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Graphs/277162: how do i solve a the problem 5/3(6)+8 what is the answer and is it a negative

1 solutions

Answer 201825 by jim_thompson5910(28504) About Me  on 2010-03-04 13:03:16 (Show Source):
You can put this solution on YOUR website!
If the expression is %285%2F3%29%286%29%2B8, then %285%2F3%29%286%29%2B8=%285%2A6%29%2F3%2B8=30%2F3%2B8=10%2B8=18


On the other hand, if the expression is 5%2F%283%286%29%29%2B8, then 5%2F%283%286%29%29%2B8=5%2F18%2B8=149%2F18


Or if the expression is 5%2F%283%286%29%2B8%29, then 5%2F%283%286%29%2B8%29=5%2F%2818%2B8%29=5%2F26

The answer will depend on the grouping of the terms.


Equations/277025: How could I solve this equation dealing with fractions.
x/x+4 - 2 = 12/x-12
1 solutions

Answer 201760 by jim_thompson5910(28504) About Me  on 2010-03-04 01:12:41 (Show Source):
You can put this solution on YOUR website!
x%2F%28x%2B4%29+-+2+=+12%2F%28x-12%29 Start with the given equation


Multiply EVERY term by the LCD %28x%2B4%29%28x-12%29 to clear out the fractions.


%28x-12%29%28x%29-+2%28x%2B4%29%28x-12%29=%28x%2B4%29%2812%29 Simplify


x%28x-12%29-+2%28x%2B4%29%28x-12%29=12%28x%2B4%29 Rearrange the terms.


x%28x-12%29-+2%28x%5E2-8x-48%29=12%28x%2B4%29 FOIL


x%5E2-12x-+2x%5E2%2B16x%2B96=12x%2B48 Distribute


x%5E2-12x-2x%5E2%2B16x%2B96-12x-48=0 Get every term to the left side.


-x%5E2-8x%2B48=0 Combine like terms.


Notice that the quadratic -x%5E2-8x%2B48 is in the form of Ax%5E2%2BBx%2BC where A=-1, B=-8, and C=48


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-8%29+%2B-+sqrt%28+%28-8%29%5E2-4%28-1%29%2848%29+%29%29%2F%282%28-1%29%29 Plug in A=-1, B=-8, and C=48


x+=+%288+%2B-+sqrt%28+%28-8%29%5E2-4%28-1%29%2848%29+%29%29%2F%282%28-1%29%29 Negate -8 to get 8.


x+=+%288+%2B-+sqrt%28+64-4%28-1%29%2848%29+%29%29%2F%282%28-1%29%29 Square -8 to get 64.


x+=+%288+%2B-+sqrt%28+64--192+%29%29%2F%282%28-1%29%29 Multiply 4%28-1%29%2848%29 to get -192


x+=+%288+%2B-+sqrt%28+64%2B192+%29%29%2F%282%28-1%29%29 Rewrite sqrt%2864--192%29 as sqrt%2864%2B192%29


x+=+%288+%2B-+sqrt%28+256+%29%29%2F%282%28-1%29%29 Add 64 to 192 to get 256


x+=+%288+%2B-+sqrt%28+256+%29%29%2F%28-2%29 Multiply 2 and -1 to get -2.


x+=+%288+%2B-+16%29%2F%28-2%29 Take the square root of 256 to get 16.


x+=+%288+%2B+16%29%2F%28-2%29 or x+=+%288+-+16%29%2F%28-2%29 Break up the expression.


x+=+%2824%29%2F%28-2%29 or x+=++%28-8%29%2F%28-2%29 Combine like terms.


x+=+-12 or x+=+4 Simplify.


So the solutions are x+=+-12 or x+=+4


I'll let you check these solutions.


Quadratic_Equations/277032: trying to solve a velocity equation where s=4.9t^2+Vot

Velocity = Vo = 20m/s
Height = s = 158.4m
time = t = which is what we are solving for
so...158.4=4.9t%5E2+%2B+20t
I got as far as 4.9t^2 + 20t - 158.4=0
1 solutions

Answer 201758 by jim_thompson5910(28504) About Me  on 2010-03-04 01:06:29 (Show Source):
You can put this solution on YOUR website!
4.9t%5E2+%2B+20t+-+158.4=0 Start with the given equation


49t%5E2+%2B+200t+-+1584=0 Multiply every term by 10 to make every number a whole number (ie move the decimal one spot to the right).


