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expressions/153295: evaluate:
3^0
1 solutions

Answer 112831 by jim_thompson5910(28595) About Me  on 2008-08-25 08:54:02 (Show Source):
You can put this solution on YOUR website!
3%5E0=1

note: x%5E0=1 where x%3C%3E0. In other words, any number to the zeroth power (except zero) is 1.


Numeric_Fractions/153296: convert to a decimal:
(2/3)^-1
1 solutions

Answer 112830 by jim_thompson5910(28595) About Me  on 2008-08-25 08:52:57 (Show Source):


Polynomials-and-rational-expressions/153300: factor completly:
36m^2-48m+16

1 solutions

Answer 112829 by jim_thompson5910(28595) About Me  on 2008-08-25 08:51:42 (Show Source):
You can put this solution on YOUR website!

36m%5E2-48m%2B16 Start with the given expression


4%289m%5E2-12m%2B4%29 Factor out the GCF 4


Now let's focus on the inner expression 9m%5E2-12m%2B4




------------------------------------------------------------





Looking at the expression 9m%5E2-12m%2B4, we can see that the first coefficient is 9, the second coefficient is -12, and the last term is 4.


Now multiply the first coefficient 9 by the last term 4 to get %289%29%284%29=36.


Now the question is: what two whole numbers multiply to 36 (the previous product) and add to the second coefficient -12?


To find these two numbers, we need to list all of the factors of 36 (the previous product).


Factors of 36:
1,2,3,4,6,9,12,18,36
-1,-2,-3,-4,-6,-9,-12,-18,-36


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 36.
1*36
2*18
3*12
4*9
6*6
(-1)*(-36)
(-2)*(-18)
(-3)*(-12)
(-4)*(-9)
(-6)*(-6)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -12:


First NumberSecond NumberSum
1361+36=37
2182+18=20
3123+12=15
494+9=13
666+6=12
-1-36-1+(-36)=-37
-2-18-2+(-18)=-20
-3-12-3+(-12)=-15
-4-9-4+(-9)=-13
-6-6-6+(-6)=-12



From the table, we can see that the two numbers -6 and -6 add to -12 (the middle coefficient).


So the two numbers -6 and -6 both multiply to 36 and add to -12


Now replace the middle term -12m with -6m-6m. Remember, -6 and -6 add to -12. So this shows us that -6m-6m=-12m.


9m%5E2%2Bhighlight%28-6m-6m%29%2B4 Replace the second term -12m with -6m-6m.


%289m%5E2-6m%29%2B%28-6m%2B4%29 Group the terms into two pairs.


3m%283m-2%29%2B%28-6m%2B4%29 Factor out the GCF 3m from the first group.


3m%283m-2%29-2%283m-2%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%283m-2%29%283m-2%29 Combine like terms. Or factor out the common term 3m-2


%283m-2%29%5E2 Condense


So 9m%5E2-12m%2B4 factors to %283m-2%29%5E2


This means that the expression goes from 4%289m%5E2-12m%2B4%29 and factors further to 4%283m-2%29%5E2



------------------
Answer:

So 36m%5E2-48m%2B16 factors to 4%283m-2%29%5E2


Expressions-with-variables/153303: Factor the expression 4n^3 + 8n^2 - 5n - 10
Factor k^2 + kf - 2f^2
Factor 6g^2 + 11g - 35

I am not sure how to factor these. I am especially "stuck" on the one that uses kf.
Can you help? Thanks!
1 solutions

Answer 112828 by jim_thompson5910(28595) About Me  on 2008-08-25 08:49:14 (Show Source):
You can put this solution on YOUR website!
# 1



4n%5E3%2B8n%5E2-5n-10 Start with the given expression


%284n%5E3%2B8n%5E2%29%2B%28-5n-10%29 Group like terms


4n%5E2%28n%2B2%29-5%28n%2B2%29 Factor out the GCF 4n%5E2 out of the first group. Factor out the GCF -5 out of the second group


%284n%5E2-5%29%28n%2B2%29 Since we have the common term n%2B2, we can combine like terms


So 4n%5E3%2B8n%5E2-5n-10 factors to %284n%5E2-5%29%28n%2B2%29





# 2


Looking at k%5E2%2Bkf-2f%5E2 we can see that the first term is k%5E2 and the last term is -2f%5E2 where the coefficients are 1 and -2 respectively.

