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expressions/242940: how do you simplify
(xy+ab^2)(xy-ab^2)
1 solutions

Answer 177957 by jim_thompson5910(28476) About Me  on 2009-11-26 21:19:22 (Show Source):
You can put this solution on YOUR website!
You could use the difference of squares formula, but let's do it the long way.




%28x%2Ay%2Ba%2Ab%5E2%29%28x%2Ay-a%2Ab%5E2%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%28x%2Ay%29%2Ba%2Ab%5E2%29%28highlight%28x%2Ay%29-a%2Ab%5E2%29 Multiply the First terms:%28x%2Ay%29%2A%28x%2Ay%29=x%5E2%2Ay%5E2.


%28highlight%28x%2Ay%29%2Ba%2Ab%5E2%29%28x%2Ay%2Bhighlight%28-a%2Ab%5E2%29%29 Multiply the Outer terms:%28x%2Ay%29%2A%28-a%2Ab%5E2%29=-x%2Ay%2Aa%2Ab%5E2.


%28x%2Ay%2Bhighlight%28a%2Ab%5E2%29%29%28highlight%28x%2Ay%29-a%2Ab%5E2%29 Multiply the Inner terms:%28a%2Ab%5E2%29%2A%28x%2Ay%29=x%2Ay%2Aa%2Ab%5E2.


%28x%2Ay%2Bhighlight%28a%2Ab%5E2%29%29%28x%2Ay%2Bhighlight%28-a%2Ab%5E2%29%29 Multiply the Last terms:%28a%2Ab%5E2%29%2A%28-a%2Ab%5E2%29=-a%5E2%2Ab%5E4.


---------------------------------------------------
So we have the terms: x%5E2%2Ay%5E2, -x%2Ay%2Aa%2Ab%5E2, x%2Ay%2Aa%2Ab%5E2, and -a%5E2%2Ab%5E4


x%5E2%2Ay%5E2-x%2Ay%2Aa%2Ab%5E2%2Bx%2Ay%2Aa%2Ab%5E2-a%5E2%2Ab%5E4 Now add every term listed above to make a single expression.


x%5E2%2Ay%5E2-a%5E2%2Ab%5E4 Now combine like terms.


So %28x%2Ay%2Ba%2Ab%5E2%29%28x%2Ay-a%2Ab%5E2%29 FOILs to x%5E2%2Ay%5E2-a%5E2%2Ab%5E4.


In other words, %28x%2Ay%2Ba%2Ab%5E2%29%28x%2Ay-a%2Ab%5E2%29=x%5E2%2Ay%5E2-a%5E2%2Ab%5E4.



Note: recall that the difference of squares formula is %28A%2BB%29%28A-B%29=A%5E2-B%5E2. So you could have used this formula where in this case A=xy and B=ab%5E2


logarithm/242934: Hello,
Problem: log16^1/2.
I tried solving and I got 4.
What I'm not sure of is if its negative 4 or positive?
I might be completly off, but learning what i have about logarithms I think I might be on the right track.
Please let me know if its negative or positive, and my answer 4 is right.
Thanks
1 solutions

Answer 177956 by jim_thompson5910(28476) About Me  on 2009-11-26 21:16:19 (Show Source):
You can put this solution on YOUR website!
log%2816%2C%281%2F2%29%29 Start with the given expression.


log%2810%2C%281%2F2%29%29%2Flog%2810%2C%2816%29%29 Use the change of base formula.


log%2810%2C%282%5E%28-1%29%29%29%2Flog%2810%2C%2816%29%29 Rewrite 1%2F2 as 2%5E%28-1%29


log%2810%2C%282%5E%28-1%29%29%29%2Flog%2810%2C%282%5E4%29%29 Rewrite 16 as 2%5E4


%28-1%2Alog%2810%2C%282%29%29%29%2F%284%2Alog%2810%2C%282%29%29%29 Pull down the exponents using the identity log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29


%28-1%2Across%28log%2810%2C%282%29%29%29%29%2F%284%2Across%28log%2810%2C%282%29%29%29%29 Cancel out the common terms.


-1%2F4 Simplify


So log%2816%2C%281%2F2%29%29=-1%2F4


expressions/242938: can you help me simplify this problem?
(x-2)(x^2-4x+3)
1 solutions

Answer 177953 by jim_thompson5910(28476) About Me  on 2009-11-26 21:10:29 (Show Source):
You can put this solution on YOUR website!

%28x-2%29%28x%5E2-4x%2B3%29 Start with the given expression.


x%28x%5E2-4x%2B3%29-2%28x%5E2-4x%2B3%29 Expand.


Distribute.


x%5E3-4%2Ax%5E2%2B3%2Ax-2%2Ax%5E2%2B8%2Ax-6 Multiply.


x%5E3-6%2Ax%5E2%2B11%2Ax-6 Now combine like terms.


So %28x-2%29%28x%5E2-4x%2B3%29 expands to x%5E3-6%2Ax%5E2%2B11%2Ax-6.


In other words, %28x-2%29%28x%5E2-4x%2B3%29=x%5E3-6%2Ax%5E2%2B11%2Ax-6.


