See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'funmath'

funmath answered: 2925 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939, >>Next

Linear-equations/56931: can someone please assist me...thanks
GRAPH USING THE INTERCEPT METHOD: 2X-5Y=10
THANKS IS ANDVANCE
1 solutions

Answer 38673 by funmath(2925) About Me  on 2006-10-18 15:16:54 (Show Source):
You can put this solution on YOUR website!
GRAPH USING THE INTERCEPT METHOD: 2X-5Y=10
Let x=0 and solve for y to find the y-intercept.
2(0)-5y=10
-5y=10
-5y/-5=10/-5
y=-2
Plot (0,-2)
Let y=0 and solve for x, this is the x-intercept:
2x-5(0)=10
2x=10
2x/2=10/2
x=5
Plot (5,0)
Connect the points and you have the line:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%28-2x%2B10%29%2F-5%29
Happy Calculating!!!


Exponents/56929: simplify - (4X³)(-2X4)³
(4x to the third power)(-2x to the 4th power)³
1 solutions

Answer 38671 by funmath(2925) About Me  on 2006-10-18 15:09:12 (Show Source):
You can put this solution on YOUR website!
simplify - (4X³)(-2X4)³
I'm not sure if you meant
-%284x%5E3%29%28-2x%5E4%29%5E3
-%284x%5E3%29%28-2%29%5E3%28x%5E4%29%5E3
-%284x%5E3%29%28-2%29%28-2%29%28-2%29%28x%5E%284%2A3%29%29
-%284x%5E3%29%28-8%29%28x%5E12%29
%28-4x%5E3%29%28-8%29%28x%5E12%29
%28-4%29%28-8%29%28x%5E3%29%28x%5E12%29
32x%5E%283%2B12%29
32x%5E15
If you didn't mean to include the negative sign at the beginning, the sign would be -.
Happy Calculating!!!


Exponents/56835: This question is from textbook Algebra 1
x^a+4=x^4x^8 Solve for a.
THANK YOU!
1 solutions

Answer 38670 by funmath(2925) About Me  on 2006-10-18 14:55:28 (Show Source):
You can put this solution on YOUR website!
x%5E%28a%2B4%29=x%5E4x%5E8 Solve for a.
x%5E%28a%2B4%29=x%5E%284%2B8%29
x%5E%28a%2B4%29=x%5E12 the bases are equal so equate their exponents:
a+4=12
a+4-4=12-4
a=8
Happy Calculating!!!


Divisibility_and_Prime_Numbers/56801: 15y-30. Solve by find the larger common factor.
1 solutions

Answer 38669 by funmath(2925) About Me  on 2006-10-18 14:42:45 (Show Source):
You can put this solution on YOUR website!
15y-30. Factor by finding the larger common factor.
15*y-15*2
15(y-2)
::::::::::
You can't solve this unless it is written as an equation:
15(y-2)=0
%2815%2F15%29%28y-2%29=0%2F15
y-2=0
y-2%2B2=0%2B2
y=2
Happy Calculating!!!


Functions/56925: I honestly have no idea how to answer this problem. It's not from a book, my teacher made it up.
f(x)=x+4
find (f(x))^2
I wrote down (x+4)^2 which equals x^2+16 just to have an answer. I'd rather have an example problem like this one so I could learn from that instead of just having a correct answer. Thank you!
1 solutions

Answer 38668 by funmath(2925) About Me  on 2006-10-18 14:32:23 (Show Source):
You can put this solution on YOUR website!
I honestly have no idea how to answer this problem. It's not from a book, my teacher made it up.
f(x)=x+4
find (f(x))^2
I'd rather have an example problem like this one so I could learn from that instead of just having a correct answer. Thank you!
:
Ok, here you go.
What if f(x)=x+5
Find %28f%28x%29%29%5E2
=%28x%2B5%29%5E2 does not =x%5E2%2B25, observe:
=%28x%2B5%29%28x%2B5%29
=x%28x%2B5%29%2B5%28x%2B5%29
=x%28x%29%2Bx%285%29%2B5%28x%29%2B5%285%29
=x%5E2%2B5x%2B5x%2B25
=x%5E2%2B10x%2B25
You are missing your middle term, because you didn't FOIL.
I hope you liked my example, I admire your ethics.
Happy Calculating!!!
funmath


