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Probability-and-statistics/197124: 1. A data set has a z-score of 3 for the value 32 and a mean of 20. Find the standard deviation.
1 solutions

Answer 147779 by jim_thompson5910(28595) About Me  on 2009-05-20 19:24:22 (Show Source):
You can put this solution on YOUR website!
Recall, the z score can be found by the formula




where is the mean and is the standard deviation.


So all you have to do is plug in the corresponding values to get:





and solve for to get the standard deviation.


Expressions-with-variables/197120: could you please explain to me how to solve this problem 2 over 5(15p-20)= negative 8p+3(p-6)
1 solutions

Answer 147778 by jim_thompson5910(28595) About Me  on 2009-05-20 19:20:52 (Show Source):
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%282%2F5%29%2815p-20%29=-8p%2B3%28p-6%29 Start with the given equation.


%282%2F5%29%2815p%29-%282%2F5%29%2820%29=-8p%2B3%28p%29%2B3%28-6%29 Distribute.


6p-8=-8p%2B3p-18 Multiply.


6p-8=-5p-18 Combine like terms on the right side.


6p=-5p-18%2B8 Add 8 to both sides.


6p%2B5p=-18%2B8 Add 5p to both sides.


11p=-18%2B8 Combine like terms on the left side.


11p=-10 Combine like terms on the right side.


p=%28-10%29%2F%2811%29 Divide both sides by 11 to isolate p.


----------------------------------------------------------------------

Answer:

So the solution is p=-10%2F11 which approximates to p=-0.909.


Functions/197097: I'm not sure if this is the correct category...
Please help me solve this:

1 solutions

Answer 147777 by jim_thompson5910(28595) About Me  on 2009-05-20 19:19:02 (Show Source):
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5hk%5E2%282h%5E2k-hk%5E3%2B44h%5E2k%5E2%29 Start with the given expression.


5hk%5E2%282h%5E2k%29%2B5hk%5E2%28-hk%5E3%29%2B5hk%5E2%2844h%5E2k%5E2%29 Distribute


10hk%5E2%2Ah%5E2k-5hk%5E2%2Ahk%5E3%2B220hk%5E2%2Ah%5E2k%5E2 Multiply the coefficients


Multiply the variable terms by adding the exponents.


10h%5E3k%5E3-5h%5E2k%5E5%2B220h%5E3k%5E4 Add


So 5hk%5E2%282h%5E2k-hk%5E3%2B44h%5E2k%5E2%29=10h%5E3k%5E3-5h%5E2k%5E5%2B220h%5E3k%5E4


Equations/197037: please solve this equation.

1 over 5(x-120)=-34

thank you
1 solutions

Answer 147700 by jim_thompson5910(28595) About Me  on 2009-05-20 00:44:11 (Show Source):
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Is the equation %281%2F5%29%28x-120%29=-34 ???


%281%2F5%29%28x-120%29=-34 Start with the given equation.


x-120=5%28-34%29 Multiply both sides by 5.


x-120=-170 Multiply.


x=-170%2B120 Add 120 to both sides.


x=-50 Combine like terms on the right side.


----------------------------------------------------------------------

Answer:

So the solution is x=-50


Surface-area/197029: Find the area of a square whose perimeter is 32 inches? Multiple Choice: A.)8square inches, B.) 16, C.) 32, D.)64 But no measurements are given...If I had measurements I could do something but I guess that's what I am supposed to fiqure out right? I suck at geometry!!
1 solutions

Answer 147695 by jim_thompson5910(28595) About Me  on 2009-05-19 22:57:18 (Show Source):
You can put this solution on YOUR website!
Remember, the perimeter of a square is simply the sum of the four sides of a square (ie add up ALL of the 4 sides). To shorten it, we can multiply one side by 4 (since they're all equal). So if "s" is the side length, then P=4s is the perimeter.



P=4s Start with the given equation.


32=4s Plug in the given perimeter P=32


32%2F4=s Divide both sides by 4 to isolate "s".


8=s Reduce



So the side length is s=8 which means that the side of the square is 8 inches long.


Now that you have the side length, do you think you can continue? If not, repost or email me.


Distributive-associative-commutative-properties/196991: For all a, (3a+4)(4a-3)=
1 solutions

Answer 147690 by jim_thompson5910(28595) About Me  on 2009-05-19 21:48:16 (Show Source):
You can put this solution on YOUR website!

%283a%2B4%29%284a-3%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%283a%29%2B4%29%28highlight%284a%29-3%29 Multiply the First terms:%283a%29%284a%29=12a%5E2.


%28highlight%283a%29%2B4%29%284a%2Bhighlight%28-3%29%29 Multiply the Outer terms:%283a%29%28-3%29=-9a.


%283a%2Bhighlight%284%29%29%28highlight%284a%29-3%29 Multiply the Inner terms:%284%29%284a%29=16a.


%283a%2Bhighlight%284%29%29%284a%2Bhighlight%28-3%29%29 Multiply the Last terms:%284%29%28-3%29=-12.


---------------------------------------------------
So we have the terms: 12a%5E2, -9a, 16a, and -12


12a%5E2-9a%2B16a-12 Now add every term listed above to make a single expression.


12a%5E2%2B7a-12 Now combine like terms.


So %283a%2B4%29%284a-3%29 FOILs to 12a%5E2%2B7a-12.


In other words, %283a%2B4%29%284a-3%29=12a%5E2%2B7a-12.


Functions/197006: This question is from textbook Algebra 1
Find the number of solutions for this equation. x2-3x+4=0
1 solutions

Answer 147688 by jim_thompson5910(28595) About Me  on 2009-05-19 21:44:46 (Show Source):
You can put this solution on YOUR website!

