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(xy+ab^2)(xy-ab^2) 1 solutions
Answer 177957 by jim_thompson5910(28476) on 2009-11-26 21:19:22 (Show Source):
You can put this solution on YOUR website!You could use the difference of squares formula, but let's do it the long way.
 Start with the given expression.
Now let's FOIL the expression.
Remember, when you FOIL an expression, you follow this procedure:
 Multiply the First terms:  .
 Multiply the Outer terms:  .
 Multiply the Inner terms:  .
 Multiply the Last terms:  .
---------------------------------------------------
So we have the terms:  ,  ,  , and
 Now add every term listed above to make a single expression.
 Now combine like terms.
So  FOILs to  .
In other words,  .
Note: recall that the difference of squares formula is  . So you could have used this formula where in this case  and
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Trigonometry-basics/242933: please help me:
The range of F in F(x)=2sinx;-pi/2
HERE ARE THE POSSIBLE ANSWERS:
a)-2<_F(x)<_2
b)-2<_F(x)<_0
c)F(x)<_2 1 solutions
Answer 177946 by jim_thompson5910(28476) on 2009-11-26 20:11:48 (Show Source):
You can put this solution on YOUR website!If you graph  , you get
and you can see that the min y value is -2 while the max y value is 2. So the range is  making the answer a)
Another way you can do it is look at a table of values for 2*sin(x) and determine the max/min values.
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Equations/242931: I need to express the following problem in terms of B:
a = 1/sq root of(1-B^2)
I cannot figure out how to get rid of the square root since 1-b^2 simplifies to (1+B)(1-B) 1 solutions
Answer 177920 by jim_thompson5910(28476) on 2009-11-26 19:13:56 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Multiply both sides by  .
 Divide both sides by 'a'.
 Square both sides.
 Square  to get
 Subtract 1 from both sides.
 Multiply 1 by
 Combine the fractions.
 Divide both sides by -1.
 Distribute
 Take the square root of both sides.
 or  Break up the plus/minus
 or  Break up the square root.
 or  Simplify the square roots in the denominator.
So the solutions are:  or
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logarithm/242902: Please help me solve this problem.
If log(m)n=log(n)m, m not equal to n, m not equal to 1, n not equal to 1 and m.n>0, evaluate m.n. Please note (m) and (n) are subscripts (bases) 1 solutions
Answer 177918 by jim_thompson5910(28476) on 2009-11-26 19:05:29 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Use the change of base formula on the left side.
 Use the change of base formula on the right side.
 Cross multiply
 Condense the terms.
 Get everything to one side
 Factor the left side using the difference of squares formula
 or  Use the zero product property.
 or  Get the  term to the other side.
 or  Use the identity  to rewrite the right side (of the first equation)
 or  Simplify
 or  Now equate the arguments.
Since we're told that  , this means that the only solution is  (which is the same as saying  )
Now multiply n and m to get:  . So the product of m and n is 1.
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Geometry_proofs/242906: given; CP bisects angle BCR and angle BPR
prove; triangle BCP congruent to triangle RCP
pls reply me back this my homework
i will be waiting thank you 1 solutions
Answer 177915 by jim_thompson5910(28476) on 2009-11-26 18:18:24 (Show Source):
You can put this solution on YOUR website!If you draw the picture, you might get
note: there's more than one way to draw it, but the idea should be the same.
Here's how the proof would go:
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Proofs/242905: How do I solve these proofs?