Notice that the quadratic 49t%5E2%2B200t-1584 is in the form of At%5E2%2BBt%2BC where A=49, B=200, and C=-1584


Let's use the quadratic formula to solve for "t":


t+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


t+=+%28-%28200%29+%2B-+sqrt%28+%28200%29%5E2-4%2849%29%28-1584%29+%29%29%2F%282%2849%29%29 Plug in A=49, B=200, and C=-1584


t+=+%28-200+%2B-+sqrt%28+40000-4%2849%29%28-1584%29+%29%29%2F%282%2849%29%29 Square 200 to get 40000.


t+=+%28-200+%2B-+sqrt%28+40000--310464+%29%29%2F%282%2849%29%29 Multiply 4%2849%29%28-1584%29 to get -310464


t+=+%28-200+%2B-+sqrt%28+40000%2B310464+%29%29%2F%282%2849%29%29 Rewrite sqrt%2840000--310464%29 as sqrt%2840000%2B310464%29


t+=+%28-200+%2B-+sqrt%28+350464+%29%29%2F%282%2849%29%29 Add 40000 to 310464 to get 350464


t+=+%28-200+%2B-+sqrt%28+350464+%29%29%2F%2898%29 Multiply 2 and 49 to get 98.


t+=+%28-200+%2B-+592%29%2F%2898%29 Take the square root of 350464 to get 592.


t+=+%28-200+%2B+592%29%2F%2898%29 or t+=+%28-200+-+592%29%2F%2898%29 Break up the expression.


t+=+%28392%29%2F%2898%29 or t+=++%28-792%29%2F%2898%29 Combine like terms.


t+=+4 or t+=+-396%2F49 Simplify.


So the possible solutions are t+=+4 or t+=+-396%2F49


However, since a negative time value doesn't make any sense, we must ignore the value t+=+-396%2F49


So the only solution is t+=+4


absolute-value/276997: |7-10|-|-5| =-2
(I don't understand and I can not work out how this equation works at all.
1 solutions

Answer 201752 by jim_thompson5910(28504) About Me  on 2010-03-03 23:49:47 (Show Source):
You can put this solution on YOUR website!
First, 7-10 = -3, but remember that the absolute value of any number is positive. So |7 - 10| = |-3| = 3

This also applies to |-5| which means that |-5|=5

Put this all together to get:

|7 - 10| - | -5 | = | -3 | - | -5 | = 3 - 5 = -2


In the end, |7 - 10| - | -5 | = -2


Quadratic_Equations/277006: What is 6x^2-8xy-8y^2 equal to?
My book states the answer to be (3x+2y)(2x-4y), how do I get to this answer?
1 solutions

Answer 201751 by jim_thompson5910(28504) About Me  on 2010-03-03 23:46:07 (Show Source):
You can put this solution on YOUR website!

6x%5E2-8xy-8y%5E2 Start with the given expression


2%283x%5E2-4xy-4y%5E2%29 Factor out the GCF 2


Now let's focus on the inner expression 3x%5E2-4xy-4y%5E2




------------------------------------------------------------



Looking at 3x%5E2-4xy-4y%5E2 we can see that the first term is 3x%5E2 and the last term is -4y%5E2 where the coefficients are 3 and -4 respectively.

Now multiply the first coefficient 3 and the last coefficient -4 to get -12. Now what two numbers multiply to -12 and add to the middle coefficient -4? Let's list all of the factors of -12:



Factors of -12:
1,2,3,4,6,12

-1,-2,-3,-4,-6,-12 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -12
(1)*(-12)
(2)*(-6)
(3)*(-4)
(-1)*(12)
(-2)*(6)
(-3)*(4)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to -4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -4


First NumberSecond NumberSum
1-121+(-12)=-11
2-62+(-6)=-4
3-43+(-4)=-1
-112-1+12=11
-26-2+6=4
-34-3+4=1





From this list we can see that 2 and -6 add up to -4 and multiply to -12


Now looking at the expression 3x%5E2-4xy-4y%5E2, replace -4xy with 2xy-6xy (notice 2xy-6xy combines back to -4xy. So it is equivalent to -4xy)

3x%5E2%2Bhighlight%282xy-6xy%29-4y%5E2


Now let's factor 3x%5E2%2B2xy-6xy-4y%5E2 by grouping:


%283x%5E2%2B2xy%29%2B%28-6xy-4y%5E2%29 Group like terms


x%283x%2B2y%29-2y%283x%2B2y%29 Factor out the GCF of x out of the first group. Factor out the GCF of -2y out of the second group


%28x-2y%29%283x%2B2y%29 Since we have a common term of 3x%2B2y, we can combine like terms

So 3x%5E2%2B2xy-6xy-4y%5E2 factors to %28x-2y%29%283x%2B2y%29


So this also means that 3x%5E2-4xy-4y%5E2 factors to %28x-2y%29%283x%2B2y%29 (since 3x%5E2-4xy-4y%5E2 is equivalent to 3x%5E2%2B2xy-6xy-4y%5E2)



------------------------------------------------------------




So our expression goes from 2%283x%5E2-4xy-4y%5E2%29 and factors further to 2%28x-2y%29%283x%2B2y%29


------------------


Answer:

So 6x%5E2-8xy-8y%5E2 factors to 2%28x-2y%29%283x%2B2y%29


Note: if you distribute the 2 into the first group, you get %282x-4y%29%283x%2B2y%29.


