See tutors' answers!

Algebra ->  Tutoring on algebra.com -> See tutors' answers!      Log On


   
By Tutor
 | By Problem Number | 

Tutor:
New! Get regular updates about newly solved problems via algebra.com's RSS system.

Recent problems solved by 'checkley77'

checkley77 answered: 12560 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569, >>Next

Linear_Algebra/162932: what is the solution set for
3(x+3) less than or equal to 5x-5
1 solutions

Answer 120103 by checkley77(12569) About Me  on 2008-10-19 17:57:47 (Show Source):
You can put this solution on YOUR website!
3(x+3)<=5x-5
3x+9<=5x-5
3x-5x<=-5-9
-2x<=-14
x>-14/-2 when dividing by a negative number the < sign changes to a > sign.
x>=7 Answer.
Proof:
Let x=8
3(8+3)<=5*8-5
3*11<=40-5
33<=35


Problems-with-consecutive-odd-even-integers/162936: Five times the first of two consecutive odd integers is three times the second. Find the integers?
1 solutions

Answer 120100 by checkley77(12569) About Me  on 2008-10-19 17:54:11 (Show Source):
You can put this solution on YOUR website!
5x=3(x+2)
5x=3x+6
5x-3x=6
2x=6
x=6/2
x=3 Answer.
Proof:
5*3=3(3+2)
15=3*5
15=15


Problems-with-consecutive-odd-even-integers/162940: This question is from textbook
the sum of two consecutive even integers is -298. what are the integers?
1 solutions

Answer 120099 by checkley77(12569) About Me  on 2008-10-19 17:50:59 (Show Source):
You can put this solution on YOUR website!
let x & x+2 be the two integers.
x+x+2=-298
2x=-298+2
2x=-300
x=-300/2
x=-150 for the first even integer.
-150+2=-148 for the second integer.
Proof:
-150+(-148)=-298
-298=-298


Graphs/162942: How do you graph y=1/4x? I really appreciate this. Thanks Mary
1 solutions

Answer 120097 by checkley77(12569) About Me  on 2008-10-19 17:47:20 (Show Source):
You can put this solution on YOUR website!
y=1/4x
y=x/4
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=+x%2F4%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = x/4).
Two points are: (0,0) & (4,1)


test/162946: This question is from textbook 445234
4n-2n=18
1 solutions

Answer 120096 by checkley77(12569) About Me  on 2008-10-19 17:44:28 (Show Source):
You can put this solution on YOUR website!
4n-2n=18
2n=18
n=18/2
n=9 Answer.
Proof:
4*9-2*9=18
36-18=18
18=18


Linear_Equations_And_Systems_Word_Problems/162969: A garden table and a bench cost $450 combined. The price of the garden table is two times the price of the bench. What is the cost of the bench?
1 solutions

Answer 120095 by checkley77(12569) About Me  on 2008-10-19 17:41:47 (Show Source):
You can put this solution on YOUR website!
2x=x=450
3x=450
x=450/3
x=150 for the bench.
2*150=300 for the table.
Proof:
150+300=450
450=450


expressions/162973: I need help solving -(5a+31)+ a =5
1 solutions

Answer 120094 by checkley77(12569) About Me  on 2008-10-19 17:39:29 (Show Source):
You can put this solution on YOUR website!
-(5a+31)+ a =5
-5a-31+a=5
-4a=5+31
-4a=36
a=36/-4
a=-9 Answer.
Proof:
-(5*-9+31)+(-9)=5
-(-45+31)-9=5
-(-14)-9=5
+14-9=5
5=5


Linear-systems/162975: ) Demonstrate by determining the intercepts of "14x + 7y = 21". Non graphing
1 solutions

Answer 120093 by checkley77(12569) About Me  on 2008-10-19 17:36:20 (Show Source):
You can put this solution on YOUR website!
14x + 7y = 21
7y=-14x+21 the y intercept=(0,21)
Setting y=0 & solving for x we get:
7*0=-14x+21
-14x=21
x=21/-14
x=-3/2=-1.5 Thus the x intecept=(-1.5,0)


Linear_Algebra/162974: This question is from textbook Algebra 2
Solve each system by elimination
3m+4n= -13
3m+6m= -19

1 solutions

Answer 120092 by checkley77(12569) About Me  on 2008-10-19 17:33:22 (Show Source):
You can put this solution on YOUR website!
3m+4n= -13
-(3m+6[n]= -19) assuming the second term is suposed to be an n not an m.
---------------- subtract the second from the first equation.
-2n=6
n=6/-2
n=-3 Answer.
3m+4*-3=-13
3m-12=-13
3m=-13+12
m=-1/3 Answer.


