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 Polynomials-and-rational-expressions/63972: This question is from textbook algebra for college students hello how do you factor this polynomial? x^2 - 20x + 100 thank you!1 solutions Answer 44625 by funmath(2925)   on 2006-12-05 14:26:24 (Show Source): You can put this solution on YOUR website!x^2 - 20x + 100 (x____)(x_____) We need to fill the blanks with two numbers that multiply to get the last term, 100. But add together to get the coefficient of the middle term, -20. -10*-10=100 -10+-10=-20 (x-10)(x-10) (x-10)^2 Happy Calculating!!!
 Polynomials-and-rational-expressions/63973: This question is from textbook algebra for college students hello how do i factor this polynomial completely: 2x^2 - 8 thank you!1 solutions Answer 44624 by funmath(2925)   on 2006-12-05 14:20:14 (Show Source): You can put this solution on YOUR website! Factor out the GCF, 2 Factor the difference of squares , a=x, b=2 Happy Calculating!!!
 Functions/63961: determine the critical numbers and the critical points for each of the following functions A. f(x)= x^3 + 13x^2 + 7x - 165 B. g(x)= X^3 +6x^2 - 13x - 42 C. h(x)= x^3-10x^2 + 7x + 18 THESE PROBLEMS ARE TOUGH....I REALLY NEED HELP WITH THEM...I TRIED DOING THEM BUT THE ANSWERS AREN'T RIGHT BECAUSE I KNOW THERE ARE SUPPOSED TO BE 2 ANSWERS 4 EACH BUT IM NOT SURE HOW TO GET THE SECOND NUMBER...PLEASE HELP...THANK YOU 1 solutions Answer 44623 by funmath(2925)   on 2006-12-05 14:17:23 (Show Source): You can put this solution on YOUR website!determine the critical numbers and the critical points for each of the following functions A. f(x)= x^3 + 13x^2 + 7x - 165 f'(x)=3x^2+26x+7 0=3x^2+26x+7 Use the quadratic formula: a=3, b=26, and c=7 and and and : B. g(x)= X^3 +6x^2 - 13x - 42 g'(x)=3x^2+12x-13 0=3x^2+12x-13 Use the quadratic formula, a=3, b=12, and c=-13 and and and : C. h(x)= x^3-10x^2 + 7x + 18 h'(x)=3x^2-20x+7 0=3x^2-20x+7 Use the quadratic formula a=3, b=-20, and c=7 or or or Happy Calculating!!!
 Functions/63959: calculate the first derivative f'(x) for each of the following. Express your final answers using positive exponents A. f(x)= 5/6x^3/4 + 5/6x^3/2 + 2/5x^3/2 B. f(x)=3/2x^3/2 + 3/2x^3/4 + 3/2x^2/3 C.f(x)= 5/6x^3/4 + 5/6x^3/2 I NEED HELP WITH THESE PROBLEMS...I WOULD APPRECIATE THE HELP..I'VE TRIED TO DO THEM BUT IT DOESN'T COME OUT RIGHT...1 solutions Answer 44622 by funmath(2925)   on 2006-12-05 13:48:14 (Show Source): You can put this solution on YOUR website!calculate the first derivative f'(x) for each of the following. Express your final answers using positive exponents A. f'(x)= f'(x)= f'(x)= : B. f'(x)= f'(x)= f'(x)= : C. f'(x)= f'(x)= f'(x)= : Happy Calculating!!!
 logarithm/63956: Please assist with solving the following problem: Thank you so much!! 4(3^x)=10(2^x)1 solutions Answer 44621 by funmath(2925)   on 2006-12-05 13:27:44 (Show Source): You can put this solution on YOUR website! x = approximately 2.259851005 Happy Calculating!!!
 Inequalities/63831: 3x is less than or equal to 2x plus 71 solutions Answer 44613 by funmath(2925)   on 2006-12-05 12:03:18 (Show Source): You can put this solution on YOUR website! Graph on a number line: <<======]--------> 3 4 5 6 7 8 9 10 11 Interval notation: (-infinity,7] Happy Calculating!!!
 Systems-of-equations/63948: Hi! I need some help solving this equation.... 2-|6-8|+5 3(----------) + (sqrt)9+16 4-5*2 Thanks in advance for your help1 solutions Answer 44612 by funmath(2925)   on 2006-12-05 11:58:28 (Show Source): You can put this solution on YOUR website!If this is what you meant... Let me know if I misinterpretted your problem. Happy Calculating!!!
