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If all the digits are repeating from the beginning, you would place those in the numerator and 9's in the denominator.
You place as many nines as you have digits repeating;
ex.
0.18 and the 18 is repeating;
; then reduce
Ex.
.405 and the 405 is repeating;
; then reduce
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Factor x squared minus 9 over 3x minus 9


Cancel out the (x-3);

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(-4)(15p)= -60p
You would multiply the -4(15), which is a negative * a positive, so the answer will be negative, also 4(15)=60
So tou have -60, and the p stays p because we do not now what it =.
So your answer would be;
-60p
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=48
Distribute the
=48
=48
Multiply each side by 9;
(9)=48(9)
That cancels out the nine on the left side of equation;
-8x+16=432
Subtract 16 form both sides
-8x+16-16=432-16
-8x=416
Divide each side by -8;

x=-52
Don't forget to check your answer
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Find three consecutive odd intergers whose sum is 105.
The consecutive numbers will be;
x, x+2, x+4
x+(x+2)+(x+4)=105
3x+6=105
3x=105-6
3x=99
x=33
Now that you have the first odd integer, you think you could get the others?
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5b+15
______
7b+21
Start with the numerator;
5b+15;
to factorout the 5,
5(b+3)
Now the denominator;
7b+21
facot out the 7;
7(b+3)
now you have;

Now you can cancel out the (b+3); and your answer would be;

Glad to hear your coming back, GOOD LUCK!!!
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Two consecutive odd numbers. Five less than twice the smaller is equal to four more than the larger. Find the two numbers
Our odd numbers will be;
x, x+2
Five less than twice the smaller is equal to;
2x-5=
four more than the larger
(x+2)+4
Now but them together;
2x-5=(x+2)+4
2x-5=x+6
2x-x=6+5
x=11
x+2=13
So the odd numbers are;
11, 13
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x=greater number
y=lesser number
the greater of 2 numbers is 7 more than the lesser
x=y+7
Three times the greater number is 5 more than 4 times the lesser number
3x=5+4y
We will begin by substituting x=y+7 in the second equation;
3(y+7)=5+4y
3y+21=5+4y
3y-4y=5-21
-y=-16
y=16
Now we have what y =, so we plug it into the equation to find x,
x=y+7
x=16+7
x=23
We are done, we have both y and x;
x=23
y=16
Don't forget to check your answer!
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The sun of two numbers is 64. Twice the lesser number is five more that the greater number. Find the numbers.
let x = the lesser number
let y = greater number
So our equations would be;
x+y=64
2x=y+5
Now first we will solve x;
x+y=64
y=64-x
Now substitute this answer for y into one of the equations;
2x=(64-x)+5
2x=69-x
2x+x=69
3x=69
x=23
So now we have our x, so we can plug it into an equation to get y;
2(23)=y+5
46=y+5
46-5=y
41=y
So now we have;
x=23
y=41
Don't forget to check your answer!
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We will solve this one using elimination so we can find what one variable =;
We begin by adding the two equations toogether;
5x+5y=40
-5x+4y=-4
----------
9y=36
Divide both sides by 9

y=4
Now we have what y=, so now we can solve for x;
5x+5(4)=40
5x+20=40
5x=40-20
5x=20
x=4
So now we have;
x=4
y=4
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4(5n-7)=10n+2
First distribute the 4(5n-7);
20n-28=10n+2
Now subtract both sides by 10n and add 28 to both sides;
20n-10n=2+28
10n=30
n=3
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eqn.1 x+6y=2
eqn.2 5x+4y=36
We will begin this by eliminating one variable so we can solve the other.
Lets eliminate the x, to do that we need to multiply -5 to eqn.1
(-5)x+6y=2
-5x-30y=-10;
Now we will add eqn.1 and eqn.2 together;
-5x-30y=-10
5x+4y=36
-----------
-26y=26
y=-1
Now we have what y =, so we can plug that into either equation and find x;
x+6(-1)=2
x-6=2
x=8
Now we have our answer;
x=8, y=-1
Don't forget to check;
x+6y=2
8+6(-1)=2
8-6=2
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"Batman is 20 years older then robin. In 4 years, Batman will be twice Robin age. How old are they now?"
Robin=x
Batman=20+x(Batman older by 20 years )
Very good, you have this correct;
But you do not have the next eqution correct;
Batman will be twice Robin age;
In your equation you have Batmans age;
Batman=2(20+x)
It should be;
2x(Robins age)
Batman is 20 years older then robin,In 4 years,
20+x+4=
Batman will be twice Robin age.
2x
So our equation would be;
20+x+4=2x
x+24=2x
24=2x-x
24=x
So Robins age is 24;
Batmans age;
(24)+20=44
Now check;
20+(24)+4=2(24)
48=48
Hope you see where you went wrong, you were doing a good job though;
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Like terms are any term that is EXACTLY ALIKE.
such as;
x+x=; you can add them together because they are exactly alike;
x+x=2x
But if you had terms such as;
; you could not add them together because they are not exactly alike.
the first x is to the power of one, the second x is to the power of 2;
So in your equations;
8s - 3s + 4k =
You can subtract 8s-3s, because they are like terms;
8s-3s+4k=11s+4k; you can not add these together because they are not like terms, they have different variables.
10x + 6y -5x =;
You can subtract 10x-5x, because they are like terms,
10x-5x=5x+6y; you can not add together because they are not like terms.
12 + 6p + 3q - 5p + 7q =
You can subtract 6p-5p=p;
3q+7q=10q;
So you have;
12+p+10q
You can not add the 12 because it is not like any other term.
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Find two consecutive even integers such that five times the first equals ten more than three times the second.
Our 2 integers will be;
x, x+2
Now 5 times the first;
5x=
10 more than 3 times the second;
3(x+2)+10
So we have;
5x=3(x+2)+10
5x=3x+6+10
5x-3x=16
2x=16
x=8
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{2w+5y=-24
{3w-5y=14
Add both equations together to eliminate one variable;

