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Expressions-with-variables/200968: please help with step by step 5x^4+2x^3 over 2x^4+3x^3 multiply by 2x^3+x^2-3x over 5x^2-3x-2
1 solutions

Answer 151206 by jim_thompson5910(28476) About Me  on 2009-06-23 21:57:52 (Show Source):
You can put this solution on YOUR website!

Start with the given expression.


Factor 5x%5E4%2B2x%5E3 to get x%5E3%285x%2B2%29.


Factor 2x%5E4%2B3x%5E3 to get x%5E3%282x%2B3%29.


Factor 2x%5E3%2Bx%5E2-3x to get x%282x%2B3%29%28x-1%29.


Factor 5x%5E2-3x-2 to get %285x%2B2%29%28x-1%29.


Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


x Simplify.


So simplifies to x.


In other words,


Expressions-with-variables/200969: please help with step by step 5x^2-125 over x^3+5x^2 multiply 6x^2+2x over 5x-25
1 solutions

Answer 151205 by jim_thompson5910(28476) About Me  on 2009-06-23 21:54:05 (Show Source):
You can put this solution on YOUR website!

%28%285x%5E2-125%29%2F%28x%5E3%2B5x%5E2%29%29%28%286x%5E2%2B2x%29%2F%285x-25%29%29 Start with the given expression.


Factor 5x%5E2-125 to get 5%28x-5%29%28x%2B5%29.


Factor x%5E3%2B5x%5E2 to get x%2Ax%28x%2B5%29.


Factor 6x%5E2%2B2x to get 2x%283x%2B1%29.


Factor 5x-25 to get 5%28x-5%29.


%285%2A2x%2A%28x-5%29%28x%2B5%29%283x%2B1%29%29%2F%285x%2Ax%28x%2B5%29%28x-5%29%29 Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


%282%283x%2B1%29%29%2Fx Simplify.


%286x%2B2%29%2Fx Distribute


So %28%285x%5E2-125%29%2F%28x%5E3%2B5x%5E2%29%29%28%286x%5E2%2B2x%29%2F%285x-25%29%29 simplifies to %286x%2B2%29%2Fx.


In other words,


Polynomials-and-rational-expressions/200970: please help with step by step 21x^2-49x-42 over 4x^2-28x+48 divided by 21x+14 over 8x^2-32x
1 solutions

Answer 151203 by jim_thompson5910(28476) About Me  on 2009-06-23 21:49:24 (Show Source):
You can put this solution on YOUR website!
%28%2821x%5E2-49x-42%29%2F%284x%5E2-28x%2B48%29%29%2F%28%2821x%2B14%29%2F%288x%5E2-32x%29%29 Start with the given expression.


%28%2821x%5E2-49x-42%29%2F%284x%5E2-28x%2B48%29%29%28%288x%5E2-32x%29%2F%2821x%2B14%29%29 Multiply the first fraction %2821x%5E2-49x-42%29%2F%284x%5E2-28x%2B48%29 by the reciprocal of the second fraction %2821x%2B14%29%2F%288x%5E2-32x%29.


Factor 21x%5E2-49x-42 to get 7%283x%2B2%29%28x-3%29.


Factor 4x%5E2-28x%2B48 to get 4%28x-3%29%28x-4%29.


Factor 8x%5E2-32x to get 4%2A2x%28x-4%29.


Factor 21x%2B14 to get 7%283x%2B2%29.


%287%2A4%2A2x%283x%2B2%29%28x-3%29%28x-4%29%29%2F%284%2A7%28x-3%29%28x-4%29%283x%2B2%29%29 Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


2x Simplify.



So %28%2821x%5E2-49x-42%29%2F%284x%5E2-28x%2B48%29%29%2F%28%2821x%2B14%29%2F%288x%5E2-32x%29%29 simplifies to 2x.


In other words,


Quadratic_Equations/200964: This question is from textbook Beginning Algebra
solve using the quadratic formula
9x -2 = 3x^2
1 solutions

Answer 151192 by jim_thompson5910(28476) About Me  on 2009-06-23 20:59:14 (Show Source):
You can put this solution on YOUR website!
9x+-2+=+3x%5E2 Start with the given equation.


0+=+3x%5E2-9x%2B2 Get everything to one side


Notice that the quadratic 3x%5E2-9x%2B2 is in the form of Ax%5E2%2BBx%2BC where A=3, B=-9, and C=2


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-9%29+%2B-+sqrt%28+%28-9%29%5E2-4%283%29%282%29+%29%29%2F%282%283%29%29 Plug in A=3, B=-9, and C=2


x+=+%289+%2B-+sqrt%28+%28-9%29%5E2-4%283%29%282%29+%29%29%2F%282%283%29%29 Negate -9 to get 9.


x+=+%289+%2B-+sqrt%28+81-4%283%29%282%29+%29%29%2F%282%283%29%29 Square -9 to get 81.


x+=+%289+%2B-+sqrt%28+81-24+%29%29%2F%282%283%29%29 Multiply 4%283%29%282%29 to get 24


x+=+%289+%2B-+sqrt%28+57+%29%29%2F%282%283%29%29 Subtract 24 from 81 to get 57


x+=+%289+%2B-+sqrt%28+57+%29%29%2F%286%29 Multiply 2 and 3 to get 6.


x+=+%289%2Bsqrt%2857%29%29%2F%286%29 or x+=+%289-sqrt%2857%29%29%2F%286%29 Break up the expression.


So the solutions are x+=+%289%2Bsqrt%2857%29%29%2F%286%29 or x+=+%289-sqrt%2857%29%29%2F%286%29


which approximate to x=2.758 or x=0.242


Square-cubic-other-roots/200951: Simplify
sqrt 12c^6

1 solutions

Answer 151179 by jim_thompson5910(28476) About Me  on 2009-06-23 17:58:51 (Show Source):
You can put this solution on YOUR website!

sqrt%2812%2Ac%5E6%29 Start with the given expression.


sqrt%284%2A3%2Ac%5E6%29 Factor 12 into 4%2A3


sqrt%284%2A3%2Ac%5E2%2Ac%5E2%2Ac%5E2%29 Factor c%5E6 into c%5E2%2Ac%5E2%2Ac%5E2


sqrt%284%29%2Asqrt%283%29%2Asqrt%28c%5E2%29%2Asqrt%28c%5E2%29%2Asqrt%28c%5E2%29 Break up the square root using the identity sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29.


2%2Asqrt%283%29%2Asqrt%28c%5E2%29%2Asqrt%28c%5E2%29%2Asqrt%28c%5E2%29 Take the square root of 4 to get 2.


2%2Asqrt%283%29%2Ac%2Ac%2Ac Take the square root of c%5E2 to get c.


2c%5E3%2Asqrt%283%29 Rearrange and combine the terms.

==================================================

Answer:


So sqrt%2812%2Ac%5E6%29 simplifies to 2c%5E3%2Asqrt%283%29


In other words, sqrt%2812%2Ac%5E6%29=2c%5E3%2Asqrt%283%29 where c%3E=0.


Functions/200946: The following function computes the cost, C (in millions of dollars), of implementing a city recycling project when x percent of the citizens participate. C(X)=1.4x/100-x
a)Using the model, find the cost if 60% of the citizens participate.
b)Using the model, determine the percentage of participation that can be expected if $4 million is spent on this recycling project. Set up an equation and solve algebraically. Round to the nearest whole percent.

