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Permutations/191392: This question is from textbook MATHEMATICS: Structure and Method, Course 2
I DON'T KNOW WHAT TO DO! HELP ME HERE IS THE QUESTION-
Philip wishes to check out two books out of his school library. If the library contains 800 books, in how many ways might Philip get his choice of books?
PLEASE RESPOND IMMEDIATELY!!!!!!!!!!!IT'S DUE TOMMOROW!!!!!!!!!!!!!!!!!!!!!!!!! 1 solutions
Answer 143630 by jim_thompson5910(28476) on 2009-04-15 21:49:28 (Show Source):
You can put this solution on YOUR website!For the first selection, you have a choice of 800 books. Once that selection has been made, you now have 799 books left over. So if the order matters, then you simply multiply 800 by 799 to get:
800 x 799 = 639,200
So there are 639,200 different ways to choose two books (where the order of the books matters).
----------------------------------------------
If the order of the books does NOT matter, then simply divide by 2 (since xy is the same as yx) to get
639,200/2=319,600
So there are 319,600 different ways to choose two books if the order does NOT matter.
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Linear-systems/191384: This question is from textbook algebra 1
the question (i have to do 11 of these) is:
"Determine whether each system is consistent or inconsistent by solving it graphically and algebraically"
{ y=-4x+6
{ 2y=-8x-8
i tried doing "step 1: 2(-4x+6)=-8x-8 step 2: -8x+12=-8x-8 step 3: 0x+12=-8"
and i know it isn't right, could someone explain how you find the answer please.
thanks!!
1 solutions
Answer 143624 by jim_thompson5910(28476) on 2009-04-15 21:20:52 (Show Source):
You can put this solution on YOUR website!You have the correct steps. Since the equation  is NOT true, this means that there are NO solutions. So the system is inconsistent.
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Graphs/191381: Hello, can you please help me solve this problem.
--Solve the system by using the substitution method--
with this under it  1 solutions
Answer 143621 by jim_thompson5910(28476) on 2009-04-15 20:54:45 (Show Source):
You can put this solution on YOUR website! Start with the second equation.
 Add "y" to both sides.
 Move onto the first equation
 Plug in
 FOIL
 Subtract 113 from both sides.
 Combine like terms.
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for y
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the answers for "y" are  or
Now take these solutions and plug them into  to find "x"
So when  ,
So when  ,
So the solutions as ordered pairs are (8,7) or (-7,-8)
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logarithm/191371: Question: Write an exponential function, y=ab^x for a graph that includes points at (1, 12) and (2, 36).
I do not understand how to find this. Can you please show me the steps and answer? 1 solutions
Answer 143618 by jim_thompson5910(28476) on 2009-04-15 20:49:24 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Plug in  and  . These are the x and y coordinates to the point (1,12)
 Simplify
 Divide both sides by "a".
 Rearrange the equation
------------------------
 Go back to the given equation.
 Plug in  and  . These are the x and y coordinates to the point (2,36)
 Plug in
 Square  to get
 Multiply
 Reduce
 Multiply both sides by "a".
 Divide both sides by 36.
 Reduce
-----------------------
 Go back to the first isolated equation
 Plug in
 Reduce
So the exponential equation is
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Polynomials-and-rational-expressions/191261: Please help me factorize and state the roots of the following polynomial. Please, I beg you, I need to know how to to this and would really appreciate whatever help I can get. This was a take home assignment. Thanks.
P(x)=4x^7+28x^6+27x^5-203x^4-591x^3-431x^2+146x+120 1 solutions
Answer 143585 by jim_thompson5910(28476) on 2009-04-15 17:04:37 (Show Source):
You can put this solution on YOUR website!Wow, this is as long as it gets (well I hope so anyway...). Here are two ways to do this:
Method #1:
Use the rational root theorem to find all of the possible roots and test EVERY possible root to see if it is actually a root. Since the degree of the equation is 7, this means that once you find 7 roots, then you don't need to check any more possible roots.
