Tutor:

New! Get regular updates about newly solved problems via algebra.com's RSS system.

---

Recent problems solved by 'checkley77'

checkley77 answered: 12560 problems
Jump to solutions: 0..29 , 30..59 , 60..89 , 90..119 , 120..149 , 150..179 , 180..209 , 210..239 , 240..269 , 270..299 , 300..329 , 330..359 , 360..389 , 390..419 , 420..449 , 450..479 , 480..509 , 510..539 , 540..569 , 570..599 , 600..629 , 630..659 , 660..689 , 690..719 , 720..749 , 750..779 , 780..809 , 810..839 , 840..869 , 870..899 , 900..929 , 930..959 , 960..989 , 990..1019 , 1020..1049 , 1050..1079 , 1080..1109 , 1110..1139 , 1140..1169 , 1170..1199 , 1200..1229 , 1230..1259 , 1260..1289 , 1290..1319 , 1320..1349 , 1350..1379 , 1380..1409 , 1410..1439 , 1440..1469 , 1470..1499 , 1500..1529 , 1530..1559 , 1560..1589 , 1590..1619 , 1620..1649 , 1650..1679 , 1680..1709 , 1710..1739 , 1740..1769 , 1770..1799 , 1800..1829 , 1830..1859 , 1860..1889 , 1890..1919 , 1920..1949 , 1950..1979 , 1980..2009 , 2010..2039 , 2040..2069 , 2070..2099 , 2100..2129 , 2130..2159 , 2160..2189 , 2190..2219 , 2220..2249 , 2250..2279 , 2280..2309 , 2310..2339 , 2340..2369 , 2370..2399 , 2400..2429 , 2430..2459 , 2460..2489 , 2490..2519 , 2520..2549 , 2550..2579 , 2580..2609 , 2610..2639 , 2640..2669 , 2670..2699 , 2700..2729 , 2730..2759 , 2760..2789 , 2790..2819 , 2820..2849 , 2850..2879 , 2880..2909 , 2910..2939 , 2940..2969 , 2970..2999 , 3000..3029 , 3030..3059 , 3060..3089 , 3090..3119 , 3120..3149 , 3150..3179 , 3180..3209 , 3210..3239 , 3240..3269 , 3270..3299 , 3300..3329 , 3330..3359 , 3360..3389 , 3390..3419 , 3420..3449 , 3450..3479 , 3480..3509 , 3510..3539 , 3540..3569 , 3570..3599 , 3600..3629 , 3630..3659 , 3660..3689 , 3690..3719 , 3720..3749 , 3750..3779 , 3780..3809 , 3810..3839 , 3840..3869 , 3870..3899 , 3900..3929 , 3930..3959 , 3960..3989 , 3990..4019 , 4020..4049 , 4050..4079 , 4080..4109 , 4110..4139 , 4140..4169 , 4170..4199 , 4200..4229 , 4230..4259 , 4260..4289 , 4290..4319 , 4320..4349 , 4350..4379 , 4380..4409 , 4410..4439 , 4440..4469 , 4470..4499 , 4500..4529 , 4530..4559 , 4560..4589 , 4590..4619 , 4620..4649 , 4650..4679 , 4680..4709 , 4710..4739 , 4740..4769 , 4770..4799 , 4800..4829 , 4830..4859 , 4860..4889 , 4890..4919 , 4920..4949 , 4950..4979 , 4980..5009 , 5010..5039 , 5040..5069 , 5070..5099 , 5100..5129 , 5130..5159 , 5160..5189 , 5190..5219 , 5220..5249 , 5250..5279 , 5280..5309 , 5310..5339 , 5340..5369 , 5370..5399 , 5400..5429 , 5430..5459 , 5460..5489 , 5490..5519 , 5520..5549 , 5550..5579 , 5580..5609 , 5610..5639 , 5640..5669 , 5670..5699 , 5700..5729 , 5730..5759 , 5760..5789 , 5790..5819 , 5820..5849 , 5850..5879 , 5880..5909 , 5910..5939 , 5940..5969 , 5970..5999 , 6000..6029 , 6030..6059 , 6060..6089 , 6090..6119 , 6120..6149 , 6150..6179 , 6180..6209 , 6210..6239 , 6240..6269 , 6270..6299 , 6300..6329 , 6330..6359 , 6360..6389 , 6390..6419 , 6420..6449 , 6450..6479 , 6480..6509 , 6510..6539 , 6540..6569 , 6570..6599 , 6600..6629 , 6630..6659 , 6660..6689 , 6690..6719 , 6720..6749 , 6750..6779 , 6780..6809 , 6810..6839 , 6840..6869 , 6870..6899 , 6900..6929 , 6930..6959 , 6960..6989 , 6990..7019 , 7020..7049 , 7050..7079 , 7080..7109 , 7110..7139 , 7140..7169 , 7170..7199 , 7200..7229 , 7230..7259 , 7260..7289 , 7290..7319 , 7320..7349 , 7350..7379 , 7380..7409 , 7410..7439 , 7440..7469 , 7470..7499 , 7500..7529 , 7530..7559 , 7560..7589 , 7590..7619 , 7620..7649 , 7650..7679 , 7680..7709 , 7710..7739 , 7740..7769 , 7770..7799 , 7800..7829 , 7830..7859 , 7860..7889 , 7890..7919 , 7920..7949 , 7950..7979 , 7980..8009 , 8010..8039 , 8040..8069 , 8070..8099 , 8100..8129 , 8130..8159 , 8160..8189 , 8190..8219 , 8220..8249 , 8250..8279 , 8280..8309 , 8310..8339 , 8340..8369 , 8370..8399 , 8400..8429 , 8430..8459 , 8460..8489 , 8490..8519 , 8520..8549 , 8550..8579 , 8580..8609 , 8610..8639 , 8640..8669 , 8670..8699 , 8700..8729 , 8730..8759 , 8760..8789 , 8790..8819 , 8820..8849 , 8850..8879 , 8880..8909 , 8910..8939 , 8940..8969 , 8970..8999 , 9000..9029 , 9030..9059 , 9060..9089 , 9090..9119 , 9120..9149 , 9150..9179 , 9180..9209 , 9210..9239 , 9240..9269 , 9270..9299 , 9300..9329 , 9330..9359 , 9360..9389 , 9390..9419 , 9420..9449 , 9450..9479 , 9480..9509 , 9510..9539 , 9540..9569 , 9570..9599 , 9600..9629 , 9630..9659 , 9660..9689 , 9690..9719 , 9720..9749 , 9750..9779 , 9780..9809 , 9810..9839 , 9840..9869 , 9870..9899 , 9900..9929 , 9930..9959 , 9960..9989 , 9990..10019 , 10020..10049 , 10050..10079 , 10080..10109 , 10110..10139 , 10140..10169 , 10170..10199 , 10200..10229 , 10230..10259 , 10260..10289 , 10290..10319 , 10320..10349 , 10350..10379 , 10380..10409 , 10410..10439 , 10440..10469 , 10470..10499 , 10500..10529 , 10530..10559 , 10560..10589 , 10590..10619 , 10620..10649 , 10650..10679 , 10680..10709 , 10710..10739 , 10740..10769 , 10770..10799 , 10800..10829 , 10830..10859 , 10860..10889 , 10890..10919 , 10920..10949 , 10950..10979 , 10980..11009 , 11010..11039 , 11040..11069 , 11070..11099 , 11100..11129 , 11130..11159 , 11160..11189 , 11190..11219 , 11220..11249 , 11250..11279 , 11280..11309 , 11310..11339 , 11340..11369 , 11370..11399 , 11400..11429 , 11430..11459 , 11460..11489 , 11490..11519 , 11520..11549 , 11550..11579 , 11580..11609 , 11610..11639 , 11640..11669 , 11670..11699 , 11700..11729 , 11730..11759 , 11760..11789 , 11790..11819 , 11820..11849 , 11850..11879 , 11880..11909 , 11910..11939 , 11940..11969 , 11970..11999 , 12000..12029 , 12030..12059 , 12060..12089 , 12090..12119 , 12120..12149 , 12150..12179 , 12180..12209 , 12210..12239 , 12240..12269 , 12270..12299 , 12300..12329 , 12330..12359 , 12360..12389 , 12390..12419 , 12420..12449 , 12450..12479 , 12480..12509 , 12510..12539 , 12540..12569, >>Next

