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Equations/223189: hello i need help with solving equations with variables on both sides of the equations and so if possible could you help me like do the problem step by step fully so i will understand and know how to do it


8x + 5=-3(x+2) please help
1 solutions

Answer 166930 by jim_thompson5910(28715) About Me  on 2009-10-07 16:05:06 (Show Source):
You can put this solution on YOUR website!

8x%2B5=-3%28x%2B2%29 Start with the given equation.


8x%2B5=-3x-6 Distribute.


8x=-3x-6-5 Subtract 5 from both sides.


8x%2B3x=-6-5 Add 3x to both sides.


11x=-6-5 Combine like terms on the left side.


11x=-11 Combine like terms on the right side.


x=%28-11%29%2F%2811%29 Divide both sides by 11 to isolate x.


x=-1 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=-1


Inequalities/223197: pleas help 6x+6-5x≤10
1 solutions

Answer 166929 by jim_thompson5910(28715) About Me  on 2009-10-07 16:04:01 (Show Source):
You can put this solution on YOUR website!

6x%2B6-5x%3C=10 Start with the given inequality.


x%2B6%3C=10 Combine like terms on the left side.


x%3C=10-6 Subtract 6 from both sides.


x%3C=4 Combine like terms on the right side.


----------------------------------------------------------------------

Answer:

So the answer is x%3C=4


Polynomials-and-rational-expressions/223195: 16j^2 + 24j +9
1 solutions

Answer 166928 by jim_thompson5910(28715) About Me  on 2009-10-07 16:03:14 (Show Source):
You can put this solution on YOUR website!
I'm assuming you want to factor.


Looking at the expression 16j%5E2%2B24j%2B9, we can see that the first coefficient is 16, the second coefficient is 24, and the last term is 9.


Now multiply the first coefficient 16 by the last term 9 to get %2816%29%289%29=144.


Now the question is: what two whole numbers multiply to 144 (the previous product) and add to the second coefficient 24?


To find these two numbers, we need to list all of the factors of 144 (the previous product).


Factors of 144:
1,2,3,4,6,8,9,12,16,18,24,36,48,72,144
-1,-2,-3,-4,-6,-8,-9,-12,-16,-18,-24,-36,-48,-72,-144


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 144.
1*144
2*72
3*48
4*36
6*24
8*18
9*16
12*12
(-1)*(-144)
(-2)*(-72)
(-3)*(-48)
(-4)*(-36)
(-6)*(-24)
(-8)*(-18)
(-9)*(-16)
(-12)*(-12)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 24:


First NumberSecond NumberSum
11441+144=145
2722+72=74
3483+48=51
4364+36=40
6246+24=30
8188+18=26
9169+16=25
121212+12=24
-1-144-1+(-144)=-145
-2-72-2+(-72)=-74
-3-48-3+(-48)=-51
-4-36-4+(-36)=-40
-6-24-6+(-24)=-30
-8-18-8+(-18)=-26
-9-16-9+(-16)=-25
-12-12-12+(-12)=-24



From the table, we can see that the two numbers 12 and 12 add to 24 (the middle coefficient).


So the two numbers 12 and 12 both multiply to 144 and add to 24


Now replace the middle term 24j with 12j%2B12j. Remember, 12 and 12 add to 24. So this shows us that 12j%2B12j=24j.


16j%5E2%2Bhighlight%2812j%2B12j%29%2B9 Replace the second term 24j with 12j%2B12j.


%2816j%5E2%2B12j%29%2B%2812j%2B9%29 Group the terms into two pairs.


4j%284j%2B3%29%2B%2812j%2B9%29 Factor out the GCF 4j from the first group.


4j%284j%2B3%29%2B3%284j%2B3%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%284j%2B3%29%284j%2B3%29 Combine like terms. Or factor out the common term 4j%2B3


%284j%2B3%29%5E2 Condense

---------------------------------------------


Answer:


So 16j%5E2%2B24j%2B9 factors to %284j%2B3%29%5E2.


Note: you can check the answer by FOILing %284j%2B3%29%5E2 to get 16j%5E2%2B24j%2B9 or by graphing the original expression and the answer (the two graphs should be identical).


