Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On

 Tutoring Home For Students Tools for Tutors Our Tutors Register Recently Solved
 By Tutor
| By Problem Number |

Tutor:

Recent problems solved by 'jim_thompson5910'

Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569 , 12570..12599 , 12600..12629 , 12630..12659 , 12660..12689 , 12690..12719 , 12720..12749 , 12750..12779 , 12780..12809 , 12810..12839 , 12840..12869 , 12870..12899 , 12900..12929 , 12930..12959 , 12960..12989 , 12990..13019 , 13020..13049 , 13050..13079 , 13080..13109 , 13110..13139 , 13140..13169 , 13170..13199 , 13200..13229 , 13230..13259 , 13260..13289 , 13290..13319 , 13320..13349 , 13350..13379 , 13380..13409 , 13410..13439 , 13440..13469 , 13470..13499 , 13500..13529 , 13530..13559 , 13560..13589 , 13590..13619 , 13620..13649 , 13650..13679 , 13680..13709 , 13710..13739 , 13740..13769 , 13770..13799 , 13800..13829 , 13830..13859 , 13860..13889 , 13890..13919 , 13920..13949 , 13950..13979 , 13980..14009 , 14010..14039 , 14040..14069 , 14070..14099 , 14100..14129 , 14130..14159 , 14160..14189 , 14190..14219 , 14220..14249 , 14250..14279 , 14280..14309 , 14310..14339 , 14340..14369 , 14370..14399 , 14400..14429 , 14430..14459 , 14460..14489 , 14490..14519 , 14520..14549 , 14550..14579 , 14580..14609 , 14610..14639 , 14640..14669 , 14670..14699 , 14700..14729 , 14730..14759 , 14760..14789 , 14790..14819 , 14820..14849 , 14850..14879 , 14880..14909 , 14910..14939 , 14940..14969 , 14970..14999 , 15000..15029 , 15030..15059 , 15060..15089 , 15090..15119 , 15120..15149 , 15150..15179 , 15180..15209 , 15210..15239 , 15240..15269 , 15270..15299 , 15300..15329 , 15330..15359 , 15360..15389 , 15390..15419 , 15420..15449 , 15450..15479 , 15480..15509 , 15510..15539 , 15540..15569 , 15570..15599 , 15600..15629 , 15630..15659 , 15660..15689 , 15690..15719 , 15720..15749 , 15750..15779 , 15780..15809 , 15810..15839 , 15840..15869 , 15870..15899 , 15900..15929 , 15930..15959 , 15960..15989 , 15990..16019 , 16020..16049 , 16050..16079 , 16080..16109 , 16110..16139 , 16140..16169 , 16170..16199 , 16200..16229 , 16230..16259 , 16260..16289 , 16290..16319 , 16320..16349 , 16350..16379 , 16380..16409 , 16410..16439 , 16440..16469 , 16470..16499 , 16500..16529 , 16530..16559 , 16560..16589 , 16590..16619 , 16620..16649 , 16650..16679 , 16680..16709 , 16710..16739 , 16740..16769 , 16770..16799 , 16800..16829 , 16830..16859 , 16860..16889 , 16890..16919 , 16920..16949 , 16950..16979 , 16980..17009 , 17010..17039 , 17040..17069 , 17070..17099 , 17100..17129 , 17130..17159 , 17160..17189 , 17190..17219 , 17220..17249 , 17250..17279 , 17280..17309 , 17310..17339 , 17340..17369 , 17370..17399 , 17400..17429 , 17430..17459 , 17460..17489 , 17490..17519 , 17520..17549 , 17550..17579 , 17580..17609 , 17610..17639 , 17640..17669 , 17670..17699 , 17700..17729 , 17730..17759 , 17760..17789 , 17790..17819 , 17820..17849 , 17850..17879 , 17880..17909 , 17910..17939 , 17940..17969 , 17970..17999 , 18000..18029 , 18030..18059 , 18060..18089 , 18090..18119 , 18120..18149 , 18150..18179 , 18180..18209 , 18210..18239 , 18240..18269 , 18270..18299 , 18300..18329 , 18330..18359 , 18360..18389 , 18390..18419 , 18420..18449 , 18450..18479 , 18480..18509 , 18510..18539 , 18540..18569 , 18570..18599 , 18600..18629 , 18630..18659 , 18660..18689 , 18690..18719 , 18720..18749 , 18750..18779 , 18780..18809 , 18810..18839 , 18840..18869 , 18870..18899 , 18900..18929 , 18930..18959 , 18960..18989 , 18990..19019 , 19020..19049 , 19050..19079 , 19080..19109 , 19110..19139 , 19140..19169 , 19170..19199 , 19200..19229 , 19230..19259 , 19260..19289 , 19290..19319 , 19320..19349 , 19350..19379 , 19380..19409 , 19410..19439 , 19440..19469 , 19470..19499 , 19500..19529 , 19530..19559 , 19560..19589 , 19590..19619 , 19620..19649 , 19650..19679 , 19680..19709 , 19710..19739 , 19740..19769 , 19770..19799 , 19800..19829 , 19830..19859 , 19860..19889 , 19890..19919 , 19920..19949 , 19950..19979 , 19980..20009 , 20010..20039 , 20040..20069 , 20070..20099 , 20100..20129 , 20130..20159 , 20160..20189 , 20190..20219 , 20220..20249 , 