See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'jim_thompson5910'

jim_thompson5910 answered: 28493 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069 , 17070..17099 , 17100..17129 , 17130..17159 , 17160..17189 , 17190..17219 , 17220..17249 , 17250..17279 , 17280..17309 , 17310..17339 , 17340..17369 , 17370..17399 , 17400..17429 , 17430..17459 , 17460..17489 , 17490..17519 , 17520..17549 , 17550..17579 , 17580..17609 , 17610..17639 , 17640..17669 , 17670..17699 , 17700..17729 , 17730..17759 , 17760..17789 , 17790..17819 , 17820..17849 , 17850..17879 , 17880..17909 , 17910..17939 , 17940..17969 , 17970..17999 , 18000..18029 , 18030..18059 , 18060..18089 , 18090..18119 , 18120..18149 , 18150..18179 , 18180..18209 , 18210..18239 , 18240..18269 , 18270..18299 , 18300..18329 , 18330..18359 , 18360..18389 , 18390..18419 , 18420..18449 , 18450..18479 , 18480..18509 , 18510..18539 , 18540..18569 , 18570..18599 , 18600..18629 , 18630..18659 , 18660..18689 , 18690..18719 , 18720..18749 , 18750..18779 , 18780..18809 , 18810..18839 , 18840..18869 , 18870..18899 , 18900..18929 , 18930..18959 , 18960..18989 , 18990..19019 , 19020..19049 , 19050..19079 , 19080..19109 , 19110..19139 , 19140..19169 , 19170..19199 , 19200..19229 , 19230..19259 , 19260..19289 , 19290..19319 , 19320..19349 , 19350..19379 , 19380..19409 , 19410..19439 , 19440..19469 , 19470..19499 , 19500..19529 , 19530..19559 , 19560..19589 , 19590..19619 , 19620..19649 , 19650..19679 , 19680..19709 , 19710..19739 , 19740..19769 , 19770..19799 , 19800..19829 , 19830..19859 , 19860..19889 , 19890..19919 , 19920..19949 , 19950..19979 , 19980..20009 , 20010..20039 , 20040..20069 , 20070..20099 , 20100..20129 , 20130..20159 , 20160..20189 , 20190..20219 , 20220..20249 , 20250..20279 , 20280..20309 , 20310..20339 , 20340..20369 , 20370..20399 , 20400..20429 , 20430..20459 , 20460..20489 , 20490..20519 , 20520..20549 , 20550..20579 , 20580..20609 , 20610..20639 , 20640..20669 , 20670..20699 , 20700..20729 , 20730..20759 , 20760..20789 , 20790..20819 , 20820..20849 , 20850..20879 , 20880..20909 , 20910..20939 , 20940..20969 , 20970..20999 , 21000..21029 , 21030..21059 , 21060..21089 , 21090..21119 , 21120..21149 , 21150..21179 , 21180..21209 , 21210..21239 , 21240..21269 , 21270..21299 , 21300..21329 , 21330..21359 , 21360..21389 , 21390..21419 , 21420..21449 , 21450..21479 , 21480..21509 , 21510..21539 , 21540..21569 , 21570..21599 , 21600..21629 , 21630..21659 , 21660..21689 , 21690..21719 , 21720..21749 , 21750..21779 , 21780..21809 , 21810..21839 , 21840..21869 , 21870..21899 , 21900..21929 , 21930..21959 , 21960..21989 , 21990..22019 , 22020..22049 , 22050..22079 , 22080..22109 , 22110..22139 , 22140..22169 , 22170..22199 , 22200..22229 , 22230..22259 , 22260..22289 , 22290..22319 , 22320..22349 , 22350..22379 , 22380..22409 , 22410..22439 , 22440..22469 , 22470..22499 , 22500..22529 , 22530..22559 , 22560..22589 , 22590..22619 , 22620..22649 , 22650..22679 , 22680..22709 , 22710..22739 , 22740..22769 , 22770..22799 , 22800..22829 , 22830..22859 , 22860..22889 , 22890..22919 , 22920..22949 , 22950..22979 , 22980..23009 , 23010..23039 , 23040..23069 , 23070..23099 , 23100..23129 , 23130..23159 , 23160..23189 , 23190..23219 , 23220..23249 , 23250..23279 , 23280..23309 , 23310..23339 , 23340..23369 , 23370..23399 , 23400..23429 , 23430..23459 , 23460..23489 , 23490..23519 , 23520..23549 , 23550..23579 , 23580..23609 , 23610..23639 , 23640..23669 , 23670..23699 , 23700..23729 , 23730..23759 , 23760..23789 , 23790..23819 , 23820..23849 , 23850..23879 , 23880..23909 , 23910..23939 , 23940..23969 , 23970..23999 , 24000..24029 , 24030..24059 , 24060..24089 , 24090..24119 , 24120..24149 , 24150..24179 , 24180..24209 , 24210..24239 , 24240..24269 , 24270..24299 , 24300..24329 , 24330..24359 , 24360..24389 , 24390..24419 , 24420..24449 , 24450..24479 , 24480..24509 , 24510..24539 , 24540..24569 , 24570..24599 , 24600..24629 , 24630..24659 , 24660..24689 , 24690..24719 , 24720..24749 , 24750..24779 , 24780..24809 , 24810..24839 , 24840..24869 , 24870..24899 , 24900..24929 , 24930..24959 , 24960..24989 , 24990..25019 , 25020..25049 , 25050..25079 , 25080..25109 , 25110..25139 , 25140..25169 , 25170..25199 , 25200..25229 , 25230..25259 , 25260..25289 , 25290..25319 , 25320..25349 , 25350..25379 , 25380..25409 , 25410..25439 , 25440..25469 , 25470..25499 , 25500..25529 , 25530..25559 , 25560..25589 , 25590..25619 , 25620..25649 , 25650..25679 , 25680..25709 , 25710..25739 , 25740..25769 , 25770..25799 , 25800..25829 , 25830..25859 , 25860..25889 , 25890..25919 , 25920..25949 , 25950..25979 , 25980..26009 , 26010..26039 , 26040..26069 , 26070..26099 , 26100..26129 , 26130..26159 , 26160..26189 , 26190..26219 , 26220..26249 , 26250..26279 , 26280..26309 , 26310..26339 , 26340..26369 , 26370..26399 , 26400..26429 , 26430..26459 , 26460..26489 , 26490..26519 , 26520..26549 , 26550..26579 , 26580..26609 , 26610..26639 , 26640..26669 , 26670..26699 , 26700..26729 , 26730..26759 , 26760..26789 , 26790..26819 , 26820..26849 , 26850..26879 , 26880..26909 , 26910..26939 , 26940..26969 , 26970..26999 , 27000..27029 , 27030..27059 , 27060..27089 , 27090..27119 , 27120..27149 , 27150..27179 , 27180..27209 , 27210..27239 , 27240..27269 , 27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499, >>Next

