See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'jim_thompson5910'

jim_thompson5910 answered: 28465 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069 , 17070..17099 , 17100..17129 , 17130..17159 , 17160..17189 , 17190..17219 , 17220..17249 , 17250..17279 , 17280..17309 , 17310..17339 , 17340..17369 , 17370..17399 , 17400..17429 , 17430..17459 , 17460..17489 , 17490..17519 , 17520..17549 , 17550..17579 , 17580..17609 , 17610..17639 , 17640..17669 , 17670..17699 , 17700..17729 , 17730..17759 , 17760..17789 , 17790..17819 , 17820..17849 , 17850..17879 , 17880..17909 , 17910..17939 , 17940..17969 , 17970..17999 , 18000..18029 , 18030..18059 , 18060..18089 , 18090..18119 , 18120..18149 , 18150..18179 , 18180..18209 , 18210..18239 , 18240..18269 , 18270..18299 , 18300..18329 , 18330..18359 , 18360..18389 , 18390..18419 , 18420..18449 , 18450..18479 , 18480..18509 , 18510..18539 , 18540..18569 , 18570..18599 , 18600..18629 , 18630..18659 , 18660..18689 , 18690..18719 , 18720..18749 , 18750..18779 , 18780..18809 , 18810..18839 , 18840..18869 , 18870..18899 , 18900..18929 , 18930..18959 , 18960..18989 , 18990..19019 , 19020..19049 , 19050..19079 , 19080..19109 , 19110..19139 , 19140..19169 , 19170..19199 , 19200..19229 , 19230..19259 , 19260..19289 , 19290..19319 , 19320..19349 , 19350..19379 , 19380..19409 , 19410..19439 , 19440..19469 , 19470..19499 , 19500..19529 , 19530..19559 , 19560..19589 , 19590..19619 , 19620..19649 , 19650..19679 , 19680..19709 , 19710..19739 , 19740..19769 , 19770..19799 , 19800..19829 , 19830..19859 , 19860..19889 , 19890..19919 , 19920..19949 , 19950..19979 , 19980..20009 , 20010..20039 , 20040..20069 , 20070..20099 , 20100..20129 , 20130..20159 , 20160..20189 , 20190..20219 , 20220..20249 , 20250..20279 , 20280..20309 , 20310..20339 , 20340..20369 , 20370..20399 , 20400..20429 , 20430..20459 , 20460..20489 , 20490..20519 , 20520..20549 , 20550..20579 , 20580..20609 , 20610..20639 , 20640..20669 , 20670..20699 , 20700..20729 , 20730..20759 , 20760..20789 , 20790..20819 , 20820..20849 , 20850..20879 , 20880..20909 , 20910..20939 , 20940..20969 , 20970..20999 , 21000..21029 , 21030..21059 , 21060..21089 , 21090..21119 , 21120..21149 , 21150..21179 , 21180..21209 , 21210..21239 , 21240..21269 , 21270..21299 , 21300..21329 , 21330..21359 , 21360..21389 , 21390..21419 , 21420..21449 , 21450..21479 , 21480..21509 , 21510..21539 , 21540..21569 , 21570..21599 , 21600..21629 , 21630..21659 , 21660..21689 , 21690..21719 , 21720..21749 , 21750..21779 , 21780..21809 , 21810..21839 , 21840..21869 , 21870..21899 , 21900..21929 , 21930..21959 , 21960..21989 , 21990..22019 , 22020..22049 , 22050..22079 , 22080..22109 , 22110..22139 , 22140..22169 , 22170..22199 , 22200..22229 , 22230..22259 , 22260..22289 , 22290..22319 , 22320..22349 , 22350..22379 , 22380..22409 , 22410..22439 , 22440..22469 , 22470..22499 , 22500..22529 , 22530..22559 , 22560..22589 , 22590..22619 , 22620..22649 , 22650..22679 , 22680..22709 , 22710..22739 , 22740..22769 , 22770..22799 , 22800..22829 , 22830..22859 , 22860..22889 , 22890..22919 , 22920..22949 , 22950..22979 , 22980..23009 , 23010..23039 , 23040..23069 , 23070..23099 , 23100..23129 , 23130..23159 , 23160..23189 , 23190..23219 , 23220..23249 , 23250..23279 , 23280..23309 , 23310..23339 , 23340..23369 , 23370..23399 , 23400..23429 , 23430..23459 , 23460..23489 , 23490..23519 , 23520..23549 , 23550..23579 , 23580..23609 , 23610..23639 , 23640..23669 , 23670..23699 , 23700..23729 , 23730..23759 , 23760..23789 , 23790..23819 , 23820..23849 , 23850..23879 , 23880..23909 , 23910..23939 , 23940..23969 , 23970..23999 , 24000..24029 , 24030..24059 , 24060..24089 , 24090..24119 , 24120..24149 , 24150..24179 , 24180..24209 , 24210..24239 , 24240..24269 , 24270..24299 , 24300..24329 , 24330..24359 , 24360..24389 , 24390..24419 , 24420..24449 , 24450..24479 , 24480..24509 , 24510..24539 , 24540..24569 , 24570..24599 , 24600..24629 , 24630..24659 , 24660..24689 , 24690..24719 , 24720..24749 , 24750..24779 , 24780..24809 , 24810..24839 , 24840..24869 , 24870..24899 , 24900..24929 , 24930..24959 , 24960..24989 , 24990..25019 , 25020..25049 , 25050..25079 , 25080..25109 , 25110..25139 , 25140..25169 , 25170..25199 , 25200..25229 , 25230..25259 , 25260..25289 , 25290..25319 , 25320..25349 , 25350..25379 , 25380..25409 , 25410..25439 , 25440..25469 , 25470..25499 , 25500..25529 , 25530..25559 , 25560..25589 , 25590..25619 , 25620..25649 , 25650..25679 , 25680..25709 , 25710..25739 , 25740..25769 , 25770..25799 , 25800..25829 , 25830..25859 , 25860..25889 , 25890..25919 , 25920..25949 , 25950..25979 , 25980..26009 , 26010..26039 , 26040..26069 , 26070..26099 , 26100..26129 , 26130..26159 , 26160..26189 , 26190..26219 , 26220..26249 , 26250..26279 , 26280..26309 , 26310..26339 , 26340..26369 , 26370..26399 , 26400..26429 , 26430..26459 , 26460..26489 , 26490..26519 , 26520..26549 , 26550..26579 , 26580..26609 , 26610..26639 , 26640..26669 , 26670..26699 , 26700..26729 , 26730..26759 , 26760..26789 , 26790..26819 , 26820..26849 , 26850..26879 , 26880..26909 , 26910..26939 , 26940..26969 , 26970..26999 , 27000..27029 , 27030..27059 , 27060..27089 , 27090..27119 , 27120..27149 , 27150..27179 , 27180..27209 , 27210..27239 , 27240..27269 , 27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469, >>Next

Geometry_proofs/188693: Prove that if 3x%5E2%2B6=18 and x<0, then x=-2 is true.
1 solutions

Answer 141506 by jim_thompson5910(28476) About Me  on 2009-03-28 14:20:56 (Show Source):
You can put this solution on YOUR website!

