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Polynomials-and-rational-expressions/317784: factorize 6x^2+17x+5 by splitting middle term snd by using the factor theorm 1 solutions
Answer 227548 by jim_thompson5910(28717) on 2010-06-26 17:34:18 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,5,6,10,15,30
-1,-2,-3,-5,-6,-10,-15,-30
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*30 = 30
2*15 = 30
3*10 = 30
5*6 = 30
(-1)*(-30) = 30
(-2)*(-15) = 30
(-3)*(-10) = 30
(-5)*(-6) = 30
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 30 | 1+30=31 | | 2 | 15 | 2+15=17 | | 3 | 10 | 3+10=13 | | 5 | 6 | 5+6=11 | | -1 | -30 | -1+(-30)=-31 | | -2 | -15 | -2+(-15)=-17 | | -3 | -10 | -3+(-10)=-13 | | -5 | -6 | -5+(-6)=-11 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Matrices-and-determiminant/317782: A movie theater charges $7 for adults, $4.50 for children, and $1 for senior citizens. On one day, the theater sold 635 tickets and collected $2910.00 in receipts. there were 2 times as many children's tickets sold as adult tickets. How many adults, children, and senior citizens went to the movies that day? (solve using matrices. find the reduced row echelon form).
x = adults y = children and z = senior citizens
equation 1: x + y + z = 635
equation 2: $7x + $4.5y + $1z = $2910.00
equation 3: x = 2y (IS THIS RIGHT????)
equation 4: x greater than or equal to 0
equation 5: y is greater than or equal to 0
How do I figure out the third equation and solve using a matrix and putting it into reduced row echelon form? I need to know how to figure that part out, I can get it into reduced row echelon form. Your help is appreciated. Thank you! 1 solutions
Answer 227545 by jim_thompson5910(28717) on 2010-06-26 16:49:32 (Show Source):
You can put this solution on YOUR website!Since "there were 2 times as many children's tickets sold as adult tickets", this means that  . Let's say that there were x=10 adult tickets. This then means that there are y=2(10)=20 children's tickets since "there were 2 times as many children's tickets sold as adult tickets".
So the third equation is  . If you get everything to one side, you get
So the three equations are
Note: I multiplied ALL of the terms of the second equation by 10 to make every number a whole number.
which translates into the matrix equation
Now append the right side to the 3x3 matrix on the left side to get the augmented matrix
Now let's row reduce. Note: Solution provided by the Linear Algebra Toolkit
Now look at the last column of the last matrix (ie the last step shown). This column has the values 175, 350, and 110. This means that  ,  and
So 175 adults, 350 children, and 110 seniors went to the movies that day.
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Parallelograms/317780: Given points A(3, 3), B(3, -2), C(-1, -1), D(-1, 4). Determine whether quadrilateral ABCD with the given vertices is a parallelogram or not. 1 solutions
Answer 227540 by jim_thompson5910(28717) on 2010-06-26 16:01:09 (Show Source):
You can put this solution on YOUR website!Hint: Find the slope of the line segments AB, BC, CD, and AD. If you can show that the slope of AB is equal to the slope of CD and show that the slope of BC is equal to the slope of AD, then you will have shown that ABCD is a parallelogram.
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Inequalities/317771: problem:-2/3z+9 > and = 2/3z+1
I subtracted 2/3z from right side ande added it to the left side.
I subtracted 9 from left and added to right.
I ended up with -4/3z >and = -8.
I dont think that is right.
1 solutions
Answer 227533 by jim_thompson5910(28717) on 2010-06-26 15:29:38 (Show Source):
You can put this solution on YOUR website! Start with the given inequality.
 Multiply both sides by the LCD  to clear any fractions.
 Distribute and multiply.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  . note: Remember, the inequality sign flips when we divide both sides by a negative number.
 Reduce.
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Answer:
So the solution is
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Average/317669: find a number between 9/8 and 10/8. write your answer as improper fraction and as mixed number. 1 solutions
Answer 227500 by jim_thompson5910(28717) on 2010-06-26 04:44:19 (Show Source):
You can put this solution on YOUR website!One easy way to find a number between two numbers is to simply average the two given numbers. Ie add them up and divide by 2:
So the number  , which is the mixed number  , is in between the numbers  and
Other ways would involve you picking a number between 9 and 10, say 9.7, and writing that as a fraction over 8 like this:
So  , which is the mixed number  , is another number in between the numbers  and
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Equations/317395: Solve for the variable. Noninteger answers may be left in fractional or decimal form.
5/6y + 4/9 = 1/6y - 2/5
I can not solve it! can you should me how to work it out? 1 solutions
Answer 227258 by jim_thompson5910(28717) on 2010-06-25 00:53:00 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
 Multiply EVERY term by the LCD  to clear the fractions.
 Multiply and simplify.
 Multiply.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
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Answer:
So the solution is
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Inequalities/317381: use the properties of inequalities to solve the following inequality. write the solution set using set-builder notation.
9(x-8)>or=to -9x-7.
thank you
1 solutions
Answer 227257 by jim_thompson5910(28717) on 2010-06-25 00:50:04 (Show Source):
You can put this solution on YOUR website! Start with the given inequality.
 Distribute.
 Add  to both sides.
 Add  to both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
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Answer:
So the solution is
The answer in set-builder notation is
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Equations/317310: find the value of a in this proportion (a+1)/4=2/3 1 solutions
Answer 227172 by jim_thompson5910(28717) on 2010-06-24 18:09:45 (Show Source):
You can put this solution on YOUR website! Start with the given equation.