Trigonometry-basics/242933: please help me:
The range of F in F(x)=2sinx;-pi/2 HERE ARE THE POSSIBLE ANSWERS:
a)-2<_F(x)<_2
b)-2<_F(x)<_0
c)F(x)<_2
1 solutions

Answer 177946 by jim_thompson5910(28476) About Me  on 2009-11-26 20:11:48 (Show Source):
You can put this solution on YOUR website!
If you graph f%28x%29=2%2Asin%28x%29, you get



and you can see that the min y value is -2 while the max y value is 2. So the range is -2%3C=f%28x%29%3C=2 making the answer a)


Another way you can do it is look at a table of values for 2*sin(x) and determine the max/min values.


Equations/242931: I need to express the following problem in terms of B:
a = 1/sq root of(1-B^2)
I cannot figure out how to get rid of the square root since 1-b^2 simplifies to (1+B)(1-B)
1 solutions

Answer 177920 by jim_thompson5910(28476) About Me  on 2009-11-26 19:13:56 (Show Source):
You can put this solution on YOUR website!
a=1%2Fsqrt%281-b%5E2%29 Start with the given equation.


a%2Asqrt%281-b%5E2%29=1 Multiply both sides by sqrt%281-b%5E2%29.


sqrt%281-b%5E2%29=1%2Fa Divide both sides by 'a'.


1-b%5E2=%281%2Fa%29%5E2 Square both sides.


1-b%5E2=1%2Fa%5E2 Square 1%2Fa to get 1%2Fa%5E2


-b%5E2=1%2Fa%5E2-1 Subtract 1 from both sides.


-b%5E2=1%2Fa%5E2-%28a%5E2%29%2F%28a%5E2%29 Multiply 1 by %28a%5E2%29%2F%28a%5E2%29


-b%5E2=%281-a%5E2%29%2Fa%5E2 Combine the fractions.


b%5E2=-%281-a%5E2%29%2Fa%5E2 Divide both sides by -1.


b%5E2=%28a%5E2-1%29%2Fa%5E2 Distribute


b=%27%27%2B-sqrt%28%28a%5E2-1%29%2Fa%5E2%29 Take the square root of both sides.


b=sqrt%28%28a%5E2-1%29%2Fa%5E2%29 or b=-sqrt%28%28a%5E2-1%29%2Fa%5E2%29 Break up the plus/minus


b=sqrt%28a%5E2-1%29%2Fsqrt%28a%5E2%29 or b=-sqrt%28a%5E2-1%29%2Fsqrt%28a%5E2%29 Break up the square root.


b=sqrt%28a%5E2-1%29%2Fa or b=-sqrt%28a%5E2-1%29%2Fa Simplify the square roots in the denominator.


So the solutions are: b=sqrt%28a%5E2-1%29%2Fa or b=-sqrt%28a%5E2-1%29%2Fa


logarithm/242902: Please help me solve this problem.
If log(m)n=log(n)m, m not equal to n, m not equal to 1, n not equal to 1 and m.n>0, evaluate m.n. Please note (m) and (n) are subscripts (bases)
1 solutions

Answer 177918 by jim_thompson5910(28476) About Me  on 2009-11-26 19:05:29 (Show Source):
You can put this solution on YOUR website!
log%28m%2C%28n%29%29=log%28n%2C%28m%29%29 Start with the given equation.


log%2810%2C%28n%29%29%2Flog%2810%2C%28m%29%29=log%28n%2C%28m%29%29 Use the change of base formula on the left side.


log%2810%2C%28n%29%29%2Flog%2810%2C%28m%29%29=log%2810%2C%28m%29%29%2Flog%2810%2C%28n%29%29 Use the change of base formula on the right side.


log%2810%2C%28n%29%29log%2810%2C%28n%29%29=log%2810%2C%28m%29%29log%2810%2C%28m%29%29 Cross multiply


%28log%2810%2C%28n%29%29%29%5E2=%28log%2810%2C%28m%29%29%29%5E2 Condense the terms.


%28log%2810%2C%28n%29%29%29%5E2-%28log%2810%2C%28m%29%29%29%5E2=0 Get everything to one side


Factor the left side using the difference of squares formula


log%2810%2C%28n%29%29%2Blog%2810%2C%28m%29%29=0 or log%2810%2C%28n%29%29-log%2810%2C%28m%29%29=0 Use the zero product property.


log%2810%2C%28n%29%29=-log%2810%2C%28m%29%29 or log%2810%2C%28n%29%29=log%2810%2C%28m%29%29 Get the log%2810%2C%28m%29%29 term to the other side.


log%2810%2C%28n%29%29=log%2810%2C%28m%5E%28-1%29%29%29 or log%2810%2C%28n%29%29=log%2810%2C%28m%29%29 Use the identity y%2Alog%28b%2C%28x%29%29=log%28b%2C%28x%5Ey%29%29 to rewrite the right side (of the first equation)


log%2810%2C%28n%29%29=log%2810%2C%281%2Fm%29%29 or log%2810%2C%28n%29%29=log%2810%2C%28m%29%29 Simplify


n=1%2Fm or n=m Now equate the arguments.


