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27270..27299 , 27300..27329 , 27330..27359 , 27360..27389 , 27390..27419 , 27420..27449 , 27450..27479 , 27480..27509 , 27510..27539 , 27540..27569 , 27570..27599 , 27600..27629 , 27630..27659 , 27660..27689 , 27690..27719 , 27720..27749 , 27750..27779 , 27780..27809 , 27810..27839 , 27840..27869 , 27870..27899 , 27900..27929 , 27930..27959 , 27960..27989 , 27990..28019 , 28020..28049 , 28050..28079 , 28080..28109 , 28110..28139 , 28140..28169 , 28170..28199 , 28200..28229 , 28230..28259 , 28260..28289 , 28290..28319 , 28320..28349 , 28350..28379 , 28380..28409 , 28410..28439 , 28440..28469 , 28470..28499 , 28500..28529, >>NextExponential-and-logarithmic-functions/274779: Can someone please explain why logbx/ logby does not equal logbx - logby? 1 solutions
Answer 200502 by jim_thompson5910(28536) on 2010-02-27 00:20:19 (Show Source):
You can put this solution on YOUR website!To prove something false, we usually resort to a counterexample. A counterexample is an explicit example in which proves a theorem or equation false (usually by a contradiction of some sort).
So let's say that  and  . This would then mean that
Now plug  and  into  to get
So in short,  and  when  and  .
Clearly  which means that  when  and  .
---------------------------------------------------------------
Here's another way of looking at it.
By the change of base formula,
By another identity,
So let's assume that  . If this is the case, then
Equate the bases and arguments to get  and  . The second equation simplifies to  . Solve for b to get  .
Now if  , this means that  which is impossible (you can't divide by zero).
|
Points-lines-and-rays/274776: I am having a hard time with my Geomarty homework I would really like if i were to get some kind of help. The question on the homework says...
1.Draw the following triangle A(-3,2) B(9,2) C(3,-6) 1 solutions
Answer 200500 by jim_thompson5910(28536) on 2010-02-27 00:01:21 (Show Source):
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Points-lines-and-rays/274778: Whats the distance between (4,4) and (7,8) 1 solutions
Answer 200499 by jim_thompson5910(28536) on 2010-02-26 23:51:12 (Show Source):
You can put this solution on YOUR website!Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the distance formula.
 Plug in  ,  ,  , and  .
 Subtract  from  to get  .
 Subtract  from  to get  .
 Square  to get  .
 Square  to get  .
 Add  to  to get  .
 Take the square root of  to get  .
So our answer is
So the distance between the two points is 5 units.
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Linear-equations/274739: Find the equation of the line through the points (-3,-1) and (-9,-6) 1 solutions
Answer 200469 by jim_thompson5910(28536) on 2010-02-26 20:14:43 (Show Source):
You can put this solution on YOUR website!First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
------------------------------------------------------------------------------------------------
Now remember that the general slope intercept equation is  where 'm' is the slope of the line and 'b' is the y-intercept. We can use this general equation to find the equation of the line.
Since the line goes through the point (-3,-1), this means that x=-3 and y=-1. In addition, we know that the slope is  . So we can use these values to solve for 'b'.
 Start with the general slope-intercept equation.
 Plug in  ,  and
 Multiply.
 Reduce.
 Add  to both sides to isolate 'b'
 Combine like terms.
So the value of 'b' is
Since  and  , we can plug these values into  to get
======================================================================
Answer:
So the equation of the line in slope-intercept form through the points (-3,-1) and (-9,-6) is
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Functions/274719: Determine whether the correspondence is a function.
Celebrity~~~~~~~~~~~~~~~~ Birthday
Sigourney Weaver~~~~~~~~~~~ October 8
Jesse Jackson~~~~~~~~~~~~ October 8
Chevy Chase ~~~~~~~~~~~~~~ October 8
Muhammad Ali~~~~~~~~~~~~January 17
Jim Carrey~~~~~~~~~~~~~~January 17
Thank you for your help! 1 solutions
Answer 200447 by jim_thompson5910(28536) on 2010-02-26 19:19:26 (Show Source):
You can put this solution on YOUR website!Since each celebrity has ONLY ONE birthday, this means that each input (celebrity) has ONLY ONE output (birthday). So this relation is a function.
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Linear-equations/274720: I need to find an equation of the line containing the given pair of points; (-3,-1) and (-9,-6). The equation of the line in the slope-intercept is y=?
m=y2-y1= -6-(-1)= -5
x2-x1 -9-(-3) -6
y-(-1)=m(x-x1)
y-(-1)=-5(x-(-3))
-6
y-(-1)=-5x-5
-6 2
y=-5 -3
6x 2
Apparently I did this wrong somewhere and I am not sure what I did wrong. Can someone help me please. 1 solutions
Answer 200446 by jim_thompson5910(28536) on 2010-02-26 19:17:54 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Rewrite  as
 Distribute
 Multiply
 Subtract 1 from both sides.
 Combine like terms. note: If you need help with fractions, check out this solver.
So the equation that goes through the points ) and ) is
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Graphs/274663: what is the euclidean distance from the point (3,5) to the line y=2x 1 solutions
Answer 200418 by jim_thompson5910(28536) on 2010-02-26 16:16:50 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Finding a distance between a point given by coordinates (x, y) and a line given by equation y=ax+b |
We want to find the perpendicular distance between a point given by coordinates ( , )
and a line given by equation 
First, let's draw a diagram of general situation with point P (xo, yo) and
line L: y= a.x + b. The required distance is PC. (in the diagram below)
Methodology
We will first find the vertices of the triangle in order to get the side lengths and then by applying
Sine Rule on right angle triangle PAB and PBC we will calculate the desired distance PC.
Step1
Calculation of the vertices of triangle PAB:
Draw a vertical line passing through the point 'P'. This line will cut the given line 'L'
at point 'A'. The X coordinate of A(x1) will be same as . To find the Y-coordinate of
'A' we will use the fact that point 'A' lies on the given line 'L' and satisfies the equation
of the line 'L' .
Now, plug this in to the equation of line: y=2*x+0