Money_Word_Problems/167912: At a skating rink, students pay $.75 admission and adults pay $1.25. For one night, the recipts were $85 and 100 people paid. How many people were adults? 1 solutions Answer 123754 by checkley77(12569)   on 2008-11-16 16:38:27 (Show Source): You can put this solution on YOUR website! 1.25X+.75(100-X)=85 1.25X+75-.75X=85 .5X=85-75 .5X=10 X=10/.5 X=20 ADULT TICKETS WERE SOLD. PROOF: 1.25*20+.75(100-20)=85 25+.75*80=85 25+60=85 85=85

Numbers_Word_Problems/167909: Find the number of two-digit positive integers whose digits total 7. I know the answer is 7 (16, 25, 34, 43, 52, 61, 70) but my teacher wants me to show it in an algebraic formula. How do I do that? This question is not from a textbook. 1 solutions Answer 123753 by checkley77(12569)   on 2008-11-16 16:35:41 (Show Source): You can put this solution on YOUR website! X+Y=7 MAKE UP A TABLE WITH X=0,1,2,3,4,5,6 & 7 AND SOLVE FOR Y. 0+Y=7 Y=7 OR 07 1+Y=7 Y=7-1 Y=6 OR 16 2=Y=7 Y=7-2 Y=5 OR 25 3=Y=7 Y=7-3 Y=4 OR 34 5+Y=7 Y=7-5 Y=2 OR 52 6+Y=7 Y=7-6 Y=1 OR 61 7+Y=7 Y=7-7 Y=0 OR 70

Distributive-associative-commutative-properties/167895: Help! I am lost. (5x2 – 3x + 2) + (-3x2 + 9x – 8) – (x2 + 3x – 10) 1 solutions Answer 123752 by checkley77(12569)   on 2008-11-16 16:27:48 (Show Source): You can put this solution on YOUR website! IF YOU JUST WANT TO COMBINE THESE TERMS THEN: (5x^2–3x+2)+(-3x^2+9x–8)–(x^2+3x–10) 5X^2-3X+2-3X^2+9X-8-X^2-3X+10 X^2+3X+4 ans.

Finance/167896: can someone help please: Find the present value of the future amount. Assume 365 days in a year. Round to the nearest cent. $15,000 for 110 days; money earns 8% 1 solutions Answer 123750 by checkley77(12569)   on 2008-11-16 16:19:16 (Show Source): You can put this solution on YOUR website! 15,000(1+.08*110/365)^110/365 15,000(1.0241)^.30137 15,000*1.0072=$15,108.04 ANS.

Rational-functions/167898: I need to solve for x. 4x(x-2)-5x(x-1)=2 I have already taken the steps to make the problem 4x^2-8x-5x^2-5x=2, but that is all I have. I have been trying by "substitution", but have not found the answer. Please help me solve for x. Thank you, Rachel 1 solutions Answer 123748 by checkley77(12569)   on 2008-11-16 16:12:50 (Show Source): You can put this solution on YOUR website! 4x(x-2)-5x(x-1)=2 4X^2-8X-5X^2+5X-2=0 -X^2-3X-2=0 X^2+3X+2=0 (X+2)(X+1)=0 X+2=0 X=-2 ANS. X+1=0 X=-1 ANS. PROOFS: 4*-2(-2-2)-5*-2(-2-1)=2 -8*-4+10*-3=2 32-30=2 2=2 4*-1(-1-2)-5*-1(-1-1)=2 -4*-3+5*-2=2 12-10=2

Equations/167901: I have to write an inequality that demonstrates that I wish to spend no less than $6000 and no more than #10000. How do I go about this? 1 solutions Answer 123747 by checkley77(12569)   on 2008-11-16 16:10:39 (Show Source): You can put this solution on YOUR website! $6,000$10,000

