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edjones answered: 7568 problems
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logarithm/370280: solve for x log(x+9)-logx=2
1 solutions

Answer 263907 by edjones(7569) About Me  on 2010-11-12 21:43:45 (Show Source):
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log(x+9)-logx=2
10^(log(x+9))/10^log(x)=10^2
(x+9)/x=100
x+9=100x
99x=9
x=1/11
.
Ed


Inequalities/370278: is each number a solution of x>-1
yes or no
1 solutions

Answer 263906 by edjones(7569) About Me  on 2010-11-12 21:39:22 (Show Source):
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There is only one number, -1.
x is a variable.
You are solving for x,to find out what x is greater than.
The solution is "x>-1".
.
Ed


Square-cubic-other-roots/370276: Can a cubic equation have only two roots?

1 solutions

Answer 263904 by edjones(7569) About Me  on 2010-11-12 21:32:03 (Show Source):
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It can have three roots, two of which are identical.


Complex_Numbers/370274: Hello. Can you please help me? I'd greatly appreciate it.
I need to simplify the following:
4i(-6i)^2
Thank you!
1 solutions

Answer 263903 by edjones(7569) About Me  on 2010-11-12 21:28:23 (Show Source):
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4i(-6i)^2
=4i*-36
=-144i
.
Ed


Probability-and-statistics/370273: In a casino game, a player is given three numbers from 1 to 3. That is, he is given 1, 2, or 3, then again 1, 2, or 3, and then a third time 1, 2, or 3. Write out the sample space. What is the probability that the player will receive three different numbers?
1 solutions

Answer 263902 by edjones(7569) About Me  on 2010-11-12 21:25:02 (Show Source):
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(111) (112) (113)
(121) (122) (123)
(131) (132) (133)
I did all the permutations of the set of numbers beginning with one in the sample space to give you the idea of what the sample space should look like.
There are 3^3=27 groups of 3 numbers in all. You can do the other 18.
As you can see 2/9 is the probability that the player will receive three different numbers.
.
Ed


Permutations/370261: what are all of the possible combinations that can be made of 4 digits using numbers 0-9?
1 solutions

Answer 263900 by edjones(7569) About Me  on 2010-11-12 21:05:50 (Show Source):
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nCr=combination of n things taken r at a time= n!/((n-r)!r!)
Arrangement is not important.
=10!/(6!*4!)
=210
.
Ed


Probability-and-statistics/370256: According to the bureau of the census, the following statistics describe the number (in thousand) of young adults living at homr or in a dormitory in the year 2004.
ages 18-24 ages 25-34
--------------------------
male 7922 2543
female 5779 995
choose one student at random. Find the probability that the student is
a. a female student aged 25-34
b. Male or aged 18-24
c. Under 25 years if age and not male
1 solutions

Answer 263898 by edjones(7569) About Me  on 2010-11-12 20:39:50 (Show Source):
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17,239 total students.
a) 995/17239=.0577
.
b)
Male: 10465
female 18-24: 5779
(10465+5779)/17239
=.9423
.
c)
5779/17239
=.3352
.
Ed


Probability-and-statistics/370132: In a string of length 9 with elements being a, b or c. How many strings will contain at least 6 b’s?
1 solutions

Answer 263896 by edjones(7569) About Me  on 2010-11-12 20:19:30 (Show Source):
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expand(b+a+c)^9
1 b^9
2*9 b^8...
2*36+72 b^7...
2*84+252*2 b^6...
-------add
835 strings will contain at least 9 b's.
.
Ed


Probability-and-statistics/370130: There are ten lottery tickets, two of which are winners. Find the probability that in a sample of 6 tickets there will be no more than one winning ticket.


1 solutions

Answer 263885 by edjones(7569) About Me  on 2010-11-12 19:51:24 (Show Source):
You can put this solution on YOUR website!
nCr=combinayion of n things taken r at a time.
((8C5 * 2C1)+(8C6))/10C6
=((56*2)+28)/210
=2/3 the probability that in a sample of 6 tickets there will be no more than one winning ticket.
.
Ed


Probability-and-statistics/370140: There are ten lottery tickets, two of which are winners. Find the probability that in a sample of 6 tickets there will be no more than one winning ticket.
1 solutions

Answer 263884 by edjones(7569) About Me  on 2010-11-12 19:43:58 (Show Source):
You can put this solution on YOUR website!
nCr=combinayion of n things taken r at a time.
((8C5 * 2C1)+(8C6))/10C6
=((56*2)+28)/210
=2/3 the probability that in a sample of 6 tickets there will be no more than one winning ticket.
.
Ed


