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Radicals/186806: This question is from textbook saxon algebra 2
Simplify. sqrt%28128%29+-+sqrt%2875%29+-+sqrt%2898%29
The square root 75 is confusing. What do you do with that?
1 solutions

Answer 140025 by jim_thompson5910(28503) About Me  on 2009-03-15 17:41:22 (Show Source):
You can put this solution on YOUR website!

sqrt%28128%29-sqrt%2875%29-sqrt%2898%29 Start with the given expression


8%2Asqrt%282%29-sqrt%2875%29-sqrt%2898%29 Simplify sqrt%28128%29 to get 8%2Asqrt%282%29. Note: If you need help with simplifying square roots, check out this solver.


8%2Asqrt%282%29-5%2Asqrt%283%29-sqrt%2898%29 Simplify sqrt%2875%29 to get 5%2Asqrt%283%29.


8%2Asqrt%282%29-5%2Asqrt%283%29-7%2Asqrt%282%29 Simplify sqrt%2898%29 to get 7%2Asqrt%282%29.


%288%2Asqrt%282%29-7%2Asqrt%282%29%29-5%2Asqrt%283%29 Group like terms.


sqrt%282%29-5%2Asqrt%283%29 Combine like terms.


So sqrt%28128%29-sqrt%2875%29-sqrt%2898%29=sqrt%282%29-5%2Asqrt%283%29


Graphs/186798: This question is from textbook saxon algebra 2
Evaluate the piecewise function for x=0 and x=6.
f(x)={18, if x is less than 0
{7, if 0 is less than or equal to x is less than 6
{-3, if x is greater than or equal to 6
I worked it out to: when x=0, f(x)= -6 so f(0)= -6,
when x=6, f(x)= -3, so f(6)= -3
Am I correct?
1 solutions

Answer 140024 by jim_thompson5910(28503) About Me  on 2009-03-15 17:38:52 (Show Source):
You can put this solution on YOUR website!
The piecewise function




really means that

f%28x%29=18 ONLY when x%3C0, or f%28x%29=7 ONLY when 0%3C=x%3C6, or f%28x%29=-3 ONLY when x%3E=6


Since x=0 is in the interval 0%3C=x%3C6, this means that f%280%29=7 (as this function corresponds with this interval).


Also, because x=6 is in the interval x%3E=6 (which is the third interval), this means that f%286%29=-3 since this is the corresponding function to the given interval.


Radicals/186790: I need to find the cubed root of 27%2F1000 .
Please show your work.
Thank you
1 solutions

Answer 140013 by jim_thompson5910(28503) About Me  on 2009-03-15 16:10:37 (Show Source):
You can put this solution on YOUR website!
root%283%2C27%2F1000%29=root%283%2C27%29%2Froot%283%2C1000%29=3%2F10


Note: 3%5E3=27 and 10%5E3=1000. So this means that root%283%2C27%29=3 and root%283%2C1000%29=10


So root%283%2C27%2F1000%29=3%2F10


Square-cubic-other-roots/186786: Could someone help me with this one;
sqrt(-25)sqrt(-9)
My answer was 15, but it got marked wrong on my test, but sqrt(-25)=-5 and sqrt(-9)=-3 and -5*-3=15 so I dont really understand why its wrong.
1 solutions

Answer 140004 by jim_thompson5910(28503) About Me  on 2009-03-15 15:17:58 (Show Source):
You can put this solution on YOUR website!
Note: sqrt%28-25%29%3C%3E-5 and sqrt%28-9%29%3C%3E-3 since you CANNOT take the square root of a negative number. Instead, we denote the value i=sqrt%28-1%29 where 'i' is an imaginary number.


So...




This means that sqrt%28-25%29%2Asqrt%28-9%29=-15


So you were off by a sign.


Square-cubic-other-roots/186777: Could someone help me out here?
I understand how to simplify sqrt(3/25) but how do you simplify;
sqrt(a^2)/sqrt(b^5)
or
sqrt(a/b)sqrt(a^2)/(b^2)
1 solutions

Answer 139999 by jim_thompson5910(28503) About Me  on 2009-03-15 14:57:21 (Show Source):
You can put this solution on YOUR website!
sqrt%28a%5E2%29%2Fsqrt%28b%5E5%29 Start with the given expression.


sqrt%28a%5E2%29%2Fsqrt%28b%5E2%2Ab%5E2%2Ab%29 Factor b%5E5 to get b%5E2%2Ab%5E2%2Ab


sqrt%28a%5E2%29%2F%28sqrt%28b%5E2%29%2Asqrt%28b%5E2%29%2Asqrt%28b%29%29 Break up the square root.


a%2F%28b%2Ab%2Asqrt%28b%29%29 Take the square root of a%5E2 to get 'a'. Take the square root of b%5E2 to get 'b'


a%2F%28b%5E2%2Asqrt%28b%29%29 Multiply


%28a%2Asqrt%28b%29%29%2F%28b%5E2%2Asqrt%28b%29%2Asqrt%28b%29%29 Multiply BOTH the numerator and denominator by sqrt%28b%29


%28a%2Asqrt%28b%29%29%2F%28b%5E2%2Ab%29 Multiply sqrt%28b%29 by itself to get 'b'


%28a%2Asqrt%28b%29%29%2F%28b%5E3%29 Multiply



So sqrt%28a%5E2%29%2Fsqrt%28b%5E5%29=%28a%2Asqrt%28b%29%29%2F%28b%5E3%29 where both 'a' and 'b' are positive.


