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Polynomials-and-rational-expressions/173300: (11x+3y)(x+4y)
1 solutions

Answer 128137 by jim_thompson5910(28546) About Me  on 2008-12-14 18:11:49 (Show Source):
You can put this solution on YOUR website!

%2811x%2B3y%29%28x%2B4y%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%2811x%29%2B3y%29%28highlight%28x%29%2B4y%29 Multiply the First terms:%2811%2Ax%29%2A%28x%29=11%2Ax%5E2.


%28highlight%2811x%29%2B3y%29%28x%2Bhighlight%284y%29%29 Multiply the Outer terms:%2811%2Ax%29%2A%284%2Ay%29=44%2Ax%2Ay.


%2811x%2Bhighlight%283y%29%29%28highlight%28x%29%2B4y%29 Multiply the Inner terms:%283%2Ay%29%2A%28x%29=3%2Ax%2Ay.


%2811x%2Bhighlight%283y%29%29%28x%2Bhighlight%284y%29%29 Multiply the Last terms:%283%2Ay%29%2A%284%2Ay%29=12%2Ay%5E2.


---------------------------------------------------


11%2Ax%5E2%2B44%2Ax%2Ay%2B3%2Ax%2Ay%2B12%2Ay%5E2 Now collect every term to make a single expression.


11%2Ax%5E2%2B47%2Ax%2Ay%2B12%2Ay%5E2 Now combine like terms.


So %2811x%2B3y%29%28x%2B4y%29 FOILs to 11%2Ax%5E2%2B47%2Ax%2Ay%2B12%2Ay%5E2.


In other words, %2811x%2B3y%29%28x%2B4y%29=11%2Ax%5E2%2B47%2Ax%2Ay%2B12%2Ay%5E2.


Equations/173299: how do you solve this problem?
x+x
_ _
5 7
1 solutions

Answer 128131 by jim_thompson5910(28546) About Me  on 2008-12-14 17:32:46 (Show Source):
You can put this solution on YOUR website!
x%2F5%2Bx%2F7 Start with the given expression


Take note that the LCD is 35.


%287x%29%2F35%2Bx%2F7 Multiply the first fraction by 7%2F7


%287x%29%2F35%2B%285x%29%2F35 Multiply the second fraction by 7%2F7


%287x%2B5x%29%2F35 Combine the fractions (this is now possible since the denominators are equal)


%2812x%29%2F35 Add


So x%2F5%2Bx%2F7=%2812x%29%2F35


Radicals/173294: how do you solve this problem
2 sq. root 2 + 8 s. root 2- sq. root 2
1 solutions

Answer 128122 by jim_thompson5910(28546) About Me  on 2008-12-14 17:04:54 (Show Source):
You can put this solution on YOUR website!
Let z=sqrt%282%29


So the expression 2%2Asqrt%282%29+%2B+8%2Asqrt%282%29-+sqrt%282%29 becomes 2z+%2B+8z-+z


Now combine like terms to get 9z.


Now replace "z" with sqrt%282%29 to get 9%2Asqrt%282%29


So 2%2Asqrt%282%29+%2B+8%2Asqrt%282%29-+sqrt%282%29=9%2Asqrt%282%29


Equations/173293: how do you solve this problem
x+4=x-3
_ _
2 3
1 solutions

Answer 128121 by jim_thompson5910(28546) About Me  on 2008-12-14 17:02:30 (Show Source):
You can put this solution on YOUR website!
%28x%2B4%29%2F2=%28x-3%29%2F3 Start with the given equation.


6%28%28x%2B4%29%2Fcross%282%29%29=6%28%28x-3%29%2Fcross%283%29%29 Multiply both sides by the LCD 6 to clear the fractions.



3%28x%2B4%29=2%28x-3%29 Simplify.


3x%2B12=2x-6 Distribute.


3x=2x-6-12 Subtract 12 from both sides.


3x-2x=-6-12 Subtract 2x from both sides.


x=-6-12 Combine like terms on the left side.


x=-18 Combine like terms on the right side.


----------------------------------------------------------------------

Answer:

So the answer is x=-18


Polynomials-and-rational-expressions/173291: Can you please explain the following in full depth:
3x^2+26xy+16y^2

1 solutions

Answer 128119 by jim_thompson5910(28546) About Me  on 2008-12-14 16:54:55 (Show Source):
You can put this solution on YOUR website!

Looking at 3x%5E2%2B26xy%2B16y%5E2 we can see that the first term is 3x%5E2 and the last term is 16y%5E2 where the coefficients are 3 and 16 respectively.

Now multiply the first coefficient 3 and the last coefficient 16 to get 48. Now what two numbers multiply to 48 and add to the middle coefficient 26? Let's list all of the factors of 48:



Factors of 48:
1,2,3,4,6,8,12,16,24,48

-1,-2,-3,-4,-6,-8,-12,-16,-24,-48 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 48
1*48
2*24
3*16
4*12
6*8
(-1)*(-48)
(-2)*(-24)
(-3)*(-16)
(-4)*(-12)
(-6)*(-8)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 26? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 26

First NumberSecond NumberSum
1481+48=49
2242+24=26
3163+16=19
4124+12=16
686+8=14
-1-48-1+(-48)=-49
-2-24-2+(-24)=-26
-3-16-3+(-16)=-19
-4-12-4+(-12)=-16
-6-8-6+(-8)=-14



From this list we can see that 2 and 24 add up to 26 and multiply to 48


Now looking at the expression 3x%5E2%2B26xy%2B16y%5E2, replace 26xy with 2xy%2B24xy (notice 2xy%2B24xy adds up to 26xy. So it is equivalent to 26xy)