Probability-and-statistics/370180: If Minh picks a letter of the alphabet at random, what is the probability it occurs in the name "Hattiesburg, Mississippi"? Express your answer as a common fraction
1 solutions

Answer 263873 by edjones(7569) About Me  on 2010-11-12 19:09:57 (Show Source):


Probability-and-statistics/370227: What are the next seven terms of the lexicographic ordering of the n-tuple 34276 where each digit belongs to {2,3,4,6,7} set
1 solutions

Answer 263871 by edjones(7569) About Me  on 2010-11-12 19:00:36 (Show Source):
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34627
34672
34726
34762
36247
36274
.
Ed


Probability-and-statistics/369968: From a group of eight women and seven men, a committee of six is chosen randomly. Find the probability that three women and three men will be chosen.
Thank you!!!
1 solutions

Answer 263606 by edjones(7569) About Me  on 2010-11-11 22:23:20 (Show Source):
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(8C3 * 7C3)/15C6
=(56*35)/5005
=1960/5005
=.3916
.
Ed


Probability-and-statistics/369923: A computer prints out three digits chosen at random from 0 to 9, inclusive. Find the probability that:
a) All three digits are different.
b) The third digit differs from the first two digits.
Thank yoy very much for your answer!
1 solutions

Answer 263604 by edjones(7569) About Me  on 2010-11-11 22:15:39 (Show Source):
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a) 10/10 * 9/10 * 8/10 = 720/1000 = 18/25
.
b)
((8/10 * 9) + 9/10)/10 Because of a 1/10 chance both of the first 2 digits are the same.
= (72/10 + 9/10)/10
= 81/100
.
Ed


Permutations/369747: Aunt Rose has a children's table for Thanksgiving dinner. There are 4 children. For chairs she has a small bean bag, a small rocking chair, a stool, and a little desk chair. How many different ways could she seat those 4 children at the table?
1 solutions

Answer 263503 by edjones(7569) About Me  on 2010-11-11 18:08:24 (Show Source):


Probability-and-statistics/369692: In a survey of 150 seniors executives, 47% said that most common job interview mistake is to have little or no knowledge of the company. I need help with part B

a) If 6 of those surveyed executives are randomly selected without replacement for a follow-up survey, find the probability ... b) If part (a) is changed so that 9 of the surveyed executives are to be randomly selected without replacement, explain why the binomial probability formula cannot be used.
1 solutions

Answer 263446 by edjones(7569) About Me  on 2010-11-11 15:58:51 (Show Source):
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Because binomial probability is used WITH replacement.


Linear-systems/369660: Can you help me with this problem please? 2u+v=9
u/2 -1/2=-v
I have to solve it using elimination but every time I try to check my solution it comes out incorrect. Can you help me please? I would really appreciate it! Thank you!
1 solutions

Answer 263421 by edjones(7569) About Me  on 2010-11-11 15:25:58 (Show Source):
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2u+v=9
.
u/2 -1/2=-v
u-1=-2v multiply each side by 2.
u+2v=1
-2u-4v=-2 multiply each side by -2.
.
2u+v=9
-2u-4v=-2
-----------add
-3v=7
.
v=-7/3
u=17/3
.
Ed


test/369666: Erin, Molly, Jillian and Brendan go to the carnival
They have pink, blue, green and red cotton candy. How many different combinations can there be?
1 solutions

Answer 263419 by edjones(7569) About Me  on 2010-11-11 15:07:56 (Show Source):


logarithm/369662: Solve the following to the nearest hundredth.
+6%5E%28x-3%29+=+11+
I am only able to get this problem so far, then I get stuck. This is what I have done so far:
+log6%5E%28x-3%29+=+log11+
+%28x-3%29log6+=+log11+
+xlog6+-+3log6+=+log11+
+xlog6+=+log11+%2B+3log6+
I am not sure as to what the next step in solving this problem is, the three at the beginning of the 3log6 is my issue with solving this equation
1 solutions

Answer 263418 by edjones(7569) About Me  on 2010-11-11 15:01:09 (Show Source):
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6^(x-3) = 11
log[6](6^(x-3)) = log[6](11)
x-3=1.34
x=3+1.34
x=4.34
.
Ed


Probability-and-statistics/369654: Enrollment statistics at a certain college show that 55% of all students are men, 18% of the student body consists of women majoring in business, and 40% of all students major in business. A student is selected at random.
Find the conditional probability that the person majors in business if we are certain the person is a woman.
I've got P(men) = 55 and P(women majoring in business) = 18, but the 40% I do not know what to do. I tried Venn diagram and:
P(M U W) = P(M) + P(W) - P(M n W) I still cannot get answer..




