See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'jim_thompson5910'

jim_thompson5910 answered: 28705 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069 , 17070..17099 , 17100..17129 , 17130..17159 , 17160..17189 , 17190..17219 , 17220..17249 , 17250..17279 , 17280..17309 , 17310..17339 , 17340..17369 , 17370..17399 , 17400..17429 , 17430..17459 , 17460..17489 , 17490..17519 , 17520..17549 , 17550..17579 , 17580..17609 , 17610..17639 , 17640..17669 , 17670..17699 , 17700..17729 , 17730..17759 , 17760..17789 , 17790..17819 , 17820..17849 , 17850..17879 , 17880..17909 , 17910..17939 , 17940..17969 , 17970..17999 , 18000..18029 , 18030..18059 , 18060..18089 , 18090..18119 , 18120..18149 , 18150..18179 , 18180..18209 , 18210..18239 , 18240..18269 , 18270..18299 , 18300..18329 , 18330..18359 , 18360..18389 , 18390..18419 , 18420..18449 , 18450..18479 , 18480..18509 , 18510..18539 , 18540..18569 , 18570..18599 , 18600..18629 , 18630..18659 , 18660..18689 , 18690..18719 , 18720..18749 , 18750..18779 , 18780..18809 , 18810..18839 , 18840..18869 , 18870..18899 , 18900..18929 , 18930..18959 , 18960..18989 , 18990..19019 , 19020..19049 , 19050..19079 , 19080..19109 , 19110..19139 , 19140..19169 , 19170..19199 , 19200..19229 , 19230..19259 , 19260..19289 , 19290..19319 , 19320..19349 , 19350..19379 , 19380..19409 , 19410..19439 , 19440..19469 , 19470..19499 , 19500..19529 , 19530..19559 , 19560..19589 , 19590..19619 , 19620..19649 , 19650..19679 , 19680..19709 , 19710..19739 , 19740..19769 , 19770..19799 , 19800..19829 , 19830..19859 , 19860..19889 , 19890..19919 , 19920..19949 , 19950..19979 , 19980..20009 , 20010..20039 , 20040..20069 , 20070..20099 , 20100..20129 , 20130..20159 , 20160..20189 , 20190..20219 , 20220..20249 , 20250..20279 , 20280..20309 , 20310..20339 , 20340..20369 , 20370..20399 , 20400..20429 , 20430..20459 , 20460..20489 , 20490..20519 , 20520..20549 , 20550..20579 , 20580..20609 , 20610..20639 , 20640..20669 , 20670..20699 , 20700..20729 , 20730..20759 , 20760..20789 , 20790..20819 , 20820..20849 , 20850..20879 , 20880..20909 , 20910..20939 , 20940..20969 , 20970..20999 , 21000..21029 , 21030..21059 , 21060..21089 , 21090..21119 , 21120..21149 , 21150..21179 , 21180..21209 , 21210..21239 , 21240..21269 , 21270..21299 , 21300..21329 , 21330..21359 , 21360..21389 , 21390..21419 , 21420..21449 , 21450..21479 , 21480..21509 , 21510..21539 , 21540..21569 , 21570..21599 , 21600..21629 , 21630..21659 , 21660..21689 , 21690..21719 , 21720..21749 , 21750..21779 , 21780..21809 , 21810..21839 , 21840..21869 , 21870..21899 , 21900..21929 , 21930..21959 , 21960..21989 , 21990..22019 , 22020..22049 , 22050..22079 , 22080..22109 , 22110..22139 , 22140..22169 , 22170..22199 , 22200..22229 , 22230..22259 , 22260..22289 , 22290..22319 , 22320..22349 , 22350..22379 , 22380..22409 , 22410..22439 , 22440..22469 , 22470..22499 , 22500..22529 , 22530..22559 , 22560..22589 , 22590..22619 , 22620..22649 , 22650..22679 , 22680..22709 , 22710..22739 , 22740..22769 , 22770..22799 , 22800..22829 , 22830..22859 , 22860..22889 , 22890..22919 , 22920..22949 , 22950..22979 , 22980..23009 , 23010..23039 , 23040..23069 , 23070..23099 , 23100..23129 , 23130..23159 , 23160..23189 , 23190..23219 , 23220..23249 , 23250..23279 , 23280..23309 , 23310..23339 , 23340..23369 , 23370..23399 , 23400..23429 , 23430..23459 , 23460..23489 , 23490..23519 , 23520..23549 , 23550..23579 , 23580..23609 , 23610..23639 , 23640..23669 , 23670..23699 , 23700..23729 , 23730..23759 , 23760..23789 , 23790..23819 , 23820..23849 , 23850..23879 , 23880..23909 , 23910..23939 , 23940..23969 , 23970..23999 , 24000..24029 , 24030..24059 , 24060..24089 , 24090..24119 , 24120..24149 , 24150..24179 , 24180..24209 , 24210..24239 , 24240..24269 , 24270..24299 , 24300..24329 , 24330..24359 , 24360..24389 , 24390..24419 , 24420..24449 , 24450..24479 , 24480..24509 , 24510..24539 , 24540..24569 , 24570..24599 , 24600..24629 , 24630..24659 , 24660..24689 , 24690..24719 , 24720..24749 , 24750..24779 , 24780..24809 , 24810..24839 , 24840..24869 , 24870..24899 , 24900..24929 , 24930..24959 , 24960..24989 , 24990..25019 , 25020..25049 , 25050..25079 , 25080..25109 , 25110..25139 , 25140..25169 , 25170..25199 , 25200..25229 , 25230..25259 , 25260..25289 , 25290..25319 , 25320..25349 , 25350..25379 , 25380..25409 , 25410..25439 , 25440..25469 , 25470..25499 , 25500..25529 , 25530..25559 , 25560..25589 , 25590..25619 , 25620..25649 , 25650..25679 , 25680..25709 , 25710..25739 , 25740..25769 , 25770..25799 , 25800..25829 , 25830..25859 , 25860..25889 , 25890..25919 , 25920..25949 , 25950..25979 , 25980..26009 , 26010..26039 , 26040..26069 , 26070..26099 , 26100..26129 , 26130..26159 , 26160..26189 , 26190..26219 , 26220..26249 , 26250..26279 , 26280..26309 , 26310..26339 , 26340..26369 , 26370..26399 , 26400..26429 , 26430..26459 , 26460..26489 , 26490..26519 , 26520..26549 , 26550..26579 , 26580..26609 , 26610..26639 , 26640..26669 , 26670..26699 , 26700..26729 , 26730..26759 , 26760..26789 , 26790..26819 , 26820..26849 , 26850..26879 , 26880..26909 , 26910..26939 , 26940..26969 , 26970..26999 , 27000..27029 , 27030..27059 , 27060..27089 , 27090..27119 , 27120..27149 , 27150..27179 , 27180..27209 , 27210..27239 , 27240..27269 , 27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499 , 28500..28529 , 28530..28559 , 28560..28589 , 28590..28619 , 28620..28649 , 28650..28679 , 28680..28709, >>Next