 Radicals/63923: Really need help with this one. Solve the equation. ^3 sqrt(x^2) = 41 solutions Answer 44611 by funmath(2925)   on 2006-12-05 11:52:43 (Show Source): You can put this solution on YOUR website!I don't really know what you mean. What did you mean by ^3? Did you mean the third root of x^2? If so, this is what you do. Solve the equation. 3rd rt(x^2) = 4 (3rd rt(x^2))^3=4^3 x^2=64 x=+\-8 : Check for extraneous solutions: 3rd rt((8)^2)=4 3rd rt (64)=4 4=4 x=8 checks out. 3rd rt((-8)^2)=4 3rd rt(64)=4 4=4 x=-8 also checks out. Happy Calculating!!!
 Exponential-and-logarithmic-functions/63849: slove algebraically log base 4 (x+41)- log base 4(2x-5)=21 solutions Answer 44610 by funmath(2925)   on 2006-12-05 11:42:36 (Show Source): You can put this solution on YOUR website!slove algebraically log base 4 (x+41)- log base 4(2x-5)=2 log base 4((x+41)/(2x-5))=2 because log(a)-log(b)=log(a/b) if the bases are the same. because log base a (b)=x ==> a^x=b Check: log base 4 (121/31+41)-log base 4 (2(121/31)-5)=2 log base 4 (1392/31)-log base 4 (87/31)=2 log base 4 ((1392/31)/(87/31))=2 log base 4((1392/31)(31/87))=2 log base 4(1392/87)=2 log base 4 (16)=2 log base 4 (4^2)=2 2=2 We're right!!! Happy Calculating!!!
 Exponential-and-logarithmic-functions/63881: Find E^x for the following set of numbers: –3.5, –1.4, –0.5, 3, 5, 1, 2 1 solutions Answer 44608 by funmath(2925)   on 2006-12-05 11:29:53 (Show Source): You can put this solution on YOUR website!Find E^x for the following set of numbers: –3.5, –1.4, –0.5, 3, 5, 1, 2 You need a calculator to do this. e=2.718281828... e^(-3/2)=.2231301601 e^(-1.4)=.2465969639 e^(-0.5)=.6065306597 e^(3)=20.08553692 e^(5)=148.4131591 e^(1)=2.718281828 e^(2)=7.389056099 Round off to whatever your teacher asks for. Happy Calculating!!!
 logarithm/63947: Thank you for helping me with the solution to the following problem. Our solutions do not seem to be going in the same direction would you please assist as to what I am doing wrong. This is as far as I could get with the problem. Problem: 3log(X^2)-4log(X^2)+log(2X^3): 3log(X^2)-4log(X^2)+log(2X^3): log((X^2)^3)-log((X^2)4)+log(2X^3) log(X^6)-log(X^8)+log(2X^3) log(X^-8/X^6,2X^3)log(X^-8 I am stuck here with my completion.1 solutions Answer 44607 by funmath(2925)   on 2006-12-05 11:17:11 (Show Source): You can put this solution on YOUR website!Problem: 3log(X^2)-4log(X^2)+log(2X^3): If you're the same person I just answered this for, there is more than one way to skin this cat, however you should still come up with the same conclusion. Doing it your way: 3log(X^2)-4log(X^2)+log(2X^3): log((X^2)^3)-log((X^2)4)+log(2X^3) log(X^6)-log(X^8)+log(2X^3) log(x^6/x^8)+log(2x^3) because loga-logb=log(a/b) log(1/x^2)+log(2x^3) reduce log((1/x^2)(2x^3)) because loga+logb=log(ab) log(2x^3/x^2) log(2x) reduce Happy Calculating!!!
 test/63931: calculate the first derivatives f(x) for each of the following: show all work A)f(x)= 2/3x3/4 + 3/4x2/3+ 5/6x2/3 B) f(x)= 2/5x3/2 + 5/6x3/4 + 5/6x3/2 C) f(x)= 3/4x2/3 +5/6x3/2 + 3/4x3/2 1 solutions Answer 44606 by funmath(2925)   on 2006-12-05 11:04:48 (Show Source): You can put this solution on YOUR website!I am assuming that the fractions after the variables are exponents, let me know if I'm not interpretting you correctly: calculate the first derivatives f(x) for each of the following: show all work A)f(x)= 2/3x3/4 + 3/4x2/3+ 5/6x2/3 f'(x)= f'(x)= f'(x)= : B) f(x)= 2/5x3/2 + 5/6x3/4 + 5/6x3/2 f'(x)= f'(x)= f'(x)= : C) f(x)= 3/4x2/3 +5/6x3/2 + 3/4x3/2 f'(x)= f'(x)= f'(x)= Happy Calculating!!!