Number one
1.~B v[(C>D)&(E>D)]
2. B&(C v E) /therefore, D
Number two
1. W&(A&M)
2. (A&W)>([(N v(R v H)]
3. ~N & (~P&~H) /therefore, R
Number three
1. (O&T)>(S&M)
2. R>~M
3. T&R
4. O&S /therefore, V
Number 4. last one
1. F>W /therefore, (F&S)>W
1 solutions
Answer 177901 by jim_thompson5910(28476) on 2009-11-26 17:35:32 (Show Source):
You can put this solution on YOUR website!# 1
1. ~B v [(C -> D) & (E -> D)]
2. B & (C v E) /therefore D
--------------------------------
3. (C v E) & B 2 Commutation
4. B 2 Simplification
5. C v E 3 Simplification
6. ~~B 4 Double Negation
7. (C -> D) & (E -> D) 1,6 Disjunctive Syllogism
8. D v D 7,5 Constructive Dilemma
9. D 8 Tautology
==============================================
# 2
1. W & (A & M)
2. (A & W) -> [N v (R v H)]
3. ~N & ( ~P & ~H ) /therefore, R
----------------------------------
4. (W & A) & M 1 Association
5. W & A 4 Simplification
6. A & W 5 Commutation
7. N v (R v H) 2,6 Modus Ponens
8. ~N 3 Simplification
9. ( ~P & ~H ) & ~N 3 Commutation
10. ~P & ~H 9 Simplification
11. ~H & ~P 10 Commutation
12. ~H 11 Simplification
13. R v H 7,8 Disjunctive Syllogism
14. H v R 13 Commutation
15. R 14,12 Disjunctive Syllogism
==============================================
# 3
1. (O & T)>(S & M)
2. R -> ~M
3. T & R
4. O & S /therefore, V
----------------------------------
5. R & T 3 Commutation
6. R 5 Simplification
7. O 4 Simplification
8. T 3 Simplification
9. O & T 7,8 Conjunction
10. S & M 1,9 Modus Ponens
11. M & S 10 Commutation
12. M 11 Simplification
13. ~~M 12 Double Negation
14. ~R 2,13 Modus Tollens
15. R & ~R 6,14 Conjunction
16. F 15 Contradiction
17. F v V 16 Addition
18. V 17 Tautology
note: the truth value of R & ~R is ALWAYS false (since R can't be both true and false at the same time). I'm denoting 'false' as the letter 'F'. Also, the truth value of F v V is dependent on the truth value of V (since F is a constant). So F v V is equivalent to V
==============================================
# 4
1. F -> W /therefore, (F & S) -> W
---------------------------------------
2. ~F v W 1 Material Implication
3. (~F v W) v ~S 2 Addition
4. ~F v (W v ~S) 3 Association
5. ~F v (~S v W) 4 Commutation
6. (~F v ~S) v W 5 Association
7. ~(F & S) v W 6 De Morgan's Law
8. (F & S) -> W 7 Material Implication
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Equations/242824: Solve
6y^2+5y-14=0
thank you 1 solutions
Answer 177792 by jim_thompson5910(28476) on 2009-11-25 20:51:12 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "y":
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the solutions are  or
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Quadratic_Equations/242799: solve the equation
(3m-6)^2 + 3(3m-6)-10=0
Thank you 1 solutions
Answer 177767 by jim_thompson5910(28476) on 2009-11-25 19:29:47 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
Let
 Replace each '3m-6' with 'z'
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "z":
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the solutions in terms of z are  or
Since  , this means that  or  . Solving for 'm' gets us the final solutions
 or
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logarithm/242790: w^2 - 3w + 5 = 0 1 solutions
Answer 177747 by jim_thompson5910(28476) on 2009-11-25 17:56:25 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "w":
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
 or  Break up the expression.
So the solutions are  or
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Complex_Numbers/242786: square root of p^2-3p+16 (the square root ends on top of 16)=p+1 1 solutions
Answer 177746 by jim_thompson5910(28476) on 2009-11-25 17:55:46 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Square both sides.
 FOIL
 Subtract  from both sides.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
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Linear_Algebra/242759: solve the system for all soulutions usin any suitable method y=3x+2 and x-2y=11 1 solutions
Answer 177713 by jim_thompson5910(28476) on 2009-11-25 15:44:18 (Show Source):
You can put this solution on YOUR website! Start with the second equation.
 Plug in
 Distribute.
 Combine like terms on the left side.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
 Go back to the first equation.
 Plug in
 Multiply
 Add
So the solutions are  and  giving us the ordered pair (-3,-7)
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Polynomials-and-rational-expressions/242760: I sent this problem earlier but after receiving a response quickly realized I entered the wrong problem, can u please help me with this one? I have no clue where to start. Thanks in advance!!
Solve:
(x+2)(x-2)(x+1)>0
a)the solution set is
b)solution is all real numbers
c)there is no solution 1 solutions
Answer 177712 by jim_thompson5910(28476) on 2009-11-25 15:41:48 (Show Source):
You can put this solution on YOUR website! Start with the given inequality.
 Set the left side equal to zero
Set each individual factor equal to zero:
 ,  or
Solve for x in each case:
 ,  or
So our critical values are  ,  and
Now set up a number line and plot the critical values on the number line
So let's pick some test points that are near the critical values and evaluate them.