Rational-functions/56917: I am at a loss as to how to solve this. I keep getting 3x as the answer but it is wrong.
3x(x1/2(<--exponent)+1)2 <---squared
1 solutions

Answer 38665 by funmath(2925) About Me  on 2006-10-18 14:14:16 (Show Source):
You can put this solution on YOUR website!
You must need to expand or simplify this. You didn't include your directions.
3x%28x%5E%281%2F2%29%2B1%29%5E2
3x%28x%5E%281%2F2%29%2B1%29%28x%5E%281%2F2%29%2B1%29

3x%28x%5E%282%2F2%29%2Bx%5E%281%2F2%29%2Bx%5E%281%2F2%29%2B1%29
3x%28x%2B2x%5E%281%2F2%29%2B1%29
3x%28x%29%2B3x%282x%5E%281%2F2%29%29%2B3x%281%29
3x%5E2%2B6x%5E%281%2B1%2F2%29%2B3x
3x%5E2%2B6x%5E%282%2F2%2B1%2F2%29%2B3x
3x%5E2%2B6x%5E%283%2F2%29%2B3x
Happy Calculating!!!


Equations/56918: CAN SOMEONE PLEASE ASSIST:
SOLVE: 4X+6=3X
A) -6
B) -5
C) 6
D) 5
1 solutions

Answer 38653 by funmath(2925) About Me  on 2006-10-18 12:56:19 (Show Source):
You can put this solution on YOUR website!
SOLVE: 4X+6=3X
highlight%28A%29 -6
B) -5
C) 6
D) 5
:
4x+6=3x
-4x+4x+6=-4x+3x
6=-x
-(6)=-(-x)
-6=x (A)
Happy Calculating!!!


Linear-systems/56880: SOLVE THE SYSTEM BY GRAPHING
X+Y=4
-X+Y=2
ANY AND ALL ASSISTANCE WOULD BE SO GRATEFUL..PLEASE
1 solutions

Answer 38650 by funmath(2925) About Me  on 2006-10-18 12:52:29 (Show Source):
You can put this solution on YOUR website!
SOLVE THE SYSTEM BY GRAPHING
L1) X+Y=4
L2) -X+Y=2
For L1, graph using the intercept method:
Let x=0, then solve for y:
0+y=4
y=4
Plot (0,4) (this is the y-intercept)
Then let y=0 and solve for x:
x+0=4
x=4
Plot (4,0) (this is the x-intercept)
Connect the points and you have a line:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C-x%2B4%29
For L2, graph using the intercept method:
Let x=0 and solve for y:
-(0)+y=2
y=2
Plot (0,2) this is your y-intercept.
Let y=0 and solve for x:
-x+0=2
-x=2
-(-x)=-(2)
x=2
Plot (2,0) this is your x-intercept.
Connect your points and you have a second line:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C-x%2B4%2Cx%2B2%29
The lines intersect at (1,3), therefore your solution is (1,3)
Happy Calculating!!!


absolute-value/56900: PLEASE HELP:
5. Evaluate. |-19| - |-5|
A) -24
B) -14
C) 14
D) 24
1 solutions

Answer 38639 by funmath(2925) About Me  on 2006-10-18 11:55:15 (Show Source):
You can put this solution on YOUR website!
PLEASE HELP:
5. Evaluate. |-19| - |-5|
A) -24
B) -14
highlight%28C%29 14
D) 24
|-19|-|-5| Work the absolute value first
(19)-(5) Then subtract.
19-5
14 (C)
Happy Calculating!!!


Exponents-negative-and-fractional/56742: n^-2/n^3
1 solutions

Answer 38555 by funmath(2925) About Me  on 2006-10-17 18:00:36 (Show Source):
You can put this solution on YOUR website!
The rules we're going to use are:
highlight%28a%5E%28-m%29=1%2Fa%5Em%29
highlight%28%28a%5Em%29%28a%5En%29=a%5E%28m%2Bn%29%29
n%5E%28-2%29%2Fn%5E3
1%2F%28%28n%5E2%29%28n%5E3%29%29
1%2F%28n%5E%282%2B3%29%29
1%2Fn%5E5
Happy Calculating!!!