1 solutions

Answer 151174 by jim_thompson5910(28476) About Me  on 2009-06-23 16:56:55 (Show Source):


Average/200943: What is the average (arithmetic mean) of 8, 7, 7, 5, 3, 2, and 2?
A. 3 4/7
B. 4 5/6
C. 4 6/7
D. 5
E. 6 4/5

Please show me how to this step by step.Ireally need to know.Thank you so much!

1 solutions

Answer 151168 by jim_thompson5910(28476) About Me  on 2009-06-23 16:29:47 (Show Source):
You can put this solution on YOUR website!
Simply add up the numbers and divide that sum by 7 (since there are 7 values)

Mean=%282%2B2%2B3%2B5%2B7%2B7%2B8%29%2F7=34%2F7=28%2F7%2B6%2F7=4%2B6%2F7=4%266%2F7


So the answer is C) 4%266%2F7


Note: normally the mean is represented in decimal form.




Polynomials-and-rational-expressions/200942: x/x+1 + 5/x = 1/x^2+x
1 solutions

Answer 151165 by jim_thompson5910(28476) About Me  on 2009-06-23 15:39:37 (Show Source):
You can put this solution on YOUR website!
x%2F%28x%2B1%29%2B5%2Fx=1%2F%28x%5E2%2Bx%29 Start with the given equation.


x%2F%28x%2B1%29%2B5%2Fx=1%2F%28x%28x%2B1%29%29 Factor the last denominator


Multiply EVERY term by the LCD x%28x%2B1%29 to clear out the fractions.


x%2Ax%2B5%28x%2B1%29=1 Simplify


x%2Ax%2B5%2Ax%2B5%2A1=1 Distribute


x%5E2%2B5x%2B5=1 Multiply


x%5E2%2B5x%2B5-1=0 Subtract 1 from both sides.


x%5E2%2B5x%2B4=0 Combine like terms.


Notice that the quadratic x%5E2%2B5x%2B4 is in the form of Ax%5E2%2BBx%2BC where A=1, B=5, and C=4


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%285%29+%2B-+sqrt%28+%285%29%5E2-4%281%29%284%29+%29%29%2F%282%281%29%29 Plug in A=1, B=5, and C=4


x+=+%28-5+%2B-+sqrt%28+25-4%281%29%284%29+%29%29%2F%282%281%29%29 Square 5 to get 25.


x+=+%28-5+%2B-+sqrt%28+25-16+%29%29%2F%282%281%29%29 Multiply 4%281%29%284%29 to get 16


x+=+%28-5+%2B-+sqrt%28+9+%29%29%2F%282%281%29%29 Subtract 16 from 25 to get 9


x+=+%28-5+%2B-+sqrt%28+9+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


x+=+%28-5+%2B-+3%29%2F%282%29 Take the square root of 9 to get 3.


x+=+%28-5+%2B+3%29%2F%282%29 or x+=+%28-5+-+3%29%2F%282%29 Break up the expression.


x+=+%28-2%29%2F%282%29 or x+=++%28-8%29%2F%282%29 Combine like terms.


x+=+-1 or x+=+-4 Simplify.


So the possible solutions are x+=+-1 or x+=+-4


However, recall that x%3C%3E-1, this means that the only solution is x+=+-4

=============================================================

Answer:

So the solution is x+=+-4


Radicals/200938: This is 5 different problems I've been having problems with for a while.
4/sqrt5
4sqrtx^12/24sqrtx^12
15sqrt8x^16/5sqrt2x^4
(3sqrt5)(2sqrt10)
(2sqrtx)(5sqrtx^3)
1 solutions

Answer 151157 by jim_thompson5910(28476) About Me  on 2009-06-23 14:13:34 (Show Source):
You can put this solution on YOUR website!
I'll do the first three to get you going in the right direction.


# 1

4%2Fsqrt%285%29 Start with the given expression.


%284%2Asqrt%285%29%29%2F%28sqrt%285%29%2Asqrt%285%29%29 Multiply both the numerator and denominator by sqrt%285%29


%284%2Asqrt%285%29%29%2F%28sqrt%285%2A5%29%29 Combine the roots.


%284%2Asqrt%285%29%29%2F%28sqrt%2825%29%29 Multiply


%284%2Asqrt%285%29%29%2F5 Take the square root of 25 to get 5



So 4%2Fsqrt%285%29=%284%2Asqrt%285%29%29%2F5





# 2


%284%2Asqrt%28x%5E12%29%29%2F%2824%2Asqrt%28x%5E12%29%29 Start with the given expression.


%284%2Asqrt%28x%5E12%29%29%2F%284%2A6%2Asqrt%28x%5E12%29%29 Factor 24 to get 4*6


%28cross%284%29%2Asqrt%28x%5E12%29%29%2F%28cross%284%29%2A6%2Asqrt%28x%5E12%29%29 Cancel out the common terms.


%28sqrt%28x%5E12%29%29%2F%286%2Asqrt%28x%5E12%29%29 Simplify


sqrt%28%28x%5E12%29%2F%28x%5E12%29%29%2F%286%29 Combine the roots


sqrt%281%29%2F6 Divide


1%2F6 Simplify


So %284%2Asqrt%28x%5E12%29%29%2F%2824%2Asqrt%28x%5E12%29%29=1%2F6 where x%3E0





# 3


%2815%2Asqrt%288x%5E16%29%29%2F%285%2Asqrt%282x%5E4%29%29 Start with the given expression.


%285%2A3%2Asqrt%288x%5E16%29%29%2F%285%2Asqrt%282x%5E4%29%29 Factor 15 into 5*3


%28cross%285%29%2A3%2Asqrt%288x%5E16%29%29%2F%28cross%285%29%2Asqrt%282x%5E4%29%29 Cancel out the common terms.


%283%2Asqrt%288x%5E16%29%29%2F%28sqrt%282x%5E4%29%29 Simplify


3%2Asqrt%28%288x%5E16%29%2F%282x%5E4%29%29 Combine the roots.


3%2Asqrt%28%284%2A2x%5E16%29%2F%282x%5E4%29%29 Factor 8 into 4*2


3%2Asqrt%28%284%2Across%282%29x%5E16%29%2F%28cross%282%29x%5E4%29%29 Cancel out the common terms.


3%2Asqrt%28%284x%5E16%29%2F%28x%5E4%29%29 Simplify


3%2Asqrt%284x%5E%2816-4%29%29 Divide the variable terms by subtracting the exponents.


3%2Asqrt%284x%5E12%29 Subtract


3%2Asqrt%284%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%29 Factor x%5E12 into x%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2%2Ax%5E2 note: there are 6 x%5E2 terms.


Break up the square root using the identity sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29.


Take the square root of 4 to get 2.


3%2A2%2Ax%2Ax%2Ax%2Ax%2Ax%2Ax Take the square root of x%5E2 to get x.


6x%5E6 Multiply.