Trigonometry-basics/684448: Solve the triangle using the given information.
a=7cm
b=4cm
c=5cm
How do I find the angles? Law of cosines?
Please provide all steps.
1 solutions

Answer 424099 by jim_thompson5910(28504) About Me  on 2012-11-24 20:50:24 (Show Source):
You can put this solution on YOUR website!
a^2 = b^2 + c^2 - 2*b*c*cos(A)

49 = 4^2 + 5^2 - 2*4*5*cos(A)

49 = 16 + 25 - 40*cos(A)

49 = 41 - 40*cos(A)

49 - 41 = -40*cos(A)

8 = -40*cos(A)

8/(-40) = cos(A)

-1/5 = cos(A)

cos(A) = -1/5

A = arccos(-1/5)

A = 101.536959

So the angle A is roughly 101.536959 degrees.

I'll let you find angles B and C



Trigonometry-basics/684424: Solve the triangle using the given information.
A=105degrees
b=12
c=9
I'm pretty sure you need to use law of sines: because your given two sides and one angle.
But I don't know how to start. Please provide full steps
1 solutions

Answer 424085 by jim_thompson5910(28504) About Me  on 2012-11-24 18:56:10 (Show Source):
You can put this solution on YOUR website!
You use the law of cosines actually to find the length of 'a'

a^2 = b^2 + c^2 - 2*b*c*cos(A)

a^2 = 12^2 + 9^2 - 2*12*9*cos(105)

a^2 = 225 - 216*cos(105)

a^2 = 225 - 216*(-0.258819)

a^2 = 280.904904

a = sqrt(280.904904)

a = 16.76021789

Now that you know that

a = 16.76021789
b = 12
c = 9

You can use the law of sines to find angles B and C. I'll show you how to find angle B and I'll let you find angle C

sin(B)/b = sin(A)/a

sin(B)/12 = sin(105)/16.76021789

sin(B)/12 = 0.9659258/16.76021789

sin(B)/12 = 0.0576321

sin(B) = 12*0.0576321

sin(B) = 0.6915852

B = arcsin(0.6915852)