Systems-of-equations/186755: 2x+4y=12
x +y= 4


answer: (2,2)

i need a full break down on how my text book got 2,2 as a solution
1 solutions

Answer 139993 by jim_thompson5910(28503) About Me  on 2009-03-15 14:44:37 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:
system%282x%2B4y=12%2Cx%2By=4%29


-2%28x%2By%29=-2%284%29 Multiply the both sides of the second equation by -2.


-2x-2y=-8 Distribute and multiply.


So we have the new system of equations:
system%282x%2B4y=12%2C-2x-2y=-8%29


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%282x%2B4y%29%2B%28-2x-2y%29=%2812%29%2B%28-8%29


%282x%2B-2x%29%2B%284y%2B-2y%29=12%2B-8 Group like terms.


0x%2B2y=4 Combine like terms.


2y=4 Simplify.


y=%284%29%2F%282%29 Divide both sides by 2 to isolate y.


y=2 Reduce.


------------------------------------------------------------------


2x%2B4y=12 Now go back to the first equation.


2x%2B4%282%29=12 Plug in y=2.


2x%2B8=12 Multiply.


2x=12-8 Subtract 8 from both sides.


2x=4 Combine like terms on the right side.


x=%284%29%2F%282%29 Divide both sides by 2 to isolate x.


x=2 Reduce.


So the solutions are x=2 and y=2.


Which form the ordered pair .


This means that the system is consistent and independent.


Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.


Graph of 2x%2B4y=12 (red) and x%2By=4 (green)


Rectangles/186761: This question is from textbook A Survey of Mathematics with Application
Find the volume of a rectangular bread box that is 9 inches tall and has a base that is 18 inches by 12 inches.
1 solutions

Answer 139986 by jim_thompson5910(28503) About Me  on 2009-03-15 14:07:49 (Show Source):
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Volume = Length * Width * Height


Volume = 18 * 12 * 9


Volume = 216 * 9


Volume = 1,944


So the volume of the rectangular bread box is 1,944 cubic inches.


real-numbers/186769: Which is a irrational number the square root of 5, the square root, of 9, the square root of -1, or the square root of 2 thirds
1 solutions

Answer 139985 by jim_thompson5910(28503) About Me  on 2009-03-15 14:03:59 (Show Source):
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sqrt%285%29 is irrational (since it CANNOT be written as a fraction of integers)


sqrt%289%29=3 which is rational since 3=3%2F1


sqrt%28-1%29=i which is complex (ie not real)


is irrational as it can't be written as a fraction of 2 integers.


Systems-of-equations/186754: 2x-3y= 7
3x+7y= -1
answer (2,-1)


need a break down of how my text book got the solutions 2, -1
1 solutions

Answer 139984 by jim_thompson5910(28503) About Me  on 2009-03-15 13:36:28 (Show Source):
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Start with the given system of equations:
system%282x-3y=7%2C3x%2B7y=-1%29


3%282x-3y%29=3%287%29 Multiply the both sides of the first equation by 3.


6x-9y=21 Distribute and multiply.


-2%283x%2B7y%29=-2%28-1%29 Multiply the both sides of the second equation by -2.


-6x-14y=2 Distribute and multiply.


So we have the new system of equations:
system%286x-9y=21%2C-6x-14y=2%29


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%286x-9y%29%2B%28-6x-14y%29=%2821%29%2B%282%29


%286x%2B-6x%29%2B%28-9y%2B-14y%29=21%2B2 Group like terms.


0x%2B-23y=23 Combine like terms.


-23y=23 Simplify.


y=%2823%29%2F%28-23%29 Divide both sides by -23 to isolate y.


y=-1 Reduce.


------------------------------------------------------------------


6x-9y=21 Now go back to the first equation.


6x-9%28-1%29=21 Plug in y=-1.


6x%2B9=21 Multiply.


6x=21-9 Subtract 9 from both sides.


6x=12 Combine like terms on the right side.


x=%2812%29%2F%286%29 Divide both sides by 6 to isolate x.


x=2 Reduce.


So the solutions are x=2 and y=-1.


Which form the ordered pair .


This means that the system is consistent and independent.


Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.


Graph of 2x-3y=7 (red) and 3x%2B7y=-1 (green)


Equations/186744: my daughter has brought home her homework but left her book at school. Can you help? All the questions are similar so i would just need help with a couple to get started. Thanks
-2x-4=3x-19
-3-2x=-7x+57
-3x+2=-5x+16
4-6x=x+32
1 solutions

Answer 139982 by jim_thompson5910(28503) About Me  on 2009-03-15 13:32:52 (Show Source):
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# 1



-2x-4=3x-19 Start with the given equation.