3x%5E2%2Bhighlight%282xy%2B24xy%29%2B16y%5E2


Now let's factor 3x%5E2%2B2xy%2B24xy%2B16y%5E2 by grouping:


%283x%5E2%2B2xy%29%2B%2824xy%2B16y%5E2%29 Group like terms


x%283x%2B2y%29%2B8y%283x%2B2y%29 Factor out the GCF of x out of the first group. Factor out the GCF of 8y out of the second group


%28x%2B8y%29%283x%2B2y%29 Since we have a common term of 3x%2B2y, we can combine like terms

So 3x%5E2%2B2xy%2B24xy%2B16y%5E2 factors to %28x%2B8y%29%283x%2B2y%29


So this also means that 3x%5E2%2B26xy%2B16y%5E2 factors to %28x%2B8y%29%283x%2B2y%29 (since 3x%5E2%2B26xy%2B16y%5E2 is equivalent to 3x%5E2%2B2xy%2B24xy%2B16y%5E2)



------------------------------------------------------------



Answer:
So 3x%5E2%2B26xy%2B16y%5E2 factors to %28x%2B8y%29%283x%2B2y%29


Square-cubic-other-roots/173280: I really messed up posting this the last time so I will try again please bare with me 4/(root(3,5x^2)
1 solutions

Answer 128114 by jim_thompson5910(28546) About Me  on 2008-12-14 16:49:45 (Show Source):
You can put this solution on YOUR website!
4%2F%28root%283%2C5x%5E2%29%29 Start with the given expression


Multiply the fraction by root%283%2C5x%5E2%29%2Froot%283%2C5x%5E2%29 twice (to get a total of 3 copies of root%283%2C5x%5E2%29 in the denominator)



Now notice how


So let's replace the denominator with 5x%5E2


%284%2Aroot%283%2C5x%5E2%29root%283%2C5x%5E2%29%29%2F%285x%5E2%29


Now multiply 4%2Aroot%283%2C5x%5E2%29root%283%2C5x%5E2%29 out to get



So replace the the numerator with

%284x%2Aroot%283%2C25x%29%29%2F%285x%5E2%29


%284%2Aroot%283%2C25x%29%29%2F%285x%29 Reduce %284x%29%2F%285x%5E2%29 to get 4%2F%285x%29



==================================================================

Answer:


So 4%2F%28root%283%2C5x%5E2%29%29 simplifies to %284%2Aroot%283%2C25x%29%29%2F%285x%29


In other words, 4%2F%28root%283%2C5x%5E2%29%29=%284%2Aroot%283%2C25x%29%29%2F%285x%29 where x%3C%3E0


Square-cubic-other-roots/173283: I need to simplify this problem can you help? sqrt-100/sqrt-25 I got the answer of 2 should it be negitive?
1 solutions

Answer 128109 by jim_thompson5910(28546) About Me  on 2008-12-14 16:40:04 (Show Source):


Polynomials-and-rational-expressions/173284: I need to simplify this problem(5-2i)^2 I do not know if I did it right but the answer I got was 25-16i was I close?
1 solutions

Answer 128105 by jim_thompson5910(28546) About Me  on 2008-12-14 16:34:46 (Show Source):
You can put this solution on YOUR website!
%285-2i%29%5E2 Start with the given expression.


%285-2i%29%2A%285-2i%29 Expand


%285%29%285%29%2B%285%29%28-2i%29%2B%28-2i%29%285%29%2B%28-2i%29%28-2i%29 FOIL.


25-10i-10i%2B4i%5E2 Multiply.


25-10i-10i%2B4%28-1%29 Replace i%5E2 with -1. Note: i%5E2=-1.


25-10i-10i-4 Multiply.


21-20i Combine like terms.


So %285-2i%29%5E2=21-20i.


So the expression is now in standard form a%2Bbi where a=21 and b=-20


Equations/173285: 2=(10+Z)/-3
Can you give me step by step instructions on how to solve this. I know the answer is Z=-16, but not sure of how to arrive at it. Thanks.
1 solutions

Answer 128103 by jim_thompson5910(28546) About Me  on 2008-12-14 16:32:44 (Show Source):
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2=%2810%2Bz%29%2F%28-3%29 Start with the given equation.


2%28-3%29=10%2Bz Multiply both sides by -3.


-6=10%2Bz Multiply.


-6-10=z Subtract 10 from both sides.


-16=z Subtract.


=============================================

Answer:


So the solution is z=-16


Radicals/173273: heres another radical problem I'm not sure of, can you help check my answer?2+sqrt(5)/4+3sqrt(5) the answer I got was 7+2sqrt(5)/29
1 solutions

Answer 128095 by jim_thompson5910(28546) About Me  on 2008-12-14 15:48:31 (Show Source):
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%282%2Bsqrt%285%29%29%2F%284%2B3%2Asqrt%285%29%29 Start with the given expression.


Multiply the fraction by %284-3%2Asqrt%285%29%29%2F%284-3%2Asqrt%285%29%29 (which is the conjugate of the denominator)


Combine the fractions.


FOIL the numerator.


FOIL the denominator.


Multiply.


Square sqrt%285%29 to get 5.


%288-6%2Asqrt%285%29%2B4%2Asqrt%285%29-15%29%2F%2816-3%2Asqrt%285%29%2B3%2Asqrt%285%29-45%29 Multiply.


%28-7-2%2Asqrt%285%29%29%2F%28-29%29 Combine like terms.


