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Recent problems solved by 'edjones'
edjones answered: 7568 problems
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president of the United States. The pollster will select 10 of these questions. How many
different arrangements are there for the order of the 10 selected questions?
1 solutions
Answer 328503 by edjones(7569) on 2011-08-08 20:19:48 (Show Source):
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Probability-and-statistics/479410: The Pizza Shop wanted to determine what proportion of its customers ordered only cheese pizza. Out of 80 customers surveyed, 15 ordered cheese pizza. What is the 99% confidence interval of the true proportion of customers who order only cheese pizza? 1 solutions
Answer 328502 by edjones(7569) on 2011-08-08 20:15:03 (Show Source):
You can put this solution on YOUR website!p=15/80=.1875, q=.8125,

(a,b)=.1875 +-(2.576*.0436) [2.576 is the area under the normal curve for the 99% confidence level.]
=.1875 +-.1123
=(.2998, .0752) the 99% confidence interval of the true proportion of customers who order only cheese pizza.
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test/479362: 1.If 3x-11/2=5x^0,what is the value of x?
2.If 2x^-1=5/3,what is the value of x?
3.If k/x-1x^2=k,what is the value of x when k=4?
Please help and thank you so much.I really appreciate for giving your time to help solve these problems.Thanks again. 1 solutions
Answer 328471 by edjones(7569) on 2011-08-08 18:20:38 (Show Source):
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Average/479364: On a school test, The average score for the girls in the class is 91, and the average score for the boys in the class is 85. If the average score for the class is 89, what fraction of the class are boys?
I should resolve it by a system...
91x + 85y= 89 (x+y)
But then??
Thanks in advance. 1 solutions
Answer 328465 by edjones(7569) on 2011-08-08 18:14:45 (Show Source):
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Probability-and-statistics/475616: You have measured the percentage of days your company met production targets across two sites. At one site, you measure 80 days and found that the site missed the production goals 11 times. At site two, you measured 92 days and found that the site missed the production goals 10 times. At the 90% confidence level, can you say that site two missed the production goal fewer times than site one? State your hypothesis:
1 solutions
Answer 326161 by edjones(7569) on 2011-07-28 22:22:26 (Show Source):
You can put this solution on YOUR website!H[o]: site two missed the production goal fewer times than site one.
Site #1: p=11/80=.1375, q=1-.1375=.8625, n=80
Site #2: p=10/92=.1087, q=1-.1087=.8913, n=92
 =.0385+.0325=.071
z=(.1375-.1087)/.071=.4056
Using a single tailed test z=.4056 has an area of .3245 under the normal curve and the null hypothesis is not confirmed.
.
Ed
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Probability-and-statistics/474194: A slot machine is configured so that there is a 1/2000 probability of winning the jackpot on any individual trial. Suppose a guest claims that she played the slot machine 5 times and hit the jackpot twice. Find the probability of exactly 2 jackpots in 5 trials. find the probability of at least 2 jackpots in 5 trials. does the guest's claim of hitting 2 jackpots in 5 trials seem valid? 1 solutions
Answer 325241 by edjones(7569) on 2011-07-25 16:31:03 (Show Source):
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Probability-and-statistics/474198: Which of the following statistics are unbiased estimators of population parameters?
a. sample mean used to estimate a population mean
b. sample median used to estimate a population median
c. sample range used to estimate a population range 1 solutions
Answer 325236 by edjones(7569) on 2011-07-25 16:15:36 (Show Source):
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Probability-and-statistics/474201: Mars Inc, claims 24% of M&M plain candies are blue. Suppose that a sample of 100 M&Ms are randomly selected and 27 are found to be blue. Assuming the claimed blue M&Ms rate of 24% is correct, find the probility of randomly selecting 100 M&Ms and getting 27 or more that are blue. Based on your result, is 27 an unusually high number of blue M&Ms when 100 are randomly selected? 1 solutions
Answer 325226 by edjones(7569) on 2011-07-25 16:02:15 (Show Source):
You can put this solution on YOUR website!p=24, q=.76, n=100

z=(27.5-24)/4.48=3.5/4.48=.781
area under normal curve above z=.781 is .217 the probility of randomly selecting 100 M&Ms and getting 27 or more that are blue. It is not an unusually high result.
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Ed
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