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 Signed-numbers/181959: -4(-5+y)+4(5y+6)1 solutions Answer 136581 by jim_thompson5910(28546)   on 2009-02-14 19:55:43 (Show Source): You can put this solution on YOUR website! Start with the given expression. Distribute Multiply Combine like terms. So
 Signed-numbers/181960: y=1/4x+51 solutions Answer 136580 by jim_thompson5910(28546)   on 2009-02-14 19:52:25 (Show Source): You can put this solution on YOUR website!Do you want to graph this? Please post full instructions. If you want to graph, then... Looking at we can see that the equation is in slope-intercept form where the slope is and the y-intercept is Since this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis So we have one point Now since the slope is comprised of the "rise" over the "run" this means Also, because the slope is , this means: which shows us that the rise is 1 and the run is 4. This means that to go from point to point, we can go up 1 and over 4 So starting at , go up 1 unit and to the right 4 units to get to the next point Now draw a line through these points to graph So this is the graph of through the points and
 Linear-systems/181961: Find the values of x and y that solve the following systems of equations. 6x+7y=-5 4x+3y=-151 solutions Answer 136579 by jim_thompson5910(28546)   on 2009-02-14 19:50:18 (Show Source): You can put this solution on YOUR website! Start with the given system of equations: Multiply the both sides of the first equation by 2. Distribute and multiply. Multiply the both sides of the second equation by -3. Distribute and multiply. So we have the new system of equations: Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this: Group like terms. Combine like terms. Simplify. Divide both sides by to isolate . Reduce. ------------------------------------------------------------------ Now go back to the first equation. Plug in . Multiply. Subtract from both sides. Combine like terms on the right side. Divide both sides by to isolate . Reduce. So our answer is and . Which form the ordered pair . This means that the system is consistent and independent. Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer. Graph of (red) and (green)
Polynomials-and-rational-expressions/181957: 46. Factor completely. -3t^3+ 3t^2-6t

60. Factor polynomial completely. 10a^2+ab-2b^2
80. Factor completely. 4m^2+20m+25
90. Factor each polynomial completely, given that the binomial Following it is a factor of the polynomial. x^3-4x^2-3x-10, x-5
102. Solve each equation. t2+1=13/6t

1 solutions

Answer 136578 by jim_thompson5910(28546)   on 2009-02-14 19:49:08 (Show Source):
You can put this solution on YOUR website!
I'll do the first three to get you started:

# 46

Factor out the GCF

So factors to

================================================

# 60

Looking at we can see that the first term is and the last term is where the coefficients are 10 and -2 respectively.

Now multiply the first coefficient 10 and the last coefficient -2 to get -20. Now what two numbers multiply to -20 and add to the middle coefficient 1? Let's list all of the factors of -20:

Factors of -20:
1,2,4,5,10,20

-1,-2,-4,-5,-10,-20 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -20
(1)*(-20)
(2)*(-10)
(4)*(-5)
(-1)*(20)
(-2)*(10)
(-4)*(5)

note: remember, the product of a negative and a positive number is a negative number

Now which of these pairs add to 1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 1

First NumberSecond NumberSum
1-201+(-20)=-19
2-102+(-10)=-8
4-54+(-5)=-1
-120-1+20=19
-210-2+10=8
-45-4+5=1

From this list we can see that -4 and 5 add up to 1 and multiply to -20

Now looking at the expression , replace with (notice adds up to . So it is equivalent to )

Now let's factor by grouping:

Group like terms

Factor out the GCF of out of the first group. Factor out the GCF of out of the second group

Since we have a common term of , we can combine like terms

So factors to

So this also means that factors to (since is equivalent to )

------------------------------------------------------------

So factors to

================================================

# 80

Looking at we can see that the first term is and the last term is where the coefficients are 4 and 25 respectively.