1 solutions

Answer 263416 by edjones(7569) About Me  on 2010-11-11 14:56:07 (Show Source):
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Make a Venn diagram of Women and Bussiness majors.
P=P(WnB)|P(W)(.18/.45=.40 the conditional probability that the person majors in business if we are certain the person is a woman.
.
Ed


Average/369651: Hi. I hope you can help me. This is for 10th grade regents math homework. Here is the quesion. "Through a given point P, on a plane, how many planes can be drawn that are perpendicular to that plane?"
A) 1
B) 2
C) infinitely many
D) none
Please email the answer to me and if you can explain how you got it. Thanks :)
1 solutions

Answer 263411 by edjones(7569) About Me  on 2010-11-11 14:45:35 (Show Source):
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D) none
The plane is the paper the dot is on. Since all line draw must be in the plane of the paper, none can be perpendicular to it.
.
Ed


Equations/369646: Im really stumped on how to find the answer to these two equations:
2x=x/5+28

2(x+8)=3-(4x-7)
Can you please help me solve these! Thank you!!
1 solutions

Answer 263406 by edjones(7569) About Me  on 2010-11-11 14:40:45 (Show Source):
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2x=x/5+28
10x=x+140 multiply each side by 5.
9x=140
x=140/9
.
Ed


Human-and-algebraic-language/369576: A group of stockholders are to elect a president, vice-president, secretary, and a treasurer from 6 board members who qualify. How many different ways can the officers be elected?
1 solutions

Answer 263405 by edjones(7569) About Me  on 2010-11-11 14:35:32 (Show Source):
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nPr=n!/(n-r)!=permutation of n thing taken r at a time. Arrangement is important.
6P4=(6*5*4*3*2!)/2!
=360 ways
.
Ed


Permutations/368468: A committee of 5 people is selected from a group of 8 men and 9 women. In how many ways can the committee be selected so it contains at least one woman?
1 solutions

Answer 263403 by edjones(7569) About Me  on 2010-11-11 14:18:23 (Show Source):
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17C5=6188 every possible combination.
8C5=56 all men
6188-56=6132 contains at least one woman.
.
Ed


Permutations/369622: A test consists of 10 true-or-false questions. If a student randomly chooses answers for each question, find the probability that the student:
Answers at least 1 question correctly. (3 decimals)
I got 2^10 = 1,024
I did this way, but does not work, very close...
C(10,1)/1024 =
10/1024 = .00976
The answer is 0.999 but how?


1 solutions

Answer 263399 by edjones(7569) About Me  on 2010-11-11 14:09:41 (Show Source):
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Let x=.5 probability of getting a problem wrong.
1- probability that he gets them all wrong = the probability that the student answers at least 1 question correctly.
1-.5^10=.9990
.
Ed


Triangles/368864: Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
6-inch apothem
A = sq. in
1 solutions

Answer 262837 by edjones(7569) About Me  on 2010-11-10 00:09:03 (Show Source):
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There are now two 30-60-90 triangles with side ratios of 1:sqrt(3):2
Let b=base
b/1=6/sqrt(3) Proportion
A=0.5*6*(6/sqrt(3))
=18/sqrt(3)
=18/sqrt(3) * sqrt(3)/sqrt(3) Rationalize the denominator.
=18sqrt(3)/3
=6sqrt(3)
.
Ed


Triangles/368752: how do i identify congruent angles?
1 solutions

Answer 262831 by edjones(7569) About Me  on 2010-11-09 23:44:23 (Show Source):
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They are equal.


Probability-and-statistics/368773: Which of the following statements are correct?
a. A normal distribution is any distribution that is not unusual.
b. The graph of a normal distribution is bell-shaped.
c. If a population has a normal distribution, the mean and the median are not equal.
d. The graph of a normal distribution is symmetric.

1 solutions

Answer 262828 by edjones(7569) About Me  on 2010-11-09 23:42:27 (Show Source):


Probability-and-statistics/368065: Three cards are drawn from an ordinary deck of 52 cards without replacement. What is the probability that the second and third cards are spades if the first card was not a spade?

1 solutions

Answer 262324 by edjones(7569) About Me  on 2010-11-08 19:46:37 (Show Source):
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13/51 * 12/50 = .0612
.
Ed


Equations/368009: 36/54=2x/6
1 solutions

Answer 262286 by edjones(7569) About Me  on 2010-11-08 18:38:16 (Show Source):
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36/54=2x/6
2/3=x/3
x=2 multiply each side by 3.
.
Ed


Equations/368011: -x^2+x+20=0
1 solutions

Answer 262284 by edjones(7569) About Me  on 2010-11-08 18:34:49 (Show Source):
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-x^2+x+20=0
x^2-x-20=0 multiply each side by -1
(x-5)(x+4)=0
x=5, x=-4
.
Ed