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edjones answered: 7568 problems
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Coordinate-system/241791: please help me in graphing parabolas y=x^2 - 2 1 solutions
Answer 177082 by edjones(7569) on 2009-11-22 18:53:13 (Show Source):
You can put this solution on YOUR website!To graph it you don't have to figure out the problem.
Create a table with x and y at the top.
put in a value for x and calculate the value for y.
put a dot on graph paper for those values. Use small whole numbers for x values and don't forget negative values for x and x=zero.
pretty soon you'll have a parabola.
.
Ed
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Linear-equations/241534: can someone please tell me the method to solving this linear equation?
3n-1/5 + n/2 = 2
/ means over as in 5 over 10 (5 divided by 10) 1 solutions
Answer 176925 by edjones(7569) on 2009-11-22 08:41:13 (Show Source):
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Quadratic_Equations/241543: Here's my question.
Graph each parabola. Identify the vertex, intercepts, and the maximum or minimum y-value.
f(x) = 16 – x^2
Once I figure out the problem then I should be able to graph it I hope. Thanks. 1 solutions
Answer 176922 by edjones(7569) on 2009-11-22 08:36:10 (Show Source):
You can put this solution on YOUR website!To graph it you don't have to figure out the problem.
Replace f(x) with y.
Create a table with x and y at the top.
put in a value for x and calculate the value for y.
put a dot on graph paper for those values. Use small whole numbers for x values and don't forget negative values for x and x=zero.
pretty soon you'll have a parabola.
.
Ed
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logarithm/241397: how to solve: 4^(3x-1)=3^(x-1)
i can't rember how to solve for x.
i am lost. 1 solutions
Answer 176789 by edjones(7569) on 2009-11-21 15:42:56 (Show Source):
You can put this solution on YOUR website!4^(3x-1)=3^(x-1)
log[4](4^3x-1)=log[3](3^(x-1))/log[3](4) Change of base formula from 3 to 4 on the right side.
3x-1=(x-1)/1.2619
3.7856x-1.2619=x-1
2.7856x=.2619
x=.094...
.
Ed
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Probability-and-statistics/241382: Suppose that the probability that a new medication will cause a bad side effect is 0.03. If this medication is given to 150 people, what is the probability that more than three of them will experience a bad side effect? Round answer to 4 decimal places.
I think I know how to compute for "exactly three students," but I cannot figure out how to do "more than three students"
Here's how I approached "exactly three":
p = 0.03, q = 1 - p = 0.97, n = 150
P(r, n) = nCr (p)^r * (q)^(n - r)
P(3, 150) = 150C3 * 0.03^3 * 0.97^147 = 0.1691
Since I am trying to figure out how to do these types of problems on my own, please include the steps.
Thank you!
1 solutions
Answer 176783 by edjones(7569) on 2009-11-21 15:00:49 (Show Source):
You can put this solution on YOUR website!You are correct so far as you have gone.
Now do the same procedure for exactly 2, 1 and 0 students.
Find the sum of the 4 probabilities and subtract it from 1 and you have your answer.
.
Ed
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Linear-equations/241386: x + y =5
2x - y =4
-2x +-2y = -10 2x-y =4
2x - y = 4 2x -2 =4
3y -6
__ ___
3 = 3
y = -2 __
then lost - is this right so far and can you show me how to do problem? 1 solutions
Answer 176781 by edjones(7569) on 2009-11-21 14:39:28 (Show Source):
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Mixture_Word_Problems/241234: Could someone please help me with this mixture problem? I have been pouring over it for two days (total of over 4 hours), and have tried various methods none of them yielding the correct answer.
A mechanic has 363 gallons of gasoline and 17 gallons of oil to make gas/oil mixtures. He wants one mixture to be 6% oil and the other mixture to be 2.5% oil. If he wants to use all of the gas and oil, how many gallons of gas and oil are in each of the resulting mixtures? 1 solutions
Answer 176699 by edjones(7569) on 2009-11-21 00:36:58 (Show Source):
You can put this solution on YOUR website!Let x=gals of gas required to make a .025 mixture.
Let y=gals of oil required to make a .025 mixture.
.
A) y/(x+y)=.025
B) (17-y)/(363-x+17-y)=.06
.
A)
y=.025x+.025y
.975y=.025x
y=.0256x
.
B)
(17-.0256x)/(380-x-.0256x)=.06
17-.0256x=22.8-.0615x
.0359x=5.8
x=161.56 gal
.
A)
y/(161.56+y)=.025
y=4.039+.025y
.975y=4.039
y=4.142 gal
It wont be exact because of rounding errors.
.
Ed
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Quadratic_Equations/240936: How do you solve the following quadratic equations:
-6(u+5)^2=120
3s^2-1=7s^2 1 solutions
Answer 176489 by edjones(7569) on 2009-11-19 19:34:21 (Show Source):
You can put this solution on YOUR website!-6(u+5)^2=120
(u+5)^2=-20
u^2+10u+25=-20
u^2+10u+45=0
u^2+10u =-45
u^2+10u+25=-45+25 Completing the square
(u+5)^2=-20
u+5=+-sqrt(-20) Take sqrt of each side.
u=-5+-2sqrt(-5)
u=-5+2sqrt(5)i, u=-5-2sqrt(5)i
.
Ed
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Linear-systems/240926: i need help on solving for elmination, i get confused.
Problem: 2x+6y=17
2x-10y=9
break it down for me step by step, if you can..thank you! :) 1 solutions
Answer 176474 by edjones(7569) on 2009-11-19 19:13:53 (Show Source):
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