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Answer 266756 by jim_thompson5910(28598) on 2010-11-22 18:37:28 (Show Source):
You can put this solution on YOUR website!I'm assuming you want to factor.
 Start with the given expression.
 Factor out the GCF  .
Now let's try to factor the inner expression
---------------------------------------------------------------
Looking at the expression  , we can see that the first coefficient is  , the second coefficient is  , and the last term is  .
Now multiply the first coefficient  by the last term  to get  .
Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient  ?
To find these two numbers, we need to list all of the factors of  (the previous product).
Factors of  :
1,2,3,4,5,6,9,10,12,15,18,20,27,30,36,45,54,60,90,108,135,180,270,540
-1,-2,-3,-4,-5,-6,-9,-10,-12,-15,-18,-20,-27,-30,-36,-45,-54,-60,-90,-108,-135,-180,-270,-540
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*540 = 540
2*270 = 540
3*180 = 540
4*135 = 540
5*108 = 540
6*90 = 540
9*60 = 540
10*54 = 540
12*45 = 540
15*36 = 540
18*30 = 540
20*27 = 540
(-1)*(-540) = 540
(-2)*(-270) = 540
(-3)*(-180) = 540
(-4)*(-135) = 540
(-5)*(-108) = 540
(-6)*(-90) = 540
(-9)*(-60) = 540
(-10)*(-54) = 540
(-12)*(-45) = 540
(-15)*(-36) = 540
(-18)*(-30) = 540
(-20)*(-27) = 540
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 540 | 1+540=541 | | 2 | 270 | 2+270=272 | | 3 | 180 | 3+180=183 | | 4 | 135 | 4+135=139 | | 5 | 108 | 5+108=113 | | 6 | 90 | 6+90=96 | | 9 | 60 | 9+60=69 | | 10 | 54 | 10+54=64 | | 12 | 45 | 12+45=57 | | 15 | 36 | 15+36=51 | | 18 | 30 | 18+30=48 | | 20 | 27 | 20+27=47 | | -1 | -540 | -1+(-540)=-541 | | -2 | -270 | -2+(-270)=-272 | | -3 | -180 | -3+(-180)=-183 | | -4 | -135 | -4+(-135)=-139 | | -5 | -108 | -5+(-108)=-113 | | -6 | -90 | -6+(-90)=-96 | | -9 | -60 | -9+(-60)=-69 | | -10 | -54 | -10+(-54)=-64 | | -12 | -45 | -12+(-45)=-57 | | -15 | -36 | -15+(-36)=-51 | | -18 | -30 | -18+(-30)=-48 | | -20 | -27 | -20+(-27)=-47 |
From the table, we can see that the two numbers  and  add to  (the middle coefficient).
So the two numbers  and  both multiply to and add to
Now replace the middle term  with  . Remember,  and  add to  . So this shows us that  .
 Replace the second term  with  .
 Group the terms into two pairs.
 Factor out the GCF  from the first group.
 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.
 Combine like terms. Or factor out the common term
--------------------------------------------------
So  then factors further to
===============================================================
Answer:
So  completely factors to  .
In other words,  .
Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
|
Reduction-of-unit-multipliers/375128: find the measures of the side of a square with an area of 75 sq. units
1 solutions
Answer 266755 by jim_thompson5910(28598) on 2010-11-22 18:36:12 (Show Source):
You can put this solution on YOUR website! Start with the area of a square formula.
 Take the square root of both sides (note: we're only taking the positive square root since a negative length doesn't make sense).
 Flip the equation.
 Plug in  .
 Simplify the square root.
 Evaluate the right side with a calculator.
So if a square has an area of  square units, then it has a side length of approximately  units.
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Inequalities/375112: how do I solve 8-6x<8x-4x 1 solutions
Answer 266748 by jim_thompson5910(28598) on 2010-11-22 18:25:53 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality.
 Combine like terms on the right side.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Divide both sides by  to isolate  . note: Remember, the inequality sign flips when we divide both sides by a negative number.
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
|
Inequalities/375114: how do I solve 2x+9>6x+11 1 solutions
Answer 266747 by jim_thompson5910(28598) on 2010-11-22 18:25:17 (Show Source):
You can put this solution on YOUR website!
 Start with the given inequality.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  . note: Remember, the inequality sign flips when we divide both sides by a negative number.
 Reduce.
----------------------------------------------------------------------
Answer:
So the solution is
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
|
Radicals/375116: Write each expression below in simplest radical form. SHOW YOUR STEPS.
√4x^8
I'm pretty sure that the answer is 2x^4√, but how do I show the steps?
I'd appreciate some help! Thank you! :) 1 solutions
Answer 266746 by jim_thompson5910(28598) on 2010-11-22 18:24:26 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Factor  into
 Break up the square root using the identity  .
 Take the square root of  to get  .
 Take the square root of  to get  .