3x%5E2%2B6=18 Start with the given equation.


3x%5E2%2B6-18=0 Subtract 18 from both sides.


3x%5E2-12=0 Combine like terms.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=3, b=0, and c=-12


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%280%29+%2B-+sqrt%28+%280%29%5E2-4%283%29%28-12%29+%29%29%2F%282%283%29%29 Plug in a=3, b=0, and c=-12


x+=+%280+%2B-+sqrt%28+0-4%283%29%28-12%29+%29%29%2F%282%283%29%29 Square 0 to get 0.


x+=+%280+%2B-+sqrt%28+0--144+%29%29%2F%282%283%29%29 Multiply 4%283%29%28-12%29 to get -144


x+=+%280+%2B-+sqrt%28+0%2B144+%29%29%2F%282%283%29%29 Rewrite sqrt%280--144%29 as sqrt%280%2B144%29


x+=+%280+%2B-+sqrt%28+144+%29%29%2F%282%283%29%29 Add 0 to 144 to get 144


x+=+%280+%2B-+sqrt%28+144+%29%29%2F%286%29 Multiply 2 and 3 to get 6.


x+=+%280+%2B-+12%29%2F%286%29 Take the square root of 144 to get 12.


x+=+%280+%2B+12%29%2F%286%29 or x+=+%28-0+-+12%29%2F%286%29 Break up the expression.


x+=+%2812%29%2F%286%29 or x+=++%28-12%29%2F%286%29 Combine like terms.


x+=+2 or x+=+-2 Simplify.


So the answers are x+=+2 or x+=+-2



However, since x%3C0, this means that "x" is negative. So this means that x=-2 is the only solution (if the inequality restriction is applied).


Equations/188660: This question is from textbook saxon algebra 2
The formula for the area of a trapezoid is A=1/2(b1+b2)h. Solve the formula for b1. The numbers next to the b's are supposed to drop down. Like the opposite of an exponent.
1 solutions

Answer 141473 by jim_thompson5910(28476) About Me  on 2009-03-27 22:39:35 (Show Source):
You can put this solution on YOUR website!
A=%281%2F2%29%28b%5B1%5D%2Bb%5B2%5D%29h Start with the given equation.


2A=%28b%5B1%5D%2Bb%5B2%5D%29h Multiply both sides by 2.


2A=h%28b%5B1%5D%2Bb%5B2%5D%29 Rearrange the terms.


%282A%29%2Fh=b%5B1%5D%2Bb%5B2%5D Divide both sides by "h".


%282A%29%2Fh-b%5B2%5D=b%5B1%5D Subtract b%5B2%5D from both sides.


%282A%29%2Fh-%28h%2Ab%5B2%5D%29%2Fh=b%5B1%5D Multiply b%5B2%5D by h%2Fh


%282A-h%2Ab%5B2%5D%29%2Fh=b%5B1%5D Combine the fractions.


So the solution is b%5B1%5D=%282A-h%2Ab%5B2%5D%29%2Fh


Complex_Numbers/188659: This question is from textbook saxon algebra 2
Solve the equation. Write the solutions in the form a+bi.
x^2+10x+30=0

1 solutions

Answer 141471 by jim_thompson5910(28476) About Me  on 2009-03-27 22:31:22 (Show Source):
You can put this solution on YOUR website!

x%5E2%2B10x%2B30=0 Start with the given equation.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=10, and c=30


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%2810%29+%2B-+sqrt%28+%2810%29%5E2-4%281%29%2830%29+%29%29%2F%282%281%29%29 Plug in a=1, b=10, and c=30


x+=+%28-10+%2B-+sqrt%28+100-4%281%29%2830%29+%29%29%2F%282%281%29%29 Square 10 to get 100.


x+=+%28-10+%2B-+sqrt%28+100-120+%29%29%2F%282%281%29%29 Multiply 4%281%29%2830%29 to get 120


x+=+%28-10+%2B-+sqrt%28+-20+%29%29%2F%282%281%29%29 Subtract 120 from 100 to get -20


x+=+%28-10+%2B-+sqrt%28+-20+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%28-10+%2B-+2i%2Asqrt%285%29%29%2F%282%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


x+=+%28-10%29%2F%282%29+%2B-+%282i%2Asqrt%285%29%29%2F%282%29 Break up the fraction.


x+=+-5+%2B-+sqrt%285%29%2Ai Reduce.


x+=+-5%2Bsqrt%285%29%2Ai or x+=+-5-sqrt%285%29%2Ai Break up the expression.


So the answers are x+=+-5%2Bsqrt%285%29%2Ai or x+=+-5-sqrt%285%29%2Ai



So the solutions are in the form a%2Bbi where a=-5 (for both solutions), b=sqrt%285%29 for the first solution, and b=-sqrt%285%29 for the second solution.


Polynomials-and-rational-expressions/188658: I do not know where to begin? 4x^4-10x^3+8x^2/2x I am supposed to express in the lowest term.
1 solutions

Answer 141469 by jim_thompson5910(28476) About Me  on 2009-03-27 22:29:27 (Show Source):
You can put this solution on YOUR website!
%284x%5E4-10x%5E3%2B8x%5E2%29%2F%282x%29 Start with the given expression.


%282x%5E2%282x%5E2-5x%2B4%29%29%2F%282x%29 Factor out the GCF 2x%5E2 from the numerator


%282x%2Ax%282x%5E2-5x%2B4%29%29%2F%282x%29 Factor x%5E2 to get x%2Ax


%28highlight%282x%29%2Ax%282x%5E2-5x%2B4%29%29%2Fhighlight%282x%29 Highlight the common terms.


%28cross%282x%29%2Ax%282x%5E2-5x%2B4%29%29%2Fcross%282x%29 Cancel out the common terms.


x%282x%5E2-5x%2B4%29 Simplify


2x%5E3-5x%5E2%2B4x Distribute


So %284x%5E4-10x%5E3%2B8x%5E2%29%2F%282x%29=2x%5E3-5x%5E2%2B4x where x%3C%3E0


Rational-functions/188592: Divide. State any restrictions on the variable.
y^2+5y+4/y^2-49 divide by 2y^2+5y-12/y^2+9y+14
1 solutions

Answer 141468 by jim_thompson5910(28476) About Me  on 2009-03-27 21:57:31 (Show Source):
You can put this solution on YOUR website!

Start with the given expression.


Multiply the first fraction %28y%5E2%2B5y%2B4%29%2F%28y%5E2-49%29 by the reciprocal of the second fraction %282y%5E2%2B5y-12%29%2F%28y%5E2%2B9y%2B14%29.


Factor y%5E2%2B5y%2B4 to get %28y%2B4%29%28y%2B1%29.


Factor y%5E2-49 to get %28y-7%29%28y%2B7%29.


Factor y%5E2%2B9y%2B14 to get %28y%2B7%29%28y%2B2%29.