Since we're told that m%3C%3En, this means that the only solution is n=1%2Fm (which is the same as saying m=1%2Fn)


Now multiply n and m to get: mn=%281%2Fn%29%28n%29=n%2Fn=1. So the product of m and n is 1.


Geometry_proofs/242906: given; CP bisects angle BCR and angle BPR
prove; triangle BCP congruent to triangle RCP
pls reply me back this my homework
i will be waiting thank you
1 solutions

Answer 177915 by jim_thompson5910(28476) About Me  on 2009-11-26 18:18:24 (Show Source):
You can put this solution on YOUR website!
If you draw the picture, you might get




note: there's more than one way to draw it, but the idea should be the same.


Here's how the proof would go:




Exponential-and-logarithmic-functions/242917: 3^x+8=4x
a. -30.551
b.30.551
c.31.721
d.29.381
I think the answer is b. please let me know
1 solutions

Answer 177907 by jim_thompson5910(28476) About Me  on 2009-11-26 17:44:33 (Show Source):
You can put this solution on YOUR website!
If the equation is 3%5E%28x%2B8%29+=+4%5Ex, then the approximate answer is which rounds to 30.551. So if that is the correct equation, then you have the correct answer.


expressions/242921: If y=y3, then y3(y3-y)=
1 solutions

Answer 177906 by jim_thompson5910(28476) About Me  on 2009-11-26 17:42:27 (Show Source):
You can put this solution on YOUR website!
If y=y%5E3, then y%5E3%28y%5E3-y%29=y%5E3%28y%5E3-y%5E3%29=y%5E3%280%29=0. So if y=y%5E3, then y%5E3%28y%5E3-y%29=0


Exponential-and-logarithmic-functions/242919: Express as a difference of logarithms
log base b 5/w
Is log base b 5-log base b w
the answer?
1 solutions

Answer 177905 by jim_thompson5910(28476) About Me  on 2009-11-26 17:41:05 (Show Source):
You can put this solution on YOUR website!
You are correct. Good job. log%28b%2C%285%2Fw%29%29=log%28b%2C%285%29%29-log%28b%2C%28w%29%29


Exponential-and-logarithmic-functions/242916: Solve the exponenetial equation
3^(1+2x)=243
a)2
b)-2
c)6
d)81
I think the answer is A
Please let me know. thanks
1 solutions

Answer 177904 by jim_thompson5910(28476) About Me  on 2009-11-26 17:39:36 (Show Source):
You can put this solution on YOUR website!
You are correct. Note how 243=3%5E5. So 3%5E%281%2B2x%29=243 becomes 3%5E%281%2B2x%29=3%5E5. Equate the exponents to get 1%2B2x=5 and solve for 'x' to get 2x=4 ---> x=2 which is the answer.


Exponential-and-logarithmic-functions/242918: simplify
log base a a8
a.a^8
b.8log base a a
c. 1
d.8
I chose d. Is this correct?
1 solutions

Answer 177903 by jim_thompson5910(28476) About Me  on 2009-11-26 17:37:19 (Show Source):
You can put this solution on YOUR website!
You are correct. Recall that log%28b%2C%28x%29%29=log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29.

So in this case, .


In other words, log%28a%2C%28a%5E8%29%29=8


Proofs/242905: How do I solve these proofs?
Number one
1.~B v[(C>D)&(E>D)]
2. B&(C v E) /therefore, D


Number two
1. W&(A&M)
2. (A&W)>([(N v(R v H)]
3. ~N & (~P&~H) /therefore, R

Number three
1. (O&T)>(S&M)
2. R>~M
3. T&R
4. O&S /therefore, V

Number 4. last one
1. F>W /therefore, (F&S)>W

1 solutions

Answer 177901 by jim_thompson5910(28476) About Me  on 2009-11-26 17:35:32 (Show Source):
You can put this solution on YOUR website!
# 1
1.  ~B v [(C -> D) & (E -> D)]
2.  B & (C v E) /therefore   D
--------------------------------
3.  (C v E) & B                2     Commutation
4.  B                          2     Simplification
5.  C v E                      3     Simplification
6.  ~~B                        4     Double Negation
7.  (C -> D) & (E -> D)        1,6   Disjunctive Syllogism
8.  D v D                      7,5   Constructive Dilemma
9.  D                          8     Tautology


==============================================
# 2


1.  W & (A & M)
2.  (A & W) -> [N v (R v H)]
3.  ~N & ( ~P & ~H )    /therefore, R
---------------------------------- 
4.  (W & A) & M                     1      Association
5.  W & A                           4      Simplification
6.  A & W                           5      Commutation
7.  N v (R v H)                     2,6    Modus Ponens
8.  ~N                              3      Simplification
9.  ( ~P & ~H ) & ~N                3      Commutation
10. ~P & ~H                         9      Simplification
11.  ~H & ~P                        10     Commutation
12.  ~H                             11     Simplification
13.  R v H                          7,8    Disjunctive Syllogism
14.  H v R                          13     Commutation
15.  R                              14,12  Disjunctive Syllogism