Now multiply the first coefficient 1 and the last coefficient -2 to get -2. Now what two numbers multiply to -2 and add to the middle coefficient 1? Let's list all of the factors of -2:



Factors of -2:
1,2

-1,-2 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -2
(1)*(-2)
(-1)*(2)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 1

First NumberSecond NumberSum
1-21+(-2)=-1
-12-1+2=1



From this list we can see that -1 and 2 add up to 1 and multiply to -2


Now looking at the expression k%5E2%2Bkf-2f%5E2, replace kf with -kf%2B2kf (notice -kf%2B2kf adds up to kf. So it is equivalent to kf)

k%5E2%2Bhighlight%28-kf%2B2kf%29%2B-2f%5E2


Now let's factor k%5E2-kf%2B2kf-2f%5E2 by grouping:


%28k%5E2-kf%29%2B%282kf-2f%5E2%29 Group like terms


k%28k-f%29%2B2f%28k-f%29 Factor out the GCF of k out of the first group. Factor out the GCF of 2f out of the second group


%28k%2B2f%29%28k-f%29 Since we have a common term of k-f, we can combine like terms

So k%5E2-kf%2B2kf-2f%5E2 factors to %28k%2B2f%29%28k-f%29


So this also means that k%5E2%2Bkf-2f%5E2 factors to %28k%2B2f%29%28k-f%29 (since k%5E2%2Bkf-2f%5E2 is equivalent to k%5E2-kf%2B2kf-2f%5E2)



------------------------------------------------------------



Answer:
So k%5E2%2Bkf-2f%5E2 factors to %28k%2B2f%29%28k-f%29





# 3



Looking at the expression 6g%5E2%2B11g-35, we can see that the first coefficient is 6, the second coefficient is 11, and the last term is -35.


Now multiply the first coefficient 6 by the last term -35 to get %286%29%28-35%29=-210.


Now the question is: what two whole numbers multiply to -210 (the previous product) and add to the second coefficient 11?


To find these two numbers, we need to list all of the factors of -210 (the previous product).


Factors of -210:
1,2,3,5,6,7,10,14,15,21,30,35,42,70,105,210
-1,-2,-3,-5,-6,-7,-10,-14,-15,-21,-30,-35,-42,-70,-105,-210


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -210.
1*(-210)
2*(-105)
3*(-70)
5*(-42)
6*(-35)
7*(-30)
10*(-21)
14*(-15)
(-1)*(210)
(-2)*(105)
(-3)*(70)
(-5)*(42)
(-6)*(35)
(-7)*(30)
(-10)*(21)
(-14)*(15)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 11:


First NumberSecond NumberSum
1-2101+(-210)=-209
2-1052+(-105)=-103
3-703+(-70)=-67
5-425+(-42)=-37
6-356+(-35)=-29
7-307+(-30)=-23
10-2110+(-21)=-11
14-1514+(-15)=-1
-1210-1+210=209
-2105-2+105=103
-370-3+70=67
-542-5+42=37
-635-6+35=29
-730-7+30=23
-1021-10+21=11
-1415-14+15=1



From the table, we can see that the two numbers -10 and 21 add to 11 (the middle coefficient).


So the two numbers -10 and 21 both multiply to -210 and add to 11


Now replace the middle term 11g with -10g%2B21g. Remember, -10 and 21 add to 11. So this shows us that -10g%2B21g=11g.


6g%5E2%2Bhighlight%28-10g%2B21g%29-35 Replace the second term 11g with -10g%2B21g.


%286g%5E2-10g%29%2B%2821g-35%29 Group the terms into two pairs.


2g%283g-5%29%2B%2821g-35%29 Factor out the GCF 2g from the first group.


2g%283g-5%29%2B7%283g-5%29 Factor out 7 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%282g%2B7%29%283g-5%29 Combine like terms. Or factor out the common term 3g-5

---------------------------------------------


Answer:


So 6g%5E2%2B11g-35 factors to %282g%2B7%29%283g-5%29.


Note: you can check the answer by FOILing %282g%2B7%29%283g-5%29 to get 6g%5E2%2B11g-35 or by graphing the original expression and the answer (the two graphs should be identical).


expressions/153286: simplify: +%289q%5E3+-+4%29+-+%287q%5E2+-+5%29+%2B+%287q%5E3+%2B+2q%5E2%29+
1 solutions

Answer 112809 by jim_thompson5910(28595) About Me  on 2008-08-25 00:12:22 (Show Source):
You can put this solution on YOUR website!
+%289q%5E3+-+4%29+-+%287q%5E2+-+5%29+%2B+%287q%5E3+%2B+2q%5E2%29+ Start with the given equation.


+9q%5E3+-+4+-+7q%5E2+%2B+5+%2B+7q%5E3+%2B+2q%5E2+ Distribute the negative


%289q%5E3%2B7q%5E3%29%2B%28-7q%5E2%2B2q%5E2%29%2B%28-4%2B5%29 Group the common terms


16q%5E3-5q%5E2%2B1 Combine like terms



So %289q%5E3+-+4%29+-+%287q%5E2+-+5%29+%2B+%287q%5E3+%2B+2q%5E2%29=16q%5E3-5q%5E2%2B1


Exponents-negative-and-fractional/153260: 4x^2-81
1 solutions

Answer 112794 by jim_thompson5910(28595) About Me  on 2008-08-24 20:28:50 (Show Source):
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Do you want to factor this?



4x%5E2-81 Start with the given expression.