Factor 2y%5E2%2B5y-12 to get %28y%2B4%29%282y-3%29.


Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


%28%28y%2B1%29%28y%2B2%29%29%2F%28%28y-7%29%282y-3%29%29 Simplify.


So simplifies to %28%28y%2B1%29%28y%2B2%29%29%2F%28%28y-7%29%282y-3%29%29.


In other words, where y%3C%3E-7, y%3C%3E-4, y%3C%3E-2, y%3C%3E3%2F2, or y%3C%3E7 (these are the restrictions to avoid division by zero).


Rational-functions/188591: Multiply. State any restrictions on the variable.

x^2+6x-7/x^2+5x times 3x^2+16x+5/2x^2+7x-9
1 solutions

Answer 141467 by jim_thompson5910(28476) About Me  on 2009-03-27 21:51:17 (Show Source):
You can put this solution on YOUR website!

Start with the given expression.


Factor x%5E2%2B6x-7 to get %28x%2B7%29%28x-1%29.


Factor x%5E2%2B5x to get x%28x%2B5%29.


Factor 3x%5E2%2B16x%2B5 to get %28x%2B5%29%283x%2B1%29.


Factor 2x%5E2%2B7x-9 to get %282x%2B9%29%28x-1%29.


%28%28x%2B7%29%28x-1%29%28x%2B5%29%283x%2B1%29%29%2F%28x%28x%2B5%29%282x%2B9%29%28x-1%29%29 Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


%28%28x%2B7%29%283x%2B1%29%29%2F%28x%282x%2B9%29%29 Simplify.


So simplifies to %28%28x%2B7%29%283x%2B1%29%29%2F%28x%282x%2B9%29%29.



In other words, where x%3C%3E-5, x%3C%3E-9%2F2, x%3C%3E0, or x%3C%3E1 (these are the restrictions to avoid dividing by zero).


logarithm/188597: Evaluate each logarithm. key: () means that number is the base.. thanks
please do these.. i had like 50 to do and these are the most confusin one and i just cant figure out.. thanks

log(5)125
log(1/2)1/4
log(3)729
log(9)1/3
log(1/4)16
log(8)1/256
1 solutions

Answer 141445 by jim_thompson5910(28476) About Me  on 2009-03-27 18:19:05 (Show Source):
You can put this solution on YOUR website!
I'll do the first three to get you started


I'm using the identities: log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29 and log%28b%2C%28b%29%29=1




# 1

log%285%2C%28125%29%29=log%285%2C%285%5E3%29%29=3%2Alog%285%2C%285%29%29=3%281%29=3


So log%285%2C%28125%29%29=3


--------------------------------------------------------

# 2




So log%281%2F2%2C%281%2F4%29%29=2

--------------------------------------------------------

# 3


log%283%2C%28729%29%29=log%283%2C%28%283%29%5E6%29%29=6%2Alog%283%2C%283%29%29=6%281%29=6


So log%283%2C%28729%29%29=6


Radicals/188648: . Rationalize the denominator:
2____
√[6] – √[5]

It came out fuzzy I will retype it

2/sqrt[6]-[5]

. Simplify the rational expression:
x2 – 3x – 10 find the gcf of the polynomial
x2 – x – 20




. Simplify:
√[144x10y12z18]

1 solutions

Answer 141444 by jim_thompson5910(28476) About Me  on 2009-03-27 18:05:46 (Show Source):
You can put this solution on YOUR website!
# 1


2%2F%28+sqrt%286%29-sqrt%285%29+%29+ Start with the given expression.


Multiply both the numerator and denominator by sqrt%286%29%2Bsqrt%285%29 (the conjugate of the denominator). This will rationalize the denominator


FOIL


%282%28+sqrt%286%29%2Bsqrt%285%29+%29%29%2F%28+6-5+%29 Square each term.


%282%28+sqrt%286%29%2Bsqrt%285%29+%29%29%2F%28+1+%29 Subtract


2%28+sqrt%286%29%2Bsqrt%285%29+%29 Reduce


2%2Asqrt%286%29%2B2%2Asqrt%285%29 Distribute


So 2%2F%28+sqrt%286%29-sqrt%285%29+%29+=+2%2Asqrt%286%29%2B2%2Asqrt%285%29+






# 2




%28x%5E2-3x-10%29%2F%28x%5E2-x-20%29 Start with the given expression.


%28%28x%2B2%29%2A%28x-5%29%29%2F%28x%5E2-x-20%29 Factor x%5E2-3x-10 to get %28x%2B2%29%2A%28x-5%29.


%28%28x%2B2%29%2A%28x-5%29%29%2F%28%28x%2B4%29%2A%28x-5%29%29 Factor x%5E2-x-20 to get %28x%2B4%29%2A%28x-5%29.


%28%28x%2B2%29highlight%28%28x-5%29%29%29%2F%28%28x%2B4%29highlight%28%28x-5%29%29%29 Highlight the common terms.


%28%28x%2B2%29cross%28%28x-5%29%29%29%2F%28%28x%2B4%29cross%28%28x-5%29%29%29 Cancel out the common terms. Note: the GCF is x-5 and is canceled out.


%28x%2B2%29%2F%28x%2B4%29 Simplify.


So %28x%5E2-3x-10%29%2F%28x%5E2-x-20%29 simplifies to %28x%2B2%29%2F%28x%2B4%29.


In other words, %28x%5E2-3x-10%29%2F%28x%5E2-x-20%29=%28x%2B2%29%2F%28x%2B4%29 where x%3C%3E-4 or x%3C%3E5






# 3




sqrt%28144%2Ax%5E10%2Ay%5E12%2Az%5E18%29 Start with the given expression.


sqrt%28144%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ay%5E12%2Az%5E18%29 Factor x%5E10 into x%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2


Factor y%5E12 into y%5E2%2Ay%5E2%2Ay%5E2%2Ay%5E2%2Ay%5E2%2Ay%5E2


Factor z%5E18 into z%5E2%2Az%5E2%2Az%5E2%2Az%5E2%2Az%5E2%2Az%5E2%2Az%5E2%2Az%5E2%2Az%5E2


Break up the square root using the identity sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29.


Take the square root of 144 to get 12.


Take the square root of x%5E2 to get x.


Take the square root of y%5E2 to get y.


12%2Ax%2Ax%2Ax%2Ax%2Ax%2Ay%2Ay%2Ay%2Ay%2Ay%2Ay%2Az%2Az%2Az%2Az%2Az%2Az%2Az%2Az%2Az Take the square root of z%5E2 to get z.


12x%5E5y%5E6z%5E9 Rearrange and multiply the terms.

==================================================

Answer:


So sqrt%28144%2Ax%5E10%2Ay%5E12%2Az%5E18%29 simplifies to 12x%5E5y%5E6z%5E9


In other words, sqrt%28144%2Ax%5E10%2Ay%5E12%2Az%5E18%29=12x%5E5y%5E6z%5E9 where every variable is non-negative.