From x%5E2-3x%2B4 we can see that a=1, b=-3, and c=4


D=b%5E2-4ac Start with the discriminant formula.


D=%28-3%29%5E2-4%281%29%284%29 Plug in a=1, b=-3, and c=4


D=9-4%281%29%284%29 Square -3 to get 9


D=9-16 Multiply 4%281%29%284%29 to get %284%29%284%29=16


D=-7 Subtract 16 from 9 to get -7


Since the discriminant is less than zero, this means that there are two complex solutions.


In other words, there are no real solutions.


Polynomials-and-rational-expressions/197009: This question is from textbook Algebra and Trigonometry Structure and Method book 2
I have been working on this math problem and I can't seem to figure it out. I was wondering if someone could help me? Please and Thank You!! I would deeply appreciate it!!
Laws of Logarithms
Express as a logarithm of a single number or expression
1 - 3 log base 5 of x
1 solutions

Answer 147685 by jim_thompson5910(28595) About Me  on 2009-05-19 21:42:32 (Show Source):
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1-3%2Alog%285%2C%28x%29%29 Start with the given expression.


log%285%2C%285%29%29-3%2Alog%285%2C%28x%29%29 Rewrite "1" as log%285%2C%285%29%29


Note: log%28b%2C%28b%29%29=1 where b%3E1.


log%285%2C%285%29%29-log%285%2C%28x%5E3%29%29 Rewrite the second log using the identity y%2Alog%28b%2C%28x%29%29=log%28b%2C%28x%5Ey%29%29


log%285%2C%285%2F%28x%5E3%29%29%29 Combine the logs using the identity log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29


So 1-3%2Alog%285%2C%28x%29%29=log%285%2C%285%2F%28x%5E3%29%29%29 where x%3E0




Equations/197010: please help solve

3(2c-3)-2(-3c-3)=45

thank you
1 solutions

Answer 147684 by jim_thompson5910(28595) About Me  on 2009-05-19 21:35:08 (Show Source):
You can put this solution on YOUR website!

3%282c-3%29-2%28-3c-3%29=45 Start with the given equation.


6c-9%2B6c%2B6=45 Distribute.


12c-3=45 Combine like terms on the left side.


12c=45%2B3 Add 3 to both sides.


12c=48 Combine like terms on the right side.


c=%2848%29%2F%2812%29 Divide both sides by 12 to isolate c.


c=4 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is c=4


Numbers_Word_Problems/196978: The average of two numbers is 7. Find the numbers if three times one of the numbers is one half the other number.
I tried using substitution from the two equations given, which I think are :
(x + y) / 2 = 7 and
3x = 1/2y
But I didn't have any luck
1 solutions

Answer 147661 by jim_thompson5910(28595) About Me  on 2009-05-19 17:55:14 (Show Source):
You can put this solution on YOUR website!
3x+=+%281%2F2%29y Start with the second equation.


3x%282%29+=+y Multiply both sides by 2.


6x+=+y Multiply


y=6x Rearrange the equation


------------------------------------------------


%28x+%2B+y%29+%2F+2+=+7+ Move onto the first equation


%28x+%2B+6x%29+%2F+2+=+7+ Plug in y=6x


%287x%29+%2F+2+=+7+ Add


7x+=+7%282%29+ Multiply both sides by 2.


7x+=+14+ Multiply


x=%2814%29%2F%287%29 Divide both sides by 7 to isolate x.


x=2 Reduce.


So one of the numbers is 2


y=6x Go back to the second equation


y=6%282%29 Plug in x=2


y=12 Multiply


So the other number is 12


Rational-functions/196960: x/x-2 - x-5/5 = x-2/5
1 solutions

Answer 147652 by jim_thompson5910(28595) About Me  on 2009-05-19 16:59:45 (Show Source):
You can put this solution on YOUR website!
x%2F%28x-2%29-%28x-5%29%2F5=%28x-2%29%2F5 Start with the given equation.


Multiply EVERY term by the LCD 5%28x-2%29 to clear out the fractions.


5x-%28x-2%29%28x-5%29=%28x-2%29%28x-2%29 Simplify


5x-%28x%5E2-7x%2B10%29=x%5E2-4x%2B4 FOIL


5x-x%5E2%2B7x-10=x%5E2-4x%2B4 Distribute


5x-x%5E2%2B7x-10-x%5E2%2B4x-4=0 Get all terms to the left side.


-2x%5E2%2B16x-14=0 Combine like terms.


Notice we have a quadratic in the form of Ax%5E2%2BBx%2BC where A=-2, B=16, and C=-14


Let's use the quadratic formula to solve for x


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%2816%29+%2B-+sqrt%28+%2816%29%5E2-4%28-2%29%28-14%29+%29%29%2F%282%28-2%29%29 Plug in A=-2, B=16, and C=-14


x+=+%28-16+%2B-+sqrt%28+256-4%28-2%29%28-14%29+%29%29%2F%282%28-2%29%29 Square 16 to get 256.


x+=+%28-16+%2B-+sqrt%28+256-112+%29%29%2F%282%28-2%29%29 Multiply 4%28-2%29%28-14%29 to get 112


x+=+%28-16+%2B-+sqrt%28+144+%29%29%2F%282%28-2%29%29 Subtract 112 from 256 to get 144


x+=+%28-16+%2B-+sqrt%28+144+%29%29%2F%28-4%29 Multiply 2 and -2 to get -4.


x+=+%28-16+%2B-+12%29%2F%28-4%29 Take the square root of 144 to get 12.


x+=+%28-16+%2B+12%29%2F%28-4%29 or x+=+%28-16+-+12%29%2F%28-4%29 Break up the expression.


x+=+%28-4%29%2F%28-4%29 or x+=++%28-28%29%2F%28-4%29 Combine like terms.


x+=+1 or x+=+7 Simplify.


