New!
Get regular updates about newly solved problems
via algebra.com's RSS system.
Recent problems solved by 'edjones'
edjones answered: 7568 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589, >>NextPolynomials-and-rational-expressions/456556: We are working on rational expression and equations this week and I am completely lost with the following problem.
1. Divide and simplify
b+3/b-9 / 9b+27/b-4
2. Solve the equation and check your answer.
q+6/7 + q-2/2=8/7
3. Add. 6/z+3 + 9/7z
4. Subtract. Simplify, if possible.
g/s+g - g/s-g
These are the last ones I need help with, thank you very much for the help. 1 solutions
Answer 313335 by edjones(7569) on 2011-06-02 01:06:10 (Show Source):
|
Permutations/456585: There are 15 teams in the Eastern Conference of the National Hockey League for 2006-2007 season, divided into 3 divisions of 5 teams each. Eight of these teams will participate in the playoff. The division winner from each division goes to the playoff; in addition the next 5 ranked teams in the conference, based on regular season records will participate in the playoffs. How many different collections of eight teams from the Eastern Conference could go to the playoffs? 1 solutions
Answer 313328 by edjones(7569) on 2011-06-02 00:45:22 (Show Source):
You can put this solution on YOUR website!5^3=125 possible combinations of division winners.
12C5=792 Next 5 ranked teams in the conference.
.
792+125=917 possible combinations (with the Boston Bruins winning it all this year)
.
Ed
|
Permutations/456579: An advertising firm based in Boston has 12 advertising agents. Next week, agents must meet with 3 prospective clients in Orlando, Chicago, and Seattle. The firm will send 3 agents to Orlando, 4 to Chicago, and 3 to Seattle. Assuming no agent will travel to more than one destination, how many different arrangements of agents are possible to meet with 3 prospective clients? 1 solutions
Answer 313318 by edjones(7569) on 2011-06-01 23:57:35 (Show Source):
|
Quadratic_Equations/456575: I have been working on a problem and I cannot figure out how to get an approximated answer to three decimals. Can you show me how to get this.
This is what I have so far.
In the right trianle, find the length of the side not given. Give an exact answer and an approximation to 3 decimal places.
a = 13 b = 13 a+b=c 13^2+13^2=c^2 169+169=c^2
169+169=338 338=c^2
This is what I have so far. Take the square root of both sides c=338. The exact value of c is the sqrt of 338. The value approximated to three decimals is ?
Am I doing this problem correctly? If I am I do not know how to get the value appoximated to three decimals. Can you help me please? 1 solutions
Answer 313315 by edjones(7569) on 2011-06-01 23:42:37 (Show Source):
|
Number-Line/456450: 1. What integer is one-third of the distance from 4 to 2 on the number line?
2. What integer is three-fourths of the distance from 5 to 19 on the number line? 1 solutions
Answer 313253 by edjones(7569) on 2011-06-01 18:49:34 (Show Source):
|
Probability-and-statistics/456318: QUESTIONS 1-5 ARE BASED ON THE FOLLOWING INFORMATION
The fill in bottles of a wine is normally distributed with mean μ = 750 milliliters (ml) and standard deviation of σ = 9 ml.
1 For samples of size n = 64 bottles selected from this population, the mean of the sampling distribution of x̄ is _____ and the standard error of x̄ ______.
a E(x̄) = 93.75 se(x̄) = 9
b E(x̄) = 750 se(x̄) = 9
c E(x̄) = 750 se(x̄) = 0.141
d E(x̄) = 750 se(x̄) = 1.125
2 "The probability that the mean of a sample of n = 64 bottles falls between 748 and 752 ml is,
P(748 < x̄ < 752) = _____."
a 0.9500
b 0.9250
c 0.8165
d 0.7154
3 The proportion of the means obtained from samples of size n = 64 bottles that fall within ±1 ml from the mean of the population of bottles is _____.
a 0.6827
b 0.6266
c 0.5223
d 0.4039
4 The margin of error for the interval which contains 80% of all sample means is: MOE = _______.
a 2.21 ml.
b 1.85 ml.
c 1.44 ml.
d 1.29 ml.
5 To obtain a margin of error MOE = ± 1 ml for an interval that contains 95% of all sample means, the sample size is n = _____.
a 312
b 217
c 159
d 122
1 solutions
Answer 313234 by edjones(7569) on 2011-06-01 18:26:49 (Show Source):
You can put this solution on YOUR website!1)s=9/sqrt(64)=9/8=1.125
m=750
.
2)
z=2/1.125=1.78
area under curve for +-1.78=.9250
.
3)
1/1.125 = .89
area under curve for +-0.89=0.6266
.
4)
For the area under the curve of 0.8 the z=+-1.28
1.28 * 9/8 = 1.44 ml
.
5)
For the area under the curve of 0.95 the z=+-1.96
1.96 * 9/sqrt(x)=1 ml
sqrt(x)=1.96*9=17.64
x=311.17=312 always round up.
.
Ed
|
Triangles/456343: the ratio of the measures of the sides of a triangle is 2:5:6. If the length of the longest side is 48 inches, find the perimeter
1 solutions
Answer 313213 by edjones(7569) on 2011-06-01 17:00:09 (Show Source):
|
Probability-and-statistics/456360: At a picnic a cooler filled with ice there are 100 cans of soda. With a mixture of sodas. 30 cans of cola, 40 cans of orange, 20 cans of root beer and 10 cans of cream soda. What are the odds of, if you reach in and you select just ONE can, and that can is either a cola or a orange soda?
This is what I have done so far.
N= 100, r= 30
= 30/100 = 3/10 =0.3
n=100, r=40
= 40/100= 4/10 = 0.4
= 0.3 + 0.4 = 0.7 times chance of getting either a cola or a can of orange soda.
-------------------------------------------------------------------------------
Please help me! 1 solutions
Answer 313200 by edjones(7569) on 2011-06-01 16:10:25 (Show Source):
You can put this solution on YOUR website!P=70/100=7/10 probability of success.
3/10 probability of failure.
Odds in favor of success are 7/10 to 3/10 or simply 7 to 3.
.
Ed
|
Human-and-algebraic-language/456075: A bag contains 2 red marbles,4 green marbles, and 4 blue marbles. You choose one marble at random, put the marble back into the bag, then choose a second marble at random. what is the probability that you choose 2 red marbles? 1 solutions
Answer 313086 by edjones(7569) on 2011-05-31 22:42:51 (Show Source):
|
|