-2x=3x-19%2B4 Add 4 to both sides.


-2x-3x=-19%2B4 Subtract 3x from both sides.


-5x=-19%2B4 Combine like terms on the left side.


-5x=-15 Combine like terms on the right side.


x=%28-15%29%2F%28-5%29 Divide both sides by -5 to isolate x.


x=3 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=3






# 2



-3-2x=-7x%2B57 Start with the given equation.


-2x=-7x%2B57%2B3 Add 3 to both sides.


-2x%2B7x=57%2B3 Add 7x to both sides.


5x=57%2B3 Combine like terms on the left side.


5x=60 Combine like terms on the right side.


x=%2860%29%2F%285%29 Divide both sides by 5 to isolate x.


x=12 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=12





# 3



-3x%2B2=-5x%2B16 Start with the given equation.


-3x=-5x%2B16-2 Subtract 2 from both sides.


-3x%2B5x=16-2 Add 5x to both sides.


2x=16-2 Combine like terms on the left side.


2x=14 Combine like terms on the right side.


x=%2814%29%2F%282%29 Divide both sides by 2 to isolate x.


x=7 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=7





# 4



4-6x=x%2B32 Start with the given equation.


-6x=x%2B32-4 Subtract 4 from both sides.


-6x-x=32-4 Subtract x from both sides.


-7x=32-4 Combine like terms on the left side.


-7x=28 Combine like terms on the right side.


x=%2828%29%2F%28-7%29 Divide both sides by -7 to isolate x.


x=-4 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=-4


real-numbers/186706: This is the last question for an assignment. My mind is mush at this time, can someone please help? It is a three part question. The instructor wants us to write three (3) quadratic equations with a,b,and c (coefficients of x^2, x, and the constant) as: 1: Integers, 2: Rational numbers, and 3: Irrational numbers. I need this by 3 a.m. central time. Please help! This is for Intermediate Algebra and does not come from a book that I know of.
1 solutions

Answer 139960 by jim_thompson5910(28503) About Me  on 2009-03-15 00:43:03 (Show Source):
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Remember, all quadratics are of the form y=ax%5E2%2Bbx%2Bc

So when they say that they want the values of 'a', 'b' and 'c' to be integers, they just want them to be whole numbers. So we could say that a=1, b=2, and c=7 to get y=x%5E2%2B2x%2B7


For rational values, just substitute in fractions for 'a', 'b' and 'c'

Finally, for irrational values, just plug in non perfect square roots such as sqrt%282%29, sqrt%285%29 and sqrt%2811%29 into 'a', 'b' and 'c'


Rational-functions/186689: x^-4-3x^-2-4=0
1 solutions

Answer 139950 by jim_thompson5910(28503) About Me  on 2009-03-14 21:58:03 (Show Source):
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x%5E%28-4%29-3x%5E%28-2%29-4=0 Start with the given equation.


Let z=x%5E%28-2%29. So this means that z%5E2=x%5E%28-4%29


z%5E2-3z-4=0 Replace x%5E%28-4%29 with z%5E2. Replace x%5E%28-2%29 with z




Notice we have a quadratic equation in the form of az%5E2%2Bbz%2Bc where a=1, b=-3, and c=-4


Let's use the quadratic formula to solve for z


z+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


z+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%28-4%29+%29%29%2F%282%281%29%29 Plug in a=1, b=-3, and c=-4


z+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%28-4%29+%29%29%2F%282%281%29%29 Negate -3 to get 3.


z+=+%283+%2B-+sqrt%28+9-4%281%29%28-4%29+%29%29%2F%282%281%29%29 Square -3 to get 9.


z+=+%283+%2B-+sqrt%28+9--16+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-4%29 to get -16


z+=+%283+%2B-+sqrt%28+9%2B16+%29%29%2F%282%281%29%29 Rewrite sqrt%289--16%29 as sqrt%289%2B16%29


z+=+%283+%2B-+sqrt%28+25+%29%29%2F%282%281%29%29 Add 9 to 16 to get 25


z+=+%283+%2B-+sqrt%28+25+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


z+=+%283+%2B-+5%29%2F%282%29 Take the square root of 25 to get 5.


z+=+%283+%2B+5%29%2F%282%29 or z+=+%283+-+5%29%2F%282%29 Break up the expression.


z+=+%288%29%2F%282%29 or z+=++%28-2%29%2F%282%29 Combine like terms.


z+=+4 or z+=+-1 Simplify.


----------------------------------------


z+=+4 Start with the first solution


x%5E%28-2%29+=+4 Plug in z=x%5E%28-2%29


1%2Fx%5E2+=+4 Rewrite the left side with a positive exponent.