==============================================
# 3

1.  (O & T)>(S & M)
2.  R -> ~M
3.  T & R
4.  O & S          /therefore, V 
----------------------------------
5.  R & T                         3        Commutation
6.  R                             5        Simplification
7.  O                             4        Simplification
8.  T                             3        Simplification
9.  O & T                         7,8      Conjunction
10. S & M                         1,9      Modus Ponens
11. M & S                         10       Commutation
12. M                             11       Simplification
13. ~~M                           12       Double Negation
14. ~R                            2,13     Modus Tollens
15. R & ~R                        6,14     Conjunction
16. F                             15       Contradiction
17. F v V                         16       Addition
18. V                             17       Tautology


note: the truth value of R & ~R is ALWAYS false (since R can't be both true and false at the same time). I'm denoting 'false' as the letter 'F'. Also, the truth value of F v V is dependent on the truth value of V (since F is a constant). So F v V is equivalent to V

==============================================
# 4

1.  F -> W          /therefore, (F & S) -> W
---------------------------------------
2.  ~F v W                             1      Material Implication
3.  (~F v W) v ~S                      2      Addition
4.  ~F v (W v ~S)                      3      Association
5.  ~F v (~S v W)                      4      Commutation
6.  (~F v ~S) v W                      5      Association
7.  ~(F & S) v W                       6      De Morgan's Law
8.  (F & S) -> W                       7      Material Implication


Equations/242824: Solve
6y^2+5y-14=0
thank you
1 solutions

Answer 177792 by jim_thompson5910(28476) About Me  on 2009-11-25 20:51:12 (Show Source):
You can put this solution on YOUR website!

6y%5E2%2B5y-14=0 Start with the given equation.


Notice that the quadratic 6y%5E2%2B5y-14 is in the form of Ay%5E2%2BBy%2BC where A=6, B=5, and C=-14


Let's use the quadratic formula to solve for "y":


y+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


y+=+%28-%285%29+%2B-+sqrt%28+%285%29%5E2-4%286%29%28-14%29+%29%29%2F%282%286%29%29 Plug in A=6, B=5, and C=-14


y+=+%28-5+%2B-+sqrt%28+25-4%286%29%28-14%29+%29%29%2F%282%286%29%29 Square 5 to get 25.


y+=+%28-5+%2B-+sqrt%28+25--336+%29%29%2F%282%286%29%29 Multiply 4%286%29%28-14%29 to get -336


y+=+%28-5+%2B-+sqrt%28+25%2B336+%29%29%2F%282%286%29%29 Rewrite sqrt%2825--336%29 as sqrt%2825%2B336%29


y+=+%28-5+%2B-+sqrt%28+361+%29%29%2F%282%286%29%29 Add 25 to 336 to get 361


y+=+%28-5+%2B-+sqrt%28+361+%29%29%2F%2812%29 Multiply 2 and 6 to get 12.


y+=+%28-5+%2B-+19%29%2F%2812%29 Take the square root of 361 to get 19.


y+=+%28-5+%2B+19%29%2F%2812%29 or y+=+%28-5+-+19%29%2F%2812%29 Break up the expression.


y+=+%2814%29%2F%2812%29 or y+=++%28-24%29%2F%2812%29 Combine like terms.


y+=+7%2F6 or y+=+-2 Simplify.


So the solutions are y+=+7%2F6 or y+=+-2



Quadratic_Equations/242799: solve the equation
(3m-6)^2 + 3(3m-6)-10=0
Thank you
1 solutions

Answer 177767 by jim_thompson5910(28476) About Me  on 2009-11-25 19:29:47 (Show Source):
You can put this solution on YOUR website!
%283m-6%29%5E2+%2B+3%283m-6%29-10=0 Start with the given equation.


Let z=3m-6


z%5E2+%2B+3z-10=0 Replace each '3m-6' with 'z'


Notice that the quadratic z%5E2%2B3z-10 is in the form of Az%5E2%2BBz%2BC where A=1, B=3, and C=-10


Let's use the quadratic formula to solve for "z":


z+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


z+=+%28-%283%29+%2B-+sqrt%28+%283%29%5E2-4%281%29%28-10%29+%29%29%2F%282%281%29%29 Plug in A=1, B=3, and C=-10


z+=+%28-3+%2B-+sqrt%28+9-4%281%29%28-10%29+%29%29%2F%282%281%29%29 Square 3 to get 9.


z+=+%28-3+%2B-+sqrt%28+9--40+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-10%29 to get -40


z+=+%28-3+%2B-+sqrt%28+9%2B40+%29%29%2F%282%281%29%29 Rewrite sqrt%289--40%29 as sqrt%289%2B40%29


z+=+%28-3+%2B-+sqrt%28+49+%29%29%2F%282%281%29%29 Add 9 to 40 to get 49


z+=+%28-3+%2B-+sqrt%28+49+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


z+=+%28-3+%2B-+7%29%2F%282%29 Take the square root of 49 to get 7.


z+=+%28-3+%2B+7%29%2F%282%29 or z+=+%28-3+-+7%29%2F%282%29 Break up the expression.


z+=+%284%29%2F%282%29 or z+=++%28-10%29%2F%282%29 Combine like terms.


z+=+2 or z+=+-5 Simplify.