Numbers_Word_Problems/223183: what is the lowest number possible that when divided by 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 always has one left over, or a remainder of one? thanks a bunch.
1 solutions

Answer 166923 by jim_thompson5910(28715) About Me  on 2009-10-07 15:58:04 (Show Source):
You can put this solution on YOUR website!
Well first off, if you divide ANY number by one, you'll ALWAYS get a remainder of 0 (since 1 goes into every number evenly). So I'm assuming that the set of numbers should be 2, 3, 4, 5, 6, 7, 8, 9, and 10 (otherwise, there is no answer).

Note: I'm going to ignore the obvious answer of 1 and assume that this number is larger than each value in the group.


Take note that 2, 3, 4, 5, 6, 7, 8, 9, and 10 all go into the LCM which is 2520. So 2520 divided by any number in this group leaves a remainder of 0. So just add 1 to this value to get 2521. This new number will leave a remainder of 1 if you divide it by any number in that group. So 2521 is the smallest number (except for 1) that leaves a remainder of 1 when dividing by these given numbers.


Note: Other values that leave a remainder of 1 can be generated by adding on multiples of 2520.


Equations/223178: 1/7 = 14 - x
one over seven equals fourteen minus x
how did you come to the answer????
1 solutions

Answer 166918 by jim_thompson5910(28715) About Me  on 2009-10-07 15:46:30 (Show Source):
You can put this solution on YOUR website!

1%2F7=14-x Start with the given equation.


7%281%2Fcross%287%29%29=7%2814-x%29 Multiply both sides by the LCD 7 to clear any fractions.


1=98-7x Distribute and multiply.


0=98-7x-1 Subtract 1 from both sides.


7x=98-1 Add 7x to both sides.


7x=97 Combine like terms on the right side.


x=%2897%29%2F%287%29 Divide both sides by 7 to isolate x.


----------------------------------------------------------------------

Answer:

So the answer is x=97%2F7 which approximates to x=13.857.


Equations/223180: i need help with solving equations with variables on both sides of the equation and here is the problem and if it is possible if you could explain it step by step how to do it that would be great so i will understand fully how to do it


11x-5=7(x-2)need help
1 solutions

Answer 166917 by jim_thompson5910(28715) About Me  on 2009-10-07 15:45:21 (Show Source):
You can put this solution on YOUR website!

11x-5=7%28x-2%29 Start with the given equation.


11x-5=7x-14 Distribute.


11x=7x-14%2B5 Add 5 to both sides.


11x-7x=-14%2B5 Subtract 7x from both sides.


4x=-14%2B5 Combine like terms on the left side.


4x=-9 Combine like terms on the right side.


x=%28-9%29%2F%284%29 Divide both sides by 4 to isolate x.


----------------------------------------------------------------------

Answer:

So the answer is x=-9%2F4 which in decimal form is x=-2.25.


Square-cubic-other-roots/223169: please help me solve simplify: sqrt+%2840x%5E2%29+%2A+sqrt+%2810x%29+
1 solutions

Answer 166916 by jim_thompson5910(28715) About Me  on 2009-10-07 15:44:28 (Show Source):
You can put this solution on YOUR website!
sqrt%2840x%5E2%29%2Asqrt%2810x%29 Start with the given expression.


sqrt%28%2840x%5E2%29%2810x%29%29+ Combine the roots.


sqrt%28400x%5E3%29 Multiply


sqrt%28400%29%2Asqrt%28x%5E3%29 Break up the root.


sqrt%28400%29%2Asqrt%28x%5E2%2Ax%29 Factor


sqrt%28400%29%2Asqrt%28x%5E2%29%2Asqrt%28x%29 Break up the root again.


20%2Asqrt%28x%5E2%29%2Asqrt%28x%29 Take the square root of 400 to get 20.


20%2Ax%2Asqrt%28x%29 Take the square root of x%5E2 to get 'x'.


So sqrt%2840x%5E2%29%2Asqrt%2810x%29=20x%2Asqrt%28x%29 where x%3E=0


Linear-equations/223172: graph the equation y=4
1 solutions

Answer 166915 by jim_thompson5910(28715) About Me  on 2009-10-07 15:39:02 (Show Source):
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The graph of y=4 is simply a horizontal line at y=4 and it looks like this


+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+0%2C4%29+


Graph of y=4 (green horizontal line)


Quadratic-relations-and-conic-sections/223022: what is the graph of the equation 6x^2-24x-5y^2-10y-11=0?
How do yo identify the solutions of the system of equations y^2-x^2=16
x^2-y^2=16
*Can you please show steps so i will know how to solve these kinds of problems in the future
1 solutions

Answer 166914 by jim_thompson5910(28715) About Me  on 2009-10-07 15:36:12 (Show Source):
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# 1

From
Wikipedia (see conic section article), if you have a conic of the form Ax%5E2%2BBxy%2BCy%5E2%2BDx%2BEy%2BF=0, then one of the following is possible:


1) If B%5E2+-+4AC+%3C+0, then the equation represents an ellipse


Special Case: if A+=+C and B+=+0, the equation represents a circle (which is a special case of an ellipse).


or...