Rational-functions/167899: I am working with my school website on My Math Lab and this is a question asked. I need to solve for x. 4x(x-2)-5x(x-1)=2 I have already taken the steps to make the problem 4x^2-8x-5x^2-5x=2, but that is all I have. I have been trying by "substitution", but have not found the answer. Please help me solve for x. Thank you, Rachel 1 solutions Answer 123746 by checkley77(12569)   on 2008-11-16 16:09:02 (Show Source): You can put this solution on YOUR website! 4x(x-2)-5x(x-1)=2 4X^2-8X-5X^2+5X-2=0 -X^2-3X-2=0 X^2+3X+2=0 (X+2)(X+1)=0 X+2=0 X=-2 ANS. X+1=0 X=-1 ANS. PROOFS: 4*-2(-2-2)-5*-2(-2-1)=2 -8*-4+10*-3=2 32-30=2 2=2 4*-1(-1-2)-5*-1(-1-1)=2 -4*-3+5*-2=2 12-10=2 2=2

Linear_Algebra/167817: Solve each system by the addition method. x + y = 7 X – y = 9 x – y = 12 2x + y = 3 2x – y = -5 3x + 2y = 3 3x + 4y = -5 5x + 6y = -7 1 solutions Answer 123722 by checkley77(12569)   on 2008-11-16 09:54:40 (Show Source): You can put this solution on YOUR website! x+y=7 x–y=9 add ------------- 2x=16 x=16/2 x=8 ans. 8+y=7 y=7-8 y=-1 ans. ************************* x–y=12 2x+y=3 add ------------------- 3x=15 x=15/3 x=5 ans. 5-y=12 -y=12-5 -y=7 y=-7 ans. *********************************** 2x–y=-5 multiply this equation by 2 & add. 3x+2y=3 4x-2y=-10 ----------- 7x=-7 x=-7/7 x=-1 ans. 2*-1-y=-5 -2-y=-5 -y=-5+2 -y=-3 y=3 ans. ************************* 3x+4y=-5 multiply by 5 5x+6y=-7 multiply by -3 & add. 15x+20y=-25 -15x-18y=21 ------------------ 2y=-4 y=-4/2 y=-2 ans. 3x+4*-2=-5 3x-8=-5 3x=-5+8 3x=3 x=3/3 x=1 ans.

Square-cubic-other-roots/167824: Find all real or imaginary solutions. Sqrt(2x^2+x-12)=x 1 solutions Answer 123719 by checkley77(12569)   on 2008-11-16 09:44:22 (Show Source): You can put this solution on YOUR website! Sqrt(2x^2+x-12)=x squaring both sides we get: 2x^2+x-12=x^2 2x^2-x^2+x-12=0 x^2+x-12=0 (x+4)(x-3) x+4=0 x=-4 ans. x-3 x=3 ans. Proofs: sqrt(2*-4^2+(-4)-12=-4 sqrt(2*16-4-12)=-4 sqrt(32-16)=-4 sqrt16=-4 -4=-4 sqrt(2*3^2+3-12)=3 sqrt(2*9+3-12)=3 sqrt(18+3-12)=3 sqrt9=3 3=3

Exponents-negative-and-fractional/167823: Simplify the expression: (9y^4 x^1/2)^1/2. Please help. 1 solutions Answer 123717 by checkley77(12569)   on 2008-11-16 09:38:17 (Show Source): You can put this solution on YOUR website! 9y^4 x^1/2)^1/2 SQRT(9Y^4SQRTX) 3Y^2(4THRTX) OR:

Exponential-and-logarithmic-functions/167820: Simplfy by removing non-positive exponents: x to the -1 plus y to the -1 divided by x squared minus y squared. 1 solutions Answer 123714 by checkley77(12569)   on 2008-11-16 09:20:02 (Show Source): You can put this solution on YOUR website! (X^-1+Y^-1)/(X^2-Y^2) (X^-1+Y^-1)/(X+Y)(X-Y) 1/(X+Y)(X+Y)(X-Y)