20250..20279 , 20280..20309 , 20310..20339 , 20340..20369 , 20370..20399 , 20400..20429 , 20430..20459 , 20460..20489 , 20490..20519 , 20520..20549 , 20550..20579 , 20580..20609 , 20610..20639 , 20640..20669 , 20670..20699 , 20700..20729 , 20730..20759 , 20760..20789 , 20790..20819 , 20820..20849 , 20850..20879 , 20880..20909 , 20910..20939 , 20940..20969 , 20970..20999 , 21000..21029 , 21030..21059 , 21060..21089 , 21090..21119 , 21120..21149 , 21150..21179 , 21180..21209 , 21210..21239 , 21240..21269 , 21270..21299 , 21300..21329 , 21330..21359 , 21360..21389 , 21390..21419 , 21420..21449 , 21450..21479 , 21480..21509 , 21510..21539 , 21540..21569 , 21570..21599 , 21600..21629 , 21630..21659 , 21660..21689 , 21690..21719 , 21720..21749 , 21750..21779 , 21780..21809 , 21810..21839 , 21840..21869 , 21870..21899 , 21900..21929 , 21930..21959 , 21960..21989 , 21990..22019 , 22020..22049 , 22050..22079 , 22080..22109 , 22110..22139 , 22140..22169 , 22170..22199 , 22200..22229 , 22230..22259 , 22260..22289 , 22290..22319 , 22320..22349 , 22350..22379 , 22380..22409 , 22410..22439 , 22440..22469 , 22470..22499 , 22500..22529 , 22530..22559 , 22560..22589 , 22590..22619 , 22620..22649 , 22650..22679 , 22680..22709 , 22710..22739 , 22740..22769 , 22770..22799 , 22800..22829 , 22830..22859 , 22860..22889 , 22890..22919 , 22920..22949 , 22950..22979 , 22980..23009 , 23010..23039 , 23040..23069 , 23070..23099 , 23100..23129 , 23130..23159 , 23160..23189 , 23190..23219 , 23220..23249 , 23250..23279 , 23280..23309 , 23310..23339 , 23340..23369 , 23370..23399 , 23400..23429 , 23430..23459 , 23460..23489 , 23490..23519 , 23520..23549 , 23550..23579 , 23580..23609 , 23610..23639 , 23640..23669 , 23670..23699 , 23700..23729 , 23730..23759 , 23760..23789 , 23790..23819 , 23820..23849 , 23850..23879 , 23880..23909 , 23910..23939 , 23940..23969 , 23970..23999 , 24000..24029 , 24030..24059 , 24060..24089 , 24090..24119 , 24120..24149 , 24150..24179 , 24180..24209 , 24210..24239 , 24240..24269 , 24270..24299 , 24300..24329 , 24330..24359 , 24360..24389 , 24390..24419 , 24420..24449 , 24450..24479 , 24480..24509 , 24510..24539 , 24540..24569 , 24570..24599 , 24600..24629 , 24630..24659 , 24660..24689 , 24690..24719 , 24720..24749 , 24750..24779 , 24780..24809 , 24810..24839 , 24840..24869 , 24870..24899 , 24900..24929 , 24930..24959 , 24960..24989 , 24990..25019 , 25020..25049 , 25050..25079 , 25080..25109 , 25110..25139 , 25140..25169 , 25170..25199 , 25200..25229 , 25230..25259 , 25260..25289 , 25290..25319 , 25320..25349 , 25350..25379 , 25380..25409 , 25410..25439 , 25440..25469 , 25470..25499 , 25500..25529 , 25530..25559 , 25560..25589 , 25590..25619 , 25620..25649 , 25650..25679 , 25680..25709 , 25710..25739 , 25740..25769 , 25770..25799 , 25800..25829 , 25830..25859 , 25860..25889 , 25890..25919 , 25920..25949 , 25950..25979 , 25980..26009 , 26010..26039 , 26040..26069 , 26070..26099 , 26100..26129 , 26130..26159 , 26160..26189 , 26190..26219 , 26220..26249 , 26250..26279 , 26280..26309 , 26310..26339 , 26340..26369 , 26370..26399 , 26400..26429 , 26430..26459 , 26460..26489 , 26490..26519 , 26520..26549 , 26550..26579 , 26580..26609 , 26610..26639 , 26640..26669 , 26670..26699 , 26700..26729 , 26730..26759 , 26760..26789 , 26790..26819 , 26820..26849 , 26850..26879 , 26880..26909 , 26910..26939 , 26940..26969 , 26970..26999 , 27000..27029 , 27030..27059 , 27060..27089 , 27090..27119 , 27120..27149 , 27150..27179 , 27180..27209 , 27210..27239 , 27240..27269 , 27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499 , 28500..28529 , 28530..28559 , 28560..28589 , 28590..28619 , 28620..28649 , 28650..28679 , 28680..28709 , 28710..28739 , 28740..28769 , 28770..28799 , 28800..28829 , 28830..28859 , 28860..28889 , 28890..28919 , 28920..28949 , 28950..28979 , 28980..29009 , 29010..29039 , 29040..29069 , 29070..29099 , 29100..29129 , 29130..29159 , 29160..29189 , 29190..29219 , 29220..29249 , 29250..29279 , 29280..29309 , 29310..29339 , 29340..29369 , 29370..29399 , 29400..29429 , 29430..29459 , 29460..29489 , 29490..29519 , 29520..29549 , 29550..29579 , 29580..29609, >>Next