So the solutions in terms of z are z+=+2 or z+=+-5

Since z=3m-6, this means that 3m-6=2 or 3m-6=-5. Solving for 'm' gets us the final solutions


m=8%2F3 or m=1%2F3


decimal-numbers/242787: -(-3) to the third power?
1 solutions

Answer 177757 by jim_thompson5910(28476) About Me  on 2009-11-25 18:34:12 (Show Source):


logarithm/242790: w^2 - 3w + 5 = 0
1 solutions

Answer 177747 by jim_thompson5910(28476) About Me  on 2009-11-25 17:56:25 (Show Source):
You can put this solution on YOUR website!

w%5E2-3w%2B5=0 Start with the given equation.


Notice that the quadratic w%5E2-3w%2B5 is in the form of Aw%5E2%2BBw%2BC where A=1, B=-3, and C=5


Let's use the quadratic formula to solve for "w":


w+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


w+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%285%29+%29%29%2F%282%281%29%29 Plug in A=1, B=-3, and C=5


w+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%285%29+%29%29%2F%282%281%29%29 Negate -3 to get 3.


w+=+%283+%2B-+sqrt%28+9-4%281%29%285%29+%29%29%2F%282%281%29%29 Square -3 to get 9.


w+=+%283+%2B-+sqrt%28+9-20+%29%29%2F%282%281%29%29 Multiply 4%281%29%285%29 to get 20


w+=+%283+%2B-+sqrt%28+-11+%29%29%2F%282%281%29%29 Subtract 20 from 9 to get -11


w+=+%283+%2B-+sqrt%28+-11+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


w+=+%283+%2B-+i%2Asqrt%2811%29%29%2F%282%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


w+=+%283%2Bi%2Asqrt%2811%29%29%2F%282%29 or w+=+%283-i%2Asqrt%2811%29%29%2F%282%29 Break up the expression.


So the solutions are w+=+%283%2Bi%2Asqrt%2811%29%29%2F%282%29 or w+=+%283-i%2Asqrt%2811%29%29%2F%282%29


Complex_Numbers/242786: square root of p^2-3p+16 (the square root ends on top of 16)=p+1
1 solutions

Answer 177746 by jim_thompson5910(28476) About Me  on 2009-11-25 17:55:46 (Show Source):
You can put this solution on YOUR website!
sqrt%28p%5E2-3p%2B16%29=p%2B1 Start with the given equation.


p%5E2-3p%2B16=%28p%2B1%29%5E2 Square both sides.


p%5E2-3p%2B16=p%5E2%2B2p%2B1 FOIL


-3p%2B16=2p%2B1 Subtract p%5E2 from both sides.


-3p=2p%2B1-16 Subtract 16 from both sides.


-3p-2p=1-16 Subtract 2p from both sides.


-5p=1-16 Combine like terms on the left side.


-5p=-15 Combine like terms on the right side.


p=%28-15%29%2F%28-5%29 Divide both sides by -5 to isolate p.


p=3 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is p=3


Linear_Algebra/242759: solve the system for all soulutions usin any suitable method y=3x+2 and x-2y=11
1 solutions

Answer 177713 by jim_thompson5910(28476) About Me  on 2009-11-25 15:44:18 (Show Source):
You can put this solution on YOUR website!
x-2y=11 Start with the second equation.


x-2%283x%2B2%29=11 Plug in y=3x%2B2


x-6x-4=11 Distribute.


-5x-4=11 Combine like terms on the left side.


-5x=11%2B4 Add 4 to both sides.


-5x=15 Combine like terms on the right side.


x=%2815%29%2F%28-5%29 Divide both sides by -5 to isolate x.


x=-3 Reduce.


y=3x%2B2 Go back to the first equation.


y=3%28-3%29%2B2 Plug in x=-3


y=-9%2B2 Multiply


y=-7 Add


So the solutions are x=-3 and y=-7 giving us the ordered pair (-3,-7)


Polynomials-and-rational-expressions/242760: I sent this problem earlier but after receiving a response quickly realized I entered the wrong problem, can u please help me with this one? I have no clue where to start. Thanks in advance!!
Solve:
(x+2)(x-2)(x+1)>0
a)the solution set is
b)solution is all real numbers
c)there is no solution
1 solutions

Answer 177712 by jim_thompson5910(28476) About Me  on 2009-11-25 15:41:48 (Show Source):
You can put this solution on YOUR website!
%28x-2%29%28x%2B2%29%28x%2B1%29%3E0 Start with the given inequality.


%28x-2%29%28x%2B2%29%28x%2B1%29=0 Set the left side equal to zero


Set each individual factor equal to zero:

x-2=0, x%2B2=0 or x%2B1=0

Solve for x in each case:

x=2, x=-2 or x=-1


So our critical values are x=2, x=-2 and x=-1

Now set up a number line and plot the critical values on the number line

number_line%28+600%2C+-10%2C+10%2C2%2C-2%2C-1%29



So let's pick some test points that are near the critical values and evaluate them.