%287%2B2%2Asqrt%285%29%29%2F%2829%29 Reduce



So %282%2Bsqrt%285%29%29%2F%284%2B3%2Asqrt%285%29%29=%287%2B2%2Asqrt%285%29%29%2F%2829%29.


So you are correct.


Trigonometry-basics/173275: This question is from textbook Algebra and trigonometry
(27^4)^-1/12
1 solutions

Answer 128092 by jim_thompson5910(28546) About Me  on 2008-12-14 15:34:56 (Show Source):


Geometry_proofs/173265: Given: Segment CS and segment AT are altitudes; Segment CS is congruent to segment AT
Prove: Segment AS is congruent to segment CT
Use this diagram to help you:
http://i164.photobucket.com/albums/u27/foxymccloud/geometry.jpg
1 solutions

Answer 128091 by jim_thompson5910(28546) About Me  on 2008-12-14 15:29:09 (Show Source):
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    Statement                                      Reason
-----------------------------------------------------------------------

1.  Angle ASC is right angle                       Definition of Altitude (given) 


2.  Angle ATC is right angle                       Definition of Altitude (given)


3.  Angle ATC = Angle ASC                          Right Angle Theorem


4.  CS = AT                                        Given


5.  AC = AC                                        Reflexive Property of Congruence


6.  triangle ASC = triangle ATC                    SAS Postulate


7.  AS = CT                                        CPCTC





Notes:

# 1 Remember, an altitude is a segment that runs from one vertex to the opposite side (and forms a 90 degree angle with the opposite side).

# 2 The Right Angle Theorem states that all right angles are congruent.

# 3 CPCTC = Corresponding parts of congruent triangles are congruent.


Linear-systems/173267: I am having a problem understanding how to solve a system byusing substitution.
Here are few of the problems I'm facing. Could you please explain them to me?
1. y = -3x+19
y + 2x-1
2. y = x +4
3x-2y=6
3. 2x-y = 4
2x-y=3
I've looked at tons of reasons on how these problems work, and none of them make sense. The ones I've looked at are not specific enough on the what, why and how of the problem.
Thanks for your help!
Angela
1 solutions

Answer 128087 by jim_thompson5910(28546) About Me  on 2008-12-14 15:16:10 (Show Source):
You can put this solution on YOUR website!
The goal of solving ANY system of equations with 2 variables is to eliminate one variable so you can solve for the other variable. To eliminate one variable, simply "substitute" an expression in terms of the other variable.


# 1

Note: I'm assuming that the second equation is y+=+2x-1


y+=+-3x%2B19 Start with the first equation


2x-1+=+-3x%2B19 Plug in y+=+2x-1. In other words, replace "y" with 2x-1. Notice how the "y" term is gone.


Now we can solve for "x".


2x=-3x%2B19%2B1 Add 1 to both sides.


2x%2B3x=19%2B1 Add 3x to both sides.


5x=19%2B1 Combine like terms on the left side.


5x=20 Combine like terms on the right side.


x=%2820%29%2F%285%29 Divide both sides by 5 to isolate x.


x=4 Reduce. So this is the first answer.


--------------------------------


y+=+2x-1 Go back to the second equation


y+=+2%284%29-1 Plug in x=4


y+=+8-1 Multiply


y+=+7 Subtract. So this is the second answer.


=========================================

Answer:


So the solutions are x=4 and y+=+7


which form the ordered pair (4,7)


So the system is consistent and independent.






# 2


3x-2y=6+ Start with the second equation


3x-2%28x%2B4%29=6+ Plug in y+=+x+%2B4. In other words, replace "y" with x+4. Notice how the "y" term is gone.


Now we can solve for "x".


3x-2x-8=6 Distribute.


x-8=6 Combine like terms on the left side.


x=6%2B8 Add 8 to both sides.


x=14 Combine like terms on the right side. So this is the first answer.


-------------------------------------------


y+=+x+%2B4 Go back to the first equation


y+=+14+%2B4 Plug in x=14


y+=+18 Add. So this is the second answer.


=========================================

Answer:


So the solutions are x=14 and y+=+18


which form the ordered pair (14,18)


So the system is consistent and independent.





# 3





Start with the given system of equations:

system%282x-y=4%2C2x-y=3%29



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the first equation


2x-y=4 Start with the first equation


-y=4-2x Subtract 2x from both sides


-y=-2x%2B4 Rearrange the equation


y=%28-2x%2B4%29%2F%28-1%29 Divide both sides by -1


y=%28%28-2%29%2F%28-1%29%29x%2B%284%29%2F%28-1%29 Break up the fraction


y=2x-4 Reduce



---------------------

Since y=2x-4, we can now replace each y in the second equation with 2x-4 to solve for x



2x-highlight%28%282x-4%29%29=3 Plug in y=2x-4 into the second equation. In other words, replace each y with 2x-4. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



2x-2x%2B4=3 Distribute the negative


4=3 Combine like terms on the left side


Since this equation is NEVER true for any x value, this means there are no solutions.


So the system is inconsistent.