Equations/165615: This question is from textbook Amscos Integrated Algebra 1
1/2t-6+8(t-9+7)=4t*3-5+2+3/4t
1 solutions

Answer 122082 by jim_thompson5910(28717) About Me  on 2008-11-03 19:08:39 (Show Source):
You can put this solution on YOUR website!
%281%2F2%29t-6%2B8%28t-9%2B7%29=4t%2A3-5%2B2%2B%283%2F4%29t Start with the given equation


%281%2F2%29t-6%2B8%28t-9%2B7%29=12t-5%2B2%2B%283%2F4%29t Multiply


%281%2F2%29t-6%2B8t-72%2B56=12t-5%2B2%2B%283%2F4%29t Distribute.


4%28%281%2Fcross%282%29%29t-6%2B8t-72%2B56%29=4%2812t-5%2B2%2B%283%2Fcross%284%29%29t%29 Multiply both sides by the LCD 4 to clear any fractions.


2t-24%2B32t-288%2B224=48t-20%2B8%2B3t Distribute and multiply.


-88%2B34t=48t-20%2B8%2B3t Combine like terms on the left side.


-88%2B34t=-12%2B51t Combine like terms on the right side.


34t=-12%2B51t%2B88 Add 88 to both sides.


34t-51t=-12%2B88 Subtract 51t from both sides.


-17t=-12%2B88 Combine like terms on the left side.


-17t=76 Combine like terms on the right side.


t=%2876%29%2F%28-17%29 Divide both sides by -17 to isolate t.


t=-76%2F17 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is t=-76%2F17 which approximates to t=-4.471.


Linear-systems/165439: Solve the system by addition or substitution.
-9x - 3y = 22
y = -3x - 6
1 solutions

Answer 121954 by jim_thompson5910(28717) About Me  on 2008-11-03 00:12:53 (Show Source):
You can put this solution on YOUR website!

Start with the given system
-9x-3y=22
y=-3x-6



-9x-3%28-3x-6%29=22 Plug in y=-3x-6 into the first equation. In other words, replace each y with -3x-6. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.


-9x%2B9x%2B18=22 Distribute


18=22 Combine like terms on the left side


0=22-18Subtract 18 from both sides


0=4 Combine like terms on the right side


Since this equation is never true for any x value, this means there are no solutions.


Linear-systems/165449: Solve the system by graphing.
x + y = 3
x + y = -1
1 solutions

Answer 121953 by jim_thompson5910(28717) About Me  on 2008-11-03 00:09:23 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:


system%28x%2By=3%2Cx%2By=-1%29


In order to graph these equations, we must solve for y first.


Let's graph the first equation:


x%2By=3 Start with the first equation.


y=3-x Subtract x from both sides.


y=-x%2B3 Rearrange the terms and simplify.


Now let's graph the equation:


Graph of y=-x%2B3.


-------------------------------------------------------------------


Now let's graph the second equation:


x%2By=-1 Start with the second equation.


y=-1-x Subtract x from both sides.


y=-x-1 Rearrange the terms and simplify.


Now let's graph the equation:


Graph of y=-x-1.


-------------------------------------------------------------------


Now let's graph the two equations together:


Graph of y=-x%2B3 (red). Graph of y=-x-1 (green)


From the graph, we can see that the two lines are parallel, which means that they will never intersect. So there are no solutions. This means that the system of equations is inconsistent.


logarithm/165416: This is not from a textbook, just from a worksheet my teacher made up.
The question is : 4logx = 4
I think that you can move the first 4 to make the question logx^4=4 , but that is as far as I have gotten.
Thank You For Your Help!
1 solutions

Answer 121913 by jim_thompson5910(28717) About Me  on 2008-11-02 19:36:31 (Show Source):
You can put this solution on YOUR website!
Note: I'm assuming that the base is 10


4%2Alog%2810%2C%28x%29%29=4 Start with the given equation


%28cross%284%29%2Alog%2810%2C%28x%29%29%29%2F%28cross%284%29%29=cross%284%29%2Fcross%284%29 Divide both sides by 4


log%2810%2C%28x%29%29=1 Divide and simplify


10%5E1=x Rewrite the equation using the property: log%28b%2C%28x%29%29=y ====> b%5Ey=x


10=x Raise 10 to the first power to get 10


So the solution is x=10


Rational-functions/165403: Find all horizontal/vertical asymptotes and all x-intercepts:
%28x%5E2-5x%2B6%29%2F%28x-1%29
1 solutions

Answer 121908 by jim_thompson5910(28717) About Me  on 2008-11-02 19:33:28 (Show Source):
You can put this solution on YOUR website!
x-intercepts:


y=%28x%5E2-5x%2B6%29%2F%28x-1%29%29 Start with the given equation


0=%28x%5E2-5x%2B6%29%2F%28x-1%29%29 Plug in y=0


x%5E2-5x%2B6=0 Set the numerator equal to zero


%28x-3%29%28x-2%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:
x-3=0 or x-2=0

x=3 or x=2 Now solve for x in each case


So our answers are

x=3 or x=2



So the x-intercepts are (3,0) and (2,0)


===========================================================
Asymptotes:

Looking at the numerator x%5E2-5x%2B6, we can see that the degree is 2 since the highest exponent of the numerator is 2. For the denominator x-1, we can see that the degree is 1 since the highest exponent of the denominator is 1.


Oblique Asymptote:

Since the degree of the numerator (which is 2) is greater than the degree of the denominator (which is 1), there is no horizontal asymptote. In this case, there's an oblique asymptote.


To find the oblique asymptote, simply use polynomial long division to find it.