Equations/56795: This question is from textbook Pre-Algebra
Describe what steps you would take to solve 8x+5=2x-7.
1 solutions

Answer 38554 by funmath(2925) About Me  on 2006-10-17 17:55:40 (Show Source):
You can put this solution on YOUR website!
Describe what steps you would take to solve 8x+5=2x-7.
First we want to get the numbers with x's on one side of the equal sign and the numbers without x's on the other side of the equal sign within the rules of algebra. What ever you do to one side of the = sign to accomplish that you have to do to the other side.
8x+5=2x-7 Subtract 2x from both sides:
-2x+8x+5=-2x+2x-7
6x+5=0-7
6x+5=-7 Now subtract 5 from both sides:
6x+5-5=-7-5
6x+0=-12
6x=-12 The x is being multiplied by 6, the opposite of multiplying is dividing, so divide 6 on both sides:
6x/6=-12/6
1x=-2
highlight%28x=-2%29
To check your answer, substitute x=-2 into the original equation and see if both sides =.
8(-2)+5=2(-2)-7
-16+5=-4-7
-11=-11 We're right!!!
Happy Calculating!!!


Mixture_Word_Problems/56767: 9. Sally bought three chocolate bars and a pack of gum and paid $1.75. Jake bought two chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum.
Thank you very much for all you do to help those who struggle!

1 solutions

Answer 38551 by funmath(2925) About Me  on 2006-10-17 17:47:47 (Show Source):
You can put this solution on YOUR website!
9. Sally bought three chocolate bars and a pack of gum and paid $1.75. Jake bought two chocolate bars and four packs of gum and paid $2.00. Find the cost of a chocolate bar and the cost of a pack of gum.
Let the price of the chocolate be:x
Let the price of the gum be:y
Then Sally's equation is:
3x+y=1.75
Jake's equation is:
2x+4y=2.00
Solve Sally's equation for y and substitute that into Jake's equation and solve for x:
3x+y=1.75
-3x+3x+y=1.75-3x
y=1.75-3x
2x%2B4%2Ahighlight%281.75-3x%29=2.00
2x%2B7-12x=2
-10x%2B7=2
-10x%2B7-7=2-7
-10x=-5
-10x%2F-10=-5%2F-10
x=.50
Substitute that itnto Sally's equation for x and solve for y:
3%2Ahighlight%28.50%29%2By=1.75
1.50%2By=1.75
-1.50%2B1.50%2By=1.75-1.50
y=.25
The chocolate cost x=$.50 and the gum cost y=$.25
Happy Calculating!!!


Complex_Numbers/56790: (x-4)
______
(x/4)-(4/x)
that line makes it a fraction. please simplify this complex fraction. thanks.
1 solutions

Answer 38546 by funmath(2925) About Me  on 2006-10-17 17:29:22 (Show Source):
You can put this solution on YOUR website!
%28x-4%29%2F%28%28x%2F4-4%2Fx%29%29 Multiply the numerator and denominator by the LCD of the whole complex fraction, 4x.
4x%28x-4%29%2F%284x%28x%2F4-4%2Fx%29%29
4x%28x-4%29%2F%284x%5E2%2F4-16x%2Fx%29
4x%28x-4%29%2F%28x%5E2-16%29 Factor the bottom:
4x%28x-4%29%2F%28%28x%2B4%29%28x-4%29%29 Cancel the (x-4)'s
4x%2Across%28%28x-4%29%29%2F%28%28x%2B4%29%2Across%28%28x-4%29%29%29
highlight%284x%2F%28x%2B4%29%29
Happy Calculating!!!


Linear-equations/56774: 16. Are the following lines parallel, perpendicular, or neither?
L1 through (–4, –7) and (1, 3)
L2 through (2, 6) and (4, 10)
A) Parallel
B) Perpendicular
C) Neither
Thanks for all your help!!
1 solutions

Answer 38541 by funmath(2925) About Me  on 2006-10-17 17:22:05 (Show Source):
You can put this solution on YOUR website!
16. Are the following lines parallel, perpendicular, or neither?
L1 through (–4, –7) and (1, 3)
L2 through (2, 6) and (4, 10)
A) Parallel
B) Perpendicular
C) Neither
If the lines are parallel their slopes (m)are equal.
If the lines are perpendicular their slopes are negative reciprocals (opposite signs and upside down).
If it's not either of those it's neither.
The formula for finding the slope (m) given two points (x1,y1) and (x2,y2) is: highlight%28m=%28y2-y1%29%2F%28x2-x1%29%29
L1 has a slope of m1=%283-%28-7%29%29%2F%281-%28-4%29%29
m1=%283%2B7%29%2F%281%2B4%29
m1=10%2F5
highlight%28m1=2%29
L2 has a slope of m2=%2810-6%29%2F%284-2%29
m2=4%2F2
highlight%28m2=2%29
m1=m2, therefore the lines are parallel. (A)
Happy Calculating!!!