Coordinate-system/173255: This question is from textbook
how can you write an equation of the line that connects points (-3,7) and (4,2)?
1 solutions

Answer 128083 by jim_thompson5910(28546) About Me  on 2008-12-14 14:54:45 (Show Source):
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First let's find the slope of the line through the points and


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%282-7%29%2F%284--3%29 Plug in y%5B2%5D=2, y%5B1%5D=7, x%5B2%5D=4, and x%5B1%5D=-3


m=%28-5%29%2F%284--3%29 Subtract 7 from 2 to get -5


m=%28-5%29%2F%287%29 Subtract -3 from 4 to get 7


So the slope of the line that goes through the points and is m=-5%2F7


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-7=%28-5%2F7%29%28x--3%29 Plug in m=-5%2F7, x%5B1%5D=-3, and y%5B1%5D=7


y-7=%28-5%2F7%29%28x%2B3%29 Rewrite x--3 as x%2B3


y-7=%28-5%2F7%29x%2B%28-5%2F7%29%283%29 Distribute


y-7=%28-5%2F7%29x-15%2F7 Multiply


y=%28-5%2F7%29x-15%2F7%2B7 Add 7 to both sides.


y=%28-5%2F7%29x%2B34%2F7 Combine like terms. note: If you need help with fractions, check out this solver.


So the equation that goes through the points and is y=%28-5%2F7%29x%2B34%2F7


Equations/173252: -x = -36
what is x
1 solutions

Answer 128077 by jim_thompson5910(28546) About Me  on 2008-12-14 14:25:36 (Show Source):
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-x=-36 Start with the given equation.


x=%28-36%29%2F%28-1%29 Divide both sides by -1 to isolate x.


x=36 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=36


Proofs/173249: I can't seem to get to solve this proof.
1. W->S
2. U->F
3. (S and F) -> O
4. ~O THEREFORE (~W v ~U)
1 solutions

Answer 128073 by jim_thompson5910(28546) About Me  on 2008-12-14 14:14:10 (Show Source):
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1. W->S
2. U->F
3. (S and F) -> O
4. ~O THEREFORE (~W v ~U)
------------------------------

5. ~(S and F) .......................... Modus Tollens (using lines 3, 4)

6. ~S v ~F .......................... DeMorgan's Theorem (using line 5)

7. S -> ~F .......................... Material Implication (using line 6)

8. W -> ~F .......................... Hypothetical Syllogism (using lines 1,7)

9. ~F -> ~U .......................... Transposition (using line 2)

10. W -> ~U .......................... Hypothetical Syllogism (using lines 8,10)

11. ~W v ~U .......................... Material Implication (using line 10)


Polynomials-and-rational-expressions/173199: This question is from textbook Introductory Algebra
Divide and, if possible, simplify.
x^2 + 7x + 10/x + 5 divided by x^2 - 4/5x - 10
1 solutions

Answer 128071 by jim_thompson5910(28546) About Me  on 2008-12-14 13:57:58 (Show Source):
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%28%28x%5E2%2B7x%2B10%29%2F%28x%2B5%29%29%2F%28%28x%5E2-4%29%2F%285x-10%29%29 Start with the given expression.


%28%28x%5E2%2B7x%2B10%29%2F%28x%2B5%29%29%28%285x-10%29%2F%28x%5E2-4%29%29 Multiply the first fraction %28x%5E2%2B7x%2B10%29%2F%28x%2B5%29 by the reciprocal of the second fraction %28x%5E2-4%29%2F%285x-10%29.


%28%28%28x%2B5%29%28x%2B2%29%29%2F%28x%2B5%29%29%28%285x-10%29%2F%28x%5E2-4%29%29 Factor x%5E2%2B7x%2B10 to get %28x%2B5%29%28x%2B2%29.


%28%28%28x%2B5%29%28x%2B2%29%29%2F%28x%2B5%29%29%28%285%28x-2%29%29%2F%28x%5E2-4%29%29 Factor 5x-10 to get 5%28x-2%29.


Factor x%5E2-4 to get %28x-2%29%28x%2B2%29.


%285%28x%2B5%29%28x%2B2%29%28x-2%29%29%2F%28%28x%2B5%29%28x-2%29%28x%2B2%29%29 Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


5 Simplify.


So %28%28x%5E2%2B7x%2B10%29%2F%28x%2B5%29%29%2F%28%28x%5E2-4%29%2F%285x-10%29%29 simplifies to 5.


In other words, %28%28x%5E2%2B7x%2B10%29%2F%28x%2B5%29%29%2F%28%28x%5E2-4%29%2F%285x-10%29%29=5 where x%3C%3E-5, x%3C%3E-2 or x%3C%3E2


Triangles/173177: Can you please help me with this question:
The altitudes of a triangle are concurrent at a point called the _________?
(1)centroid (2)circumcenter (3)incenter (4)orthocenter
1 solutions

Answer 128067 by jim_thompson5910(28546) About Me  on 2008-12-14 13:49:34 (Show Source):
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The altitudes of a triangle are concurrent at a point called the orthocenter.


Linear-systems/173188: This question is from textbook algebra2
-4x+y=-5
2x+y=7
1 solutions

Answer 128066 by jim_thompson5910(28546) About Me  on 2008-12-14 13:47:40 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:
system%28-4x%2By=-5%2C2x%2By=7%29


2%282x%2By%29=2%287%29 Multiply the both sides of the second equation by 2.


4x%2B2y=14 Distribute and multiply.


So we have the new system of equations:
system%28-4x%2By=-5%2C4x%2B2y=14%29


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%28-4x%2By%29%2B%284x%2B2y%29=%28-5%29%2B%2814%29


%28-4x%2B4x%29%2B%281y%2B2y%29=-5%2B14 Group like terms.


0x%2B3y=9 Combine like terms. Notice how the x terms cancel out.


3y=9 Simplify.


y=%289%29%2F%283%29 Divide both sides by 3 to isolate y.


y=3 Reduce.


------------------------------------------------------------------


-4x%2By=-5 Now go back to the first equation.