2) If B%5E2+-+4AC+=+0, then the equation represents a parabola.


or...


3) if B%5E2+-+4AC+%3E+0, then the equation represents a hyperbola.


Special Case: if A%2BC=0 (ie A=-C), then the conic is a rectangular hyperbola.


------------------------------------------------------------


Now let's solve the problem at hand.


6x%5E2-24x-5y%5E2-10y-11=0 Start with the given conic.


6x%5E2-5y%5E2-24x-10y-11=0 Rearrange the conic into the form Ax%5E2%2BBxy%2BCy%5E2%2BDx%2BEy%2BF=0.


By looking at the last equation, we see that A=6, B=0, C=-5, D=-24, E=-10 and F=-11(just match up the corresponding coefficients).


So in order to classify the given conic, we're going to use the formula B%5E2-4AC and compare it to one of the cases described above.


B%5E2-4AC Start with the given formula.


%280%29%5E2-4%286%29%28-5%29 Plug in A=6, B=0, and C=-5.


0-4%286%29%28-5%29 Square 0 to get 0.


0--120 Multiply to get 4%286%29%28-5%29 -120.


120 Combine like terms.


So B%5E2-4AC=120.


Since B%5E2-4AC%3E0, this means that the conic is an hyperbola.


Here's a graph to verify that result:


Graph of 6x%5E2-24x-5y%5E2-10y-11=0


======================================================================
# 2

y%5E2-x%5E2=16 Start with the first equation


y%5E2=x%5E2%2B16 Add x%5E2 to both sides.

--------

x%5E2-y%5E2=16 Move onto the second equation.


x%5E2-%28x%5E2%2B16%29=16 Plug in y%5E2=x%5E2%2B16


x%5E2-x%5E2-16=16 Distribute


-16=16 Combine like terms.


Since the equation is NEVER true for any value of 'x' or 'y', this means that there are no solutions to the system. Visually, this means that the two graphs will NEVER intersect (ie cross).


Sequences-and-series/222944: 31+34+37+.....+325+328=
the numbers go up in three's. what is the sum of the question above
1 solutions

Answer 166858 by jim_thompson5910(28715) About Me  on 2009-10-07 11:21:54 (Show Source):
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Hint: Use the formula to find the sum of the series


Linear-systems/222939: solve the system of equations
4x + 5y = -41
3x - 2y = 21
1 solutions

Answer 166855 by jim_thompson5910(28715) About Me  on 2009-10-07 11:17:55 (Show Source):
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Start with the given system of equations:
system%284x%2B5y=-41%2C3x-2y=21%29


2%284x%2B5y%29=2%28-41%29 Multiply the both sides of the first equation by 2.


8x%2B10y=-82 Distribute and multiply.


5%283x-2y%29=5%2821%29 Multiply the both sides of the second equation by 5.


15x-10y=105 Distribute and multiply.


So we have the new system of equations:
system%288x%2B10y=-82%2C15x-10y=105%29


Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:


%288x%2B10y%29%2B%2815x-10y%29=%28-82%29%2B%28105%29


%288x%2B15x%29%2B%2810y%2B-10y%29=-82%2B105 Group like terms.


23x%2B0y=23 Combine like terms. Notice how the y terms cancel out.


23x=23 Simplify.


x=%2823%29%2F%2823%29 Divide both sides by 23 to isolate x.


x=1 Reduce.


------------------------------------------------------------------


8x%2B10y=-82 Now go back to the first equation.


8%281%29%2B10y=-82 Plug in x=1.


8%2B10y=-82 Multiply.


10y=-82-8 Subtract 8 from both sides.


10y=-90 Combine like terms on the right side.


y=%28-90%29%2F%2810%29 Divide both sides by 10 to isolate y.


y=-9 Reduce.