Here's where this method gets really tedious: there are A LOT of possible roots (48 in total)
But, here's how to find them:
Any rational zero can be found through this equation
 where p and q are the factors of the last and first coefficients
So let's list the factors of 120 (the last coefficient):
Now let's list the factors of 4 (the first coefficient):
Now let's divide each factor of the last coefficient by each factor of the first coefficient
Now simplify
These are all the distinct rational zeros of the function that could occur
Once you have all of the possible rational roots, either plug them in directly or use synthetic division to determine which ones are actually roots.
Method #2:
Since the first method seems like a lot of busy work (which it is), just use a graphing calculator to find some of the roots, and then use those roots to find other roots (using synthetic division). Eventually, you'll reduce that massive polynomial to a quadratic which you can solve using the quadratic formula.
If you're completely stuck, then repost or email me. By the way, the 7 roots are: 3, -1/2, 1/2, -4, -2, -2+i, -2-i
Also,  completely factors (over the reals) to
In other words,
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Radicals/191291: This question is from textbook
I need some help with a problem that states I need to rationalize the denominator. The problem is (square(3)-square(4))/(square(3)+square(4)). I did the steps that it said to, but my answer does not match the answer in the book. When I solved the problem I got (square(3)-square(4)(square(3)+square(4) with a - 1 for the denominator?
What am I doing wrong?
Any help would be greatly appreciated! 1 solutions
Answer 143582 by jim_thompson5910(28476) on 2009-04-15 16:46:51 (Show Source):
You can put this solution on YOUR website! Start with the given expression.
 Multiply both the numerator and denominator by
Note:  is the conjugate of the denominator  . Multiplying these two expressions yields a rational expression
 FOIL the denominator (use the difference of squares formula)
 FOIL the numerator (use the perfect square formula)
 Square each term
 Combine and multiply the roots.
 Combine like terms.
 Simplify  to get
 Multiply
 Reduce
So
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Quadratic_Equations/191307: Solve for x
If the solutions are complex numbers, then give soulutions in the usual a + bi form
a) x^2 - 6x + 9 = 0
b) x^2 + 4x + 7 = 0 1 solutions
Answer 143581 by jim_thompson5910(28476) on 2009-04-15 16:37:42 (Show Source):
You can put this solution on YOUR website!a)
 Start with the given equation.
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So solution is
---------------------------------------------------------------
b)
 Start with the given equation.
Notice we have a quadratic equation in the form of  where  ,  , and
Let's use the quadratic formula to solve for x
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
 Break up the fraction.
 Reduce.
 or  Break up the expression.
So the answers are  or  where
Note: the solutions are in the form  or  where  and
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Equations/191305: X+3/x-1=x+4/x-5
(x+3)(x-5)=(x-1)(x+4)
x^2+3x-15=x^2-x-4
x^2+4x+11=x^2 1 solutions
Answer 143578 by jim_thompson5910(28476) on 2009-04-15 16:34:06 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Cross multiply
 FOIL (this is where you made a mistake)
 Get everything to the left side
 Combine like terms.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the answer is  which in decimal form is  .
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Complex_Numbers/191251: This question is from textbook algebra and trigonometry structure and method book 2
Find the number of times r is a root of P(x)=0.
P(x)= x^4+4x^3-16x-16; r=-2
i found the depressed eruation twice but the numbers were all messed up. please help and explain. 1 solutions
Answer 143544 by jim_thompson5910(28476) on 2009-04-15 13:12:17 (Show Source):
You can put this solution on YOUR website!First, perform synthetic division where -2 is the test zero (let me know if you need help with synthetic division)
-2 | 1 4 0 -16 -16
| -2 -4 8 16
------------------------
1 2 -4 -8 0
Since the last number in the bottom row is zero, this means that the remainder is 0. So -2 is a root of
The first 4 numbers form the depressed polynomial  . This means that
=================================
Now perform synthetic division on  using the same test zero:
-2 | 1 2 -4 -8
| -2 0 8
------------------
1 0 -4 0
Notice how the last number in the bottom row is 0. So -2 is a root of  . So far, r=-2 is a root of multiplicity 2 (ie -2 is a root twice).
The first 3 numbers in the bottom row form the new polynomial  . This tells us that
So
=================================
Now perform synthetic division on the polynomial
-2 | 1 0 -4
| -2 4
------------
1 -2 0
So -2 is a root of  . So this means that r=-2 is a root of multiplicity 3 (ie -2 is a root three times).