Travel_Word_Problems/56780: A plane flies 500 miles with the wind and 340 miles against the wind in the same length of time. If the speed of the wind is 28mph, what is the speed of the plane in still air?
1 solutions

Answer 38534 by funmath(2925) About Me  on 2006-10-17 17:13:19 (Show Source):
You can put this solution on YOUR website!
A plane flies 500 miles with the wind and 340 miles against the wind in the same length of time. If the speed of the wind is 28mph, what is the speed of the plane in still air?
the distance formula is d=rt solve tihs for t and you have: d%2Fr=t
Both our t's are the same so we're going to let t=t or d/r with the wind =d/r against the wind.
Let the rate of the plane be:x
Then the rate with the wind is: x+28
And the rate against the wind is: x-28
The distance with the wind is:500
The distance against the wind is: 340
The problem to solve is:
500%2F%28x%2B28%29=340%2F%28x-28%29
500%28x%2B28%29%28x-28%29%2F%28x%2B28%29=340%28x%2B28%29%28x-28%29%2F%28x-28%29

500%28x-28%29=340%28x%2B28%29
500x-14000=340x%2B9520
-340x%2B500x-14000=-340x%2B340x%2B9520
160x-14000=9520
160x-14000%2B14000=14000%2B9520
160x=23520
160x%2F160=23520%2F160
x=147
The rate of the plane in still air is: 147 mph
Happy Calculating!!!


Linear-equations/56784: I am using the intercept method and I do not know the beginning this is the problem and this is what I got
2x+3y=6
3x=6-2x subtract
6-2 add from there I am lost please help me get the concept Thank you
1 solutions

Answer 38528 by funmath(2925) About Me  on 2006-10-17 16:55:03 (Show Source):
You can put this solution on YOUR website!
I am using the intercept method:
2x+3y=6
Let x=0 and solve for y, this is the y-intecept:
2(0)+3y=6
0+3y=6
3y=6
3y/3=6/3
y=2
Plot the y-intercept: (0,2)
Let y=0 and solve for x, this is the x-intercept:
2x+3(0)=6
2x+0=6
2x=6
2x/2=6/2
x=3
Plot the x-intercept: (3,0)
Connect the dots and you should have a line that looks like:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%28-2x%2B6%29%2F3%29
Happy Calculating!!!


Money_Word_Problems/56781: This question is from textbook Beginning Algebra
Can someone help me on this problem?
In planning for a new item, a manufacturer assumes that the number of items produced x and the cost in dollars C of producing these items are related by a linear equation. Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce. Find the equation that relates C and x.
Thanks,
Sher
1 solutions

Answer 38525 by funmath(2925) About Me  on 2006-10-17 16:46:25 (Show Source):
You can put this solution on YOUR website!
Hi Sher,
In planning for a new item, a manufacturer assumes that the number of items produced x and the cost in dollars C of producing these items are related by a linear equation. Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce. Find the equation that relates C and x.
Let (x1,C1)=(100,10000) Notice, I'm letting C=y and using the formulas that you've already used.
Let (x2,C2)=(300,22000)
Find their rate, or slope using: m=%28C2-C1%29%2F%28x2-x1%29
m=%2822000-10000%29%2F%28300-100%29
m=12000%2F200
m=60
Use the point slope formulaC-C1=m%28x-x1%29
C-10000=60%28x-100%29
C-10000=60x-6000
C-10000%2B10000=60x-6000%2B10000
C=60x%2B4000
Another way to write this is:
C%28x%29=60x%2B4000
Happy Calculating, Sher!!!