So our answer is x=1 and y=-9.


Which form the ordered pair .


This means that the system is consistent and independent.


Notice when we graph the equations, we see that they intersect at . So this visually verifies our answer.


Graph of 4x%2B5y=-41 (red) and 3x-2y=21 (green)


Linear-equations/222940: Find an equation of the line with the given slope and containing the given point.
Slope= 2/3; (-3,3)
1 solutions

Answer 166854 by jim_thompson5910(28715) About Me  on 2009-10-07 11:16:55 (Show Source):
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If you want to find the equation of line with a given a slope of 2%2F3 which goes through the point (-3,3), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y-3=%282%2F3%29%28x--3%29 Plug in m=2%2F3, x%5B1%5D=-3, and y%5B1%5D=3 (these values are given)


y-3=%282%2F3%29%28x%2B3%29 Rewrite x--3 as x%2B3


y-3=%282%2F3%29x%2B%282%2F3%29%283%29 Distribute 2%2F3

y-3=%282%2F3%29x%2B2 Multiply 2%2F3 and 3 to get 2

y=%282%2F3%29x%2B2%2B3 Add 3 to both sides to isolate y

y=%282%2F3%29x%2B5 Combine like terms 2 and 3 to get 5
------------------------------------------------------------------------------------------------------------
Answer:


So the equation of the line with a slope of 2%2F3 which goes through the point (-3,3) is:

y=%282%2F3%29x%2B5 which is now in y=mx%2Bb form where the slope is m=2%2F3 and the y-intercept is b=5

Notice if we graph the equation y=%282%2F3%29x%2B5 and plot the point (-3,3), we get (note: if you need help with graphing, check out this solver)

Graph of y=%282%2F3%29x%2B5 through the point (-3,3)
and we can see that the point lies on the line. Since we know the equation has a slope of 2%2F3 and goes through the point (-3,3), this verifies our answer.


Equations/222955: Solve for the equation:
3t-2(t+3)=t
1 solutions

Answer 166853 by jim_thompson5910(28715) About Me  on 2009-10-07 11:16:17 (Show Source):
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3t-2%28t%2B3%29=t Start with the given equation.


3t-2t-6=t Distribute.


-6%2Bt=t Combine like terms on the left side.


t=t%2B6 Add 6 to both sides.


t-t=6 Subtract t from both sides.


0t=6 Combine like terms on the left side.


0=6 Simplify.


Since this equation is never true for any t value, this means that there are no solutions.


Polynomials-and-rational-expressions/223020: Write each polynomial in descending order of the variable x.
5xy^2+3x^2y-9-2x^3
1 solutions

Answer 166851 by jim_thompson5910(28715) About Me  on 2009-10-07 11:13:25 (Show Source):
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First, write the term that has the largest exponent for 'x'. That would be -2x%5E3. Now add on the next term that has the second largest exponent for 'x'. That would be 3x%5E2y.

So far, we have -2x%5E3%2B3x%5E2y. Now add on the next term has the third largest exponent for 'x', which is 5xy%5E2 to get -2x%5E3%2B3x%5E2y%2B5xy%5E2. Now finally add on the last term -9 to get -2x%5E3%2B3x%5E2y%2B5xy%5E2-9

So the answer is -2x%5E3%2B3x%5E2y%2B5xy%5E2-9


Equations/223017: how do do the problem -1=5-z-z where do i start?
1 solutions

Answer 166850 by jim_thompson5910(28715) About Me  on 2009-10-07 11:10:51 (Show Source):
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-1=5-z-z Start with the given equation.


-1=-2z%2B5 Combine like terms on the right side.


-1-5=-2z Subtract 5 from both sides.


-6=-2z Combine like terms.


-2z=-6 Rearrange the equation.


z=%28-6%29%2F%28-2%29 Divide both sides by -2 to isolate z.


z=3 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is z=3


Probability-and-statistics/223002: There are 3 blue and 5 red balloons, what are the odds that you pick one blue balloon?
1 solutions

Answer 166847 by jim_thompson5910(28715) About Me  on 2009-10-07 11:07:00 (Show Source):
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P(blue) = n(blue)/n(total) = 3/(5+3)=3/8=0.375

note: n(blue) means "number of blue"

So there's a 37.5% chance that you'll select a blue balloon.


logarithm/223004: Here is the problem using natural logarithm:
23=3ln(x-1)+14
What we did was the following:
23=3ln(x-1)+14
subtract 14 from both sides
9=3ln(x-1)
divide both sides by 3
3=ln(x-1)
x-1=e^3
add 1 to both sides
x=e^3+1
Please help!!! It's driving us nuts!!
1 solutions

Answer 166846 by jim_thompson5910(28715) About Me  on 2009-10-07 11:05:01 (Show Source):
You can put this solution on YOUR website!
If the original problem is 23=3ln%28x-1%29%2B14 and your answer is x=e%5E3%2B1, then you are correct.