Proportions/162897: The interests earned on an investment varies directly with interest rate. If a 10% rate gives 200$, the interest rate that gives 300$ is..
1 solutions

Answer 120054 by checkley77(12569) About Me  on 2008-10-19 10:57:05 (Show Source):
You can put this solution on YOUR website!
.10/200=x/300
200x=.1*300
200x=30
x=30/200
x=.15 or 15% interst rate yields the $300.


Graphs/162828: Please help! I am struggling with these type problems.
Solve then graph.
a + 4 < -12
The solution set is {a/a< _____}
Show the graph.

1 solutions

Answer 120053 by checkley77(12569) About Me  on 2008-10-19 10:54:31 (Show Source):
You can put this solution on YOUR website!
a + 4 < -12
a<-12-4
a<-16 Answer.
Proof:
let a=-17
-17+4<-12
-13<-12


Linear-equations/162860: would you please be able to tell me how to make this equation x-y=-9 into a general form and would you also be able to explain how you got it please
1 solutions

Answer 120052 by checkley77(12569) About Me  on 2008-10-19 10:49:53 (Show Source):
You can put this solution on YOUR website!
x-y=-9
IF you're talking about a line equation then:
-y=-x-9
y=x+9 Answer as a line equation.
Graph follows:
+graph%28+300%2C+200%2C+-10%2C+5%2C+-10%2C+10%2C+x+%2B9%29+ (graph 300x200 pixels, x from -10 to 5, y from -10 to 10, x +9).


Radicals/162865: This question is from textbook
Simplify (3sqrt5 - 2sqrt3)(sqrt5 - 3sqrt3)
Using the FOIL method:
I got 3sqrt25 - 9sqrt15 - 2sqrt15 +6sqrt9
simplified to -11sqrt15
Is this correct any help appreciated
1 solutions

Answer 120050 by checkley77(12569) About Me  on 2008-10-19 10:46:46 (Show Source):
You can put this solution on YOUR website!
I'm afraid it isn't correct.
(3sqrt5 - 2sqrt3)(sqrt5 - 3sqrt3)
3*5-2sqrt15-9sqrt15+6*3
15+18-11sqrt15
33-11sqrt15
11(3-sqrt15) answer.


Problems-with-consecutive-odd-even-integers/162868: if the product of two consecutive odd integers is decreased by 3, the result is 12. find the integers
1 solutions

Answer 120048 by checkley77(12569) About Me  on 2008-10-19 10:42:40 (Show Source):
You can put this solution on YOUR website!
x(x+2)-3=12
x^2+2x-3=12
x^2+2x-3-12=0
x^2+2x-15=0
(x+5)(x-3)=0
x+5=0
x=-5 answer.
x-3=0
x=3 answer.
Proofs:
-5(-5+2)-3=12
-5*-3-3=12
15-3=12
12=12
3(3+2)-3=12
3*5-3=12
15-3=12
12=12



Linear-systems/162870: please help me solve this equation(4r-2)-(3r=1)
1 solutions

Answer 120046 by checkley77(12569) About Me  on 2008-10-19 10:36:06 (Show Source):
You can put this solution on YOUR website!
(4r-2)-(3r=1)
4r-2-3r=-1
r-2=-1
r=-1+2
r=1 answer.
UNLESS you meant:
(4r-2)-(3r)=1 then:
4r-2-3r=1
r=1+2
r=3 answer.


