New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'jim_thompson5910'
jim_thompson5910 answered: 28705 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069 , 17070..17099 , 17100..17129 , 17130..17159 , 17160..17189 , 17190..17219 , 17220..17249 , 17250..17279 , 17280..17309 , 17310..17339 , 17340..17369 , 17370..17399 , 17400..17429 , 17430..17459 , 17460..17489 , 17490..17519 , 17520..17549 , 17550..17579 , 17580..17609 , 17610..17639 , 17640..17669 , 17670..17699 , 17700..17729 , 17730..17759 , 17760..17789 , 17790..17819 , 17820..17849 , 17850..17879 , 17880..17909 , 17910..17939 , 17940..17969 , 17970..17999 , 18000..18029 , 18030..18059 , 18060..18089 , 18090..18119 , 18120..18149 , 18150..18179 , 18180..18209 , 18210..18239 , 18240..18269 , 18270..18299 , 18300..18329 , 18330..18359 , 18360..18389 , 18390..18419 , 18420..18449 , 18450..18479 , 18480..18509 , 18510..18539 , 18540..18569 , 18570..18599 , 18600..18629 , 18630..18659 , 18660..18689 , 18690..18719 , 18720..18749 , 18750..18779 , 18780..18809 , 18810..18839 , 18840..18869 , 18870..18899 , 18900..18929 , 18930..18959 , 18960..18989 , 18990..19019 , 19020..19049 , 19050..19079 , 19080..19109 , 19110..19139 , 19140..19169 , 19170..19199 , 19200..19229 , 19230..19259 , 19260..19289 , 19290..19319 , 19320..19349 , 19350..19379 , 19380..19409 , 19410..19439 , 19440..19469 , 19470..19499 , 19500..19529 , 19530..19559 , 19560..19589 , 19590..19619 , 19620..19649 , 19650..19679 , 19680..19709 , 19710..19739 , 19740..19769 , 19770..19799 , 19800..19829 , 19830..19859 , 19860..19889 , 19890..19919 , 19920..19949 , 19950..19979 , 19980..20009 , 20010..20039 , 20040..20069 , 20070..20099 , 20100..20129 , 20130..20159 , 20160..20189 , 20190..20219 , 20220..20249 , 20250..20279 , 20280..20309 , 20310..20339 , 20340..20369 , 20370..20399 , 20400..20429 , 20430..20459 , 20460..20489 , 20490..20519 , 20520..20549 , 20550..20579 , 20580..20609 , 20610..20639 , 20640..20669 , 20670..20699 , 20700..20729 , 20730..20759 , 20760..20789 , 20790..20819 , 20820..20849 , 20850..20879 , 20880..20909 , 20910..20939 , 20940..20969 , 20970..20999 , 21000..21029 , 21030..21059 , 21060..21089 , 21090..21119 , 21120..21149 , 21150..21179 , 21180..21209 , 21210..21239 , 21240..21269 , 21270..21299 , 21300..21329 , 21330..21359 , 21360..21389 , 21390..21419 , 21420..21449 , 21450..21479 , 21480..21509 , 21510..21539 , 21540..21569 , 21570..21599 , 21600..21629 , 21630..21659 , 21660..21689 , 21690..21719 , 21720..21749 , 21750..21779 , 21780..21809 , 21810..21839 , 21840..21869 , 21870..21899 , 21900..21929 , 21930..21959 , 21960..21989 , 21990..22019 , 22020..22049 , 22050..22079 , 22080..22109 , 22110..22139 , 22140..22169 , 22170..22199 , 22200..22229 , 22230..22259 , 22260..22289 , 22290..22319 , 22320..22349 , 22350..22379 , 22380..22409 , 22410..22439 , 22440..22469 , 22470..22499 , 22500..22529 , 22530..22559 , 22560..22589 , 22590..22619 , 22620..22649 , 22650..22679 , 22680..22709 , 22710..22739 , 22740..22769 , 22770..22799 , 22800..22829 , 22830..22859 , 22860..22889 , 22890..22919 , 22920..22949 , 22950..22979 , 22980..23009 , 23010..23039 , 23040..23069 , 23070..23099 , 23100..23129 , 23130..23159 , 23160..23189 , 23190..23219 , 23220..23249 , 23250..23279 , 23280..23309 , 23310..23339 , 23340..23369 , 23370..23399 , 23400..23429 , 