The first two numbers in the bottom row form the new polynomial:
Now because -2 is NOT a root of  , this means that we can stop looking for more roots of -2.
So
Or in other words,
Notice how the factor  is repeated 3 times, this supports our conclusion that r=-2 is a root of multiplicity 3
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Equations/191061: This question is from textbook saxon algebra2
solve.
3x/x^2-1=5/x
I worked it out to:
2(x-5)(x+1)
Is this correct? 1 solutions
Answer 143449 by jim_thompson5910(28476) on 2009-04-14 15:41:00 (Show Source):
You can put this solution on YOUR website!I'm assuming that the equation is  .
 Start with the given equation
 Cross multiply
 Distribute and multiply
 Subtract  from both sides
 Combine like terms.
 Divide both sides by -2
 Reduce
 Take the square root of both sides
 or  Break up the "plus/minus" to form 2 separate equations.
 or  Simplify the square root.
So the solutions are  or
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Polynomials-and-rational-expressions/191090: factor by grouping
5x^2-12x+7 1 solutions
Answer 143448 by jim_thompson5910(28476) on 2009-04-14 15:30:04 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,5,7,35
-1,-5,-7,-35
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*35
5*7
(-1)*(-35)
(-5)*(-7)
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 35 | 1+35=36 | | 5 | 7 | 5+7=12 | | -1 | -35 | -1+(-35)=-36 | | -5 | -7 | -5+(-7)=-12 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
---------------------------------------------
Answer:
So  factors to  .
Note: you can check the answer by FOILing  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Polynomials-and-rational-expressions/191092: factor by grouping
4x^2-4x-3 1 solutions
Answer 143447 by jim_thompson5910(28476) on 2009-04-14 15:28:19 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,6,12
-1,-2,-3,-4,-6,-12
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-12)
2*(-6)
3*(-4)
(-1)*(12)
(-2)*(6)
(-3)*(4)
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -12 | 1+(-12)=-11 | | 2 | -6 | 2+(-6)=-4 | | 3 | -4 | 3+(-4)=-1 | | -1 | 12 | -1+12=11 | | -2 | 6 | -2+6=4 | | -3 | 4 | -3+4=1 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
---------------------------------------------
Answer:
So  factors to  .
Note: you can check the answer by FOILing  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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logarithm/191051: This question is from textbook
Given f(x) = e^-2x + 1, evaluate the following. Round to the nearest ten-thousandth.
f(-1)
f(3)
f(-2)
Show your work here:
f(-1)=e -2(-1)+1=x-1
f(-1)=e^2+1
f(-1)=7.389+1
f(-1) = 8.389
1 solutions
Answer 143446 by jim_thompson5910(28476) on 2009-04-14 15:27:15 (Show Source):
You can put this solution on YOUR website!I'm assuming that the function is  .
Evaluating f(-1):
 Start with the given equation.
 Plug in  .
 Multiply -2 and -1 to get 2.
 Raise "e" to the 2nd power to get 7.3891 (note: this value is approximate).
 Add 1 to 7.3891 to get 8.3891.
----------------------------
Evaluating f(3):
 Start with the given equation.
 Plug in  .
 Multiply -2 and 3 to get -6.
 Raise "e" to the -6th power to get 0.0025 (note: this value is approximate).
 Add 1 to 0.0025 to get 1.0025.
----------------------------
Evaluating f(-2):
 Start with the given equation.
 Plug in  .
 Multiply -2 and -2 to get 4.
 Raise "e" to the 4th power to get 54.5982 (note: this value is approximate).
 Add 1 to 54.5982 to get 55.5982.
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Exponential-and-logarithmic-functions/191078: Please help me solve this equation
5-5 Completing the Square
Solving a quadratic equation if the coefficient of x^2 is NOT 1
4x^2+24x-8=0 1 solutions
Answer 143444 by jim_thompson5910(28476) on 2009-04-14 15:15:06 (Show Source):
You can put this solution on YOUR website!First, let's complete the square for the left side of the equation
 Start with the given expression.
