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Parallelograms/378075: Suppose the heights of 18-year-old men are approximately normally distributed, with mean 69 inches and standard deviation 2 inches.
(a) What is the probability that an 18-year-old man selected at random is between 68 and 70 inches tall?
(b) If a random sample of sixteen 18-year-old men is selected, what is the probability that the mean height x is between 68 and 70 inches? 1 solutions
Answer 268702 by ewatrrr(10682) on 2010-11-30 09:30:03 (Show Source):
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logarithm/377694:
please help! i"m trying to solve:
log 2 (x-1) - log 2 (x+3) = log 2 (1/x)
This is what i tried, but i think it's wrong: used quotient rule like this: log 2 (x-1/x+3) = log 2 (1/x) OK! NOW WHAT???!!! I'm lost! :(
1 solutions
Answer 268396 by ewatrrr(10682) on 2010-11-29 16:23:29 (Show Source):
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Polynomials-and-rational-expressions/377655: Graph the parabolas. Show the vertex, axis of symmetry, x intercepts, y intercepts and write the domain and range in interval notation.
f(x)=x^2-4x+3
f(x) = (x+1)^2-4 1 solutions
Answer 268357 by ewatrrr(10682) on 2010-11-29 15:28:55 (Show Source):
You can put this solution on YOUR website!
Hi
Note: the vertex form of a parabola, where(h,k) is the vertex
f(x)=x^2-4x+3 Or f(x)= (x-2)^2 -1 in vertex form: x-intercepts (3,0)&(1,0)
vertex Pt(2,-1), axis of symmetry x = 2, (0,3) the y-intercept

f(x) = (x+1)^2-4 x-intercepts (1,0)&(-3,0)
vertex Pt(-1,-4), axis of symmetry x = -1, (0,-3) the y-intercept

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Rate-of-work-word-problems/377620: I have a problem on my homework that has very little detail in the textbook. I need to know a formula for the following: Two pipes working together can fill a tank in 12hrs. Working alone, the larger one can fill the tank in 18hrs less than the smaller one. How long does it take for the smaller tank working alone? Thank you so much! 1 solutions
Answer 268310 by ewatrrr(10682) on 2010-11-29 14:24:02 (Show Source):
You can put this solution on YOUR website!Hi
the larger one can fill the tank in 18hrs less than the smaller one.
Let x represent the time for the smaller alone,
then (x-18hr)would be the time for the larger alone
Per hour is the Equalizer
1/x + 1/(x-18) = 1/12 Mulitiplying each term by 12x(x-18)so all denominators = 1
12(x-18) + 12x = x(x-18)
solving for x
12x - 12*18 +12x = x^2 - 18x
24x - 12*18 = x^2 - 18x
x^2 - 42x + 216 = 0

x = 6 Cannot use
x = 36hr, the time for the smaller alone. 18hr for the larger alone (36-18)
CHECKING our Anwer
1/36 + 1/18 = 2/72 + 4/72 = 6/72 = 1/12
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Linear-systems/377618: I am needing help with this verbal problem please read entire thing to the bottom as is a little long and Thank you for you help.
a. when x=75
c=2x+20
=2(75)+20
=150+20
=170
we have the ordered pair(75,170)
b.when x=300
c=2x+20
=2(300)+20
=600+20
=620
we have the ordered pair(300,620)
c. when x=1000
c=2x+20
=2(1000)+20
=2000+20
=2020
WE HAVE THE ORDERED PAIR (1,000,2020)
In the example, find the number of units produced when the total cost is (a)$430, (b)$700 and (c)$1,400. write the answers as ordered pairs. I am really confused as to how to do this and the steps to take to do this. I would really appreciate some help on this.
1 solutions
Answer 268303 by ewatrrr(10682) on 2010-11-29 14:02:31 (Show Source):
You can put this solution on YOUR website!
Hi
c=2x+20
Can only assume that x is the number of units and c is the cost of producing them.
(a)$430
$430 = 2x + 20
$410 = 2x
205 = x, the number of units costing $430 (205,430)
(b)$700 c = $700
$700 = 2x + 20
$680 = 2x
340 = x, the number of units costing $700 (340,700)
(c)$1,400 c =$1400
$1400 = 2x + 20
$1380 = 2x
690 = x the number of units costing $1400 (690,1400)
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