==================================================

Answer:


So %2815%2Asqrt%288x%5E16%29%29%2F%285%2Asqrt%282x%5E4%29%29 simplifies to 6x%5E6


In other words, %2815%2Asqrt%288x%5E16%29%29%2F%285%2Asqrt%282x%5E4%29%29=6x%5E6 where x%3E0



Edit: The other poster is correct in saying that "x" doesn't need to be non-negative, BUT recall that sqrt%28x%5E2%29=abs%28x%29. If we assume that x%3E=0 (ie it is NOT negative), then sqrt%28x%5E2%29=x which simplifies things greatly. If "x" can be any number, then you must include the absolute value.


Divisibility_and_Prime_Numbers/200927: How many whole numbers between 1 to 200 are divisible by 6 and not by 10 ?
1 solutions

Answer 151156 by jim_thompson5910(28476) About Me  on 2009-06-23 13:49:35 (Show Source):
You can put this solution on YOUR website!
Just list all the multiples of 6 and take off any numbers that are multiples of 10. So here are all the numbers from 1 to 200 that are are divisible by 6 and not by 10:


6, 12, 18, 24, 36, 42, 48, 54, 66, 72, 78, 84, 96, 102, 108, 114, 126, 132, 138, 144, 156, 162, 168, 174, 186, 192, 198


There are 27 numbers here.


Inequalities/200909: Solve:
(5/7)<=(x-5/3)<2



1 solutions

Answer 151155 by jim_thompson5910(28476) About Me  on 2009-06-23 13:32:56 (Show Source):
You can put this solution on YOUR website!
5%2F7%3C=x-5%2F3%3C2 Start with the given compound inequality.


Multiply EVERY term by the LCD 21 to clear out any fractions.


3%285%29%3C=21x-7%285%29%3C21%2A2 Simplify


15%3C=21x-35%3C42 Multiply


15%2B35%3C=21x%3C42%2B35 Add 35 to all sides.


50%3C=21x%3C42%2B35 Combine like terms on the left side.


50%3C=21x%3C77 Combine like terms on the right side.


%2850%29%2F21%3C=x%3C%2877%29%2F21 Divide all sides by 21.


50%2F21%3C=x%3C11%2F3 Reduce.


So the solution is 50%2F21%3C=x%3C11%2F3


Exponential-and-logarithmic-functions/200907: find y' when
y=ln(x+2)/(x^2+1) this problem has the big ( around all)
thanks for help

1 solutions

Answer 151154 by jim_thompson5910(28476) About Me  on 2009-06-23 13:27:30 (Show Source):
You can put this solution on YOUR website!
I'm assuming that the problem is right???


Recall that if , then




In your case, , which means that and


Now derive f and g to get: and



Now plug these functions into the formula to get:





Now multiply every term by the inner LCD x+2 and simplify






you could perform more simplifications, but that would only change how the answer looks.


Linear-equations/200921: This question is from textbook Geometry
given points R (-2,3) and S (5,1) find the slop of every line perpendicular to RS. please show all your work for full credit.
A.Slope of RS
B.Slope of Perendicular lines
1 solutions

Answer 151153 by jim_thompson5910(28476) About Me  on 2009-06-23 13:15:49 (Show Source):
You can put this solution on YOUR website!
A)

Note: is the first point R and is the second point S .


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%281-3%29%2F%285--2%29 Plug in y%5B2%5D=1, y%5B1%5D=3, x%5B2%5D=5, and x%5B1%5D=-2


m=%28-2%29%2F%285--2%29 Subtract 3 from 1 to get -2


m=%28-2%29%2F%287%29 Subtract -2 from 5 to get 7


So the slope of the line that goes through the points R and S is m=-2%2F7


-------------------------------------------------------------

B)

Now simply flip the fraction -2%2F7 to get -7%2F2. Finally, change the sign to get 7%2F2. So the slope of ANY perpendicular line to segment RS is m=7%2F2


Travel_Word_Problems/200936: This question(200898) is in your data base but i am not positive if it is correct. I was told there is a answer. Could somebody else PLEASE look at this problem again and work it to verify if it is correct or wrong. I would really appreciate it..Thanks
Question:
A biker can travel 18 mph with no wind. The same rider can bicycle 8 mi against the wind in the same time it takes to bicycle 12 miles with the wind. What is the speed of the wind?

1 solutions

Answer 151152 by jim_thompson5910(28476) About Me  on 2009-06-23 13:13:16 (Show Source):
You can put this solution on YOUR website!
Let w = speed of the wind (in mph)


First, let's set up the equation involving the trip against the wind:


d=rt Start with the distance-rate-time formula


8=%2818-w%29t Plug in d=8 and r=18-w (the wind slows him down, so you must subtract "w" from 18)


8%2F%2818-w%29=t Divide both sides by 18-w.


t=8%2F%2818-w%29 Rearrange the equation


-----------------------------------


d=rt Go back to the distance-rate-time formula


12=%2818%2Bw%29t Plug in d=12 and r=18%2Bw (the wind speeds him up, so you must add "w" to 18)


12%2F%2818%2Bw%29=t Divide both sides by 18%2Bw.


t=12%2F%2818%2Bw%29 Rearrange the equation

-------------------------------------


Now recall that he "can bicycle 8 mi against the wind in the same time it takes to bicycle 12 miles with the wind". So this means that the times "t" are the same variable. This means that we can plug one equation into another:


t=12%2F%2818%2Bw%29 Start with the given equation.


8%2F%2818-w%29=12%2F%2818%2Bw%29 Plug in t=8%2F%2818-w%29


8%2818%2Bw%29=12%2818-w%29 Cross multiply


144%2B8w=216-12w Distribute.


8w=216-12w-144 Subtract 144 from both sides.


8w%2B12w=216-144 Add 12w to both sides.


20w=216-144 Combine like terms on the left side.


20w=72 Combine like terms on the right side.


w=%2872%29%2F%2820%29 Divide both sides by 20 to isolate w.


w=18%2F5 Reduce.


w=3.6 Divide (either use a calculator or long division)


----------------------------------------------------------------------

Answer:

So the solution is w=3.6 which means that the speed of the wind is 3.6 mph.


Note: if you are expecting a whole number for an answer, I would verify that you have the correct problem written down.


Numbers_Word_Problems/200929: The number 9 can be written as the sum of 9 consecutive integers. What is the product of these 9 integers ?
1 solutions

Answer 151150 by jim_thompson5910(28476) About Me  on 2009-06-23 13:00:44 (Show Source):
You can put this solution on YOUR website!
Let x = first integer


So x+1 is the next integer, x+2 is the next integer after that, etc...


So because "The number 9 can be written as the sum of 9 consecutive integers", this means that


Start with the given equation.


x%2Bx%2B1%2Bx%2B2%2Bx%2B3%2Bx%2B4%2Bx%2B5%2Bx%2B6%2Bx%2B7%2Bx%2B8=9 Remove the parenthesis.


9x%2B36=9 Combine like terms on the left side.


9x=9-36 Subtract 36 from both sides.


9x=-27 Combine like terms on the right side.


x=%28-27%29%2F%289%29 Divide both sides by 9 to isolate x.


x=-3 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x=-3 which means that the first integer is -3


So the 9 consecutive integers are:

-3, -2, -1, 0, 1, 2, 3, 4, 5


If you multiply them together, you'll get 0 (since 0 is being multiplied here).




