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Equations/277025: How could I solve this equation dealing with fractions.
x/x+4 - 2 = 12/x-12 1 solutions
Answer 201760 by jim_thompson5910(28504) on 2010-03-04 01:12:41 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Multiply EVERY term by the LCD  to clear out the fractions.
 Simplify
 Rearrange the terms.
 FOIL
 Distribute
 Get every term to the left side.
 Combine like terms.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "x":
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the solutions are  or
I'll let you check these solutions.
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Quadratic_Equations/277032: trying to solve a velocity equation where s=4.9t^2+Vot
Velocity = Vo = 20m/s
Height = s = 158.4m
time = t = which is what we are solving for
so...
I got as far as 4.9t^2 + 20t - 158.4=0 1 solutions
Answer 201758 by jim_thompson5910(28504) on 2010-03-04 01:06:29 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Multiply every term by 10 to make every number a whole number (ie move the decimal one spot to the right).
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "t":
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the possible solutions are  or
However, since a negative time value doesn't make any sense, we must ignore the value
So the only solution is
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absolute-value/276997: |7-10|-|-5| =-2
(I don't understand and I can not work out how this equation works at all. 1 solutions
Answer 201752 by jim_thompson5910(28504) on 2010-03-03 23:49:47 (Show Source):
You can put this solution on YOUR website!First, 7-10 = -3, but remember that the absolute value of any number is positive. So |7 - 10| = |-3| = 3
This also applies to |-5| which means that |-5|=5
Put this all together to get:
|7 - 10| - | -5 | = | -3 | - | -5 | = 3 - 5 = -2
In the end, |7 - 10| - | -5 | = -2
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Quadratic_Equations/277006: What is 6x^2-8xy-8y^2 equal to?
My book states the answer to be (3x+2y)(2x-4y), how do I get to this answer? 1 solutions
Answer 201751 by jim_thompson5910(28504) on 2010-03-03 23:46:07 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression
 Factor out the GCF
Now let's focus on the inner expression
------------------------------------------------------------
Looking at  we can see that the first term is  and the last term is  where the coefficients are 3 and -4 respectively.
Now multiply the first coefficient 3 and the last coefficient -4 to get -12. Now what two numbers multiply to -12 and add to the middle coefficient -4? Let's list all of the factors of -12:
Factors of -12:
1,2,3,4,6,12
-1,-2,-3,-4,-6,-12 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -12
(1)*(-12)
(2)*(-6)
(3)*(-4)
(-1)*(12)
(-2)*(6)
(-3)*(4)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -4
| First Number | Second Number | Sum | | 1 | -12 | 1+(-12)=-11 | | 2 | -6 | 2+(-6)=-4 | | 3 | -4 | 3+(-4)=-1 | | -1 | 12 | -1+12=11 | | -2 | 6 | -2+6=4 | | -3 | 4 | -3+4=1 |
From this list we can see that 2 and -6 add up to -4 and multiply to -12
Now looking at the expression  , replace  with  (notice  combines back to  . So it is equivalent to  )
Now let's factor  by grouping:
 Group like terms
 Factor out the GCF of  out of the first group. Factor out the GCF of  out of the second group
 Since we have a common term of  , we can combine like terms
So  factors to
So this also means that  factors to  (since  is equivalent to  )
------------------------------------------------------------
So our expression goes from  and factors further to
------------------
Answer:
So  factors to
Note: if you distribute the 2 into the first group, you get  .
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Quadratic_Equations/276999: Put the equation 5x^2-10x-2 in turning point form a(x-h)^2+k, by completing the square. 1 solutions
Answer 201749 by jim_thompson5910(28504) on 2010-03-03 23:36:25 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Factor out the  coefficient  . This step is very important: the  coefficient must be equal to 1.
Take half of the  coefficient  to get  . In other words,  .
Now square  to get  . In other words,
 Now add and subtract  inside the parenthesis. Make sure to place this after the "x" term. Notice how  . So the expression is not changed.
 Group the first three terms.
 Factor  to get  .
 Combine like terms.
 Distribute.
 Multiply.
So after completing the square,  transforms to  . So  .
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Polynomials-and-rational-expressions/276797: Factor.
2y^2+17y+30 1 solutions
Answer 201671 by jim_thompson5910(28504) on 2010-03-03 18:05:18 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,5,6,10,12,15,20,30,60
-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*60 = 60
2*30 = 60
3*20 = 60
4*15 = 60
5*12 = 60
6*10 = 60
(-1)*(-60) = 60
(-2)*(-30) = 60
(-3)*(-20) = 60
(-4)*(-15) = 60
(-5)*(-12) = 60
(-6)*(-10) = 60
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 60 | 1+60=61 | | 2 | 30 | 2+30=32 | | 3 | 20 | 3+20=23 | | 4 | 15 | 4+15=19 | | 5 | 12 | 5+12=17 | | 6 | 10 | 6+10=16 | | -1 | -60 | -1+(-60)=-61 | | -2 | -30 | -2+(-30)=-32 | | -3 | -20 | -3+(-20)=-23 | | -4 | -15 | -4+(-15)=-19 | | -5 | -12 | -5+(-12)=-17 | | -6 | -10 | -6+(-10)=-16 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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sets-and-operations/276775: Find n(A) for the set.