Photobucket - Video and Image Hosting



So the quotient is x-4, this means that the oblique asymptote is y=x-4




--------------------------------------------------



Vertical Asymptote:
To find the vertical asymptote, just set the denominator equal to zero and solve for x

x-1=0 Set the denominator equal to zero


x=0%2B1Add 1 to both sides


x=1 Combine like terms on the right side


So the vertical asymptote is x=1


Notice if we graph y=%28x%5E2-5x%2B6%29%2F%28x-1%29, we can visually verify our answers:

Graph of y=%28x%5E2-5x%2B6%29%2F%28x-1%29%29 with the x-intercepts (3,0) and (2,0), the oblique asymptote y=x-4 (blue line) and the vertical asymptote x=1 (green line)


Linear-systems/165385: This question is from textbook Algebra 2
How do you use substitution to solve each system of equations.
{12x+y=21
{18x-3y=-36
1 solutions

Answer 121891 by jim_thompson5910(28717) About Me  on 2008-11-02 17:42:25 (Show Source):
You can put this solution on YOUR website!
Start with the given system of equations:

system%2812x%2By=21%2C18x-3y=-36%29



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the first equation

12x%2By=21 Start with the first equation


y=21-12x Subtract 12x from both sides


y=-12x%2B21 Rearrange the equation


---------------------

Since y=-12x%2B21, we can now replace each y in the second equation with -12x%2B21 to solve for x



18x-3highlight%28%28-12x%2B21%29%29=-36 Plug in y=-12x%2B21 into the second equation. In other words, replace each y with -12x%2B21. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



18x%2B%28-3%29%28-12%29x%2B%28-3%29%2821%29=-36 Distribute -3 to -12x%2B21


18x%2B36x-63=-36 Multiply


54x-63=-36 Combine like terms on the left side


54x=-36%2B63Add 63 to both sides


54x=27 Combine like terms on the right side


x=%2827%29%2F%2854%29 Divide both sides by 54 to isolate x



x=1%2F2 Reduce





-----------------First Answer------------------------------


So the first part of our answer is: x=1%2F2









Since we know that x=1%2F2 we can plug it into the equation y=-12x%2B21 (remember we previously solved for y in the first equation).



y=-12x%2B21 Start with the equation where y was previously isolated.


y=-12%281%2F2%29%2B21 Plug in x=1%2F2


y=-12%2F2%2B21 Multiply


y=15 Combine like terms and reduce. (note: if you need help with fractions, check out this solver)



-----------------Second Answer------------------------------


So the second part of our answer is: y=15









-----------------Summary------------------------------

So our answers are:

x=1%2F2 and y=15

which form the ordered pair



Functions/165387: This is my problem and I believe I have the answer (C(x))=3x+27,000 but I don't know the proper process for illustrating this. Please help!
# If the relationship between the total cost and the number of units produced is linear and if the total cost increases by $3 for each additional unit made:
1. Find the equation of the total cost function C(x) using the fact that C(1,000) = 30,000 (dollars) where x is the number of units produced.
1 solutions

Answer 121890 by jim_thompson5910(28717) About Me  on 2008-11-02 17:39:43 (Show Source):
You can put this solution on YOUR website!
Since the "total cost increases by $3 for each additional unit made", this means that the slope is m=3. Also, because C(1,000) = 30,000 , this means that we have the point (1000,30000).


So let's find the equation of the line that has a slope of 3 and goes through the point (1000,30000)


If you want to find the equation of line with a given a slope of 3 which goes through the point (1000,30000), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y-30000=%283%29%28x-1000%29 Plug in m=3, x%5B1%5D=1000, and y%5B1%5D=30000 (these values are given)


y-30000=3x%2B%283%29%28-1000%29 Distribute 3

y-30000=3x-3000 Multiply 3 and -1000 to get -3000

y=3x-3000%2B30000 Add 30000 to both sides to isolate y

y=3x%2B27000 Combine like terms -3000 and 30000 to get 27000
------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line with a slope of 3 which goes through the point (1000,30000) is:

y=3x%2B27000 which is now in y=mx%2Bb form where the slope is m=3 and the y-intercept is b=27000


So in function notation, the cost function is C%28x%29=3x%2B27000. So you are correct.


Polynomials-and-rational-expressions/165290: f(x)=4x^3-3x^2+2x-1. Find f(1+2i). Please help me out, I really don't have any idea on what to do!!!
1 solutions

Answer 121859 by jim_thompson5910(28717) About Me  on 2008-11-02 12:14:27 (Show Source):
You can put this solution on YOUR website!
Note: it's helpful to remember that i%5E2=-1


f%28x%29=4x%5E3-3x%5E2%2B2x-1 Start with the given function


f%281%2B2i%29=4%281%2B2i%29%5E3-3%281%2B2i%29%5E2%2B2%281%2B2i%29-1 Plug in x=1%2B2i. In other words, replace each "x" with "1+2i"


f%281%2B2i%29=4%281%2B2i%29%5E2%281%2B2i%29-3%281%2B2i%29%5E2%2B2%281%2B2i%29-1 Break up %281%2B2i%29%5E3 to get %281%2B2i%29%5E2%281%2B2i%29


f%281%2B2i%29=4%28-3%2B4i%29%281%2B2i%29-3%28-3%2B4i%29%2B2%281%2B2i%29-1 FOIL %281%2B2i%29%5E2 to get 1%2B4i%2B4i%5E2=1%2B4i%2B4%28-1%29=-3%2B4i


f%281%2B2i%29=4%28-11-2i%29-3%28-3%2B4i%29%2B2%281%2B2i%29-1 FOIL %28-3%2B4i%29%281%2B2i%29 to get %28-3%2B4i%29%281%2B2i%29=-3-2i%2B8i%5E2=-3-2i%2B8%28-1%29=-11-2i


f%281%2B2i%29=-44-8i%2B9-12i%2B2%2B4i-1 Distribute


f%281%2B2i%29=-34-16i Combine like terms.


So the answer is f%281%2B2i%29=-34-16i


Quadratic_Equations/165304: given f(x)= %28x%2B1%29%28x%5E3-27%29 find all zeros (real and imaginary)
1 solutions

Answer 121857 by jim_thompson5910(28717) About Me  on 2008-11-02 12:09:42 (Show Source):
You can put this solution on YOUR website!
f%28x%29=%28x%2B1%29%28x%5E3-27%29 Start with the given function


0=%28x%2B1%29%28x%5E3-27%29 Plug in f%28x%29=0



0=%28x%2B1%29%28x-3%29%28x%5E2%2B3x%2B9%29 Factor x%5E3-27 to get %28x-3%29%28x%5E2%2B3x%2B9%29. Note: use the difference of cubes formula.


x%2B1=0 or x-3=0 or x%5E2%2B3x%2B9=0 Set each individual factor equal to zero


Solve the first two equations to get x=-1 or x=3. These are the first two zeros


Now let's solve x%5E2%2B3x%2B9=0


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=3, and c=9


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%283%29+%2B-+sqrt%28+%283%29%5E2-4%281%29%289%29+%29%29%2F%282%281%29%29 Plug in a=1, b=3, and c=9


x+=+%28-3+%2B-+sqrt%28+9-4%281%29%289%29+%29%29%2F%282%281%29%29 Square 3 to get 9.


x+=+%28-3+%2B-+sqrt%28+9-36+%29%29%2F%282%281%29%29 Multiply 4%281%29%289%29 to get 36


x+=+%28-3+%2B-+sqrt%28+-27+%29%29%2F%282%281%29%29 Subtract 36 from 9 to get -27


x+=+%28-3+%2B-+sqrt%28+-27+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%28-3+%2B-+3i%2Asqrt%283%29%29%2F%282%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x+=+%28-3%2B3i%2Asqrt%283%29%29%2F%282%29 or x+=+%28-3-3i%2Asqrt%283%29%29%2F%282%29 Break up the expression.