Now multiply the first coefficient 4 and the last coefficient 25 to get 100. Now what two numbers multiply to 100 and add to the middle coefficient 20? Let's list all of the factors of 100:

Factors of 100:
1,2,4,5,10,20,25,50

-1,-2,-4,-5,-10,-20,-25,-50 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 100
1*100
2*50
4*25
5*20
10*10
(-1)*(-100)
(-2)*(-50)
(-4)*(-25)
(-5)*(-20)
(-10)*(-10)

note: remember two negative numbers multiplied together make a positive number

Now which of these pairs add to 20? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 20

First NumberSecond NumberSum
11001+100=101
2502+50=52
4254+25=29
5205+20=25
101010+10=20
-1-100-1+(-100)=-101
-2-50-2+(-50)=-52
-4-25-4+(-25)=-29
-5-20-5+(-20)=-25
-10-10-10+(-10)=-20

From this list we can see that 10 and 10 add up to 20 and multiply to 100

Now looking at the expression , replace with (notice adds up to . So it is equivalent to )

Now let's factor by grouping:

Group like terms

Factor out the GCF of out of the first group. Factor out the GCF of out of the second group

Since we have a common term of , we can combine like terms

So factors to

So this also means that factors to (since is equivalent to )

note: is equivalent to since the term occurs twice. So also factors to

------------------------------------------------------------

So factors to

 Signed-numbers/181958: -2(x+5)=5x+461 solutions Answer 136577 by jim_thompson5910(28546)   on 2009-02-14 19:42:37 (Show Source): You can put this solution on YOUR website! Start with the given equation. Distribute. Add to both sides. Subtract from both sides. Combine like terms on the left side. Combine like terms on the right side. Divide both sides by to isolate . Reduce. ---------------------------------------------------------------------- Answer: So the answer is
Polynomials-and-rational-expressions/181956: Factor each polynomial a^2-2a-35

1 solutions

Answer 136576 by jim_thompson5910(28546)   on 2009-02-14 19:33:03 (Show Source):
You can put this solution on YOUR website!

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .

Now multiply the first coefficient by the last term to get .

Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?

To find these two numbers, we need to list all of the factors of (the previous product).

Factors of :
1,5,7,35
-1,-5,-7,-35

Note: list the negative of each factor. This will allow us to find all possible combinations.

These factors pair up and multiply to .
1*(-35)
5*(-7)
(-1)*(35)
(-5)*(7)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :

First NumberSecond NumberSum
1-351+(-35)=-34
5-75+(-7)=-2
-135-1+35=34
-57-5+7=2

From the table, we can see that the two numbers and add to (the middle coefficient).

So the two numbers and both multiply to and add to

Now replace the middle term with . Remember, and add to . So this shows us that .

Replace the second term with .

Group the terms into two pairs.

Factor out the GCF from the first group.

Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.

Combine like terms. Or factor out the common term

---------------------------------------------

So factors to .

Note: you can check the answer by FOILing to get or by graphing the original expression and the answer (the two graphs should be identical).

Graphs/181947: graph the function f(x)=x^2-2
1 solutions

Answer 136569 by jim_thompson5910(28546)   on 2009-02-14 18:04:08 (Show Source):
You can put this solution on YOUR website!

Step 1: Finding the Vertex
Step 2: Finding two points to left of axis of symmetry
Step 3: Reflecting two points to get points right of axis of symmetry
Step 4: Plotting the Points (with table)
Step 5: Graphing the Parabola

In order to graph , we can follow the steps:

Step 1) Find the vertex (the vertex is the either the highest or lowest point on the graph). Also, the vertex is at the axis of symmetry of the parabola (ie it divides it in two).

Step 2) Once you have the vertex, find two points on the left side of the axis of symmetry (the line that vertically runs through the vertex).

Step 3) Reflect those two points over the axis of symmetry to get two more points on the right side of the axis of symmetry.

Step 4) Plot all of the points found (including the vertex).

Step 5) Draw a curve through all of the points to graph the parabola.

Let's go through these steps in detail

Step 1)

#### Finding the vertex:

In order to find the vertex, we first need to find the x-coordinate of the vertex.

To find the x-coordinate of the vertex, use this formula: .

From , we can see that , , and .

Plug in and .

Multiply 2 and to get .

Divide.

So the x-coordinate of the vertex is . Note: this means that the axis of symmetry is also .

Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.

Plug in .

Square to get .

Multiply and to get .

Combine like terms.

So the y-coordinate of the vertex is .