Check:

23=3ln%28x-1%29%2B14 Start with the given equation


23=3ln%28e%5E3%2B1-1%29%2B14 Plug in x=e%5E3%2B1


23=3ln%28e%5E3%29%2B14 Combine like terms.


23=3%2A3ln%28e%29%2B14 Pull down the exponent.


23=3%2A3%281%29%2B14 Evaluate the natural log of 'e' to get 1.


23=9%2B14 Multiply


23=23 Add. Since the equation is true, this verifies the solution.


Equations/223012: -3x-6(x-4)=9
1 solutions

Answer 166845 by jim_thompson5910(28715) About Me  on 2009-10-07 11:00:29 (Show Source):
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-3x-6%28x-4%29=9 Start with the given equation.


-3x-6x%2B24=9 Distribute.


-9x%2B24=9 Combine like terms on the left side.


-9x=9-24 Subtract 24 from both sides.


-9x=-15 Combine like terms on the right side.


x=%28-15%29%2F%28-9%29 Divide both sides by -9 to isolate x.


x=5%2F3 Reduce.


----------------------------------------------------------------------

Answer:

So the answer is x=5%2F3 which approximates to x=1.667.


Systems-of-equations/222888: find all of the ordered pairs, (x,y) of integers that satisfy all four of the given equations: 5*x*3*y=180, x^2+y^2=40, 8*x-8*y=32, 12x/4y=1 The ordered pair has to satisfy all equations and i have to find all of them. for example, if x=5 and y=9, that ordered pair needs to work for every equation. I'm guessing since it says find all of them, there is probably more than one.
1 solutions

Answer 166775 by jim_thompson5910(28715) About Me  on 2009-10-06 22:36:06 (Show Source):
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I think they gave your 4 equations just to scare you a bit. It turns out that the four equations 5x%2A3y=180, x%5E2%2By%5E2=40, 8x-8y=32, and 12x%2F%284y%29=1 are a hyperbola, a circle, and two straight lines respectively. Since 8x-8y=32 and 12x%2F%284y%29=1 are equations of lines, you need to satisfy all 4 equations, and the intersection of two lines is either going to give you a) no solutions, b) infinite solutions, or c) 1 solution, this means that your best bet is to solve the system system%288x-8y=32%2C12x%2F%284y%29=1%29


Note: you should find that there is only one solution to the system of two equations above, which would mean that there is only one solution to the given system of four equations.



Linear-systems/222851: How do you sove this equation?
absolute value (7x-4)-4=-11
1 solutions

Answer 166761 by jim_thompson5910(28715) About Me  on 2009-10-06 21:39:25 (Show Source):
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abs%287x-4%29-4=-11 Start with the given equation


abs%287x-4%29=-7 Add 4 to both sides.


Since the equation abs%287x-4%29=-7 is never true (note: remember, the absolute value of any number is always positive), there are no solutions to abs%287x-4%29=-7


This means that there are no solutions to the equation abs%287x-4%29-4=-11


Equations/222853: -5X+2=2
1 solutions

Answer 166757 by jim_thompson5910(28715) About Me  on 2009-10-06 21:37:34 (Show Source):
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-5x%2B2=2 Start with the given equation.


-5x=2-2 Subtract 2 from both sides.


-5x=0 Combine like terms on the right side.


x=%280%29%2F%28-5%29 Divide both sides by -5 to isolate x.


x=0 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x=0


Complex_Numbers/222848: how do i know if i get the right answer? a lot of times on tests, i don't know if i have the right answer or not, usually on the more difficult questions.
here's one question: (2+3i)+(-4+5i)-(9-3i)/3.
the slash is dividing. the answer is -5-9i i beleive. what i wanna know, is how do you expand this question? how is it solved?
thanks.
1 solutions

Answer 166755 by jim_thompson5910(28715) About Me  on 2009-10-06 21:34:12 (Show Source):
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If the expression is %282%2B3i%29%2B%28-4%2B5i%29-%289-3i%29%2F3, then...