-4x%2B3=-5 Plug in y=3.


-4x%2B3=-5 Multiply.


-4x=-5-3 Subtract 3 from both sides.


-4x=-8 Combine like terms on the right side.


x=%28-8%29%2F%28-4%29 Divide both sides by -4 to isolate x.


x=2 Reduce.


So our answer is x=2 and y=3.


Which form the ordered pair .


This means that the system is consistent and independent.


Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.


Graph of -4x%2By=-5 (red) and 2x%2By=7 (green)


Polynomials-and-rational-expressions/173191: This question is from textbook Introductory Algebra
Factor by grouping
x^3 - 8x^2 + 5x - 40
1 solutions

Answer 128065 by jim_thompson5910(28546) About Me  on 2008-12-14 13:45:57 (Show Source):
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x%5E3-8x%5E2%2B5x-40 Start with the given expression


%28x%5E3-8x%5E2%29%2B%285x-40%29 Group like terms


x%5E2%28x-8%29%2B5%28x-8%29 Factor out the GCF x%5E2 out of the first group. Factor out the GCF 5 out of the second group


%28x%5E2%2B5%29%28x-8%29 Since we have the common term x-8, we can combine like terms


So x%5E3-8x%5E2%2B5x-40 factors to %28x%5E2%2B5%29%28x-8%29


Polynomials-and-rational-expressions/173192: This question is from textbook Introductory Algebra
Factor completely
4x^3 + 4x^2 - 80x
1 solutions

Answer 128064 by jim_thompson5910(28546) About Me  on 2008-12-14 13:44:32 (Show Source):
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4x%5E3%2B4x%5E2-80x Start with the given expression


4x%28x%5E2%2Bx-20%29 Factor out the GCF 4x


Now let's focus on the inner expression x%5E2%2Bx-20




------------------------------------------------------------



Looking at 1x%5E2%2B1x-20 we can see that the first term is 1x%5E2 and the last term is -20 where the coefficients are 1 and -20 respectively.

Now multiply the first coefficient 1 and the last coefficient -20 to get -20. Now what two numbers multiply to -20 and add to the middle coefficient 1? Let's list all of the factors of -20:



Factors of -20:
1,2,4,5,10,20

-1,-2,-4,-5,-10,-20 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -20
(1)*(-20)
(2)*(-10)
(4)*(-5)
(-1)*(20)
(-2)*(10)
(-4)*(5)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 1

First NumberSecond NumberSum
1-201+(-20)=-19
2-102+(-10)=-8
4-54+(-5)=-1
-120-1+20=19
-210-2+10=8
-45-4+5=1



From this list we can see that -4 and 5 add up to 1 and multiply to -20


Now looking at the expression 1x%5E2%2B1x-20, replace 1x with -4x%2B5x (notice -4x%2B5x adds up to 1x. So it is equivalent to 1x)

1x%5E2%2Bhighlight%28-4x%2B5x%29%2B-20


Now let's factor 1x%5E2-4x%2B5x-20 by grouping:


%281x%5E2-4x%29%2B%285x-20%29 Group like terms


x%28x-4%29%2B5%28x-4%29 Factor out the GCF of x out of the first group. Factor out the GCF of 5 out of the second group


%28x%2B5%29%28x-4%29 Since we have a common term of x-4, we can combine like terms

So 1x%5E2-4x%2B5x-20 factors to %28x%2B5%29%28x-4%29


So this also means that 1x%5E2%2B1x-20 factors to %28x%2B5%29%28x-4%29 (since 1x%5E2%2B1x-20 is equivalent to 1x%5E2-4x%2B5x-20)



------------------------------------------------------------




So our expression goes from 4x%28x%5E2%2Bx-20%29 and factors further to 4x%28x%2B5%29%28x-4%29


------------------
Answer:

So 4x%5E3%2B4x%5E2-80x factors to 4x%28x%2B5%29%28x-4%29


Polynomials-and-rational-expressions/173198: This question is from textbook Introductory Algebra
In a sports league of n teams in which each team plays every other team twice, the total number N of games to be played is given by N = n^2 - n. How many teams are in a softball league if the total number of games played is 42?
1 solutions

Answer 128063 by jim_thompson5910(28546) About Me  on 2008-12-14 13:41:47 (Show Source):
You can put this solution on YOUR website!
"if the total number of games played is 42", this means that N=42


N+=+n%5E2+-+n Start with the given equation


42+=+n%5E2+-+n Plug in N=42


0+=+n%5E2+-+n+-+42 Subtract 42 from both sides.


Notice we have a quadratic equation in the form of an%5E2%2Bbn%2Bc where a=1, b=-1, and c=-42


Let's use the quadratic formula to solve for n


n+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


n+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%281%29%28-42%29+%29%29%2F%282%281%29%29 Plug in a=1, b=-1, and c=-42


n+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%281%29%28-42%29+%29%29%2F%282%281%29%29 Negate -1 to get 1.


n+=+%281+%2B-+sqrt%28+1-4%281%29%28-42%29+%29%29%2F%282%281%29%29 Square -1 to get 1.


n+=+%281+%2B-+sqrt%28+1--168+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-42%29 to get -168


n+=+%281+%2B-+sqrt%28+1%2B168+%29%29%2F%282%281%29%29 Rewrite sqrt%281--168%29 as sqrt%281%2B168%29


n+=+%281+%2B-+sqrt%28+169+%29%29%2F%282%281%29%29 Add 1 to 168 to get 169


n+=+%281+%2B-+sqrt%28+169+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


n+=+%281+%2B-+13%29%2F%282%29 Take the square root of 169 to get 13.


n+=+%281+%2B+13%29%2F%282%29 or n+=+%281+-+13%29%2F%282%29 Break up the expression.


n+=+%2814%29%2F%282%29 or n+=++%28-12%29%2F%282%29 Combine like terms.


n+=+7 or n+=+-6 Simplify.