1=4x%5E2 Multiply both sides by x%5E2.


x%5E2=1%2F4 Divide both sides by 4 and rearrange the equation


x=sqrt%281%2F4%29 or x=-sqrt%281%2F4%29 Take the square root of both sides (don't forget the plus/minus)


x=1%2F2 or x=-1%2F2 Take the square root of 1%2F4 to get 1%2F2


So the first two solutions are x=1%2F2 or x=-1%2F2

-----------------------------------------------

z+=+-1 Start with the second solution


x%5E%28-2%29+=+-1 Plug in z=x%5E%28-2%29


1%2Fx%5E2+=+-1 Rewrite the left side with a positive exponent.


1=-x%5E2 Multiply both sides by x%5E2


x%5E2=-1 Divide both sides by -1 and rearrange the equation.


x=sqrt%28-1%29 or x=-sqrt%28-1%29 Take the square root of both sides (don't forget the plus/minus)


x=i or x=-i Simplify (note: i=sqrt%28-1%29



So the next two solutions are x=i or x=-i


=================================================

Answer:

So the solutions are x=1%2F2, x=-1%2F2, x=i or x=-i


Rational-functions/186688: 1+3/x=5/x^2
1 solutions

Answer 139946 by jim_thompson5910(28503) About Me  on 2009-03-14 21:22:46 (Show Source):
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1%2B3%2Fx=5%2Fx%5E2 Start with the given equation.


x%5E2%2B3x=5 Multiply EVERY term by the LCD x%5E2 to clear out the fractions.


x%5E2%2B3x-5=0 Subtract 5 from both sides.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=3, and c=-5


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%283%29+%2B-+sqrt%28+%283%29%5E2-4%281%29%28-5%29+%29%29%2F%282%281%29%29 Plug in a=1, b=3, and c=-5


x+=+%28-3+%2B-+sqrt%28+9-4%281%29%28-5%29+%29%29%2F%282%281%29%29 Square 3 to get 9.


x+=+%28-3+%2B-+sqrt%28+9--20+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-5%29 to get -20


x+=+%28-3+%2B-+sqrt%28+9%2B20+%29%29%2F%282%281%29%29 Rewrite sqrt%289--20%29 as sqrt%289%2B20%29


x+=+%28-3+%2B-+sqrt%28+29+%29%29%2F%282%281%29%29 Add 9 to 20 to get 29


x+=+%28-3+%2B-+sqrt%28+29+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%28-3%2Bsqrt%2829%29%29%2F%282%29 or x+=+%28-3-sqrt%2829%29%29%2F%282%29 Break up the expression.


So the answers are x+=+%28-3%2Bsqrt%2829%29%29%2F%282%29 or x+=+%28-3-sqrt%2829%29%29%2F%282%29


which approximate to x=1.193 or x=-4.193


Rational-functions/186687: 1-13/x+36/x^2=0
1 solutions

Answer 139945 by jim_thompson5910(28503) About Me  on 2009-03-14 21:18:35 (Show Source):
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1-13%2Fx%2B36%2Fx%5E2=0 Start with the given equation.


x%5E2-13x%2B36=0 Multiply EVERY term by the LCD x%5E2 to clear out the fractions.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=-13, and c=36


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%28-13%29+%2B-+sqrt%28+%28-13%29%5E2-4%281%29%2836%29+%29%29%2F%282%281%29%29 Plug in a=1, b=-13, and c=36


x+=+%2813+%2B-+sqrt%28+%28-13%29%5E2-4%281%29%2836%29+%29%29%2F%282%281%29%29 Negate -13 to get 13.


x+=+%2813+%2B-+sqrt%28+169-4%281%29%2836%29+%29%29%2F%282%281%29%29 Square -13 to get 169.


x+=+%2813+%2B-+sqrt%28+169-144+%29%29%2F%282%281%29%29 Multiply 4%281%29%2836%29 to get 144


x+=+%2813+%2B-+sqrt%28+25+%29%29%2F%282%281%29%29 Subtract 144 from 169 to get 25


x+=+%2813+%2B-+sqrt%28+25+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%2813+%2B-+5%29%2F%282%29 Take the square root of 25 to get 5.


x+=+%2813+%2B+5%29%2F%282%29 or x+=+%2813+-+5%29%2F%282%29 Break up the expression.


x+=+%2818%29%2F%282%29 or x+=++%288%29%2F%282%29 Combine like terms.


x+=+9 or x+=+4 Simplify.


So the solutions are x+=+9 or x+=+4


Linear-systems/186684: half of a certain number is subtracted from 26 and the result is then tripled, and the answer is 18. find the number
1 solutions

Answer 139944 by jim_thompson5910(28503) About Me  on 2009-03-14 21:09:17 (Show Source):
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"half of a certain number is subtracted from 26 and the result is then tripled, and the answer is 18" translates to 3%2826-%281%2F2%29x%29=18



3%2826-%281%2F2%29x%29=18 Start with the given equation.


26-%281%2F2%29x=18%2F3 Divide both sides by 3.


26-%281%2F2%29x=6 Reduce


-%281%2F2%29x=6-26 Subtract 26 from both sides.