%282%2B3i%29%2B%28-4%2B5i%29-%289-3i%29%2F3 Start with the given expression.


%282%2B3i%29%2B%28-4%2B5i%29-%289%2F3-%283i%29%2F3%29 Break up the fraction


%282%2B3i%29%2B%28-4%2B5i%29-%283-i%29 Reduce.


2%2B3i-4%2B5i-3%2Bi Distribute


-5%2B9i Combine like terms.


So %282%2B3i%29%2B%28-4%2B5i%29-%289-3i%29%2F3=-5%2B9i


Equations/222844: Solve equation. Did I do this right?
11-5(3-x)=-2(x+3)+6x
I got x=-2
1 solutions

Answer 166753 by jim_thompson5910(28715) About Me  on 2009-10-06 21:30:42 (Show Source):
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11-5%283-x%29=-2%28x%2B3%29%2B6x Start with the given equation.


11-15%2B5x=-2x-6%2B6x Distribute.


5x-4=-2x-6%2B6x Combine like terms on the left side.


5x-4=4x-6 Combine like terms on the right side.


5x=4x-6%2B4 Add 4 to both sides.


5x-4x=-6%2B4 Subtract 4x from both sides.


x=-6%2B4 Combine like terms on the left side.


x=-2 Combine like terms on the right side.


----------------------------------------------------------------------

Answer:

So the solution is x=-2


So you are correct.


Linear-equations/222842: How can 12 - 6 = -6
This is a problem I got from my algebra teacher today.
12 - 6 = -n
she said the answer is -6
How can that be true when in elementary school I learned that 12 - 6 = 6.
Thanks
1 solutions

Answer 166751 by jim_thompson5910(28715) About Me  on 2009-10-06 21:29:21 (Show Source):
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What she meant by "the answer is -6" is that the value of n=-6 satisfies the equation 12-6=-n. Take note that the left side is simply 6 (since 12-6=6). So the equation then becomes 6=-n. Now plug in n=-6 to get 6=-%28-6%29 and now simplify 6=6. Since this is a true equation, this verifies the answer.


Note: none of this means that 12-6=-6 (since this isn't even true anyway).


logarithm/222790: Let (((log(a,X))))=C and (((log(b,X))))=D. Find the general statement that expresses (((log(ab,X))))in term of C and D.
I already know the answer is (CD)/(C+D)
I cannot figure out how to write a proof for this question.
I know all of the logarithmic principles as well but I can only come up with either (C)(D) as my answer or (C+D). I can't get a fraction.
1 solutions

Answer 166740 by jim_thompson5910(28715) About Me  on 2009-10-06 21:16:27 (Show Source):
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I found that it helps to work backwards for a bit to find out how to go forward. In this case, I broke down log%28ab%2C%28x%29%29 to get:

log%28ab%2C%28x%29%29


log%2810%2C%28x%29%29%2Flog%2810%2C%28ab%29%29 (used the change of base formula here)


log%2810%2C%28x%29%29%2F%28log%2810%2C%28a%29%29%2Blog%2810%2C%28b%29%29%29 (used the identity log%28b%2C%28A%2AB%29%29=log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29)


Then I realized that I needed to find substitutions for log%2810%2C%28a%29%29 and log%2810%2C%28b%29%29 (to somehow get 'x' in there). So I figured I'd solve for those respective expressions like so:



log%28a%2C%28x%29%29=C Start with the first equation.


log%2810%2C%28x%29%29%2Flog%2810%2C%28a%29%29=C Use the change of base formula.


log%2810%2C%28x%29%29=C%2Alog%2810%2C%28a%29%29 Multiply both sides by log%2810%2C%28a%29%29.


log%2810%2C%28x%29%29%2FC=log%2810%2C%28a%29%29 Divide both sides by C.


So this means log%2810%2C%28a%29%29=log%2810%2C%28x%29%29%2FC


---------------------

log%28b%2C%28x%29%29=D Start with the second equation.


log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29=D Use the change of base formula.


log%2810%2C%28x%29%29=D%2Alog%2810%2C%28b%29%29 Multiply both sides by log%2810%2C%28b%29%29


log%2810%2C%28x%29%29%2FD=log%2810%2C%28b%29%29 Divide both sides by D.