A={1/2,1/3,1/4,1/5,...,1/29,1/30} 1 solutions
Answer 201649 by jim_thompson5910(28504) on 2010-03-03 17:36:09 (Show Source):
You can put this solution on YOUR website!Notice how there are 30 elements in the set {1, 2, 3, 4, 5,...,29, 30} by simply noting that 30-1+1=30 or that the elements are integers, start at 1 and end at 30.
Simply invert each element to get {1/1, 1/2, 1/3, 1/4, 1/5, ..., 1/29, 1/30} which is close to what we want, but we have to remove the element 1/1 to get {1/2, 1/3, 1/4, 1/5, ..., 1/29, 1/30}. Since we removed one element, we now have 29 elements in this set.
So n(A) = # of elements in set A = 29
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Inequalities/276649: 5(2k+3)-2(k-8)>3(2k+4)+k-2 1 solutions
Answer 201590 by jim_thompson5910(28504) on 2010-03-03 13:34:44 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Distribute.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Subtract 31 from both sides.
 Subtract 7k from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
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Answer:
So the solution is
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Inequalities/276626: plese explain how to solve the inequality
14x +4 <26x +20 1 solutions
Answer 201573 by jim_thompson5910(28504) on 2010-03-03 12:46:12 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Subtract 4 from both sides.
 Subtract 26x from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by -12 to isolate x. Remember that the inequality sign flips when you divide by a negative number.
 Reduce.
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Answer:
So the solution is
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Quadratic_Equations/276480: Please help me answer this question.
What are the linear factors of 12x^2+7x-12?
The answer given is 4x-3 and 3x+4.
I'm just not too sure how to get to this answer. 1 solutions
Answer 201553 by jim_thompson5910(28504) on 2010-03-03 12:15:49 (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: Factoring using the AC method (Factor by Grouping) |
In order to factor , first multiply the leading coefficient 12 and the last term -12 to get -144. Now we need to ask ourselves: What two numbers multiply to -144 and add to 7? Lets find out by listing all of the possible factors of -144
Factors:
1,2,3,4,6,8,9,12,16,18,24,36,48,72,144,
-1,-2,-3,-4,-6,-8,-9,-12,-16,-18,-24,-36,-48,-72,-144, List the negative factors as well. This will allow us to find all possible combinations
These factors pair up to multiply to -144.
(-1)*(144)=-144
(-2)*(72)=-144
(-3)*(48)=-144
(-4)*(36)=-144
(-6)*(24)=-144
(-8)*(18)=-144
(-9)*(16)=-144
(-12)*(12)=-144
Now which of these pairs add to 7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 7
| First Number | | | Second Number | | | Sum | | 1 | | | -144 | || | 1+(-144)=-143 | | 2 | | | -72 | || | 2+(-72)=-70 | | 3 | | | -48 | || | 3+(-48)=-45 | | 4 | | | -36 | || | 4+(-36)=-32 | | 6 | | | -24 | || | 6+(-24)=-18 | | 8 | | | -18 | || | 8+(-18)=-10 | | 9 | | | -16 | || | 9+(-16)=-7 | | 12 | | | -12 | || | 12+(-12)=0 | | -1 | | | 144 | || | (-1)+144=143 | | -2 | | | 72 | || | (-2)+72=70 | | -3 | | | 48 | || | (-3)+48=45 | | -4 | | | 36 | || | (-4)+36=32 | | -6 | | | 24 | || | (-6)+24=18 | | -8 | | | 18 | || | (-8)+18=10 | | -9 | | | 16 | || | (-9)+16=7 | | -12 | | | 12 | || | (-12)+12=0 |
We can see from the table that -9 and 16 add to 7. So the two numbers that multiply to -144 and add to 7 are: -9 and 16
So the original quadratic

breaks down to this (just replace with the two numbers that multiply to -144 and add to 7, which are: -9 and 16)
Replace with 
Group the first two terms together and the last two terms together like this:

Factor a 3x out of the first group and factor a 4 out of the second group.

Now since we have a common term we can combine the two terms.
Combine like terms.
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Answer:
So the quadratic factors to 
Notice how foils back to our original problem . This verifies our answer. | |
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Linear-equations/276245: need help with this problem
y= -1/5x + 4
1 solutions
Answer 201364 by jim_thompson5910(28504) on 2010-03-02 18:06:00 (Show Source):
You can put this solution on YOUR website!Are you trying to graph? If so, then...