Radicals/200934: what if the radical expression is not a rational expression, for example what if I had √12 + √108? How would I begin on simplifying it? Afterall, there is no denominator other than 1.

1 solutions

Answer 151149 by jim_thompson5910(28476) About Me  on 2009-06-23 12:54:53 (Show Source):
You can put this solution on YOUR website!

sqrt%2812%29%2Bsqrt%28108%29 Start with the given expression


2%2Asqrt%283%29%2Bsqrt%28108%29 Simplify sqrt%2812%29 to get 2%2Asqrt%283%29. Note: If you need help with simplifying square roots, check out this solver.


2%2Asqrt%283%29%2B6%2Asqrt%283%29 Simplify sqrt%28108%29 to get 6%2Asqrt%283%29.


Since we have the common term sqrt%283%29, we can combine like terms


%282%2B6%29sqrt%283%29 Factor out the GCF sqrt%283%29


8%2Asqrt%283%29 Combine like terms.


So sqrt%2812%29%2Bsqrt%28108%29 simplifies to 8%2Asqrt%283%29.


In other words, sqrt%2812%29%2Bsqrt%28108%29=8%2Asqrt%283%29


You can verify this with a calculator.


Quadratic_Equations/200869: a(a+1)-3(a+1)=a+1
1 solutions

Answer 151109 by jim_thompson5910(28476) About Me  on 2009-06-22 19:34:21 (Show Source):
You can put this solution on YOUR website!
a%28a%2B1%29-3%28a%2B1%29=a%2B1 Start with the given equation.


a%5E2%2Ba-3a-3=a%2B1 Distribute


a%5E2%2Ba-3a-3-a=1 Subtract "a" from both sides.


a%5E2%2Ba-3a-3-a-1=0 Subtract 1 from both sides.


a%5E2-3a-4=0 Combine like terms.


Notice that the quadratic a%5E2-3a-4 is in the form of Aa%5E2%2BBa%2BC where A=1, B=-3, and C=-4


Let's use the quadratic formula to solve for "a":


a+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


a+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%28-4%29+%29%29%2F%282%281%29%29 Plug in A=1, B=-3, and C=-4


a+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%28-4%29+%29%29%2F%282%281%29%29 Negate -3 to get 3.


a+=+%283+%2B-+sqrt%28+9-4%281%29%28-4%29+%29%29%2F%282%281%29%29 Square -3 to get 9.


a+=+%283+%2B-+sqrt%28+9--16+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-4%29 to get -16


a+=+%283+%2B-+sqrt%28+9%2B16+%29%29%2F%282%281%29%29 Rewrite sqrt%289--16%29 as sqrt%289%2B16%29


a+=+%283+%2B-+sqrt%28+25+%29%29%2F%282%281%29%29 Add 9 to 16 to get 25


a+=+%283+%2B-+sqrt%28+25+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


a+=+%283+%2B-+5%29%2F%282%29 Take the square root of 25 to get 5.


a+=+%283+%2B+5%29%2F%282%29 or a+=+%283+-+5%29%2F%282%29 Break up the expression.


a+=+%288%29%2F%282%29 or a+=++%28-2%29%2F%282%29 Combine like terms.


a+=+4 or a+=+-1 Simplify.


So the solutions are a+=+4 or a+=+-1


Quadratic_Equations/200858: This question is from textbook Elementary and Intermediate Algebra
Throwing a wrench. An angry construction worker throws
his wrench downward from a height of 128 feet with an
initial velocity of 32 feet per second. The height of the
wrench above the ground after t seconds is given
by S(t) = -16t2 - 32t + 128.
a) What is the height of the wrench after 1 second?
b) How long does it take for the wrench to reach the
ground?

1 solutions

Answer 151105 by jim_thompson5910(28476) About Me  on 2009-06-22 18:09:15 (Show Source):
You can put this solution on YOUR website!
a)

S%28t%29=-16t%5E2-32t%2B128 Start with the given function.


S%281%29=-16%281%29%5E2-32%281%29%2B128 Plug in t=1.


S%281%29=-16%281%29-32%281%29%2B128 Square 1 to get 1.


S%281%29=-16-32%281%29%2B128 Multiply -16 and 1 to get -16.


S%281%29=-16-32%2B128 Multiply -32 and 1 to get -32.


S%281%29=80 Combine like terms.


So the wrench is 80 feet in the air after 1 second.


-----------------------------------------------------------------------

b)

S%28t%29=-16t%5E2-32t%2B128 Start with the given function.


0=-16t%5E2-32t%2B128 Plug in S%28t%29=0 (ie make the height equal to zero).


Notice that the quadratic -16t%5E2-32t%2B128 is in the form of At%5E2%2BBt%2BC where A=-16, B=-32, and C=128


Let's use the quadratic formula to solve for "t":


t+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


t+=+%28-%28-32%29+%2B-+sqrt%28+%28-32%29%5E2-4%28-16%29%28128%29+%29%29%2F%282%28-16%29%29 Plug in A=-16, B=-32, and C=128


t+=+%2832+%2B-+sqrt%28+%28-32%29%5E2-4%28-16%29%28128%29+%29%29%2F%282%28-16%29%29 Negate -32 to get 32.


t+=+%2832+%2B-+sqrt%28+1024-4%28-16%29%28128%29+%29%29%2F%282%28-16%29%29 Square -32 to get 1024.


t+=+%2832+%2B-+sqrt%28+1024--8192+%29%29%2F%282%28-16%29%29 Multiply 4%28-16%29%28128%29 to get -8192


t+=+%2832+%2B-+sqrt%28+1024%2B8192+%29%29%2F%282%28-16%29%29 Rewrite sqrt%281024--8192%29 as sqrt%281024%2B8192%29


t+=+%2832+%2B-+sqrt%28+9216+%29%29%2F%282%28-16%29%29 Add 1024 to 8192 to get 9216


t+=+%2832+%2B-+sqrt%28+9216+%29%29%2F%28-32%29 Multiply 2 and -16 to get -32.


t+=+%2832+%2B-+96%29%2F%28-32%29 Take the square root of 9216 to get 96.


t+=+%2832+%2B+96%29%2F%28-32%29 or t+=+%2832+-+96%29%2F%28-32%29 Break up the expression.


t+=+%28128%29%2F%28-32%29 or t+=++%28-64%29%2F%28-32%29 Combine like terms.


t+=+-4 or t+=+2 Simplify.


So the possible solutions are t+=+-4 or t+=+2

But remember that a negative time value doesn't make much sense. So we'll ignore t+=+-4


So the only solution is t+=+2 which means that it takes 2 seconds for the wrench to hit the ground.


Expressions-with-variables/200859: In writing out an answer, for example: m more than nineteen. Will it be the variable first or the number? Is their a rule when putting which first?
1 solutions

Answer 151103 by jim_thompson5910(28476) About Me  on 2009-06-22 18:07:55 (Show Source):
You can put this solution on YOUR website!
There isn't a rule, but it's conventional to place the variable first like so m%2B19. Why? Well later you'll learn about polynomials and you'll find that the constant terms are placed last.


Note: the expression 19%2Bm is the exact same expression (ie m%2B19=19%2Bm for all values of "m").