 Equations/213735: solve algebraically, using one variable. find three consecutive intergers such that three times the sum of the first two intergers is three less than seven times the third. 1 solutions Answer 161462 by jim_thompson5910(29613)   on 2009-09-15 01:01:17 (Show Source): You can put this solution on YOUR website!Recall that consecutive integers are of the form: x, x+1, x+2, x+3, etc... The statement: "three times the sum of the first two intergers is three less than seven times the third" translates to Start with the given equation. Remove unneeded parenthesis. Combine like terms. Distribute. Combine like terms on the right side. Subtract from both sides. Subtract from both sides. Combine like terms on the left side. Combine like terms on the right side. Divide both sides by to isolate . Reduce. ---------------------------------------------------------------------- Answer: So the solution is This means that the three numbers are -8, -7, and -6
 Expressions-with-variables/213734: (-3)^2-4^3-2(-3)(-1)^21 solutions Answer 161461 by jim_thompson5910(29613)   on 2009-09-15 00:56:33 (Show Source): You can put this solution on YOUR website! Start with the given expression. Cube 4 to get 64 Square -3 to get 9 Square -1 to get 1 Multiply Combine like terms. So
 Equations/213733: 1 solutions Answer 161460 by jim_thompson5910(29613)   on 2009-09-15 00:39:49 (Show Source): You can put this solution on YOUR website! Start with the given equation. Multiply both sides by 5. Multiply So the solution is
 Exponential-and-logarithmic-functions/213724: Recall that the formula for compounding interest is A = P(1+ r)t where A is the total accumulated amount in an account with principal P compounded at a annual interest rate r once per year for t years. a. How many years will it take for a principal of P =1000 to reach an amount of A = 5000 when compounded once a year at an annual interest rate of 6%? b. If the interest rate is doubled to 12%, what will the number of years be for the principal of P =1000 to reach an amount of A = 5000? 1 solutions Answer 161453 by jim_thompson5910(29613)   on 2009-09-14 23:28:07 (Show Source): You can put this solution on YOUR website!a) Start with the given equation. Plug in , , and Add Divide both sides by 1000. Divide Take the log of both sides. Pull down the exponent. Evaluate the left side Evaluate the log on the right side Divide both sides by 0.02531. Divide and rearrange the equation. So it will take about 27.61 years (a little over 27 and a half years) for $1,000 to become$5,000 at an interest rate of 6% ------------------------------------ b) Start with the given equation. Plug in , , and Add Divide both sides by 1000. Divide Take the log of both sides. Pull down the exponent. Evaluate the left side Evaluate the log on the right side Divide both sides by 0.04922. Divide and rearrange the equation. So it will take about 14.2 years (a little over 14 years) for $1,000 to become$5,000 at an interest rate of 12%
 Human-and-algebraic-language/213503: In isosceles trapezoid ABCD, the longer base, AB, is one and one half times as long as the short base, CD. The other two sides, AD and BC, are both 13 cm long. A. If the perimeter is 76 cm, find the lengths of AB and CD. this is what i did: AD = 13 BC = 13 CD = x AB = x* 1 1/2 the equation i got : 13+13+x+1 1/2*x=76 but when i follow through with the equation i can't get 76, help please, i have no idea what i'm doing wrong.1 solutions Answer 161310 by jim_thompson5910(29613)   on 2009-09-14 15:57:31 (Show Source): You can put this solution on YOUR website!Note: the mixed fraction is equivalent to the improper fraction . Ie. . So the equation becomes If you multiply EVERY term by the LCD 2, you'll clear out the fractions to get . Now you have a much simpler equation to solve. I'll let you do that.