So the solutions are x+=+1 or x+=+7


Polynomials-and-rational-expressions/196958: 5y/(5y+15)(divided by) 15y/(y+3)
1 solutions

Answer 147651 by jim_thompson5910(28595) About Me  on 2009-05-19 16:54:06 (Show Source):
You can put this solution on YOUR website!

%28%285y%29%2F%285y%2B15%29%29%2F%28%2815y%29%2F%28y%2B3%29%29 Start with the given expression.


%28%285y%29%2F%285y%2B15%29%29%28%28y%2B3%29%2F%2815y%29%29 Multiply the first fraction %285y%29%2F%285y%2B15%29 by the reciprocal of the second fraction %2815y%29%2F%28y%2B3%29.


%28%285y%29%2F%285%28y%2B3%29%29%29%28%28y%2B3%29%2F%2815y%29%29 Factor 5y%2B15 to get 5%28y%2B3%29.


%28%285y%29%2F%285%28y%2B3%29%29%29%28%28%28y%2B3%29%29%2F%283%2A5y%29%29 Factor 15y to get 3%2A5y.


%285y%28y%2B3%29%29%2F%285%2A3%2A5y%28y%2B3%29%29 Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


1%2F%285%2A3%29 Simplify.


1%2F15 Multiply


So %28%285y%29%2F%285y%2B15%29%29%2F%28%2815y%29%2F%28y%2B3%29%29 simplifies to 1%2F15.


In other words, %28%285y%29%2F%285y%2B15%29%29%2F%28%2815y%29%2F%28y%2B3%29%29=1%2F15 where y%3C%3E-3 or y%3C%3E0


Equations/196927: Subtract -x+y from 3x+y
1 solutions

Answer 147635 by jim_thompson5910(28595) About Me  on 2009-05-19 13:19:26 (Show Source):
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%283x%2By%29-%28-x%2By%29 Start with the given expression.


3x%2By%2Bx-y Distribute


%283x%2Bx%29%2B%28y-y%29 Group like terms


4x Combine like terms


So %283x%2By%29-%28-x%2By%29=4x


Equations/196925: Factor: 16x²-81
1 solutions

Answer 147633 by jim_thompson5910(28595) About Me  on 2009-05-19 13:13:48 (Show Source):
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16x%5E2-81 Start with the given expression.


%284x%29%5E2-81 Rewrite 16x%5E2 as %284x%29%5E2.


%284x%29%5E2-%289%29%5E2 Rewrite 81 as %289%29%5E2.


Notice how we have a difference of squares A%5E2-B%5E2 where in this case A=4x and B=9.


So let's use the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29 to factor the expression:


A%5E2-B%5E2=%28A%2BB%29%28A-B%29 Start with the difference of squares formula.


%284x%29%5E2-%289%29%5E2=%284x%2B9%29%284x-9%29 Plug in A=4x and B=9.


So this shows us that 16x%5E2-81 factors to %284x%2B9%29%284x-9%29.


In other words 16x%5E2-81=%284x%2B9%29%284x-9%29.


Trigonometry-basics/196914: This question is from textbook
2y+1
___________
y^2-y-6
1 solutions

Answer 147631 by jim_thompson5910(28595) About Me  on 2009-05-19 12:57:55 (Show Source):
You can put this solution on YOUR website!
I'm assuming that you want to perform a partial fraction decomposition...


%282y%2B1%29%2F%28y%5E2-y-6%29 Start with the given expression.


%282y%2B1%29%2F%28%28y%2B2%29%28y-3%29%29 Factor the denominator



Since both factors are linear and are of multiplicity 1, this means that the fraction decomposes into:

%282y%2B1%29%2F%28%28y%2B2%29%28y-3%29%29=A%2F%28y%2B2%29%2BB%2F%28y-3%29


Multiply EVERY term by the LCD %28y%2B2%29%28y-3%29 to clear out the fractions.


2y%2B1=A%28y-3%29%2BB%28y%2B2%29 Simplify


2y%2B1=Ay-3A%2BBy%2B2B Distribute


2y%2B1=Ay%2BBy-3A%2B2B Rearrange the terms


2y%2B1=%28A%2BB%29y-3A%2B2B Combine like terms.



Since the "y" coefficient on the right side is A%2BB, this means that A%2BB=2. Also, the constant term -3A%2B2B=1



So this means that we have the system:

system%28A%2BB=2%2C-3A%2B2B=1%29


Solve this system of equations (using any method) to get the solutions:

A=3%2F5 and B=7%2F5


Now plug these values back into the original equation to get:






And simplify


%282y%2B1%29%2F%28%28y%2B2%29%28y-3%29%29=3%2F%285%28y%2B2%29%29%2B7%2F%285%28y-3%29%29

===============================================

Answer:

So %282y%2B1%29%2F%28y%5E2-y-6%29=3%2F%285%28y%2B2%29%29%2B7%2F%285%28y-3%29%29


Quadratic_Equations/196896: I have a few problems I'm struggling with:
1: x^2 - 3x = -10 (directions say use quadratic formula, use radicals as needed).
2: (x+12)(x-8)(x+8)>0 (directions say to use one equality or compount equality)
3: 2x^2 - 5x +1 (evaluate polynomial for x= -4
4: (9x^8 - 3)(x^9 - 3) (use FOIL to find product)
I thank you in advance for time spent in helping with these problems
1 solutions

Answer 147630 by jim_thompson5910(28595) About Me  on 2009-05-19 12:43:44 (Show Source):
You can put this solution on YOUR website!
# 1

x%5E2-3x=-10 Start with the given equation.


x%5E2-3x%2B10=0 Get all terms to the left side.