Radicals/200827: Please walk me through each step in solving this problem:
Square root of 25x - 25 minus square root of 9x-9. (Sorry, I cannot product the square root symbol). They say the answer is 2times square root of x-1
1 solutions

Answer 151087 by jim_thompson5910(28476) About Me  on 2009-06-22 14:08:06 (Show Source):
You can put this solution on YOUR website!
sqrt%2825x-25%29-sqrt%289x-9%29 Start with the given expression.


sqrt%2825%28x-1%29%29-sqrt%289x-9%29 Factor out the GCF 25 from the first radicand


sqrt%2825%28x-1%29%29-sqrt%289%28x-1%29%29 Factor out the GCF 9 from the second radicand


sqrt%2825%29%2Asqrt%28x-1%29-sqrt%289%29%2Asqrt%28x-1%29 Break up the roots using the identity sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29


5%2Asqrt%28x-1%29-sqrt%289%29%2Asqrt%28x-1%29 Take the square root of 25 to get 5


5%2Asqrt%28x-1%29-3%2Asqrt%28x-1%29 Take the square root of 9 to get 3


%285-3%29%2Asqrt%28x-1%29 Factor out the GCF sqrt%28x-1%29


2%2Asqrt%28x-1%29 Combine like terms.



So sqrt%2825x-25%29-sqrt%289x-9%29=2%2Asqrt%28x-1%29 where x%3E=1


Radicals/200828: Please walk me through each step in solving this problem:
Simplify by collecting like radical terms, if possible:
3times the cube root of y^5 + 4 times cube root of y^2 + cube root of 8y^6.
They say the answer is (3y+4)times cube root of y^2 + 2y^2.
Sorry I cannor provide the symbol for square root.
1 solutions

Answer 151086 by jim_thompson5910(28476) About Me  on 2009-06-22 14:04:35 (Show Source):
You can put this solution on YOUR website!
3%2Aroot%283%2Cy%5E5%29%2B4%2Aroot%283%2Cy%5E2%29%2Broot%283%2C8y%5E6%29 Start with the given expression.


3%2Aroot%283%2Cy%5E5%29%2B4%2Aroot%283%2Cy%5E2%29%2Broot%283%2C2%5E3%2Ay%5E6%29 Rewrite 8 as 2%5E3


3%2Aroot%283%2Cy%5E3%2Ay%5E2%29%2B4%2Aroot%283%2Cy%5E2%29%2Broot%283%2C2%5E3%2Ay%5E6%29 Rewrite y%5E5 as y%5E3%2Ay%5E2


Rewrite y%5E6 as y%5E3%2Ay%5E3


Break up the roots using the identity root%28n%2Cx%2Ay%29=root%28n%2Cx%29%2Aroot%28n%2Cy%29


Evaluate the cube root of 2%5E3 to get 2


3%2Ay%2Aroot%283%2Cy%5E2%29%2B4%2Aroot%283%2Cy%5E2%29%2B2%2Ay%2Ay Evaluate the cube root of y%5E3 to get "y"


3%2Ay%2Aroot%283%2Cy%5E2%29%2B4%2Aroot%283%2Cy%5E2%29%2B2y%5E2 Multiply


%283y%2B4%29%2Aroot%283%2Cy%5E2%29%2B2y%5E2 Factor out the root%283%2Cy%5E2%29 from the first two terms. note: this step isn't necessary, but your book does it.


=======================================================
Answer:


So 3%2Aroot%283%2Cy%5E5%29%2B4%2Aroot%283%2Cy%5E2%29%2Broot%283%2C8y%5E6%29 simplifies to %283y%2B4%29%2Aroot%283%2Cy%5E2%29%2B2y%5E2



In other words,


Polynomials-and-rational-expressions/200829: Divide: (x^3-2x^2+8) / (x+2)
1 solutions

Answer 151085 by jim_thompson5910(28476) About Me  on 2009-06-22 13:54:52 (Show Source):
You can put this solution on YOUR website!

Let's simplify this expression using synthetic division


Start with the given expression %28x%5E3+-+2x%5E2+%2B+8%29%2F%28x%2B2%29

First lets find our test zero:

x%2B2=0 Set the denominator x%2B2 equal to zero

x=-2 Solve for x.

so our test zero is -2


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.(note: remember if a polynomial goes from -2x%5E2 to 8x%5E0 there is a zero coefficient for x%5E1. This is simply because x%5E3+-+2x%5E2+%2B+8 really looks like 1x%5E3%2B-2x%5E2%2B0x%5E1%2B8x%5E0
-2|1-208
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 1)
-2|1-208
|
1

Multiply -2 by 1 and place the product (which is -2) right underneath the second coefficient (which is -2)
-2|1-208
|-2
1

Add -2 and -2 to get -4. Place the sum right underneath -2.
-2|1-208
|-2
1-4

Multiply -2 by -4 and place the product (which is 8) right underneath the third coefficient (which is 0)
-2|1-208
|-28
1-4

Add 8 and 0 to get 8. Place the sum right underneath 8.
-2|1-208
|-28
1-48

Multiply -2 by 8 and place the product (which is -16) right underneath the fourth coefficient (which is 8)
-2|1-208
|-28-16
1-48

Add -16 and 8 to get -8. Place the sum right underneath -16.
-2|1-208
|-28-16
1-48-8

Since the last column adds to -8, we have a remainder of -8. This means x%2B2 is not a factor of x%5E3+-+2x%5E2+%2B+8
Now lets look at the bottom row of coefficients:

The first 3 coefficients (1,-4,8) form the quotient

x%5E2+-+4x+%2B+8

and the last coefficient -8, is the remainder, which is placed over x%2B2 like this

-8%2F%28x%2B2%29



Putting this altogether, we get:

x%5E2+-+4x+%2B+8%2B-8%2F%28x%2B2%29

So %28x%5E3+-+2x%5E2+%2B+8%29%2F%28x%2B2%29=x%5E2+-+4x+%2B+8%2B-8%2F%28x%2B2%29

which looks like this in remainder form:

%28x%5E3+-+2x%5E2+%2B+8%29%2F%28x%2B2%29=x%5E2+-+4x+%2B+8 remainder -8


Numbers_Word_Problems/200848: in x years from now, Robert will be k years old. How old was Robert m years ago?
The possible answers are: a) x-(k+m)
b) k-x
c) k-x-m
d) x-(k-m)
e) k+m-x

Thank you for helping me!
1 solutions

Answer 151084 by jim_thompson5910(28476) About Me  on 2009-06-22 13:52:32 (Show Source):
You can put this solution on YOUR website!
Let r=Robert's age right now


So if "in x years from now, Robert will be k years old", this means that we simply add "x" to "r" to get "k" like so: x%2Br=k. Now solve for "r" to get r=k-x. So Robert's age right now (in terms of "k" and "x") is k-x


Now just subtract off "m" more years from k-x to get k-x-m


So the answer is C) k-x-m


-----------------------------------------------------------------------


Note: if this doesn't make any sense, just plug in some values. Let's say that Robert is 12 years old. So r=12. In two years, he will be 14 (which means k=14). So this means that we'll make x=2. Now how old was Robert 5 years ago (note: m=5)


So plug in k=14, x=2 and m=5 into k-x-m to get:

14-2-5=12-5=7

So he was 7 years old 5 years ago (from his current age of 12)


Linear-systems/200854: The Jurassic Zoo charges $28.00 for each adult admission and $12.00 for each child. The total bill for 254 people from a school trip was $3864.00. How many adults and how many children went to the zoo?
1 solutions

Answer 151082 by jim_thompson5910(28476) About Me  on 2009-06-22 13:23:18 (Show Source):
You can put this solution on YOUR website!
Let
a = # of adults that attended
c = # of children that attended


Since a total of 254 people attended, this means that a%2Bc=254. Also, because "The Jurassic Zoo charges $28.00 for each adult admission and $12.00 for each child" and "The total bill for 254 people from a school trip was $3864.00", we know that 28a%2B12c=3864


So we have the system of equations:

system%28a%2Bc=254%2C28a%2B12c=3864%29



In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for "a", we would have to eliminate "c" (or vice versa).