 Permutations/213492: Can you give me a formula to work out the amount of squares within a square eg. a chess board 1 solutions Answer 161292 by jim_thompson5910(29613)   on 2009-09-14 14:28:00 (Show Source): You can put this solution on YOUR website!If you're asking just about the number of 1x1 squares, then the last post is correct. If you're asking about larger squares (2x2, 3x3, etc..), then there's more to this problem. Check out this page to see the answer.
 Functions/213488: I am still unsure when it comes to functions. I have a question that is as follows: Is f(x) = x^2 + 2x - 3 a one-to-one function? Explain your answer. When figuring out the problem if f(a) = f(b) then my answer would be no as a^2 + 2a - 3 = b^2 + 2b -3 does not factor down to a = b. Am I figuring this correctly? Thank you = Lori1 solutions Answer 161291 by jim_thompson5910(29613)   on 2009-09-14 14:15:01 (Show Source): You can put this solution on YOUR website!You're on the right track. A function is one-to-one if only means . In other words, if two outputs of a function are equal, then the inputs must be equal for the function to be one-to-one. So if you think that this function is NOT one-to-one, then simply pick a counter-example to prove this claim false. Let's say that . Plugging this into gets us . Now solve for 'x' to get or So if we plug in either 0 or -2 into f(x), we'll get -3 as an output. Ie. . Since , this means that the function is NOT one-to-one. So you are correct.
 Distributive-associative-commutative-properties/213060: This question is from textbook Prentice PRE-ALGEBRA Trying to simplify this equation and Justify each step. w+3w+4(5+w-3w) Here is what I have tried w+3w+4(5+w-3w) w+3w+4(2w) w+3w+8w w+11w1 solutions Answer 160950 by jim_thompson5910(29613)   on 2009-09-12 20:03:03 (Show Source): You can put this solution on YOUR website! Start with the given expression. Combine like terms. Distribute. Multiply Combine like terms. So
 Graphs/212993: If an object on Earth is projected upward with an initial velocity of 32 feet per second, then its height after (t) seconds is given by: h(t)=32t-16t^2. Find the maximum height attained by the object and the number of seconds it takes to hit the ground. I began like this: h(t)=-16t^2 + 32t -32/2(-16)=-32/32=1 -16(1)^2 + 32(1) -16+32=16 and now I am stuck!1 solutions Answer 160900 by jim_thompson5910(29613)   on 2009-09-12 14:52:08 (Show Source): You can put this solution on YOUR website!You're pretty much done. What you just did was find the vertex of . The vertex is (1,16) and at the vertex is the max value of h(t) (ie the height). So the max height is 16 ft (which occurs at t=1 second).
 Linear-equations/212930: How do I find the equation of the line which passes through the points (-3,2) and (3,-2)1 solutions Answer 160891 by jim_thompson5910(29613)   on 2009-09-12 13:54:24 (Show Source): You can put this solution on YOUR website!First let's find the slope of the line through the points and Note: is the first point . So this means that and . Also, is the second point . So this means that and . Start with the slope formula. Plug in , , , and Subtract from to get Subtract from to get Reduce So the slope of the line that goes through the points and is Now let's use the point slope formula: Start with the point slope formula Plug in , , and Rewrite as Distribute Multiply Add 2 to both sides. Combine like terms. Simplify So the equation that goes through the points and is Notice how the graph of goes through the points and . So this visually verifies our answer. Graph of through the points and
Polynomials-and-rational-expressions/212774: need help to find the slope of the line containing the points
p1(5,-3) and p2(3,-1)
1 solutions