-%281%2F2%29x=-20 Combine like terms.


x=-20%28-2%29 Multiply both sides by -2.


x=40 Multiply


===============================================

Answer:

So the solution is x=40 which means that the number is 40


sets-and-operations/186683: U = {1,2,3,4,5,6,7}
A = {1,3,5,7}
B = {1,2,3}
C = {2,3,4,5,6}
Find each of the following sets

(C' upsidedown U A) U (C' upsidedown U B')



1 solutions

Answer 139943 by jim_thompson5910(28503) About Me  on 2009-03-14 21:02:58 (Show Source):
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Since B = {1,2,3} and U = {1,2,3,4,5,6,7}, this means that B'= everything in U that is NOT in B = {4,5,6,7}


Also, because C = {2,3,4,5,6} and U = {1,2,3,4,5,6,7}, this means C' = everything in U that is NOT in C = {1,7}


Now let's evaluate . So simply find the elements that BOTH C' and A have in common:


Note: the elements 1 and 7 are BOTH in C' and A


-----------------------------------------------

Now evaluate . So simply find the elements that BOTH C' and B' have in common:


Note: 7 is the only element that is BOTH in C' and B


So




then becomes




combine them to get





Answer:

So this means that



sets-and-operations/186680: Set Operations and Venn Diagrams with three sets
Find each of the following sets
(C' backwards U A) U (C' backwards or upsidedown U B')


1 solutions

Answer 139941 by jim_thompson5910(28503) About Me  on 2009-03-14 20:28:55 (Show Source):
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Looking at





notice how there is the common term C' and the alternation of set operators and . This means that the distributive property can be used here:


So




Complex_Numbers/186677: how do you solve 3x+8yi=15-32i
1 solutions

Answer 139940 by jim_thompson5910(28503) About Me  on 2009-03-14 20:18:29 (Show Source):
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The equation 3x%2B8yi=15-32i means that


Real part of the left side = Real part of the right side

and

Imaginary part of the left side = Imaginary part of the right side



This means that


3x=15 and 8yi=-32i


So 3x=15 ---> x=5

and 8yi=-32i ---> 8y=-32 ---> y=-4


So x=5 and y=-4


Complex_Numbers/186676: how do you simplify 5√(-6)*4√(-10)
1 solutions

Answer 139939 by jim_thompson5910(28503) About Me  on 2009-03-14 20:15:45 (Show Source):
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5%2Asqrt%28-6%29%2A4%2Asqrt%28-10%29 Start with the given expression.


5%2Asqrt%28-1%2A6%29%2A4%2Asqrt%28-1%2A10%29 Factor -6 into -1*6. Factor -10 into -1*10


5%2Asqrt%28-1%29%2Asqrt%286%29%2A4%2Asqrt%28-1%29%2Asqrt%2810%29 Break up the square root.


5%2Ai%2Asqrt%286%29%2A4%2Ai%2Asqrt%2810%29 Replace the square root of -1 with 'i' (note: i=sqrt%28-1%29)


%285%2A4%29%2A%28sqrt%286%29%2Asqrt%2810%29%29%2A%28i%2Ai%29 Rearrange the terms.


%285%2A4%29%2A%28sqrt%286%29%2Asqrt%2810%29%29%2A%28i%5E2%29 Multiply 'i' and 'i' to get i%5E2


%285%2A4%29%2A%28sqrt%286%29%2Asqrt%2810%29%29%2A%28-1%29 Replace i%5E2 with -1. Remember, since i=sqrt%28-1%29, then i%5E2=-1


%285%2A4%2A%28-1%29%29%2A%28sqrt%286%29%2Asqrt%2810%29%29 Rearrange the terms again


-20%2A%28sqrt%286%29%2Asqrt%2810%29%29 Multiply


-20%2Asqrt%286%2A10%29 Combine the roots.


-20%2Asqrt%2860%29%29 Multiply


-20%2Asqrt%284%2A15%29 Factor 60 into 4*15. Note: one factor is a perfect square


-20%2Asqrt%284%29%2Asqrt%2815%29 Break up the square root.


-20%2A2%2Asqrt%2815%29 Take the square root of 4 to get 2


-40%2Asqrt%2815%29 Multiply


So 5%2Asqrt%28-6%29%2A4%2Asqrt%28-10%29=-40%2Asqrt%2815%29


Pythagorean-theorem/186672: I need a day-to-day example using the Pythagorean theorem. I cant come up with anything. My mind is completely blank. Can anyone help me??? Thank you!
1 solutions

Answer 139937 by jim_thompson5910(28503) About Me  on 2009-03-14 19:33:48 (Show Source):
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Let's say that you have a ladder resting against a wall. You know that the ladder is 10 feet long (it says so on the ladder itself) and you know that the ladder reaches 8 feet on the wall (ie the 8 ft mark on the wall) since there's a tape measure that runs from the ceiling to the floor. Now the question is: How far is the base of the ladder from the wall?