Complex_Numbers/188637: True or False....
1 + 3/(2 − i) = 5 - i

Can you provide a detailed explanation of how you found the solution?
1 solutions

Answer 141442 by jim_thompson5910(28476) About Me  on 2009-03-27 17:21:03 (Show Source):
You can put this solution on YOUR website!
1+%2B+3%2F%282+-+i%29 Start with the left side of the given equation.


1+%2B+%283%282+%2B+i%29%29%2F%28%282+-+i%29%282+%2B+i%29%29 Multiply the fraction by %282%2Bi%29%2F%282%2Bi%29 (this is to make the denominator a real number)


1+%2B+%283%282+%2B+i%29%29%2F%284-i%5E2%29 FOIL


1+%2B+%283%282+%2B+i%29%29%2F%284-%28-1%29%29 Plug in i%5E2=-1


1+%2B+%283%282+%2B+i%29%29%2F%284%2B1%29 Rewrite the denominator


1+%2B+%283%282+%2B+i%29%29%2F%285%29 Add



1+%2B+%286%2B3i%29%2F%285%29 Distribute


5%2F5+%2B+%286%2B3i%29%2F%285%29 Multiply the first term 1 by 5%2F5


%285%2B6%2B3i%29%2F%285%29 Combine the fractions


%2811%2B3i%29%2F%285%29 Combine like terms.


11%2F5%2B%283i%29%2F%285%29 Break up the fraction


Since 11%2F5%3C%3E5 and %283i%29%2F%285%29%3C%3E-i, this means that 11%2F5%2B%283i%29%2F%285%29%3C%3E5-i


So consequently 1+%2B+3%2F%282+-+i%29%3C%3E5-i

So the statement is false.


Rational-functions/188590: Simplify. State any restrictions on the variable[thanks for your wonderful help]
x^2+x-6/x^2+3x


4x^2-25/2x^2+3x-20
1 solutions

Answer 141417 by jim_thompson5910(28476) About Me  on 2009-03-27 13:42:58 (Show Source):
You can put this solution on YOUR website!
%28x%5E2%2Bx-6%29%2F%28x%5E2%2B3x%29 Start with the given expression


%28%28x%2B3%29%28x-2%29%29%2F%28x%5E2%2B3x%29 Factor the numerator


%28%28x%2B3%29%28x-2%29%29%2F%28x%28x%2B3%29%29 Factor the denominator


%28cross%28%28x%2B3%29%29%28x-2%29%29%2F%28x%2Across%28%28x%2B3%29%29%29 Cancel out the common terms.


%28x-2%29%2Fx Simplify


So %28x%5E2%2Bx-6%29%2F%28x%5E2%2B3x%29=%28x-2%29%2Fx where x%3C%3E0 or x%3C%3E-3 (these are the restrictions). Note: These restrictions are made to avoid division by zero.



------------------------------------------------------------------------

%284x%5E2-25%29%2F%282x%5E2%2B3x-20%29 Start with the given expression


%28%282x%2B5%29%282x-5%29%29%2F%28x%5E2%2B3x%29 Factor the numerator


%28%282x%2B5%29%282x-5%29%29%2F%28%28x%2B4%29%282x-5%29%29 Factor the denominator


%28%282x%2B5%29cross%28%282x-5%29%29%29%2F%28%28x%2B4%29cross%28%282x-5%29%29%29 Cancel out the common terms.


%282x%2B5%29%2F%28x%2B4%29 Simplify


So %284x%5E2-25%29%2F%282x%5E2%2B3x-20%29=%282x%2B5%29%2F%28x%2B4%29 where x%3C%3E-4 or x%3C%3E5%2F2 (these are the restrictions). Note: These restrictions are made to avoid division by zero.


Polynomials-and-rational-expressions/188535: 24x^2-37-5
my teacher taugt us lIke multi:AC then subtract to get -37
0k so 24*5=120 then she said see what all goes into that number
then when u found it see if it is the same is B which is -37..
i got -40+3 is -37
but when i put it all together
24x^2-40x+3x-5
4x(6x-10)+1(3x-5) and Its suppose to be the same
i get lost can u help me im hopin u can understand wat im sayin
thats the best way i can explain it
1 solutions

Answer 141366 by jim_thompson5910(28476) About Me  on 2009-03-26 22:52:08 (Show Source):
You can put this solution on YOUR website!

Looking at the expression 24x%5E2-37x-5, we can see that the first coefficient is 24, the second coefficient is -37, and the last term is -5.


Now multiply the first coefficient 24 by the last term -5 to get %2824%29%28-5%29=-120.


Now the question is: what two whole numbers multiply to -120 (the previous product) and add to the second coefficient -37?


To find these two numbers, we need to list all of the factors of -120 (the previous product).


Factors of -120:
1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120
-1,-2,-3,-4,-5,-6,-8,-10,-12,-15,-20,-24,-30,-40,-60,-120


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -120.
1*(-120)
2*(-60)
3*(-40)
4*(-30)
5*(-24)
6*(-20)
8*(-15)
10*(-12)
(-1)*(120)
(-2)*(60)
(-3)*(40)
(-4)*(30)
(-5)*(24)
(-6)*(20)
(-8)*(15)
(-10)*(12)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -37:


First NumberSecond NumberSum
1-1201+(-120)=-119
2-602+(-60)=-58
3-403+(-40)=-37
4-304+(-30)=-26
5-245+(-24)=-19
6-206+(-20)=-14
8-158+(-15)=-7
10-1210+(-12)=-2
-1120-1+120=119
-260-2+60=58
-340-3+40=37
-430-4+30=26
-524-5+24=19
-620-6+20=14
-815-8+15=7
-1012-10+12=2



From the table, we can see that the two numbers 3 and -40 add to -37 (the middle coefficient).


So the two numbers 3 and -40 both multiply to -120 and add to -37


Now replace the middle term -37x with 3x-40x. Remember, 3 and -40 add to -37. So this shows us that 3x-40x=-37x.


24x%5E2%2Bhighlight%283x-40x%29-5 Replace the second term -37x with 3x-40x.


%2824x%5E2%2B3x%29%2B%28-40x-5%29 Group the terms into two pairs.


3x%288x%2B1%29%2B%28-40x-5%29 Factor out the GCF 3x from the first group.


3x%288x%2B1%29-5%288x%2B1%29 Factor out 5 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%283x-5%29%288x%2B1%29 Combine like terms. Or factor out the common term 8x%2B1

---------------------------------------------


Answer:


So 24x%5E2-37x-5 factors to %283x-5%29%288x%2B1%29.


Note: you can check the answer by FOILing %283x-5%29%288x%2B1%29 to get 24x%5E2-37x-5 or by graphing the original expression and the answer (the two graphs should be identical).