Answer 160691 by jim_thompson5910(29613)   on 2009-09-11 12:17:55 (Show Source):
You can put this solution on YOUR website!
 Solved by pluggable solver: Finding the slope Slope of the line through the points (5, -3) and (3, -1) Answer: Slope is

Linear-equations/212770: need help with the slope of the line containing points
p1(-1,2) and p2(3,3)
1 solutions

Answer 160690 by jim_thompson5910(29613)   on 2009-09-11 12:17:00 (Show Source):
You can put this solution on YOUR website!
 Solved by pluggable solver: Finding the slope Slope of the line through the points (-1, 2) and (3, 3) Answer: Slope is

 Graphs/212735: Hi there. I need to see if I am on the right track. I need to graph the following y = -2 abs(x+1)-4. I need to construc a sequence of five graphs to get from one to another. I am setting up my 5 graphs as follows: (1) y = abs(x) (2) y = abs(x+1) (3) y = -2 abs (x+1) (4) y = 2 abs (x+1) and (5) y = -2 abs (x+1)-4. Am I on the right track with the above equations? Thanks - Lori1 solutions Answer 160671 by jim_thompson5910(29613)   on 2009-09-11 11:05:06 (Show Source): You can put this solution on YOUR website!To graph , simply follow the given steps below: Step 1) Graph Graph of Note: the graph of is simply comprised of the lines and (just don't graph the portion that lies below the x-axis). Step 2) Shift 1 unit to the left to get Graph of (red) and (green) Step 3) Vertically stretch by a factor of 2 to get Graph of (red) and (green) Step 4) Reflect over the x axis to get Graph of (red) and (green) Step 5) Shift the entire graph of down 4 units to get Graph of (red) and (green) So the graph of is Graph of
 absolute-value/212385: This question is from textbook precalculus explain why the graphs of y=x and y=(root x)^2 are not the same1 solutions Answer 160400 by jim_thompson5910(29613)   on 2009-09-10 00:13:06 (Show Source): You can put this solution on YOUR website!Let's say that 'x' can be negative. So let's plug in The first equation is simply (after plugging in ) which is a real number; however, the second equation does not produce a real number. So the two are not equal when . They are not equal when . If we said that , then would be true.
 Radicals/212370: I’m really confusing with this factoring, Can anyone please help me with step by step? Thank you very much! Simplify by factoring. 1.4*sqrt(405x^8y^10)=? 2.5*sqrt(64x^12y^15)=? 1 solutions Answer 160399 by jim_thompson5910(29613)   on 2009-09-10 00:10:04 (Show Source): You can put this solution on YOUR website!I'll do the first one to get you going in the right direction. # 1 Start with the given expression. Break up the square root using the identity Factor 405 into 81*5 Rewrite 81 as Rewrite as Rewrite as Break up the first square root (using that same identity) Take the square root of to get 9 (notice how the squares and the square roots 'undo' each other). Take the square root of to get . Take the square root of to get . Rearrange the terms. So where every variable is nonnegative.
 Square-cubic-other-roots/212356: I am so confused with this problem. Express as a sum, difference, and product of logarithims, without using exponents. 3 log b √ x^8/y^2z^5 I could not get it to show the way the problem does. It reads log (small b below) square root with 3 above the square root symbol. Inside the square root symbol it has x^8 over y^2z^5. 1 solutions Answer 160385 by jim_thompson5910(29613)   on 2009-09-09 22:27:11 (Show Source): You can put this solution on YOUR website! ... Start with the given expression. ... Convert to rational exponent notation. ... Pull down the exponent using the identity ... Break up the log using the identity ... Break up the second log using the identity Distribute ... Pull down the exponents using the identity ... Distribute So assuming that every variable is positive.
 Quadratic_Equations/212341: given f(x) = ax^2 + bx + 5. Find a and b such that f(x + 1) - f(x) = 8x + 31 solutions Answer 160377 by jim_thompson5910(29613)   on 2009-09-09 22:12:59 (Show Source): You can put this solution on YOUR website!Since , this means that . Or simply ---------------------------------------------- Start with the given equation. Plug in and Distribute Combine like terms. So we then get that which means or Also, we find that . Plug in to get and solve to get