Quadratic_Equations/276999: Put the equation 5x^2-10x-2 in turning point form a(x-h)^2+k, by completing the square.
1 solutions

Answer 201749 by jim_thompson5910(28504) About Me  on 2010-03-03 23:36:25 (Show Source):
You can put this solution on YOUR website!

5x%5E2-10x-2 Start with the given expression.


5%28x%5E2-2x-2%2F5%29 Factor out the x%5E2 coefficient 5. This step is very important: the x%5E2 coefficient must be equal to 1.


Take half of the x coefficient -2 to get -1. In other words, %281%2F2%29%28-2%29=-1.


Now square -1 to get 1. In other words, %28-1%29%5E2=%28-1%29%28-1%29=1


5%28x%5E2-2x%2Bhighlight%281-1%29-2%2F5%29 Now add and subtract 1 inside the parenthesis. Make sure to place this after the "x" term. Notice how 1-1=0. So the expression is not changed.


5%28%28x%5E2-2x%2B1%29-1-2%2F5%29 Group the first three terms.


5%28%28x-1%29%5E2-1-2%2F5%29 Factor x%5E2-2x%2B1 to get %28x-1%29%5E2.


5%28%28x-1%29%5E2-7%2F5%29 Combine like terms.


5%28x-1%29%5E2%2B5%28-7%2F5%29 Distribute.


5%28x-1%29%5E2-7 Multiply.


So after completing the square, 5x%5E2-10x-2 transforms to 5%28x-1%29%5E2-7. So 5x%5E2-10x-2=5%28x-1%29%5E2-7.



Square-cubic-other-roots/276973: √14÷√7
1 solutions

Answer 201741 by jim_thompson5910(28504) About Me  on 2010-03-03 22:42:03 (Show Source):


Polynomials-and-rational-expressions/276797: Factor.
2y^2+17y+30
1 solutions

Answer 201671 by jim_thompson5910(28504) About Me  on 2010-03-03 18:05:18 (Show Source):
You can put this solution on YOUR website!

Looking at the expression 2y%5E2%2B17y%2B30, we can see that the first coefficient is 2, the second coefficient is 17, and the last term is 30.


Now multiply the first coefficient 2 by the last term 30 to get %282%29%2830%29=60.


Now the question is: what two whole numbers multiply to 60 (the previous product) and add to the second coefficient 17?


To find these two numbers, we need to list all of the factors of 60 (the previous product).


Factors of 60:
1,2,3,4,5,6,10,12,15,20,30,60
-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-30,-60


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 60.
1*60 = 60
2*30 = 60
3*20 = 60
4*15 = 60
5*12 = 60
6*10 = 60
(-1)*(-60) = 60
(-2)*(-30) = 60
(-3)*(-20) = 60
(-4)*(-15) = 60
(-5)*(-12) = 60
(-6)*(-10) = 60

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 17:


First NumberSecond NumberSum
1601+60=61
2302+30=32
3203+20=23
4154+15=19
5125+12=17
6106+10=16
-1-60-1+(-60)=-61
-2-30-2+(-30)=-32
-3-20-3+(-20)=-23
-4-15-4+(-15)=-19
-5-12-5+(-12)=-17
-6-10-6+(-10)=-16



From the table, we can see that the two numbers 5 and 12 add to 17 (the middle coefficient).


So the two numbers 5 and 12 both multiply to 60 and add to 17


Now replace the middle term 17y with 5y%2B12y. Remember, 5 and 12 add to 17. So this shows us that 5y%2B12y=17y.


2y%5E2%2Bhighlight%285y%2B12y%29%2B30 Replace the second term 17y with 5y%2B12y.


%282y%5E2%2B5y%29%2B%2812y%2B30%29 Group the terms into two pairs.


y%282y%2B5%29%2B%2812y%2B30%29 Factor out the GCF y from the first group.


y%282y%2B5%29%2B6%282y%2B5%29 Factor out 6 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28y%2B6%29%282y%2B5%29 Combine like terms. Or factor out the common term 2y%2B5


===============================================================


Answer:


So 2y%5E2%2B17y%2B30 factors to %28y%2B6%29%282y%2B5%29.


In other words, 2y%5E2%2B17y%2B30=%28y%2B6%29%282y%2B5%29.


Note: you can check the answer by expanding %28y%2B6%29%282y%2B5%29 to get 2y%5E2%2B17y%2B30 or by graphing the original expression and the answer (the two graphs should be identical).


sets-and-operations/276775: Find n(A) for the set.
A={1/2,1/3,1/4,1/5,...,1/29,1/30}
1 solutions

Answer 201649 by jim_thompson5910(28504) About Me  on 2010-03-03 17:36:09 (Show Source):
You can put this solution on YOUR website!
Notice how there are 30 elements in the set {1, 2, 3, 4, 5,...,29, 30} by simply noting that 30-1+1=30 or that the elements are integers, start at 1 and end at 30.