%282x%29%5E2-81 Rewrite 4x%5E2 as %282x%29%5E2.


%282x%29%5E2-%289%29%5E2 Rewrite 81 as %289%29%5E2.


Notice how we have a difference of squares. So let's use the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29 to factor the expression:


%282x%2B9%29%282x-9%29 Factor the expression using the difference of squares.


So 4x%5E2-81 factors to %282x%2B9%29%282x-9%29.


In other words 4x%5E2-81=%282x%2B9%29%282x-9%29.


Expressions-with-variables/153250: This question is from textbook Algebra Structure and Method
Please help with this problem.
1-3/4(v+2)=-5

1 solutions

Answer 112789 by jim_thompson5910(28595) About Me  on 2008-08-24 19:50:56 (Show Source):
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1-%283%2F4%29%28v%2B2%29=-5 Start with the given equation.


4%281-%283%2Fcross%284%29%29%28v%2B2%29%29=4%28-5%29 Multiply both sides by the LCD 4 to clear any fractions.


4-3%28v%2B2%29=-20 Distribute and multiply.


4-3v-6=-20 Distribute again.


-3v-2=-20 Combine like terms on the left side.


-3v=-20%2B2 Add 2 to both sides.


-3v=-18 Combine like terms on the right side.


v=%28-18%29%2F%28-3%29 Divide both sides by -3 to isolate v.


v=6 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is v=6


Equations/153243: HELP!!!
Solve the equation algebraically by factoring or using quadratic formula;
x squared - 2x -3 = 0
very confused!!!!!
1 solutions

Answer 112787 by jim_thompson5910(28595) About Me  on 2008-08-24 19:23:27 (Show Source):
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x%5E2-2x-3=0 Start with the given equation.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=-2, and c=-3


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%28-3%29+%29%29%2F%282%281%29%29 Plug in a=1, b=-2, and c=-3


x+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%28-3%29+%29%29%2F%282%281%29%29 Negate -2 to get 2.


x+=+%282+%2B-+sqrt%28+4-4%281%29%28-3%29+%29%29%2F%282%281%29%29 Square -2 to get 4.


x+=+%282+%2B-+sqrt%28+4--12+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-3%29 to get -12


x+=+%282+%2B-+sqrt%28+4%2B12+%29%29%2F%282%281%29%29 Rewrite sqrt%284--12%29 as sqrt%284%2B12%29


x+=+%282+%2B-+sqrt%28+16+%29%29%2F%282%281%29%29 Add 4 to 12 to get 16


x+=+%282+%2B-+sqrt%28+16+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%282+%2B-+4%29%2F%282%29 Take the square root of 16 to get 4.


x+=+%282+%2B+4%29%2F%282%29 or x+=+%282+-+4%29%2F%282%29 Break up the expression.


x+=+%286%29%2F%282%29 or x+=++%28-2%29%2F%282%29 Combine like terms.


x+=+3 or x+=+-1 Simplify.


So the answers are x+=+3 or x+=+-1



Equations/153241: This question is from textbook intermediate algebra
on page 58 of the textbook. the problem is a=180-(a-2/n) solve for n.
this is what i got so far up to point where i am stuck.
a=180(1-2/n) distribute
a=180-360/n +360/n
360/n=180-a -a
?
am i doing this right so far? Also im not sure of the next step. After i got to this point i didnt know what to do
1 solutions

Answer 112772 by jim_thompson5910(28595) About Me  on 2008-08-24 17:56:23 (Show Source):
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So the equation is a=180%281-2%2Fn%29 ?


a=180%281-2%2Fn%29 Start with the given equation.


%28a%29%2F%28180%29=1-2%2Fn Divide both sides by 180.


%28a%29%2F%28180%29-1=-2%2Fn Subtract 1 from both sides.


%28a-180%29%2F%28180%29=-2%2Fn Combine the fractions.


%28n%28a-180%29%29%2F%28180%29=-2 Multiply both sides by "n".


n%28a-180%29=-2%28180%29 Multiply both sides by 180.


n%28a-180%29=-360 Multiply


n=-360%2F%28a-180%29 Divide both sides by a-180.


percentage/153239: what percent of one u.s. dollar is $.25?
1 solutions

Answer 112771 by jim_thompson5910(28595) About Me  on 2008-08-24 17:52:23 (Show Source):
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Note: $0.25 = 25 cents and $1 = 100 cents


Percent+=+%28part%2Fwhole%29%2A100 Start with the given formula.