Exponential-and-logarithmic-functions/162871: Please answer the folong question for me:
12/(3x-2)+5/(x+4)=1
Thank you.
1 solutions

Answer 120044 by checkley77(12569) About Me  on 2008-10-19 10:32:46 (Show Source):
You can put this solution on YOUR website!
Would I get the same answer with 12/3x-2+5/x+4=1? Answer=NO!
12/3x-2+5/x+4=0
4/x-2+5/x+4=0
4/x+5/x=2-4
9/x=-2
-2x=9
x=9/-2
x=-4.5 Answer.
--------------------------------------------------
12/(3x-2)+5/(x+4)=1
[12(X+4)+5(3X-2)/(3X-2)(X+4)=1
(12X+48+15X-10)=(3X-2)(X+4
27X+38=3X^2+10X-8
3X^2+10X-27X-8+38=0
3X^2-17X+30=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(17+-SQRT[-17^2-4*3*30])/2*3
X=(17+-SQRT[289-360])/6
X=(17+-SQRT-71)/6
X=(17+-8.426i)/6
X=17/6+-8.426i/6
X=2.833+-1.4i ANSWERS.


Equations/162876: Can someone please varify if this is correct?
Problem: 2mh-k=Ek solve for m
2mh-k=Ek
+k +k
----------
2mh=Ekk
/2h /2h
----------
m=Ekk/2h
Thanks!
1 solutions

Answer 120043 by checkley77(12569) About Me  on 2008-10-19 10:20:54 (Show Source):
You can put this solution on YOUR website!
2mh-k=Ek
2MH=EK+K
M=(EK+K)/2H
M=K(E+1)/2H ANSWER.


Linear_Equations_And_Systems_Word_Problems/162881: Ruth purchases some $.01 stamps, some $.15 stamps and some $.20 stamps. She has spend a total of $5.00. There are three times as many $.01 stamps as $.20 stamps and 8 more $.15 stamps than $.20 stamps. How many stamps in all does she buy?
1 solutions

Answer 120042 by checkley77(12569) About Me  on 2008-10-19 10:16:46 (Show Source):
You can put this solution on YOUR website!
.01*3X+.15(X+8)+.20X=5.00
.03X+.15X+1.2+.20X=5.00
.38X=5.00-1.20
.38X=3.80
X=3.80/.38
X=10 .20 CENT STANPS WERE PERDHASED.
3*10=30 .01 CENT STAMPS WERE PURCHASED.
10+8=18 .15 CENT STAMPS WERE PURCHASED.
10+30+18=58 A TOTAL OF 58 STAMPS WERE PURCHASED.
PROOF:
.01*30+.15*18+.20*10=5.00
.30+2.70+2.00=5.00
5.00=5.00


Polynomials-and-rational-expressions/162884: find the product of
-5x(2x^3 - 5x +2) = -10x^4 - 25x^2 + 10 is that the right answer
also
do the addition:
7a^3 + 7a^2 + 4
-4a^3 + 9a - 5
2a^3 - 5a^2 + 9a + 9

1 solutions

Answer 120041 by checkley77(12569) About Me  on 2008-10-19 10:09:16 (Show Source):
You can put this solution on YOUR website!
-5x(2x^3 - 5x +2) = -10x^4 - 25x^2 + 10 is that the right answer.
NO IT IS WRONG.
-10X^4+25X^2-10X IS THE CORRECT ANSWER.
[-5X*-5X=+25X^2]
[-5X*2=-10X]


Travel_Word_Problems/162809: At midnight a train left for Denver bound for Chicago, and another train left Chicago bound for Denver, both traveling at consatent speeds on adjacent tracks. The first train took 12 hours to complete the trip, and the second train took 16 hours to complete the trip. At what time did they passeach other?
1 solutions

Answer 120015 by checkley77(12569) About Me  on 2008-10-18 19:33:19 (Show Source):
You can put this solution on YOUR website!
AVERAGE TIME=(12+16)/2=14 HOURS.
THUS THE HALF WAY POINT WOULD BE 14/2=7 HOURS (7:00 AM) INTO THE TRIP THEY WOULD PASS EACH OTHER.