Let's pick a test value that is less than -2 (notice how it's to the left of the leftmost endpoint). This corresponds to the left most interval ()


So let's pick x=-3

%28x-2%29%28x%2B2%29%28x%2B1%29%3E0 Start with the given inequality


%28-3-2%29%28-3%2B2%29%28-3%2B1%29%3E+0 Plug in x=-3


-10%3E+0 Evaluate and simplify the left side

Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.


---------------------------------------------------------------------------------------------



Let's pick a test value that is in between -2 and -1. This corresponds to the left middle interval ()

So let's pick x=-1.5

%28x-2%29%28x%2B2%29%28x%2B1%29%3E0 Start with the given inequality


%28-1.5-2%29%28-1.5%2B2%29%28-1.5%2B1%29%3E+0 Plug in x=-1.5


0.875%3E+0 Evaluate and simplify the left side

Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is ()





---------------------------------------------------------------------------------------------



Let's pick a test value that is in between -1 and 2. This corresponds to the right middle interval ()

So let's pick x=0

%28x-2%29%28x%2B2%29%28x%2B1%29%3E0 Start with the given inequality


%280-2%29%280%2B2%29%280%2B1%29%3E+0 Plug in x=0


-4%3E+0 Evaluate and simplify the left side

Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.


---------------------------------------------------------------------------------------------



Let's pick a test value that is greater than 2 (notice how it's to the right of the rightmost endpoint). This corresponds to the right most interval ()

So let's pick x=3

x%5E3%2Bx%5E2-4x-4%3E0 Start with the given inequality


%283-2%29%283%2B2%29%283%2B1%29%3E+0 Plug in x=3


20%3E+0 Evaluate and simplify the left side

Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.
So part our solution in interval notation is ()





---------------------------------------------------------------------------------------------





Summary:

So the solution in interval notation is:


() ()


Polynomials-and-rational-expressions/242758: Directions are to Solve and I don't even know where to start. I thought to set the equation equal to zero, but very confused, can someone please help me??
w^2 - 7w - 18 = 0
1 solutions

Answer 177706 by jim_thompson5910(28476) About Me  on 2009-11-25 15:31:04 (Show Source):
You can put this solution on YOUR website!

w%5E2-7w-18=0 Start with the given equation.


Notice that the quadratic w%5E2-7w-18 is in the form of Aw%5E2%2BBw%2BC where A=1, B=-7, and C=-18


Let's use the quadratic formula to solve for "w":


w+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


w+=+%28-%28-7%29+%2B-+sqrt%28+%28-7%29%5E2-4%281%29%28-18%29+%29%29%2F%282%281%29%29 Plug in A=1, B=-7, and C=-18


w+=+%287+%2B-+sqrt%28+%28-7%29%5E2-4%281%29%28-18%29+%29%29%2F%282%281%29%29 Negate -7 to get 7.


w+=+%287+%2B-+sqrt%28+49-4%281%29%28-18%29+%29%29%2F%282%281%29%29 Square -7 to get 49.


w+=+%287+%2B-+sqrt%28+49--72+%29%29%2F%282%281%29%29 Multiply 4%281%29%28-18%29 to get -72


w+=+%287+%2B-+sqrt%28+49%2B72+%29%29%2F%282%281%29%29 Rewrite sqrt%2849--72%29 as sqrt%2849%2B72%29


w+=+%287+%2B-+sqrt%28+121+%29%29%2F%282%281%29%29 Add 49 to 72 to get 121


w+=+%287+%2B-+sqrt%28+121+%29%29%2F%282%29 Multiply 2 and 1 to get 2.


w+=+%287+%2B-+11%29%2F%282%29 Take the square root of 121 to get 11.


w+=+%287+%2B+11%29%2F%282%29 or w+=+%287+-+11%29%2F%282%29 Break up the expression.


w+=+%2818%29%2F%282%29 or w+=++%28-4%29%2F%282%29 Combine like terms.


w+=+9 or w+=+-2 Simplify.


So the solutions are w+=+9 or w+=+-2



Quadratic_Equations/242738: 3x^2+14x-24=0
1 solutions

Answer 177703 by jim_thompson5910(28476) About Me  on 2009-11-25 15:26:50 (Show Source):
You can put this solution on YOUR website!

3x%5E2%2B14x-24=0 Start with the given equation.


Notice that the quadratic 3x%5E2%2B14x-24 is in the form of Ax%5E2%2BBx%2BC where A=3, B=14, and C=-24


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%2814%29+%2B-+sqrt%28+%2814%29%5E2-4%283%29%28-24%29+%29%29%2F%282%283%29%29 Plug in A=3, B=14, and C=-24


x+=+%28-14+%2B-+sqrt%28+196-4%283%29%28-24%29+%29%29%2F%282%283%29%29 Square 14 to get 196.


x+=+%28-14+%2B-+sqrt%28+196--288+%29%29%2F%282%283%29%29 Multiply 4%283%29%28-24%29 to get -288


x+=+%28-14+%2B-+sqrt%28+196%2B288+%29%29%2F%282%283%29%29 Rewrite sqrt%28196--288%29 as sqrt%28196%2B288%29


x+=+%28-14+%2B-+sqrt%28+484+%29%29%2F%282%283%29%29 Add 196 to 288 to get 484


x+=+%28-14+%2B-+sqrt%28+484+%29%29%2F%286%29 Multiply 2 and 3 to get 6.


x+=+%28-14+%2B-+22%29%2F%286%29 Take the square root of 484 to get 22.


x+=+%28-14+%2B+22%29%2F%286%29 or x+=+%28-14+-+22%29%2F%286%29 Break up the expression.


x+=+%288%29%2F%286%29 or x+=++%28-36%29%2F%286%29 Combine like terms.


x+=+4%2F3 or x+=+-6 Simplify.