Percent+=+%2825%2F100%29%2A100 Plug in 25 cents for the numerator and 100 cents for the denominator


Percent+=+%2825%2Fcross%28100%29%29%2Across%28100%29 Cancel like terms


Percent+=+25 Simplify


So $0.25 is 25% of one U.S. dollar


Linear-systems/153240: you have used all of a $50 gift certificate watching movies at the local theater. Afternoon movies are $4 and evening movies are $6. you have watched a total of 10 movies. HOw much have you spent on evening movies?
1 solutions

Answer 112770 by jim_thompson5910(28595) About Me  on 2008-08-24 17:48:17 (Show Source):
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Let x=# of $6 movies and y=# of $4 movies

Since "you have watched a total of 10 movies", this means that the first equation is x%2By=10

Also, since you only have $50 to spend, this means that the second equation is 6x%2B4y=50



So we have the system of equations:

system%28x%2By=10%2C6x%2B4y=50%29


Let's use substitution to solve this system.

Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the first equation

x%2By=10 Start with the first equation


y=10-x Subtract x from both sides


y=-x%2B10 Rearrange the equation




---------------------

Since y=-x%2B10, we can now replace each y in the second equation with -x%2B10 to solve for x



6x%2B4highlight%28%28-x%2B10%29%29=50 Plug in y=-x%2B10 into the first equation. In other words, replace each y with -x%2B10. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



6x%2B%284%29%28-1%29x%2B%284%29%2810%29=50 Distribute 4 to -x%2B10


6x-4x%2B40=50 Multiply


2x%2B40=50 Combine like terms on the left side


2x=50-40Subtract 40 from both sides


2x=10 Combine like terms on the right side


x=%2810%29%2F%282%29 Divide both sides by 2 to isolate x



x=5 Divide





-----------------First Answer------------------------------


So the first part of our answer is: x=5









Since we know that x=5 we can plug it into the equation y=-x%2B10 (remember we previously solved for y in the first equation).



y=-x%2B10 Start with the equation where y was previously isolated.


y=-%285%29%2B10 Plug in x=5


y=-5%2B10 Multiply


y=5 Combine like terms



-----------------Second Answer------------------------------


So the second part of our answer is: y=5









-----------------Summary------------------------------

So our answers are:

x=5 and y=5


This means that you bought 5 $6 movies and 5 $4 movies


Linear-equations/153233: c=2n+20
1 solutions

Answer 112768 by jim_thompson5910(28595) About Me  on 2008-08-24 17:42:36 (Show Source):
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What do you want to do with this equation? Do you want to solve for n?

c=2n%2B20 Start with the given equation.


c-20=2n Subtract 20 from both sides.


%28c-20%29%2F2=n Divide both sides by 2.


n=%28c-20%29%2F2 Rearrange the equation


Polynomials-and-rational-expressions/153238: (3u^2v – 2)(4u^2v + 6)
this is what I got...but to be honest i'm confused a little.
(3u^2v – 2)(4u^2v + 6)
12u^2v + 18u^2v
8u^2v - 12
12u^2v + 26u^2v – 12
38u^4v^2 – 12

1 solutions

Answer 112767 by jim_thompson5910(28595) About Me  on 2008-08-24 17:40:58 (Show Source):
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%283u%5E2v-2%29%284u%5E2v%2B6%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%283u%5E2v%29-2%29%28highlight%284u%5E2v%29%2B6%29 Multiply the First terms:%283%2Au%5E2%2Av%29%2A%284%2Au%5E2%2Av%29=12%2Au%5E4%2Av%5E2.


%28highlight%283u%5E2v%29-2%29%284u%5E2v%2Bhighlight%286%29%29 Multiply the Outer terms:%283%2Au%5E2%2Av%29%2A%286%29=18%2Au%5E2%2Av.


%283u%5E2v%2Bhighlight%28-2%29%29%28highlight%284u%5E2v%29%2B6%29 Multiply the Inner terms:%28-2%29%2A%284%2Au%5E2%2Av%29=-8%2Au%5E2%2Av.


%283u%5E2v%2Bhighlight%28-2%29%29%284u%5E2v%2Bhighlight%286%29%29 Multiply the Last terms:%28-2%29%2A%286%29=-12.


12%2Au%5E4%2Av%5E2%2B18%2Au%5E2%2Av-8%2Au%5E2%2Av-12 Now collect every term to make a single expression.


12%2Au%5E4%2Av%5E2%2B10%2Au%5E2%2Av-12 Now combine like terms.


So %283u%5E2v-2%29%284u%5E2v%2B6%29 FOILs to 12%2Au%5E4%2Av%5E2%2B10%2Au%5E2%2Av-12.


In other words, %283u%5E2v-2%29%284u%5E2v%2B6%29=12u%5E4v%5E2%2B10u%5E2v-12.


Expressions-with-variables/153182: B 2b
----+----
b-1 b squared - 1
1 solutions

Answer 112764 by jim_thompson5910(28595) About Me  on 2008-08-24 17:32:30 (Show Source):
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b%2F%28b-1%29%2B%282b%29%2F%28b%5E2-1%29 Start with the given expression.


b%2F%28b-1%29%2B%282b%29%2F%28%28b-1%29%28b%2B1%29%29 Factor b%5E2-1 to get %28b-1%29%28b%2B1%29. Notice how the LCD is %28b-1%29%28b%2B1%29


%28%28b%2B1%29%2F%28b%2B1%29%29%28b%2F%28b-1%29%29%2B%282b%29%2F%28%28b-1%29%28b%2B1%29%29 Multiply the first term by %28b%2B1%29%2F%28b%2B1%29. The goal is to get the first denominator equal to the LCD %28b-1%29%28b%2B1%29


%28b%28b%2B1%29%29%2F%28%28b-1%29%28b%2B1%29%29%2B%282b%29%2F%28%28b-1%29%28b%2B1%29%29 Combine the fractions.