Polynomials-and-rational-expressions/188463: Factor the polynomial completly:
x^3y+2x^2y^2+xy^3
Factor the polinomial completly:
32x^2y-2y^3
Use grouping to factor the polynomial completly:
x^3+x^2-x-1
Use grouping to factor the polynomial completly"
y^3-5y^2+8y-40
1 solutions

Answer 141354 by jim_thompson5910(28476) About Me  on 2009-03-26 21:50:33 (Show Source):
You can put this solution on YOUR website!
I'll do the first two to get you started

# 1




x%5E3y%2B2x%5E2y%5E2%2Bxy%5E3 Start with the given expression


xy%28x%5E2%2B2xy%2By%5E2%29 Factor out the GCF xy


Now let's focus on the inner expression x%5E2%2B2xy%2By%5E2




------------------------------------------------------------



Looking at x%5E2%2B2xy%2By%5E2 we can see that the first term is x%5E2 and the last term is y%5E2 where the coefficients are 1 and 1 respectively.

Now multiply the first coefficient 1 and the last coefficient 1 to get 1. Now what two numbers multiply to 1 and add to the middle coefficient 2? Let's list all of the factors of 1:



Factors of 1:
1

-1 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 1
1*1
(-1)*(-1)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2

First NumberSecond NumberSum
111+1=2
-1-1-1+(-1)=-2



From this list we can see that 1 and 1 add up to 2 and multiply to 1


Now looking at the expression x%5E2%2B2xy%2By%5E2, replace 2xy with xy%2Bxy (notice xy%2Bxy adds up to 2xy. So it is equivalent to 2xy)

x%5E2%2Bhighlight%28xy%2Bxy%29%2By%5E2


Now let's factor x%5E2%2Bxy%2Bxy%2By%5E2 by grouping:


%28x%5E2%2Bxy%29%2B%28xy%2By%5E2%29 Group like terms


x%28x%2By%29%2By%28x%2By%29 Factor out the GCF of x out of the first group. Factor out the GCF of y out of the second group


%28x%2By%29%28x%2By%29 Since we have a common term of x%2By, we can combine like terms

So x%5E2%2Bxy%2Bxy%2By%5E2 factors to %28x%2By%29%28x%2By%29


So this also means that x%5E2%2B2xy%2By%5E2 factors to %28x%2By%29%28x%2By%29 (since x%5E2%2B2xy%2By%5E2 is equivalent to x%5E2%2Bxy%2Bxy%2By%5E2)


note: %28x%2By%29%28x%2By%29 is equivalent to %28x%2By%29%5E2 since the term x%2By occurs twice. So x%5E2%2B2xy%2By%5E2 also factors to %28x%2By%29%5E2



------------------------------------------------------------




So our expression goes from xy%28x%5E2%2B2xy%2By%5E2%29 and factors further to xy%28x%2By%29%5E2


------------------
Answer:

So x%5E3y%2B2x%5E2y%5E2%2Bxy%5E3 completely factors to xy%28x%2By%29%5E2






# 2


32x%5E2y-2y%5E3 Start with the given expression


2y%2816x%5E2-y%5E2%29 Factor out the GCF 2y


2y%28%284x%29%5E2-%28y%29%5E2%29 Rewrite 16x%5E2 as %284x%29%5E2


2y%284x%2By%29%284x-y%29 Factor %284x%29%5E2-%28y%29%5E2 to get %284x%2By%29%284x-y%29 (use the difference of squares)



So 32x%5E2y-2y%5E3 completely factors to 2y%284x%2By%29%284x-y%29


Equations/188517: (5x+4)^2=100
1 solutions

Answer 141352 by jim_thompson5910(28476) About Me  on 2009-03-26 21:44:44 (Show Source):
You can put this solution on YOUR website!

%285x%2B4%29%5E2=100 Start with the given equation.


5x%2B4=0%2B-sqrt%28100%29 Take the square root of both sides.


5x%2B4=sqrt%28100%29 or 5x%2B4=-sqrt%28100%29 Break up the "plus/minus" to form two equations.


5x%2B4=10 or 5x%2B4=-10 Take the square root of 100 to get 10.


5x=-4%2B10 or 5x=-4-10 Subtract 4 from both sides.


5x=6 or 5x=-14 Combine like terms.


x=6%2F5 or x=-14%2F5 Divide both sides by 5 to isolate x.


--------------------------------------


Answer:


So the solutions are x=6%2F5 or x=-14%2F5.


Exponents-negative-and-fractional/188525: Simplify expression showing work
(25y^2)^1/2 (fraction 1/2)
1 solutions

Answer 141350 by jim_thompson5910(28476) About Me  on 2009-03-26 21:43:08 (Show Source):
You can put this solution on YOUR website!
%2825y%5E2%29%5E%281%2F2%29 Start with the given expression.


sqrt%2825%2Ay%5E2%29 Convert to radical notation.


sqrt%2825%29%2Asqrt%28y%5E2%29 Break up the square root using the identity sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29.


5%2Asqrt%28y%5E2%29 Take the square root of 25 to get 5.


5y Take the square root of y%5E2 to get y.



==================================================

Answer:


So %2825y%5E2%29%5E%281%2F2%29 simplifies to 5y


In other words, %2825y%5E2%29%5E%281%2F2%29=5y where y%3E=0


test/188526: Find the Vertex

I did the problem but I still dont really get how to do this that much and I dont know if this is right either.
y = x2+6x+8 a=1 b=6


x= b = 6 = -6 = -3
_ _____ _ _____ ____
2a 2(1) 2


y = x2+6x+8
= 1(-3)2+6(-3)+8
= 9-18+8
= 1

Vertex= (-3 ,1 )






1 solutions

Answer 141349 by jim_thompson5910(28476) About Me  on 2009-03-26 21:40:31 (Show Source):
You can put this solution on YOUR website!

In order to find the vertex, we first need to find the x-coordinate of the vertex.


To find the x-coordinate of the vertex, use this formula: x=%28-b%29%2F%282a%29.


x=%28-b%29%2F%282a%29 Start with the given formula.


From y=x%5E2%2B6x%2B8, we can see that a=1, b=6, and c=8.


x=%28-%286%29%29%2F%282%281%29%29 Plug in a=1 and b=6.


x=%28-6%29%2F%282%29 Multiply 2 and 1 to get 2.


x=-3 Divide.


So the x-coordinate of the vertex is x=-3. Note: this means that the axis of symmetry is also x=-3.


Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.


y=x%5E2%2B6x%2B8 Start with the given equation.


y=%28-3%29%5E2%2B6%28-3%29%2B8 Plug in x=-3.


y=1%289%29%2B6%28-3%29%2B8 Square -3 to get 9.


y=9%2B6%28-3%29%2B8 Multiply 1 and 9 to get 9.


y=9-18%2B8 Multiply 6 and -3 to get -18.


y=-1 Combine like terms. Note: 9-18=-9 and -9+8=-1


So the y-coordinate of the vertex is y=-1.


So the vertex is .


So you were off by a sign.


Square-cubic-other-roots/188434: simplify the square root of 144+25
1 solutions

Answer 141302 by jim_thompson5910(28476) About Me  on 2009-03-26 17:47:28 (Show Source):
You can put this solution on YOUR website!
Is it sqrt%28144%29%2B25 ???

If so, then sqrt%28144%29%2B25=12%2B25=37


OR...


Is it sqrt%28144%2B25%29 ???