So this means log%2810%2C%28b%29%29=log%2810%2C%28x%29%29%2FD

-------------------------------------------


Now let's get back to the main problem:


log%28ab%2C%28x%29%29 Start with the given expression.


log%2810%2C%28x%29%29%2Flog%2810%2C%28ab%29%29 Use the change of base formula.


log%2810%2C%28x%29%29%2F%28log%2810%2C%28a%29%29%2Blog%2810%2C%28b%29%29%29 Use the identity log%28b%2C%28A%2AB%29%29=log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29 to break up the denominator.


Now here's where the substitutions come into play:


log%2810%2C%28x%29%29%2F%28log%2810%2C%28x%29%29%2FC%2Blog%2810%2C%28x%29%29%2FD%29 Plug in log%2810%2C%28a%29%29=log%2810%2C%28x%29%29%2FC and log%2810%2C%28b%29%29=log%2810%2C%28x%29%29%2FD


From here, it's just boils down to algebraically simplifying the expression:


Multiply the first inner fraction by D%2FD.


Multiply the second inner fraction by C%2FC.


Combine the lower fractions.


Multiply log%2810%2C%28x%29%29 by the reciprocal of the lower fraction.


Multiply


%28CD%2Alog%2810%2C%28x%29%29%29%2F%28log%2810%2C%28x%29%29%28D%2BC%29%29 Factor out the GCF log%2810%2C%28x%29%29 from the denominator.


Cancel out the common terms.


%28CD%29%2F%28D%2BC%29 Simplify


%28CD%29%2F%28C%2BD%29 Rearrange the terms (trivial, but I figured that I'd match the book).


So this means log%28ab%2C%28x%29%29=%28CD%29%2F%28C%2BD%29 where log%28a%2C%28x%29%29=C and log%28b%2C%28x%29%29=D


Proportions/222784: In the Dicovering Algebra: An Investigative approach, there is a question that says Find the value of the unknown number in each proportion? The problem is 52/91=42/s. So do i inverse it. Swich it up like this: 91/52=s/42? or keep it the same?
1 solutions

Answer 166720 by jim_thompson5910(28715) About Me  on 2009-10-06 20:24:02 (Show Source):
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52%2F91=42%2Fs Start with the given equation.


%2852%2F91%29%2As=42 Multiply both sides by s


52%2As=42%2A91 Multiply both sides by 91


52%2As=3822 Multiply


s=3822%2F52 Divide both sides by 52


s=147%2F2 Reduce.


So our answer is s=147%2F2 which in decimal form is s=73.5


Equations/222726: what is the answer to -4%2Ax%2B9=x-11 written form negitive+4+times+x+plus+9+=+x+subtract+11
i have tried to get rid of one of the X's but i dont remember how
1 solutions

Answer 166714 by jim_thompson5910(28715) About Me  on 2009-10-06 19:54:08 (Show Source):
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-4x%2B9=x-11 Start with the given equation.


-4x=x-11-9 Subtract 9 from both sides.


-4x-x=-11-9 Subtract x from both sides.


-5x=-11-9 Combine like terms on the left side.


-5x=-20 Combine like terms on the right side.


x=%28-20%29%2F%28-5%29 Divide both sides by -5 to isolate x.


x=4 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x=4


Square-cubic-other-roots/222738: square root of 72x^2 y^3
please help, im stuck.
thank you.

1 solutions

Answer 166712 by jim_thompson5910(28715) About Me  on 2009-10-06 19:49:56 (Show Source):
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sqrt%2872%2Ax%5E2%2Ay%5E3%29 Start with the given expression.


sqrt%2836%2A2%2Ax%5E2%2Ay%5E3%29 Factor 72 into 36%2A2


sqrt%2836%2A2%2Ax%5E2%2Ay%5E2%2Ay%29 Factor y%5E3 into y%5E2%2Ay


sqrt%2836%29%2Asqrt%282%29%2Asqrt%28x%5E2%29%2Asqrt%28y%5E2%29%2Asqrt%28y%29 Break up the square root using the identity sqrt%28A%2AB%29=sqrt%28A%29%2Asqrt%28B%29.


6%2Asqrt%282%29%2Asqrt%28x%5E2%29%2Asqrt%28y%5E2%29%2Asqrt%28y%29 Take the square root of 36 to get 6.