%28b%5E2%2Bb%29%2F%28%28b-1%29%28b%2B1%29%29%2B%282b%29%2F%28%28b-1%29%28b%2B1%29%29 Distribute


%28b%5E2%2Bb%2B2b%29%2F%28%28b-1%29%28b%2B1%29%29 Add the fractions.


%28b%5E2%2B3b%29%2F%28%28b-1%29%28b%2B1%29%29 Combine like terms.


So b%2F%28b-1%29%2B%282b%29%2F%28b%5E2-1%29=%28b%5E2%2B3b%29%2F%28%28b-1%29%28b%2B1%29%29 where b%3C%3E-1 or b%3C%3E1


Graphs/153223: on my book i have this question
graph the inequality
x>-2
and i dont get it can you help me
ohh and it asks for the open or close dot
cant you explain that to me

1 solutions

Answer 112763 by jim_thompson5910(28595) About Me  on 2008-08-24 17:27:22 (Show Source):
You can put this solution on YOUR website!


Start with the given inequality


Plot the point x=-2 on a number line

number_line%28+500%2C+-12%2C+8%2C+-2+%29


Now plug in x=0 into the inequality





Since is true, this means that we shade the entire region that x=0 is in.


So shade to the right of x=-2 . Note: there is a open circle at x=-2



Exponential-and-logarithmic-functions/153228: This question is from textbook elementary and intermediate algebra
Simplify and write with positive exponents:
7yx^-5
______
28y^-5


Simplify and write with positive exponents
x^-4 y^5
________
z^-1

Evaluate (1/3)^2 + 1/4 -(4/3)^2 * (1/2)^3

Evaluate 2*(5 - 3)^3 + 8 ÷ 2 + (9 - 4)^2

Evaluate {3(7 - 9) + 16}^3 ÷ (-5) - 2^4

Thanks everyone for your help. :)
1 solutions

Answer 112761 by jim_thompson5910(28595) About Me  on 2008-08-24 17:23:51 (Show Source):
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# 1



%287yx%5E-5%29%2F%2828y%5E-5%29 Start with the given expression.


%281%2F4%29%28yx%5E-5%2Fy%5E-5%29 Divide the coefficients 7 and 28 to get 1%2F4


%281%2F4%29x%5E%28-5%29y%5E%281--5%29 When you divide monomials, simply subtract the exponents.


%281%2F4%29x%5E%28-5%29y%5E6 Subtract.


%281%2F4%29%28y%5E6%2Fx%5E5%29 Rewrite x%5E%28-5%29 as 1%2Fx%5E5


%28y%5E6%29%2F%284x%5E5%29 Combine the fractions.


So %287y%2Ax%5E%28-5%29%29%2F%2828y%5E%28-5%29%29=%28y%5E6%29%2F%284x%5E5%29 where x%3C%3E0 or y%3C%3E0







# 2

Note: x%5E%28-4%29=1%2Fx%5E4 and z%5E%28-1%29=1%2Fz%5E1=1%2Fz


So where x%3C%3E0 and z%3C%3E0







# 3



So %281%2F3%29%5E2+%2B+1%2F4+-%284%2F3%29%5E2+%2A+%281%2F2%29%5E3=5%2F36






# 4




So %282%2A%285+-+3%29%5E3+%2B+8%29+%2F%28+2+%2B+%289+-+4%29%5E2%29+=+8%2F9





# 5



So %28%283%287+-+9%29+%2B+16%29%5E3%29%2F%28-5+-+2%5E4%29=-1000%2F21


Polynomials-and-rational-expressions/153225: For all r not equal to + or - 2, r^2-5r+6/r^2-4
1 solutions

Answer 112759 by jim_thompson5910(28595) About Me  on 2008-08-24 17:10:03 (Show Source):
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%28r%5E2-5r%2B6%29%2F%28r%5E2-4%29 Start with the given expression.


%28%28r-2%29%28r-3%29%29%2F%28r%5E2-4%29 Factor r%5E2-5r%2B6 to get %28r-2%29%28r-3%29.


%28%28r-2%29%28r-3%29%29%2F%28%28r-2%29%28r%2B2%29%29 Factor r%5E2-4 to get %28r-2%29%28r%2B2%29.


%28highlight%28%28r-2%29%29%28r-3%29%29%2F%28highlight%28%28r-2%29%29%28r%2B2%29%29 Highlight the common terms.