So lets eliminate "c". In order to do that, we need to have both "c" coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero and cancel out.

So to make the "c" coefficients equal but opposite, we need to multiply both "c" coefficients by some number to get them to an equal number. So if we wanted to get 1 and 12 to some equal number, we could try to get them to the LCM 12. However, we want one number equal to 12 and the other equal to -12.


Because one "c" coefficient is already equal to 12, we need to multiply both sides of the first equation by -12 (to get the "c" coefficient equal to -12).





28a%2B12c=3864 Start with the first equation.


-12%28a%2Bc%29=-12%28254%29 Multiply the both sides of the first equation by -12.


-12a-12c=-3048 Distribute and multiply.


So we have the new system of equations:


system%28-12a-12c=-3048%2C28a%2B12c=3864%29


Take note that the "c" coefficients are equal but opposite.


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%28-12a-12c%29%2B%2828a%2B12c%29=%28-3048%29%2B%283864%29


%28-12a%2B28a%29%2B%28-12c%2B12c%29=-3048%2B3864 Group like terms.


16a%2B0c=816 Combine like terms.


16a=816 Simplify.


a=%28816%29%2F%2816%29 Divide both sides by 16 to isolate a.


a=51 Reduce.


------------------------------------------------------------------


-12a-12c=-3048 Now go back to the first equation.


-12%2851%29-12c=-3048 Plug in a=51.


-612-12c=-3048 Multiply.


-12c=-3048%2B612 Add 612 to both sides.


-12c=-2436 Combine like terms on the right side.


c=%28-2436%29%2F%28-12%29 Divide both sides by -12 to isolate c.


c=203 Reduce.


============================================================================

Answer:


So the solutions are a=51 and c=203.


This means that 51 adults attended and 203 children attended.



Linear-equations/200801: give an ordered pair (x,y) of numbers that satisfy the equation
6x + y = 6
1 solutions

Answer 151048 by jim_thompson5910(28476) About Me  on 2009-06-22 01:22:46 (Show Source):
You can put this solution on YOUR website!
Here's one possible ordered pair: (0,6)


6(0)+6=6 ---> 0+6=6 ---> 6=6 ... which is true

------------------------------

And another possible ordered pair: (1, 0)

6(1)+0=6 ---> 6+0=6 ---> 6=6 ... which is true

------------------------------

And another possible ordered pair: (2, -6)

6(2)-6=6 ---> 12-6=6 ---> 6=6 ... which is true


------------------------------

And another possible ordered pair: (3, -12)

6(3)-12=6 ---> 18-12=6 ---> 6=6 ... which is true

------------------------------

etc...

So this shows us that there are an infinite number of ordered pairs that satisfy this equation.

Note: only specific pairs of numbers satisfy the equation. You can't just make up two random numbers and hope that they work.


Inverses/200800: Please help me solve this equation
{2x-y^2}/ {x-y}
x=10 and y=(-5)
According to the TI-84 the answer is 3 How?
1 solutions

Answer 151047 by jim_thompson5910(28476) About Me  on 2009-06-22 00:43:33 (Show Source):
You can put this solution on YOUR website!
%282x-y%5E2%29%2F%28x-y%29 Start with the given expression.


%282%2810%29-%28-5%29%5E2%29%2F%2810-%28-5%29%29 Plug in x=10 and y=-5


%282%2810%29-%28-5%29%5E2%29%2F%2810%2B5%29 Rewrite 10-%28-5%29 as 10%2B5


%282%2810%29-25%29%2F%2810%2B5%29 Square -5 to get 25


%2820-25%29%2F%2810%2B5%29 Multiply


%28-5%29%2F%2815%29 Combine like terms.


-1%2F3 Reduce


So %282x-y%5E2%29%2F%28x-y%29=-1%2F3 when x=10 and y=-5


So either you entered the problem in wrong or there's a typo somewhere in your book. Is there something missing? Repost with the clarifications.


Matrices-and-determiminant/200660: Hi all I asked a similiar question recently and got a reaaly good response, but this imiliar problem is still giving me trouble.
I need to solve the following Matrices and comment on the outcomes.For the following:
A =
(2 3 0)
1 4 -3
B =
(1 -1 4)
2 3 5
C =
(2 -1)
3 5
Find and state why or why not the following is possible.
i) A+B
ii) C^-1
iii) AB
1v) B^C
1 solutions

Answer 151046 by jim_thompson5910(28476) About Me  on 2009-06-22 00:31:35 (Show Source):
You can put this solution on YOUR website!


Table of Contents:
Part i)
Part ii)
Part iii)
Part iv)


Given Matrices:


A=%28matrix%282%2C3%2C2%2C3%2C0%2C1%2C4%2C-3%29%29


B=%28matrix%282%2C3%2C1%2C-1%2C4%2C2%2C3%2C5%29%29


C=%28matrix%282%2C2%2C2%2C-1%2C3%2C5%29%29




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Part i)


Start with the addition of the two given matrices


A%2BB=%28matrix%282%2C3%2C2%2B1%2C3%2B%28-1%29%2C0%2B4%2C1%2B2%2C4%2B3%2C-3%2B5%29%29 Add up the matrices by adding the corresponding entries


A%2BB=%28matrix%282%2C3%2C3%2C2%2C4%2C3%2C7%2C2%29%29 Add

===========================================

Answer:

So A%2BB=%28matrix%282%2C3%2C3%2C2%2C4%2C3%2C7%2C2%29%29





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Part ii)

To find the inverse of the matrix C=%28matrix%282%2C2%2C2%2C-1%2C3%2C5%29%29, we can follow these steps:


Step 1) Find the determinant


The determinant of %28matrix%282%2C2%2C2%2C-1%2C3%2C5%29%29 is abs%28matrix%282%2C2%2C2%2C-1%2C3%2C5%29%29=13. So this means that d=13

note: since the determinant is NOT equal to zero, the matrix inverse exists.