 Rearrange and multiply the terms.
==================================================
Answer:
So  simplifies to
In other words,  where x is nonnegative.
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
|
Radicals/375118: Write the expression below in simplest radical form. SHOW YOUR STEPS.
√27a^3
I think that the answer is 3a√3a, but how do I show my steps??
Please help me! Thank you!!!! :) 1 solutions
Answer 266745 by jim_thompson5910(28598) on 2010-11-22 18:23:06 (Show Source):
You can put this solution on YOUR website!
 Start with the given expression.
 Factor  into
 Factor  into
 Break up the square root using the identity  .
 Take the square root of  to get  .
 Take the square root of  to get  .
 Rearrange and multiply the terms.
==================================================
Answer:
So  simplifies to
In other words,  where every variable is non-negative.
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
|
Graphs/375069: How do I solve this equation? graphing this equation y = -3/4x-3. Been working on it but can't figure it out,I think the y intercept is -3 1 solutions
Answer 266729 by jim_thompson5910(28598) on 2010-11-22 17:13:33 (Show Source):
You can put this solution on YOUR website!Looking at  we can see that the equation is in slope-intercept form  where the slope is  and the y-intercept is
Since  this tells us that the y-intercept is ) .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
Also, because the slope is  , this means:
which shows us that the rise is -3 and the run is 4. This means that to go from point to point, we can go down 3 and over 4
So starting at ) , go down 3 units
and to the right 4 units to get to the next point
Now draw a line through these points to graph
 So this is the graph of  through the points ) and
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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Quadratic_Equations/375065: Hello everyone, finding the following question puzzling, i have not covered this before, and am trying to get a heads up for when i start my course
Use logarithmic differentiation to differentiate the following:
(i) y = 2^x (ii) y = x^x
Cheers 1 solutions
Answer 266728 by jim_thompson5910(28598) on 2010-11-22 17:12:31 (Show Source):
You can put this solution on YOUR website!i)
 Start with the given equation.
 Take the natural log of both sides.
 Pull down the exponent.
) ... Derive both sides
) ... Solve for y'
) ... Now plug in
Note: the derivative of  is
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ii)
 Start with the given equation.
 Take the natural log of both sides.
 Pull down the exponent.
+1) ... Derive both sides
+1)) ... Solve for y'
+1)) ... Now plug in
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Linear-equations/375059: find an equation that satisfies the points (9,136) and (3,40) 1 solutions
Answer 266722 by jim_thompson5910(28598) on 2010-11-22 17:01:20 (Show Source):
You can put this solution on YOUR website!
First let's find the slope of the line through the points ) and
Note: ) is the first point ) . So this means that  and  .
Also, ) is the second point ) . So this means that  and  .
 Start with the slope formula.
 Plug in  ,  ,  , and
 Subtract  from  to get
 Subtract  from  to get
 Reduce
So the slope of the line that goes through the points ) and ) is
Now let's use the point slope formula:
 Start with the point slope formula
 Plug in  ,  , and
 Distribute
 Multiply
 Add 136 to both sides.
 Combine like terms.
 Simplify
So the equation that goes through the points ) and ) is
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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Radicals/375049: Divide and simplify so that there are no radicals in the denominator. SHOW YOUR STEPS.
√ 7/100
I didn't really know how to type it out, but the --> √ <-- thing is supposed to be for both the 7 and the ten. I have no clue how to solve this problem, can someone please help me? Thanks so much! I'd really appreciate it :) 1 solutions
Answer 266717 by jim_thompson5910(28598) on 2010-11-22 16:45:36 (Show Source):
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Radicals/375045: Divide and simplify so that there are no radicals in the denominator. SHOW YOUR STEPS.
√18+√24/√6
I don't know how to do this kind of problem at all, can someone help me, please? Thanks so much! :) 1 solutions
Answer 266716 by jim_thompson5910(28598) on 2010-11-22 16:44:08 (Show Source):
You can put this solution on YOUR website! Start with the given expression.
 Factor 18 into 3*6 and factor 24 into 4*6 (notice the presence of 6)
 Break up the square roots using the identity
 Take the square root of 4 to get 2.
 Factor out the GCF
 Highlight the common terms.
 Cancel out the common terms.
 Simplify.
So
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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Radicals/375044: Divide and simplify so that there are no radicals in the denominator. SHOW YOUR STEPS.
8/6√
PLEEEEASE help me!!!!!!! I'd really appreciate some help because I am totally stuck on this. Thank you!!!!! :) 1 solutions
Answer 266715 by jim_thompson5910(28598) on 2010-11-22 16:35:10 (Show Source):
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Age_Word_Problems/375011: Bill is 6 years older than Tom. Three years ago, Bill's age was four times Tom's age. What are the boys ages now? How do I write this in a single variable equation? I have tried and I have gotten this wrong on two different quizzes, so I am curious what the correct answer is? 1 solutions
Answer 266713 by jim_thompson5910(28598) on 2010-11-22 16:30:02 (Show Source):
You can put this solution on YOUR website!Let B = bill's age now, T = Tom's age now
So Bill's age 3 yrs ago was  and Tom's age 3 yrs ago was
Since "Bill is 6 years older than Tom", we know that
Also, because "Bill's age was four times Tom's age", we know that
-------------------------
 Start with the second equation.