23430..23459 , 23460..23489 , 23490..23519 , 23520..23549 , 23550..23579 , 23580..23609 , 23610..23639 , 23640..23669 , 23670..23699 , 23700..23729 , 23730..23759 , 23760..23789 , 23790..23819 , 23820..23849 , 23850..23879 , 23880..23909 , 23910..23939 , 23940..23969 , 23970..23999 , 24000..24029 , 24030..24059 , 24060..24089 , 24090..24119 , 24120..24149 , 24150..24179 , 24180..24209 , 24210..24239 , 24240..24269 , 24270..24299 , 24300..24329 , 24330..24359 , 24360..24389 , 24390..24419 , 24420..24449 , 24450..24479 , 24480..24509 , 24510..24539 , 24540..24569 , 24570..24599 , 24600..24629 , 24630..24659 , 24660..24689 , 24690..24719 , 24720..24749 , 24750..24779 , 24780..24809 , 24810..24839 , 24840..24869 , 24870..24899 , 24900..24929 , 24930..24959 , 24960..24989 , 24990..25019 , 25020..25049 , 25050..25079 , 25080..25109 , 25110..25139 , 25140..25169 , 25170..25199 , 25200..25229 , 25230..25259 , 25260..25289 , 25290..25319 , 25320..25349 , 25350..25379 , 25380..25409 , 25410..25439 , 25440..25469 , 25470..25499 , 25500..25529 , 25530..25559 , 25560..25589 , 25590..25619 , 25620..25649 , 25650..25679 , 25680..25709 , 25710..25739 , 25740..25769 , 25770..25799 , 25800..25829 , 25830..25859 , 25860..25889 , 25890..25919 , 25920..25949 , 25950..25979 , 25980..26009 , 26010..26039 , 26040..26069 , 26070..26099 , 26100..26129 , 26130..26159 , 26160..26189 , 26190..26219 , 26220..26249 , 26250..26279 , 26280..26309 , 26310..26339 , 26340..26369 , 26370..26399 , 26400..26429 , 26430..26459 , 26460..26489 , 26490..26519 , 26520..26549 , 26550..26579 , 26580..26609 , 26610..26639 , 26640..26669 , 26670..26699 , 26700..26729 , 26730..26759 , 26760..26789 , 26790..26819 , 26820..26849 , 26850..26879 , 26880..26909 , 26910..26939 , 26940..26969 , 26970..26999 , 27000..27029 , 27030..27059 , 27060..27089 , 27090..27119 , 27120..27149 , 27150..27179 , 27180..27209 , 27210..27239 , 27240..27269 , 27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499 , 28500..28529 , 28530..28559 , 28560..28589 , 28590..28619 , 28620..28649 , 28650..28679 , 28680..28709, >>NextQuadratic_Equations/151430: .
.
.
. 1 solutions
Answer 111318 by jim_thompson5910(28717) on 2008-08-09 23:34:11 (Show Source):
You can put this solution on YOUR website!I'll do the first two to get you started.
# 1
 Start with the given equation.
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Break up the fraction for each case.
 or  Reduce.
 or  Simplify.
So our answers are  or
# 2
 Start with the given equation.
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
 or  Break up the expression.
 or  Reduce.
So the answers are  or
which approximate to  or
|
Quadratic_Equations/151432: Will the quadratic equation work on an equation such as x^2 - 3=0? 1 solutions
Answer 111317 by jim_thompson5910(28717) on 2008-08-09 23:29:06 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Take note that  really looks like
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
 Break up the fraction.
 Reduce.
 or  Break up the expression.
So our answers are  or
which approximate to  or
Note: even though the quadratic formula works perfectly here, there is a much faster way to solve this problem.
|
Quadratic_Equations/151404: How would I go about writing the quadratic function, in (standard) form, which has a vertex of (-6, 2) and passes through (5, 12)?