%28cross%28%28r-2%29%29%28r-3%29%29%2F%28cross%28%28r-2%29%29%28r%2B2%29%29 Cancel out the common terms.


%28r-3%29%2F%28r%2B2%29 Simplify.


So %28r%5E2-5r%2B6%29%2F%28r%5E2-4%29 simplifies to %28r-3%29%2F%28r%2B2%29.


In other words, %28r%5E2-5r%2B6%29%2F%28r%5E2-4%29=%28r-3%29%2F%28r%2B2%29 where r%3C%3E-2 or r%3C%3E2


Triangles/153234: what is the perimeter of a triangle which sides measure 6,8,and 10 inches?
1 solutions

Answer 112758 by jim_thompson5910(28595) About Me  on 2008-08-24 17:07:55 (Show Source):
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Perimeter of a triangle:

P=side1+side2+side3

P=6+8+10=14+10=24


So the perimeter of the triangle is 24 inches


Functions/153214: This question is from textbook
find a function formula that takes the x values and produces the y values
x y
0 -2
1 1
2 4
3 7
4 10
I will send a check for your help can you give me a mailing address
1 solutions

Answer 112747 by jim_thompson5910(28595) About Me  on 2008-08-24 14:56:14 (Show Source):
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Notice how as x goes up by 1, y goes up by 3. So this implies a linear relationship. This means that the equation is a line.



So let's find equation of the line through the first two points (0,-2) and (1,1) (note: you can pick any pair of points)




First let's find the slope of the line through the points and


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%281--2%29%2F%281-0%29 Plug in y%5B2%5D=1, y%5B1%5D=-2, x%5B2%5D=1, x%5B1%5D=0, ,


m=%283%29%2F%281-0%29 Subtract -2 from 1 to get 3


m=%283%29%2F%281%29 Subtract 0 from 1 to get 1


m=3 Reduce


So the slope of the line that goes through the points and is m=3


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y--2=3%28x-0%29 Plug in m=3, x%5B1%5D=0, and y%5B1%5D=-2


y%2B2=3%28x-0%29 Rewrite y--2 as y%2B2


y%2B2=3x%2B3%28-0%29 Distribute


y%2B2=3x%2B0 Multiply


y=3x%2B0-2 Subtract 2 from both sides.


y=3x-2 Combine like terms.


y=3x-2 Simplify


So the equation that goes through the points and is y=3x-2


--------------------------------------

Answer:

So the function takes the x values and produces the y values is f%28x%29=3x-2


Notice how the graph of f%28x%29=3x-2 goes through the points (0,-2), (1,1), (2,4), (3,7) and (4,10). So this visually verifies our answer.


Graph of y=3x-2


Linear-equations/153217: Find the slope of the line containing the points (2,5) and (4,9).
1 solutions

Answer 112745 by jim_thompson5910(28595) About Me  on 2008-08-24 14:50:43 (Show Source):
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m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%289-5%29%2F%284-2%29 Plug in y%5B2%5D=9, y%5B1%5D=5, x%5B2%5D=4, x%5B1%5D=2, ,


m=%284%29%2F%284-2%29 Subtract 5 from 9 to get 4


m=%284%29%2F%282%29 Subtract 2 from 4 to get 2


m=2 Reduce


So the slope of the line that goes through the points and is m=2


Graphs/153218: Find the equation of the line in point slope form that passes through (4,3)and is parallel to the line 3x-y=7.
1 solutions

Answer 112743 by jim_thompson5910(28595) About Me  on 2008-08-24 14:49:42 (Show Source):
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3x-y=7 Start with the given equation.


-y=7-3x Subtract 3x from both sides.


-y=-3x%2B7 Rearrange the terms.


y=%28-3x%2B7%29%2F%28-1%29 Divide both sides by -1 to isolate y.


y=%28%28-3%29%2F%28-1%29%29x%2B%287%29%2F%28-1%29 Break up the fraction.


y=3x-7 Reduce.


We can see that the equation y=3x-7 has a slope m=3 and a y-intercept b=-7.


Since parallel lines have equal slopes, this means that we know that the slope of the unknown parallel line is m=3.
Now let's use the point slope formula to find the equation of the parallel line by plugging in the slope m=3 and the coordinates of the given point .


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-3=3%28x-4%29 Plug in m=3, x%5B1%5D=4, and y%5B1%5D=3


y-3=3x%2B3%28-4%29 Distribute


y-3=3x-12 Multiply


y=3x-12%2B3 Add 3 to both sides.


y=3x-9 Combine like terms.


So the equation of the line parallel to 3x-y=7 that goes through the point is y=3x-9.


Here's a graph to visually verify our answer:
Graph of the original equation y=3%2Ax-7 (red) and the parallel line y=3x-9 (green) through the point .


Linear_Algebra/153216: two lines are parallel if and only if their slopes are _____________.
1 solutions

Answer 112741 by jim_thompson5910(28595) About Me  on 2008-08-24 14:48:36 (Show Source):
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Two lines are parallel if and only if their slopes are equal.