 Factor out the  coefficient  . This step is very important: the  coefficient must be equal to 1.
Take half of the  coefficient  to get  . In other words,  .
Now square  to get  . In other words,
 Now add and subtract  inside the parenthesis. Make sure to place this after the "x" term. Notice how  . So the expression is not changed.
 Group the first three terms.
 Factor  to get  .
 Combine like terms.
 Distribute.
 Multiply.
So after completing the square,  transforms to  . So  .
So  is equivalent to  .
-----------------------------------------------------------
Now let's solve
 Start with the given equation.
 Add 44 to both sides
 Divide both sides by  .
 Reduce.
 Take the square root of both sides.
 or  Break up the "plus/minus" to form two equations.
 or  Subtract  from both sides.
--------------------------------------
Answer:
So the solutions are  or  .
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Polynomials-and-rational-expressions/191084: Please help me solve this equation
5-5 Completing the Square
Solving a quadratic equation if the coefficient of x^2 is NOT 1
3x^2+12x-9=0 1 solutions
Answer 143443 by jim_thompson5910(28476) on 2009-04-14 15:10:52 (Show Source):
You can put this solution on YOUR website!First, let's complete the square for the left side of the equation
 Start with the given expression.
 Factor out the  coefficient  . This step is very important: the  coefficient must be equal to 1.
Take half of the  coefficient  to get  . In other words,  .
Now square  to get  . In other words,
 Now add and subtract  inside the parenthesis. Make sure to place this after the "x" term. Notice how  . So the expression is not changed.
 Group the first three terms.
 Factor  to get  .
 Combine like terms.
 Distribute.
 Multiply.
So after completing the square,  transforms to  . So  .
So  is equivalent to  .
-----------------------------------------------------------
Now let's solve
 Start with the given equation.
 Add 21 to both sides
 Divide both sides by  .
 Reduce.
 Take the square root of both sides. (note: don't forget the "plus/minus")
 or  Break up the "plus/minus" to form two equations.
 or  Subtract  from both sides.
--------------------------------------
Answer:
So the solutions are  or  .
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Exponential-and-logarithmic-functions/191085: Please help me solve this equation
5-5 Completing the Square
Solving a quadratic equation if the coefficient of x^2 is NOT 1
3x^2+12x-9=0 1 solutions
Answer 143442 by jim_thompson5910(28476) on 2009-04-14 15:09:51 (Show Source):
You can put this solution on YOUR website!First, let's complete the square for the left side of the equation
 Start with the given expression.
 Factor out the  coefficient  . This step is very important: the  coefficient must be equal to 1.
Take half of the  coefficient  to get  . In other words,  .
Now square  to get  . In other words,
 Now add and subtract  inside the parenthesis. Make sure to place this after the "x" term. Notice how  . So the expression is not changed.
 Group the first three terms.
 Factor  to get  .
 Combine like terms.
 Distribute.
 Multiply.
So after completing the square,  transforms to  . So  .
So  is equivalent to  .
-----------------------------------------------------------
Now let's solve
 Start with the given equation.
 Add 21 to both sides
 Divide both sides by  .
 Reduce.
 Take the square root of both sides. (note: don't forget the "plus/minus")
 or  Break up the "plus/minus" to form two equations.
 or  Subtract  from both sides.
--------------------------------------
Answer:
So the solutions are  or  .
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Graphs/190944: A Line parallel to -3x + 2y = 9 and contains points (-2,1)
How do I set this up?? 1 solutions
Answer 143362 by jim_thompson5910(28476) on 2009-04-13 19:39:06 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Add  to both sides.
 Rearrange the terms.
 Divide both sides by  to isolate y.
 Break up the fraction.
We can see that the equation  has a slope  and a y-intercept  .
Since parallel lines have equal slopes, this means that we know that the slope of the unknown parallel line is  .
Now let's use the point slope formula to find the equation of the parallel line by plugging in the slope  and the coordinates of the given point ) .
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Distribute
 Multiply
 Add 1 to both sides.
 Combine like terms.
So the equation of the line parallel to  that goes through the point ) is  .