Travel_Word_Problems/162810: A car went 4 miles up a hill at 10 miles per hour and back down the same hill 20 miles per hour. What was the average speed for the round trip?
1 solutions

Answer 120014 by checkley77(12569) About Me  on 2008-10-18 19:18:03 (Show Source):
You can put this solution on YOUR website!
D=RT OR D/R=T
4/10+4/20=.4+.2=.6 IS THE TIME FOR THE TOTAL TRIP.
8/.6=13.33 MPH IS THE AVERAGE SPEED.


Travel_Word_Problems/162811: Two cyclists racing on parrell roads maintain constant speeds of 30 mph and 25 mph. The faster cyclist crosses the finish line one hour before the slower cyclist. How long was the race in miles?
1 solutions

Answer 120013 by checkley77(12569) About Me  on 2008-10-18 19:14:00 (Show Source):
You can put this solution on YOUR website!
D=RT
30(T-1)=25T
30T-30=25T
30T-25T=30
5T=30
T=30/5
T=6 HOURS IS THE RACE TIME FOR THE SLOWER CYCLIST.
25*6=150 MILES IS THE RACE DISTANCE.


Travel_Word_Problems/162808: A train left Denver bound for Omaha at speed of 80 miles per hour, and at the same time another train left at Omaha bound for Denver at a speed of 100 miles per hour. When the trains passed each other, what fraction of the trip had the train from Denver completed?
1 solutions

Answer 120012 by checkley77(12569) About Me  on 2008-10-18 19:02:05 (Show Source):
You can put this solution on YOUR website!
Assume they have been on the rail for 1 hour thus they ahve covered a total of (80+100=180) miles & the Denver train has covered 80 miles.
Thus:
80/(80+100)=80/180=.444=44.4% or the trip.


Graphs/162749: solve the following system of equations
x+2y=3
x=5-2y
what is the order pair??

1 solutions

Answer 120007 by checkley77(12569) About Me  on 2008-10-18 18:31:55 (Show Source):
You can put this solution on YOUR website!
x+2y=3
x=5-2y or x+2y=5
x+2y=3
-(x+2y=5) now subtract.
-------------------------
0x+0y=-2
No solution for x & y as these two equations represent parallel lines if graphed.
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-x%2F2+%2B3%2F2%2C+-x%2F2+%2B5%2F2%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions -x/2 +3/2 and -x/2 +5/2).


Signed-numbers/162756: .12(y-6)+.06y=.08y-.07(10)
1 solutions

Answer 120006 by checkley77(12569) About Me  on 2008-10-18 18:22:46 (Show Source):
You can put this solution on YOUR website!
.12(y-6)+.06y=.08y-.07(10)
.12Y-.72+.06Y=.08Y-.7
.12Y+.06Y-.08Y=-.7+.72
.1Y=.02
Y=.02/.1
Y=.2 ANSWER.
PROOF:
.12(.2-6)+.06*.2=.08*.2-.07*10
.12*-5.8+.012=.016-.7
-.696+.012=-.684
-.684=-.684


Mixture_Word_Problems/162773: This question is from textbook
Beverly can drive 600 miles in the same time as it takes Susan to drive 500 miles. If Beverly drives 10 mpg faster than Susan, then how fast does Beverly drive?
1 solutions

Answer 120002 by checkley77(12569) About Me  on 2008-10-18 17:34:09 (Show Source):
You can put this solution on YOUR website!
D=RT OR D/R=T
SEEING AS THE TIMES ARE THE SAME.
THEN:
600/(R+10)=500/R
500(R+10)=600R
500R+5,000=600R
500R-600R=-5,000
-100R=-5,000
R=-5,000/-100
R=50 MPH FOR SUSAN.
50+10=60 MPH FOR BEVERLY.
PROOF:
600/60=500/50
10=10


Equations/162806: This question is from textbook algergra tools for a changing world
x/4 + 3x/5 = 17 I tried 16x/20 = 629
1 solutions

Answer 120001 by checkley77(12569) About Me  on 2008-10-18 17:28:43 (Show Source):
You can put this solution on YOUR website!
x/4 + 3x/5 = 17
(5X+4*3X)/20=17
(5X+12X)/20=17
17X=20*17
17X=340
X=340/17
X=20 ANSWER.
PROOF:
20/4+3*20/5=17
5+60/5=17
5+12=17
17=17