Notice we have a quadratic in the form of Ax%5E2%2BBx%2BC where A=1, B=-3, and C=10


Let's use the quadratic formula to solve for x


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%2810%29+%29%29%2F%282%281%29%29 Plug in A=1, B=-3, and C=10


x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%2810%29+%29%29%2F%282%281%29%29 Negate -3 to get 3.


x+=+%283+%2B-+sqrt%28+9-4%281%29%2810%29+%29%29%2F%282%281%29%29 Square -3 to get 9.


x+=+%283+%2B-+sqrt%28+9-40+%29%29%2F%282%281%29%29 Multiply 4%281%29%2810%29 to get 40


x+=+%283+%2B-+sqrt%28+-31+%29%29%2F%282%281%29%29 Subtract 40 from 9 to get -31


x+=+%283+%2B-+sqrt%28+-31+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%283+%2B-+i%2Asqrt%2831%29%29%2F%282%29 Simplify the square root


x+=+%283%2Bi%2Asqrt%2831%29%29%2F%282%29 or x+=+%283-i%2Asqrt%2831%29%29%2F%282%29 Break up the expression.


So the answers are x+=+%283%2Bi%2Asqrt%2831%29%29%2F%282%29 or x+=+%283-i%2Asqrt%2831%29%29%2F%282%29




# 2

%28x%2B8%29%28x-8%29%28x%2B12%29%3E0 Start with the given inequality


%28x%2B8%29%28x-8%29%28x%2B12%29=0 Set the left side equal to zero


Set each individual factor equal to zero:

x%2B8=0, x-8=0 or x%2B12=0

Solve for x in each case:

x=-8, x=8 or x=-12


So our critical values are x=-8, x=8 and x=-12

Now set up a number line and plot the critical values on the number line

number_line%28+600%2C+-15%2C+10%2C-8%2C8%2C-12%29



So let's pick some test points that are near the critical values and evaluate them.


Let's pick a test value that is less than -12 (notice how it's to the left of the leftmost endpoint):

So let's pick x=-13

%28x%2B8%29%28x-8%29%28x%2B12%29%3E0 Start with the given inequality


%28-13%2B8%29%28-13-8%29%28-13%2B12%29%3E+0 Plug in x=-13


-105%3E+0 Evaluate and simplify the left side

Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.


---------------------------------------------------------------------------------------------



Let's pick a test value that is in between -12 and -8:

So let's pick x=-10

%28x%2B8%29%28x-8%29%28x%2B12%29%3E0 Start with the given inequality


%28-10%2B8%29%28-10-8%29%28-10%2B12%29%3E+0 Plug in x=-10


72%3E+0 Evaluate and simplify the left side

Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is ()





---------------------------------------------------------------------------------------------



Let's pick a test value that is in between -8 and 8:

So let's pick x=0

%28x%2B8%29%28x-8%29%28x%2B12%29%3E0 Start with the given inequality


%280%2B8%29%280-8%29%280%2B12%29%3E+0 Plug in x=0


-768%3E+0 Evaluate and simplify the left side

Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.


---------------------------------------------------------------------------------------------



Let's pick a test value that is greater than 8 (notice how it's to the right of the rightmost endpoint):

So let's pick x=9

%28x%2B8%29%28x-8%29%28x%2B12%29%3E0 Start with the given inequality


%289%2B8%29%289-8%29%289%2B12%29%3E+0 Plug in x=9


357%3E+0 Evaluate and simplify the left side

Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is ()





---------------------------------------------------------------------------------------------





Summary:

So the solution in interval notation is:


() ()






# 3

2x%5E2-5x%2B1 Start with the given expression.


2%28-4%29%5E2-5%28-4%29%2B1 Plug in x=-4.


2%2816%29-5%28-4%29%2B1 Square -4 to get 16.


32-5%28-4%29%2B1 Multiply 2 and 16 to get 32.


32%2B20%2B1 Multiply -5 and -4 to get 20.


53 Combine like terms.


So 2x%5E2-5x%2B1=53 when x=-4




# 4




%289x%5E8-3%29%28x%5E9-3%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%289x%5E8%29-3%29%28highlight%28x%5E9%29-3%29 Multiply the First terms:%289%2Ax%5E8%29%2A%28x%5E9%29=9%2Ax%5E17. Note: simply add the exponents


%28highlight%289x%5E8%29-3%29%28x%5E9%2Bhighlight%28-3%29%29 Multiply the Outer terms:%289%2Ax%5E8%29%2A%28-3%29=-27%2Ax%5E8.


%289x%5E8%2Bhighlight%28-3%29%29%28highlight%28x%5E9%29-3%29 Multiply the Inner terms:%28-3%29%2A%28x%5E9%29=-3%2Ax%5E9.


%289x%5E8%2Bhighlight%28-3%29%29%28x%5E9%2Bhighlight%28-3%29%29 Multiply the Last terms:%28-3%29%2A%28-3%29=9.


---------------------------------------------------
So we have the terms: 9%2Ax%5E17, -27%2Ax%5E8, -3%2Ax%5E9, 9


9%2Ax%5E17-27%2Ax%5E8-3%2Ax%5E9%2B9 Now add every term listed above to make a single expression.


So %289x%5E8-3%29%28x%5E9-3%29 FOILs to 9%2Ax%5E17-27%2Ax%5E8-3%2Ax%5E9%2B9.


In other words, %289x%5E8-3%29%28x%5E9-3%29=9%2Ax%5E17-27%2Ax%5E8-3%2Ax%5E9%2B9.