Just as a visual guide, here's what the problem would look like:






Now let's say that you want to solve this problem:


Solution:


Since the legs are 8 and x this means that a=8 and b=x


Also, since the hypotenuse is 10, this means that c=10.


a%5E2%2Bb%5E2=c%5E2 Start with the Pythagorean theorem.


8%5E2%2Bx%5E2=10%5E2 Plug in a=8, b=x, c=10


64%2Bx%5E2=10%5E2 Square 8 to get 64.


64%2Bx%5E2=100 Square 10 to get 100.


x%5E2=100-64 Subtract 64 from both sides.


x%5E2=36 Combine like terms.


x=sqrt%2836%29 Take the square root of both sides. Note: only the positive square root is considered (since a negative length doesn't make sense).


x=6 Simplify the square root.


================================================================


Answer:


So the solution is x=6.


This means that the base of the ladder is 6 ft from the wall.


Radicals/186671: solve, step by step √(x+5)+√(2x+3)=9
√=square root
( )=what is under the square roots
1 solutions

Answer 139936 by jim_thompson5910(28503) About Me  on 2009-03-14 19:27:49 (Show Source):
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sqrt%28x%2B5%29%2Bsqrt%282x%2B3%29=9 Start with the given equation.


sqrt%28x%2B5%29=9-sqrt%282x%2B3%29 Subtract sqrt%282x%2B3%29 from both sides.


x%2B5=%289-sqrt%282x%2B3%29%29%5E2 Square both sides


x%2B5=81-18%2Asqrt%282x%2B3%29%2B2x%2B3 FOIL


x%2B5=84%2B2x-18%2Asqrt%282x%2B3%29 Combine like terms.


x%2B5-84-2x=-18%2Asqrt%282x%2B3%29 Subtract 84 from both sides. Subtract 2x from both sides.


-x-79=-18%2Asqrt%282x%2B3%29 Combine like terms.


%28-x-79%29%5E2=%28-18%2Asqrt%282x%2B3%29%29%5E2 Square both sides


x%5E2%2B158x%2B6241=324%2A%282x%2B3%29 FOIL and square the right side


x%5E2%2B158x%2B6241=648x%2B972 Distribute


x%5E2%2B158x%2B6241-648x-972=0 Get everything to the left side.


x%5E2-490x%2B5269=0 Combine like terms.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=-490, and c=5269


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%28-490%29+%2B-+sqrt%28+%28-490%29%5E2-4%281%29%285269%29+%29%29%2F%282%281%29%29 Plug in a=1, b=-490, and c=5269


x+=+%28490+%2B-+sqrt%28+%28-490%29%5E2-4%281%29%285269%29+%29%29%2F%282%281%29%29 Negate -490 to get 490.


x+=+%28490+%2B-+sqrt%28+240100-4%281%29%285269%29+%29%29%2F%282%281%29%29 Square -490 to get 240100.


x+=+%28490+%2B-+sqrt%28+240100-21076+%29%29%2F%282%281%29%29 Multiply 4%281%29%285269%29 to get 21076


x+=+%28490+%2B-+sqrt%28+219024+%29%29%2F%282%281%29%29 Subtract 21076 from 240100 to get 219024


x+=+%28490+%2B-+sqrt%28+219024+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%28490+%2B-+468%29%2F%282%29 Take the square root of 219024 to get 468.


x+=+%28490+%2B+468%29%2F%282%29 or x+=+%28490+-+468%29%2F%282%29 Break up the expression.


x+=+%28958%29%2F%282%29 or x+=++%2822%29%2F%282%29 Combine like terms.


x+=+479 or x+=+11 Simplify.


So the possible answers are x+=+479 or x+=+11



However, if you plug in x+=+479, the original equation will NOT be true. So x+=+479 is NOT a solution



===========================================================

Answer:

So the solution is x+=+11


Exponential-and-logarithmic-functions/186664: i really need help on these problems.. thank you :)
describe how the graph of the function is related to the graph of its parent function.
y = 3^x-4
Write the logarithmic expression as a single logarithm.
log a - log ab
expand the logarithm
log y^2/z
write the experssion as a single natural log
5 ln a + 3 ln b
1 solutions

Answer 139935 by jim_thompson5910(28503) About Me  on 2009-03-14 19:20:54 (Show Source):
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I'll do the first two to get you going in the right direction.

# 1



I'm assuming that the equation is y=3%5Ex-4.


The parent function is y=3%5Ex which looks like


Graph of y=3%5Ex



and the function y=3%5Ex-4 is simply the parent function shifted down 4 units like this


Graph of y=3%5Ex (red) and y=3%5Ex-4 (green)






# 2

log%2810%2C%28a%29%29-log%2810%2C%28ab%29%29 Start with the given expression.


log%2810%2C%28a%2F%28ab%29%29%29 Combine the logs using the identity log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29


log%2810%2C%28cross%28a%29%2F%28cross%28a%29%2Ab%29%29%29 Cancel out the common terms.


log%2810%2C%281%2Fb%29%29


So log%2810%2C%28a%29%29-log%2810%2C%28ab%29%29=log%2810%2C%281%2Fb%29%29 where a%3E0 and b%3E0


Complex_Numbers/186670: how do you solve, step by step,: x(2+6i)+y(3+8i)=-6-14i?
1 solutions

Answer 139933 by jim_thompson5910(28503) About Me  on 2009-03-14 19:12:44 (Show Source):
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x%282%2B6i%29%2By%283%2B8i%29=-6-14i Start with the given equation.