Numbers_Word_Problems/162804: Find 3 #'s in which the second # is 3 times the first # and the third # is 2 less than 5 times the first #. The sum of three #'s is 115. Find the three #'s.
What I have tried:
3(x+2)+2(5x+1)=115
3x+6+10x+1=115
13x+7=115
-7 -7
13x=108
/13 /13
x=8.31
I know this isn't correct. Please help

1 solutions

Answer 119998 by checkley77(12569) About Me  on 2008-10-18 17:25:50 (Show Source):
You can put this solution on YOUR website!
S=3F
T=5F-2
F+S+T=115
F+3F+(5F-2)=115
9F=115+2
9F=117
F=117/9
F=13 FOR THE FIRST NUMBER.
3*13=39 FOR THE SECOND NUMBER.
5*13-2=65-2=63 FOR THE THIRD NUMBER.
PROOF:
13+39+63=115
115=115


Geometry_Word_Problems/162805: What will it cost to tile a rectangular floor measuring 297 feet by 38 feet if the tile costs $14 per square foot?
I tried:
A=LW
A=297(38)
A= 11,286ft
11286(14)= $158,004
1 solutions

Answer 119996 by checkley77(12569) About Me  on 2008-10-18 17:19:52 (Show Source):
You can put this solution on YOUR website!
297*38=11,286 FT^2 IS TO BE TILED.
11,286*14=$158,004 COST OF THE TILE.
YOU'RE RIGHT ON.


Rectangles/162778: As a real estate tycoon you have bought a rectangular parcel of waterfront property and want to enclose your land as follows: Using 5000 feet of fencing you want to enclose a rectangular section on only three sides using the water as the 4th side. What dimensions (length and width of the rectangle) should the enclosure be to assure maximum area?
I have been working on this problem for over two hours, it's ripping my mind apart! PLEASE HELP.
1 solutions

Answer 119995 by checkley77(12569) About Me  on 2008-10-18 17:17:13 (Show Source):
You can put this solution on YOUR website!
THE MAXIMUM AREA FOR A FENCE AROUND 3 SIDES OF A RECTANGLE IS:
1*1*2=4 EQUAL MEASUREMENTS.
5,000/4=1250 FT.
SO YOU'LL HAVE 2 SIDES=1,250 EACH & 1 SIDE=2*1,250 OR 2,500 FT.
1,250+1,250+2,500=5,000 FT. OF FENCING.
1,250*2,500=3,125,000 FT^2 IS THE MAXIMUM AREA ENCLOSED.
PROOF:
REDUCE EAACH OF THE TWO 1,250 FT. FENCES BY 1 FOOT & INCREASE THE 2,500 FT FENCE BY 2 FT.
1,249*2,502=3,124,998 FT^2.
OR DECREASE THE 2,500 FT FENCE BY 1 FT & INCREASE EACH OF THE 1,250 FT FENCES BY 0.5 FT.
2,499*1,250.5=3,124,999 FT^2.


test/162785: This question is from textbook Elementary and Intermediate
104) Venture captial. Henry invested $12,000 in a new restaurant. When the restaurant was sold two years later, be received $27,000. Find his average annual return by solving the equation 12,000(1+r)^2 = 27,000
1 solutions

Answer 119993 by checkley77(12569) About Me  on 2008-10-18 17:06:44 (Show Source):
You can put this solution on YOUR website!
12,000(1+r)^2 = 27,000
12,000(1+2R+R^2)=27,000
12,000+24,000R+12,000R^2=27,000
12,000R^2+24,000R+12,000-27,000=0
12,000R^2+24,000R-15,000=0
3,000(4R^2+8R-5)=0
3,000(2R-1)(2R+5)=0
2R-1=0
2R=1
R=1/2 OR .5 OR 50% ANNUAL RETURN.
PROOF:
12,000(1+.5)^2=27,000
12,000(1.5)^2=27,000
12,000*2.25=27,000
27,000=27,000