So the zeros of x%5E2%2B3x%2B9 are x+=+%28-3%2B3i%2Asqrt%283%29%29%2F%282%29 or x+=+%28-3-3i%2Asqrt%283%29%29%2F%282%29


which approximate to x=-1.5%2B2.598i or x=-1.5-2.598i



=======================================================


Answer:


So in total, the 4 zeros are: x=-1, x=3, x+=+%28-3%2B3i%2Asqrt%283%29%29%2F%282%29 or x+=+%28-3-3i%2Asqrt%283%29%29%2F%282%29


Which in decimal form are x=-1, x=3, x=-1.5%2B2.598i or x=-1.5-2.598i


Complex_Numbers/165291: f(x)=4x^3-3x^2+2x-1. Find f(1+2i). Please help me out, I really don't have any idea on what to do!!!
1 solutions

Answer 121854 by jim_thompson5910(28717) About Me  on 2008-11-02 11:54:34 (Show Source):
You can put this solution on YOUR website!
Note: it's helpful to remember that i%5E2=-1


f%28x%29=4x%5E3-3x%5E2%2B2x-1 Start with the given function


f%281%2B2i%29=4%281%2B2i%29%5E3-3%281%2B2i%29%5E2%2B2%281%2B2i%29-1 Plug in x=1%2B2i. In other words, replace each "x" with "1+2i"


f%281%2B2i%29=4%281%2B2i%29%5E2%281%2B2i%29-3%281%2B2i%29%5E2%2B2%281%2B2i%29-1 Break up %281%2B2i%29%5E3 to get %281%2B2i%29%5E2%281%2B2i%29


f%281%2B2i%29=4%28-3%2B4i%29%281%2B2i%29-3%28-3%2B4i%29%2B2%281%2B2i%29-1 FOIL %281%2B2i%29%5E2 to get 1%2B4i%2B4i%5E2=1%2B4i%2B4%28-1%29=-3%2B4i


f%281%2B2i%29=4%28-11-2i%29-3%28-3%2B4i%29%2B2%281%2B2i%29-1 FOIL %28-3%2B4i%29%281%2B2i%29 to get %28-3%2B4i%29%281%2B2i%29=-3-2i%2B8i%5E2=-3-2i%2B8%28-1%29=-11-2i


f%281%2B2i%29=-44-8i%2B9-12i%2B2%2B4i-1 Distribute


f%281%2B2i%29=-34-16i Combine like terms.


So the answer is f%281%2B2i%29=-34-16i


Linear-systems/165293: Solve by the substition method
8m+n=7
m-6n=56
1 solutions

Answer 121853 by jim_thompson5910(28717) About Me  on 2008-11-02 11:42:58 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:

system%288m%2Bn=7%2Cm-6n=56%29



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for n.




So let's isolate n in the first equation

8m%2Bn=7 Start with the first equation


n=7-8m Subtract 8m from both sides


n=-8m%2B7 Rearrange the equation



---------------------

Since n=-8m%2B7, we can now replace each n in the second equation with -8m%2B7 to solve for m



m-6highlight%28%28-8m%2B7%29%29=56 Plug in n=-8m%2B7 into the second equation. In other words, replace each n with -8m%2B7. Notice we've eliminated the n variables. So we now have a simple equation with one unknown.



m%2B%28-6%29%28-8%29m%2B%28-6%29%287%29=56 Distribute -6 to -8m%2B7


m%2B48m-42=56 Multiply


49m-42=56 Combine like terms on the left side


49m=56%2B42Add 42 to both sides


49m=98 Combine like terms on the right side


m=%2898%29%2F%2849%29 Divide both sides by 49 to isolate m



m=2 Divide





-----------------First Answer------------------------------


So the first part of our answer is: m=2









Since we know that m=2 we can plug it into the equation n=-8m%2B7 (remember we previously solved for n in the first equation).



n=-8m%2B7 Start with the equation where n was previously isolated.


n=-8%282%29%2B7 Plug in m=2


n=-16%2B7 Multiply


n=-9 Combine like terms



-----------------Second Answer------------------------------


So the second part of our answer is: n=-9









-----------------Summary------------------------------

So our answers are:

m=2 and n=-9

which form the point


Linear-systems/165294: Solve the system of equations using the substitution method.
If the answer is a unique solution, present it as an ordered pair: (x, y). If not, specify whether the answer is “no solution” or “infinitely many solutions.”
3x + y = 7
4x – y = 21

1 solutions

Answer 121851 by jim_thompson5910(28717) About Me  on 2008-11-02 11:39:30 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:

system%283x%2By=7%2C4x-y=21%29



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the first equation

3x%2By=7 Start with the first equation


y=7-3x Subtract 3x from both sides


y=-3x%2B7 Rearrange the equation


---------------------

Since y=-3x%2B7, we can now replace each y in the second equation with -3x%2B7 to solve for x



4x-highlight%28%28-3x%2B7%29%29=21 Plug in y=-3x%2B7 into the second equation. In other words, replace each y with -3x%2B7. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



4x%2B3x-7=21 Distribute the negative


7x-7=21 Combine like terms on the left side


7x=21%2B7Add 7 to both sides


7x=28 Combine like terms on the right side


x=%2828%29%2F%287%29 Divide both sides by 7 to isolate x



x=4 Divide





-----------------First Answer------------------------------


So the first part of our answer is: x=4









Since we know that x=4 we can plug it into the equation y=-3x%2B7 (remember we previously solved for y in the first equation).



y=-3x%2B7 Start with the equation where y was previously isolated.


y=-3%284%29%2B7 Plug in x=4


y=-12%2B7 Multiply


y=-5 Combine like terms



-----------------Second Answer------------------------------


So the second part of our answer is: y=-5









-----------------Summary------------------------------

So our answers are:

x=4 and y=-5

which form the point








Now let's graph the two equations (if you need help with graphing, check out this solver)


From the graph, we can see that the two equations intersect at . This visually verifies our answer.




graph of 3x%2By=7 (red) and 4x-y=21 (green) and the intersection of the lines (blue circle).



Triangles/165224: This question is from textbook Lets Review Math A
QUESTION: In isosceles triangle ABC the ratio of the measure of vertex angle A to the measure of angle B is 2 to 5. Find angle C.