So the possible answers are n+=+7 or n+=+-6


However, you cannot have a negative number of teams. So this means that the only solution is n+=+7



=====================================================

Answer:


So the solution is n+=+7 which means that there are 7 teams in the league.


Linear-equations/173208: What is the equation in slope intercept form of the line that passes through (5,-7) and (2,1)?
What is the equation in standard form that passes through the point (-2,6) and has a slope of 4?
1 solutions

Answer 128060 by jim_thompson5910(28546) About Me  on 2008-12-14 13:34:20 (Show Source):
You can put this solution on YOUR website!
# 1

Problem:

What is the equation in slope intercept form of the line that passes through (5,-7) and (2,1)?



Solution:




First let's find the slope of the line through the points and


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%281--7%29%2F%282-5%29 Plug in y%5B2%5D=1, y%5B1%5D=-7, x%5B2%5D=2, and x%5B1%5D=5


m=%288%29%2F%282-5%29 Subtract -7 from 1 to get 8


m=%288%29%2F%28-3%29 Subtract 5 from 2 to get -3


m=-8%2F3 Reduce


So the slope of the line that goes through the points and is m=-8%2F3


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y--7=%28-8%2F3%29%28x-5%29 Plug in m=-8%2F3, x%5B1%5D=5, and y%5B1%5D=-7


y%2B7=%28-8%2F3%29%28x-5%29 Rewrite y--7 as y%2B7


y%2B7=%28-8%2F3%29x%2B%28-8%2F3%29%28-5%29 Distribute


y%2B7=%28-8%2F3%29x%2B40%2F3 Multiply


y=%28-8%2F3%29x%2B40%2F3-7 Subtract 7 from both sides.


y=%28-8%2F3%29x%2B19%2F3 Combine like terms. note: If you need help with fractions, check out this solver.


y=%28-8%2F3%29x%2B19%2F3 Simplify


So the equation that goes through the points and is y=%28-8%2F3%29x%2B19%2F3







# 2


Problem:


What is the equation in standard form that passes through the point (-2,6) and has a slope of 4




Solution:




If you want to find the equation of line with a given a slope of 4 which goes through the point (-2,6), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line


y-6=%284%29%28x--2%29 Plug in m=4, x%5B1%5D=-2, and y%5B1%5D=6 (these values are given)


y-6=%284%29%28x%2B2%29 Rewrite x--2 as x%2B2


y-6=4x%2B%284%29%282%29 Distribute 4


y-6=4x%2B8 Multiply 4 and 2 to get 8


y-6-4x=8 Subtract 4x from both sides.


y-4x=8%2B6 Add 6 to both sides.


-4x%2By=14 Combine like terms.


4x-y=-14 Multiply EVERY term by -1 to make the "x" coefficient positive.

-----------------------------------

Answer:


So the equation in standard form that has a slope of 4 and passes through the point (-2,6) is


4x-y=-14


Distributive-associative-commutative-properties/173210: Factorize 10x^2-x-3
1 solutions

Answer 128058 by jim_thompson5910(28546) About Me  on 2008-12-14 13:27:02 (Show Source):
You can put this solution on YOUR website!

Looking at the expression 10x%5E2-x-3, we can see that the first coefficient is 10, the second coefficient is -1, and the last term is -3.


Now multiply the first coefficient 10 by the last term -3 to get %2810%29%28-3%29=-30.


Now the question is: what two whole numbers multiply to -30 (the previous product) and add to the second coefficient -1?


To find these two numbers, we need to list all of the factors of -30 (the previous product).


Factors of -30:
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -30.
1*(-30)
2*(-15)
3*(-10)
5*(-6)
(-1)*(30)
(-2)*(15)
(-3)*(10)
(-5)*(6)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -1:


First NumberSecond NumberSum
1-301+(-30)=-29
2-152+(-15)=-13
3-103+(-10)=-7
5-65+(-6)=-1
-130-1+30=29
-215-2+15=13
-310-3+10=7
-56-5+6=1



From the table, we can see that the two numbers 5 and -6 add to -1 (the middle coefficient).


So the two numbers 5 and -6 both multiply to -30 and add to -1


Now replace the middle term -1x with 5x-6x. Remember, 5 and -6 add to -1. So this shows us that 5x-6x=-1x.


10x%5E2%2Bhighlight%285x-6x%29-3 Replace the second term -1x with 5x-6x.


%2810x%5E2%2B5x%29%2B%28-6x-3%29 Group the terms into two pairs.


5x%282x%2B1%29%2B%28-6x-3%29 Factor out the GCF 5x from the first group.


5x%282x%2B1%29-3%282x%2B1%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%285x-3%29%282x%2B1%29 Combine like terms. Or factor out the common term 2x%2B1

---------------------------------------------


Answer:


So 10x%5E2-x-3 factors to %285x-3%29%282x%2B1%29.


Note: you can check the answer by FOILing %285x-3%29%282x%2B1%29 to get 10x%5E2-x-3 or by graphing the original expression and the answer (the two graphs should be identical).


Quadratic_Equations/173216: What are all the solutions of 4x²+3x-8=3x²+2
1 solutions

Answer 128057 by jim_thompson5910(28546) About Me  on 2008-12-14 13:25:17 (Show Source):
You can put this solution on YOUR website!