Geometry_Word_Problems/56759: I'm not sure if I'm going about answering this algabraic question right or not. If you could please let me know whether or not I'm on the right track that would be greatly appreciated. The question is as follows:
The length of a rectangle is 10cm more than twice the width. The perimeter of the rectangle is 66cm. FInd the length and width.
This is what I'm doing to solve:
Let x = width
10+2x = length
2(length+width)= Perimeter
solving with this beginning:
x + (10+2x)= 66
Is this the correct procedure to getting my answer or have I forgotten something?
1 solutions

Answer 38511 by funmath(2925) About Me  on 2006-10-17 15:44:56 (Show Source):
You can put this solution on YOUR website!
I'm not sure if I'm going about answering this algabraic question right or not. If you could please let me know whether or not I'm on the right track that would be greatly appreciated. The question is as follows:
The length of a rectangle is 10cm more than twice the width. The perimeter of the rectangle is 66cm. FInd the length and width.
This is what I'm doing to solve:
Let x = width
10+2x = length
2(length+width)= Perimeter
solving with this beginning:
2(x + (10+2x))= 66 <---You forgot your 2.
2(3x+10)=66
6x+20=66
6x+20-20=66-20
6x=46
6x/6=46/6
x=7.6667 cm
Width=7.6667 cm
length=10+2x=10+2(7.6667)=25.33333 cm
Happy Calculating!!!



real-numbers/56758: Again, didn't know where to put this problem.
Solve and Check:
In baseball a player's batting average is the ratio of hits to the number of times he or she has batted. Thus, if the player has an average of .3000, it means he or she got 300 hits in 1000 at bats. In order to have an average of .300, how many hits would the batter have to get in 400 times at bat?
1 solutions

Answer 38508 by funmath(2925) About Me  on 2006-10-17 15:36:06 (Show Source):
You can put this solution on YOUR website!
Solve and Check:
In baseball a player's batting average is the ratio of hits to the number of times he or she has batted. Thus, if the player has an average of .3000, it means he or she got 300 hits in 1000 at bats. In order to have an average of .300, how many hits would the batter have to get in 400 times at bat?
batting average=(hits)/(times batted)
your batting average =.300
times batted=400
hits=x
.300=x%2F400
%28400%29%28.300%29=400x%2F400
120=x
check:
.300=120%2F400
.300=.300 We're right!!!
Happy Calculating!!!


logarithm/56747: I having trouble solving this equation
log (x+3)=1-log x
1 solutions

Answer 38507 by funmath(2925) About Me  on 2006-10-17 15:29:18 (Show Source):
You can put this solution on YOUR website!
The rules we are going to use are:
highlight%28log%28a%29%2Blog%28b%29=log%28a%2Ab%29%29
highlight%28log%28a%29=m%29==>>highlight%2810%5Em=a%29
log%28%28x%2B3%29%29=1-log%28%28x%29%29
log%28%28x%29%29%2Blog%28%28x%2B3%29%29=1-log%28%28x%29%29%2Blog%28%28x%29%29
log%28%28x%29%29%2Blog%28%28x%2B3%29%29=1
log%28x%28x%2B3%29%29=1
10%5E1=x%28x%2B3%29
10=x%5E2%2B3x
-10%2B10=x%5E2%2B3x-10
0=x%5E2%2B3x-10 Factor:
0=(x__)(x___)
We need to fill the blanks with two integers that multiply to give us:-10, but add to give us:+3
5*(-2)=-10 and 5-2=+3
0=(x+5)(x-2)
x+5=0 and x-2=0
x=-5 and x=2
We have to check for extraneous solutions:
log%28-5%2B3%29=1-log%28-5%29 x=-5 is extraneous, because we can't take the log of a negative number.
log%282%2B3%29=1-log%282%29
log%285%29=1-log%282%29
.6989700043=.698700043
x=2 is a solution.
Happy Calculating!!!


Equations/56751: Solve and check:
(x + 1)/6=4/3
1 solutions

Answer 38506 by funmath(2925) About Me  on 2006-10-17 15:11:25 (Show Source):
You can put this solution on YOUR website!
Solve and check:
%28x%2B1%29%2F6=4%2F3Multiply both sides by the LCD, 6:
6%28x%2B1%29%2F6=6%284%2F3%29
cross%286%29%2A%28x%2B1%29%2Fcross%286%29=24%2F3
x%2B1=8
x%2B1-1=8-1
highlight%28x=7%29
Check by substituting x=7 into the original equation and see if both sides =.
%287%2B1%29%2F6=4%2F3
8%2F6=4%2F3
2%2A4%2F%282%2A3%29=4%2F3
4%2F3=4%2F3 We're right again!!!

Happy Calculating!!!