Here's a graph to visually verify our answer:
 Graph of the original equation  (red) and the parallel line  (green) through the point ) .
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Geometry_Word_Problems/190946: I have a homework problem that I could use some help with-thank you. What is another measure for an angle that measures 283 degrees? _________ degrees. 1 solutions
Answer 143359 by jim_thompson5910(28476) on 2009-04-13 19:30:32 (Show Source):
You can put this solution on YOUR website!Just add 360 degrees to the angle to get 283+360=643. So another angle measure is 643 degrees.
Note: adding 360 to an angle makes the angle wrap around one full revolution and come back to the same location as the original angle.
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Polynomials-and-rational-expressions/190939: Please help me with this question 3n(squared) + 2n - 1. Thank You 1 solutions
Answer 143354 by jim_thompson5910(28476) on 2009-04-13 19:11:48 (Show Source):
You can put this solution on YOUR website!I'm assuming you want to factor?
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,3
-1,-3
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-3)
(-1)*(3)
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -3 | 1+(-3)=-2 | | -1 | 3 | -1+3=2 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
---------------------------------------------
Answer:
So  factors to  .
Note: you can check the answer by FOILing  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Trigonometry-basics/190819: Can you help me complete this identity?
1)secx - 1/sec x=?
1 solutions
Answer 143336 by jim_thompson5910(28476) on 2009-04-13 16:14:45 (Show Source):
You can put this solution on YOUR website!-\frac{1}{\sec(x)}) ... Start with the given expression
}-\frac{1}{\frac{1}{\cos(x)}}) ... Replace each secant with
}-\cos(x)) Multiply the second fraction by the reciprocal
}-\frac{\cos(x)\cdot\cos(x)}{\cos(x)}) ... Multiply the second term by
}-\frac{\cos^2(x)}{\cos(x)}) Multiply
}{\cos(x)}) Subtract the fractions
}{\cos(x)}) Replace ) with
So
Note: you can rewrite }{\cos(x)}) as \frac{\sin(x)}{\cos(x)}) and then rewrite as \tan(x)) (using the identity  )
So this also means that
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expressions/190842: This question is from textbook Intermediate Algebra an Applied Approach
We are working on logarithms. This was added to our prefinal homework. I am so confused at this point.
Given F(x) = 3x-2, evaluate the following.
a. F(-4)
b. F(-1)
c. F(0)
Here is what i've done so far after several attempts I keep doing it different and confusing myself. I need to understand as finals are next week. Thank you for any help.
f(F,x)=3^(x-2),F(-4)
Evaluate F(-4) by replacing x with -4 in the function.
F(-4)=3^((-4)-2)
F(-4)=(1)/(729)
((1)/(729))
1 solutions
Answer 143332 by jim_thompson5910(28476) on 2009-04-13 16:00:22 (Show Source):
You can put this solution on YOUR website!Is the function  ???
Evaluating f(-4):
 Start with the given function
 Plug in
 Subtract
 Rewrite the right side with a positive exponent by writing the reciprocal of the base.
 Raise 3 to the 6th power to get 729
----------------------------
Evaluating f(-1):
 Start with the given function
 Plug in
 Subtract
 Rewrite the right side with a positive exponent by writing the reciprocal of the base.
 Raise 3 to the 3rd power to get 27
----------------------------
Evaluating f(0):
 Start with the given function
 Plug in
 Subtract
 Rewrite the right side with a positive exponent by writing the reciprocal of the base.
 Square 3 to get 9
----------------------------
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absolute-value/190867: Homework - absolute value
abs(x^2-3) = 2x
I know in absolute value you work it twice once + then -, but im not sure what to do with this one. Thanks 1 solutions
Answer 143321 by jim_thompson5910(28476) on 2009-04-13 15:39:29 (Show Source):
You can put this solution on YOUR website!If you have the equation  , to find "x", you simply solve the two equations  or
So in this case, to solve  , you'll need to solve  (you'll get two solutions here) and you'll need to solve  (you'll get two more solutions here)
Once you have the four possible solutions, you need to check them. If any possible solutions do not satisfy the original equation  , then they are not a solution.
Let me know if this makes sense. If not, then repost or email me.
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