1st APPROACH: we know that in an isosceles triangle two angles are the same and the sides opposite them are also the same.

Since this problem doesn't tell you which is the base vertex in this isosceles triangle, I have assumed it to be 5x. Because of "RULE:"
the length of each side is less than the sum of the lengths of the other two sides and greater than the difference between these lengths....3less than x less than 7. Therefore x is in the range of 4, 5, 6.

2x+5x+5x=180

12x=180

x=15
Angle C is 75 degrees


2nd APPROACH: we know that in an isosceles triangle two angles are the same and the sides opposite them are also the same.


Since we already used 5x as the base vertex in our previous approach lets assume 2x is the base angle, this time, because it's an isosceles triangle.


2x+2x+5x=180

9x=180

x=20
Angle C is 40 degrees


BOOKS ANSWER IS 100 degrees, why?

1 solutions

Answer 121825 by jim_thompson5910(28717) About Me  on 2008-11-02 00:51:12 (Show Source):
You can put this solution on YOUR website!
Here's a quick note about what the ratio is really saying:

Since the ratio is vertex angle A to the measure of angle B, this means that we have this ratio:

A:B ---> 2:5

So this means that the vertex angle is SMALLER than the base angle. However, if you have a base angle of 40 degrees, this means that the vertex angle is 180-2%2A40=180-80=100 which means that the vertex angle is larger (not smaller) than the base angle. So this effectively rules out the "2nd Approach" answer. Remember, the ratio is vertex:base angle (not the other way around)


However, I agree with your first approach. That answer is correct. You'll find that the base angles are 75 degrees and the vertex angle is 30 degrees. Since the ratio of 30:75 reduces to 2:5, this verifies the answer.


Note: it is IMPOSSIBLE to have both an isosceles triangle AND have a base angle that is greater than 90 degrees. Why? Base angles are equal. So if there is an obtuse base angle, there are really 2 obtuse angles in the triangle (which is impossible; triangles can only have at most one obtuse angles). So this means that either the book is wrong or maybe you read the wrong answer.


Polynomials-and-rational-expressions/165265: 7.) Solve by completing the square.
2x^2+x-6=0
the answer shows -2,3/2 I am not sure how they got the answer?
1 solutions

Answer 121823 by jim_thompson5910(28717) About Me  on 2008-11-02 00:18:28 (Show Source):
You can put this solution on YOUR website!

2x%5E2%2Bx-6 Start with the given expression.


2%28x%5E2%2B%281%2F2%29x-3%29 Factor out the x%5E2 coefficient 2. This step is very important: the x%5E2 coefficient MUST be equal to 1.


Take half of the x coefficient 1%2F2 to get 1%2F4. In other words, %281%2F2%29%281%2F2%29=1%2F4.


Now square 1%2F4 to get 1%2F16. In other words, %281%2F4%29%5E2=%281%2F4%29%281%2F4%29=1%2F16


2%28x%5E2%2B%281%2F2%29x%2Bhighlight%281%2F16-1%2F16%29-3%29 Now add and subtract 1%2F16 inside the parenthesis. Make sure to place this after the "x" term. Notice how 1%2F16-1%2F16=0. So the expression is not changed.


2%28%28x%5E2%2B%281%2F2%29x%2B1%2F16%29-1%2F16-3%29 Group the first three terms.


2%28%28x%2B1%2F4%29%5E2-1%2F16-3%29 Factor x%5E2%2B%281%2F2%29x%2B1%2F16 to get %28x%2B1%2F4%29%5E2.


2%28%28x%2B1%2F4%29%5E2-49%2F16%29 Combine like terms.


2%28x%2B1%2F4%29%5E2%2B2%28-49%2F16%29 Distribute.


2%28x%2B1%2F4%29%5E2-49%2F8 Multiply.


So after completing the square, 2x%5E2%2Bx-6 transforms to 2%28x%2B1%2F4%29%5E2-49%2F8. So 2x%5E2%2Bx-6=2%28x%2B1%2F4%29%5E2-49%2F8.


So 2x%5E2%2Bx-6=0 is equivalent to 2%28x%2B1%2F4%29%5E2-49%2F8=0.


2%28x%2B1%2F4%29%5E2=0%2B49%2F8Add 49%2F8 to both sides.


2%28x%2B1%2F4%29%5E2=49%2F8 Combine like terms.


%28x%2B1%2F4%29%5E2=%2849%2F8%29%2F%282%29 Divide both sides by 2.


%28x%2B1%2F4%29%5E2=49%2F16 Reduce.


x%2B1%2F4=0%2B-sqrt%2849%2F16%29 Take the square root of both sides.


x%2B1%2F4=sqrt%2849%2F16%29 or x%2B1%2F4=-sqrt%2849%2F16%29 Break up the "plus/minus" to form two equations.


x%2B1%2F4=7%2F4 or x%2B1%2F4=-7%2F4 Take the square root of 49%2F16 to get 7%2F4.


x=-1%2F4%2B7%2F4 or x=-1%2F4-7%2F4 Subtract 1%2F4 from both sides.


x=3%2F2 or x=-2 Combine like terms.


--------------------------------------


Answer:


So the solutions are x=3%2F2 or x=-2.


Note: the order of the solutions does NOT matter.


Linear-systems/165268: There are two numbers whose sum is 50. Three times the first is five more than twice the second. What are the numbers?
Please DO answer quickly.
1 solutions

Answer 121822 by jim_thompson5910(28717) About Me  on 2008-11-02 00:14:17 (Show Source):
You can put this solution on YOUR website!
"There are two numbers whose sum is 50" ---> x%2By=50

"Three times the first is five more than twice the second" ---> 3x=2y%2B5


x%2By=50 Start with the first equation.


y=50-x Subtract x from both sides.


3x=2y%2B5 Move onto the second equation


3x=2%2850-x%29%2B5 Plug in y=50-x


3x=100-2x%2B5 Distribute.


3x=-2x%2B105 Combine like terms on the right side.


3x%2B2x=105 Add 2x to both sides.


5x=105 Combine like terms on the left side.


x=%28105%29%2F%285%29 Divide both sides by 5 to isolate x.


x=21 Reduce.


y=50-x Go back to the previously isolated equation


y=50-21 Plug in x=21


y=29 Subtract


----------------------------------------------------------------------

Answer:

So the solutions are x=21 and y=29 which form the ordered pair (21,29)


Subset/165241: Let c = {p,l,u,s}. How many subsets does c have?
1 solutions

Answer 121821 by jim_thompson5910(28717) About Me  on 2008-11-02 00:09:52 (Show Source):
You can put this solution on YOUR website!
Subsets of c (16 total):

{p,l,u,s},
{p,l,u},{p,l,s},{p,u,s},{l,u,s}
{p,l},{p,u},{p,s},{l,u},{l,s},{u,s}
{p},{l},{u},{s}
{}

Note: {} denotes the empty set


To help confirm (not completely verify) that we have the right answer, notice how there are 16 subsets. It turns out that for any set A of "n" elements, the total number of subsets of set A is 2%5En. Since there are 4 elements in set c, and 2%5E4=16, this helps confirm that we at least have the right number of subsets listed.