Polynomials-and-rational-expressions/196916: could you please tell me how to do this promplem 6x-4+4x-3 and explain what the x means thanks
1 solutions

Answer 147629 by jim_thompson5910(28595) About Me  on 2009-05-19 12:33:59 (Show Source):
You can put this solution on YOUR website!
The "x" is simply a place holder for any number. For example, when we say x%2B5, we're saying: "take any number and add 5 to it".





6x-4%2B4x-3 Start with the given expression


%286x%2B4x%29%2B%28-4-3%29 Group like terms


10x-7 Combine like terms


So 6x-4%2B4x-3=10x-7


Equations/196882: ((3x+2)/4)=(9/4)-((3-2x)/6)
1 solutions

Answer 147601 by jim_thompson5910(28595) About Me  on 2009-05-18 23:24:54 (Show Source):
You can put this solution on YOUR website!
%283x%2B2%29%2F4=9%2F4-%283-2x%29%2F6 Start with the given equation.


Multiply EVERY term by the LCD 12 to clear out the fractions.


3%283x%2B2%29=3%289%29-2%283-2x%29 Simplify


3%283x%2B2%29=27-2%283-2x%29 Multiply


9x%2B6=27-6%2B4x Distribute.


9x%2B6=4x%2B21 Combine like terms on the right side.


9x=4x%2B21-6 Subtract 6 from both sides.


9x-4x=21-6 Subtract 4x from both sides.


5x=21-6 Combine like terms on the left side.


5x=15 Combine like terms on the right side.


x=%2815%29%2F%285%29 Divide both sides by 5 to isolate x.


x=3 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x=3


Quadratic_Equations/196864: This question is from textbook McDougal Littell Algebra 1
Please help me solve this equation: x^2+3/5x-1=0
It is called completing the square and has to do with solving quadratic equations.
1 solutions

Answer 147600 by jim_thompson5910(28595) About Me  on 2009-05-18 23:13:57 (Show Source):
You can put this solution on YOUR website!
First, let's complete the square:


x%5E2%2B%283%2F5%29x-1 Start with the left side of the given equation.


Take half of the x coefficient 3%2F5 to get 3%2F10. In other words, %281%2F2%29%283%2F5%29=3%2F10.


Now square 3%2F10 to get 9%2F100. In other words, %283%2F10%29%5E2=%283%2F10%29%283%2F10%29=9%2F100


x%5E2%2B%283%2F5%29x%2Bhighlight%289%2F100-9%2F100%29-1 Now add and subtract 9%2F100. Make sure to place this after the "x" term. Notice how 9%2F100-9%2F100=0. So the expression is not changed.


%28x%5E2%2B%283%2F5%29x%2B9%2F100%29-9%2F100-1 Group the first three terms.


%28x%2B3%2F10%29%5E2-9%2F100-1 Factor x%5E2%2B%283%2F5%29x%2B9%2F100 to get %28x%2B3%2F10%29%5E2.


%28x%2B3%2F10%29%5E2-109%2F100 Combine like terms.


So after completing the square, x%5E2%2B3%2F5x-1 transforms to %28x%2B3%2F10%29%5E2-109%2F100. So x%5E2%2B3%2F5x-1=%28x%2B3%2F10%29%5E2-109%2F100.


So x%5E2%2B%283%2F5%29x-1=0 is equivalent to %28x%2B3%2F10%29%5E2-109%2F100=0.


------------------------------------------------------------------------

Now let's solve %28x%2B3%2F10%29%5E2-109%2F100=0


%28x%2B3%2F10%29%5E2-109%2F100=0 Start with the given equation.


%28x%2B3%2F10%29%5E2=0%2B109%2F100Add 109%2F100 to both sides.


%28x%2B3%2F10%29%5E2=109%2F100 Combine like terms.


x%2B3%2F10=0%2B-sqrt%28109%2F100%29 Take the square root of both sides.


x%2B3%2F10=sqrt%28109%2F100%29 or x%2B3%2F10=-sqrt%28109%2F100%29 Break up the "plus/minus" to form two equations.


x%2B3%2F10=sqrt%28109%29%2F10 or x%2B3%2F10=-sqrt%28109%29%2F10 Simplify the square root.


x=-3%2F10%2Bsqrt%28109%29%2F10 or x=-3%2F10-sqrt%28109%29%2F10 Subtract 3%2F10 from both sides.


x=%28-3%2Bsqrt%28109%29%29%2F%2810%29 or x=%28-3-sqrt%28109%29%29%2F%2810%29 Combine the fractions.


--------------------------------------


Answer:


So the solutions are x=%28-3%2Bsqrt%28109%29%29%2F%2810%29 or x=%28-3-sqrt%28109%29%29%2F%2810%29.


Miscellaneous_Word_Problems/196872: Estimate 3004 x 5982
1 solutions

Answer 147596 by jim_thompson5910(28595) About Me  on 2009-05-18 22:25:36 (Show Source):
You can put this solution on YOUR website!
3004 can be rounded to 3000 and 5982 rounded to 6000 (both are rounded to the nearest thousand)


So we can then multiply 3000 and 6000 mentally to get 18,000,000 (3*6 = 18 and just add 2 sets of 3 zeros)


So 3004 x 5982 estimates to 18,000,000


Quadratic_Equations/196865: This question is from textbook McDougal Littell Algebra 1
Please help me solve this equation: 5x^2-20x-20=5
It is called completing the square and has to do with solving quadratic equations.
1 solutions

Answer 147595 by jim_thompson5910(28595) About Me  on 2009-05-18 22:18:01 (Show Source):
You can put this solution on YOUR website!
5x%5E2-20x-20=5 Start with the given equation.


5x%5E2-20x-20-5=0 Subtract 5 from both sides.


5x%5E2-20x-25=0 Combine like terms.


---------------------------------------------------------------

Now let's complete the square for the left side expression 5x%5E2-20x-25


5x%5E2-20x-25 Start with the given expression.