 Plug in  (ie replace each 'B' with 'T+6'). So this would be the starting point of the single variable equation you're looking for.
 Distribute.
 Combine like terms on the left side.
 Subtract  from both sides.
 Subtract  from both sides.
 Combine like terms on the left side.
 Combine like terms on the right side.
 Divide both sides by  to isolate  .
 Reduce.
So this means that Tom is 5 yrs old.
Now plug this value into  to get  . So  which means that Bill is 11 yrs old.
Notice that 3 yrs ago, Bill was 11-3=8 yrs old and Tom was 5-3=2 years old. Also notice that 8 is 4 times 2.
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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Quadratic_Equations/375035: What 2 numbers have a product of 128 and a sum of 48?
I don't believe it has a solution with whole numbers anyway.
1 solutions
Answer 266710 by jim_thompson5910(28598) on 2010-11-22 16:21:14 (Show Source):
You can put this solution on YOUR website!To find these two numbers, we need to list all of the factors of  .
Factors of  :
1,2,4,8,16,32,64,128
-1,-2,-4,-8,-16,-32,-64,-128
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to  .
1*128 = 128
2*64 = 128
4*32 = 128
8*16 = 128
(-1)*(-128) = 128
(-2)*(-64) = 128
(-4)*(-32) = 128
(-8)*(-16) = 128
Now let's add up each pair of factors to see if one pair adds to the middle coefficient  :
| First Number | Second Number | Sum | | 1 | 128 | 1+128=129 | | 2 | 64 | 2+64=66 | | 4 | 32 | 4+32=36 | | 8 | 16 | 8+16=24 | | -1 | -128 | -1+(-128)=-129 | | -2 | -64 | -2+(-64)=-66 | | -4 | -32 | -4+(-32)=-36 | | -8 | -16 | -8+(-16)=-24 |
From the table, we can see that there are no pairs of numbers which add to  .
So you are correct. There are no two rational numbers which multiply to 128 and add to 48.
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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Linear-systems/375032: y=3x
2x+y=5
This is the substitution method.its one problem.Please help me find the answer to this problem 1 solutions
Answer 266709 by jim_thompson5910(28598) on 2010-11-22 16:16:59 (Show Source):
You can put this solution on YOUR website! Start with the second equation.
 Plug in  (ie replace every 'y' with '3x')
 Combine like terms on the left side.
 Divide both sides by  to isolate  .
 Reduce.
 Go back to the first equation.
 Plug in
 Multiply
So the answers are  and  which form the ordered pair (1,3)
This means that the system is consistent and independent.
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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Quadratic-relations-and-conic-sections/374779: what is the equation of the circle that has its center at (3,-1) and passes through the point (-2,2) 1 solutions
Answer 266518 by jim_thompson5910(28598) on 2010-11-22 00:12:32 (Show Source):
You can put this solution on YOUR website! Start with the general equation of a circle.
 Plug in  and  (since the center is the point (h,k) ).
 Plug in  and  (this is the point that lies on the circle, which is in the form (x,y) ).
 Combine like terms.
 Square each term.
 Add.
So because  ,  , and  , this means that the equation of the circle with center (3,-1) that goes through the point (-2,2) is
 .
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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Quadratic-relations-and-conic-sections/374780: The two points (-2,4) and (4,2) are the endpoints of the diameter of a circle. What is the equation of this circle in standard form? 1 solutions
Answer 266517 by jim_thompson5910(28598) on 2010-11-22 00:10:35 (Show Source):
You can put this solution on YOUR website!Recall that the general equation of a circle is  .
So we need the center (h,k) and the radius squared  .
First, let's find the center (h,k).
Since the center is the midpoint of the line segment with endpoints (-2,4) and (4,2), we need to find the midpoint.
X-Coordinate of Midpoint =
Since the x coordinate of midpoint is  , this means that
Y-Coordinate of Midpoint =
Since the y coordinate of midpoint is  , this means that
So the center is the point (1, 3)
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Now let's find the radius squared
Use the formula  , where (h,k) is the center and (x,y) is an arbitrary point on the circle.
In this case,  and  . Also,  and  . Plug these values into the equation above and simplify to get:
So because  ,  , and  , this means that the equation of the circle that passes through the points (-2,4) and (4,2) (which are the endpoints of the diameter) is
 .
If you need more help, email me at jim_thompson5910@hotmail.com
Also, feel free to check out my tutoring website
Jim
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