2x%2B6xi%2B3y%2B8yi=-6-14i Distribute


%282x%2B3y%29%2B%286x%2B8y%29i=-6-14i Rearrange and group like terms.


This means that

2x%2B3y=-6 (this is the real part)

and

6x%2B8y=-14 (this is the imaginary part)



So all that you have to do is solve the system



system%282x%2B3y=-6%2C6x%2B8y=-14%29


to find 'x' and 'y'


Polynomials-and-rational-expressions/186669: This is a problem I need help with.[(1/9)+(1/3x)] / [(x/9)-(1/x)]
1 solutions

Answer 139931 by jim_thompson5910(28503) About Me  on 2009-03-14 19:06:59 (Show Source):
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In order to simplify %281%2F9%2B1%2F%283x%29%29%2F%28x%2F9-1%2Fx%29 let's simplify the numerator and denominator separately first


Simplifying the numerator 1%2F9%2B1%2F%283x%29:



1%2F9%2B1%2F%283x%29 Start with the numerator. Take note that the LCD 9x%2F9x



x%2F%289x%29%2B1%2F%283x%29 Multiply the first fraction by x%2Fx


x%2F%289x%29%2B3%2F%289x%29 Multiply the second fraction by 3%2F3


%28x%2B3%29%2F%289x%29 Add the fractions.


So 1%2F9%2B1%2F%283x%29=%28x%2B3%29%2F%289x%29 where x%3C%3E0


----------------------------------------------------------


Simplifying the denominator x%2F9-1%2Fx:


x%2F9-1%2Fx Start with the denominator. Take note that the LCD 9x%2F9x


%28x%5E2%29%2F%289x%29-1%2Fx Multiply the first fraction by x%2Fx


%28x%5E2%29%2F%289x%29-9%2F%289x%29 Multiply the second fraction by 9%2F9


%28x%5E2-9%29%2F%289x%29 Subtract the fractions.


So x%2F9-1%2Fx=%28x%5E2-9%29%2F%289x%29 where x%3C%3E0



---------------------------------------------------------------


Now that we've simplified the numerator of %281%2F9%2B1%2F%283x%29%29%2F%28x%2F9-1%2Fx%29, we then get:


%28%28x%2B3%29%2F%289x%29%29%2F%28%28x%5E2-9%29%2F%289x%29%29




%28%28x%2B3%29%2F%289x%29%29%2F%28%28x%5E2-9%29%2F%289x%29%29 Start with the simplified expression.


%28%28x%2B3%29%2F%289x%29%29%2A%28%289x%29%2F%28x%5E2-9%29%29 Multiply the first fraction by the reciprocal of the second fraction.


%28%28x%2B3%29%2F%289x%29%29%2A%28%289x%29%2F%28%28x%2B3%29%28x-3%29%29%29 Factor x%5E2-9 to get %28x%2B3%29%28x-3%29


%289x%28x%2B3%29%29%2F%289x%28x%2B3%29%28x-3%29%29%29 Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


1%2F%28x-3%29 Simplify



==================================================================

Answer:

So %281%2F9%2B1%2F%283x%29%29%2F%28x%2F9-1%2Fx%29 simplified to %28%28x%2B3%29%2F%289x%29%29%2F%28%28x%5E2-9%29%2F%289x%29%29 which in turn simplified to 1%2F%28x-3%29



So in short, %281%2F9%2B1%2F%283x%29%29%2F%28x%2F9-1%2Fx%29 simplifies to 1%2F%28x-3%29



In other words, %281%2F9%2B1%2F%283x%29%29%2F%28x%2F9-1%2Fx%29=1%2F%28x-3%29 where x%3C%3E-3, x%3C%3E0, or x%3C%3E3


test/186666: do you tutors have a website in which you provide tutoring for calculis problems, if so please email me a link to the website
1 solutions

Answer 139929 by jim_thompson5910(28503) About Me  on 2009-03-14 18:56:04 (Show Source):


Exponential-and-logarithmic-functions/186668: Write an exponential function for a graph that includes the given points.
1.)(–1, 5),(0.5, 40)
1 solutions

Answer 139928 by jim_thompson5910(28503) About Me  on 2009-03-14 18:44:07 (Show Source):
You can put this solution on YOUR website!
y=a%2Ab%5Ex Start with the general exponential equation.


5=a%2Ab%5E%28-1%29 Plug in x=-1 and y=5 Note: this is the point (-1,5)


5=a%2Fb Rewrite the right side with a positive exponent


a=5b Solve for 'a'


-----------------------


y=a%2Ab%5Ex Go back to the first equation


40=a%2Ab%5E%280.5%29 Plug in x=0.5 and y=40 Note: this is the point (0.5, 40)


40=%285b%29%2Ab%5E%280.5%29 Plug in a=5b


40=5b%5E%281%2B0.5%29 Multiply by adding the exponents.