 Angles/212281: I have to figure out the measure of the angles. The problem is "find the measure of angle T if the measure of angle T is 20 more than four times its supplement" I know the answer is 148 but I can't figure out how to get to that. I tried solving it by setting up the equation 4t+20=180 but I got 40. And I just really can't figure out how to so this. Please help!!1 solutions Answer 160322 by jim_thompson5910(29613)   on 2009-09-09 19:39:32 (Show Source): You can put this solution on YOUR website!Let S = measure of supplement So by definition (since supplemental angles add to 180 degrees). Also, since "the measure of angle T is 20 more than four times its supplement", this means Start with the first equation. Plug in Combine like terms on the left side. Subtract from both sides. Combine like terms on the right side. Divide both sides by to isolate . Reduce. ---------------------------------------------------------------------- Answer: So the solution is This means that the supplemental angle is 32 degrees while angle T is degrees.
 Radicals/212277: 2 SQRT over 3 * 6 SQRT over 6 And then you get 12 outside the radical, cause 2 * 6 = 12 But what do you get inside.1 solutions Answer 160321 by jim_thompson5910(29613)   on 2009-09-09 19:37:51 (Show Source): You can put this solution on YOUR website! Start with the given expression. Group like terms. Multiply 2 and 6 to get 12 Combine the roots using the identity Multiply Factor 18 into 9*2 Break up the root using the identity Take the square root of 9 to get 3. Multiply. So
 Radicals/212275: 2 SQRT over6^2 + 6 SQRT over 2^2 = c^2 My friend said that this was the answer.. 12 + 12 = c^2 c=SQRT over 24 But I don't know where she got it or if its right. I'm really not good with Square roots.1 solutions Answer 160320 by jim_thompson5910(29613)   on 2009-09-09 19:34:27 (Show Source): You can put this solution on YOUR website!Is the problem ??? Start with the given equation. Evaluate the square root of to get 6. Evaluate the square root of to get 2. Multiply Combine like terms. Rearrange the equation. Take the square root of both sides. or Break up the 'plus/minus' or Factor 24 to get 4*6 or Break up the square root. or Take the square root of 4 to get 2. So the solutions are or
 sets-and-operations/212276: using only 3 nines, create an equation that equals 12. you can use addition, subtraction, multiplying, dividing, and square roots 1 solutions Answer 160319 by jim_thompson5910(29613)   on 2009-09-09 19:28:45 (Show Source): You can put this solution on YOUR website!Here's one way to do it:
 Angles/212249: find the measure of angle T if the measure of angle T is 20 more than four times its supplement.1 solutions Answer 160302 by jim_thompson5910(29613)   on 2009-09-09 18:21:30 (Show Source): You can put this solution on YOUR website!Let S = measure of supplement So by definition (since supplemental angles add to 180 degrees). Also, since "the measure of angle T is 20 more than four times its supplement", this means Start with the first equation. Plug in Combine like terms on the left side. Subtract from both sides. Combine like terms on the right side. Divide both sides by to isolate . Reduce. ---------------------------------------------------------------------- Answer: So the solution is This means that the supplemental angle is 32 degrees while angle T is degrees.
 sets-and-operations/212248: Using only 3 nines and no other numbers, create an equation that equals 4. You may use addition, subtraction, multiplying, dividing, and square roots.1 solutions Answer 160298 by jim_thompson5910(29613)   on 2009-09-09 18:17:49 (Show Source): You can put this solution on YOUR website!Here's one equation:
 Linear-equations/211922: -5(2x-1)= 3(x+4)1 solutions Answer 160099 by jim_thompson5910(29613)   on 2009-09-08 17:17:15 (Show Source): You can put this solution on YOUR website! Start with the given equation. Distribute. Subtract from both sides. Subtract from both sides. Combine like terms on the left side. Combine like terms on the right side. Divide both sides by to isolate . Reduce. ---------------------------------------------------------------------- Answer: So the solution is which approximates to .
 absolute-value/211857: Please could you help find the value of x in the following equation: 2(x+1)=3x Many thanks1 solutions Answer 160056 by jim_thompson5910(29613)   on 2009-09-08 13:47:44 (Show Source): You can put this solution on YOUR website! Start with the given equation Distribute Subtract 2x from both sides. Combine like terms. Rearrange the equation So the solution is
Matrices-and-determiminant/211775: find the value of
|5...3..-2|
|1...0...4|
|4...1...2|
1 solutions