Simply invert each element to get {1/1, 1/2, 1/3, 1/4, 1/5, ..., 1/29, 1/30} which is close to what we want, but we have to remove the element 1/1 to get {1/2, 1/3, 1/4, 1/5, ..., 1/29, 1/30}. Since we removed one element, we now have 29 elements in this set.

So n(A) = # of elements in set A = 29


Polynomials-and-rational-expressions/276721: x%5E3%2Bx%5E2-10x-6/x-3
Can you please help me solve this? Thank you.
1 solutions

Answer 201622 by jim_thompson5910(28504) About Me  on 2010-03-03 16:19:52 (Show Source):
You can put this solution on YOUR website!
In order to simplify this, we can use polynomial long division.




So the quotient is x%5E2%2B4x%2B2 and the remainder is 0. This means that %28x%5E3%2Bx%5E2-10x-6%29%2F%28x-3%29=x%5E2%2B4x%2B2%2B0%2F%28x-3%29 or more simply %28x%5E3%2Bx%5E2-10x-6%29%2F%28x-3%29=x%5E2%2B4x%2B2


Note: consequently, this means that x%5E3%2Bx%5E2-10x-6=%28x-3%29%28x%5E2%2B4x%2B2%29 (just multiply both sides by x-3)


Geometry_Word_Problems/276730: what is the area of a square whos sides measures 10 centimeters
1 solutions

Answer 201620 by jim_thompson5910(28504) About Me  on 2010-03-03 16:12:23 (Show Source):
You can put this solution on YOUR website!
Area: A+=+s%5E2+=+10%5E2+=+10%2A10+=+100

So the area of the square is 100 square cm.


Inequalities/276649: 5(2k+3)-2(k-8)>3(2k+4)+k-2
1 solutions

Answer 201590 by jim_thompson5910(28504) About Me  on 2010-03-03 13:34:44 (Show Source):
You can put this solution on YOUR website!

5%282k%2B3%29-2%28k-8%29%3E3%282k%2B4%29%2Bk-2 Start with the given equation.


10k%2B15-2k%2B16%3E6k%2B12%2Bk-2 Distribute.


8k%2B31%3E6k%2B12%2Bk-2 Combine like terms on the left side.


8k%2B31%3E7k%2B10 Combine like terms on the right side.


8k%3E7k%2B10-31 Subtract 31 from both sides.


8k-7k%3E10-31 Subtract 7k from both sides.


k%3E10-31 Combine like terms on the left side.


k%3E-21 Combine like terms on the right side.


----------------------------------------------------------------------
Answer:
So the solution is k%3E-21


Inequalities/276626: plese explain how to solve the inequality
14x +4 <26x +20
1 solutions

Answer 201573 by jim_thompson5910(28504) About Me  on 2010-03-03 12:46:12 (Show Source):
You can put this solution on YOUR website!
14x%2B4%3C26x%2B20 Start with the given equation.


14x%3C26x%2B20-4 Subtract 4 from both sides.


14x-26x%3C20-4 Subtract 26x from both sides.


-12x%3C20-4 Combine like terms on the left side.


-12x%3C16 Combine like terms on the right side.


x%3E16%2F%28-12%29 Divide both sides by -12 to isolate x. Remember that the inequality sign flips when you divide by a negative number.


x%3E-4%2F3 Reduce.


----------------------------------------------------------------------
Answer:
So the solution is x%3E-4%2F3


percentage/276400: 11/4 into a percent
1 solutions

Answer 201555 by jim_thompson5910(28504) About Me  on 2010-03-03 12:18:13 (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Converting to and from percents, decimals, and fractions


There are two ways to do this


Method #1:

First, we must convert the given fraction into a decimal number. So use a calculator or long division to convert the given fraction 11%2F4 to a decimal number. In this case, 11%2F4=2.75


Now just multiply the equivalent decimal 2.75 by 100 to convert it into a percent. So 100%2A2.75=275. Take note that we're simply moving the decimal point two spots to the right.


So the given fraction 11%2F4 is equivalent to 275%


--------------------------

Or...


Method # 2


Recall that a percent can be represented by the equation


  
     percent           part
  ------------- = ----------------
      100              whole
  
  



where 'percent' is the answer we want, the 'part' is the numerator of the given fraction, and 'whole' is the denominator of the given fraction.


So let's make 'x' the unknown percentage.