Numeric_Fractions/167822: Mother spent 1/2 of her money in the first store. She spent 2/3 of her money in the second store. She has $25 left. How much money does she have first? 1 solutions Answer 123712 by checkley77(12569)   on 2008-11-16 09:05:34 (Show Source): You can put this solution on YOUR website! x=25+2/3*1/2x+1/2x x=25+2x/6+x/2 x=25+(2x+3x)/6 x=25+5x/6 x-5x/6=25 x/6=25 x=25*6 x=$150 initial amount Mother had. Proof: 150=25+2/3*150/2+150/2 150=25+300/6+150/2 150=25+50+75 150=150

Linear_Equations_And_Systems_Word_Problems/167760: john has retired and needs $ 6000 per annum to live. he has $50000 to invest and can invest in bonds at 15 % annual interest or in bank certificates at an annual rate of 7 % .how much money should he invest in each type of investment to get a income of 6000 $ per annum? what if he determines he actually requires an income of 7000 per year 1 solutions Answer 123676 by checkley77(12569)   on 2008-11-15 21:48:35 (Show Source): You can put this solution on YOUR website! .15x+.07(50,000-x)=6000 .15x+3,500-.07x=6,000 .08x=6,000-3,500 .08x=2,500 x=2,500/.08 x=$31.250 needs to be invested @ 15% 50,000-31,250=18,750 invested @ 7% ------------------------------------- .15x+.07(50,000-x)=7000 .15x+3,500-.07x=7,000 .08x=7,000-3,500 .08x=3,500 x=3,500/.08 x=43,750 amount invested @ 15% 50,000-43,750=6,250 invested @ 7%

Miscellaneous_Word_Problems/167771: P dollars is invested at annual interest rate r for 1 year. If the interest is compounded semiannually, then the polynomial p(1+r/2)^2 represents the value of the investment after 1 year. Rewrite this expression without parentheses. Evaluate the polynomial if P = $200 and r =10%. I am so confused can someone please help me? Thank you 1 solutions Answer 123673 by checkley77(12569)   on 2008-11-15 21:40:19 (Show Source): You can put this solution on YOUR website! p(1+r/2)^2 200(1+.10/2)^2 200(1.05)^2 200*1.1025=220.50 is the value of the investment after 1 year..

Travel_Word_Problems/167772: Two cars that are 375 miles apart and whose speeds differ by 5 miles per hour, are moving toward each other. They will meet in hours. What is the speed of each car? 1 solutions Answer 123671 by checkley77(12569)   on 2008-11-15 21:37:04 (Show Source): You can put this solution on YOUR website! Did you leave out the number of hours?

expressions/167775: Solve using the square root property: 2x2 = 40 1 solutions Answer 123670 by checkley77(12569)   on 2008-11-15 21:35:28 (Show Source): You can put this solution on YOUR website! 2x2 = 40 If you mean 2x^2=40 then: x^2=40/2 x^2=20 x=sqrt20 x=2sqrt5 or 4.4721359 answer.

Polynomials-and-rational-expressions/167666: FACTOR COMPLETELY -10x^4yz^2-25x^2z^3 1 solutions Answer 123583 by checkley77(12569)   on 2008-11-15 09:09:34 (Show Source): You can put this solution on YOUR website! -10x^4yz^2-25x^2z^3 -5X^2Z^2(2X^2Y+5Z) ANSWER.

Polynomials-and-rational-expressions/167681: Factorise: 125x^6 + 59x^3y^3 + 64y^6 1 solutions Answer 123582 by checkley77(12569)   on 2008-11-15 09:07:16 (Show Source): You can put this solution on YOUR website! 125x^6 + 59x^3y^3 + 64y^6 X=(-59+-SQRT[59^2-4*125*64])/2*125 X=(-59+-SQRT[3,481-32,000])/250 X=(-59+-SQRT-28,519)/250 X=(-59+-168.87569i)/250 X=-59/250+-168.87569i/250 X=-0.236+-0.6755i ANSWERS.