B = 43.7557225

So the angle B is roughly 43.7557225 degrees

I'll let you find angle C

Note: there are 2 ways to find angle C, you can use the fact that A+B+C = 180 (ie all angles must add to 180) or you can use the law of sines again.


Triangles/684164: right angled triangles/triangles that have the same angles have _____?
1 solutions

Answer 423951 by jim_thompson5910(28504) About Me  on 2012-11-23 17:57:47 (Show Source):
You can put this solution on YOUR website!
right angled triangles/triangles that have the same angles have __proportional corresponding sides__


Percentage-and-ratio-word-problems/684161: If the ratio of buses to passengers is 1 to 17 and there are 51 passengers, how many buses are there?
1 solutions

Answer 423946 by jim_thompson5910(28504) About Me  on 2012-11-23 17:36:30 (Show Source):
You can put this solution on YOUR website!
1/17 = x/51

1*51 = 17x

51 = 17x

51/17 = x

3 = x

x = 3

So there are 3 buses.


Equations/684156: Show that the points A (3,-5), B (-3,-1) and C (7,1) are vertices of an isosceles triangle. Find the area? Help pls. with graph and solution!
1 solutions

Answer 423939 by jim_thompson5910(28504) About Me  on 2012-11-23 17:14:35 (Show Source):
You can put this solution on YOUR website!
Hint:

Find the distance between

* Points A and B

* Points B and C

* Points A and C

if two of those distances are the same, then you have an isosceles triangle

You can use the distance formula to do the above

distance formula: d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29

-------------------------------------------------------



To find the area, you can use hero's or herons formula, which can be seen at the link below (if you forget it)

http://www.mathsisfun.com/geometry/herons-formula.html


Let me know if you need more help with this. Thanks.


Linear-systems/684152: how do i solve 2x-3y=6
2x-y=7
substitution method linear systems

1 solutions

Answer 423937 by jim_thompson5910(28504) About Me  on 2012-11-23 16:56:39 (Show Source):
You can put this solution on YOUR website!
Hint:

Solve the second equation for y

2x-y=7

-y = -2x+7

y = 2x-7

Then plug this into the first equation

2x-3y=6

2x-3(2x-7) = 6

2x-6x+21 = 6

-4x+21 = 6

I'll let you finish. Solve for x. Then use the solution for x to find the solution for y.


Points-lines-and-rays/684131: Write an equation for the line that is parallel to the given line and passes through the given point. y = x + 8; (4, 10)
A. y = x
B. y = x + 6
C. y = x – 6
D. y = x + 6
1 solutions

Answer 423927 by jim_thompson5910(28504) About Me  on 2012-11-23 16:16:24 (Show Source):
You can put this solution on YOUR website!
y = x + 8 ----> m = 1, b = 8

-------------------------------------------------------

y = mx+b

y = 1x + b

y = x + b

10 = 4 + b

10-4 = b

6 = b

b = 6

-------------------------------------------------------

y = mx+b

y = 1x + 6

y = x + 6

So the answer is choice B


Graphs/684114: Describe in words how you would obtain the graph of y = 3(x-4)^2 from transmission of the graph y = x^2 make sketches of both parabolas on the same set of axis.
can you please explain this to me? thanks in advance
1 solutions

Answer 423911 by jim_thompson5910(28504) About Me  on 2012-11-23 14:41:46 (Show Source):
You can put this solution on YOUR website!
Step 1) Start with the graph of y = x^2 (shown in green)



==========================================================================

Step 2) Shift it 4 units to the right to get y = (x-4)^2 (shown in blue)






==========================================================================

Step 3) Then vertically stretch it by a factor of 3 to get y = 3(x-4)^2 (shown in purple)



==========================================================================

For the sake of comparison, here are the two graphs y = x^2 (in green) and y = 3(x-4)^2 (in blue)




and finally, here is the graph of just 3(x-4)^2 (in green)