Money_Word_Problems/56732: A riding stable borrowed $1,000 at a cost of $15 interest. If the loan was made at 6% simple interest, the length of the loan was:


a. 9 months
b. 90 days
c. 25 days
d. 4 days


1 solutions

Answer 38505 by funmath(2925) About Me  on 2006-10-17 15:06:05 (Show Source):
You can put this solution on YOUR website!
A riding stable borrowed $1,000 at a cost of $15 interest. If the loan was made at 6% simple interest, the length of the loan was:


a. 9 months
b. 90 days
c. 25 days
d. 4 days

highlight%28I=Prt%29, where I = interest, P=principle(money borrowed in this case), r=rate, and t=time in years (they count a year as 360 days for some reason.)
I%2FPr=Prt%2FPr
I%2FPr=t I=15, P=1000, and r=6/100=.06
t=%2815%29%2F%281000%2A.06%29
t=15%2F60
t=1%2F4
1/4 of a year is t=%281%2F4%29%28360%29days
t=90 days (b)
Happy Calculating!!!


Expressions-with-variables/56722: 2(t-3)+2=2(2t-6). The answer I got was -4, but the answer in the book is 4. What am I doing wrong. Could you please show me the distribution/elimination for this equation.
Thank you very much.
1 solutions

Answer 38504 by funmath(2925) About Me  on 2006-10-17 14:57:16 (Show Source):
You can put this solution on YOUR website!
2(t-3)+2=2(2t-6)
2(t)+2(-3)+2=2(2t)+2(-6)
2t-6+2=4t-12
2t-4=4t-12 Notice I move the smallest coefficient of t, to avoid problems with signs. Maybe that will help you.
-2t+2t-4=-2t+4t-12
-4=2t-12
12-4=2t-12+12
8=2t
8/2=2t/2
4=t
Happy Calculating!!!


Linear-equations/56711: This question is from textbook
Find the x-intercept and y-intercept of the equation 5x - 3y = 30.
1 solutions

Answer 38503 by funmath(2925) About Me  on 2006-10-17 14:48:31 (Show Source):
You can put this solution on YOUR website!
Find the x-intercept and y-intercept of the equation 5x - 3y = 30.
For the y-intercept, let x=0 and solve for y:
5(0)-3y=30
-3y=30
-3y/-3=30/-3
y=-10
The y-intercept is (0,-10)
For the x intercept let y=0 and solve for x:
5x-3(0)=30
5x=30
5x/5=30/5
x=6
The x-intercept is (6,0)
Happy Calculating!!!


Functions/56716: This question is from textbook
If f(x) =x^2 + 5, find f(a+h)-f(a)
1 solutions

Answer 38502 by funmath(2925) About Me  on 2006-10-17 14:13:49 (Show Source):
You can put this solution on YOUR website!
If f%28x%29=x%5E2%2B5, find f(a+h)-f(a)
f%28a%2Bh%29=%28a%2Bh%29%5E2%2B5=a%5E2%2B2ah%2Bh%5E2%2B5
f%28a%29=a%5E2%2B5
f%28a%2Bh%29-f%28a%29=%28a%5E2%2B2ah%2Bh%5E2%2B5%29-%28a%5E2%2B5%29
f%28a%2Bh%29-f%28a%29=a%5E2%2B2ah%2Bh%5E2%2B5-a%5E2-5
f%28a%2Bh%29-f%28a%29=2ah%2Bh%5E2
Happy Calculating!!!


Linear-equations/56713: This question is from textbook
Find an equation for the line with slope 1/2 and the y-intercept 3.
1 solutions

Answer 38498 by funmath(2925) About Me  on 2006-10-17 14:01:28 (Show Source):
You can put this solution on YOUR website!
Find an equation for the line with slope 1/2 and the y-intercept 3.
The slope intercept form of a line is highlight%28y=mx%2Bb%29, where m=slope and b=y-intercept. Your m=1/2 and b=3
y=%281%2F2%29x%2B3
Happy Calculating!!!


Linear-equations/56714: This question is from textbook
Find the slope of the line through the points A(-1,6) and B(5,2)
1 solutions

Answer 38495 by funmath(2925) About Me  on 2006-10-17 13:45:52 (Show Source):
You can put this solution on YOUR website!
Find the slope of the line through the points (x1,y1)=A(-1,6) and (x2,y2)=B(5,2)
The formula for finding the slope (m) when given two points is:highlight%28m=%28y2-y1%29%2F%28x2-x1%29%29
m=%282-6%29%2F%285-%28-1%29%29
m=-4%2F6
m=2%2A%28-2%29%2F%282%2A3%29
m=-2%2F3
Happy Calculating!!!