 Cross multiply.
 Multiply 2 and 4 to get 8.
 Distribute.
 Subtract  from both sides.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
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Answer:
So the solution is
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Quadratic_Equations/317300: This is a quadratic equation question. Solve for x:
x^2+14x+4=0 1 solutions
Answer 227156 by jim_thompson5910(28717) on 2010-06-24 17:42:19 (Show Source):
You can put this solution on YOUR website!
 Start with the given equation.
Notice that the quadratic  is in the form of  where  ,  , and
Let's use the quadratic formula to solve for "x":
 Start with the quadratic formula
 Plug in  ,  , and
 Square  to get  .
 Multiply  to get
 Subtract  from  to get
 Multiply  and  to get  .
 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
 Break up the fraction.
 Reduce.
 or  Break up the expression.
So the solutions are  or
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Equations/317100: The product of page numbers on two facing pages of a book is 182. How would you find the page numbers? I have tried and cannot figure out how to do this.Can you show me how? 1 solutions
Answer 227022 by jim_thompson5910(28717) on 2010-06-24 04:42:25 (Show Source):
You can put this solution on YOUR website!Hint: Since "The product of page numbers on two facing pages of a book is 182", this means that  where 'x' is the first of the two pages and 'x+1' is the next page.
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Equations/317097: I am having trouble figuring out how to factor the three problems listed below:1. x^2+2x-2x-4;2.v^2+9v+14;3. r^2-2r-48. I have been working on them for about 1 1/2 hours at this time and just can not seem to get any where can you help? 1 solutions
Answer 227020 by jim_thompson5910(28717) on 2010-06-24 04:40:48 (Show Source):
You can put this solution on YOUR website!# 1
 Start with the given expression
 Group like terms
 Factor out the GCF  out of the first group. Factor out the GCF  out of the second group
 Since we have the common term  , we can combine like terms
So  factors to
In other words,
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# 2
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,7,14
-1,-2,-7,-14
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*14 = 14
2*7 = 14
(-1)*(-14) = 14
(-2)*(-7) = 14
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 14 | 1+14=15 | | 2 | 7 | 2+7=9 | | -1 | -14 | -1+(-14)=-15 | | -2 | -7 | -2+(-7)=-9 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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# 3
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,6,8,12,16,24,48
-1,-2,-3,-4,-6,-8,-12,-16,-24,-48
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*(-48) = -48
2*(-24) = -48
3*(-16) = -48
4*(-12) = -48
6*(-8) = -48
(-1)*(48) = -48
(-2)*(24) = -48
(-3)*(16) = -48
(-4)*(12) = -48
(-6)*(8) = -48
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | -48 | 1+(-48)=-47 | | 2 | -24 | 2+(-24)=-22 | | 3 | -16 | 3+(-16)=-13 | | 4 | -12 | 4+(-12)=-8 | | 6 | -8 | 6+(-8)=-2 | | -1 | 48 | -1+48=47 | | -2 | 24 | -2+24=22 | | -3 | 16 | -3+16=13 | | -4 | 12 | -4+12=8 | | -6 | 8 | -6+8=2 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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Equations/317098: Using the principle of zero products how would you solve the following problems:1. (9b+5)(4b-12)=0; 2.b^2+8b+12=0. I have been trying and can not seem to get the correct answer. Can you help? 1 solutions
Answer 227019 by jim_thompson5910(28717) on 2010-06-24 04:38:07 (Show Source):
You can put this solution on YOUR website!# 1
 Start with the given equation
Now set each factor equal to zero:
 or
Now solve for b for each factor:
 or
So the solutions are  or
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# 2
 Start with the given equation
 Factor the left side
Now set each factor equal to zero:
 or
 or  Now solve for b in each case
So the solutions are  or
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Square-cubic-other-roots/317101: from special relativity, I can get most of the way apart from the very last step
how do you simplify ,
the answer should be 
but I don't see how it's done
thanks
John
1 solutions
Answer 227018 by jim_thompson5910(28717) on 2010-06-24 04:34:18 (Show Source):
You can put this solution on YOUR website!It's not much of a simplification (in my opinion) as the expression doesn't get any simpler, but here it goes...
 Start with the given expression.
 Divide both the numerator and the denominator by 'c'
 Reduce  to get 1.
 Rewrite  as  . Note: this implies that 'c' is a non-negative number, which it is.
 Combine the lower square roots using the identity
 Break up the lower inner fraction.
 Reduce  to get 1.
So
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expressions/317059: Factor the following trinomial, if possible. If the coefficient of the first term is negative, factor out -1 to make the first term positive.
10a^2 - 9a + 2 1 solutions
Answer 226994 by jim_thompson5910(28717) on 2010-06-23 21:56:58 (Show Source):
You can put this solution on YOUR website!
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,4,5,10,20
-1,-2,-4,-5,-10,-20
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*20 = 20
2*10 = 20
4*5 = 20
(-1)*(-20) = 20
(-2)*(-10) = 20
(-4)*(-5) = 20
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 20 | 1+20=21 | | 2 | 10 | 2+10=12 | | 4 | 5 | 4+5=9 | | -1 | -20 | -1+(-20)=-21 | | -2 | -10 | -2+(-10)=-12 | | -4 | -5 | -4+(-5)=-9 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
===============================================================
Answer:
So  factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
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