If so, then sqrt%28144%2B25%29=sqrt%28169%29=13


Expressions-with-variables/188342: This question is from textbook
n- 2/3= 3/4
1 solutions

Answer 141203 by jim_thompson5910(28476) About Me  on 2009-03-25 22:00:20 (Show Source):
You can put this solution on YOUR website!

n-2%2F3=3%2F4 Start with the given equation.


12%28n%29-cross%2812%29%5E4%282%2Fcross%283%29%29=cross%2812%29%5E3%283%2Fcross%284%29%29 Multiply EVERY term by the LCD 12 to clear any fractions.


12n-8=9 Multiply and simplify.


12n=9%2B8 Add 8 to both sides.


12n=17 Combine like terms on the right side.


n=%2817%29%2F%2812%29 Divide both sides by 12 to isolate n.


----------------------------------------------------------------------

Answer:

So the answer is n=17%2F12 which approximates to n=1.417.


Systems-of-equations/188362: Hi need help please in solving all values of x and y and can you please show me each step this is another one
1. x^2 - 3y^2 = 13
x - 2y = 1
1 solutions

Answer 141202 by jim_thompson5910(28476) About Me  on 2009-03-25 21:58:35 (Show Source):
You can put this solution on YOUR website!
x+-+2y+=+1 Start with the second equation.


x=+1%2B2y Add 2y to both sides to isolate "x".


-----------------


x%5E2+-+3y%5E2+=+13 Move onto the first equation


%281%2B2y%29%5E2+-+3y%5E2+=+13 Plug in x=+1%2B2y


1%2B4y%2B4y%5E2-+3y%5E2+=+13 FOIL


1%2B4y%2B4y%5E2-+3y%5E2+-+13=0 Subtract 13 from both sides.


y%5E2%2B4y+-+12=0 Combine like terms.



Notice we have a quadratic equation in the form of ay%5E2%2Bby%2Bc where a=1, b=4, and c=-12


Let's use the quadratic formula to solve for y


y+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


y+=+%28-%284%29+%2B-+sqrt%28+%284%29%5E2-4%281%29%28-12%29+%29%29%2F%282%281%29%29 Plug in a=1, b=4, and c=-12


y+=+%28-4+%2B-+sqrt%28+16-4%281%29%28-12%29+%29%29%2F%282%281%29%29 Square 4 to get 16.


y+=+%28-4+%2B-+sqrt%28+16--48+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-12%29 to get -48


y+=+%28-4+%2B-+sqrt%28+16%2B48+%29%29%2F%282%281%29%29 Rewrite sqrt%2816--48%29 as sqrt%2816%2B48%29


y+=+%28-4+%2B-+sqrt%28+64+%29%29%2F%282%281%29%29 Add 16 to 48 to get 64


y+=+%28-4+%2B-+sqrt%28+64+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


y+=+%28-4+%2B-+8%29%2F%282%29 Take the square root of 64 to get 8.


y+=+%28-4+%2B+8%29%2F%282%29 or y+=+%28-4+-+8%29%2F%282%29 Break up the expression.


y+=+%284%29%2F%282%29 or y+=++%28-12%29%2F%282%29 Combine like terms.


y+=+2 or y+=+-6 Simplify.


So the answers for "y" are y+=+2 or y+=+-6


Now simply plug each solution of "y" into x=1%2B2y to find "x"


Plug in y+=+2

x=1%2B2%282%29=1%2B4=5


So one set of solutions is x=5 and y=2 giving us the ordered pair (or point of intersection) (5,2)

-------------------


Plug in y+=+-6

x=1%2B2%28-6%29=1-12=-11


This means that another set of solutions is x=-11 and y=-6 giving us the ordered pair (or point of intersection) (-11,-6)


Here's a graph to visually confirm the answer:



Graph of x%5E2+-+3y%5E2+=+13 (red) and x+-+2y+=+1 (blue) with the intersection points (-11,-6) and (5,2) (black points)


Trigonometry-basics/188358: I need help solving the following question.
1. Solve the equation:
tan3x=1
1 solutions

Answer 141199 by jim_thompson5910(28476) About Me  on 2009-03-25 21:49:23 (Show Source):
You can put this solution on YOUR website!
tan%283x%29=1 Start with the given equation.


3x=arctan%281%29 Take the arctangent of both sides (to eliminate the tangent on the left side)


3x=pi%2F4%2Bpi%2An Evaluate the arctangent of 1 to get pi%2F4 (use the unit circle). Remember to add pi%2An (to account for all of the solutions).

Note: n is an integer


x=%28pi%2F4%2Bpi%2An%29%2F3 Divide both sides by 3.


x=pi%2F12%2B%28pi%2An%29%2F3 Break up the fraction and simplify


So the solutions are x=pi%2F12%2B%28pi%2An%29%2F3 where "n" is an integer.


Systems-of-equations/188361: Hi need help please in solving all values of x and y and can you please show me each step
1. 5x + 2y =16
3x - 5y =-9



1 solutions

Answer 141198 by jim_thompson5910(28476) About Me  on 2009-03-25 21:44:00 (Show Source):
You can put this solution on YOUR website!

Start with the given system of equations:
system%285x%2B2y=16%2C3x-5y=-9%29


5%285x%2B2y%29=5%2816%29 Multiply the both sides of the first equation by 5.


25x%2B10y=80 Distribute and multiply.


2%283x-5y%29=2%28-9%29 Multiply the both sides of the second equation by 2.


6x-10y=-18 Distribute and multiply.


So we have the new system of equations:
system%2825x%2B10y=80%2C6x-10y=-18%29


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%2825x%2B10y%29%2B%286x-10y%29=%2880%29%2B%28-18%29


%2825x%2B6x%29%2B%2810y%2B-10y%29=80%2B-18 Group like terms.


31x%2B0y=62 Combine like terms.


31x=62 Simplify.


x=%2862%29%2F%2831%29 Divide both sides by 31 to isolate x.


x=2 Reduce.


------------------------------------------------------------------


25x%2B10y=80 Now go back to the first equation.


25%282%29%2B10y=80 Plug in x=2.


50%2B10y=80 Multiply.


10y=80-50 Subtract 50 from both sides.


10y=30 Combine like terms on the right side.


y=%2830%29%2F%2810%29 Divide both sides by 10 to isolate y.


y=3 Reduce.


So the solutions are x=2 and y=3.


Which form the ordered pair .


This means that the system is consistent and independent.


Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.


Graph of 5x%2B2y=16 (red) and 3x-5y=-9 (green)


Linear-equations/188360: Linear Equations: I need help on how to undersatnd this because i don't get non of this. The tuter thing i just saw didn't help me at all. I'm only 14 years old.

1 solutions

Answer 141197 by jim_thompson5910(28476) About Me  on 2009-03-25 21:42:56 (Show Source):
You can put this solution on YOUR website!
Please post a problem so we can walk you through it. Thanks.