 Rational-functions/63937: (a-1)/2+5a1 solutions Answer 44600 by funmath(2925)   on 2006-12-05 10:39:04 (Show Source): You can put this solution on YOUR website!If you're supposed to simplify: The LCD is 2 Happy Calculating!!!
 Graphs/63938: y = |x|1 solutions Answer 44596 by funmath(2925)   on 2006-12-05 10:20:19 (Show Source): You can put this solution on YOUR website!y = |x| What are your directions? This is an absolute value function, if you need to graph it, plot a couple of positive and negative x's. When x=0 y=|0| y=0 Plot(0,0) When x=1 y=|1| y=1 Plot(1,1) When x=2 y=|2| y=2 Plot(2,2) When x=-1 y=|-1| y=1 Plot(-1,1) When x=-2 y=|-2| y=2 Plot (-2,2) Connect your points: Happy Calculating!!!
 logarithm/63943: 3log(X^2)-4log(X^2)+log(2X^3)1 solutions Answer 44595 by funmath(2925)   on 2006-12-05 10:15:39 (Show Source): You can put this solution on YOUR website!Are the directions to express as a single log, or to simplify? I am going to express as a single log, then simplify. 3log(X^2)-4log(X^2)+log(2X^3) -log(x^2)+log(2X^3) log(X^-2)+log(2X^3) log(1/X^2)+log(2X^3) log(2X^3/X^2) log(2X) <==single log log(2)+log(X) <==simplified Happy Calculating!!!
 Divisibility_and_Prime_Numbers/63944: please help solve factor out the greatest ommon factor. Simplify if possible. 5(2-x)^2-(2-x)^3+4(2-x) 1 solutions Answer 44593 by funmath(2925)   on 2006-12-05 10:04:56 (Show Source): You can put this solution on YOUR website!factor out the greatest ommon factor. Simplify if possible. 5(2-x)^2-(2-x)^3+4(2-x) The GCF is (2-x) Happy Calculating!!!
 Quadratic-relations-and-conic-sections/63939: y= 1/x1 solutions Answer 44592 by funmath(2925)   on 2006-12-05 09:57:29 (Show Source): You can put this solution on YOUR website!y= 1/x I'm not sure what you want. This is a hyperbolic function. If you need to graph this, plot some points. There is a vertical asymptote at x=0, because the funciton is undefined when the denominator = 0. There is a horizontal asymptote at y=0 because there is nothing we can do to make the function =0. Plot two points on both sides of the vertical asymptote: Let x=-1 y=1/-1=-1 Plot (-1,-1) Let x=-2 y=1/-2 Plot(-2,-1/2) Let x=1 y=1/1=1 Plot(1,1) Let x=2 y=1/2 Plot (1,1/2) The graph will look like this: Happy Calculating!!!
 Exponential-and-logarithmic-functions/63941: solve log base is 3.4 ans is 5 and exponent is 2x-11 solutions Answer 44591 by funmath(2925)   on 2006-12-05 09:48:21 (Show Source): You can put this solution on YOUR website!I'm not sure what you mean. This is the way I type log problems, write your problem back to me and I'll see what I can do to help. log3(4^(x-4))=17 The 3 is the base, x-4 is an exponent.
 test/63932: determine the critical numbers and the critical points for each of the following functions:show all work A)f(x)= x3 + 3x2 -33x -35 B) g(x)=x3 - 36x C) h(x)= x3 -3x2 -40x1 solutions Answer 44590 by funmath(2925)   on 2006-12-05 09:43:49 (Show Source): You can put this solution on YOUR website!determine the critical numbers and the critical points for each of the following functions:show all work A)f(x)= x^3 + 3x^2 -33x -35 f'(x)=3x^2+6x-33 We can't solve this by factoring, so use the quadratic formula: a=1, b=2, c=-11 and and : B) g(x)=x^3 - 36x g'(x)=3x^2-36 +\- +\- +\- : C) h(x)= x^3 -3x^2 -40x h'(x)=3x^2-6x-40 0=3x^2-6x-40 use the quadratic formula again. a=3, b=-6, and c=-40 and and and : Happy Calculating!!!