So the solutions are x+=+4%2F3 or x+=+-6



Exponents-negative-and-fractional/242757: what is negative 3 to the fourth
1 solutions

Answer 177702 by jim_thompson5910(28476) About Me  on 2009-11-25 15:26:00 (Show Source):


Polynomials-and-rational-expressions/242743: Desperate for help, I understand how to start but I am getting very confused the answer I arrived at was 4y- 39/(y+6)(y-6), but I don't think it's right, please help!!!
Perform the indicated operations and simplify:
y-3/y-6-y+1/y+6+y-42/y^2-36
1 solutions

Answer 177701 by jim_thompson5910(28476) About Me  on 2009-11-25 15:25:08 (Show Source):
You can put this solution on YOUR website!
%28y-3%29%2F%28y-6%29-%28y%2B1%29%2F%28y%2B6%29%2B%28y-42%29%2F%28y%5E2-36%29 Start with the given expression.


%28y-3%29%2F%28y-6%29-%28y%2B1%29%2F%28y%2B6%29%2B%28y-42%29%2F%28%28y-6%29%28y%2B6%29%29 Factor the last denominator.


Take note that the LCD is %28y-6%29%28y%2B6%29


Multiply the first fraction by %28y%2B6%29%2F%28y%2B6%29 to get that denominator equal to the LCD.


Multiply the second fraction by %28y-6%29%2F%28y-6%29 to get that denominator equal to the LCD.


FOIL.


%28y%5E2%2B3y-18-%28y%5E2-5y-6%29%2B%28y-42%29%29%2F%28%28y-6%29%28y%2B6%29%29 Combine the fractions.


%28y%5E2%2B3y-18-y%5E2%2B5y%2B6%2By-42%29%2F%28%28y-6%29%28y%2B6%29%29 Distribute.


%289y-54%29%2F%28%28y-6%29%28y%2B6%29%29 Combine like terms.


%289%28y-6%29%29%2F%28%28y-6%29%28y%2B6%29%29 Factor the numerator.


%289cross%28%28y-6%29%29%29%2F%28cross%28%28y-6%29%29%28y%2B6%29%29 Cancel out the common terms.


9%2F%28y%2B6%29 Simplify.


So where y%3C%3E-6 or y%3C%3E6


Equations/242466: 6(2x+8)-5(x-7)=5x+91+x
3(3x+1)=5-5(3x-3)
2-8(x+3)<-38-3(x+8)+3x
1 solutions

Answer 177481 by jim_thompson5910(28476) About Me  on 2009-11-24 15:12:40 (Show Source):
You can put this solution on YOUR website!
#1


6%282x%2B8%29-5%28x-7%29=5x%2B91%2Bx Start with the given equation.


12x%2B48-5x%2B35=5x%2B91%2Bx Distribute.


7x%2B83=5x%2B91%2Bx Combine like terms on the left side.


7x%2B83=6x%2B91 Combine like terms on the right side.


7x=6x%2B91-83 Subtract 83 from both sides.


7x-6x=91-83 Subtract 6x from both sides.


x=91-83 Combine like terms on the left side.


x=8 Combine like terms on the right side.


----------------------------------------------------------------------

Answer:

So the solution is x=8




# 2


3%283x%2B1%29=5-5%283x-3%29 Start with the given equation.


9x%2B3=5-15x%2B15 Distribute.


9x%2B3=-15x%2B20 Combine like terms on the right side.


9x=-15x%2B20-3 Subtract 3 from both sides.


9x%2B15x=20-3 Add 15x to both sides.


24x=20-3 Combine like terms on the left side.


24x=17 Combine like terms on the right side.


x=%2817%29%2F%2824%29 Divide both sides by 24 to isolate x.


----------------------------------------------------------------------

Answer:

So the solution is x=17%2F24 which approximates to x=0.708.




# 3


2-8%28x%2B3%29%3C-38-3%28x%2B8%29%2B3x Start with the given inequality.


2-8x-24%3C-38-3x-24%2B3x Distribute.


-8x-22%3C-38-3x-24%2B3x Combine like terms on the left side.


-8x-22%3C-62 Combine like terms on the right side.


-8x%3C-62%2B22 Add 22 to both sides.


-8x%3C-40 Combine like terms on the right side.


x%3E%28-40%29%2F%28-8%29 Divide both sides by -8 to isolate x. note: Remember, the inequality sign flips when we divide both sides by a negative number.


x%3E5 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is x%3E5


expressions/242461: evaluate the factorial expression 409!/408!
1 solutions

Answer 177478 by jim_thompson5910(28476) About Me  on 2009-11-24 14:56:57 (Show Source):
You can put this solution on YOUR website!
Because 409! and 408! are huge numbers, we can't directly calculate them. However, we can note that 409!=409*408!