Let's pick a test value that is less than  (notice how it's to the left of the leftmost endpoint). This corresponds to the left most interval ( )
So let's pick
 Start with the given inequality
 Plug in
 Evaluate and simplify the left side
Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.
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Let's pick a test value that is in between  and  . This corresponds to the left middle interval ( )
So let's pick
 Start with the given inequality
 Plug in
 Evaluate and simplify the left side
Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is ( )
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Let's pick a test value that is in between  and  . This corresponds to the right middle interval ( )
So let's pick
 Start with the given inequality
 Plug in
 Evaluate and simplify the left side
Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.
---------------------------------------------------------------------------------------------
Let's pick a test value that is greater than  (notice how it's to the right of the rightmost endpoint). This corresponds to the right most interval ( )
So let's pick
 Start with the given inequality
 Plug in
 Evaluate and simplify the left side
Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is ( )
---------------------------------------------------------------------------------------------
Summary:
So the solution in interval notation is:
( ) ( )
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Polynomials-and-rational-expressions/242758: Directions are to Solve and I don't even know where to start. I thought to set the equation equal to zero, but very confused, can someone please help me??
w^2 - 7w - 18 = 0 1 solutions
Answer 177706 by jim_thompson5910(28476) on 2009-11-25 15:31:04 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "w":
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the solutions are  or
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Quadratic_Equations/242738: 3x^2+14x-24=0 1 solutions
Answer 177703 by jim_thompson5910(28476) on 2009-11-25 15:26:50 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "x":
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the solutions are  or
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Polynomials-and-rational-expressions/242743: Desperate for help, I understand how to start but I am getting very confused the answer I arrived at was 4y- 39/(y+6)(y-6), but I don't think it's right, please help!!!
Perform the indicated operations and simplify:
y-3/y-6-y+1/y+6+y-42/y^2-36 1 solutions
Answer 177701 by jim_thompson5910(28476) on 2009-11-25 15:25:08 (Show Source):
You can put this solution on YOUR website! Start with the given expression.
 Factor the last denominator.
Take note that the LCD is
 Multiply the first fraction by  to get that denominator equal to the LCD.
 Multiply the second fraction by  to get that denominator equal to the LCD.
 FOIL.
 Combine the fractions.
 Distribute.
 Combine like terms.
 Factor the numerator.
 Cancel out the common terms.
 Simplify.
So  where  or
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Equations/242466: 6(2x+8)-5(x-7)=5x+91+x
3(3x+1)=5-5(3x-3)
2-8(x+3)<-38-3(x+8)+3x 1 solutions
Answer 177481 by jim_thompson5910(28476) on 2009-11-24 15:12:40 (Show Source):
You can put this solution on YOUR website!#1
 Start with the given equation.
 Distribute.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
----------------------------------------------------------------------
Answer:
So the solution is
# 2
 Start with the given equation.
 Distribute.
 Combine like terms on the right side.
 Subtract  from both sides.
 Add  to both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
----------------------------------------------------------------------
Answer:
So the solution is  which approximates to  .
# 3
 Start with the given inequality.
 Distribute.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  . note: Remember, the inequality sign flips when we divide both sides by a negative number.
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
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Polynomials-and-rational-expressions/242287: find the roots of 2x squared -5x+1=0 1 solutions
Answer 177366 by jim_thompson5910(28476) on 2009-11-23 23:07:19 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "x":
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 or  Break up the expression.
So the solutions are  or
which approximate to  or
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Equations/242074: how do you solve something like this 6-b=5b+30? 1 solutions
Answer 177226 by jim_thompson5910(28476) on 2009-11-23 16:03:27 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
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logarithm/242094: I need help on how to solve a logarithmic Equation. The question is
3 Log (base 2) x+1 = 7
When I tried putting this equation into exponential form, I got
2^7 = (x+1)^3. However, when I solved for this, I did not end up with
the answer that is needed. I ended up looking up the answer in the back of the book so that i could see if i could backtrack from there, but it was simply 4.
Thanks,
dmc93x@yahoo.com 1 solutions
Answer 177224 by jim_thompson5910(28476) on 2009-11-23 16:00:07 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Subtract 1 from both sides.
 Combine like terms.
 Divide both sides by 3.
 Reduce
 Convert to exponential form.
 Square 2 to get 4.
So the solution is
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