2w+5y=-24
3w-5y=14
----------
5w=-10
Divide both sides by 5;
w=-2
Now that you know what w = we can plug that in the equation and find y;
2(-2)+5y=-24
-4+5y=-24
5y=-24+4
5y=-20
y=-4
w=-2
y=-4
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19-(2x+3)=2(x+3)+x take everthing out of bracket
19-2x+3=2x+6+x without Bracket
+2x+22=2x+6+x Added 19+3
+22=-2x+2x+x move variable to one side
+22=x -2x+2x cancel each other out
First when you distribute the -1 to (2x+3), they both change to -;
19-2x-3=2(x+3)+x
Now distribute the 2(x+3);
which you did correctly;
so you have:
19-2x-3=2x+6+x
Now move variable to one side and add like terms;
16-6=2x+x+2x
10=5x
Divide by 5;
=
2=x
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22x + 2(3x+5)=66
You want to start with distributing the 2;
2*3x+2*5=6x+10;
Now you have ;
22x+6x+10=66
Add like terms;
28x+10=66
Subtract 10 from both sides;
28x+10-10=66-10
28x=56
Divide both sides by 28;
=
x=2
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Multiplying and dividing fractions are much easier than adding and subtracting.
6 divided by 2/3?
With your first problem, when it comes to dividing fractions, you need to multiply the inverseinvert the divisor:
Which is 2/3 and it becomes 3/2
Now we multiply the fractions;
6/1*3/2=18/2=9
2/5 x 1/2?
You multiply the numerator times the numerator and denominator times the denominator.
2/5*1/2=2*1, 5*2
2/10=1/5
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find 3 consecutive integers that are equal to 99
Let x = the first integer;
So, x+1=second integer
x+2=third integer
So we have;
x+(x+1)+(x+2)=99
3x+3=99
3x=96
x=32
So our first integer is 32, can you figure out what the next two are?
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-7n-10=4
Add 10 to both sides;
-7n-10+10=4+10
-7n=14
Divide both sides by -7;
=
n=-2
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e-3=-2
Add 3 to both sides;
e-3+3=-2+3
e=1
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r + 23 = 56 You subtract 23 from both sides;
r+23-23=56-23
When you do that it cancels out the 23 on the left side and leaves the variable by itself;
r=33
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Why does the equation n + (n+1) + (n+2) = 84
Since you do not know what the integers are you will make the first integer =n;
Now since they are consecutive, it means the next integer right after n, which would be n+1,
ex.
lets say 3 is our first integer, what is the next integer after 3? 4
What do you add to 3 to get 4? 3+1
The third integer would be? 3+2=5
So since you do not know the integers, you use a variable such as n.
n = first integer
n+1=second integer
n+2= third integer
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5/24=X/600
24x=5(600)
24x=3000
x=
x=125
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3/4 (24 - 8b) = 2 (5b + 1)
First of all distribute on left side;
b=b, simplify
18-6b
Now the right side distribute:
2*5b+2*1=10b+2
But the equation together;
18-6b=10b+2
Subtract 18 from both sides, and subtract 10b from both sides;
18-6b-18-10b=10b+2-18-10b
-16b=-16
Divide each side by -16
b=1
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I'm not sure what you mean by "work out percentages"
Do you mean change to decimal form, or fractions?Could you send an example of a problem?
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3M x 4N=12MN
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BRAVO!!
YOU ARE RIGHT!
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The answer would be;
16+4y
You can not add these toogether because they are not like terms.
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y-intercept