Linear-equations/56715: This question is from textbook
Find an equation for the line with y-intercept 3 that is perpendicular to the line y=2/3x -4.
1 solutions

Answer 38494 by funmath(2925) About Me  on 2006-10-17 13:38:05 (Show Source):
You can put this solution on YOUR website!
Find an equation for the line with y-intercept 3 that is perpendicular to the line y=2/3x -4.
The slope intercept form of a line is highlight%28y=mx%2Bb%29 where m=slope and b=y-intercept.
The line they gave you has a slope of:y=highlight%28%282%2F3%29%29x-4, m=2/3.
Perpendicular lines have slopes that are negative reciprocals of each other, so turn the slope upside down and change its sign.
Our new line has a slope, m=-3/2 and a y-intercept,b=3. Plug those values into your slope intercept form of a line and you have:
highlight%28y=%28-3%2F2%29x%2B3%29
Happy Calculating!!!


Functions/56719: This question is from textbook Algebra 2
When working with domains and ranges and a question asks you to use a mapping diagram to represent the relation, how do you do that? I am unaware of how to make a 'mapping diagram'. Help!
1 solutions

Answer 38493 by funmath(2925) About Me  on 2006-10-17 13:31:32 (Show Source):
You can put this solution on YOUR website!
When working with domains and ranges and a question asks you to use a mapping diagram to represent the relation, how do you do that?
I can't really show you on the computer, but I should be able to get you to visualize it.
Draw an tall oval and put all your x's or independent variables in it.
Then draw another tall oval and put all your y's or dependet values in it.
Draw arrows from the x's in the first oval to their corresponding y-values in the second oval,
That's a mapping diagram, functions will only have one arrow going out of every x value.
Happy Calculating!!!


Trigonometry-basics/56717: This question is from textbook
find the maximum value of y=-x^2 + 6x
1 solutions

Answer 38492 by funmath(2925) About Me  on 2006-10-17 13:23:55 (Show Source):
You can put this solution on YOUR website!
find the maximum value of y=-x%5E2%2B6x
The maximum value of a parabola, whose coefficient of x^2 is negative, is it's vertex.
This quadratic equation is in standard for:highlight%28y=ax%5E2%2Bbx%2Bc%29, our a=-1, b=6, and c=0.
The equation for finding the x value of a quadratic equation written in standard form is: highlight%28x=-b%2F2a%29
x=-%286%29%2F%282%28-1%29%29
x=-6%2F-2
x=3
Plug that into the parabola for x and you'll find the maximum value.
y=-%283%29%5E2%2B6%283%29
y=-9%2B18
y=9
The maximum value of this parabola is at (3,9).
Happy Calculating!!!


Human-and-algebraic-language/56707: This question is from textbook
Is this just ambiguous? Which translation do you consider correct? The text seems to think it's the 2nd since the answer given is -3. Why not the 1st one (follow order of operations, no punctuation in the sentence)?
If twice a number added to 3 is divided by the number plus 1 the result is 3/2.
(2x+3)/x + 1 = 3/2
or (2x+3)/(x+1) = 3/2
or 2(x+3)/x +1 = 3/2
or 2(x+3)/(x +1)= 3/2
Would this be a correct translation for the following?
If twice, a number added to 3 is divided by the number, plus 1 the result is 3/2
2(x+3)/x + 1 = 3/2

1 solutions

Answer 38489 by funmath(2925) About Me  on 2006-10-17 13:02:34 (Show Source):
You can put this solution on YOUR website!
Which translation do you consider correct?
(2x+3)/x + 1 = 3/2 is translated: If twice the number added to three is divided by the number is added to 1 the result is 3/2.
:
(2x+3)/(x+1) = 3/2 is translated: If twice a number added to 3 is divided by the number plus 1 the result is 3/2.
:
2(x+3)/x +1 = 3/2 is translated: If twice the sum of a number and 3 is divided by the number and added to 1 the result is 3/2.
;
2(x+3)/(x +1)= 3/2 is translated: if twice the sum of a number and 3 is divided by the number plus 1 the result is 3/2.
You're right, it is kind of ambiguous. Even I'm a little mushy brained now. I think that if they wanted you to add 1 to the fraction instead of making it part of the denominator, they would have used a conjunction like "and" or a comma as you suggested.
Happy Calculating!!!