The standard form is y= a(x-h)^2+k , so i would put -6 as h and 2 as k but from there I am stuck. 1 solutions
Answer 111294 by jim_thompson5910(28717) on 2008-08-09 16:45:47 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Plug in  and
 Rewrite  as
Since the quadratic passes through (5, 12), this means that if you plug in  , you will get  . So we can plug in  and  to solve for "a"
 Plug in  and
 Add
 Square 11 to get 121
 Rearrange the terms
 Subtract 2 from both sides.
 Divide both sides by 121.
So the value of "a" is
This means that the equation is
|
expressions/151406: Multiply:
((x^2+x-12)/(x^2-x-20))X((x^2+2x-35)/(x^2+9x+14)) 1 solutions
Answer 111293 by jim_thompson5910(28717) on 2008-08-09 16:39:48 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Factor  to get  .
 Factor  to get  .
 Factor  to get  .
 Factor  to get  .
 Combine the fractions.
 Highlight the common terms.
 Cancel out the common terms.
 Simplify.
So  simplifies to  .
In other words,  where  ,  ,  , or
|
Trigonometry-basics/151392: tan(pi/6 + pi/4) 1 solutions
Answer 111290 by jim_thompson5910(28717) on 2008-08-09 15:26:19 (Show Source):
You can put this solution on YOUR website! Start with the given expression.
 Use the identity  to expand the expression.
 Using the unit circle, evaluate  to get  and evaluate  to get
 Multiply
 Combine the fractions.
 Multiply the first fraction by the reciprocal of the second fraction.
 Cancel out the common terms.
 Simplify.
 Multiply the fraction by
 Combine the fractions.
 FOIL
 Combine like terms
 Factor out the GCF
 Reduce
So
|
Miscellaneous_Word_Problems/151389: The sum of two numbers is 41 and their difference is 14. Find the numbers.
not sure but 2 + x - 14 = 41 1 solutions
Answer 111288 by jim_thompson5910(28717) on 2008-08-09 15:12:28 (Show Source):
You can put this solution on YOUR website!"The sum of two numbers is 41" translates to
and
"their difference is 14" translates to
So we have the system of equations:
Add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:
 Group like terms.
 Combine like terms. Notice how the y terms cancel out.
 Simplify.
 Divide both sides by  to isolate  .
------------------------------------------------------------------
 Now go back to the first equation.
 Plug in  .
 Multiply both sides by the LCD  to clear any fractions.
 Distribute and multiply.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
So our answer is  and  .
So the two numbers are  and
|
Graphs/151376: Graph y=2x-1 1 solutions
Answer 111267 by jim_thompson5910(28717) on 2008-08-09 12:26:50 (Show Source):
You can put this solution on YOUR website!
In order to graph this equation, we only need two points to create a straight line
--------------------------------Let's find the first point--------------------------------
 Start with the given equation
 Plug in  (you can start with any number, but zero is the easiest number to work with since anything multiplied by zero is zero)
 Multiply  and  to get
 Subtract
So when  , we have the value  . This means we have the first point
--------------------------------Let's find the second point--------------------------------
 Start with the given equation
 Plug in
 Multiply  and  to get
 Subtract
So when  , we have the value  . This means we have the second point
------------------------------------------------------------------------------------------------
So we have the two points: ) and
Now plot these two points on a coordinate system
Now draw a straight line through the two points. This line is the graph of
 Graph of  through the two points ) and
|
Polynomials-and-rational-expressions/151358: factorize 5(3x+y)^2+6(3x+y)-8 please help me understand how to solve this sum. thankyou 1 solutions
Answer 111263 by jim_thompson5910(28717) on 2008-08-09 11:39:29 (Show Source):
You can put this solution on YOUR website!Let
So the expression goes from  to
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,4,5,8,10,20,40
-1,-2,-4,-5,-8,-10,-20,-40
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-40)
2*(-20)
4*(-10)
5*(-8)
(-1)*(40)
(-2)*(20)
(-4)*(10)
(-5)*(8)
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -40 | 1+(-40)=-39 | | 2 | -20 | 2+(-20)=-18 | | 4 | -10 | 4+(-10)=-6 | | 5 | -8 | 5+(-8)=-3 | | -1 | 40 | -1+40=39 | | -2 | 20 | -2+20=18 | | -4 | 10 | -4+10=6 | | -5 | 8 | -5+8=3 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
 Plug in
 Distribute
---------------------------------------------
Answer:
So  factors to  .