Equations/684045: Find the slope and angle inclination of a line passing through A(7,-5) and B(4,4)?
Please answer.. I'm begging..
1 solutions

Answer 423908 by jim_thompson5910(28504) About Me  on 2012-11-23 14:11:22 (Show Source):
You can put this solution on YOUR website!
Note: is the first point . So this means that x%5B1%5D=7 and y%5B1%5D=-5.
Also, is the second point . So this means that x%5B2%5D=4 and y%5B2%5D=4.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%284--5%29%2F%284-7%29 Plug in y%5B2%5D=4, y%5B1%5D=-5, x%5B2%5D=4, and x%5B1%5D=7


m=%289%29%2F%284-7%29 Subtract -5 from 4 to get 9


m=%289%29%2F%28-3%29 Subtract 7 from 4 to get -3


m=-3 Reduce


So the slope of the line that goes through the points and is m=-3


The angle of inclination is

theta = arctan(rise/run)

theta = arctan(3/1) ... note: make the rise positive

theta = 71.56505

So the angle of inclination is roughly 71.56505 degrees


Radicals/684043: How to solve this :
(sqrt (2x-1))*(sqrt (2x-1))
1 solutions

Answer 423907 by jim_thompson5910(28504) About Me  on 2012-11-23 14:10:18 (Show Source):
You can put this solution on YOUR website!
(sqrt (2x-1))*(sqrt (2x-1)) = (sqrt (2x-1))^2

(sqrt (2x-1))*(sqrt (2x-1)) = 2x-1




test/684068:
1 solutions

Answer 423906 by jim_thompson5910(28504) About Me  on 2012-11-23 14:09:34 (Show Source):
You can put this solution on YOUR website!
problem missing


logarithm/683999: log(4)+log(x+5)=2
1 solutions

Answer 423861 by jim_thompson5910(28504) About Me  on 2012-11-22 20:51:18 (Show Source):
You can put this solution on YOUR website!
log(4)+log(x+5)=2

log(4(x+5))=2

4(x+5)=10^2

4(x+5)=100

x+5=100/4

x+5=25

x=25-5

x=20

So the solution is x=20. Don't forget to check it (I'll let you do this).


Quadratic_Equations/683994: A programmer is writing the code for a new interactive basketball game. As a result, she is using quadratic relations to model the path of the ball. During the game, when a ball is shot, the path it follows is modeled by the quadratic relation,h= -0.2d^2 + 3d + 6 , where h represented the height of the ball above the ground and d represented the distance of the ball from the shooter. Both distances are measured in feet.
How high was the ball when the shooter shot it?
What was the maximum height obtained by the ball?
A rim of a basketball net is 10 feet high. For what horizontal distance was the ball above the rim of the basketball net?
Please help for my review coming up ):
1 solutions

Answer 423860 by jim_thompson5910(28504) About Me  on 2012-11-22 20:49:04 (Show Source):
You can put this solution on YOUR website!
How high was the ball when the shooter shot it?

h=+-0.2d%5E2+%2B+3d+%2B+6

h=+-0.2%280%29%5E2+%2B+3%280%29+%2B+6 ... Plug in d = 0 (since the ball is zero ft away from the player when it is shot)

h=+-0.2%280%29+%2B+3%280%29+%2B+6+

h=+0+%2B+0+%2B+6+

h+=+6

So the ball is 6 ft off the ground when the shooter shot it.

=====================================================================================================================

What was the maximum height obtained by the ball?

To answer this question, we need to find the vertex

First replace all 'h' terms with y. Then replace all 'd' terms with 'x'

Now find the x coordinate of the vertex

x+=+-b%2F%282a%29

x+=+-3%2F%282%28-0.2%29%29

x+=+7.5

Then plug this in to find the y coordinate of the vertex

y+=+-0.2d%5E2+%2B+3d+%2B+6

y+=+-0.2%287.5%29%5E2+%2B+3%287.5%29+%2B+6

y+=+-0.2%2856.25%29+%2B+3%287.5%29+%2B+6

y+=+-11.25+%2B+22.5+%2B+6

y+=+17.25

The y coordinate of the vertex represents the highest point.

So the max height is 17.25 ft.