4x%5E2%2B3x-8=3x%5E2%2B2 Start with the given equation.


4x%5E2%2B3x-8-3x%5E2-2=0 Subtract 3x%5E2 from both sides. Subtract 2 from both sides.


x%5E2%2B3x-10=0 Combine like terms.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=3, and c=-10


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%283%29+%2B-+sqrt%28+%283%29%5E2-4%281%29%28-10%29+%29%29%2F%282%281%29%29 Plug in a=1, b=3, and c=-10


x+=+%28-3+%2B-+sqrt%28+9-4%281%29%28-10%29+%29%29%2F%282%281%29%29 Square 3 to get 9.


x+=+%28-3+%2B-+sqrt%28+9--40+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-10%29 to get -40


x+=+%28-3+%2B-+sqrt%28+9%2B40+%29%29%2F%282%281%29%29 Rewrite sqrt%289--40%29 as sqrt%289%2B40%29


x+=+%28-3+%2B-+sqrt%28+49+%29%29%2F%282%281%29%29 Add 9 to 40 to get 49


x+=+%28-3+%2B-+sqrt%28+49+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%28-3+%2B-+7%29%2F%282%29 Take the square root of 49 to get 7.


x+=+%28-3+%2B+7%29%2F%282%29 or x+=+%28-3+-+7%29%2F%282%29 Break up the expression.


x+=+%284%29%2F%282%29 or x+=++%28-10%29%2F%282%29 Combine like terms.


x+=+2 or x+=+-5 Simplify.


So the answers are x+=+2 or x+=+-5



Linear-systems/173215: This question is from textbook Amsco's integrated algerbra 1
x+y=12
x-7=4

how do u go about solving a question like this??
1 solutions

Answer 128056 by jim_thompson5910(28546) About Me  on 2008-12-14 13:22:36 (Show Source):
You can put this solution on YOUR website!
Note: I'm assuming that you left out the variable "y" in the second equation and it should look like x-7y=4






Start with the given system of equations:

system%28x%2By=12%2Cx-7y=4%29


Let's solve this system by use of substitution



Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.




So let's isolate y in the first equation

x%2By=12 Start with the first equation


y=12-x Subtract x from both sides


y=-x%2B12 Rearrange the equation


---------------------

Since y=-x%2B12, we can now replace each y in the second equation with -x%2B12 to solve for x



x-7highlight%28%28-x%2B12%29%29=4 Plug in y=-x%2B12 into the second equation. In other words, replace each y with -x%2B12. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.



x%2B%28-7%29%28-1%29x%2B%28-7%29%2812%29=4 Distribute -7 to -x%2B12


x%2B7x-84=4 Multiply


8x-84=4 Combine like terms on the left side


8x=4%2B84Add 84 to both sides


8x=88 Combine like terms on the right side


x=%2888%29%2F%288%29 Divide both sides by 8 to isolate x



x=11 Divide





-----------------First Answer------------------------------


So the first part of our answer is: x=11









Since we know that x=11 we can plug it into the equation y=-x%2B12 (remember we previously solved for y in the first equation).



y=-x%2B12 Start with the equation where y was previously isolated.


y=-%2811%29%2B12 Plug in x=11


y=-11%2B12 Multiply


y=1 Combine like terms



-----------------Second Answer------------------------------


So the second part of our answer is: y=1









-----------------Summary------------------------------


So the solutions are:


x=11 and y=1


which form the ordered pair


Miscellaneous_Word_Problems/173173: This question is from textbook
Can someone explain this to me and show step by step so I can have a better understand of this problem thank you so much.
True or false: The function "f(x) = 3x" grows three times faster than the function "g(x) = x". Explain.


thank you so much

1 solutions

Answer 128052 by jim_thompson5910(28546) About Me  on 2008-12-14 13:12:58 (Show Source):
You can put this solution on YOUR website!
I'm assuming that the first function is f%28x%29=3%5Ex


Think about it this way.

If x=0, then f%280%29=3%5E0=1 and g%280%29=0.


If x=1, then f%281%29=3%5E1=3 and g%281%29=3.


If x=2, then f%282%29=3%5E2=9 and g%282%29=2.


If x=3, then f%283%29=3%5E3=27 and g%283%29=3.



So we have this table of values

xf(x)g(x)
010
131
292
3273


From the table, we can see that g%28x%29 increments by 1 as x increments by 1. On the other hand, we can see that f%28x%29 goes from 1 to 3 (a difference of 2), 3 to 9 (a difference of 6), 9 to 27 (a difference of 18), etc. So the differences between each term is: 2, 6, 18, etc....


This means that from x=0 to x=1, the average rate of change for g(x) is 2. From x=1 to x=2, the average rate of change for g(x) is 6. From x=2 to x=3, the average rate of change for f(x) is 18.

-------------------

So dividing the first average rate of change 2 by 1, we get 2%2F1=2. So from x=0 to x=1, f%28x%29 is growing twice as fast as g%28x%29.


Dividing the second average rate of change 6 by 1, we get 6%2F1=6. So from x=1 to x=2, f%28x%29 is growing six times as fast as g%28x%29.


Dividing the third average rate of change 18 by 1, we get 18%2F1=18. So from x=2 to x=3, f%28x%29 is growing eighteen times as fast as g%28x%29.


As you can see, the exponential function is not growing at a constant rate. So f%28x%29 cannot be growing 3 times faster than g%28x%29




Note: the function f%28x%29=3x does however grow three times faster than g%28x%29=x, but that is for another problem.