So the vertex is .

---------------------------------------------------------------------

Step 2)

#### Find two points to the left of the axis of symmetry:

Let's find the y value when

Plug in .

Square to get .

Multiply and to get .

Combine like terms.

So the first point to the left of the axis of symmetry is (-2,2)

---------------------

Let's find the y value when

Plug in .

Square to get .

Multiply and to get .

Combine like terms.

So the second point to the left of the axis of symmetry is (-1,-1)

---------------------------------------------------------------------

Step 3)

#### Reflecting the two points over the axis of symmetry:

Now remember, the parabola is symmetrical about the axis of symmetry (which is )

This means the y-value for (which is one unit from the axis of symmetry) is equal to the y-value of (which is also one unit from the axis of symmetry). So when , which gives us the point (1,-1). So we essentially reflected the point (-1,-1) over to (1,-1).

Also, the y-value for (which is two units from the axis of symmetry) is equal to the y-value of (which is also two units from the axis of symmetry). So when , which gives us the point (2,2). So we essentially reflected the point (-2,2) over to (2,2).

---------------------------------------------------------------------

Step 4)

#### Plotting the points:

Now lets make a table of the values we have calculated:

xy
-22
-1-1
0-2
1-1
22

Now let's plot the points:

---------------------------------------------------------------------

Step 5)

#### Drawing a curve through all of the points:

Now draw a curve through all of the points to graph :

Graph of

Coordinate-system/181940: plot the graphs of the following functions:
1. f(x) = 5^x
2. f(x) = 4^x+2
3. f(x) = (1/3)^x
4. f(x) = log of x to the base of 5
could u please show me on graphs for at least two of them. thank you so much
1 solutions

Answer 136559 by jim_thompson5910(28546)   on 2009-02-14 15:55:16 (Show Source):
You can put this solution on YOUR website!
To graph ANY function, simply follow this basic routine:

1) Plug in any x value to find it's corresponding function value (or y value). This gives you an ordered pair (x,y)

2) Plot the points that you calculated from step 1

3) Draw a smooth connected through ALL of the points that you plotted in step 2

I'll do the first two to get you started. The other two follow the same basic outline.

# 1

In order to graph , we need to plot a few points.

Plug in (note: you can start at any x-value).

Raise 5 to the -2nd power to get .

So when , . So we have the point (-2,0.04).

----------------------------

Plug in .

Raise 5 to the -1st power to get .

So when , . So we have the point (-1,0.2).

----------------------------

Plug in .

Raise 5 to the 0th power to get .

So when , . So we have the point (0,1).

----------------------------

Plug in .

Raise 5 to the 1st power to get .

So when , . So we have the point (1,5).

----------------------------

Now let's make a table of the values we just found.

#### Table of Values:



xy-20.04
-10.2
01
15



Now let's plot the points:

#### Graph:

Now draw a curve through all of the points to graph :

Graph of

================================================================

# 2

In order to graph , we need to plot a few points.

Plug in (note: you can start at any x-value).

Raise 4 to the -2nd power to get .

So when , . So we have the point (-4,0.063).

----------------------------

Plug in .

Raise 4 to the -1st power to get .

So when , . So we have the point (-3,0.25).

----------------------------

Plug in .

Raise 4 to the 0th power to get .

So when , . So we have the point (-2,1).

----------------------------

Plug in .

Raise 4 to the 1st power to get .

So when , . So we have the point (-1,4).

----------------------------

Now let's make a table of the values we just found.

#### Table of Values:



xy-40.063
-30.25
-21
-14



Now let's plot the points:

#### Graph:

Now draw a curve through all of the points to graph :