So (409!)/(408!)=(409*408!)/(408!)=409

or in short, (409!)/(408!)=409


Polynomials-and-rational-expressions/242463: Multiply. thanks
(7m + 9)(8m^2 + m + 7)
1 solutions

Answer 177477 by jim_thompson5910(28476) About Me  on 2009-11-24 14:55:02 (Show Source):
You can put this solution on YOUR website!

%287m%2B9%29%288m%5E2%2Bm%2B7%29 Start with the given expression.


7m%288m%5E2%2Bm%2B7%29%2B9%288m%5E2%2Bm%2B7%29 Expand.


Distribute.


56m%5E3%2B7m%5E2%2B49m%2B72m%5E2%2B9m%2B63 Multiply.


56m%5E3%2B79m%5E2%2B58m%2B63 Now combine like terms.


So %287m%2B9%29%288m%5E2%2Bm%2B7%29 expands to 56m%5E3%2B79m%5E2%2B58m%2B63.


In other words, %287m%2B9%29%288m%5E2%2Bm%2B7%29=56m%5E3%2B79m%5E2%2B58m%2B63.


Polynomials-and-rational-expressions/242287: find the roots of 2x squared -5x+1=0
1 solutions

Answer 177366 by jim_thompson5910(28476) About Me  on 2009-11-23 23:07:19 (Show Source):
You can put this solution on YOUR website!

2x%5E2-5x%2B1=0 Start with the given equation.


Notice that the quadratic 2x%5E2-5x%2B1 is in the form of Ax%5E2%2BBx%2BC where A=2, B=-5, and C=1


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2-4%282%29%281%29+%29%29%2F%282%282%29%29 Plug in A=2, B=-5, and C=1


x+=+%285+%2B-+sqrt%28+%28-5%29%5E2-4%282%29%281%29+%29%29%2F%282%282%29%29 Negate -5 to get 5.


x+=+%285+%2B-+sqrt%28+25-4%282%29%281%29+%29%29%2F%282%282%29%29 Square -5 to get 25.


x+=+%285+%2B-+sqrt%28+25-8+%29%29%2F%282%282%29%29 Multiply 4%282%29%281%29 to get 8


x+=+%285+%2B-+sqrt%28+17+%29%29%2F%282%282%29%29 Subtract 8 from 25 to get 17


x+=+%285+%2B-+sqrt%28+17+%29%29%2F%284%29 Multiply 2 and 2 to get 4.


x+=+%285%2Bsqrt%2817%29%29%2F%284%29 or x+=+%285-sqrt%2817%29%29%2F%284%29 Break up the expression.


So the solutions are x+=+%285%2Bsqrt%2817%29%29%2F%284%29 or x+=+%285-sqrt%2817%29%29%2F%284%29


which approximate to x=2.281 or x=0.219


Equations/242074: how do you solve something like this 6-b=5b+30?
1 solutions

Answer 177226 by jim_thompson5910(28476) About Me  on 2009-11-23 16:03:27 (Show Source):
You can put this solution on YOUR website!

6-b=5b%2B30 Start with the given equation.


-b=5b%2B30-6 Subtract 6 from both sides.


-b-5b=30-6 Subtract 5b from both sides.


-6b=30-6 Combine like terms on the left side.


-6b=24 Combine like terms on the right side.


b=%2824%29%2F%28-6%29 Divide both sides by -6 to isolate b.


b=-4 Reduce.


----------------------------------------------------------------------

Answer:

So the solution is b=-4


logarithm/242094: I need help on how to solve a logarithmic Equation. The question is
3 Log (base 2) x+1 = 7
When I tried putting this equation into exponential form, I got

2^7 = (x+1)^3. However, when I solved for this, I did not end up with
the answer that is needed. I ended up looking up the answer in the back of the book so that i could see if i could backtrack from there, but it was simply 4.
Thanks,
dmc93x@yahoo.com
1 solutions

Answer 177224 by jim_thompson5910(28476) About Me  on 2009-11-23 16:00:07 (Show Source):
You can put this solution on YOUR website!
3%2Alog%282%2C%28x%29%29%2B1=7 Start with the given equation.


3%2Alog%282%2C%28x%29%29=7-1 Subtract 1 from both sides.


3%2Alog%282%2C%28x%29%29=6 Combine like terms.


log%282%2C%28x%29%29=6%2F3 Divide both sides by 3.


log%282%2C%28x%29%29=2 Reduce


x=2%5E2 Convert to exponential form.


x=4 Square 2 to get 4.


So the solution is x=4


Linear_Equations_And_Systems_Word_Problems/241772: The quotient of a number and 3 is 16
1 solutions

Answer 177065 by jim_thompson5910(28476) About Me  on 2009-11-22 18:12:50 (Show Source):
You can put this solution on YOUR website!
"The quotient of a number and 3 is 16" translates to x%2F3=16. I'll let you take it from here.