So that means that the statement is false.


Inequalities/173180: This question is from textbook Introductory Algebra
Solve using the addition and multiplication principles.
4z - 3 > 3z - 13
1 solutions

Answer 128051 by jim_thompson5910(28546) About Me  on 2008-12-14 13:11:27 (Show Source):
You can put this solution on YOUR website!

4z-3%3E3z-13 Start with the given inequality.


4z%3E3z-13%2B3 Add 3 to both sides.


4z-3z%3E-13%2B3 Subtract 3z from both sides.


z%3E-13%2B3 Combine like terms on the left side.


z%3E-10 Combine like terms on the right side.


----------------------------------------------------------------------

Answer:

So the answer is z%3E-10


Complex_Numbers/173218: What does the product (4+7i)(2-5i) equal?

What does the quotient (1+4i)/(5-2i) equal?
1 solutions

Answer 128050 by jim_thompson5910(28546) About Me  on 2008-12-14 13:07:53 (Show Source):
You can put this solution on YOUR website!
# 1

%284%2B7i%29%2A%282-5i%29 Start with the given expression.


%284%29%282%29%2B%284%29%28-5i%29%2B%287i%29%282%29%2B%287i%29%28-5i%29 FOIL.


8-20i%2B14i-35i%5E2 Multiply.


8-20i%2B14i-35%28-1%29 Replace i%5E2 with -1. Note: i%5E2=-1.


8-20i%2B14i%2B35 Multiply.


43-6i Combine like terms.


So %284%2B7i%29%2A%282-5i%29=43-6i.


So the expression is now in standard form a%2Bbi where a=43 and b=-6








# 2


%281%2B4i%29%2F%285-2i%29 Start with the given expression.


%28%281%2B4i%29%2F%285-2i%29%29%28%285%2B2i%29%2F%285%2B2i%29%29 Multiply the fraction by %285%2B2i%29%2F%285%2B2i%29 (which is the complex conjugate of the denominator).


%28%281%2B4i%29%285%2B2i%29%29%2F%28%285-2i%29%285%2B2i%29%29 Combine the fractions.


FOIL the numerator.


FOIL the denominator.


%285%2B2i%2B20i%2B8i%5E2%29%2F%2825%2B10i-10i-4i%5E2%29 Multiply.


%28-3%2B22i%29%2F%2829%29 Combine like terms.


-3%2F29%2B%2822%2F29%29%2Ai Break up the fraction.


So %281%2B4i%29%2F%285-2i%29=-3%2F29%2B%2822%2F29%29%2Ai.


So the expression is now in standard form a%2Bbi where a=-3%2F29 and b=22%2F29


Equations/173221: I need help on the equation 2(6d+3)= 18 - 3(16 - 3d)
1 solutions

Answer 128048 by jim_thompson5910(28546) About Me  on 2008-12-14 13:00:02 (Show Source):
You can put this solution on YOUR website!

2%286d%2B3%29=18-3%2816-3d%29 Start with the given equation.


12d%2B6=18-48%2B9d Distribute.


12d%2B6=9d-30 Combine like terms on the right side.


12d=9d-30-6 Subtract 6 from both sides.


12d-9d=-30-6 Subtract 9d from both sides.


3d=-30-6 Combine like terms on the left side.


3d=-36 Combine like terms on the right side.


d=%28-36%29%2F%283%29 Divide both sides by 3 to isolate d.


d=-12 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is d=-12


Quadratic_Equations/173222: Use completing the square to solve x²+8x-11=0
1 solutions

Answer 128047 by jim_thompson5910(28546) About Me  on 2008-12-14 12:57:46 (Show Source):
You can put this solution on YOUR website!

x%5E2%2B8x-11 Start with the given left side of the given equation.


Take half of the x coefficient 8 to get 4. In other words, %281%2F2%29%288%29=4.


Now square 4 to get 16. In other words, %284%29%5E2=%284%29%284%29=16


x%5E2%2B8x%2Bhighlight%2816-16%29-11 Now add and subtract 16. Make sure to place this after the "x" term. Notice how 16-16=0. So the expression is not changed.


%28x%5E2%2B8x%2B16%29-16-11 Group the first three terms.


%28x%2B4%29%5E2-16-11 Factor x%5E2%2B8x%2B16 to get %28x%2B4%29%5E2.


%28x%2B4%29%5E2-27 Combine like terms.


So after completing the square, x%5E2%2B8x-11 transforms to %28x%2B4%29%5E2-27. So x%5E2%2B8x-11=%28x%2B4%29%5E2-27.


So x%5E2%2B8x-11=0 is equivalent to %28x%2B4%29%5E2-27=0.


------------------------------------------------------------




%28x%2B4%29%5E2-27=0 Start with the given equation.


%28x%2B4%29%5E2=0%2B27Add 27 to both sides.


%28x%2B4%29%5E2=27 Combine like terms.


x%2B4=0%2B-sqrt%2827%29 Take the square root of both sides.


x%2B4=sqrt%2827%29 or x%2B4=-sqrt%2827%29 Break up the "plus/minus" to form two equations.


x%2B4=3%2Asqrt%283%29 or x%2B4=-3%2Asqrt%283%29 Simplify the square root.


x=-4%2B3%2Asqrt%283%29 or x=-4-3%2Asqrt%283%29 Subtract 4 from both sides.


--------------------------------------


Answer:


So the solutions are x=-4%2B3%2Asqrt%283%29 or x=-4-3%2Asqrt%283%29.