 Linear_Algebra/63918: This question is from textbook algebra and trigonmetry struture method with a tail wind, a helicopter traveled 300mi in an hour and 40 min. the return trip aganst the same wind took 20 min longer. find the wind speed and also the air speed of the helicopter.1 solutions Answer 44589 by funmath(2925)   on 2006-12-05 09:20:20 (Show Source): You can put this solution on YOUR website!with a tail wind, a helicopter traveled 300mi in an hour and 40 min. the return trip aganst the same wind took 20 min longer. find the wind speed and also the air speed of the helicopter. The trick to this one is remembering to convert your time in minutes to time in hours. The time with the tail wind is: 40min(1hr/60min)=40hr/60=(2/3)hr Let the rate of the helicopter be: h Let the rate of the wind be: w The distance formula is: d=rt, where d=distance, r=rate, and t=time so with the wind: 300=(2/3)(h+w) : The time against the wind is (40+20)min=60min=1 hr Therefore: 300=1(h-w) 300=h-w 300+w=h Substitute this into the equation with the wind and solve for h: 300=(2/3)((300+w)+w) 300=(2/3)(300+2w) (3/2)(300)=(3/2)(2/3)(300+2w) 450=300+2w 450-300=300-300+2w 150=2w 150/2=2w/2 75=w The speed of the wind is 75 m/h Substitute that into the equation aganst the wind and solve for h. 300+75=h 375=h The speed of the helicopter is 375 m/h. : Sanity check: If the helicopter went 375 m/h and the wind was 75 m/h, will the helicopter fly 300 miles in the allotted time with and against the wind? With the wind: (2/3)(375+75)=300 (2/3)(450)=300 300=300 so far we're right. Against the wind: (1)(375-75)=300 300=300 we're right if we understood the question and converted our time right. Happy Calculating!!!
 Travel_Word_Problems/63919: This question is from textbook algebra and trigonmetry struture method with a tail wind, a helicopter traveled 300mi in an hour and 40 min. the return trip aganst the same wind took 20 min longer. find the wind speed and also the air speed of the helicopter.1 solutions Answer 44588 by funmath(2925)   on 2006-12-05 09:19:47 (Show Source): You can put this solution on YOUR website!with a tail wind, a helicopter traveled 300mi in an hour and 40 min. the return trip aganst the same wind took 20 min longer. find the wind speed and also the air speed of the helicopter. The trick to this one is remembering to convert your time in minutes to time in hours. The time with the tail wind is: 40min(1hr/60min)=40hr/60=(2/3)hr Let the rate of the helicopter be: h Let the rate of the wind be: w The distance formula is: d=rt, where d=distance, r=rate, and t=time so with the wind: 300=(2/3)(h+w) : The time against the wind is (40+20)min=60min=1 hr Therefore: 300=1(h-w) 300=h-w 300+w=h Substitute this into the equation with the wind and solve for h: 300=(2/3)((300+w)+w) 300=(2/3)(300+2w) (3/2)(300)=(3/2)(2/3)(300+2w) 450=300+2w 450-300=300-300+2w 150=2w 150/2=2w/2 75=w The speed of the wind is 75 m/h Substitute that into the equation aganst the wind and solve for h. 300+75=h 375=h The speed of the helicopter is 375 m/h. : Sanity check: If the helicopter went 375 m/h and the wind was 75 m/h, will the helicopter fly 300 miles in the allotted time with and against the wind? With the wind: (2/3)(375+75)=300 (2/3)(450)=300 300=300 so far we're right. Against the wind: (1)(375-75)=300 300=300 we're right if we understood the question and converted our time right. Happy Calculating!!!
 Linear-equations/63929: What is the equation for the line that passes through the point (-2,2) and has a slope of 5? a. y = 5x + 2 b. y = 5x + 12 c. y = 5x - 2 d. none of these 1 solutions Answer 44580 by funmath(2925)   on 2006-12-05 08:58:36 (Show Source): You can put this solution on YOUR website!What is the equation for the line that passes through the point (-2,2) and has a slope of 5? a. y = 5x + 2 . y = 5x + 12 c. y = 5x - 2 d. none of these You can find the equation of a line when give a point and a slope using the point slope formula: , where m=slope and (x1,y1)=given point. m=5 and (x1,y1)=(-2,2) y-2=5(x-(-2)) y-2=5(x+2) y-2=5x+10 y-2+2=5x+10+2 b. Happy Calculating!!!!