Polynomials-and-rational-expressions/167682: This question is from textbook ELEMENTARY AND INTERMEDIATE ALGEBRA When all of the grocery carts escape from the supermarket, it takes Reginald 12 minutes to round them up and bring them back. Because Norman doesn’t make as much per hour as Reginald, it takes Norman 18 minutes to do the same job. How long would it take them working together to complete the roundup? 1 solutions Answer 123581 by checkley77(12569)   on 2008-11-15 08:59:25 (Show Source): You can put this solution on YOUR website! (12*18)/(12+18)=216/20=10.8 HOURS WHEN THEY WORK TOGETHER.

Polynomials-and-rational-expressions/167687: This question is from textbook ELEMENTARY AND INTERMEDIATE ALGEBRA For a certain time period the ratio of the dollar value of exports to the dollar value of imports for the United States was 2 to 3. If the value of exports during that time period was 48 billion dollars, then what was the value of imports? 1 solutions Answer 123580 by checkley77(12569)   on 2008-11-15 08:57:23 (Show Source): You can put this solution on YOUR website! E/1=2/3 48/I=2/3 2I=3*48 2I=144 I=144/2 I=$72 BILLION FOR THE IMPORTS.

Rectangles/167691: Find the lenghth of a rectangle when the width is 2 inches shorter and the perimeter is 80. Set up the equation for the perimeter involving only (L) and then sove the equation for the length and the width. 1 solutions Answer 123579 by checkley77(12569)   on 2008-11-15 08:53:37 (Show Source): You can put this solution on YOUR website! W=L-2 2L+2W=80 2L+2(L-2)=80 2L+2L-4=80 4L=80+4 4L=84 L=84/4 L=21 ANSWER FOR THE LENGTH. W=21-2 W=19 ANSWER FOR THE WIDTH. PROOF: 2*21+2*19=80 42+38=80 80=80

Exponential-and-logarithmic-functions/167592: I have a word problem that I need help with. I must show my work. 1. In a certain area, the sale price of new single-family homes has increased 4.1% per year since 1992. If a house was purchased in this area in 1992 for $75,000 and the growth continues, what will be sale price in 2006? Use y=a(1+r)^t and round to the nearest cent. Thanks 1 solutions Answer 123556 by checkley77(12569)   on 2008-11-14 20:30:20 (Show Source): You can put this solution on YOUR website! y=a(1+r)^t 75,000(1+.041)^14 75,000(1.041)^14 75,000*1.755=$131,635.03 sale price in 2006.

Percentage-and-ratio-word-problems/167646: Solve for m using just the meaning of multiplication and reasoning (no algebraic manipulation) a) 15 X 13= 9 X 13 + m X 13 b) 16m=8m+32 1 solutions Answer 123554 by checkley77(12569)   on 2008-11-14 20:25:35 (Show Source): You can put this solution on YOUR website! a) 15 X 13= 9 X 13 + m X 13 (eliminate the common X13 terms). 15=9+m 15-9=m 6=m b) 16m=8m+32 2m=m+4 2m=m+m thus m=4.

Polynomials-and-rational-expressions/167556: 64 - (B - 2)^3 1 solutions Answer 123476 by checkley77(12569)   on 2008-11-14 10:25:24 (Show Source): You can put this solution on YOUR website! 64-(b-2)^3 b-2 b-2 (multiply) ----- b^2-2b-2b+4 b^2-4b+4 b-2 (multiply) ---- b^3-4b^2+4b-2b^2+8b-8 b^3-6b^2+12b-8 64-(b^3-6b^2+12b-8) 64-b^3+6b^2-12b+8 -b^3+6b^2-12b+8+64 b^3-6b^2+12b-72 answer.

Numeric_Fractions/167578: Please help me solve this equation: 1 2/3 - 2 1/2 1 solutions Answer 123475 by checkley77(12569)   on 2008-11-14 10:09:53 (Show Source): You can put this solution on YOUR website! 1 2/3 - 2 1/2 5/3-5/2 (5*2-5*3)/6 (10-15)/6 -5/6 answer.