5%28x%5E2-4x-5%29 Factor out the x%5E2 coefficient 5. This step is very important: the x%5E2 coefficient must be equal to 1.


Take half of the x coefficient -4 to get -2. In other words, %281%2F2%29%28-4%29=-2.


Now square -2 to get 4. In other words, %28-2%29%5E2=%28-2%29%28-2%29=4


5%28x%5E2-4x%2Bhighlight%284-4%29-5%29 Now add and subtract 4 inside the parenthesis. Make sure to place this after the "x" term. Notice how 4-4=0. So the expression is not changed.


5%28%28x%5E2-4x%2B4%29-4-5%29 Group the first three terms.


5%28%28x-2%29%5E2-4-5%29 Factor x%5E2-4x%2B4 to get %28x-2%29%5E2.


5%28%28x-2%29%5E2-9%29 Combine like terms.


5%28x-2%29%5E2%2B5%28-9%29 Distribute.


5%28x-2%29%5E2-45 Multiply.


So after completing the square, 5x%5E2-20x-25 transforms to 5%28x-2%29%5E2-45. So 5x%5E2-20x-25=5%28x-2%29%5E2-45.


So 5x%5E2-20x-25=0 is equivalent to 5%28x-2%29%5E2-45=0.


-----------------------------------------------------------------


Now let's solve 5%28x-2%29%5E2-45=0


5%28x-2%29%5E2-45=0 Start with the given equation.


5%28x-2%29%5E2=0%2B45Add 45 to both sides.


5%28x-2%29%5E2=45 Combine like terms.


%28x-2%29%5E2=%2845%29%2F%285%29 Divide both sides by 5.


%28x-2%29%5E2=9 Reduce.


x-2=%27%27%2B-sqrt%289%29 Take the square root of both sides.


x-2=sqrt%289%29 or x-2=-sqrt%289%29 Break up the "plus/minus" to form two equations.


x-2=3 or x-2=-3 Take the square root of 9 to get 3.


x=2%2B3 or x=2-3 Add 2 to both sides.


x=5 or x=-1 Combine like terms.


--------------------------------------


Answer:


So the solutions are x=5 or x=-1.


Miscellaneous_Word_Problems/196868: 1. Use inductive reasoning to determine the next three numbers in the pattern:
  
__1__          ___1__         _1___ 
  3              9             27 


1 solutions

Answer 147594 by jim_thompson5910(28595) About Me  on 2009-05-18 22:12:11 (Show Source):
You can put this solution on YOUR website!
The numerators follow the pattern: 1, 1, 1, ...
The denominators follow the pattern: 3, 9, 27, ...



Notice how if multiply 3 by 3, we get 9. If we multiply 9 by 3, we get 27, etc..


So the rule is to multiply the denominators by 3 to get the next term. So the next three denominators are: 27%2A3=81, 81%2A3=243, and 243%2A3=729


This means that the next three terms are: 1%2F81, 1%2F243 and 1%2F729


Quadratic_Equations/196866: This question is from textbook McDougal Littell Algebra 1
Please help me solve this equation: 4x^2+6x-6=2
It is called completing the square and has to do with solving quadratic equations.
1 solutions

Answer 147593 by jim_thompson5910(28595) About Me  on 2009-05-18 22:08:01 (Show Source):
You can put this solution on YOUR website!
4x%5E2%2B6x-6=2 Start with the given equation.


4x%5E2%2B6x-6-2=0 Subtract 2 from both sides.


4x%5E2%2B6x-8=0 Combine like terms.


Now let's complete the square for the expression on the left side:



4x%5E2%2B6x-8 Start with the given expression.


4%28x%5E2%2B%283%2F2%29x-2%29 Factor out the x%5E2 coefficient 4. This step is very important: the x%5E2 coefficient must be equal to 1.


Take half of the x coefficient 3%2F2 to get 3%2F4. In other words, %281%2F2%29%283%2F2%29=3%2F4.


Now square 3%2F4 to get 9%2F16. In other words, %283%2F4%29%5E2=%283%2F4%29%283%2F4%29=9%2F16


4%28x%5E2%2B%283%2F2%29x%2Bhighlight%289%2F16-9%2F16%29-2%29 Now add and subtract 9%2F16 inside the parenthesis. Make sure to place this after the "x" term. Notice how 9%2F16-9%2F16=0. So the expression is not changed.


4%28%28x%5E2%2B%283%2F2%29x%2B9%2F16%29-9%2F16-2%29 Group the first three terms.


4%28%28x%2B3%2F4%29%5E2-9%2F16-2%29 Factor x%5E2%2B%283%2F2%29x%2B9%2F16 to get %28x%2B3%2F4%29%5E2.


4%28%28x%2B3%2F4%29%5E2-41%2F16%29 Combine like terms.


4%28x%2B3%2F4%29%5E2%2B4%28-41%2F16%29 Distribute.


4%28x%2B3%2F4%29%5E2-41%2F4 Multiply.


So after completing the square, 4x%5E2%2B6x-8 transforms to 4%28x%2B3%2F4%29%5E2-41%2F4. So 4x%5E2%2B6x-8=4%28x%2B3%2F4%29%5E2-41%2F4.


So 4x%5E2%2B6x-8=0 is equivalent to 4%28x%2B3%2F4%29%5E2-41%2F4=0.


-----------------------------------------------------------------------------------


Now let's solve 4%28x%2B3%2F4%29%5E2-41%2F4=0


4%28x%2B3%2F4%29%5E2-41%2F4=0 Start with the given equation.


4%28x%2B3%2F4%29%5E2=0%2B41%2F4Add 41%2F4 to both sides.


4%28x%2B3%2F4%29%5E2=41%2F4 Combine like terms.