In other words,
Note: you can check the answer by expanding  to get  .
|
Graphs/151369: graph of the line through (3, 2) with slope 1/2 1 solutions
Answer 111261 by jim_thompson5910(28717) on 2008-08-09 11:33:43 (Show Source):
You can put this solution on YOUR website!
If you want to find the equation of line with a given a slope of  which goes through the point (  ,  ), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
 where  is the slope, and ) is the given point
So lets use the Point-Slope Formula to find the equation of the line
 Plug in  ,  , and  (these values are given)
 Distribute
 Multiply  and  to get
 Add 2 to both sides to isolate y
 Combine like terms  and  to get  (note: if you need help with combining fractions, check out this solver)
------------------------------------------------------------------------------------------------------------
Answer:
So the equation of the line with a slope of  which goes through the point (  ,  ) is:
 which is now in  form where the slope is  and the y-intercept is
Notice if we graph the equation  and plot the point (  ,  ), we get (note: if you need help with graphing, check out this solver)
Graph of through the point ( , )
and we can see that the point lies on the line. Since we know the equation has a slope of and goes through the point ( , ), this verifies our answer.
|
Graphs/151365: graph linear equation y = 2x - 1 1 solutions
Answer 111258 by jim_thompson5910(28717) on 2008-08-09 11:31:07 (Show Source):
You can put this solution on YOUR website!
Looking at  we can see that the equation is in slope-intercept form  where the slope is  and the y-intercept is
Since  this tells us that the y-intercept is ) .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is  , this means:
which shows us that the rise is 2 and the run is 1. This means that to go from point to point, we can go up 2 and over 1
So starting at ) , go up 2 units
and to the right 1 unit to get to the next point
Now draw a line through these points to graph
 So this is the graph of  through the points ) and
|
Graphs/151372: write the equation of y = 1/3x - 2 in standard form using only integers and a positive coefficient of x 1 solutions
Answer 111257 by jim_thompson5910(28717) on 2008-08-09 11:21:26 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Multiply both sides by 3 to eliminate the fractions.
 Distribute and multiply.
 Subtract  from both sides.
 Rearrange the terms.
 Multiply both sides by -1. This will make the x coefficient positive.
 Distribute and multiply.
So the equation is now in standard form  where  ,  and
|
Radicals/151325: 5 square root of x + 1 = 3
2/3 = 2 - 5x-3 over x-1
solve algebraically thanks 1 solutions
Answer 111241 by jim_thompson5910(28717) on 2008-08-08 21:53:58 (Show Source):
You can put this solution on YOUR website!I'll do the first one to get you started.
 Start with the given equation.
 Divide both sides by 5.
 Square both sides.
 Square  to get
 Subtract 1 from both sides.
 Combine the fractions.
So the solution is  which approximates to
|
Matrices-and-determiminant/151324: I am lost with this assignment, HELP! I do not understand hwo these are answered!
4. A group of students decides to sell pizzas to help raise money for their senior class trip. They sold pepperoni for $12, sausage for $10, and cheese for $8. At the end of their sales the class sold a total of 600 pizzas and made $5900. The students sold 175 more cheese pizzas than sausage pizzas. Set up a system of three equations and three unknowns, use an augmented matrix to solve, and show all work to receive full credit.
A. What are the three unknowns?
B. Write a separate equation representing each of the first three sentences.
C. Determine the augmented matrix that represents the three equations.
D. Solve for the matrix. Show all work to receive full credit.
E. How many of each type of pizza were sold?
1 solutions
Answer 111240 by jim_thompson5910(28717) on 2008-08-08 21:50:26 (Show Source):
You can put this solution on YOUR website!a)
Let x=# of pepperoni sold, y=# of sausage sold, and z=# of cheese sold
b)
Since there are 3 unknowns, we need 3 equations:
Equation #1:
First, since they sold "pepperoni for $12, sausage for $10, and cheese for $8" and collected $5,900, this means that
Equation #2:
Also, we know that the students sold 600 pizzas total. So this means that the sum of all of the pizzas sold was 600. So this translates to  .