Since we're given the fraction 11%2F4, this means that the numerator is 11 and the denominator is 4. Using the equation above, we see that the 'part' is 11 while the 'whole' is 4


So let's plug these values into the equation given above to get x%2F100=11%2F4



x%2F100=11%2F4 Start with the given equation



cross%28100%29%28x%2Fcross%28100%29%29=100%2811%2F4%29 Multiply both sides by 100 to isolate 'x'.



x=100%2811%2F4%29 Simplify



x=%28100%2A11%29%2F4 Multiply 100 and 11%2F4 to get %28100%2A11%29%2F4



x=1100%2F4 Multiply 100 and 11 to get 1100



x=275 Divide



So the given fraction 11%2F4 is equivalent to 275%


Click here if you need a calculator.





Quadratic_Equations/276480: Please help me answer this question.
What are the linear factors of 12x^2+7x-12?
The answer given is 4x-3 and 3x+4.
I'm just not too sure how to get to this answer.
1 solutions

Answer 201553 by jim_thompson5910(28504) About Me  on 2010-03-03 12:15:49 (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)
In order to factor 12%2Ax%5E2%2B7%2Ax-12, first multiply the leading coefficient 12 and the last term -12 to get -144. Now we need to ask ourselves: What two numbers multiply to -144 and add to 7? Lets find out by listing all of the possible factors of -144


Factors:

1,2,3,4,6,8,9,12,16,18,24,36,48,72,144,

-1,-2,-3,-4,-6,-8,-9,-12,-16,-18,-24,-36,-48,-72,-144, List the negative factors as well. This will allow us to find all possible combinations

These factors pair up to multiply to -144.

(-1)*(144)=-144

(-2)*(72)=-144

(-3)*(48)=-144

(-4)*(36)=-144

(-6)*(24)=-144

(-8)*(18)=-144

(-9)*(16)=-144

(-12)*(12)=-144

Now which of these pairs add to 7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 7

||||||||||||||||
First Number|Second Number|Sum
1|-144|1+(-144)=-143
2|-72|2+(-72)=-70
3|-48|3+(-48)=-45
4|-36|4+(-36)=-32
6|-24|6+(-24)=-18
8|-18|8+(-18)=-10
9|-16|9+(-16)=-7
12|-12|12+(-12)=0
-1|144|(-1)+144=143
-2|72|(-2)+72=70
-3|48|(-3)+48=45
-4|36|(-4)+36=32
-6|24|(-6)+24=18
-8|18|(-8)+18=10
-9|16|(-9)+16=7
-12|12|(-12)+12=0


We can see from the table that -9 and 16 add to 7. So the two numbers that multiply to -144 and add to 7 are: -9 and 16

So the original quadratic


12%2Ax%5E2%2B7%2Ax-12


breaks down to this (just replace 7%2Ax with the two numbers that multiply to -144 and add to 7, which are: -9 and 16)


12%2Ax%5E2%2Bhighlight%28-9x%2B16x%29-12 Replace 7%2Ax with -9x%2B16x

Group the first two terms together and the last two terms together like this:

%2812%2Ax%5E2-9x%29%2B%2816x-12%29

Factor a 3x out of the first group and factor a 4 out of the second group.


3x%284x-3%29%2B4%284x-3%29


Now since we have a common term 4x-3 we can combine the two terms.


%283x%2B4%29%284x-3%29 Combine like terms.
==============================================================================

Answer:


So the quadratic 12%2Ax%5E2%2B7%2Ax-12 factors to %283x%2B4%29%284x-3%29




Notice how %283x%2B4%29%284x-3%29 foils back to our original problem 12%2Ax%5E2%2B7%2Ax-12. This verifies our answer.



logarithm/276182: Evaluate the logarithm:
log4^1/4
1 solutions

Answer 201366 by jim_thompson5910(28504) About Me  on 2010-03-02 18:08:32 (Show Source):


Linear-equations/276245: need help with this problem

y= -1/5x + 4

1 solutions

Answer 201364 by jim_thompson5910(28504) About Me  on 2010-03-02 18:06:00 (Show Source):
You can put this solution on YOUR website!
Are you trying to graph? If so, then...


Looking at y=-%281%2F5%29x%2B4 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-1%2F5 and the y-intercept is b=4


Since b=4 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is -1%2F5, this means:

rise%2Frun=-1%2F5


which shows us that the rise is -1 and the run is 5. This means that to go from point to point, we can go down 1 and over 5



So starting at , go down 1 unit


and to the right 5 units to get to the next point



Now draw a line through these points to graph y=-%281%2F5%29x%2B4

So this is the graph of y=-%281%2F5%29x%2B4 through the points and


Numeric_Fractions/276260: ok..i would like to know how to solve any fraction with an exponent for example: i started one and this is the question:(((6^8/6^6))) this is how far i got:(((6^14))) now what do i do.and what would i do if there was more than one number on the top and bottom of the fraction? thanks for the help! ;)
1 solutions

Answer 201362 by jim_thompson5910(28504) About Me  on 2010-03-02 18:04:24 (Show Source):


Parallelograms/276265: this figure must be a parallelogram and I have to prove that 4x + 20 = x + 26.
I don't understand how to do the algebra.
1 solutions

Answer 201361 by jim_thompson5910(28504) About Me  on 2010-03-02 18:02:53 (Show Source):
You can put this solution on YOUR website!
For more help with solving linear equations, check out this linear equation solver.