Miscellaneous_Word_Problems/165217: The measures of the angles of a certain triangle are consecutive even integers. Find the measures.
1 solutions

Answer 121777 by jim_thompson5910(28717) About Me  on 2008-11-01 16:13:55 (Show Source):
You can put this solution on YOUR website!
Let x=first angle, x+2=second angle, x+4=third angle


Remember, the sum of three angles in a triangle is 180 degrees. So this means that x%2Bx%2B2%2Bx%2B4=180
x%2Bx%2B2%2Bx%2B4=180 Start with the given equation.


3x%2B6=180 Combine like terms on the left side.


3x=180-6 Subtract 6 from both sides.


3x=174 Combine like terms on the right side.


x=%28174%29%2F%283%29 Divide both sides by 3 to isolate x.


x=58 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=58


So this means that the three angles are 58, 60, and 62


Functions/165207: state the domain of the following and provide a brief explanation for your answer: h(x)=3x^2+5x-3
1 solutions

Answer 121776 by jim_thompson5910(28717) About Me  on 2008-11-01 16:06:33 (Show Source):
You can put this solution on YOUR website!
Looking at h%28x%29=3x%5E2%2B5x-3, we can see that there are no square roots, logs, and other functions where there are restrictions on the domain.

Also, we can see that the function does not have a division by x (or any combination of variables and constants).
So we don't have to worry about division by zero.


Since we don't have any restrictions on the domain, this shows us that the domain is all real numbers. In other words, we can plug in any number in for x




So the domain of the function in set-builder notation is:





In plain English, this reads: x is the set of all real numbers (In other words, x can be any number)


Also, in interval notation, the domain is:




Polynomials-and-rational-expressions/165214: Please assist me with the following problem:
Determine the leading term, the leading coefficient, and the degree of the polynomial. Then classify the polynomial as constant, linear, quadratic, cubic, or quartic.
f(x)=15x^2-10+0.11x^4-7x^3

1 solutions

Answer 121775 by jim_thompson5910(28717) About Me  on 2008-11-01 16:05:05 (Show Source):
You can put this solution on YOUR website!
First, sort the terms in descending order. So the term with the largest exponent goes first.

So f%28x%29=15x%5E2-10%2B0.11x%5E4-7x%5E3 sorts to f%28x%29=0.11x%5E4-7x%5E3%2B15x%5E2-10


Leading term: The first term of the sorted terms


So the leading term is 0.11x%5E4


----------------------------------------

Leading Coefficient: coefficient of leading term


So the leading coefficient is 0.11


----------------------------------------

Degree of the Polynomial: This value is equal to the largest exponent of the polynomial


So the degree of the polynomial is 4 since 4 is the largest exponent



----------------------------------------

Since the degree of the polynomial is 4, this classifies the polynomial as a quartic


logarithm/165216: This question is from textbook
log(base5) x - log(base5)(x-2)= log(base5) 4
Many thanks.
1 solutions

Answer 121774 by jim_thompson5910(28717) About Me  on 2008-11-01 15:59:40 (Show Source):
You can put this solution on YOUR website!
log%285%2C%28x%29%29-log%285%2C%28x-2%29%29=log%285%2C%284%29%29 Start with the given equation


log%285%2C%28%28x%29%2F%28x-2%29%29%29=log%285%2C%284%29%29 Combine the logs on the left side using the identity log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29


%28x%29%2F%28x-2%29=4 Since the bases of the logs on both sides are equal, this means that the arguments of the logs (the stuff inside the logs) are equal


x=4%28x-2%29 Multiply both sides by x-2


x=4x-8 Distribute.


x-4x=-8 Subtract 4x from both sides.


-3x=-8 Combine like terms on the left side.


x=%28-8%29%2F%28-3%29 Divide both sides by -3 to isolate x.


x=8%2F3 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=8%2F3 which approximates to x=2.667.




Polynomials-and-rational-expressions/165212: Please assist me with the following problem:
Using the intermediate value theorem, determine, if possible, whether the function f has a real zero between a and b
f(x)=3x^2-2x-11; a=2, b=3

1 solutions

Answer 121772 by jim_thompson5910(28717) About Me  on 2008-11-01 15:37:29 (Show Source):
You can put this solution on YOUR website!
Let's evaluate the left endpoint a=2


f%28x%29=3x%5E2-2x-11 Start with the given equation.


f%282%29=3%282%29%5E2-2%282%29-11 Plug in x=2.


f%282%29=3%284%29-2%282%29-11 Square 2 to get 4.


f%282%29=12-2%282%29-11 Multiply 3 and 4 to get 12.


f%282%29=12-4-11 Multiply -2 and 2 to get -4.


f%282%29=-3 Combine like terms.


------------------------------------------------

Let's evaluate the right endpoint b=3


f%28x%29=3x%5E2-2x-11 Start with the given equation.


f%283%29=3%283%29%5E2-2%283%29-11 Plug in x=3.


f%283%29=3%289%29-2%283%29-11 Square 3 to get 9.


f%283%29=27-2%283%29-11 Multiply 3 and 9 to get 27.


f%283%29=27-6-11 Multiply -2 and 3 to get -6.


f%283%29=10 Combine like terms.


So as x changes from 2 to 3, f(x) (ie y) changes from -3 to 10 which means that the graph MUST have crossed over the x-axis somewhere in between x=2 and x=3. So this shows that there is a zero between a and b


Inequalities/165211: This question is from textbook Holt Algebra 1 Texas
Im not sure what the OR has to do with anything for example could you explain to me how to solve x-1<-1ORx-5>-1?
1 solutions

Answer 121768 by jim_thompson5910(28717) About Me  on 2008-11-01 15:23:24 (Show Source):
You can put this solution on YOUR website!
To solve inequalities like this, simply solve each inequality individually



Let's solve the first inequality x-1%3C-1:


x-1%3C-1 Start with the first inequality.


x%3C-1%2B1 Add 1 to both sides.


x%3C0 Combine like terms on the right side.


---------------------------------------------------------------------


Now let's solve the second inequality x-5%3E-1:


x-5%3E-1 Start with the second inequality.


x%3E-1%2B5 Add 5 to both sides.


x%3E4 Combine like terms on the right side.