Looking at  we can see that the equation is in slope-intercept form  where the slope is  and the y-intercept is
Since  this tells us that the y-intercept is ) .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is  , this means:
which shows us that the rise is -1 and the run is 5. This means that to go from point to point, we can go down 1 and over 5
So starting at ) , go down 1 unit
and to the right 5 units to get to the next point
Now draw a line through these points to graph
 So this is the graph of  through the points ) and
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Numeric_Fractions/276260: ok..i would like to know how to solve any fraction with an exponent for example: i started one and this is the question:(((6^8/6^6))) this is how far i got:(((6^14))) now what do i do.and what would i do if there was more than one number on the top and bottom of the fraction? thanks for the help! ;) 1 solutions
Answer 201362 by jim_thompson5910(28504) on 2010-03-02 18:04:24 (Show Source):
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Graphs/275934: Give the slope-intercept form of the equation for the line on which these two points lie: (4, -2) and (3, 8) 1 solutions
Answer 201187 by jim_thompson5910(28504) on 2010-03-01 21:43:15 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Distribute
 Multiply
 Subtract 2 from both sides.
 Combine like terms.
So the equation that goes through the points ) and ) is
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Exponents/275351: Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.
5^x=32
I really don't even know what the question is asking me to do. Please help! 1 solutions
Answer 200851 by jim_thompson5910(28504) on 2010-02-28 19:51:58 (Show Source):
You can put this solution on YOUR website!The goal here is to solve for 'x' in terms of either 'a' or 'b' (or both). In other words, have a solution of x = (something with 'a's and/or 'b's in it)
You have to play with it a bit, but it turns out that we never use  . So let's just work with
First convert  into logarithmic form to get  . Now use the change of base formula to get
Now move onto  and convert that into logarithmic form to get  . Rewrite 32 as  to get
Now pull down the exponent to get  and use the change of base formula:  . Take note how this is very similar to  but this just has the reverse of that expression and an extra '5' in there. If we invert 'a', we then get  which is the missing piece.
So
So the solution, in terms of 'a', is
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Numbers_Word_Problems/275343: The sum of three consecutive even numbers is 150. Find the numbers. I have tried tried a + b+c = 150. I have also tried. (x+1)+(x+2)+(x+3). I don't think I am doin this problem right. However, I know the consecutive even numbers before 150 are 148, 146, 144..Help.
Dawn 1 solutions
Answer 200844 by jim_thompson5910(28504) on 2010-02-28 19:22:14 (Show Source):
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Rational-functions/275270: I have two questions on the equations of lines.
1)Write an equation of a line passing through the points (-3,5) and (2,-7)
2) Write an equation of the line perpendicular to the line 2x-4y=7 and passing through (2,-5)
I am slightly perplexed, thanks in advance. 1 solutions
Answer 200790 by jim_thompson5910(28504) on 2010-02-28 16:53:46 (Show Source):
You can put this solution on YOUR website!# 1
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Distribute
 Multiply
 Add 5 to both sides.
 Combine like terms. note: If you need help with fractions, check out this solver.
So the equation that goes through the points ) and ) is
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# 2
 Start with the given equation.
 Subtract  from both sides.
 Rearrange the terms.
 Divide both sides by  to isolate y.
 Break up the fraction.
 Reduce.
So the slope of  and  is
| Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line |
Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of , you can find the perpendicular slope by this formula:
where is the perpendicular slope
So plug in the given slope to find the perpendicular slope
When you divide fractions, you multiply the first fraction (which is really ) by the reciprocal of the second
Multiply the fractions.
So the perpendicular slope is 
So now we know the slope of the unknown line is (its the negative reciprocal of from the line ).
Also since the unknown line goes through (2,-5), we can find the equation by plugging in this info into the point-slope formula
Point-Slope Formula:
where m is the slope and ( , ) is the given point
Plug in , , and 
Distribute 
Multiply
Subtract from both sides to isolate y
Combine like terms
So the equation of the line that is perpendicular to and goes through ( , ) is 
So here are the graphs of the equations and 
graph of the given equation (red) and graph of the line (green) that is perpendicular to the given graph and goes through ( , )
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Equations/275281: Please help me solve this equation.. 3|-8x-9|=117 1 solutions
Answer 200788 by jim_thompson5910(28504) on 2010-02-28 16:49:22 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation
 Divide both sides by 3
Break up the absolute value (remember, if you have  , then  or  )
 or  Set the expression  equal to the original value 39 and it's opposite -39
Now lets focus on the first equation
 Add 9 to both sides
 Combine like terms on the right side
 Divide both sides by -8 to isolate x
 Reduce
Now lets focus on the second equation
 Add 9 to both sides
 Combine like terms on the right side
 Divide both sides by -8 to isolate x
 Divide
So the solutions to  are:
 and
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Quadratic_Equations/275259: Can someone explain how to find the zeroes of the following problem?
f(x) = 2x^2-x+4 1 solutions
Answer 200776 by jim_thompson5910(28504) on 2010-02-28 16:32:29 (Show Source):
You can put this solution on YOUR website!The zeros are the x values which make the equation  true.
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "x":
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
Recall that 'i' is the imaginary number and
 or  Break up the expression.
So the zeros are  or
Note: if you've never seen imaginary numbers before, then the answer is simply "no solutions"
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