Solved by pluggable solver: Linear Equation Solver


4x%2B20=x%2B26 Start with the given equation.



4x=x%2B26-20 Subtract 20 from both sides.



4x-x=26-20 Subtract x from both sides.



3x=26-20 Combine like terms on the left side.



3x=6 Combine like terms on the right side.



x=%286%29%2F%283%29 Divide both sides by 3 to isolate x.



x=2 Reduce.



----------------------------------------------------------------------

Answer:

So the solution is x=2



test/276149: When is (11-a)/2 an integer?
1 solutions

Answer 201301 by jim_thompson5910(28504) About Me  on 2010-03-02 13:31:55 (Show Source):
You can put this solution on YOUR website!
%2811-a%29%2F2 is an integer when 11-a is a divisible by 2 (ie when 11-a) is even).


Graphs/275934: Give the slope-intercept form of the equation for the line on which these two points lie: (4, -2) and (3, 8)
1 solutions

Answer 201187 by jim_thompson5910(28504) About Me  on 2010-03-01 21:43:15 (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=4 and y%5B1%5D=-2.
Also, is the second point . So this means that x%5B2%5D=3 and y%5B2%5D=8.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%288--2%29%2F%283-4%29 Plug in y%5B2%5D=8, y%5B1%5D=-2, x%5B2%5D=3, and x%5B1%5D=4


m=%2810%29%2F%283-4%29 Subtract -2 from 8 to get 10


m=%2810%29%2F%28-1%29 Subtract 4 from 3 to get -1


m=-10 Reduce


So the slope of the line that goes through the points and is m=-10


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y--2=-10%28x-4%29 Plug in m=-10, x%5B1%5D=4, and y%5B1%5D=-2


y%2B2=-10%28x-4%29 Rewrite y--2 as y%2B2


y%2B2=-10x%2B-10%28-4%29 Distribute


y%2B2=-10x%2B40 Multiply


y=-10x%2B40-2 Subtract 2 from both sides.


y=-10x%2B38 Combine like terms.


So the equation that goes through the points and is y=-10x%2B38


Equations/275916: can you show me how to solve this prolem?
-(6x-5)-(-5+8)=-3
1 solutions

Answer 201171 by jim_thompson5910(28504) About Me  on 2010-03-01 20:52:56 (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Linear Equation Solver


-1%286x-5%29-1%28-5%2B8%29=-3 Start with the given equation.



-6x%2B5%2B5-8=-3 Distribute.



-6x%2B2=-3 Combine like terms on the left side.



-6x=-3-2 Subtract 2 from both sides.



-6x=-5 Combine like terms on the right side.



x=%28-5%29%2F%28-6%29 Divide both sides by -6 to isolate x.



x=5%2F6 Reduce.



----------------------------------------------------------------------

Answer:

So the solution is x=5%2F6


Sequences-and-series/275349: List the first six terms of the sequence defined recursively by
z0 = 0
z1 = 1
z2 = 2
What exactly, does this imply, and how would I start it? I'm so confused.
1 solutions

Answer 200853 by jim_thompson5910(28504) About Me  on 2010-02-28 20:02:28 (Show Source):
You can put this solution on YOUR website!
You would need to know the formula for generating the nth term. Is there more to the problem?


Exponents/275351: Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.
5^x=32
I really don't even know what the question is asking me to do. Please help!
1 solutions

Answer 200851 by jim_thompson5910(28504) About Me  on 2010-02-28 19:51:58 (Show Source):
You can put this solution on YOUR website!
The goal here is to solve for 'x' in terms of either 'a' or 'b' (or both). In other words, have a solution of x = (something with 'a's and/or 'b's in it)


You have to play with it a bit, but it turns out that we never use 2%5Eb=9. So let's just work with 2%5Ea=5


First convert 2%5Ea=5 into logarithmic form to get a=log%282%2C%285%29%29. Now use the change of base formula to get a=log%2810%2C%285%29%29%2Flog%2810%2C%282%29%29


Now move onto 5%5Ex=32 and convert that into logarithmic form to get x=log%285%2C%2832%29%29. Rewrite 32 as 2%5E5 to get x=log%285%2C%282%5E5%29%29


Now pull down the exponent to get x=5%2Alog%285%2C%282%29%29 and use the change of base formula: x=5log%2810%2C%282%29%29%2Flog%2810%2C%285%29%29. Take note how this is very similar to a=log%2810%2C%285%29%29%2Flog%2810%2C%282%29%29 but this just has the reverse of that expression and an extra '5' in there. If we invert 'a', we then get 1%2Fa=log%2810%2C%282%29%29%2Flog%2810%2C%285%29%29 which is the missing piece.