Graph of

 Graphs/181937: draw the graph of the following linear function and give the domain and range: h(x)=-2x+3?1 solutions Answer 136556 by jim_thompson5910(28546)   on 2009-02-14 15:05:04 (Show Source): You can put this solution on YOUR website! Looking at we can see that the equation is in slope-intercept form where the slope is and the y-intercept is Since this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis So we have one point Now since the slope is comprised of the "rise" over the "run" this means Also, because the slope is , this means: which shows us that the rise is -2 and the run is 1. This means that to go from point to point, we can go down 2 and over 1 So starting at , go down 2 units and to the right 1 unit to get to the next point Now draw a line through these points to graph So this is the graph of through the points and Now notice that the graph extends in both directions along the x-axis. So this means that ANY value of "x" can be plugged into the function. So the domain is all real numbers. Also, take note that the graph extends in both directions along the y-axis as well. So this tells us that the range is also ANY number. So the range is all real numbers.
Polynomials-and-rational-expressions/181934: These need to be factored completely
30z^8 + 44z^5 +16z^2 Could it be 2z^2(3z^ + 2)(5z^3 +4)
24x² + 14xy +2y²
(m+n)(x+3) + (m+n)(5+5) Could it be (m+n+3)(x+y+5)
Solve using the principal of zero products
(x+ 1/7)(x-4/5) = 0
Find the x-intercepts for the graph of the equation
Y = x² + 4x -45 Could it be (-9,0,(5,0)
Factor by grouping
-36x² -30x + 36 Could it be -6(3x-2)(2x+3)

1 solutions

Answer 136554 by jim_thompson5910(28546)   on 2009-02-14 14:25:55 (Show Source):
You can put this solution on YOUR website!
I'll do the first two, which will hopefully help you with the rest of the problems. If not, then repost.

# 1

Factor out the GCF

Now let's focus on the inner expression

------------------------------------------------------------

Looking at we can see that the first term is and the last term is where the coefficients are 15 and 8 respectively.

Now multiply the first coefficient 15 and the last coefficient 8 to get 120. Now what two numbers multiply to 120 and add to the middle coefficient 22? Let's list all of the factors of 120:

Factors of 120:
1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120

-1,-2,-3,-4,-5,-6,-8,-10,-12,-15,-20,-24,-30,-40,-60,-120 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 120
1*120
2*60
3*40
4*30
5*24
6*20
8*15
10*12
(-1)*(-120)
(-2)*(-60)
(-3)*(-40)
(-4)*(-30)
(-5)*(-24)
(-6)*(-20)
(-8)*(-15)
(-10)*(-12)

note: remember two negative numbers multiplied together make a positive number

Now which of these pairs add to 22? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 22

First NumberSecond NumberSum
11201+120=121
2602+60=62
3403+40=43
4304+30=34
5245+24=29
6206+20=26
8158+15=23
101210+12=22
-1-120-1+(-120)=-121
-2-60-2+(-60)=-62
-3-40-3+(-40)=-43
-4-30-4+(-30)=-34
-5-24-5+(-24)=-29
-6-20-6+(-20)=-26
-8-15-8+(-15)=-23
-10-12-10+(-12)=-22

From this list we can see that 10 and 12 add up to 22 and multiply to 120

Now looking at the expression , replace with (notice adds up to . So it is equivalent to )

Now let's factor by grouping:

Group like terms

Factor out the GCF of out of the first group. Factor out the GCF of out of the second group

Since we have a common term of , we can combine like terms

So factors to

So this also means that factors to (since is equivalent to )

------------------------------------------------------------

So our expression goes from and factors further to

------------------

So completely factors to

# 2

Factor out the GCF

Now let's focus on the inner expression

------------------------------------------------------------

Looking at we can see that the first term is and the last term is where the coefficients are 12 and 1 respectively.

Now multiply the first coefficient 12 and the last coefficient 1 to get 12. Now what two numbers multiply to 12 and add to the middle coefficient 7? Let's list all of the factors of 12:

Factors of 12:
1,2,3,4,6,12

-1,-2,-3,-4,-6,-12 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 12
1*12
2*6
3*4
(-1)*(-12)
(-2)*(-6)
(-3)*(-4)

note: remember two negative numbers multiplied together make a positive number

Now which of these pairs add to 7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 7

First NumberSecond NumberSum
1121+12=13
262+6=8
343+4=7
-1-12-1+(-12)=-13
-2-6-2+(-6)=-8
-3-4-3+(-4)=-7

From this list we can see that 3 and 4 add up to 7 and multiply to 12

Now looking at the expression , replace with (notice adds up to . So it is equivalent to )