Angles/153211: Find the surface area and volume of a sphere with a radius of 14cm.
Thanks,
Pat
1 solutions

Answer 112739 by jim_thompson5910(28595) About Me  on 2008-08-24 14:19:18 (Show Source):
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Surface Area:

Solved by pluggable solver: To calculate Surface area of a sphere

Geometry Surface Area and Volume of 3 Dimensional Figures
The Formula for Surface area Sphere is
Area=4%2Api%2Aradius%2Aradius
Area=4%2Api%2A14%2A14=2463.0086376


Hence, The Surface Area of Sphere of radius 14 is 2463.0086376.


For more on this topic, See the lessons on Geometry: Area and Surface Area

Some more is on Surface Area and Volume and Perimeter and Area.




Volume:

Solved by pluggable solver: FIND volume of a sphere
Volume of a sphere V=%284%2F3%29%2Api%2Ar%5E3+=+%284%2F3%29%2Api%2A14%5E3+=+11494.0401258667


Angles/153212: Find the surface area of a circular cylinder with radius of 4cm and a height of 10.2cm.
1 solutions

Answer 112738 by jim_thompson5910(28595) About Me  on 2008-08-24 14:17:42 (Show Source):
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Solved by pluggable solver: Surface area and Volume of a cylinder
The surface area (SA) of a cylinder, excluding the base area and top area, is given by
SA+=+2%2Api%2AR%2AH

When the areas of base and top are included, the surface area becomes
SA+=+2%2Api%2AR%2AH+%2B+2%2Api%2AR%5E2
SA+=+2%2Api%2AR%2A%28R%2BH%29

The volume of the cone can be found by the formula
V+=+pi%2AR%5E2%2AH


In our case the desired values are thus:

SA (without base and top) = 2%2Api%2A4%2A10.2+=+256.35396024
SA (with base and top) = 2%2Api%2A4%2A10.2+%2B+2%2Api%2A4%5E2+=+356.88492504
V = pi%2A4%5E2%2A10.2+=+512.70792048


For more on this topic, refer to Surface area and Volume.


Polynomials-and-rational-expressions/153196: simplify:
[-(-2x^2)^2]^3

1 solutions

Answer 112736 by jim_thompson5910(28595) About Me  on 2008-08-24 14:12:07 (Show Source):
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[-(-2x^2)^2]^3 = [-(-2x^2)(-2x^2)]^3 
               = [-(4x^4)]^3
               = [-4x^4]^3
               = -64x^12




Polynomials-and-rational-expressions/153197: simpify:
-4[5x-6(-5+x)]


1 solutions

Answer 112734 by jim_thompson5910(28595) About Me  on 2008-08-24 14:10:29 (Show Source):
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-4[5x-6(-5+x)] = -4[5x+30-6x]
               = -4[-x+30]
               = 4x-120




Polynomials-and-rational-expressions/153194: simplify:
(2x^3+2x^2-3x+2) / (x+2)

thanks
1 solutions

Answer 112733 by jim_thompson5910(28595) About Me  on 2008-08-24 14:08:54 (Show Source):
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Let's simplify this expression using synthetic division


Start with the given expression %282x%5E3+%2B+2x%5E2+-+3x+%2B+2%29%2F%28x%2B2%29

First lets find our test zero:

x%2B2=0 Set the denominator x%2B2 equal to zero

x=-2 Solve for x.

so our test zero is -2


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
-2|22-32
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 2)
-2|22-32
|
2

Multiply -2 by 2 and place the product (which is -4) right underneath the second coefficient (which is 2)
-2|22-32
|-4
2

Add -4 and 2 to get -2. Place the sum right underneath -4.
-2|22-32
|-4
2-2

Multiply -2 by -2 and place the product (which is 4) right underneath the third coefficient (which is -3)
-2|22-32
|-44
2-2

Add 4 and -3 to get 1. Place the sum right underneath 4.
-2|22-32
|-44
2-21

Multiply -2 by 1 and place the product (which is -2) right underneath the fourth coefficient (which is 2)
-2|22-32
|-44-2
2-21

Add -2 and 2 to get 0. Place the sum right underneath -2.
-2|22-32
|-44-2
2-210

Since the last column adds to zero, we have a remainder of zero. This means x%2B2 is a factor of 2x%5E3+%2B+2x%5E2+-+3x+%2B+2

Now lets look at the bottom row of coefficients:

The first 3 coefficients (2,-2,1) form the quotient

2x%5E2+-+2x+%2B+1


So %282x%5E3+%2B+2x%5E2+-+3x+%2B+2%29%2F%28x%2B2%29=2x%5E2+-+2x+%2B+1


Inequalities/153199: for what value of x will k(x)=4x-16 be greater than zero
1 solutions

Answer 112731 by jim_thompson5910(28595) About Me  on 2008-08-24 14:07:30 (Show Source):
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k%28x%29=4x-16 Start with the given equation.