So our answer is x%3C0 or x%3E4




So the solution in interval notation is: () ()


So the solution in set notation is:




Here's the graph of the solution set




Note:
There is an open circle at x=0 which means that we're excluding that value from the solution set.


Also, there is an open circle at x=4 which means that we're excluding that value from the solution set.


Inequalities/165210: How exactly do I solve a compound inequality such as -31 solutions

Answer 121767 by jim_thompson5910(28717) About Me  on 2008-11-01 15:19:53 (Show Source):
You can put this solution on YOUR website!
-3%3Cx%2B2%3C7 Start with the given compound inequality.


-3-2%3Cx%3C7-2 Subtract 2 from ALL sides.


-5%3Cx%3C7-2 Combine like terms on the left side.


-5%3Cx%3C5 Combine like terms on the right side.


So our answer is -5%3Cx%3C5


So the answer in interval notation is ()


So the answer in set-builder notation is


Here's the graph of the solution set

Graph of the solution set

Note:
There is an open circle at x=-5 which means that we're excluding this value from the solution set
Also, there is an open circle at x=5 which means that we're excluding this value from the solution set.


Functions/165208: State the domain of the following and provide a brief explanation for you answer: m(x)=(5)/(x^2-9)
1 solutions

Answer 121766 by jim_thompson5910(28717) About Me  on 2008-11-01 15:15:34 (Show Source):
You can put this solution on YOUR website!

m%28x%29=%285%29%2F%28x%5E2-9%29 Start with the given function


x%5E2-9=0 Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.




%28x-3%29%28x%2B3%29=0 Factor the left side (note: if you need help with factoring, check out this solver)




Now set each factor equal to zero:

x-3=0 or x%2B3=0

x=3 or x=-3 Now solve for x in each case


So our solutions are x=3 or x=-3



Since x=-3 and x=3 make the denominator equal to zero, this means we must exclude x=-3 and x=3 from our domain

So our domain is:

which in plain English reads: x is the set of all real numbers except x%3C%3E-3 or x%3C%3E3

So our domain looks like this in interval notation


note: remember, the parenthesis excludes -3 and 3 from the domain



If we wanted to graph the domain on a number line, we would get:

Graph of the domain in blue and the excluded values represented by open circles

Notice we have a continuous line until we get to the holes at x=-3 and x=3 (which is represented by the open circles).
This graphically represents our domain in which x can be any number except x cannot equal -3 or 3




test/165192: 15.) Graph each parabola identify the vertex, intercepts, and the maximum or minimum y - value.
g(x) = x^2 - 3x
1 solutions

Answer 121761 by jim_thompson5910(28717) About Me  on 2008-11-01 15:05:23 (Show Source):
You can put this solution on YOUR website!
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2+-+3x%29+ Graph of g%28x%29=x%5E2+-+3x

Vertex:


X-intercepts: (0,0) and (3,0)


Y-intercept: (0,0)


Min value:


Polynomials-and-rational-expressions/165203: simplify. only positive exponents
(2y)^-3 over (x^5y^7)^-2
1 solutions

Answer 121760 by jim_thompson5910(28717) About Me  on 2008-11-01 14:54:00 (Show Source):
You can put this solution on YOUR website!
Let's break up the expression

Numerator: %282y%29%5E%28-3%29=1%2F%282y%29%5E3=1%2F8y%5E3


Denominator: %28x%5E5y%5E7%29%5E%28-2%29=1%2F%28x%5E5y%5E7%29%5E%282%29=1%2F%28x%5E10y%5E14%29

So the expression %28%282y%29%5E%28-3%29%29%2F%28%28x%5E5y%5E7%29%5E%28-2%29%29 becomes %281%2F8y%5E3%29%2F%281%2F%28x%5E10y%5E14%29%29 which then simplifies to %28x%5E10y%5E14%29%2F%288y%5E3%29

Now divide to get %28x%5E10y%5E11%29%2F%288%29

So %28%282y%29%5E%28-3%29%29%2F%28%28x%5E5y%5E7%29%5E%28-2%29%29 simplifies to %28x%5E10y%5E11%29%2F%288%29


Radicals/165083: This question is from textbook Elementary and Intermediate
30.) Solve each equation and check for extraneous solutions.
sqrt(a-1 -5 = 1)

1 solutions

Answer 121689 by jim_thompson5910(28717) About Me  on 2008-10-31 21:55:42 (Show Source):
You can put this solution on YOUR website!
I'm assuming that you mean sqrt%28a-1%29-5+=+1??? Be careful to place your parenthesis in the right spot.


sqrt%28a-1%29-5+=+1 Start with the given equation.


sqrt%28a-1%29+=+1%2B5 Add 5 to both sides.


sqrt%28a-1%29+=+6 Add.


a-1+=+6%5E2 Square both sides to eliminate the square root.


a-1+=+36 Square 6 to get 36.


a=36%2B1 Add 1 to both sides.


a=37 Combine like terms on the right side.


----------------------------------------------------------------------

Answer:

So the answer is a=37


Evaluation_Word_Problems/165097: A circular flower bed is surrounded by a ring of grass with an Area of 314 square yards. Find the width of the ring of grass.
1 solutions

Answer 121688 by jim_thompson5910(28717) About Me  on 2008-10-31 21:52:14 (Show Source):
You can put this solution on YOUR website!
Are you sure that you don't want find the "radius" (instead of the "width")? Or do you want to find the diameter?


A=pi%2Ar%5E2 Start with the area of a circle formula


314=3.14%2Ar%5E2 Plug in A=314 and replace pi with 3.14 (this is an approximation)


314%2F3.14=r%5E2 Divide both sides by 3.14


100=r%5E2 Divide


r%5E2=100 Rearrange the equation.


r=10 Take the square root of both sides (only the positive square root is considered).


So the radius of the circle is about 10 yards which means that the diameter is about 20 yards (which is twice the radius)


Polynomials-and-rational-expressions/165095: solve each equations. indicate the lower comon demominator.
4+3/x+2=4/x^2+2x
1 solutions

Answer 121687 by jim_thompson5910(28717) About Me  on 2008-10-31 21:43:32 (Show Source):
You can put this solution on YOUR website!
4%2B3%2F%28x%2B2%29=4%2F%28x%5E2%2B2x%29 Start with the given equation


4%2B3%2F%28x%2B2%29=4%2F%28x%28x%2B2%29%29 Factor x%5E2%2B2x to get x%28x%2B2%29


So the LCD is x%28x%2B2%29


Multiply EVERY term by the LCD x%28x%2B2%29 to clear the fractions.