Equation #3:
Finally, since they sold "175 more cheese pizzas than sausage pizzas", this makes the equation
Getting all of the variables to one side for equation 3 gives us:
So we have the system
c)
This means that we have the augmented matrix matrix
d)
Solution was generated by the Linear Algebra Toolkit
=============================================================
Answer:
So the solutions are  ,  , and  (these values form the right hand column of the augmented matrix).
So this means that they sold 225 pepperoni pizzas, 100 sausage pizzas, and 275 cheese pizzas.
|
Linear-systems/151320: Hello may someone please elp me with this question im very confused!
The length of a rectangle is 3 in. more than the width. The perimeter of the rectangle is 24 in.
I THINK THAT I AHVE FOUND THE VARIABLES LENGTH=3iN. WIDTH=24iN.(AM I RIGHT???)
What is the expression for the length in terms of the width?
What is the length of the rectangle? 1 solutions
Answer 111236 by jim_thompson5910(28717) on 2008-08-08 21:26:58 (Show Source):
You can put this solution on YOUR website!Let x=width and y=length
Since the "length of a rectangle is 3 in. more than the width", this means that  . Also, because the "perimeter of the rectangle is 24 in", this tells us that
 Start with the formula for the perimeter of a rectangle
 Plug in  and
 Distribute
 Subtract 6 from both sides.
 Combine like terms.
 Divide both sides by 4.
 Reduce.
So the first part of the answer is  or  . This means that the width is 4.5 inches.
 Go back to the first equation
 Plug in
 Combine the fractions.
So the second part of the answer is  or  . This means that the length is 7.5 inches.
=======================================================
Answer:
So the width is 4.5 inches and the length is 7.5 inches
|
Distributive-associative-commutative-properties/151323: how would you...
A.) use the distributive property to solve and create a binomial to set up the FOIL method
B.) Solve with the FOIL method
could you break it down step by step?
4x(x^2-2x+5) 1 solutions
Answer 111233 by jim_thompson5910(28717) on 2008-08-08 21:13:22 (Show Source):
You can put this solution on YOUR website!This problem does not involve FOILing, but involves distribution (you use FOIL when you have two binomials). So I would double check the problem.
Anyways, here's how you would simplify the problem.
 Start with the given expression.
 Distribute.
 Multiply  and  to get
 Multiply  and  to get
 Multiply  and  to get
So  distributes and simplifies to
In other words,
|
Functions/151318: y-2-8 sqrt(y-2)+15=0 1 solutions
Answer 111230 by jim_thompson5910(28717) on 2008-08-08 21:08:49 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Combine like terms.
 Subtract 13 from both sides.
 Subtract  from both sides.
 Square both sides.
 FOIL
 Distribute
 Subtract  from both sides. Add 128 to both sides.
 Combine like terms
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for y
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So our answers are  or
|
decimal-numbers/151321: Write the solution using interval notation.
x<-6 or x>0 1 solutions
Answer 111229 by jim_thompson5910(28717) on 2008-08-08 21:03:35 (Show Source):
You can put this solution on YOUR website!
The solution in interval notation is: ( ) ( )
Also, the solution in set notation is:
Here's the graph of the solution set
Note:
There is an open circle at  which means that we're excluding that value from the solution set.
Also, there is an open circle at  which means that we're excluding that value from the solution set.
|
Systems-of-equations/151299: Could you help solve:
8/x-5/y=51/14 6/x+(-10)/y=-(29/7) 1 solutions
Answer 111201 by jim_thompson5910(28717) on 2008-08-08 14:43:54 (Show Source):
You can put this solution on YOUR website! Start with the first equation.
 Multiply both sides by  . This will eliminate the fractions.
 Distribute and multiply
 Subtract  from both sides.
 Factor out  from the right side.
 Divide both sides by  .
So after isolating y of the first equation, we get
---------------------------------
 Move onto the second equation
 Plug in  . In other words, replace "y" with
 Multiply the numerator "-10" by the reciprocal of the fraction in the denominator.
 Distribute
 Simplify.
 Multiply both sides by  . This will eliminate the fractions.
 Simplify
 Subtract  from both sides.
 Combine like terms.
 Divide both sides by -800.
 Reduce. So this is the first part of the answer.
