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Quadratic_Equations/294772: 9) Solve by using quadratic formula x2 + 2x – 4 = 0
1 solutions
Answer 212546 by jim_thompson5910(28715) on 2010-04-21 11:34:23 (Show Source):
You can put this solution on YOUR website!9)
| Solved by pluggable solver: Quadratic Formula |
Let's use the quadratic formula to solve for x:
Starting with the general quadratic

the general solution using the quadratic equation is:

So lets solve ( notice , , and )
Plug in a=1, b=2, and c=-4
Square 2 to get 4
Multiply to get 
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or 
Now break up the fraction
or 
Simplify
or 
So the solutions are:
or 
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==============================================
10)
| Solved by pluggable solver: Quadratic Formula |
Let's use the quadratic formula to solve for x:
Starting with the general quadratic

the general solution using the quadratic equation is:

So lets solve ( notice , , and )
Plug in a=1, b=-3, and c=-10
Negate -3 to get 3
Square -3 to get 9 (note: remember when you square -3, you must square the negative as well. This is because .)
Multiply to get 
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or 
Lets look at the first part:

Add the terms in the numerator
Divide
So one answer is

Now lets look at the second part:

Subtract the terms in the numerator
Divide
So another answer is

So our solutions are:
or 
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Linear_Equations_And_Systems_Word_Problems/294733: The cost in millins of dollars for a company to manufacture x thousand automobiles is given by the function C(x)= 4x^2-16x+32. Find the number of automobiles that must be produced to minimize the cost
Tried to factor out the four then simpliy. Stuck. Help! 1 solutions
Answer 212543 by jim_thompson5910(28715) on 2010-04-21 11:31:41 (Show Source):
You can put this solution on YOUR website!The minimum is the C(x) value that is the smallest (ie it is the smallest cost value). This minimum occurs at the vertex (h,k) where
In this case,  and  meaning that  . In other words, if 2 thousand autos are produced, then the cost will be at a minimum. Simply plug this value into the function to get:
 which means that  . So the minimum cost is 16 million dollars (when 2 thousand autos are manufactured).
So the vertex is the point (2,16). What this means is that if we graph  , the lowest point on the graph is (2,16)
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Quadratic_Equations/294259: Use the quadratic formula to solve for x
6x^2-9x+1=0
if more than 1 solution separate with a comma 1 solutions
Answer 212239 by jim_thompson5910(28715) on 2010-04-20 00:21:02 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "x":
 Start with the quadratic formula
 Plug in  ,  , and
 Negate  to get  .
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 or  Break up the expression.
So the solutions are  or
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Radicals/294178: √(18yz^2 ) Rewrite in simplified radical form, ssume that all variables represent positive real numbers 1 solutions
Answer 212197 by jim_thompson5910(28715) on 2010-04-19 21:17:44 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Factor  into
 Break up the square root using the identity  .
 Take the square root of  to get  .
 Take the square root of  to get  .
 Rearrange and multiply the terms.
==================================================
Answer:
So  simplifies to
In other words,  where every variable is non-negative.
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Quadratic_Equations/294173: √(12z^10 ) Rewrite in simplified radical form, assume that all variables represent positive real numbers 1 solutions
Answer 212195 by jim_thompson5910(28715) on 2010-04-19 21:15:27 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Factor  into
 Rewrite  into
 Break up the square root using the identity  .
 Take the square root of  to get  .
 Take the square root of  to get  and rearrange the terms.
==================================================
Answer:
So  simplifies to
In other words,  where  .
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Pythagorean-theorem/294162: the sides of a right triangle are x,x+32,and x+32 units long. What is the length of the hypotenuse? 1 solutions
Answer 212190 by jim_thompson5910(28715) on 2010-04-19 21:03:22 (Show Source):
You can put this solution on YOUR website!Since 'x' is positive, this means that  . Also, because we have two sides of length x+2, this means that the legs are x+2 units long leaving the hypotenuse to be 'x' units long. That's where the problem lies: the hypotenuse cannot be shorter than either leg. So either there's a typo, or something is missing.
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Quadratic_Equations/294126: Please help me solve this problem.
2x^2-11x+12 1 solutions
Answer 212182 by jim_thompson5910(28715) on 2010-04-19 20:25:11 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,6,8,12,24
-1,-2,-3,-4,-6,-8,-12,-24
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*24 = 24
2*12 = 24
3*8 = 24
4*6 = 24
(-1)*(-24) = 24
(-2)*(-12) = 24
(-3)*(-8) = 24
(-4)*(-6) = 24
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 24 | 1+24=25 | | 2 | 12 | 2+12=14 | | 3 | 8 | 3+8=11 | | 4 | 6 | 4+6=10 | | -1 | -24 | -1+(-24)=-25 | | -2 | -12 | -2+(-12)=-14 | | -3 | -8 | -3+(-8)=-11 | | -4 | -6 | -4+(-6)=-10 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Equations/294143: 5(3x-2)=x-4 1 solutions
Answer 212181 by jim_thompson5910(28715) on 2010-04-19 20:23:53 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Distribute.
 Add  to both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is  which approximates to  .
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Probability-and-statistics/294145: The digits 0, 1, 2, 3,and 4 are to be used in a three-digit ID card. How many different cards are possible if repetitions are NOT allowed?
I don't know how to do this! 1 solutions
Answer 212180 by jim_thompson5910(28715) on 2010-04-19 20:23:01 (Show Source):
You can put this solution on YOUR website!Number of choices for first digit * Number of choices for second digit * Number of choices for third digit = 5 * 4 * 3 = 60
Note: Notice how the number of digit choices decreases (since repetitions are not allowed)
So there are 60 possible 3-digit ID card combinations.