Hence, Point (A)( , )
Similarly,
Draw a horizontal line passing through the point 'P'. This line will cut the given line 'L'
at point 'B'. The Y coordinate of B(y2) will be same as . To find the X-coordinate of
B we will use the fact that point 'B' lies on the given line 'L' and satisfies the equation
of the line 'L' .
Now, plug this in to the equation of line: y=2*x+0



Hence, Point (B)( , )
Now, we have all the vertices of the triangle PAB
Step2
Calculation of the side lengths using distance formula:

Hence, The side lengths PA, PB and AB are



Step3
Apply Sine rule on common angle B in triangle PAB and triangle PBC.
Both triangle PAB and triangle PBC are right angle triangle and points 'A', 'B' and 'C' lay on the given line L.


PC is the required perpendicular distance of the point P (3, 5) from line given
lineL1: y=2*x+0.
For better understanding of this concept, look at the Lesson based on the above concept.
Lesson |
So the distance is approximately  units.
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Matrices-and-determiminant/274496: Use Cramer's rule to solve the systems:
1. 2x-9y-z=-72
x+3y+4z=51
-6x+y+z=-4
2. 4x+6y=14
2x+y=-3 1 solutions
Answer 200314 by jim_thompson5910(28536) on 2010-02-26 01:40:09 (Show Source):
You can put this solution on YOUR website!# 1
| Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 3 variables |

First let . This is the matrix formed by the coefficients of the given system of equations.
Take note that the right hand values of the system are , , and and they are highlighted here:

These values are important as they will be used to replace the columns of the matrix A.
Now let's calculate the the determinant of the matrix A to get . To save space, I'm not showing the calculations for the determinant. However, if you need help with calculating the determinant of the matrix A, check out this solver.
Notation note: denotes the determinant of the matrix A.
---------------------------------------------------------
Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix (since we're replacing the 'x' column so to speak).