40=5b%5E%281.5%29 Add


40%2F5=b%5E%281.5%29 Divide both sides by 5.


8=b%5E%283%2F2%29 Reduce and rewrite 1.5 as 3%2F2


8%5E2=b%5E3 Square both sides.


64=b%5E3 Square 8 to get 64


root%283%2C64%29=b Take the cube root of both sides


b=4 Take the cube root of 64 to get 4


--------------------------


a=5b Go back to the first isolated equation


a=5%284%29 Plug in b=4


a=20 Multiply


===========================

Answer:


So the exponential function that goes through (–1, 5),(0.5, 40) is f%28x%29=20%2A4%5Ex







Polynomials-and-rational-expressions/186667: Please respond to this problem. I really need your help !! The problem is 1/9+1/3x/x/9-1/x=.
1 solutions

Answer 139927 by jim_thompson5910(28503) About Me  on 2009-03-14 18:37:01 (Show Source):
You can put this solution on YOUR website!
There are two many division signs and no parenthesis. Which terms are the numerator? Is the expression (1/9+1/3x)/(x/9-1/x) ??? Please repost with parenthesis.


Polynomials-and-rational-expressions/186665: I need help on two(2) problems; Please!! they are (3/x+1)+(2/x-1)= and the next one is (1/9+1/3x)(x/9-1/x)=
1 solutions

Answer 139926 by jim_thompson5910(28503) About Me  on 2009-03-14 18:35:25 (Show Source):
You can put this solution on YOUR website!
# 1

3%2F%28x%2B1%29%2B2%2F%28x-1%29 Start with the given expression.


Multiply the first fraction by %28x-1%29%2F%28x-1%29


%283x-3%29%2F%28%28x%2B1%29%28x-1%29%29%2B2%2F%28x-1%29 Distribute


Multiply the second fraction by %28x%2B1%29%2F%28x%2B1%29


%283x-3%29%2F%28%28x%2B1%29%28x-1%29%29%2B%282x%2B2%29%2F%28%28x%2B1%29%28x-1%29%29 Distribute


%283x-3%2B2x%2B2%29%2F%28%28x%2B1%29%28x-1%29%29 Combine the fractions.


%285x-1%29%2F%28%28x%2B1%29%28x-1%29%29 Combine like terms.


So 3%2F%28x%2B1%29%2B2%2F%28x-1%29=%285x-1%29%2F%28%28x%2B1%29%28x-1%29%29 where x%3C%3E1 or x%3C%3E-1


---------------------------------------------------------------

# 2

%281%2F9%2B1%2F%283x%29%29%28x%2F9-1%2Fx%29 Start with the given expression.


FOIL the expression


Note: use the formula %28A%2BB%29%28C%2BD%29=%28A%29%28C%29%2B%28A%29%28D%29%2B%28B%29%28C%29%2B%28B%29%28D%29 to FOIL


x%2F81-1%2F%289x%29%2B1%2F27-1%2F%283x%5E2%29 Multiply


So %281%2F9%2B1%2F%283x%29%29%28x%2F9-1%2Fx%29=x%2F81-1%2F%289x%29%2B1%2F27-1%2F%283x%5E2%29


Finance/186659: I need help with a Pre-Algebra problem and it says: identify the domain and range of the relation. Then tell whether the relation is a function.
Here is the table
x| -2 | -1 | 3 | -5 | -8 |
--------------------------
Y| 5 | -2 | 5 | -2 | -2 |
1 solutions

Answer 139918 by jim_thompson5910(28503) About Me  on 2009-03-14 15:29:03 (Show Source):
You can put this solution on YOUR website!
Domain: All possible inputs (ie x values): {-2, -1, 3, -5, -8}

Range: All possible outputs (y values): {5, -2, 5, -2, -2}


Now look at the domain. Do you see any repeated x values? Since there are no repeated x values, this means that this relation is a function.


Square-cubic-other-roots/186657: sqrt 60
1 solutions

Answer 139916 by jim_thompson5910(28503) About Me  on 2009-03-14 15:03:27 (Show Source):


Expressions-with-variables/186604: 7x+3y/3x-x+10y/3x
1 solutions

Answer 139873 by jim_thompson5910(28503) About Me  on 2009-03-13 22:51:17 (Show Source):
You can put this solution on YOUR website!
%287x%2B3y%29%2F%283x%29-%28x%2B10y%29%2F%283x%29 Start with the given expression.


%287x%2B3y-%28x%2B10y%29%29%2F%283x%29 Combine the fractions.


%287x%2B3y-x-10y%29%2F%283x%29 Distribute


%286x-7y%29%2F%283x%29 Combine like terms.


So %287x%2B3y%29%2F%283x%29-%28x%2B10y%29%2F%283x%29=%286x-7y%29%2F%283x%29 where x%3C%3E0