Hi,

Assuming Absolute Value of (x-11)

 |x-11| = 14

  x-11 = 14   

  x-11 = -14  

 

Hi,

 y >-3  and x ≤2

 Name a point for y>-3  pt(0,-2) Pt(3,-2)  All Pts above the Green Line

 Name a point for  x ≤2  Pt(1,-4) All Pts to the Left of the Blue Line

 Name a point for both. (1,-2)

 

Hi,

 –  

 –  

 –  

 

Hi,

normal population has μ = 30 and σ = 7. 

determine the mean of X and standard deviation of X.

 random sample of size n = 6

X = 30

 s = 

 

Hi, 

While driving 90km/h how far can you travel in 3.5 hrs ?

Note: D = rt   

 

Hi, 

A triangle has side lengths of ,  and . 

Is it right acute or obtuse?

Doing the Squares Testing:   |||Obtuse Triangle

***If is true, then we have a right triangle

***If  is the case, then we have an acute triangle. 

***If , then we have an obtuse triangle.

 

Hi, Previously Posted

Last year, the personal best high jumps of track athletes in a nearby state 

were normally distributed with a mean of 205 cm and a standard deviation ofcm.

P(205< X <231) = 

For the normal distribution: 

one  standard deviation from the mean accounts for about 68.2% of the set 

 standard deviations from the mean account for about 95.4%

and three standard deviations from the mean account for about 99.7%.

 

Hi, 

body temperatures with a mean of 98.6 degrees, 

and a sample standard deviation of 0.5 degrees

what two values should 99.7% of all temperatures lie? 

Within  SD of the mean:

 

     



For the normal distribution: 

one  standard deviation from the mean accounts for about 68.2% of the set 

two standard deviations from the mean account for about 95.4%

and three standard deviations from the mean account for about 99.7%.

 

Hi, 

Last year, the personal best high jumps of track athletes in a nearby state 

were normally distributed with a mean of 205 cm and a standard deviation ofcm.

P(205< X <231) = 

For the normal distribution: 

one  standard deviation from the mean accounts for about 68.2% of the set 

 standard deviations from the mean account for about 95.4%

and three standard deviations from the mean account for about 99.7%.

 

Hi, 

foil method 

(5a+2) (a-5) =

F	First terms     a^2

O	Outside terms  -25a

I	Inside terms     2a

L	Last terms      -10

  

 

Hi,



segment parallel to one side of the triangle forms Similar Triangles:

Corresponding sides of similar triangles are proportional.

 ,  Cross Multiplying to solve



  y = 8

 ,  Cross Multiplying to solve 

     2x + 24 = 60

          2x = 36

        x = 18

      

 

Hi, 

A line through(2 , 1)meets the curve x^2- 2x - y=3 at A(-2 , 5) and at B

the line passing through (2,1) and (-2,5)

(2,1) and 

(-2,5)  m = -4/4 = -1

 y = -x + b

 1 = -2 + b     ||Using PT(2,1) to solve for b

  3 = b

  = -x + 3   AND  x^2- 2x - y=3 or  = x^2- 2x - 3

  x^2-2x-3 = -x + 3

  x^2-x - 6 = 0

 (x-3)(x+2) = 0

  (x+2) = 0  We have A(-2 , 5)

 (x-3) = 0    B(3,0)      |||  = -x + 3 

 

Hi, 

     |||Need to isolate the radical on one side the EQ

 

 

 

 

 a^2- 11a + 18 = 0

factoring:

 (a-9)(a-2) = 0

 (a-9)= 0

    a = 9

 (a-2) = 0

    a = 2

 

Hi, Previously Posted

Find the range, standard deviation, and variance for the following sample data:

89, 6, 96, 43, 11, 30, 30, 77, 34, 67, 60, 5, 91, 26, 93, 22 



Entering Date is Excel spreasheet column and Using the Data Analysis Tool...

mean: 780/16 = 48.75

variance:  1080.467

standard deviation:  =  32.87

 

Hi, 

Assume that average annual salary for a worker in th u.s. is $39,000 and the

 annual annual salary for americans are normally distributed with a SD = $7,000

 P(X<25) = P(z < -2)  NORMSDIST (-2) = .0228,   2.28%

P(X >44) = 1- P(z < (44,000 - 39,000)/7000) = 1 - P(z< .7143) = 1- .7325 = .2375,  % 

 

Hi, 

average income is approximately $45,000/year in this state, with a SD of about $9000.

using a normal distribution to approximate values that %  of houseolds lie

 1-.89 = .11, .11/2 = .055  Excel NORMSINV(.055)gives z = 1.59819

 1.59819 = (X -45000)/9000 

  X = 1.598*9000 + 45000 = $59,382

and

 -1.59819 = (x -45000)/9000 

x = -1.598*9000 + 45000 = $30,618

 

Hi, 

Solve the following equations in the interval [0, 2pi]. 