Now compute the determinant of to get . Again, as a space saver, I didn't include the calculations of the determinant. Check out this solver to see how to find this determinant.
To find the first solution, simply divide the determinant of by the determinant of to get: 
So the first solution is 
---------------------------------------------------------
We'll follow the same basic idea to find the other two solutions. Let's reset by letting again (this is the coefficient matrix).
Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix (since we're replacing the 'y' column in a way).

Now compute the determinant of to get .
To find the second solution, divide the determinant of by the determinant of to get: 
So the second solution is 
---------------------------------------------------------
Let's reset again by letting which is the coefficient matrix.
Replace the third column of A (that corresponds to the variable 'z') with the values that form the right hand side of the system of equations. We will denote this new matrix

Now compute the determinant of to get .
To find the third solution, divide the determinant of by the determinant of to get: 
So the third solution is 
====================================================================================
Final Answer:
So the three solutions are , , and giving the ordered triple (3, 8, 6)
Note: there is a lot of work that is hidden in finding the determinants. Take a look at this 3x3 Determinant Solver to see how to get each determinant.
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# 2
| Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 2 variables |

First let . This is the matrix formed by the coefficients of the given system of equations.
Take note that the right hand values of the system are and which are highlighted here:

These values are important as they will be used to replace the columns of the matrix A.
Now let's calculate the the determinant of the matrix A to get . Remember that the determinant of the 2x2 matrix is . If you need help with calculating the determinant of any two by two matrices, then check out this solver.
Notation note: denotes the determinant of the matrix A.
---------------------------------------------------------
Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix (since we're replacing the 'x' column so to speak).

Now compute the determinant of to get . Once again, remember that the determinant of the 2x2 matrix is 
To find the first solution, simply divide the determinant of by the determinant of to get: 
So the first solution is 
---------------------------------------------------------
We'll follow the same basic idea to find the other solution. Let's reset by letting again (this is the coefficient matrix).
Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix (since we're replacing the 'y' column in a way).