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Quadratic_Equations/293896: I need help in factoring this equation! I also need it to be shown to me step by step because I dont know how to solve it!
 1 solutions
Answer 212054 by jim_thompson5910(28715) on 2010-04-19 12:21:57 (Show Source):
You can put this solution on YOUR website! Start with the given equation
 Pair off the terms into two groups
 Factor out the GCF  from the first group.
 Factor out the GCF  from the second group. The goal is get a common term between the two groups.
 Factor out the GCF  from the entire left side.
 Factor  to get  using the difference of squares formula.
I'll let you take it from here.
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Triangles/293894: Can you please solve this problem
The sum of the measures of the angles in any triangle is 180 degrees. In triangle ABC angles A and B have the same measure while angle c is 9 degrees larger than each of the other two angles. Find the measure of angle C
Please show work.
Thanks 1 solutions
Answer 212053 by jim_thompson5910(28715) on 2010-04-19 12:18:32 (Show Source):
You can put this solution on YOUR website!Hint: Let 'x' be the measure of angles A and B (since they are equal) and 'y' be the measure of angle C. Because "angle c is 9 degrees larger than each of the other two angles", we know that  (just add 9 to the measure of 'x' to get 'y')
Now recall that the three angles of a triangle add to 180 degrees. So this means that: angle A + angle B + angle C = 180
which then means that  . From here, plug in  to get  and you can remove the parenthesis to get  . I'll leave it to you to solve for 'x'. Once you have the value of 'x', plug it into  to find 'y', which is the measure of angle C.
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Polynomials-and-rational-expressions/293740: Factor: tsquared+3t-10 1 solutions
Answer 211967 by jim_thompson5910(28715) on 2010-04-18 22:21:18 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,5,10
-1,-2,-5,-10
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-10) = -10
2*(-5) = -10
(-1)*(10) = -10
(-2)*(5) = -10
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -10 | 1+(-10)=-9 | | 2 | -5 | 2+(-5)=-3 | | -1 | 10 | -1+10=9 | | -2 | 5 | -2+5=3 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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expressions/293701: 12-(2x+5)=-2+(x-3) 1 solutions
Answer 211962 by jim_thompson5910(28715) on 2010-04-18 21:21:39 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Distribute.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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Graphs/293607: write the equation of the line that passes through the following points (5, -3),(8,4) 1 solutions
Answer 211902 by jim_thompson5910(28715) on 2010-04-18 18:17:03 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Rewrite  as
 Distribute
 Multiply
 Subtract 3 from both sides.
 Combine like terms. note: If you need help with fractions, check out this solver.
So the equation that goes through the points ) and ) is
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Trigonometry-basics/293596: how do you undo rcis theta?
if you have a problem such as 4(cos pi/4 + i sin pi/4) how would you put that back into a +bi?
im not asking for an answer, rather the method to do the problem 1 solutions
Answer 211898 by jim_thompson5910(28715) on 2010-04-18 18:03:05 (Show Source):
You can put this solution on YOUR website!Hint: For any polar number in the form  , where 'r' is the magnitude and 'x' is the angle, it can be converted into rectangular form  using the following equations:
1)  (this can be seen if you draw out a triangle with sides 'a', 'b', and hypotenuse 'r')
2)  (again this can be seen with a drawing of the triangle) Note: since 'b' is the vertical side, this is the side opposite from the angle 'x'
So in this case,  and  meaning that  and  . You'll then find that you'll have two equations and two unknowns which means that you can solve for both 'a' and 'b'.
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Equations/293591: Solve the equation algebraically for all values of x.
We've been trying to solve this problem for hours, but it can't be factored at all. 1 solutions
Answer 211894 by jim_thompson5910(28715) on 2010-04-18 17:50:00 (Show Source):
You can put this solution on YOUR website! Start with the given expression
 Group like terms
 Factor out the GCF  out of the first group. Factor out the GCF  out of the second group
 Since we have the common term  , we can combine like terms
 Now factor  to get  (difference of squares)
So  factors to
In other words,
This basically means that  is equivalent to  . I'll let you take it from here.
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Quadratic_Equations/293470: Find the roots of quadratic equation, if more than one, separate with commas,
W^2+2W-3=0 1 solutions
Answer 211872 by jim_thompson5910(28715) on 2010-04-18 15:50:33 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "w":
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Rewrite  as
 Add  to  to get
 Multiply  and  to get  .
 Take the square root of  to get  .
 or  Break up the expression.
 or  Combine like terms.
 or  Simplify.
So the solutions are  or
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Coordinate-system/293490: how do you find the distance between the pair of points (5,-5) and (1,-2)? 1 solutions
Answer 211870 by jim_thompson5910(28715) on 2010-04-18 15:44:22 (Show Source):
You can put this solution on YOUR website!
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the distance formula.
 Plug in  ,  ,  , and  .
 Subtract  from  to get  .
 Subtract  from  to get  .
 Square  to get  .
 Square  to get  .
 Add  to  to get  .
 Take the square root of  to get  .
So our answer is
So the distance between the two points is 5 units.
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logarithm/293498: Simplify or solve for x.
log base pi of e = x^2
I have the problem written out to look like pi^(x^2)=e
I am not sure how to figure it out from there. 1 solutions
Answer 211869 by jim_thompson5910(28715) on 2010-04-18 15:41:08 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Take the square root of both sides (don't forget about the plus/minus)
 or  Break up the plus/minus to form two equations.
So the solutions are  or
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