=====================================================================================================================

A rim of a basketball net is 10 feet high. For what horizontal distance was the ball above the rim of the basketball net?


Plug in h = 10 and solve for d

h+=+-0.2d%5E2+%2B+3d+%2B+6

10+=+-0.2d%5E2+%2B+3d+%2B+6

0+=+-0.2d%5E2+%2B+3d+%2B+6+-+10

0+=+-0.2d%5E2+%2B+3d+-+4

-0.2d%5E2+%2B+3d+-+4+=+0

10%28-0.2d%5E2+%2B+3d+-+4%29+=+10%2A0

-2d%5E2+%2B+30d+-+40+=+0

-1%28-2d%5E2+%2B+30d+-+40%29+=+-1%2A0

2d%5E2+-+30d+%2B+40+=+0

2%28d%5E2+-+15d+%2B+20%29+=+0

d%5E2+-+15d+%2B+20+=+0%2F2

d%5E2+-+15d+%2B+20+=+0

Now use the quadratic formula to solve for d

d+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29

d+=+%28-%28-15%29%2B-sqrt%28%28-15%29%5E2-4%281%29%2820%29%29%29%2F%282%281%29%29 Plug in a+=+1, b+=+-15, c+=+20

d+=+%2815%2B-sqrt%28225-%2880%29%29%29%2F%282%29

d+=+%2815%2B-sqrt%28145%29%29%2F2

d+=+%2815%2Bsqrt%28145%29%29%2F2 or d+=+%2815-sqrt%28145%29%29%2F2

d+=+13.520797 or d+=+1.479203

So the distance is either d+=+13.520797 or d+=+1.479203, which means that the distance it travels about 13.520797 - 1.479203 = 12.041594 feet horizontally when the ball is above the 10 ft rim.


test/683952: Dy/dx= xy/2lny
1 solutions

Answer 423830 by jim_thompson5910(28504) About Me  on 2012-11-22 17:08:25 (Show Source):
You can put this solution on YOUR website!
dy/dx= xy/2lny

dy= xy/2lny*dx

2ln(y)/y*dy= x*dx

int(2ln(y)/y*dy)= int(x*dx)

2*int(ln(y)/y*dy)= int(x*dx)

2*((1/2)*ln(|y|)^2)= (1/2)x^2 + C

ln(|y|)^2= (1/2)x^2 + C

ln(|y|)= sqrt( (1/2)x^2 + C )

ln(|y|) = sqrt( (1/2)x^2 + C )

|y| = e^(sqrt( (1/2)x^2 + C ))

y = +-e^(sqrt( (1/2)x^2 + C ))


Trigonometry-basics/683932: Convert the rectangular equation to polar form. y = x.
I'm confused because there are no numbers for y or x.
1 solutions

Answer 423827 by jim_thompson5910(28504) About Me  on 2012-11-22 15:22:39 (Show Source):
You can put this solution on YOUR website!
The slope of y = x is 1 or 1/1. So a 45-45-90 degree triangle forms telling us that y = x makes a 45 degree angle with the x-axis.

Therefore, the equation is if you want the angle in degrees. Or the equation is if you want the angle in radians.


test/683946: 1/6x+1/4x=-1
1 solutions

Answer 423826 by jim_thompson5910(28504) About Me  on 2012-11-22 15:18:44 (Show Source):
You can put this solution on YOUR website!
%281%2F6%29x%2B%281%2F4%29x=-1 Start with the given equation.


12%28%281%2Fcross%286%29%29x%2B%281%2Fcross%284%29%29x%29=12%28-1%29 Multiply both sides by the LCD 12 to clear any fractions.


2x%2B3x=-12 Distribute and multiply.


5x=-12 Combine like terms on the left side.


x=%28-12%29%2F%285%29 Divide both sides by 5 to isolate x.