--------------------------------
Step 2) Swap the values


Now switch the highlighted values %28matrix%282%2C2%2Chighlight%282%29%2C-1%2C3%2Chighlight%285%29%29%29 to get %28matrix%282%2C2%2Chighlight%285%29%2C-1%2C3%2Chighlight%282%29%29%29


--------------------------------


Step 3) Change the sign


Now change the sign of the highlighted values %28matrix%282%2C2%2C5%2Chighlight%28-1%29%2Chighlight%283%29%2C2%29%29 to get %28matrix%282%2C2%2C5%2Chighlight%281%29%2Chighlight%28-3%29%2C2%29%29


--------------------------------


Step 4) Multiply by the inverse of the determinant


Multiply by 1%2Fd to get %281%2Fd%29%28matrix%282%2C2%2C5%2C1%2C-3%2C2%29%29


Plug in d=13 to get %281%2F13%29%28matrix%282%2C2%2C5%2C1%2C-3%2C2%29%29


--------------------------------

Step 5) Perform scalar multiplication and simplify.


Multiply 1%2F13 by EVERY element to get


Multiply to get %28matrix%282%2C2%2C5%2F13%2C1%2F13%2C-3%2F13%2C2%2F13%29%29


=================================================================

Answer:
So the inverse of %28matrix%282%2C2%2C2%2C-1%2C3%2C5%29%29 is %28matrix%282%2C2%2C5%2F13%2C1%2F13%2C-3%2F13%2C2%2F13%29%29


This means that if C=%28matrix%282%2C2%2C2%2C-1%2C3%2C5%29%29 then C%5E%28-1%29=%28matrix%282%2C2%2C5%2F13%2C1%2F13%2C-3%2F13%2C2%2F13%29%29


note: to verify your work, multiply the matrices C and C%5E%28-1%29 and you should get the matrix %28matrix%282%2C2%2C1%2C0%2C0%2C1%29%29 (the identity matrix).






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Part iii)

Take note that the dimensions of matrices A and B are 2x3 and 2x3 respectively. Since the inner dimensions do NOT match, this means that the matrix product AB is NOT defined. In other words, AB does NOT exist.

note: if A and B are mxn and nxp matrices, then the product AB is defined. It is only defined if the number of columns of A equals the number of rows of B. Otherwise, AB does NOT exist.

===========================================

Answer:

So the matrix product AB is not defined (ie it doesn't exist).








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Part iv)

I'm sure you meant to write B%5ET%2AC correct? If so, then...


Step 1: Transpose matrix B to get B%5ET. You do this by converting each row into a column (and vice versa).




Step 2: Multiply matrices B%5ET and C. Since the inner dimensions are equal, this means that the matrix product B%5ET%2AC is defined.



Since the first matrix is a 3 by 2 matrix and the second matrix is a 2 by 2 matrix, this means that the resulting matrix will be a 3 by 2 matrix.

So the final resulting matrix will look like:


B%5ET%2AC=%28matrix%283%2C2%2Cx%2Cx%2Cx%2Cx%2Cx%2Cx%29%29


note: the "x"s are just placeholders for now



--------------------------------------------------




Multiply the corresponding entries from the 1st row of the first matrix by the 1st column of the second matrix. After multiplying, add the values:


1st row, 1st column:
%281%29%2A%282%29%2B%282%29%2A%283%29=2%2B6=8


So the element in the 1st row, 1st column of the resulting matrix is 8. Now let's update the matrix:

B%5ET%2AC=%28matrix%283%2C2%2C8%2Cx%2Cx%2Cx%2Cx%2Cx%29%29
--------------------------------------------------




Multiply the corresponding entries from the 1st row of the first matrix by the 2nd column of the second matrix. After multiplying, add the values:


1st row, 2nd column:
%281%29%2A%28-1%29%2B%282%29%2A%285%29=-1%2B10=9


So the element in the 1st row, 2nd column of the resulting matrix is 9. Now let's update the matrix:

B%5ET%2AC=%28matrix%283%2C2%2C8%2C9%2Cx%2Cx%2Cx%2Cx%29%29




================================================================================




Multiply the corresponding entries from the 2nd row of the first matrix by the 1st column of the second matrix. After multiplying, add the values:


2nd row, 1st column:
%28-1%29%2A%282%29%2B%283%29%2A%283%29=-2%2B9=7


So the element in the 2nd row, 1st column of the resulting matrix is 7. Now let's update the matrix:

B%5ET%2AC=%28matrix%283%2C2%2C8%2C9%2C7%2Cx%2Cx%2Cx%29%29
--------------------------------------------------




Multiply the corresponding entries from the 2nd row of the first matrix by the 2nd column of the second matrix. After multiplying, add the values:


2nd row, 2nd column:
%28-1%29%2A%28-1%29%2B%283%29%2A%285%29=1%2B15=16


So the element in the 2nd row, 2nd column of the resulting matrix is 16. Now let's update the matrix:

B%5ET%2AC=%28matrix%283%2C2%2C8%2C9%2C7%2C16%2Cx%2Cx%29%29




================================================================================




Multiply the corresponding entries from the 3rd row of the first matrix by the 1st column of the second matrix. After multiplying, add the values:


3rd row, 1st column:

%284%29%2A%282%29%2B%285%29%2A%283%29=8%2B15=23


So the element in the 3rd row, 1st column of the resulting matrix is 23. Now let's update the matrix:

B%5ET%2AC=%28matrix%283%2C2%2C8%2C9%2C7%2C16%2C23%2Cx%29%29
--------------------------------------------------




Multiply the corresponding entries from the 3rd row of the first matrix by the 2nd column of the second matrix. After multiplying, add the values:


3rd row, 2nd column:

%284%29%2A%28-1%29%2B%285%29%2A%285%29=-4%2B25=21


So the element in the 3rd row, 2nd column of the resulting matrix is 21. Now let's update the matrix:

B%5ET%2AC+=+%28matrix%283%2C2%2C8%2C9%2C7%2C16%2C23%2C21%29%29








==============================================================================


Answer:


So



In other words,

B%5ET%2AC+=+%28matrix%283%2C2%2C8%2C9%2C7%2C16%2C23%2C21%29%29


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Square-cubic-other-roots/200781: (3 sqrt 2) * (-4 sqrt 10)
1 solutions

Answer 151044 by jim_thompson5910(28476) About Me  on 2009-06-21 23:30:21 (Show Source):
You can put this solution on YOUR website!
%283%2Asqrt%282%29%29%2A%28-4%2Asqrt%2810%29%29 Start with the given expression.


%283%29%28-4%29%2A%28sqrt%282%29%2Asqrt%2810%29%29 Rearrange the terms.


-12%2A%28sqrt%282%29%2Asqrt%2810%29%29 Multiply 3 and -4 to get -12


-12%2Asqrt%282%2A10%29 Combine the roots using the identity sqrt%28x%29%2Asqrt%28y%29=sqrt%28x%2Ay%29


-12%2Asqrt%2820%29 Multiply 2 and 10 to get 20


-12%2Asqrt%284%2A5%29 Factor 20 to get 4*5. Note: one of the factors must be a perfect square.


-12%2Asqrt%284%29%2Asqrt%285%29 Break up the roots using the identity sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29


-12%2A2%2Asqrt%285%29 Take the square root of 4 to get 2.