4x%28x%2B2%29%2B3x=4 Simplify.


4x%5E2%2B8x%2B3x=4 Distribute.


4x%5E2%2B8x%2B3x-4=0 Subtract 4 from both sides.


4x%5E2%2B11x-4=0 Combine like terms.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=4, b=11, and c=-4


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%2811%29+%2B-+sqrt%28+%2811%29%5E2-4%284%29%28-4%29+%29%29%2F%282%284%29%29 Plug in a=4, b=11, and c=-4


x+=+%28-11+%2B-+sqrt%28+121-4%284%29%28-4%29+%29%29%2F%282%284%29%29 Square 11 to get 121.


x+=+%28-11+%2B-+sqrt%28+121--64+%29%29%2F%282%284%29%29 Multiply 4%284%29%28-4%29 to get -64


x+=+%28-11+%2B-+sqrt%28+121%2B64+%29%29%2F%282%284%29%29 Rewrite sqrt%28121--64%29 as sqrt%28121%2B64%29


x+=+%28-11+%2B-+sqrt%28+185+%29%29%2F%282%284%29%29 Add 121 to 64 to get 185


x+=+%28-11+%2B-+sqrt%28+185+%29%29%2F%288%29 Multiply 2 and 4 to get 8.


x+=+%28-11%2Bsqrt%28185%29%29%2F%288%29 or x+=+%28-11-sqrt%28185%29%29%2F%288%29 Break up the expression.


===============================================================

Answer:


So the solutions are x+=+%28-11%2Bsqrt%28185%29%29%2F%288%29 or x+=+%28-11-sqrt%28185%29%29%2F%288%29


which approximate to x=0.325 or x=-3.075


Evaluation_Word_Problems/165101: A baseball is hit at a point 3 ft above the ground at a velocity of 100ft/s and at an angle of 45 degrees with respect of the ground. The path of the baseball is given by the function f(x) = -0.0032x2 + x +3 where f(x) is the height of the baseball (in feet) and x is the horizontal distance from home plate (in feet). What's the maximum hieght reached by the baseball?
1 solutions

Answer 121685 by jim_thompson5910(28717) About Me  on 2008-10-31 21:36:09 (Show Source):
You can put this solution on YOUR website!
Remember, the max height occurs at the vertex. So if we find the y-coordinate of the vertex, we find the max height.

Note: the same applies to the min height (if there exists a min height)



In order to find the vertex, we first need to find the x-coordinate of the vertex.


To find the x-coordinate of the vertex, use this formula: x=%28-b%29%2F%282a%29.


x=%28-b%29%2F%282a%29 Start with the given formula.


From y=-0.0032x%5E2%2Bx%2B3, we can see that a=1, b=1, and c=3.


x=%28-%281%29%29%2F%282%28-0.0032%29%29 Plug in a=-0.0032 and b=1.


x=%28-1%29%2F%28-0.0064%29 Multiply.


x=156.25 Divide


So the x-coordinate of the vertex is x=156.25.



Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.


y=-0.0032x%5E2%2Bx%2B3 Start with the given equation.


y=-0.0032%28156.25%29%5E2%2B156.25%2B3 Plug in x=156.25.


y=-0.0032%2824414.0625%29%2B156.25%2B3 Square 156.25 to get 24414.0625.


y=-78.125%2B156.25%2B3 Multiply


y=81.125 Combine like terms.


So the y-coordinate of the vertex is y=81.125.


So the vertex is (156.25,81.125).


Since the y-coordinate is y=81.125, this means that the max height is 81.125 ft.


Evaluation_Word_Problems/165093: A 10m by 34m garden is surrounded by a walkway of uniform width (call it "x"). The total area of the garden and walkway is 640 square meters. what is the width of the walkway?
1 solutions

Answer 121684 by jim_thompson5910(28717) About Me  on 2008-10-31 21:24:32 (Show Source):
You can put this solution on YOUR website!
Let x = width of the path


With these type of problems, it helps to draw a picture. So draw two rectangles, one inside of the other, and label the inside rectangle's dimensions:




Photobucket - Video and Image Hosting


Now the label the width of the path "x" (denoted in red)

Photobucket - Video and Image Hosting

Since there are 2 "x" lengths per side, this means that you need to add "2x" to both the length and width of the inner rectangle to get the length and width of the outer rectangle. If this makes no sense at all, here's a visual:


Photobucket - Video and Image Hosting

So the length and width of the outer rectangle is 34%2B2x and 10%2B2x respectively. This means that for the outer rectangle A=640 (the given area of both the walkway and the garden), L=34%2B2x and W=10%2B2x


Remember, the area of any rectangle is A=LW


A=LW Start with the area of a rectangle formula


640=%2834%2B2x%29%2810%2B2x%29 Plug in A=640, L=34%2B2x and W=10%2B2x


640=340%2B68x%2B20x%2B4x%5E2 FOIL


0=340%2B68x%2B20x%2B4x%5E2-640 Subtract 640 from both sides.


0=4x%5E2%2B88x-300 Combine like terms.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=4, b=88, and c=-300


Let's use the quadratic formula to solve for x.


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%2888%29+%2B-+sqrt%28+%2888%29%5E2-4%284%29%28-300%29+%29%29%2F%282%284%29%29 Plug in a=4, b=88, and c=-300


x+=+%28-88+%2B-+sqrt%28+7744-4%284%29%28-300%29+%29%29%2F%282%284%29%29 Square 88 to get 7744.


x+=+%28-88+%2B-+sqrt%28+7744--4800+%29%29%2F%282%284%29%29 Multiply 4%284%29%28-300%29 to get -4800


x+=+%28-88+%2B-+sqrt%28+7744%2B4800+%29%29%2F%282%284%29%29 Rewrite sqrt%287744--4800%29 as sqrt%287744%2B4800%29


x+=+%28-88+%2B-+sqrt%28+12544+%29%29%2F%282%284%29%29 Add 7744 to 4800 to get 12544


x+=+%28-88+%2B-+sqrt%28+12544+%29%29%2F%288%29 Multiply 2 and 4 to get 8.


x+=+%28-88+%2B-+112%29%2F%288%29 Take the square root of 12544 to get 112.


x+=+%28-88+%2B+112%29%2F%288%29 or x+=+%28-88+-+112%29%2F%288%29 Break up the expression.


x+=+%2824%29%2F%288%29 or x+=++%28-200%29%2F%288%29 Combine like terms.


x+=+3 or x+=+-25 Simplify.


So the possible answers are x+=+3 or x+=+-25


However, since a negative width is not possible, this means that x+=+-25 is NOT a solution.


==================================================

Answer:

So the solution is x+=+3 which means that the width of the path is 3 meters.