----------------------------------------------------------------------

Answer:

So the solution is x=-12%2F5


Equations/683944: Solve for the zeroes: x^2+5x-6
1 solutions

Answer 423825 by jim_thompson5910(28504) About Me  on 2012-11-22 14:38:49 (Show Source):
You can put this solution on YOUR website!
x^2+5x-6 = 0

(x+6)(x-1) = 0

x+6=0 or x-1 = 0

x = -6 or x = 1

So the two solutions are x = -6 or x = 1


test/683943: 1/8y-1/2=1/4
1 solutions

Answer 423823 by jim_thompson5910(28504) About Me  on 2012-11-22 14:31:04 (Show Source):
You can put this solution on YOUR website!
(1/8)y-1/2=1/4

8((1/8)y-1/2)=8*(1/4)

y - 4 = 2

y = 2+4

y = 6


logarithm/683940: Write the expression in terms of natural logarithms. (Express all logarithmic functions in terms of ln(x) in your answer.)
log_(8.8)\(113\)
1 solutions

Answer 423820 by jim_thompson5910(28504) About Me  on 2012-11-22 13:58:52 (Show Source):
You can put this solution on YOUR website!
log_(8.8)\(113\) = ln(113)/ln(8.8) by the change of base formula


Graphs/683939: Write an equation of the line with the given slope and y-intercept.
slope: 7; y-intercet :4
I am thinking it will be...
y=4x+7

1 solutions

Answer 423818 by jim_thompson5910(28504) About Me  on 2012-11-22 13:48:16 (Show Source):
You can put this solution on YOUR website!
You have it backwards and it should be y+=+7x%2B4


Inequalities/683936:
1 solutions

Answer 423817 by jim_thompson5910(28504) About Me  on 2012-11-22 13:25:26 (Show Source):
You can put this solution on YOUR website!
Problem missing


Linear-equations/683937: it says write the slope-intercept form of the equation of the line through the given point with the given slope. Heres the question;
through:(-1,-1), slope=4

1 solutions

Answer 423814 by jim_thompson5910(28504) About Me  on 2012-11-22 13:05:54 (Show Source):
You can put this solution on YOUR website!
y+=+mx%2Bb

-1+=+%284%29%28-1%29%2Bb

-1+=+-4%2Bb

-1%2B4+=+b

3+=+b

b+=+3

So the equation of the line is y+=+4x%2B3


logarithm/683934: f(x)=√(25-x^2)
Find the domain.
1 solutions

Answer 423812 by jim_thompson5910(28504) About Me  on 2012-11-22 13:03:11 (Show Source):
You can put this solution on YOUR website!
25-x^2 >= 0

25 >= x^2

x^2 <= 25

sqrt(x^2) <= sqrt(25)

|x| <= 5

-5 <= x <= 5

So the domain is -5 <= x <= 5

Domain in set-builder notation:

Domain in interval notation:


Travel_Word_Problems/683928: A turtle travels 20m in 8minutes. How long does it take for the turtle to travel 0.5m?
1 solutions

Answer 423810 by jim_thompson5910(28504) About Me  on 2012-11-22 12:48:35 (Show Source):
You can put this solution on YOUR website!
20/8 = 0.5/x

20x = 8*0.5

20x = 4

x = 4/20

x = 1/5

x = 0.2

So it will take 0.2 minutes or 0.2*60 = 12 seconds.

==========================================================================

Alternative way to do this


d = rt

20 = r*8

20/8 = r

2.5 = r

r = 2.5

------------------------------

d = rt

0.5 = 2.5*t

0.5/2.5 = t

0.2 = t

t = 0.2

So we get the same answer.


Geometry_Word_Problems/683919:
1 solutions

Answer 423809 by jim_thompson5910(28504) About Me  on 2012-11-22 12:42:43 (Show Source):
You can put this solution on YOUR website!
Problem missing


Functions/683926: Is the following relation a function? Explain your answer.
(1,2), (2,3), (2,5), (2,7)
1 solutions

Answer 423808 by jim_thompson5910(28504) About Me  on 2012-11-22 12:42:09 (Show Source):
You can put this solution on YOUR website!
The x value of 2 maps to y = 3, y = 5 and y = 7 at the same time. So it is NOT a function.

It is only a function when every x value maps to EXACTLY ONE y value.


Note: Let's say that this requirement wasn't part of the definition of a function. If we have (2,3) and (2,5), then what is f(2)? Is it 3? or is it 5? It can't be both at the same time since f(2) is a single number. This is why the definition above is put in place.