Inverses/188359: Pre-Algebra- I think..not sure. This problem is from Contemporary's Number Power Algebra 3 by Robert Mitchell
TERMS ON BOTH SIDES OF AN EQUATION:
+11z-3=9z+ and *** this one I tried, but kept getting the wrong answer etc..
here is the problem***
+3%2F4x+-+7+=+7x+%2B+-582+
Any help would be greatly appreciated, as I am studying for a test in Pre-algebra/algebra, and need to attain a score of 55+ in Pre-algebra, and a score of 30+ in algebra. This test is on Saturday, (28th March), and I have been studying, religiously, but then..somewhere along the way, I become hopelessly lost, and end up with answerrs that are so-far out in left field, that I am not even sure I am in the same class etc....I should mention, that I am a returning adult...and not fresh out of High-School. My last algebra class was twenty-five+ years ago etc.....
Thank-you for your time, and any helpful suggestions..other than do not enter school would be greatly appreciated!!!! (the above joke was a lame attempt at keeping/finding humour in this stressful aspiration!!!)
Thanx~ John
1 solutions

Answer 141196 by jim_thompson5910(28476) About Me  on 2009-03-25 21:42:03 (Show Source):
You can put this solution on YOUR website!
11z-3=9z Start with the given equation.


11z=9z%2B3 Add 3 to both sides.


11z-9z=3 Subtract 9z from both sides.


2z=3 Combine like terms on the left side.


z=%283%29%2F%282%29 Divide both sides by 2 to isolate z.


----------------------------------------------------------------------

Answer:

So the answer is z=3%2F2 which in decimal form is z=1.5.





# 2


Is the equation +%283%2F4%29x+-+7+=+7x+%2B+-582+ ???


+%283%2F4%29x+-+7+=+7x+%2B+-582+ Start with the given equation.


cross%284%29%28%283%2Fcross%284%29%29x%29-4%287%29=4%287x%29%2B4%28-582%29 Multiply EVERY term by the LCD 4 to clear the fractions.


3x-28=28x-2328 Multiply and simplify.


3x=28x-2328%2B28 Add 28 to both sides.


3x-28x=-2328%2B28 Subtract 28x from both sides.


-25x=-2328%2B28 Combine like terms on the left side.


-25x=-2300 Combine like terms on the right side.


x=%28-2300%29%2F%28-25%29 Divide both sides by -25 to isolate x.


x=92 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=92




Radicals/188343: Which expression is equivalent to 7(radical)90
a)16(radical)10
b)21(radical)10
c)70(radical)9
d)(radical)630
please tell me who you got this .
1 solutions

Answer 141184 by jim_thompson5910(28476) About Me  on 2009-03-25 20:03:45 (Show Source):
You can put this solution on YOUR website!
7%2Asqrt%2890%29 Start with the given expression.


7%2Asqrt%289%2A10%29 Factor 90 into 9%2A10


7%2Asqrt%289%29%2Asqrt%2810%29 Break up the square root.


7%2A3%2Asqrt%2810%29 Take the square root of 9 to get 3


21%2Asqrt%2810%29 Multiply


So 7%2Asqrt%2890%29=21%2Asqrt%2810%29


Polynomials-and-rational-expressions/188334: Please help solve the following equation:
600 = 0.9x^ - 26.5x + 290
Thanks.
1 solutions

Answer 141177 by jim_thompson5910(28476) About Me  on 2009-03-25 19:06:38 (Show Source):
You can put this solution on YOUR website!
I'm assuming that the equation should be 600+=+0.9x%5E2+-+26.5x+%2B+290



600+=+0.9x%5E2+-+26.5x+%2B+290 Start with the given equation.


6000+=+9x%5E2+-+265x+%2B+2900 Multiply EVERY term by 10 to make every number a whole number


0+=+9x%5E2+-+265x+%2B+2900-6000 Subtract 6000 from both sides.


0+=+9x%5E2+-+265x+-3100 Combine like terms.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=9, b=-265, and c=-3100


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%28-265%29+%2B-+sqrt%28+%28-265%29%5E2-4%289%29%28-3100%29+%29%29%2F%282%289%29%29 Plug in a=9, b=-265, and c=-3100


x+=+%28265+%2B-+sqrt%28+%28-265%29%5E2-4%289%29%28-3100%29+%29%29%2F%282%289%29%29 Negate -265 to get 265.


x+=+%28265+%2B-+sqrt%28+70225-4%289%29%28-3100%29+%29%29%2F%282%289%29%29 Square -265 to get 70225.


x+=+%28265+%2B-+sqrt%28+70225--111600+%29%29%2F%282%289%29%29 Multiply 4%289%29%28-3100%29 to get -111600


x+=+%28265+%2B-+sqrt%28+70225%2B111600+%29%29%2F%282%289%29%29 Rewrite sqrt%2870225--111600%29 as sqrt%2870225%2B111600%29


x+=+%28265+%2B-+sqrt%28+181825+%29%29%2F%282%289%29%29 Add 70225 to 111600 to get 181825


x+=+%28265+%2B-+sqrt%28+181825+%29%29%2F%2818%29 Multiply 2 and 9 to get 18.


x+=+%28265+%2B-+5%2Asqrt%287273%29%29%2F%2818%29 Simplify the square root


x+=+%28265%2B5%2Asqrt%287273%29%29%2F%2818%29 or x+=+%28265-5%2Asqrt%287273%29%29%2F%2818%29 Break up the expression.


So the answers are x+=+%28265%2B5%2Asqrt%287273%29%29%2F%2818%29 or x+=+%28265-5%2Asqrt%287273%29%29%2F%2818%29


which approximate to x=38.412 or x=-8.967


Trigonometry-basics/188286: If a person bends at the waist with a straight back making an abgle of theta degrees with the horizontal, the the force F exerted on the back muscles can be modeled by the equation...
F = .6Wsin(theta + 90degrees)/ sin 12
where W is the weight of the person.
Use an identity to show that F is approximately equal to 2.9W cos theta.
I had no clue how to do this one.
1 solutions

Answer 141175 by jim_thompson5910(28476) About Me  on 2009-03-25 18:56:38 (Show Source):
You can put this solution on YOUR website!
One of the many trig identities is sin%28A%2BB%29=sin%28A%29cos%28B%29%2Bcos%28A%29sin%28B%29



... Start with the given equation.


... Use the identity given above


... Evaluate the cosine of 90 degrees to get 0. Evaluate the sine of 90 degrees to get 1.


... Multiply


... Simplify


... Evaluate the sine of 12 degrees to get approximately 0.2079


... Divide 0.6%2F0.2079 to get roughly 2.8858


... Round to the nearest tenth


Equations/188275: Multiply and write in simplest form 4 1/5 x 10/21 x 9/20? I have no clue on where to begin. Thank you.
Michelle
1 solutions

Answer 141174 by jim_thompson5910(28476) About Me  on 2009-03-25 18:47:16 (Show Source):
You can put this solution on YOUR website!
In order to multiply fractions, they must either be normal fractions like 1%2F2 or 2%2F3 or they must be improper fractions.


So we must convert 4%261%2F5 into an improper fraction


Remember, where "a" is the whole part of the fraction, "b" is the numerator, and "c" is the denominator.