1) cos(t)= (1/2)  t = 60° , 300°

2)   t = 135° , 225°

Thought You may find this Unit Circle (cosx,sinx) presentation helpful in Your studies

 

Hi, 

For a particular sample of 77 scores on a psychology exam, the following results were obtained.

 First quartile = 42 Third quartile = 69  

 Mean = 62,  Median = 56  

I. What score was earned by more students than any other score? by defn.

II. What was the highest score earned on the exam? , x =

III. What was the lowest score earned on the exam? 

 IV. According to Chebyshev's Theorem, how many students scored between 32 and 92?  ,  = 76.23 or 76 

 V. Assume that the distribution is normal. Based on the Empirical Rul... 

how many students scored between 52 and 72?  OR 52 

The empirical rule says that if you go 1 standard deviation out from the mean that you will capture 68 % of your data

 Please show all of your work. 

 

 

Hi, 

Find the range, standard deviation, and variance for the following sample data:

89, 6, 96, 43, 11, 30, 30, 77, 34, 67, 60, 5, 91, 26, 93, 22 



Entering Date is Excel spreasheet column and Using the Data Analysis Tool...

mean: 780/16 = 48.75

variance:  1080.467

standard deviation:  =  32.87

 

Hi, 

Solve then graph.

t+20 ≥ 7

Yes, t ≥ -13

to graph on a number line, one would use an arrow to the  from t = -13,

(the arrow including the dot on -13)

 

Hi, 





            a = -25

 

Hi, 

Keiko bicycles 8km/h faster than Javier. 

Let x and (x+8) represent Javier's and Keiko's speeds respectively

Question states*** Note: D = rt or D/r = t

In the same time it takes Javier to bicycle 30 km, Keiko can bicycle 54 km.

  Cross Multiplying to solve

    54x = 30x + 240

      24x = 240

        x = 240/24 =10kmph, Javier's speed.  Keiko's speed is 18kmph

 

Hi, 

preparing 500 ml of a 0.6% KCl solution from 10% KCl solution & distilled water 

         Water  = Water

 

          

               x = 200ml of distilled water needs to be added

 

Hi, 

A study was conducted to estimate the mean amount spent on birthday gifts for a typical family having two children. 

A sample of 180 was taken, and the mean  $219.76. Assuming SD = $41.77, 

find the 99% confidence interval for µ, the mean for all such families. 

ME = 2.576[41.77/sqrt(180)] 		

-----		

CI: 219.76-ME < u < 219.76 + ME	

 

Hi, 

The following data lists the average monthly snowfall for January in 15 cities around the US:

 40 44 43 15 22 29 38 22 14 13 28 29 47 31 18

Find the mean, variance, and standard deviation.

Entering Date is Excel spreashett column and Using the Data Analysis Tool...

mean: 433/15 = 28.8667 

variance:  131.981

standard deviation:  =  11.4883  

 

Hi, 

Note: use of non-caps, much easier to read for most. 

6x + 5 = 13 + 2x

   4x = 8

    x = 2

 

Hi, If I am understanding the format Properly:

 -

 -

 -

 - = 0

 

Hi, re TY... appears that 3.25lb bag was sold for 1.05 (price of 3lb bag) 

The advertisement price of potatoes is 35 cents per pound. 

If a 3-pound bag actually weighs 3 1/4 pounds,what is the closest approximation 

in cents to the actual price per pound for that bag

Assuming the bag ( that actually weighs 3.25lb) is purchased for the price of a 3lb bag: 

 = $1.05   and   

  = .32˘/lb

 

Hi, 

6 people are going to play a ball game. Each team has 3 players. 

How many different team combinations are possible? 6C3 = 6!/(3!3!) = 20 possible

 

Hi, 

A researcher claims that the average age of people who buy lottery tickets is 65

Sample mean of the 30 ages is 62.4 and sample SD = 16

z = = -.89

Sample size 30, Degree of Freedom 29,  a = 0.05%, (z = -2.05)

NOT enough evidence to reject researcher's claim

 

Hi

Solution to the following system:

 x+y=7  

2x-y=2 

 3x = 9, x = 3 and y = 4



2x+y=4 and ||||multiplying 1st EQ thru by 2 to  eliminate the y variable

3x-2y=13

4x+2y=8 and ||||Result of multiplying 1st EQ thru by 2 to  eliminate the y variable

3x-2y=13    

  7x = 21, x = 3  and y = -2   (2x+y = 4 or y = 4-2x)