 Go back to the first isolated equation
 Plug in
 Multiply and reduce
 Subtract
 Multiply the first fraction by the reciprocal of the second fraction.
 Multiply and reduce
=========================================
Answer:
So the answer is  and  which forms the ordered pair
|
Linear-systems/151298: Could you please help me solve the system of equations?
3x+3y+z=5
x-3y+2z=-13
8x-2y+3z=-8 1 solutions
Answer 111200 by jim_thompson5910(28717) on 2008-08-08 14:29:32 (Show Source):
You can put this solution on YOUR website!
Add equations 1 and 2. Let's call the result equation 4:

+ 
-----------------
Equation 4:
 Multiply both sides of equation 1 by 2
 Multiply. Let's call this equation 5
-------
 Multiply both sides of equation 3 by 3
 Multiply. Let's call this equation 6
Now add equations 5 and 6. Let's call the result equation 7:

+ 
-------------------
Equation 7:
===================================
So we now have the two equations equation 4 and equation 7:
equation 4:
equation 7:
Start with the given system of equations:
Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for z.
So let's isolate z in the first equation
 Start with the first equation
 Subtract  from both sides
 Rearrange the equation
 Divide both sides by
 Break up the fraction
 Reduce
---------------------
Since  , we can now replace each  in the second equation with  to solve for
 Plug in  into the first equation. In other words, replace each  with  . Notice we've eliminated the  variables. So we now have a simple equation with one unknown.
 Distribute  to
 Multiply
 Multiply both sides by the LCM of 3. This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)
 Distribute and multiply the LCM to each side
 Combine like terms on the left side
 Add 88 to both sides
 Combine like terms on the right side
 Divide both sides by 46 to isolate x
 Divide
So the first part of our answer is:
Since we know that  we can plug it into the equation  (remember we previously solved for  in the first equation).
 Start with the equation where  was previously isolated.
 Plug in
 Multiply
 Combine like terms and reduce. (note: if you need help with fractions, check out this solver)
So the third part of our answer is:
 Go back to the first equation
 Plug in  and
 Multiply
 Combine like terms.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
So the second part of the answer is
-----------------Summary------------------------------
So our answers are:
 ,  , and
They form the point (1,2,-4)
|
Systems-of-equations/151297: Can you help me solve this system algabraically and support the solutions graphically?
y+x^2
9x-y=20
(ordered pairs) 1 solutions
Answer 111199 by jim_thompson5910(28717) on 2008-08-08 14:19:43 (Show Source):
You can put this solution on YOUR website!What is  equal to? This is not an equation.
Did you mean to say  ??
 Start with the second equation.
 Plug in
 Subtract 20 from both sides.
 Rearrange the terms.
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the x answers are  or
 Go back to the first equation
 Plug in
 Square 4 to get 16.
So the first set of answers is  and  which form the ordered pair (4,16)
----------------
 Go back to the first equation
 Plug in
 Square 5 to get 25.
So the second set of answers is  and  which form the ordered pair (5,25)
==========================================
Answer:
So the ordered pair solutions are (4,16) and (5,25)
Notice that if we graph the two equations, we get
 Graph of  (red) and  (green).
It's hard to see, but with the help of a graphing calculator, we can see that the graphs intersect at the points (4,16) and (5,25). So this verifies our answer.
|
Exponential-and-logarithmic-functions/151295: - How many months does it take for $1000 to grow to $1500 in an account paying 12% compounded monthly? 1 solutions
Answer 111196 by jim_thompson5910(28717) on 2008-08-08 13:52:24 (Show Source):
You can put this solution on YOUR website! Start with the compound interest formula.
 Plug in  ,  ,  (note: 12%=0.12) and
 Divide both sides by 1000.
 Reduce
 Divide  to get 0.01
 Add 1 to 0.01 to get 1.01
 Take the log of both sides.
 Rewrite the right side using the identity
 Divide both sides by  .
So the answer is  which approximates to
So it takes about 3.4 years (or 40.8 months) to go from $1,000 to $1,500
|
Polynomials-and-rational-expressions/151294: 3x^2 + 8x - 3 = 0 1 solutions
Answer 111195 by jim_thompson5910(28717) on 2008-08-08 13:43:40 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So our answers are  or
|
|