Now let's factor by grouping:

Group like terms

Factor out the GCF of out of the first group. Factor out the GCF of out of the second group

Since we have a common term of , we can combine like terms

So factors to

So this also means that factors to (since is equivalent to )

------------------------------------------------------------

So our expression goes from and factors further to

------------------

So completely factors to

 Graphs/181883: The line through (2,-3) that is perpendicular to the line y= -4x + 8 written in standard form containing only integer coefficients. I am having a horrible time with these graphs, any help is greatly appreciated!1 solutions Answer 136508 by jim_thompson5910(28546)   on 2009-02-13 23:38:02 (Show Source): You can put this solution on YOUR website! We can see that the equation has a slope and a y-intercept . Now to find the slope of the perpendicular line, simply flip the slope to get . Now change the sign to get . So the perpendicular slope is . Now let's use the point slope formula to find the equation of the perpendicular line by plugging in the slope and the coordinates of the given point . Start with the point slope formula Plug in , , and Rewrite as Multiply both sides by 4. Distribute Subtract 12 from both sides. Subtract "x" from both sides. Combine like terms. Rearrange the terms. Multiply EVERY term by -1 to make the "x" coefficient positive. ============================================= Answer: So the equation of the line that is perpendicular to and goes through the point (2,-3) in standard form is Here's the graph of the two lines to verify the answer: Graph of the original equation (red) and the perpendicular line (green) through the point .
 Graphs/181882: The line through (-2,-1) that is parallel to the line 5x + 3y =9. I am having a horrible time trying to write solve this and then write it into standard form containing only integer coefficients.1 solutions Answer 136507 by jim_thompson5910(28546)   on 2009-02-13 23:12:05 (Show Source): You can put this solution on YOUR website! Start with the given equation. Rearrange the terms. Divide both sides by to isolate y. Break up the fraction. Reduce. We can see that the equation has a slope and a y-intercept . Since parallel lines have equal slopes, this means that we know that the slope of the unknown parallel line is . Now let's use the point slope formula to find the equation of the parallel line by plugging in the slope and the coordinates of the given point . Start with the point slope formula Plug in , , and Rewrite as Rewrite as Multiply both sides by 3. Distribute Add 5x to both sides. Subtract 3 from both sides. Combine and rearrange the terms. ======================================= Answer: So the equation of the line that is parallel to and that goes through (-2,-1) is: Also, the equation is in standard form where , , and
 Polynomials-and-rational-expressions/181878: This question is from textbook 5 - x-1 ____ ____ = 4 over x-x Is this correct? Thanks x x1 solutions Answer 136503 by jim_thompson5910(28546)   on 2009-02-13 22:24:20 (Show Source): You can put this solution on YOUR website! Start with the given expression. Combine the fractions. This is only possible if the denominators are equal (and they are) Distribute Combine like terms. So where
 Distributive-associative-commutative-properties/181868: Factor completely and show steps: x^2-3wx+2xy-6wy1 solutions Answer 136493 by jim_thompson5910(28546)   on 2009-02-13 20:21:39 (Show Source): You can put this solution on YOUR website! Start with the given expression Group like terms Factor out the GCF out of the first group. Factor out the GCF out of the second group Since we have the common term , we can combine like terms So factors to
 Expressions-with-variables/181877: I have tried this but I am having trouble, can you please help. Use substitution to solve each system. If it does not have one solution then put no solution or indinitely many solutions. 4X-5Y=-7 Y=5X1 solutions Answer 136491 by jim_thompson5910(28546)   on 2009-02-13 20:17:28 (Show Source): You can put this solution on YOUR website! Start with the given system Plug in into the first equation. In other words, replace each with . Notice we've eliminated the variables. So we now have a simple equation with one unknown. Distribute Combine like terms on the left side Divide both sides by -21 to isolate x Reduce Now that we know that , we can plug this into to find Substitute for each Multiply So our answer is and which also looks like
 Polynomials-and-rational-expressions/181870: Factor completely and show steps: 4x^2-36y^21 solutions Answer 136490 by jim_thompson5910(28546)   on 2009-02-13 20:12:19 (Show Source): You can put this solution on YOUR website! Start with the given expression. Rewrite as . Rewrite as . Notice how we have a difference of squares where in this case and . So let's use the difference of squares formula to factor the expression: Start with the difference of squares formula. Plug in and . So this shows us that factors to . In other words .
Polynomials-and-rational-expressions/181869: Factor completely and show steps:
x^2-5x-14
1 solutions

Answer 136489 by jim_thompson5910(28546)   on 2009-02-13 20:11:25 (Show Source):
You can put this solution on YOUR website!