So


So the solution, in terms of 'a', is x=5%2Fa


Numbers_Word_Problems/275343: The sum of three consecutive even numbers is 150. Find the numbers. I have tried tried a + b+c = 150. I have also tried. (x+1)+(x+2)+(x+3). I don't think I am doin this problem right. However, I know the consecutive even numbers before 150 are 148, 146, 144..Help.
Dawn
1 solutions

Answer 200844 by jim_thompson5910(28504) About Me  on 2010-02-28 19:22:14 (Show Source):
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"The sum of three consecutive even numbers is 150" means that x%2B%28x%2B2%29%2B%28x%2B4%29=150 or more simply x%2Bx%2B2%2Bx%2B4=150. Let's solve this equation for 'x'.


For more help with solving linear equations, check out this linear equation solver.

Solved by pluggable solver: Linear Equation Solver


x%2Bx%2B2%2Bx%2B4=150 Start with the given equation.



3x%2B6=150 Combine like terms on the left side.



3x=150-6 Subtract 6 from both sides.



3x=144 Combine like terms on the right side.



x=%28144%29%2F%283%29 Divide both sides by 3 to isolate x.



x=48 Reduce.



----------------------------------------------------------------------

Answer:

So the solution is x=48




Since x=48, this means that the three numbers are 48, 50 and 52


Equations/275344: 3y+2=y-4

1 solutions

Answer 200842 by jim_thompson5910(28504) About Me  on 2010-02-28 19:19:55 (Show Source):
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For more help with solving linear equations, check out this linear equation solver.

Solved by pluggable solver: Linear Equation Solver


3y%2B2=y-4 Start with the given equation.



3y=y-4-2 Subtract 2 from both sides.



3y-y=-4-2 Subtract y from both sides.



2y=-4-2 Combine like terms on the left side.



2y=-6 Combine like terms on the right side.



y=%28-6%29%2F%282%29 Divide both sides by 2 to isolate y.



y=-3 Reduce.



----------------------------------------------------------------------

Answer:

So the solution is y=-3



Rational-functions/275270: I have two questions on the equations of lines.
1)Write an equation of a line passing through the points (-3,5) and (2,-7)

2) Write an equation of the line perpendicular to the line 2x-4y=7 and passing through (2,-5)
I am slightly perplexed, thanks in advance.
1 solutions

Answer 200790 by jim_thompson5910(28504) About Me  on 2010-02-28 16:53:46 (Show Source):
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# 1



First let's find the slope of the line through the points and


Note: is the first point . So this means that x%5B1%5D=-3 and y%5B1%5D=5.
Also, is the second point . So this means that x%5B2%5D=2 and y%5B2%5D=-7.


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%28-7-5%29%2F%282--3%29 Plug in y%5B2%5D=-7, y%5B1%5D=5, x%5B2%5D=2, and x%5B1%5D=-3


m=%28-12%29%2F%282--3%29 Subtract 5 from -7 to get -12


m=%28-12%29%2F%285%29 Subtract -3 from 2 to get 5


So the slope of the line that goes through the points and is m=-12%2F5


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-5=%28-12%2F5%29%28x--3%29 Plug in m=-12%2F5, x%5B1%5D=-3, and y%5B1%5D=5


y-5=%28-12%2F5%29%28x%2B3%29 Rewrite x--3 as x%2B3


y-5=%28-12%2F5%29x%2B%28-12%2F5%29%283%29 Distribute


y-5=%28-12%2F5%29x-36%2F5 Multiply


y=%28-12%2F5%29x-36%2F5%2B5 Add 5 to both sides.


y=%28-12%2F5%29x-11%2F5 Combine like terms. note: If you need help with fractions, check out this solver.


So the equation that goes through the points and is y=%28-12%2F5%29x-11%2F5


======================================

# 2


2x-4y=7 Start with the given equation.


-4y=7-2x Subtract 2x from both sides.


-4y=-2x%2B7 Rearrange the terms.


y=%28-2x%2B7%29%2F%28-4%29 Divide both sides by -4 to isolate y.


y=%28%28-2%29%2F%28-4%29%29x%2B%287%29%2F%28-4%29 Break up the fraction.


y=%281%2F2%29x-7%2F4 Reduce.


So the slope of y=%281%2F2%29x-7%2F4 and 2x-4y=7 is 1%2F2

Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of 1%2F2, you can find the perpendicular slope by this formula:

m%5Bp%5D=-1%2Fm where m%5Bp%5D is the perpendicular slope


m%5Bp%5D=-1%2F%281%2F2%29 So plug in the given slope to find the perpendicular slope



m%5Bp%5D=%28-1%2F1%29%282%2F1%29 When you divide fractions, you multiply the first fraction (which is really 1%2F1) by the reciprocal of the second



m%5Bp%5D=-2%2F1 Multiply the fractions.


