate and simplify the left side
Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.
---------------------------------------------------------------------------------------------
Summary:
So the solution in interval notation is:
( ) ( )
Also, the answer in set notation is
Here's a graph to visually verify our answer:
 Graph of
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Geometric_formulas/149173: 10. The segments GA and GB are tangent to a circle with center O at A and B, and AGB is a 60-degree angle. Given that GA = 12 square root 3 cm, find the distance GO. Find the distance from G to the nearest point on the circle.
1 solutions
Answer 109434 by jim_thompson5910(28598) on 2008-07-21 23:51:37 (Show Source):
You can put this solution on YOUR website!
First let's draw the picture (take note that I'm cutting AGB in half to make 2 30 degree angles):
From the drawing, we can see that segments GA and AO are legs of a triangle while GO is the hypotenuse. Since the angle that we are working with is the 30 degree angle, this means that GA is the adjacent side. So to find the hypotenuse, we need to use the cosine function:
 Start with the cosine function.
 Plug in the given sides and angle.
 Multiply both sides by
 Divide both sides by
 Evaluate  to get
 Multiply by the reciprocal
 Cancel like terms.
 Simplify
 Multiply
So the length of GO is 24 units.
The closest point to G will lie on the line GO. So to find the distance from G to this point, we need to find the radius.
Using the previous drawing, we can see that the radius is AO. To find the length of AO, note that AO is the opposite leg to the angle 30 degrees. So let's use the sine function to find AO
 Start with the sine function.
 Plug in the angle 30 , the opposite side AO, and the hypotenuse 24
 Take the sine of 30 to get
 Cross multiply.
 Divide both sides by 2.
So the length of AO (the radius) is 12 units.
Now simply subtract the radius from the length GO to get
So the distance from G to the nearest point on the circle is 12 units.
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