Mixture_Word_Problems/167573: 40 liters of pure syrup costs $18. per liter, mixed w/ imitation syrup that cost $8.50 per liter. How much imitation is needed to make a mixture costing $11.00 per liter? 1 solutions Answer 123474 by checkley77(12569)   on 2008-11-14 10:06:31 (Show Source): You can put this solution on YOUR website! 40*18+8.50x=11(40+x) 720+8.50x=440+11x 8.5x-11x=440-720 -2.50x=-280 x=-280/-2.50 x=112 liters of $8.50 imitation syrup is used. Proof: 40*18+8.50*112=11(40+112) 720+952=11*152 1,672=1,672

Mixture_Word_Problems/167575: walnuts that cost $4.05 per kilogram were mixed w/ cashews that cost $7.25 per kilogram. How many kilograms of each were used to make a 50 kg. mixture that costs $6.25 per kilogram.(round to nearest 10th). 1 solutions Answer 123472 by checkley77(12569)   on 2008-11-14 10:00:40 (Show Source): You can put this solution on YOUR website! 7.25x+4.05(50-x)=6.25*50 7.25x+202.5-4.05x=312.50 3.2x=312.50-202.50 3.2x=110 x=110/3.2 x=34.38 kg. of cashews are used. 50-34.38=15.62 kg. of walnuts are used. Proof: 7.25*34.38+4.05*15.62=312.50 249.26+63.26=312.50 ------------------------------------------------- Rounding to thew nearest pound would be 34 & 16.

Linear-equations/167577: how do I graph... y=1/3x 1 solutions Answer 123471 by checkley77(12569)   on 2008-11-14 09:59:04 (Show Source): You can put this solution on YOUR website! y=1/3x Set x=0 & solve for y y=0/3 y=0 or (0,0) is one point. Set x=3 & solve for y y=3/3 y=3 or(3,1) is another point. Now draw a line through these 2 points. (graph 400x400 pixels, x from -5 to 5, y from -5 to 5, y = x/3).

Mixture_Word_Problems/167576: walnuts that cost $4.05 per kilogram were mixed w/ cashews that cost $7.25 per kilogram. How many kilograms of each were used to make a 50 kg. mixture that costs $6.25 per kilogram.(round to nearest 10th). 1 solutions Answer 123469 by checkley77(12569)   on 2008-11-14 09:53:08 (Show Source): You can put this solution on YOUR website! 7.25x+4.05(50-x)=6.25*50 7.25x+202.5-4.05x=312.50 3.2x=312.50-202.50 3.2x=110 x=110/3.2 x=34.38 kg. of cashews are used. 50-34.38=15.62 kg. of walnuts are used. Proof: 7.25*34.38+4.05*15.62=312.50 249.26+63.26=312.50 312.52~312.50

Numeric_Fractions/167535: 2/3 x + 1/6 x = 2 1 solutions Answer 123422 by checkley77(12569)   on 2008-11-13 22:37:24 (Show Source): You can put this solution on YOUR website! 2/3x+1/6x=2 2x/3+x/6=2 (2*2x+x)/6=2 4x+x=6*2 5x=12 x=12/5 answer. Proof: 12/5*2/3+12/5*1/6=2 24/15+12/30=2 (2*24+12)/30=2 (48+12)/30=2 60/30=2 2=2

Triangles/167531: This question is from textbook glencoe Mathmatics Geometry Find x,JM,MN,and JN if triangle JMN is an isosceles triangle with line JM congruent to line MN. JM=2X-5 MN=3x-9 JN=x-2 T.he book answer is x=4,JM=3,MN=3,JN=2 Please explain how to work 1 solutions Answer 123419 by checkley77(12569)   on 2008-11-13 22:29:19 (Show Source): You can put this solution on YOUR website! JM=MN JM=2X-5 MN=3x-9 JN=x-2 Thus: 2x-5=3x-9 2x-3x=-9+5 -x=-4 x=4 answer. 2*4-5=8-5=3 for JM. 3*4-9=12-9=3 for MN. 4-2=2 for JN.