4x-16%3E0 Set the right side greater than zero.


4x%3E0%2B16 Add 16 to both sides.


4x%3E16 Combine like terms on the right side.


x%3E%2816%29%2F%284%29 Divide both sides by 4 to isolate x.


x%3E4 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x%3E4 which means that any value of x that is greater than 4 will make k%28x%29 greater than zero.


Inequalities/153202: For what value(s)of x will k(x)=4x-16 be grater than Zero
1 solutions

Answer 112730 by jim_thompson5910(28595) About Me  on 2008-08-24 14:06:59 (Show Source):
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k%28x%29=4x-16 Start with the given equation.


4x-16%3E0 Set the right side greater than zero.


4x%3E0%2B16 Add 16 to both sides.


4x%3E16 Combine like terms on the right side.


x%3E%2816%29%2F%284%29 Divide both sides by 4 to isolate x.


x%3E4 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x%3E4 which means that any value of x that is greater than 4 will make k%28x%29 greater than zero.


Linear-systems/153208: how do you solve y= 1/3x - 3 and y= -2x + 4 algebraically?
this is the question;
Solve the above system of equations algebraically, use the elimination or substitution method.
PLEASE HELP!!!!
1 solutions

Answer 112729 by jim_thompson5910(28595) About Me  on 2008-08-24 14:05:15 (Show Source):
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y=+%281%2F3%29x+-+3 Start with the first equation.


+-2x+%2B+4=+%281%2F3%29x+-+3 Plug in y=+-2x+%2B+4


3%28-2x%2B4%29=3%28%281%2Fcross%283%29%29x-3%29 Multiply both sides by the LCD 3 to clear any fractions.


-6x%2B12=x-9 Distribute and multiply.


-6x=x-9-12 Subtract 12 from both sides.


-6x-x=-9-12 Subtract x from both sides.


-7x=-9-12 Combine like terms on the left side.


-7x=-21 Combine like terms on the right side.


x=%28-21%29%2F%28-7%29 Divide both sides by -7 to isolate x.


x=3 Reduce. This is the first part of our answer.


y=+-2x+%2B+4 Move onto the second equation


y=+-2%283%29+%2B+4 Plug in x=3


y=+-2 Simplify. This is the second part of our answer.


---------------------------------------------

Answer:

So the solutions are x=3 and y=+-2 which form the ordered pair (3,-2)


Functions/153209: Can someone help me out, please? Thank you!

The owners of a parking garage have determined that their weekly revenue and cost in dollars are given by the following:
R(x) = 56x - 2x^2
C(x) = 24x + 101
find the break even point.
1 solutions

Answer 112727 by jim_thompson5910(28595) About Me  on 2008-08-24 14:00:55 (Show Source):
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Remember,

Profit = Revenue - Cost

which is symbolically:


P%28x%29=R%28x%29-C%28x%29


P%28x%29=%2856x+-+2x%5E2%29-%2824x+%2B+101%29 Plug in R%28x%29+=+56x+-+2x%5E2 and C%28x%29+=+24x+%2B+101+


P%28x%29=56x+-+2x%5E2-24x+-+101 Distribute the negative.


P%28x%29=-2x%5E2%2B32x-101 Combine like terms


Now the break even point occurs when you neither gain money nor lose money. In other words, break even point happens when the profit is zero. So this means that the break even point occurs when P%28x%29=0


0=-2x%5E2%2B32x-101 Plug in P%28x%29=0


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=-2, b=32, and c=-101


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%2832%29+%2B-+sqrt%28+%2832%29%5E2-4%28-2%29%28-101%29+%29%29%2F%282%28-2%29%29 Plug in a=-2, b=32, and c=-101


x+=+%28-32+%2B-+sqrt%28+1024-4%28-2%29%28-101%29+%29%29%2F%282%28-2%29%29 Square 32 to get 1024.


x+=+%28-32+%2B-+sqrt%28+1024-808+%29%29%2F%282%28-2%29%29 Multiply 4%28-2%29%28-101%29 to get 808


x+=+%28-32+%2B-+sqrt%28+216+%29%29%2F%282%28-2%29%29 Subtract 808 from 1024 to get 216


x+=+%28-32+%2B-+sqrt%28+216+%29%29%2F%28-4%29 Multiply 2 and -2 to get -4.


x+=+%28-32+%2B-+6%2Asqrt%286%29%29%2F%28-4%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x+=+%28-32%2B6%2Asqrt%286%29%29%2F%28-4%29 or x+=+%28-32-6%2Asqrt%286%29%29%2F%28-4%29 Break up the expression.


So the answers are x+=+%28-32%2B6%2Asqrt%286%29%29%2F%28-4%29 or x+=+%28-32-6%2Asqrt%286%29%29%2F%28-4%29


which approximate to x=4.33 or x=11.67


So the break even points occur when the price is either $4.33 or $11.67