Answer 160048 by jim_thompson5910(29613)   on 2009-09-08 13:17:26 (Show Source):
You can put this solution on YOUR website!
 Solved by pluggable solver: Finding the Determinant of a 3x3 Matrix If you have the general 3x3 matrix:the determinant is: Which further breaks down to:Note: , and are determinants themselves. If you need help finding the determinant of 2x2 matrices (which is required to find the determinant of 3x3 matrices), check out this solver--------------------------------------------------------------From the matrix , we can see that , , , , , , , , and Start with the general 3x3 determinant. Plug in the given values (see above) Multiply Subtract Multiply Combine like terms.======================================================================Answer:So , which means that the determinant of the matrix is

 Trigonometry-basics/211815: If tan x = .88, what is cot x?1 solutions Answer 160047 by jim_thompson5910(29613)   on 2009-09-08 13:15:14 (Show Source): You can put this solution on YOUR website!Since , this means that (where the '36' repeats)
1 solutions

Answer 160046 by jim_thompson5910(29613)   on 2009-09-08 13:12:01 (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .

Now multiply the first coefficient by the last term to get .

Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?

To find these two numbers, we need to list all of the factors of (the previous product).

Factors of :

1,2,4,7,8,14,16,28,56,112

-1,-2,-4,-7,-8,-14,-16,-28,-56,-112

Note: list the negative of each factor. This will allow us to find all possible combinations.

These factors pair up and multiply to .

1*112 = 112
2*56 = 112
4*28 = 112
7*16 = 112
8*14 = 112
(-1)*(-112) = 112
(-2)*(-56) = 112
(-4)*(-28) = 112
(-7)*(-16) = 112
(-8)*(-14) = 112

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :

First NumberSecond NumberSum
11121+112=113
2562+56=58
4284+28=32
7167+16=23
8148+14=22
-1-112-1+(-112)=-113
-2-56-2+(-56)=-58
-4-28-4+(-28)=-32
-7-16-7+(-16)=-23
-8-14-8+(-14)=-22

From the table, we can see that there are no pairs of numbers which add to . So cannot be factored.

===============================================================

So doesn't factor at all (over the rational numbers).

So is prime.

So make sure that you have the correct problem.