Linear-systems/683910: can you please help me solve this:
Solve the following system by substitution
-2x=8y+18
-33=7y-4x
1 solutions

Answer 423807 by jim_thompson5910(28504) About Me  on 2012-11-22 12:39:29 (Show Source):
You can put this solution on YOUR website!
-2x = 8y+18

x = (8y+18)/(-2)

x = (8y)/(-2)+18/(-2)

x = -4y - 9


-------------------------------------------------------

-33 = 7y-4x

-33 = 7y-4(-4y-9)

-33 = 7y+16y+36

-33 = 23y+36

I'll let you finish. Once you have found the value of y, use it to find the value of x.


Matrices-and-determiminant/683916: Can you please help solve this:
Write an augmented matrix for the following system of equations.
x-4y+4z=-9
2x-9y+8z=1
6y-9z=-1
Thank you ;-)
1 solutions

Answer 423806 by jim_thompson5910(28504) About Me  on 2012-11-22 12:33:03 (Show Source):
You can put this solution on YOUR website!
x-4y+4z=-9
2x-9y+8z=1
6y-9z=-1


1x-4y+4z=-9
2x-9y+8z=1
0x+6y-9z=-1


1x+(-4)y+4z=-9
2x+(-9)y+8z=1
0x+6y+(-9)z=-1




Feel free to ask me any questions you have. Thanks.


Matrices-and-determiminant/683915: Please help me with this problem.
Solve the system. If the system has infinitely many solutions,write the set with z arbitrary.
5x-3y+z=0
x+y=0
-15x+9y-3z=0
Thanks
1 solutions

Answer 423804 by jim_thompson5910(28504) About Me  on 2012-11-22 12:23:59 (Show Source):
You can put this solution on YOUR website!
x+y=0

y=-x

-----------------------

5x-3y+z=0

5x-3(-x)+z=0

5x+3x+z=0

8x+z=0

----------------------

-15x+9y-3z=0

-15x+9(-x)-3z=0

-15x-9x-3z=0

-24x-3z=0

---------------------

So we have the new system of equations

8x+z=0
-24x-3z=0


3(8x+z)=3*0
-24x-3z=0

24x+3z=0
-24x-3z=0
----------
0x+0y=0

0=0

Since that equation is ALWAYS true regardless of what x, y and z are, this means that there are an infinite number of solutions.

Solve the first equation for x to get

8x+z = 0

8x = -z

x = -z/8

Since y = -x, we know that y = -(-z/8) ----> y = z/8


So in the end, x = -z/8, y = z/8 and z is a free variable (ie it can be any number)

Therefore, the final answer as an ordered triple is

============================================================================

Note: what does mean exactly? Well...


*** If z = 8, then becomes which turns into which is one of the infinitely many solutions. If you plug x = -1, y = 1 and z = 8 into the original system, you'll find that all 3 satisfy all 3 equations.




*** If z = 16, then becomes which turns into which is another solution of the infinitely many solutions. If you plug x = -2, y = 2 and z = 16 into the original system, you'll find that all 3 satisfy all 3 equations.


You can plug in ANY real number for 'z' to get an ordered triple that is a solution to the original system of equations.


Travel_Word_Problems/683920: If I am going 55 mph and another car is driving a mile behind me going the exact speed will they catch up to me?
1 solutions

Answer 423803 by jim_thompson5910(28504) About Me  on 2012-11-22 12:18:06 (Show Source):
You can put this solution on YOUR website!
No they will not because you both will travel the same distance in the same amount of time. However, you will have traveled a bit more distance because you got the head start. Since the car behind you travels the same distance as you (minus that head start), the car will never catch up or pass you.


Equations/683918: The density of an object is W/V. If the density of an object is 5.25x10^-7 oz/ft^3?
and the volume is 2.2x10^3 ft^3, then find the weight?
Honestly i get to an answer 2.39 x10^-10 but i guess it's nor right
So i'm be happy if somebody can help me out?
1 solutions

Answer 423802 by jim_thompson5910(28504) About Me  on 2012-11-22 12:15:58 (Show Source):
You can put this solution on YOUR website!
D = W/V

5.25x10^-7 = W/(2.2x10^3)

(5.25x10^-7)*(2.2x10^3) = W

(5.25*2.2)x(10^-7*10^3) = W

(11.55)x(10^-4) = W

(1.155 x 10^1)x(10^-4) = W

1.155 x (10^1*10^-4) = W

1.155 x 10^-3 = W

W = 1.155 x 10^-3

So the weight is roughly 1.155 x 10^-3 ounces or 0.001155 ounces.