-24%2Asqrt%285%29 Multiply -12 and 2 to get -24


So %283%2Asqrt%282%29%29%2A%28-4%2Asqrt%2810%29%29=-24%2Asqrt%285%29


Functions/200794: This question is from textbook Elementary and Intermediate Algebra
Throwing a wrench. An angry construction worker throws
his wrench downward from a height of 128 feet with an
initial velocity of 32 feet per second. The height of the
wrench above the ground after t seconds is given
by S(t)= -16t2 - 32t + 128.
a) What is the height of the wrench after 1 second?
b) How long does it take for the wrench to reach the
ground?
1 solutions

Answer 151031 by jim_thompson5910(28476) About Me  on 2009-06-21 20:11:39 (Show Source):
You can put this solution on YOUR website!
a)

S%28t%29=-16t%5E2-32t%2B128 Start with the given function.


S%281%29=-16%281%29%5E2-32%281%29%2B128 Plug in t=1.


S%281%29=-16%281%29-32%281%29%2B128 Square 1 to get 1.


S%281%29=-16-32%281%29%2B128 Multiply -16 and 1 to get -16.


S%281%29=-16-32%2B128 Multiply -32 and 1 to get -32.


S%281%29=80 Combine like terms.


So the wrench is 80 feet in the air after 1 second.


-----------------------------------------------------------------------

b)

S%28t%29=-16t%5E2-32t%2B128 Start with the given function.


0=-16t%5E2-32t%2B128 Plug in S%28t%29=0 (ie make the height equal to zero).


Notice that the quadratic -16t%5E2-32t%2B128 is in the form of At%5E2%2BBt%2BC where A=-16, B=-32, and C=128


Let's use the quadratic formula to solve for "t":


t+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


t+=+%28-%28-32%29+%2B-+sqrt%28+%28-32%29%5E2-4%28-16%29%28128%29+%29%29%2F%282%28-16%29%29 Plug in A=-16, B=-32, and C=128


t+=+%2832+%2B-+sqrt%28+%28-32%29%5E2-4%28-16%29%28128%29+%29%29%2F%282%28-16%29%29 Negate -32 to get 32.


t+=+%2832+%2B-+sqrt%28+1024-4%28-16%29%28128%29+%29%29%2F%282%28-16%29%29 Square -32 to get 1024.


t+=+%2832+%2B-+sqrt%28+1024--8192+%29%29%2F%282%28-16%29%29 Multiply 4%28-16%29%28128%29 to get -8192


t+=+%2832+%2B-+sqrt%28+1024%2B8192+%29%29%2F%282%28-16%29%29 Rewrite sqrt%281024--8192%29 as sqrt%281024%2B8192%29


t+=+%2832+%2B-+sqrt%28+9216+%29%29%2F%282%28-16%29%29 Add 1024 to 8192 to get 9216


t+=+%2832+%2B-+sqrt%28+9216+%29%29%2F%28-32%29 Multiply 2 and -16 to get -32.


t+=+%2832+%2B-+96%29%2F%28-32%29 Take the square root of 9216 to get 96.


t+=+%2832+%2B+96%29%2F%28-32%29 or t+=+%2832+-+96%29%2F%28-32%29 Break up the expression.


t+=+%28128%29%2F%28-32%29 or t+=++%28-64%29%2F%28-32%29 Combine like terms.


t+=+-4 or t+=+2 Simplify.


So the possible solutions are t+=+-4 or t+=+2

But remember that a negative time value doesn't make much sense. So we'll ignore t+=+-4


So the only solution is t+=+2 which means that it takes 2 seconds for the wrench to hit the ground.


Quadratic_Equations/200795: 3. A rectangular garden with an area of 96m^2 is 4m longer than it is wide. Find its dimensions. (Label the diagram. Solve using a quadratic eqaution!)
Thank you very much!!!!
1 solutions

Answer 151029 by jim_thompson5910(28476) About Me  on 2009-06-21 20:05:17 (Show Source):
You can put this solution on YOUR website!
Let L=length of garden and W=width of garden


Since the garden is "4m longer than it is wide", this tells us that L=W%2B4

Now remember, the area of any rectangle is A=LW


A=LW Start with the area of a rectangle formula


96=%28W%2B4%29W Plug in A=96 (the given area) and L=W%2B4


96=W%28W%2B4%29 Rearrange the terms.


96=W%5E2%2B4W Distribute


0=W%5E2%2B4W-96 Divide


Notice that the quadratic W%5E2%2B4W-96 is in the form of AW%5E2%2BBW%2BC where A=1, B=4, and C=-96


Let's use the quadratic formula to solve for "W":


W+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


W+=+%28-%284%29+%2B-+sqrt%28+%284%29%5E2-4%281%29%28-96%29+%29%29%2F%282%281%29%29 Plug in A=1, B=4, and C=-96


W+=+%28-4+%2B-+sqrt%28+16-4%281%29%28-96%29+%29%29%2F%282%281%29%29 Square 4 to get 16.


W+=+%28-4+%2B-+sqrt%28+16--384+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-96%29 to get -384


W+=+%28-4+%2B-+sqrt%28+16%2B384+%29%29%2F%282%281%29%29 Rewrite sqrt%2816--384%29 as sqrt%2816%2B384%29


W+=+%28-4+%2B-+sqrt%28+400+%29%29%2F%282%281%29%29 Add 16 to 384 to get 400


W+=+%28-4+%2B-+sqrt%28+400+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


W+=+%28-4+%2B-+20%29%2F%282%29 Take the square root of 400 to get 20.


W+=+%28-4+%2B+20%29%2F%282%29 or W+=+%28-4+-+20%29%2F%282%29 Break up the expression.


W+=+%2816%29%2F%282%29 or W+=++%28-24%29%2F%282%29 Combine like terms.


W+=+8 or W+=+-12 Simplify.


So the possible solutions are W+=+8 or W+=+-12


However, you can't have a negative width. So the only solution is W=8

So the width of the garden is 8 m.


Now add 4 m to 8m to get 4+8=12 m. So the length is 12 m


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Answer:


So the length and width of the garden are 12 meters and 8 meters.


Linear-equations/200776: Write an equation of the line that passes through the points (-5,3) and (5,-3).
1 solutions

Answer 151015 by jim_thompson5910(28476) About Me  on 2009-06-21 15:45:31 (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point and is the second point .


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%28-3-3%29%2F%285--5%29 Plug in y%5B2%5D=-3, y%5B1%5D=3, x%5B2%5D=5, and x%5B1%5D=-5


m=%28-6%29%2F%285--5%29 Subtract 3 from -3 to get -6


m=%28-6%29%2F%2810%29 Subtract -5 from 5 to get 10


m=-3%2F5 Reduce


So the slope of the line that goes through the points and is m=-3%2F5


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-3=%28-3%2F5%29%28x--5%29 Plug in m=-3%2F5, x%5B1%5D=-5, and y%5B1%5D=3


y-3=%28-3%2F5%29%28x%2B5%29 Rewrite x--5 as x%2B5


y-3=%28-3%2F5%29x%2B%28-3%2F5%29%285%29 Distribute


y-3=%28-3%2F5%29x-3 Multiply


y=%28-3%2F5%29x-3%2B3 Add 3 to both sides.


y=%28-3%2F5%29x%2B0 Combine like terms.


y=%28-3%2F5%29x Remove the trailing zero


y=%28-3%2F5%29x Simplify


So the equation that goes through the points and is y=%28-3%2F5%29x


Notice how the graph of y=%28-3%2F5%29x goes through the points and . So this visually verifies our answer.
Graph of y=%28-3%2F5%29x through the points and