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .

Now multiply the first coefficient by the last term to get .

Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?

To find these two numbers, we need to list all of the factors of (the previous product).

Factors of :
1,2,7,14
-1,-2,-7,-14

Note: list the negative of each factor. This will allow us to find all possible combinations.

These factors pair up and multiply to .
1*(-14)
2*(-7)
(-1)*(14)
(-2)*(7)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :

First NumberSecond NumberSum
1-141+(-14)=-13
2-72+(-7)=-5
-114-1+14=13
-27-2+7=5

From the table, we can see that the two numbers and add to (the middle coefficient).

So the two numbers and both multiply to and add to

Now replace the middle term with . Remember, and add to . So this shows us that .

Replace the second term with .

Group the terms into two pairs.

Factor out the GCF from the first group.

Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.

Combine like terms. Or factor out the common term

---------------------------------------------

So factors to .

Note: you can check the answer by FOILing to get or by graphing the original expression and the answer (the two graphs should be identical).

Polynomials-and-rational-expressions/181871: Factor completely and show steps:
6x^2-13x-5

1 solutions

Answer 136488 by jim_thompson5910(28546)   on 2009-02-13 20:10:38 (Show Source):
You can put this solution on YOUR website!

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .

Now multiply the first coefficient by the last term to get .

Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?

To find these two numbers, we need to list all of the factors of (the previous product).

Factors of :
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30

Note: list the negative of each factor. This will allow us to find all possible combinations.

These factors pair up and multiply to .
1*(-30)
2*(-15)
3*(-10)
5*(-6)
(-1)*(30)
(-2)*(15)
(-3)*(10)
(-5)*(6)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :

First NumberSecond NumberSum
1-301+(-30)=-29
2-152+(-15)=-13
3-103+(-10)=-7
5-65+(-6)=-1
-130-1+30=29
-215-2+15=13
-310-3+10=7
-56-5+6=1

From the table, we can see that the two numbers and add to (the middle coefficient).

So the two numbers and both multiply to and add to

Now replace the middle term with . Remember, and add to . So this shows us that .

Replace the second term with .

Group the terms into two pairs.

Factor out the GCF from the first group.

Factor out from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.

Combine like terms. Or factor out the common term

---------------------------------------------

So factors to .

Note: you can check the answer by FOILing to get or by graphing the original expression and the answer (the two graphs should be identical).

 Polynomials-and-rational-expressions/181848: This question is from textbook 3x^2+18x-48 ___________ 2x+16 Lowest terms Thank you1 solutions Answer 136443 by jim_thompson5910(28546)   on 2009-02-13 15:26:11 (Show Source): You can put this solution on YOUR website! Start with the given expression Factor the numerator Factor the denominator Highlight the common terms. Cancel out the common terms. Simplify Distribute ======================================= Answer: So simplifies to In other words, where
 Functions/181843: Write an equation of the line given the y-intercept and slope:m=1/2,b=31 solutions Answer 136441 by jim_thompson5910(28546)   on 2009-02-13 15:14:49 (Show Source): You can put this solution on YOUR website! Start with the general slope-intercept equation Plug in and So the equation of the line is
 Polynomials-and-rational-expressions/181838: This question is from textbook 4x^4-10x^3+8x^2 _______________ 2x Thank you, I am really confused.1 solutions Answer 136439 by jim_thompson5910(28546)   on 2009-02-13 15:05:49 (Show Source): You can put this solution on YOUR website! Start with the given expression Factor out the GCF Break down into Highlight the common terms. Cancel out the common terms. Simplify (by removing the canceled terms) Distribute ================================== Answer: So simplifies to In other words, where