So the perpendicular slope is -2



So now we know the slope of the unknown line is -2 (its the negative reciprocal of 1%2F2 from the line y=%281%2F2%29%2Ax-7%2F4). Also since the unknown line goes through (2,-5), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope and (x%5B1%5D,y%5B1%5D) is the given point



y%2B5=-2%2A%28x-2%29 Plug in m=-2, x%5B1%5D=2, and y%5B1%5D=-5



y%2B5=-2%2Ax%2B%282%29%282%29 Distribute -2



y%2B5=-2%2Ax%2B4 Multiply



y=-2%2Ax%2B4-5Subtract -5 from both sides to isolate y

y=-2%2Ax-1 Combine like terms

So the equation of the line that is perpendicular to y=%281%2F2%29%2Ax-7%2F4 and goes through (2,-5) is y=-2%2Ax-1


So here are the graphs of the equations y=%281%2F2%29%2Ax-7%2F4 and y=-2%2Ax-1




graph of the given equation y=%281%2F2%29%2Ax-7%2F4 (red) and graph of the line y=-2%2Ax-1(green) that is perpendicular to the given graph and goes through (2,-5)




Equations/275281: Please help me solve this equation.. 3|-8x-9|=117
1 solutions

Answer 200788 by jim_thompson5910(28504) About Me  on 2010-02-28 16:49:22 (Show Source):
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3%2Aabs%28-8x-9%29=117 Start with the given equation


abs%28-8x-9%29=39 Divide both sides by 3



Break up the absolute value (remember, if you have abs%28x%29=a, then x=-a or x=a)

-8x-9=-39 or -8x-9=39 Set the expression -8x-9 equal to the original value 39 and it's opposite -39




Now lets focus on the first equation -8x-9=-39


-8x=-39%2B9Add 9 to both sides


-8x=-30 Combine like terms on the right side


x=%28-30%29%2F%28-8%29 Divide both sides by -8 to isolate x



x=15%2F4 Reduce







Now lets focus on the second equation -8x-9=39



-8x=39%2B9Add 9 to both sides


-8x=48 Combine like terms on the right side


x=%2848%29%2F%28-8%29 Divide both sides by -8 to isolate x



x=-6 Divide





So the solutions to 3%2Aabs%28-8x-9%29=117 are:

x=15%2F4 and x=-6


Quadratic_Equations/275259: Can someone explain how to find the zeroes of the following problem?
f(x) = 2x^2-x+4
1 solutions

Answer 200776 by jim_thompson5910(28504) About Me  on 2010-02-28 16:32:29 (Show Source):
You can put this solution on YOUR website!
The zeros are the x values which make the equation 2x%5E2-x%2B4=0 true.




2x%5E2-x%2B4=0 Start with the given equation.


Notice that the quadratic 2x%5E2-x%2B4 is in the form of Ax%5E2%2BBx%2BC where A=2, B=-1, and C=4


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%282%29%284%29+%29%29%2F%282%282%29%29 Plug in A=2, B=-1, and C=4


x+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%282%29%284%29+%29%29%2F%282%282%29%29 Negate -1 to get 1.


x+=+%281+%2B-+sqrt%28+1-4%282%29%284%29+%29%29%2F%282%282%29%29 Square -1 to get 1.


x+=+%281+%2B-+sqrt%28+1-32+%29%29%2F%282%282%29%29 Multiply 4%282%29%284%29 to get 32


x+=+%281+%2B-+sqrt%28+-31+%29%29%2F%282%282%29%29 Subtract 32 from 1 to get -31


x+=+%281+%2B-+sqrt%28+-31+%29%29%2F%284%29 Multiply 2 and 2 to get 4.


x+=+%281+%2B-+i%2Asqrt%2831%29%29%2F%284%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


Recall that 'i' is the imaginary number and i=sqrt%28-1%29


x+=+%281%2Bi%2Asqrt%2831%29%29%2F%284%29 or x+=+%281-i%2Asqrt%2831%29%29%2F%284%29 Break up the expression.


So the zeros are x+=+%281%2Bi%2Asqrt%2831%29%29%2F%284%29 or x+=+%281-i%2Asqrt%2831%29%29%2F%284%29


Note: if you've never seen imaginary numbers before, then the answer is simply "no solutions"


Number-Line/275266: What do ( and [ mean when graphing on a number line??
1 solutions

Answer 200768 by jim_thompson5910(28504) About Me  on 2010-02-28 16:21:35 (Show Source):
You can put this solution on YOUR website!
( is an endpoint marker which tells you to exclude the endpoint while [ is similar to ( but tells you to include the endpoint.


Triangles/275264: can a triangle possibly have the sides of 1,3, and 5
1 solutions

Answer 200767 by jim_thompson5910(28504) About Me  on 2010-02-28 16:20:36 (Show Source):
You can put this solution on YOUR website!
No it cannot. Notice how 1+3=4 which is 1 unit short of the third length of 5.