Now compute the determinant of to get .
To find the second solution, divide the determinant of by the determinant of to get: 
So the second solution is 
====================================================================================
Final Answer:
So the solutions are and giving the ordered pair (-4, 5)
Once again, Cramer's Rule is dependent on determinants. Take a look at this 2x2 Determinant Solver if you need more practice with determinants.
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real-numbers/274513: Hello,
I am having a question on 1 problem for my online Algebra class that just are not clicking in my head. I have tried to do them several times. I would really appreciate if you could help with these two :)
Thank You
it read a-2/5 + a-3/4 = 6/5
1 solutions
Answer 200312 by jim_thompson5910(28536) on 2010-02-26 01:37:15 (Show Source):
You can put this solution on YOUR website!I'm assuming that the problem is
 Start with the given equation.
 Multiply both sides by the LCD  to clear any fractions.
 Distribute and multiply.
 Combine like terms on the left side.
 Add  to both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
----------------------------------------------------------------------
Answer:
So the solution is  which approximates to  .
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Expressions-with-variables/274504: After you show me how to solve this question I can help my son complete the rest. Luke has $5 more than sam. Together they have $73. How much does each have? 1 solutions
Answer 200306 by jim_thompson5910(28536) on 2010-02-26 00:25:45 (Show Source):
You can put this solution on YOUR website!Let x = amount that luke has and y = amount that sam has
So "Luke has $5 more than sam" means that  and "Together they have $73" tells us that
 Start with the given equation.
 Plug in
 Combine like terms on the left side.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
So this means that sam has $34
 Go back to the first equation
 Plug in
 Add
So this means that Luke has $39
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Polynomials-and-rational-expressions/274509: I can't find two numbers that multiplied give me negative 270 and added give me negative 49 1 solutions
Answer 200304 by jim_thompson5910(28536) on 2010-02-26 00:20:11 (Show Source):
You can put this solution on YOUR website!Let's list all of the factors of  (the product needed).
Factors of  :
1,2,3,5,6,9,10,15,18,27,30,45,54,90,135,270
-1,-2,-3,-5,-6,-9,-10,-15,-18,-27,-30,-45,-54,-90,-135,-270
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-270) = -270
2*(-135) = -270
3*(-90) = -270
5*(-54) = -270
6*(-45) = -270
9*(-30) = -270
10*(-27) = -270
15*(-18) = -270
(-1)*(270) = -270
(-2)*(135) = -270
(-3)*(90) = -270
(-5)*(54) = -270
(-6)*(45) = -270
(-9)*(30) = -270
(-10)*(27) = -270
(-15)*(18) = -270
Now let's add up each pair of factors to see if one pair adds to  :
| First Number | Second Number | Sum | | 1 | -270 | 1+(-270)=-269 | | 2 | -135 | 2+(-135)=-133 | | 3 | -90 | 3+(-90)=-87 | | 5 | -54 | 5+(-54)=-49 | | 6 | -45 | 6+(-45)=-39 | | 9 | -30 | 9+(-30)=-21 | | 10 | -27 | 10+(-27)=-17 | | 15 | -18 | 15+(-18)=-3 | | -1 | 270 | -1+270=269 | | -2 | 135 | -2+135=133 | | -3 | 90 | -3+90=87 | | -5 | 54 | -5+54=49 | | -6 | 45 | -6+45=39 | | -9 | 30 | -9+30=21 | | -10 | 27 | -10+27=17 | | -15 | 18 | -15+18=3 |
From the table, we can see that the two numbers  and  add to  . Since each pair multiplies to -270, this means that 5 and -54 also multiply to -270.
So the two numbers 5 and -54 both add to -49 and multiply to -270.
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Inequalities/274500: How do I graph this inequality and what is the solution?
y < 4x - 3
x - y _>_ -12
Note: _>_ Means that the sign is underline, meaning "Or equal to."
How would I graph this inequality and what is the estimated point of solution?
I already know that one line produces as true while the other produces a false answer when I substitute it with (0, 0). This leaves me stumped on where to shade, since it is an inequality.
I also need to include a point of solution, and this inequality doesn't appear to have any...
Thank you for any help. 1 solutions
Answer 200302 by jim_thompson5910(28536) on 2010-02-26 00:16:26 (Show Source):
You can put this solution on YOUR website!Start with the given system of inequalities
In order to graph this system of inequalities, we need to graph each inequality one at a time.
First lets graph the first inequality
In order to graph  , we need to graph the equation  (just replace the inequality sign with an equal sign).
So lets graph the line  (note: if you need help with graphing, check out this solver)
graph of
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality with the test point
Substitute (0,0) into the inequality
Plug in and
Simplify
Since this inequality is not true, we do not shade the entire region that contains (0,0). So this means we shade the region that is on the opposite side of the line
Graph of with the boundary (which is the line in red) and the shaded region (in green)
(note: since the inequality contains a less-than sign, this means the boundary is excluded. This means the solid red line is really a dashed line)
---------------------------------------------------------------
Now lets graph the second inequality
In order to graph , we need to graph the equation (just replace the inequality sign with an equal sign).
So lets graph the line (note: if you need help with graphing, check out this solver)
graph of
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality with the test point
Substitute (0,0) into the inequality
Plug in and
Simplify
Since this inequality is true, we simply shade the entire region that contains (0,0)
Graph of with the boundary (which is the line in red) and the shaded region (in green)
---------------------------------------------------------------
So we essentially have these 2 regions:
Region #1
Graph of
Region #2
Graph of
When these inequalities are graphed on the same coordinate system, the regions overlap to produce this region. It's a little hard to see, but after evenly shading each region, the intersecting region will be the most shaded in.
Here is a cleaner look at the intersection of regions
Here is the intersection of the 2 regions represented by the series of dots
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Matrices-and-determiminant/274498: Evaluate the determinant:
|3 3 4|
|6 1 2|
|3 2 2| 1 solutions
Answer 200301 by jim_thompson5910(28536) on 2010-02-26 00:06:00 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Finding the Determinant of a 3x3 Matrix |
If you have the general 3x3 matrix:

the determinant is: 
Which further breaks down to:

Note: , and are determinants themselves. If you need help finding the determinant of 2x2 matrices (which is required to find the determinant of 3x3 matrices), check out this solver
--------------------------------------------------------------
From the matrix , we can see that , , , , , , , , and 
Start with the general 3x3 determinant.
Plug in the given values (see above)
Multiply
Subtract
Multiply
Combine like terms.
======================================================================
Answer:
So , which means that the determinant of the matrix is 
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Polynomials-and-rational-expressions/274372: Thanks in advance for your help...
Here's my problem-
The product of two consecutive positive odd integers is 38 less than the square of the greater integer. Find the integers.
Now I know that product means mulitiplication so I thought I set the problem up as such:
x(x+2)= (x+2)^2-38.
Would this be correct? 1 solutions
Answer 200250 by jim_thompson5910(28536) on 2010-02-25 19:37:47 (Show Source):
You can put this solution on YOUR website!You have the right equation. Now let's solve for 'x'.
 Start with the given equation.
 Distribute
 FOIL
 Subtract  from both sides.
 Combine like terms on the right side.
 Subtract  from both sides.
 Combine like terms on the left side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
So the two numbers are 17 and 19.
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Polynomials-and-rational-expressions/274329: x^2+10x-128. I've had this problem a few times now (I'm a tutor myself) and it asks to solve for x. I just cannot factor this. Please help me refresh my algebra skills and help me find a way to solve for x on this one. Thank you. 1 solutions
Answer 200222 by jim_thompson5910(28536) on 2010-02-25 18:19:03 (Show Source):
You can put this solution on YOUR website!For more factoring help, check out this quadratic formula solver.
| Solved by pluggable solver: Factoring using the AC method (Factor by Grouping) |
In order to factor , first multiply the leading coefficient 1 and the last term -128 to get -128. Now we need to ask ourselves: What two numbers multiply to -128 and add to 10? Lets find out by listing all of the possible factors of -128
Factors:
1,2,4,8,16,32,64,128,
-1,-2,-4,-8,-16,-32,-64,-128, List the negative factors as well. This will allow us to find all possible combinations
These factors pair up to multiply to -128.
(-1)*(128)=-128
(-2)*(64)=-128
(-4)*(32)=-128
(-8)*(16)=-128
Now which of these pairs add to 10? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 10
| First Number | | | Second Number | | | Sum | | 1 | | | -128 | || | 1+(-128)=-127 | | 2 | | | -64 | || | 2+(-64)=-62 | | 4 | | | -32 | || | 4+(-32)=-28 | | 8 | | | -16 | || | 8+(-16)=-8 | | -1 | | | 128 | || | (-1)+128=127 | | -2 | | | 64 | || | (-2)+64=62 | | -4 | | | 32 | || | (-4)+32=28 | | -8 | | | 16 | || | (-8)+16=8 |
None of these factors add to 10. So the quadratic cannot be factored. | |
So you must use the quadratic formula
So let's use the quadratic formula to solve
For more help with the quadratic formula, check out this quadratic formula solver.
| Solved by pluggable solver: Quadratic Formula |
Let's use the quadratic formula to solve for x:
Starting with the general quadratic

the general solution using the quadratic equation is:

So lets solve ( notice , , and )
Plug in a=1, b=10, and c=-128
Square 10 to get 100
Multiply to get 
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or 
Now break up the fraction
or 
Simplify
or 
So the solutions are:
or 
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Polynomials-and-rational-expressions/274297: Hi. I'm trying to solve 2xy+5x-2y-5 over 3xy+4x-3y-4. Thank you! 1 solutions
Answer 200197 by jim_thompson5910(28536) on 2010-02-25 17:13:49 (Show Source):
You can put this solution on YOUR website!The key to this problem is factoring
Let's factor
 Start with the given expression.
 Group the terms.
 Factor out the GCF 'x' from the first group.
 Factor out the GCF -1 from the second group.
 Factor out the GCF  from the entire expression.
So  factors to
--------------------------------
Now let's factor
 Start with the given expression.
 Group the terms.
 Factor out the GCF 'x' from the first group.
 Factor out the GCF -1 from the second group.
 Factor out the GCF  from the entire expression.
So  factors to
------------------------------------------------
Now that we have the factorizations, we can now simplify:
 Start with the given expression.
 Factor the numerator (see the first factorization above)
 Factor the denominator (see the second factorization above)
 Highlight the common terms.
 Cancel out the common terms.
 Simplify.
So  simplifies to
In other words,
Note: One thing to point out is that the value of 'x' does not affect the final outcome of the expression since the 'x' terms cancel out. This isn't so obvious when you look at the original expression, but it becomes clear when we reach the last step.
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Polynomials-and-rational-expressions/274285: please help solve this problem
11/2x + 4/7x
I know first you find the LCD which is 14x but i don't know what you do after this
11/2x *14 + 4/7x *14 1 solutions
Answer 200188 by jim_thompson5910(28536) on 2010-02-25 16:50:40 (Show Source):
You can put this solution on YOUR website! Start with the given expression.
 Multiply both the numerator and denominator of the first fraction by  (to get the denominator equal to the LCD)
 Multiply both the numerator and denominator of the second fraction by  (to get the denominator equal to the LCD)
 Multiply.
 Combine the fractions (this is now possible since the denominators are now equal).
 Add
So  where
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Linear-equations/273995: Put the equation 2x - 3y = 15 into slope-intercept form. Think you get two answers...right 1 solutions
Answer 200032 by jim_thompson5910(28536) on 2010-02-24 21:48:07 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Subtract  from both sides.
 Rearrange the terms.
 Divide both sides by  to isolate y.
 Break up the fraction.
 Reduce.
So the equation  is now in slope intercept form  where the slope is  and the y-intercept is  note: the y-intercept is the point
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Exponents/273983: My daughter is very confused by this problem: Is there any difference between
-(3)(squared) and -3 (squared)? 1 solutions
Answer 200028 by jim_thompson5910(28536) on 2010-02-24 21:40:33 (Show Source):
You can put this solution on YOUR website!If you're talking about  and  , then the answer is no. There is no difference between  and  since  and
However, if you're talking about  and  , then there is a difference since  and
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Functions/273851: I am completely stumped on this question.
Given (f+g)(x)=10-3x and (f-g)(x)=5x-14, find f(x) and g(x).
Thanks so much. 1 solutions
Answer 200001 by jim_thompson5910(28536) on 2010-02-24 17:52:33 (Show Source):
You can put this solution on YOUR website!Since  , this means that  . Solve for 'f(x)' to get
Also, because  , we know that
Now plug  into  to get
Combine like terms to get
From here, simply solve for 'g(x)' (think of g(x) as any other variable). Once you have g(x), use that to find f(x).
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Rational-functions/273823: Given that 
find f(-1)
find f(x+1)
find f(x+h)
I have spent a lot of time on these problems, and I must be missing something because I cannot get them right.
My answer for the second one was 
for the third one was 
My answer for the first was the most confusing of all, depending on whether I entered it entirely into my calculator, and if I broke the problem into segments ( vs my answer changed. The first was 11, the second was -3. 1 solutions
Answer 199993 by jim_thompson5910(28536) on 2010-02-24 17:18:08 (Show Source):
You can put this solution on YOUR website!# 1
 Start with the given equation.
 Plug in  .
 Square  to get  .
 Multiply  and  to get  .
 Multiply  and  to get  .
 Combine like terms.
------------------------------------------------------------------------
# 2
 Start with the given equation.
 Replace each 'x' with 'x+1'.
 FOIL
 Distribute
 Combine like terms.
------------------------------------------------------------------------
# 3
 Start with the given equation.
 Replace each 'x' with 'x+h'.
 FOIL
 Distribute
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