So this means that




In short which means that the mixed fraction 4 and one fifth is the same as the improper fraction 21%2F5


--------------------------


... Start with the given expression.


... Replace 4%261%2F5 with 21%2F5


... Factor 20 into 2%2A10


... Cancel out the common terms.



... Simplify


... Multiply


... Combine the fractions.


... Multiply


So


test/188326: Ineed help solving the following binomial expression:
4x^2+12x+9
1 solutions

Answer 141169 by jim_thompson5910(28476) About Me  on 2009-03-25 18:24:08 (Show Source):
You can put this solution on YOUR website!
I'm assuming that you want to factor this right?


Note: 4x%5E2%2B12x%2B9 is NOT a binomial, it is a trinomial.



Looking at the expression 4x%5E2%2B12x%2B9, we can see that the first coefficient is 4, the second coefficient is 12, and the last term is 9.


Now multiply the first coefficient 4 by the last term 9 to get %284%29%289%29=36.


Now the question is: what two whole numbers multiply to 36 (the previous product) and add to the second coefficient 12?


To find these two numbers, we need to list all of the factors of 36 (the previous product).


Factors of 36:
1,2,3,4,6,9,12,18,36
-1,-2,-3,-4,-6,-9,-12,-18,-36


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 36.
1*36
2*18
3*12
4*9
6*6
(-1)*(-36)
(-2)*(-18)
(-3)*(-12)
(-4)*(-9)
(-6)*(-6)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 12:


First NumberSecond NumberSum
1361+36=37
2182+18=20
3123+12=15
494+9=13
666+6=12
-1-36-1+(-36)=-37
-2-18-2+(-18)=-20
-3-12-3+(-12)=-15
-4-9-4+(-9)=-13
-6-6-6+(-6)=-12



From the table, we can see that the two numbers 6 and 6 add to 12 (the middle coefficient).


So the two numbers 6 and 6 both multiply to 36 and add to 12


Now replace the middle term 12x with 6x%2B6x. Remember, 6 and 6 add to 12. So this shows us that 6x%2B6x=12x.


4x%5E2%2Bhighlight%286x%2B6x%29%2B9 Replace the second term 12x with 6x%2B6x.


%284x%5E2%2B6x%29%2B%286x%2B9%29 Group the terms into two pairs.


2x%282x%2B3%29%2B%286x%2B9%29 Factor out the GCF 2x from the first group.


2x%282x%2B3%29%2B3%282x%2B3%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%282x%2B3%29%282x%2B3%29 Combine like terms. Or factor out the common term 2x%2B3


%282x%2B3%29%5E2 Condense the terms.


---------------------------------------------


Answer:


So 4x%5E2%2B12x%2B9 factors to %282x%2B3%29%5E2.


Note: you can check the answer by FOILing %282x%2B3%29%5E2 to get 4x%5E2%2B12x%2B9 or by graphing the original expression and the answer (the two graphs should be identical).


Numbers_Word_Problems/188302: The product of two consecutive numbers is 72. Find the smaller of the numbers
1 solutions

Answer 141168 by jim_thompson5910(28476) About Me  on 2009-03-25 18:19:07 (Show Source):
You can put this solution on YOUR website!
I'm assuming that you want the numbers to be positive.


"The product of two consecutive numbers is 72" translates to x%28x%2B1%29=72


x%28x%2B1%29=72 Start with the given equation.


x%5E2%2Bx=72 Distribute


x%5E2%2Bx-72=0 Subtract 72 from both sides.


Notice we have a quadratic equation in the form of ax%5E2%2Bbx%2Bc where a=1, b=1, and c=-72


Let's use the quadratic formula to solve for x


x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%281%29+%2B-+sqrt%28+%281%29%5E2-4%281%29%28-72%29+%29%29%2F%282%281%29%29 Plug in a=1, b=1, and c=-72


x+=+%28-1+%2B-+sqrt%28+1-4%281%29%28-72%29+%29%29%2F%282%281%29%29 Square 1 to get 1.


x+=+%28-1+%2B-+sqrt%28+1--288+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-72%29 to get -288


x+=+%28-1+%2B-+sqrt%28+1%2B288+%29%29%2F%282%281%29%29 Rewrite sqrt%281--288%29 as sqrt%281%2B288%29


x+=+%28-1+%2B-+sqrt%28+289+%29%29%2F%282%281%29%29 Add 1 to 288 to get 289


x+=+%28-1+%2B-+sqrt%28+289+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%28-1+%2B-+17%29%2F%282%29 Take the square root of 289 to get 17.


x+=+%28-1+%2B+17%29%2F%282%29 or x+=+%28-1+-+17%29%2F%282%29 Break up the expression.


x+=+%2816%29%2F%282%29 or x+=++%28-18%29%2F%282%29 Combine like terms.


x+=+8 or x+=+-9 Simplify.


So the answers are x+=+8 or x+=+-9


However, we only want the positive numbers. So the only answer is x=8


This means that the smaller number is 8.


Polynomials-and-rational-expressions/188277: Perform the indicated operations
(4x-3)-(7x-2)+(-5x+8)
1 solutions

Answer 141167 by jim_thompson5910(28476) About Me  on 2009-03-25 18:15:56 (Show Source):
You can put this solution on YOUR website!
%284x-3%29-%287x-2%29%2B%28-5x%2B8%29 Start with the given expression.


4x-3-7x%2B2-5x%2B8 Distribute


%284x-7x-5x%29%2B%28-3%2B2%2B8%29 Rearrange and group like terms.


-8x%2B7 Combine like terms.


So %284x-3%29-%287x-2%29%2B%28-5x%2B8%29=-8x%2B7


Polynomials-and-rational-expressions/188278: Perform the indicated operations
(4x-3)-(7x-2)+(-5x+8)
1 solutions

Answer 141166 by jim_thompson5910(28476) About Me  on 2009-03-25 18:15:32 (Show Source):
You can put this solution on YOUR website!
%284x-3%29-%287x-2%29%2B%28-5x%2B8%29 Start with the given expression.


4x-3-7x%2B2-5x%2B8 Distribute


%284x-7x-5x%29%2B%28-3%2B2%2B8%29 Rearrange and group like terms.


-8x%2B7 Combine like terms.


So %284x-3%29-%287x-2%29%2B%28-5x%2B8%29=-8x%2B7


Polynomials-and-rational-expressions/188281: perform the indication operation
(4x-3)-(7x-2)+(-5x+8)
1 solutions

Answer 141165 by jim_thompson5910(28476) About Me  on 2009-03-25 18:14:36 (Show Source):
You can put this solution on YOUR website!
%284x-3%29-%287x-2%29%2B%28-5x%2B8%29 Start with the given expression.


4x-3-7x%2B2-5x%2B8 Distribute


%284x-7x-5x%29%2B%28-3%2B2%2B8%29 Rearrange and group like terms.


-8x%2B7 Combine like terms.


So %284x-3%29-%287x-2%29%2B%28-5x%2B8%29=-8x%2B7