%28x%2B3%2F4%29%5E2=%2841%2F4%29%2F%284%29 Divide both sides by 4.


%28x%2B3%2F4%29%5E2=41%2F16 Reduce.


x%2B3%2F4=%27%27%2B-sqrt%2841%2F16%29 Take the square root of both sides.


x%2B3%2F4=sqrt%2841%2F16%29 or x%2B3%2F4=-sqrt%2841%2F16%29 Break up the "plus/minus" to form two equations.


x%2B3%2F4=sqrt%2841%29%2F4 or x%2B3%2F4=-sqrt%2841%29%2F4 Simplify the square root.


x=-3%2F4%2Bsqrt%2841%29%2F4 or x=-3%2F4-sqrt%2841%29%2F4 Subtract 3%2F4 from both sides.


x=%28-3%2Bsqrt%2841%29%29%2F%284%29 or x=%28-3-sqrt%2841%29%29%2F%284%29 Combine the fractions.


--------------------------------------


Answer:


So the solutions are x=%28-3%2Bsqrt%2841%29%29%2F%284%29 or x=%28-3-sqrt%2841%29%29%2F%284%29.


Rational-functions/196861: Please help me simplify this rational expression:
1 solutions

Answer 147591 by jim_thompson5910(28595) About Me  on 2009-05-18 21:53:16 (Show Source):
You can put this solution on YOUR website!
Note: the previous solution has a sign error and the answer should be much simpler.



Start with the given expression.


Multiply the first fraction %28x%5E3%2By%5E3%29%2F%282x%5E3%2B2x%5E2y%29 by the reciprocal of the second fraction %283x%5E3-3x%5E2y%2B3xy%5E2%29%2F%286x%5E2-6y%5E2%29.


Factor x%5E3%2By%5E3 to get %28x%2By%29%28x%5E2-xy%2By%5E2%29.


Factor 2x%5E3%2B2x%5E2y to get 2x%5E2%28x%2By%29.


Factor 6x%5E2-6y%5E2 to get 6%28x-y%29%28x%2By%29.


Factor 3x%5E3-3x%5E2y%2B3xy%5E2 to get 3x%28x%5E2-xy%2By%5E2%29.


Combine the fractions.


Multiply 2x%5E2 and 3x to get 6x%5E3.


Highlight the common terms.


Cancel out the common terms.


%28%28x-y%29%28x%2By%29%29%2F%28x%5E3%29 Simplify


%28x%5E2-y%5E2%29%2F%28x%5E3%29 FOIL



So simplifies to %28x%5E2-y%5E2%29%2F%28x%5E3%29.


In other words,




Equations/196850: solve for x: 0.3x+3=30
1 solutions

Answer 147577 by jim_thompson5910(28595) About Me  on 2009-05-18 20:50:49 (Show Source):
You can put this solution on YOUR website!

0.3x%2B3=30 Start with the given equation.


10%280.3x%2B3%29=10%2830%29 Multiply both sides by 10 to clear out the decimals.


3x%2B30=300 Distribute and multiply.


3x=300-30 Subtract 30 from both sides.


3x=270 Combine like terms on the right side.


x=%28270%29%2F%283%29 Divide both sides by 3 to isolate x.


x=90 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x=90


Equations/196846: Solve for y: 5y-20=10
1 solutions

Answer 147575 by jim_thompson5910(28595) About Me  on 2009-05-18 20:32:49 (Show Source):
You can put this solution on YOUR website!

5y-20=10 Start with the given equation.


5y=10%2B20 Add 20 to both sides.


5y=30 Combine like terms on the right side.


y=%2830%29%2F%285%29 Divide both sides by 5 to isolate y.


y=6 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is y=6


Equations/196847: Solve for r: 3r-4=4(r-3)
1 solutions

Answer 147574 by jim_thompson5910(28595) About Me  on 2009-05-18 20:32:16 (Show Source):
You can put this solution on YOUR website!

3r-4=4%28r-3%29 Start with the given equation.


3r-4=4r-12 Distribute.


3r=4r-12%2B4 Add 4 to both sides.


3r-4r=-12%2B4 Subtract 4r from both sides.


-r=-12%2B4 Combine like terms on the left side.


-r=-8 Combine like terms on the right side.


r=%28-8%29%2F%28-1%29 Divide both sides by -1 to isolate r.


r=8 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is r=8


Polynomials-and-rational-expressions/196844: It says "Find each quotient. Assume that no denominator has a value of 0."
y2-36 y+6
-----/---- (/ means divided by)
y2-49 y+7
1 solutions

Answer 147573 by jim_thompson5910(28595) About Me  on 2009-05-18 20:31:34 (Show Source):
You can put this solution on YOUR website!
Is the expression %28%28y%5E2-36%29%2F%28y%5E2-49%29%29%2F%28%28y%2B6%29%2F%28y%2B7%29%29 ??? If it is, then...




%28%28y%5E2-36%29%2F%28y%5E2-49%29%29%2F%28%28y%2B6%29%2F%28y%2B7%29%29 Start with the given expression.


%28%28y%5E2-36%29%2F%28y%5E2-49%29%29%28%28y%2B7%29%2F%28y%2B6%29%29 Multiply the first fraction %28y%5E2-36%29%2F%28y%5E2-49%29 by the reciprocal of the second fraction %28y%2B6%29%2F%28y%2B7%29.


%28%28%28y-6%29%28y%2B6%29%29%2F%28y%5E2-49%29%29%28%28y%2B7%29%2F%28y%2B6%29%29 Factor y%5E2-36 to get %28y-6%29%28y%2B6%29.