6%2Asqrt%282%29%2Ax%2Asqrt%28y%5E2%29%2Asqrt%28y%29 Take the square root of x%5E2 to get x.


6%2Asqrt%282%29%2Ax%2Ay%2Asqrt%28y%29 Take the square root of y%5E2 to get y.


6xy%2Asqrt%282y%29 Rearrange and multiply the terms.

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Answer:


So sqrt%2872%2Ax%5E2%2Ay%5E3%29 simplifies to 6xy%2Asqrt%282y%29


In other words, sqrt%2872%2Ax%5E2%2Ay%5E3%29=6xy%2Asqrt%282y%29 where every variable is non-negative.


Linear-equations/222729: how to put -2x+3y=8 into slope-intercept form
1 solutions

Answer 166706 by jim_thompson5910(28715) About Me  on 2009-10-06 19:37:16 (Show Source):
You can put this solution on YOUR website!

-2x%2B3y=8 Start with the given equation.


3y=8%2B2x Add 2x to both sides.


3y=2x%2B8 Rearrange the terms.


y=%282x%2B8%29%2F%283%29 Divide both sides by 3 to isolate y.


y=%282%2F3%29x%2B8%2F3 Break up the fraction.


So the equation y=%282%2F3%29x%2B8%2F3 is now in slope intercept form y=mx%2Bb where the slope is m=2%2F3 and the y-intercept is b=8%2F3 note: the y-intercept is the point


Quadratic_Equations/222686: Multiply. (b+(1/3))(b+(1/3))
Thank you!
1 solutions

Answer 166699 by jim_thompson5910(28715) About Me  on 2009-10-06 18:54:51 (Show Source):
You can put this solution on YOUR website!

%28b%2B1%2F3%29%28b%2B1%2F3%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%28b%29%2B1%2F3%29%28highlight%28b%29%2B1%2F3%29 Multiply the First terms:%28b%29%2A%28b%29=b%5E2.


%28highlight%28b%29%2B1%2F3%29%28b%2Bhighlight%281%2F3%29%29 Multiply the Outer terms:%28b%29%2A%281%2F3%29=%281%2F3%29b.


%28b%2Bhighlight%281%2F3%29%29%28highlight%28b%29%2B1%2F3%29 Multiply the Inner terms:%281%2F3%29%2A%28b%29=%281%2F3%29b.


%28b%2Bhighlight%281%2F3%29%29%28b%2Bhighlight%281%2F3%29%29 Multiply the Last terms:%281%2F3%29%2A%281%2F3%29=%281%2A1%29%2F%283%2A3%29=1%2F9.


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So we have the terms: b%5E2, %281%2F3%29b, %281%2F3%29b, 1%2F3%5E2


b%5E2%2B%281%2F3%29b%2B%281%2F3%29b%2B1%2F9 Now add every term listed above to make a single expression.


b%5E2%2B%282%2F3%29b%2B1%2F9 Now combine like terms.


So %28b%2B1%2F3%29%28b%2B1%2F3%29 FOILs to b%5E2%2B%282%2F3%29b%2B1%2F9.


In other words, %28b%2B1%2F3%29%28b%2B1%2F3%29=b%5E2%2B%282%2F3%29b%2B1%2F9.


Polynomials-and-rational-expressions/222692: Factor completely. 64r^2-121
Thank you!!
1 solutions

Answer 166698 by jim_thompson5910(28715) About Me  on 2009-10-06 18:48:59 (Show Source):
You can put this solution on YOUR website!

64r%5E2-121 Start with the given expression.


%288r%29%5E2-121 Rewrite 64r%5E2 as %288r%29%5E2.


%288r%29%5E2-%2811%29%5E2 Rewrite 121 as %2811%29%5E2.


Notice how we have a difference of squares A%5E2-B%5E2 where in this case A=8r and B=11.


So let's use the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29 to factor the expression:


A%5E2-B%5E2=%28A%2BB%29%28A-B%29 Start with the difference of squares formula.


%288r%29%5E2-%2811%29%5E2=%288r%2B11%29%288r-11%29 Plug in A=8r and B=11.


So this shows us that 64r%5E2-121 factors to %288r%2B11%29%288r-11%29.


In other words 64r%5E2-121=%288r%2B11%29%288r-11%29.