%28%28%28y-6%29%28y%2B6%29%29%2F%28%28y-7%29%28y%2B7%29%29%29%28%28y%2B7%29%2F%28y%2B6%29%29 Factor y%5E2-49 to get %28y-7%29%28y%2B7%29.


%28%28y-6%29%28y%2B6%29%28y%2B7%29%29%2F%28%28y-7%29%28y%2B7%29%28y%2B6%29%29 Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


%28y-6%29%2F%28y-7%29 Simplify.


So %28%28y%5E2-36%29%2F%28y%5E2-49%29%29%2F%28%28y%2B6%29%2F%28y%2B7%29%29 simplifies to %28y-6%29%2F%28y-7%29.


In other words, where y%3C%3E-7, y%3C%3E-6, or y%3C%3E7


Square-cubic-other-roots/196845: This question is from textbook McDougal Littell Algebra 1
Please help me solve this equation: x^2+5x-11/4=0
It is called "completing the square" and has to do with solving quadratic equations.
1 solutions

Answer 147572 by jim_thompson5910(28595) About Me  on 2009-05-18 20:26:57 (Show Source):
You can put this solution on YOUR website!
To solve this, let's first complete the square:


x%5E2%2B5x-11%2F4 Start with the left side of the given equation.


Take half of the x coefficient 5 to get 5%2F2. In other words, %281%2F2%29%285%29=5%2F2.


Now square 5%2F2 to get 25%2F4. In other words, %285%2F2%29%5E2=%285%2F2%29%285%2F2%29=25%2F4


x%5E2%2B5x%2Bhighlight%2825%2F4-25%2F4%29-11%2F4 Now add and subtract 25%2F4. Make sure to place this after the "x" term. Notice how 25%2F4-25%2F4=0. So the expression is not changed.


%28x%5E2%2B5x%2B25%2F4%29-25%2F4-11%2F4 Group the first three terms.


%28x%2B5%2F2%29%5E2-25%2F4-11%2F4 Factor x%5E2%2B5x%2B25%2F4 to get %28x%2B5%2F2%29%5E2.


%28x%2B5%2F2%29%5E2-9 Combine like terms.


So after completing the square, x%5E2%2B5x-11%2F4 transforms to %28x%2B5%2F2%29%5E2-9. So x%5E2%2B5x-11%2F4=%28x%2B5%2F2%29%5E2-9.


So x%5E2%2B5x-11%2F4=0 is equivalent to %28x%2B5%2F2%29%5E2-9=0.



--------------------------------------------------------------------

Now let's solve %28x%2B5%2F2%29%5E2-9=0


%28x%2B5%2F2%29%5E2-9=0 Start with the given equation.


%28x%2B5%2F2%29%5E2=0%2B9Add 9 to both sides.


%28x%2B5%2F2%29%5E2=9 Combine like terms.


x%2B5%2F2=%27%27%2B-sqrt%289%29 Take the square root of both sides.


x%2B5%2F2=sqrt%289%29 or x%2B5%2F2=-sqrt%289%29 Break up the "plus/minus" to form two equations.


x%2B5%2F2=3 or x%2B5%2F2=-3 Take the square root of 9 to get 3.


x=-5%2F2%2B3 or x=-5%2F2-3 Subtract 5%2F2 from both sides.


x=1%2F2 or x=-11%2F2 Combine like terms.


--------------------------------------


Answer:


So the solutions are x=1%2F2 or x=-11%2F2.


Rational-functions/196710: For each rational function, identify any holes or horizontal or vertical asymptotes of its graph.
1. y=[1/x+4]-3
I got:
Holes: none
Vertical Asymptotes: x=-4
Horizontal Asymptotes: y=-3
For the horizontal asymptotes would it be -3 or 3? Or is it something completely different?
2. y=[3/x-1] -2
I got:
Holes: none
Vertical Asymptotes: x=1
Horizontal Asymptotes: y=-2
Would the horizontal asymptote be -2 or 2? Or something else?
Are these right?
I'm not sure if I am doing these type correctly
Thanks in advance for any help!
1 solutions

Answer 147571 by jim_thompson5910(28595) About Me  on 2009-05-18 20:22:36 (Show Source):
You can put this solution on YOUR website!
# 1
If the equation is y=1%2F%28x%2B4%29-3, then you are correct, the vertical asymptote is x=-4 and the horizontal asymptote is y=-3 (you're first choice)


# 2
Likewise, if the equation is y=3%2F%28x-1%29-2, the vertical asymptote is x=1 and the horizontal asymptote is y=-2 (again, you're first choice)


So you are correct on both of them.


Probability-and-statistics/196717: how do you find the variance and standard of the following data? 12,8,13,9,13,11,12,11,9
1 solutions

Answer 147570 by jim_thompson5910(28595) About Me  on 2009-05-18 20:12:30 (Show Source):
You can put this solution on YOUR website!
Standard Deviation:

First sort the numbers into ascending order (from least to greatest):
8,9,9,11,11,12,12,13,13



Now let's find the mean:



To find the mean, add up all of the numbers and divide the sum by the number of numbers (which in this case is 9).
Mean=%288%2B9%2B9%2B11%2B11%2B12%2B12%2B13%2B13%29%2F9=98%2F9=10.8888888888889

So the mean is 10.8888888888889


Now let's find the standard deviation.


where is the arithmetic mean, is the ith number, and is the number of numbers

So we can replace N with 9 (since there are 9 numbers)



Replace with 10.8888888888889



Expand the summation (replace each x%5Bi%5D with the respective number)




Subtract the terms in the parenthesis



Square each term



Add up all of the terms

sqrt%28%281%2F9%2926.888889%29

Multiply

sqrt%282.98765433333333%29

Take the square root

1.7284832464717

So the standard deviation is 1.7284832464717


Since and is the variance, this means that the variance is: